The diagram below illustrates changes over time in a population of foxes in the wild,
X
What process is illustrated in the diagram?
extinction
overproduction
O natural selection
O artificial selection

Answer:

Its called contraction.

Explanation:

Answer:

B for sure

Explanation:

Because they all consume

Answer: a) Temperature of [tex]170^0C[/tex]

b) [tex]C_2H_5OH\stackrel{conc H_2SO_4, 170^0C}\rightarrow C_2H_4+H_2O[/tex]

c) dehydrating agent

Explanation:

Ethanol is heated with an excess of concentrated sulfuric acid at a temperature of 170°C to produce ethene.

The balanced chemical reaction is:

[tex]C_2H_5OH\stackrel{conc H_2SO_4, 170^0C}\rightarrow C_2H_4+H_2O[/tex]

Here concentrated sulfuric acid removes a water molecule from ethanol and thus acts as a dehydrating agent.

Answer:

Ba

Explanation:

The trend for atomic radius is that it increases as you go down and decreases as you go right.

Answer:

well with that you can make a water maker that might make you brother happy because it will keep him alive

Explanation:

Answer:

you could sew a doll for him

or you could punch him in the face and tell him to cheer up

Explanation:

Answer:

Covalent bonds usually occur between nonmetals. For example, in water (H2O) each hydrogen (H) and oxygen (O) share a pair of electrons to make a molecule of two hydrogen atoms single bonded to a single oxygen atom. ... Covalent compounds tend to be soft, and have relatively low melting and boiling points.

Beryllium (Be) will form an ionic compound with nitrogen with the general formula M[tex]_3[/tex]N[tex]_2[/tex]. Therefore, the correct option is option D.

Metal refers to any of a class of substances that have excellent electrical and thermal conductivity, malleability, flexibility, or light reflection. Metals account for over 75% of any and all chemical elements currently known.

Aluminum, iron, salt, potassium, and magnesium are the most abundant elements in the Earth's crust. Most metals can be found in ores, while some, such as copper, gold, platinum, even silver, are frequently found in their free state because they do cannot easily react with other elements. Beryllium (Be) will form an ionic compound with nitrogen with the general formula M[tex]_3[/tex]N[tex]_2[/tex].

Therefore, the correct option is option D.

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Answer:

Energy and how it can change forms. Kinetic, potential, and chemical energy.

Answer:

Air pressure is greater at sea level than at the top of a mountain. The amount of air at sea level is greater than that on top of a mountain.

Explanation:

Please give thanks to all my answers and please mark as brilliant and please follow me

Answer:

the bell is longitudinal

the secound one is transverse

third is longitudinal

the fourth is transverse

Explanation:

i got it right on my mastery test

Answer:

Cellular differentiation

Explanation:

Answer:

cellular differentiation

Explanation:

Answer:

Frequency

Explanation:

When we talk about crests, we are referring to the high points of a wave.

We measure wave frequency by counting out the the number of crests (or high points) of a given wave that pass by a given point in a set amount of time. Thus, the higher the number of crests, the greater the frequency of the wave and vice versa.

We define the frequency of a wave as the number of waves that passes by a fixed point within a given period of time.

Answer: a truck crashes into a car

Explanation:

The truck drives in a wrong motion which makes the reaction of it crashing.

Answer:

7.98 × 10^3grams.

Explanation:

To find the mass of fluorine in the number of atoms provided, we first divide the number of atoms by Avagadros number (6.02 × 10^23atoms) to get the number of moles in the fluorine atom. That is;

number of moles (n) = number of atoms (nA) ÷ 6.02 × 10^23 atoms

n = 2.542 × 10^26 ÷ 6.02 × 10^23

n = 0.42 × 10^ (26-23)

n = 0.42 × 10^3

n = 4.2 × 10^2moles

Using mole = mass ÷ molar mass

Molar/atomic mass of fluorine (F) = 19g/mol

mass = molar mass × mole

Mass (g) = 19 × 4.2 × 10^2

Mass = 79.8 × 10^2

Mass = 7.98 × 10^3grams.

Answer:

a) Sodium Chloride is the limiting reactant.

b)285g of Ba3(PO4)2

Explanation:

a) 1000g Nacl x (1mol of Nacl/58.5g) x (2 Mol Na3PO4/6 mol of NaCl)= 5.70

- 2000g Ba3 (PO4)2 X 1 mol of Ba3 (PO4)2/601.9 x 2 mol of Na3PO4/1 mol of Ba3 (PO4)2= 6.65

Hence; NaCl is the limiting Reactant.

b) 1000g Nacl x (1mol of Nacl/58.5g) x 1 mol of Ba3 (PO4)2/ 6 mol of NaCl x601.9g/1 mol= 1715g  Ba3(PO4)2 USED.

2000g- 1715g=285g of Ba3(PO4)2 Left.

Sodium chloride is a limiting reagent.

284 grams of barium phosphate (excess reactant) are left.

Explanation:

Given:

[tex]6NaCl+Ba_3(PO_4)_2\rightarrow 2Na_3PO_4+3BaCl_2[/tex]

1000 grams of sodium chloride and 2000 grams of barium phosphate.

To find:

The limiting reactant and mass of excess reactant left.

