The density of crystalline cl2 at 160K is 2.02g/cm3. calculate the molar volumes

I believe the answer would be D

Explanation:

conjugated base is substance formed when an acid loses

a hydrogen ion.

conjugated acid is a type of acid that is formed when a base accepts a proton in solution

Explanation:

What do you mean by 'how many oxygen'?

oxygen atoms? or oxygen percentage?

if oxygen atoms is 12 atoms

Answer:

Water will generally require more energy for a phase change compared to a similar substance without hydrogen bonds.

Explanation:

c)

)

Na + Mg2+

Na + Mg

Na=

Mg =

=

Zn + CO2-

Zn?- + Co

Zn =

Co=

Answer:

Yes

Explanation:

You can tell because there are 2 moles of H2 on the reactants side and 1 mole of O2, and on the products side we see the same amount, meaning that no moles of H2 or O2 were added or destroyed, meaning that it follows the law of conservation of matter.

The mass of ammonium chloride that must be added is : ( A ) 4.7 g

Given data :

Volume of water ( V )  = 250 mL = 0.25 L

pH of solution = 4.85

Kb = 1.8 * 10⁻⁵

Kw = 10⁻¹⁴

Given that the dissolution of NH₄Cl gives NH₄⁺⁺ and Cl⁻ ions the equation is written as :

NH₄CI  +  H₂O  ⇄  NH₃ + H₃O⁺

where conc of H₃O⁺

[ H₃O⁺ ] = [tex]\sqrt{Ka.C}[/tex]   and Ka = Kw / Kb

∴ Ka = 5.56 * 10⁻¹⁰

Next step : Determine the concentration of H₃O⁺  in the solution

pH = - log [ H₃O⁺ ] = 4.85

∴ [ H₃O⁺ ] in the solution = 1.14125 * 10⁻⁵

Next step : Determine the concentration of NH₄CI in the solution

C = [ H₃O⁺ ]² / Ka

  = ( 1.14125 * 10⁻⁵ )² /  5.56 * 10⁻¹⁰

  = 0.359 mol / L

Determine the number of moles of NH₄CI in the solution

n = C . V

  = 0.359 mol / L  * 0.25 L =  0.08979 mole

Final step : determine the mass of ammonium chloride that must be added to 250 mL

mass = n * molar mass

         = 0.08979 * 53.5 g/mol

         = 4.80 g  ≈ 4.7 grams

Therefore we can conclude that the mass of ammonium chloride that must be added is 4.7 g

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Answer:

1050-452 = 598, the liquid is more than the ammonium chloride so it is the majority

boron, carbon, nitrogen, oxygen and flourine families in addition to the noble gases.

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also to answer the 'hello guys what is good!':nothin u?

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Answer:

About 58%.

Explanation:

We first need to write the balanced chemical equation:

[tex]\displaystyle \text{CH$_4$(g)} + 2\text{O$_2$(g)} \longrightarrow \text{CO$_2$(g)} + 2\text{H$_2$O(g)}[/tex]

We are given that 0.809 g of carbon dioxide was produced from the reaction of 0.80 g of methane and 2.1 g of oxygen gas. We want to calculate the percent yield of carbon dioxide.

First, determine the limiting reagent. We can convert each initial mass to the mass of carbon dioxide using stoichiometry. The molar mass of methane is 16.05 g/mol and the molar mass of carbon dioxie is 44.01 g/mol. From the equation, every one mole of carbon dioxide is produced from every one mole of methane and every two moles of oxygen gas.

0.80 g of methane will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 0.80 \text{ g CH$_4$} &\cdot \frac{1 \text{ mol CH$_4$}}{16.05 \text{ g CH$_4$}} \cdot \frac{1 \text{ mol CO$_2$}}{1 \text{ mol CH$_4$}} \cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 2.2 \text{ g CO$_2$}\end{aligned}[/tex]

2.1 g of oxygen gas will (theoretically) produce:

[tex]\displaystyle \begin{aligned} 2.1 \text{ g O$_2$} & \cdot \frac{ 1 \text{ mol O$_2$}}{32.00 \text{ g O$_2$}} \cdot \frac{1 \text{ mol CO$_2$}}{2 \text{ mol O$_2$}}\cdot \frac{44.01 \text{ g CO$_2$}}{1 \text{ mol CO$_2$}} \\ \\ & = 1.4 \text{ g CO$_2$} \end{aligned}[/tex]

Hence, oxygen gas is the limiting reagent. A maximum of 1.4 g of carbon dioxide can be produced.

