Answer:
I have not been able to answer it sorry
what is the sum of the geometric series 4∑ t=1 6t-1
Answer:
Hello friend kya in snap and p to Trisha
Is −8 a solution to the equation 3x = 16 − 5x? How do you know?
h=255-21t-16t^2
PLEASE HELP!!
Answer:
3.15 seconds is the answer.
Explanation
when the ball touches the ground, h =0
hence,
0=255-21t-16t²
16t²+21t-225=0
here a=16 ,b=21, c= -225
[tex]t= \frac{ - b± \sqrt{ {b }^{2} - 4ac} }{2a} \\ \\ t= \frac{ - 21± \sqrt{ {21}^{2} - 4 \times 16 \times - 225} }{2 \times 16} \\ = \frac{ - 21 ± \sqrt{441 - ( - 14400)} }{32} \\ = \frac{ - 21± \sqrt{14841} }{32} \\ = \frac{ - 21±121.82}{32} \\ \\ t = \frac{ - 21 + 121.82}{32} \: or \: \: t = \frac{ - 21 - 121.82}{32} \\ t = 3.15 \: \: or \: \: t = - 4.46[/tex]
time cannot be negative, hence t = -4.46 can be avoided
The ball takes 3.15 seconds to hit the ground.
Help please!
• 7/25
•7/24
•24/25
•24/7
Answer:
24/25
Step-by-step explanation:
The sin value is the y coordinate of the exact value point.
24/25 is the y coordinate so 24/25 is the answer.
Answer:
24/25 is the correct answer
Larry deposits $15 a week into a savings account. His balance in his savings account grows by a constant percent rate.
True
False
Answer:
The answer is true
Step-by-step explanation:
what is the value of c? enter your answer in the box. round only your final answer to the nearest whole number.
Answer:
c ≈ 21
Step-by-step explanation:
By applying cosine rule in the given triangle ABC,
c² = a² + b² - 2abcos(C)
c² = (17)² + (10)² - 2(17)(10)cos(98.8°)
c² = 289 + 100 - 340(-0.1530)
c² = 441.015
c = 21
c ≈ 21
Write an equation for the function that includes the following points (2,32) and (3,64)
Answer:
32 = a*2 +b
64 = a*3 + b
Then 32 = a
32 = 32*2 +b
b = - 32
So
Y = 32a - 32
Is the equation
Perimeter of a square with side 4 square root of 5
Answer:
16[tex]\sqrt{5}[/tex]
Step-by-step explanation:
[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]+[tex]4\sqrt{5}[/tex]
16[tex]\sqrt{5}[/tex]
The perimeter of the square is 16√5 units.
We have,
The concept used here is straightforward: to find the perimeter of a square, you sum the lengths of all four sides because all sides of a square are equal in length.
In this case, the side length is given as 4√5, so you multiply it by 4 to calculate the total perimeter.
To find the perimeter (P) of a square with a side length of 4√5 units, you simply add up all four sides of the square, as all sides of a square are equal in length.
So,
P = 4 * side length
P = 4 * 4√5
P = 16√5 units
Thus,
The perimeter of the square is 16√5 units.
Learn more about squares here:
https://brainly.com/question/22964077
#SPJ3
A photograph has a length that is inches longer than its width, x. So its area is given by the expression square inches. If the area of the photograph is square inches, what is the width of the photograph?
The width of the photograph is blank inches.
Answer:
width is also "inches"
Step-by-step explanation:
You need
1
1
4
feet of string to make 20 holiday ornaments.
To make 14 holiday ornaments, you will need
feet of string.
Answer:
79.8
Step-by-step explanation:
math
anna needs at least $1000 to pay her bills this week.she has $250 in the bank and makes $15 an hour at her job.how many hours does she have to work thus week in order to pay her bills
what is the greatest common factor of 160 and 198?
Hey there!
[tex]\large\textsf{FACTORS OF 160: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, \& 160}[/tex]
[tex]\large\textsf{FACTORS OF 198: 1, 2, 3, 6, 9, 11, 18, 22, 33, 66, 99, \& 198}[/tex]
[tex]\large\text{Go through the factors to see if there’s any like terms and if you find any,} \\\large\text{look for the greatest one the numbers share together.}[/tex]
[tex]\large\text{Like terms: \boxed{\textsf{\bf 1 \& 2}}}[/tex]
[tex]\large\checkmark\boxed{\large\text{GCF: \bf 2 }}\large\checkmark[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: \huge the GCF \underline{G}reatest \underline{C}ommon \underline{F}actor is \bf 2}}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
What’s this answer help please
B is the answer for this question hope it helps
Solve the system of equations using the elimination method. 5x + 10y = 3 10x + 20y = 8
Answer:
Can not be solved
Step-by-step explanation:
5x+10y = 3............. Equation 1
10x+20y = 8 ............ Equation 2
From the equation above,
both equations can not be solved by elimination method, because both variables will be eliminated
The ratio of girls to boys in a classroom is 3:5. Kevin says there must be 8 students in the classroom. Which explains whether Kevin is correct?