Solution:

Mass of sodium chloride = 1000 g

Moles of sodium chloride =[tex]\frac{1000 g}{58.44 g/mol}=17.11mol[/tex]

Mass of barium phosphate = 2000 g

Moles of barium phosphate =[tex]\frac{2000 g}{601.93 g/mol}=3.323 mol[/tex]

[tex]6NaCl+Ba_3(PO_4)_2\rightarrow 2Na_3PO_4+3BaCl_2[/tex]

According to reaction, 6 moles of sodium chloride reacts with 1 mole of barium phosphate, then 17.11 moles of sodium chloride will react with:

[tex]=\frac{1}{6}\times 17.11mol=2.852 \text{ mol of }Ba_3(PO_4)_2[/tex]

2.852 moles of barium phosphate reacted with 17.11 moles of sodium chloride.

But according to the question, we have 3.323 moles of barium phosphate which is more than 2.852 moles.

This indicates that barium phosphate is an excessive reagent and sodium chloride is a limiting reagent.

Moles of barium phosphate left unreacted:

[tex]=3.323 mol - 2.852 mol = 0.471 mol[/tex]

Mass of 0.471 moles of barium phosphate:

[tex]=0.471 mol\times 601.93 g/mol=283.51\approx 284 g[/tex]

Sodium chloride is a limiting reagent.

284 grams of barium phosphate (excess reactant) are left.

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Answer: The number of protons in cation is more than the number of electrons

Explanation:

cations are positive ions that means that they lose electrons to be stable nd have electron configuration (atomic number ) equivalent to the preceding noble gas

as : sodium 11 , it loses on electron to be stable and its electron configuration is equivalent to neon 10

so ,the number of protons in cation is more than the number of electrons

i hope it helps!

C. a long chain of carbon atoms with hydrogen atoms attached to them.

Explanation:

Answer:

C.

a long chain of carbon atoms with hydrogen atoms attached to it

Answer:

c. c. c c c c c cçcc. ccccccccc

Explanation:

ccc cc

When solid converts to gas then heat is required to break the intermolecular forces of attraction between the particles. In this process heat increase but temperature remains the same. So option A is correct option.

Phase transition is a process in which transition takes place from one state to another of a medium on changing temperature or pressure.  Phase transition is a physical process as there is no breaking of old bond and forming of new bonds takes place.

During phase transition temperature remain constant as the extra heat that is given to the system that goes into breaking of  intermolecular forces of attraction between the particles. So overall temperature remains same but heat keeps on increasing. Hence option A is correct.

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Answer:

6.022×1023 atoms

Explanation:

Answer: a: 0.04

b: 0

c: x

d: x

e: x

f: 0.04

Explanation:

Answer:

2C6H6 + 15O2 → 12CO2 + 6H2O

Answer:

2C6H6 + 15O2 --> 12CO2 + 6H2O

Answer:

I2 + 2S2O3^2- --------> S4O6^2- + 2I^-

Explanation:

The correct equation is;

2Na2S2O3 + I2 → Na2S4O6 + 2NaI

Oxidation half equation;

2S2O3^2- --------> S4O6^2- + 2e-

Reduction half equation;

I2 + 2e ----------> 2I^-

Overall balanced redox reaction equation;

I2 + 2S2O3^2- --------> S4O6^2- + 2I^-

Answer: 13.1

Explanation: just round the .06 to 1 creating three sig figs.

Answer:

1.

CH4 + Cl2 → CH3-Cl + HCl

2CH3-Cl +2Na → C2H6

2.

CH3-CH2-OH ---(conc. H2SO4)----> CH2=CH2 + H2O

Explanation:

1. Conversion of methane to ethane

Step 1 - Treat methane with chlorine gas presence of ultraviolet light

CH4 + Cl2 → CH3-Cl + HCl

Step 2 - Treat chloromethane formed in step 1 with the sodium metal and dry ether  (Wrutz synthesis)

2CH3-Cl +2Na → C2H6

2. On treating ethanol with excess of concentrated sulfuric acid, it converts into ethene

CH3-CH2-OH ---(conc. H2SO4)----> CH2=CH2 + H2O

Answer:

c.atomic mass

Explanation:

The total number of protons plus neutrons is called the atomic mass number for the atom.

Answer:

The SI base unit for amount of substance is the mole. 1 grams NaOH is equal to 0.025001806380511 mole.

Answer:

0.025001806380511 mole.

Explanation:

The SI base unit for amount of substance is the mole. 1 grams NaOH is equal to 0.025001806380511 mole.

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

0.137moles of water is formed, 0.0274 moles or 1.5892 g of butane burned and 0.1781 moles or 5.6992 g of O₂ is used.

Those reaction in which fuel is oxidized by the oxygen molecules and produce carbon dioxide and water molecule.

Given chemical reaction is:
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O

Given mass of water = 2.46 grams

Moles will be calculated as:

n = W/M, where

W = given mass

M = molar mass

(a) Moles of water formed is calculated as:

Moles of water n = 2.46g / 18 g/mol = 0.137moles

(b) From the stoichiometry of the reaction, it is clear that:

10 moles of water = produced by 2 moles of butane

0.137 moles of water = produced by 2/10×0.137=0.0274 moles of butane

(c) Weight of butane is calculated by using moles:

W = 0.0274 × 58 g/mol = 1.5892 g

(d) From the stoichiometry of the reaction, it is clear that:

2 moles of butane = react with 13 moles of O₂

0.027 moles of butane = react with 13/2×0.027=0.1781 moles of O₂

(e) Mass of oxygen is calculated as:
W = 0.1781 x 32 g/mol = 5.6992 g

Hence, (a) 0.137moles, (b) 0.0274 moles, (c) 1.5892 g, (d) 0.1781 moles and (e) 5.6992 g.

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