Answer:
The action is a result of the disk’s inertia.
Explanation:
In an inelastic collision:
I. only momentum is conserved
II. only kinetic energy is conserved
III. momentum and kinetic energy are both conserved.
IV. neither momentum nor kinetic energy are conserved.
Hi there!
I. Only momentum is conserved.
An inelastic collision means that there is a LOSS in the KINETIC ENERGY of the system.
However, momentum is ALWAYS conserved for every type of collision unless there is an external force acting on the system.
Two spherical balloons are filled with water. The first balloon has a radius of 3 cm, and the second has a radius of 6 cm. How much greater is the volume of water in the larger balloon than in the smaller balloon? Use 3. 14 to approximate pi. Round to the nearest hundredth if necessary. Enter your answer as a decimal in the box.
Answer:
V = 4/3 R^3
V2 / V1 = (R2 / R1)^3 = 2^3 = 8
8.00
The volume of water in the larger balloon is 8 times greater than in the smaller balloon
We'll begin by calculating the volume of each balloon.
For smaller balloon:Radius (r) = 3 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 3³
V = 113.04 cm³For larger balloon:Radius (r) = 6 cmPi (π) = 3.14Volume (V) =?V = 4/3 πr³
V = 4/3 × 3.14 × 6³
V = 904.32 cm³Finally, we shall determine how much greater the larger balloon is to the smaller balloon
Volume of smaller balloon = 113.04 cm³Volume of larger balloon = 904.32 cm³Greatness =?Greatness => large / small
Large / small = 904.32 / 113.04
Large / small = 8
Cross multiply
Large = 8 × smallTherefore, the larger balloon is 8 times greater than the smaller balloon.
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What event will produce the greatest increase in the gravitational force between the two masses?
Question 5 options:
Doubling the distance between the masses
Reducing the small mass by half
Doubling the large mass
Reducing the distance between the masses by half
Answer:
Doubling the large mass
Explanation:
By doubling the mass you will get more gravational force
What is velocity? Explain.
Answer:
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).A bullet of mass 20 g has its kinetic energy equal to 400 J. Find the speed of the bullet.
Answer:
m=20g=0.02kgK.E=400J[tex]\\ \sf\longmapsto KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}(0.02)v^2=400[/tex]
[tex]\\ \sf\longmapsto 0.01v^2=400[/tex]
[tex]\\ \sf\longmapsto v^2=40000[/tex]
[tex]\\ \sf\longmapsto v=200m/s[/tex]
how to find velocity with constant acceleration
Answer:
velocity = distance / time
example:
if a body moves "20" meters in "2" seconds
, then it's velocity = 20/2 = "10m/s"
3. A(n)______ is someone who travels to new places or does new things. A. explorer B. thrill C. expedition D. research
Answer:
explorer
Explanation:
Answer:
a) EXPLORER
Explanation:
An explorer is someone who travels to new places or does new things.
a 10 mh inductor is connected in series with a 10 ohm resistor, a switch and a 6 v battery. what is the time constant of the circuit
Answer:
The inductive time constant is just T = L / R
T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec
(.01 / 10 = .1)
why does rhododendron not grow well in the terai region of nepal give reason
Answer:
Tge Rhododendrob is the national flower of Nepal. The hills and mountain sides ranges of Nepal are decorated with diff colours and shapes
What happens to all light bulbs in a series circuit when one burns out?
Answer:
In a series circuit, every device must function for the whole circuit to be complete. One bulb burning out in a series circuit breaks the circuit. Even if you take a bulb out, the entire circuit will still stop operating. There is no closed-loop path for the current to flow through the circuit. For the whole series circuit to be complete, and on, every bulb must be working.
Explanation:
[tex] \huge{ \mathrm{question \hookleftarrow}}[/tex]
Calculate equivalent resistance of two resistors R1 and R2 in parallel where,
[tex] \sf R_ 1 = (6 \pm0.2 )\: \: ohms[/tex]
[tex] \sf R_ 2 = (3 \pm0.1 )\: \: ohms[/tex]
[tex]it \: was \: helpful \: to \: you[/tex]
# be careful#
please help quickly,the picture and choices are above.
Answer:
C because it make sens
C the light wave traveled through ice and then through a Dimond.
The frequency of a wave is 4hz. If the wavelength is 2m how fast is the water moving?
I need the Formula,Known,Substitute & Solve Answer with Units
Answer:
This is the answer that I got
Explanation:
Hope it is right.
Plz help!
A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?
The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:
Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.
Indicate in the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.
Vector A.
Aₓ = 100.0 m
Vector B.
B_y = -300.0 m
The negative sign indicates that it goes in the negative direction of the y-axis
Vector C.
We use trigonometry.