To calculate the percent yield, we divide the actual yield by the theoretical yield. The actual yield was 0.809 g and the theoretical yield is 1.4 g. Hence:

[tex]\displaystyle \begin{aligned} \%\text{Yield} & = \frac{\text{Actual}}{\text{Theoretical}} \times 100\% \\ \\ & = \frac{(0.809\text{ g CO$_2$})}{(1.4\text{ g CO$_2$})} \times 100\% \\ \\ & = 58\%\end{aligned}[/tex]

In conclusion, the percent yield of carbon dioxide is about 58%.

The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

The average atomic mass of the sample can be obtained as follow:

[tex]Average \: atomic \: mass \: = \frac{mass \: of \: A \times A\%}{100} + \frac{mass \: of \: B \times B\%}{100} \\ \\ Average \: atomic \: mass \: = \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\ \\ Average \: atomic \: mass \: = 114.54 \: amu \\ \\ [/tex]

Thus, the average atomic mass of the sample is 114.54 amu

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Answer:

Yes

Explanation:

Because first of all you used yellow food coloring second you added it third the mixute turned the color of yellow

Answer:

6.023×10^23

Explanation:

Molecular mass= 2 (H)+1 (O) =2*1+1*16=2+16= 18 gm per 1gm molecule of water

Answer:

D

Explanation:

The valence electrons are the outer electrons and must be located in the outermost shell. In this case, D.

Answer:

objects thaty release 0H+ and H- ions when dissociated

Explanation:

in chemistry

please mark brainliest

Answer:

plastic,palstic bottle,balloon,cap of water bottle,plastic slippers and plastic comb.

Explanation:

hope it helps :D

Answer:

Explanation:

Consider the general chemical reaction

                                                       [tex]\mathrm{A} \ \overset{k}{\longrightarrow} \ \mathrm{product}[/tex]  .

If [A] is the concentration of A (reactant) at any time t and n is the reaction order for the whole equation, the rate is then related to the concentration of reactant A with the following differential form of equation

                                               [tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{n}[/tex]  .

where k is the rate constant.

*Note that the differential term [tex]\displaystyle\frac{d[\mathrm{A}]}{dt}[/tex] has a negative sign to denote that the concentration of A is decreasing over time t.

Since the chemical reaction between tert-butyl bromide and water is given to be a first-order reaction, hence n = 1, and the resulting differential equation becomes

                                        [tex]Rate \ = \ -\displaystyle\frac{d[\mathrm{A}]}{dt} \ = \ k[\mathrm{A}]^{1} \ = \ k[\mathrm{A}][/tex]

To solve this first-order linear homogenous differential equation, the method of separation of variables can be used.

[tex]\-\hspace{1cm} \displaystyle\frac{d[\mathrm{A}]}{dt} \ = -\ k[\mathrm{A}] \\ \\ \-\hspace{0.5cm} \displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = -\ k \, dt \\ \\ \int\ {\displaystyle\frac{1}{[\mathrm{A}]} \, d[\mathrm{A}] \ = \ -\int {k} \, {dt}[/tex]

         [tex]\ln{[\mathrm{A}]} \ = \ -kt \ + \ C \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt \ + \ C} \\ \\ \-\hspace{0.45cm} $[A]$ \ = \ e^{-kt}e^{C} \ \ \ \ \ \ \ \ \ (e^{a \ + \ b} \ = \ e^{a}e^{b} \ \ \ \mathrm{by \ the \ law \ of \ indices})[/tex]

Since the term [tex]e^{C}[/tex] is a constant, let [tex]\alpha \ = \ e^{C}[/tex], hence [tex][\mathrm{A}] \ = \ \alpha e^{-kt}[/tex] or [tex]C \ = \ \alpha e^{-kt}[/tex] according to the question. Given that the initial concentration (t = 0) of tert-butyl bromide is 0.2 mol/L and k = 0.0537[tex]\mathrm{h^{-1}}[/tex], so

[tex]0.2 \ = \ \alpha e^{-0.0537 \ \times \ 0} \\ \\ 0.2 \ = \ \alpha \ \ \ \ \ (e^{0} \ = \ 1)[/tex]

Therefore, the rate equation is [tex]C \ = \ 0.2e^{-0.0537t}[/tex].