The angle measured from the positive side of the x-axis counterclockwise is
θ = 180 + 30 = 210
sin 210 = [tex]\frac{C_y}{C}[/tex]
cos 210 = [tex]\frac{C_x}{C}[/tex]
C_y = C sin 210
Cₓ = C cos 210
C_y = 150.0 sin 210 = -75.0 m
Cₓ = 150.0 cos 210 = -129.9 m
Vector D.
The angle from the positive side of the x-axis counterclockwise.
θ = 180-60 = 120º
sin 120 = [tex]\frac{D_y}{D}[/tex]
cos 120 = [tex]\frac{D_x}{D}[/tex]
D_y = D sin 120
Dₓ = D cos 120
D_y = 200.0 sin 120 = 173.2 m
Dₓ = 200.0 cos 120 = -100.0 m
we add the component with algebraic sum.
x = Aₓ + Cₓ + Dₓ
y = B_y + C_y + D_y
x = 100 - 129.9 -100 = -129.9 m
y = -300 - 75.0 + 173.2 = -201.8 m
We construct the resulting vector.
We use the Pythagorean theorem for the Modulus.
[tex]R+ \sqrt{x^2 +y^2}[/tex]
R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]
R = 239.99 m
We use trigonometry for the angle.
tan θ = [tex]\frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)
θ = 57.2º
Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.
θ = 270 - θ'
θ = 270 - 57.2
θ = 212.8º
In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
Learn more about vector addition here: brainly.com/question/24855749
The instant before a batter hits a 0.14-kilogram baseball, the velocity of the ball is 45 meters per second west. The instant after the batter hits the ball, the ball's velocity is 35 meters per second east. The bat and ball are in contact for 1.0 x 10-2 second.
1. find the magnitude and direction of the average acceleration of the baseball while it is in contact with the bat.
2. calculate the magnitude of the average force the Bat exerts on the ball while they are in contact.
(1) The magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is 8,000 m/s² east.
(2) The magnitude of the average force the Bat exerts on the ball while they are in contact is 1,120 N.
The given parameters:
Mass of the baseball, m = 0.14 kgInitial velocity of the baseball, u = 45 m/s west (negative direction)Final velocity of the baseball, v = 35 m/s east (positive direction)Time of contact, t = 0.01 sThe magnitude and direction of the average acceleration of the baseball while it is in contact with the bat is calculated as follows:
[tex]a = \frac{v- u}{t} \\\\a = \frac{35 - (-45)}{0.01} \\\\a = \frac{80}{0.01} \\\\a = 8,000 \ m/s^2[/tex]
The magnitude of the average force the Bat exerts on the ball while they are in contact is calculated as follows;
[tex]F = ma\\\\F = 0.14 \times 8,000\\\\F = 1,120 \ N[/tex]
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Help plz I don’t know it
Answer:
2. thermal insulator. 3. convection current. 4. conduction. 5. thermal conductor. 6. radiation.
Explanation:hope this helps you.
Suppose you take a piece of hard wax from an unlit candle. After you roll the wax between your fingers for a while, it becomes soft. What state of matter is the softer wax? Is it possible for the wax to change without changing its state?
Answer:
An amorphous solid does not have a definite melting point; instead, it melts gradually over a range of temperatures, because the bonds do not break all at once. This means an amorphous solid will melt into a soft, malleable state (think candle wax or molten glass) before turning completely into a liquid.
Explanation:
Hope this helps
May I get braineist pls?
Line segment Q R , Line segment R S and Line segment S Q are midsegments of Î"WXY. Triangle R Q S is inside triangle X Y W. Point R is the midpoint of side X Y, point S is the midpoint of side Y W, and point Q is the midpoint of side X W. The length of Q R is 2. 93 centimeters, the length of R S is 2. 04 centimeters, and the length of Q S is 2. 28 centimeters. What is the perimeter of Î"WXY? 11. 57 cm 12. 22 cm 12. 46 cm 14. 50 cm.
The perimeter of ΔWXY is : ( D ) 14.5 cm
Calculating the perimeter of ΔWXY
QR = WY / 2
RS = XW / 2
QS = XY / 2
Given that : QR = 2.93 cm , RS = 2.04 cm, QS = 2.28 cm
Therefore
Perimeter of ΔWXY = ∑ WY + XW + XY
= 2SR + 2QS + 2QR
= 2(2.04) + 2(2.28) + 2(2.93)
= 14.5 cm
Hence we can conclude that the perimeter of ΔWXY = 14.5 cm
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Answer:
The name of the shape on the right is M prime N prime O prime P prime Q prime R prime S prime because it is the image of the shape on the left.
Explanation:
I have two questions. I hope anyone can help me <3 Question 8 & Question 9.
Answer:
i have not study it till now
Explanation:
sorry i don't know
i. la protagonista ama a su gata. escribimos, en nuestros cuadernos , las razones por las que pensamos que las personas aman de manera exagerada a sus mascotas. Proponemos un antídoto para la soledad. Lo escribrimos
Las mascotas son una buena fuente de compañía y socias en la soledad.
La protagonista ama a su gato porque las mascotas son una buena fuente de compañía y es un antídoto para la soledad. Estas mascotas como perros, gatos, loros, etc. dan placer y felicidad a las personas.
La gente tiene mascotas para pasar tiempo con ellas y jugar con ellas para refrescar sus mentes. Tener mascotas es una actividad maravillosa que hace que nuestra mente esté relajada y llena de felicidad, por lo que podemos concluir que las mascotas son una buena fuente de compañía y compañera en la soledad.
Learn more about pest here: https://brainly.com/question/989131
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A horizontal force F~ is applied to a block of mass m = 1 kg placed on an inclined
at θ = 30◦ plane. The coefficients of static and dynamic friction are µs = 0.3 and µ = 0.2, respectively. Find F such that the block is moving up the slope with a constant speed.
Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
[tex]\large\boxed{F_D = \mu N}}[/tex]
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
[tex]\large\boxed{N = Mgcos\theta + Fsin\theta}}[/tex]
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
Construct an explanation for the fact that we don’t see the same amount of energy coming out at the end of these transformations as we did at the beginning. *
Answer:
When energy is transformed from one form to another, or moved from one place to another, or from one system to another there is energy loss.
Explanation:
Hope this helps! :)
Scientists suggest that the universe is still expanding. Which statement supports the claim made by the scientists?
The universe is 13.7 billion years old.
The galaxies in the universe are composed of dark matter.
The universe originated from a hot, dense point.
The galaxies in the universe are moving away from Earth at high speeds.
Answer:
The galaxies in the universe are moving away from Earth at high speeds.
Explanation:
Light years.
What would happen to a 100N gravitational force if both masses were doubled and the radius were
doubled
The force winds up unchanged, at 100 N.
Calculate the resistance of a 1km length, 1mm diameter wire made from:
a) constantan (\rho = 4.9 × 10-7 Ωm)
b) copper (\rho = 1.7 × 10-8 Ωm)
c) State which material is better suited for being used to make resistors, and justify your answer.
d) With 1 amp of current flowing through each of the wires how much energy is converted to heat?
e) What potential difference would be needed to force a current of 1 amp through that length of each type of wire?
From the values of resistivity, the resistance of copper wire is 22 Ω.
Let us recall that;
R = ρl/A
ρ = resistivity
l = length of the wire
A = cross sectional area of the wire
For constantan;
R = 4.9 × 10^-7 × 1 × 10^3/[3.14 × ((1 × 10^-3)/2)^2]
R = 620 Ω
For copper;
R = 1.7 × 10-8 × 1 × 10^3/[3.14 × ((1 × 10^-3)/2)^2]
R = 22 Ω
The material that is best suitable to make resistors is constantan wire.
For constantan, the energy converted to heat is;
I^2 R = (1)^2 × 620 Ω = 620 W
For copper, the energy converted to heat is;
I^2R = (1)^2 × 22 Ω = 22Ω
The potential difference of constantan = IR = 1 × 620 Ω = 620 V
The potential difference of copper = = IR = 1 × 22Ω = 22 V
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Grass, trees, shrubs, worms, birds, and deer that live in a certain area is known as what?
Answer:they live in grass land also called forests hope the answer helps
Explanation:
What is the gravitational force between two objects of masses 20kg and 50kg separated by a distance of
4m?
Answer:
4.16875×10^-9
Explanation:
given,
mass(M1)=20kg
mass(M2)= 50kg
distance(d)=4m
gravitational constant value (G)=6.67×10^-11
we know,
gravitational force=(Gm1m2)÷d^2
=(6.67×10^-11×20×50)÷4^2
=(6.67×10^-8)÷16
= 4.16875×10^-9
A car takes off from rest takes of from rest and covers a distance of 80m on a straight road in 10s.Calculate the magnitude of its acceleration.
Answer:
The magnitude of its acceleration is 1.6 m/s^2.
Hope you could get an idea from here.
Doubt clarification - use comment section.
The gravitational force between two asteroids is 6.2 × 108 N. Asteroid Y has three times the mass of asteroid Z.
If the distance between the asteroids is 2100 kilometers, what is the mass of asteroid Y?
Answer:
1.1x10¹⁶ kg
Explanation:
Let m = mass of asteroid y.
Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.
Given:
F = 6.2x10⁸ N
d = 2100 km = 2.1x10⁶ m
Note that
G = 6.67408x10⁻¹¹ m³/(kg-s²)
The gravitational force between the asteroids is
F = (G*m*(m/3))/d² = (Gm²)/(3d²)
or
m² = (3Fd²)/G
= [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))
= 1.229x10³² kg²
m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)
why does polishing the surface of a metal extend fatigue life
Answer:
they are machined with shape characteristics which maximize the fatigue life of a metal.
Explanation:
they are highly polished to provide the surface characteristics which enable the best fatigue life.