The concentration of tert-butyl alcohol after 1 hour is

[tex]C \ = \ 0.2e^{-0.0537 \ \times \ 1} \\ \\ C \ = \ 0.2e^{-0.0537} \\ \\ C \ = \ 0.190 \ \mathrm{mol/L} \ \ \ (3 \ \ \mathrm{s.f.})[/tex]

Answer:

A

Explanation:

reason:

H-F is most polar

because bond is polarized negative towards F which is the more electronegative atom.

Answer:

In Homogenous mixtures, the whole mixture is in the same phase whereas in Heterogeneous mixture, substances can be of two phases and layers may separate. ... Homogeneous mixture could be exemplified as a sugar solution or salt solution whereas Mixture of salt and sand could be used as an example of Heterogeneous mixture.

Answer:

0.001742moles

Explanation:

1000ml of NaOH contain 0.1moles

17.42ml of NaOH contain (0.1*17.42)/1000 moles

= 0.001742moles

There are 2 electrons in the overlapping region.

Chlorine is the second member of the halogen group which are form of family of elements that resemble one another very closely.

The electronic configuration of chlorine shows the arrangement of chlorine electrons within it's atom.

At the outer most shell of the atom is seven electrons, therefore requires only one electron each to attain the octet arrangement.

The overlapping of the orbitals indicates the chemical bond formed by sharing of electrons between atoms called covalent bonding.

To complete it's outer most shell, it will need to share electron with another chlorine atom.

Therefore, there are 2 electrons in the overlapping region.

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Answer:

6.022 × 1023

Explanation:

1 mole of H:

The definition of Avogadro's number of 6.022 × 1023/mole is the number of atoms or molecules per one gram atomic weight. For one gram atomic weight of hydrogen with an atomic weight of one gram, one mole of hydrogen contains 6.022 × 1023 hydrogen atoms. 1.45⋅6.02⋅1023≈8.73⋅1023 hydrogen atoms.

1 mole:

The value of the mole is equal to the number of atoms in exactly 12 grams of pure carbon-12. 12.00 g C-12 = 1 mol C-12 atoms = 6.022 × 1023 atoms • The number of particles in 1 mole is called Avogadro's Number (6.0221421 x 1023).

in an H:

H: 2×2×4=16 atoms of hydrogen. C: It only appears once and without a subscript, so 1×4=4 .  O : Like carbon, it's 1×4=4 .

1.00 mole:

One mole is equal to 6.02214179×1023 atoms, or other elementary units such as molecules.

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Answer:

true or false

a. very little oxygen and nitrogen are found in air. false

b. oxygen is the main cause of the formation of rust in iron.   false

c.  impure air is odourless true

.d.  plants take in oxygen gas during respiration. true

e. air contains water vapour. ​true

Explanation:

An experiment that would show that intramolecular forces are stronger than intermolecular forces will be heating a block of ice in a sealed container then allowing it to change to steam.

Intramolecular forces are the forces of attraction that hold atoms together within a molecule. Intramolecular forces require a high amount of energy to splits atoms or molecules in a chemical bonding.

Intermolecular forces are weaker forces of attraction that occur between molecules. They require lesser energy to splits molecules compared to intramolecular forces.

An experiment that would show that intramolecular forces are stronger than intermolecular forces will be heating a block of ice in a sealed container then allowing it to change to steam.

In the process, the energy required to change the state from ice to steam water is more than intermolecular forces.

Thus, we can conclude that this experiment shows that the intramolecular forces are stronger than the intermolecular forces.

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Answer:

It increases the freezing point

Explanation:

The salt lowers the temperature at which water freezes. :)

Answer:

Determining what data to collect.

Explanation:

Answer:

oxygen carbon hydrogen nitrogen

Explanation:

identified by the number of protons in its atoms