Answer:
Kevin is correct.
Step-by-step explanation:
3 girls + 5 boys = 8 students.
Answer:
he is incorrect since in a ratio you don't add them together instead what this ratio means is for every 3 girls there is 5 boys
Hope This Help!!!
Which equation could represent each grapes polynomial function?
9514 1404 393
Answer:
top graph: y = x(x +3)(x -2)bottom graph: y = x⁴ -5x² +4Step-by-step explanation:
Each x-intercept at x=a corresponds to a polynomial factor of (x -a).
__
The top graph has x-intercepts of -3, 0, +2, so the factors of this cubic are ...
y = (x +3)(x -0)(x -2)
y = x(x +3)(x -2) . . . . . . . matches upper right tile
__
The bottom graph has x-intercepts of -2, -1, 1, 2, so the factors of this quartic are ...
y = (x +2)(x +1)(x -1)(x -2) = (x² -4)(x² -1)
y = x⁴ -5x² +4 . . . . . . . matches lower left tile
Find the intercepts for the graph of the equation.
-3x + y = 6
Answer:
y = 9
Step-by-step explanation:
Consider the following game: You reach into a jar of money, and select a single bill at random to keep. There are 9 five-dollar bills, 5 ten-dollar bills, and 3 twenty-dollar bills in the jar. What should the cost of this game be in order for the game to be fair
Answer:
[tex]E(x)=\$9.118[/tex]
Step-by-step explanation:
From the question we are told that:
Available bills
[tex]\$5=N0 9\\\\\$10=N0 5[/tex]
[tex]\$20=N0 3[/tex]
Therefore
Total Bills
[tex]n=5+9+3[/tex]
[tex]n=17[/tex]
Probability of selecting each bill
[tex]For\$5[/tex]
[tex]P(\$5)=\frac{9}{17}[/tex]
[tex]For\$10[/tex]
[tex]P(\$10)=\frac{5}{17}[/tex]
[tex]For\$20[/tex]
[tex]P(\$20)=\frac{3}{17}[/tex]
Generally the equation for Expected winning is mathematically given by
[tex]E(x)=\sum(X)*P(X)[/tex]
[tex]E(x)=5*\frac{9}{17}+10*\frac{5}{17}+20*\frac{3}{17}[/tex]
[tex]E(x)=\$9.118[/tex]
A particular network service provider charges 50 Kobo per second to make a call. How many minutes will a caller with 300 naira airtime last.
9514 1404 393
Answer:
10 minutes
Step-by-step explanation:
The current legal tender conversion rate is 50 kobo = 0.50 naira. Then the airtime balance is ...
(300 NGN)/(0.50 NGN/s) × (1 min)/(60 s) = 300/(0.50×60) min = 10 min
How to answer this question
Answer:
(0.3049 ; 0.3751)
Step-by-step explanation:
The confidence interval for proportion can be obtained using the relation :
Phat ± Zcritical * [√phat(1-phat) / n]
phat = x / n
Sample size, n = 700
x = 238
phat = 238/700 = 0.34
Zcritical at 95% = 1.96
C.I = 0.34 ± 1.96 * [√0.34(1-0.34) / 700]
C.I = 0.34 ± 1.96 * 0.0179045
C. I = 0.34 ± 0.0350928
Lower boundary = 0.34 - 0.0350928 = 0.3049
Upper boundary = 0.34 + 0.0350928 = 0.37509
(0.3049 ; 0.3751)
Suppose that Bag 1 contains a red (R), a blue (B) and a white (W) ball, while Bag 2 contains a red (R), a pink (P), a yellow (Y) and a green (G) ball. A game consists of you randomly drawing a ball from each of Bag 1 and Bag 2. (a) What are the 12 outcomes in the sample space S for this experiment? (b) You win the prize of baked goods if you draw at least 1 red ball. List the outcomes in the event that you win that prize, and use them to compute the probability of this event. You should assume that all outcomes in the sample spaces obtained in (a) are equally likely.
Answer:
1 /2
Step-by-step explanation:
Given :
Bag 1 : Red (R) ; Blue (B) ; White (W)
Bag 2 : Red (R) ; Pink (P) ; Yellow (Y) ; Green (G)
Total number of possible outcomes :
3C1 * 4C1 = 3 * 4 = 12 outcomes
Sample space (S) ;
_______ R ______ B _______ W
R_____ RR _____ RB ______ RW
P_____ PR _____ PB ______ PW
Y _____YR_____ YB ______ YW
G _____GR ____ GB ______ GW
To win price of baked goods ; Atleast one red ball must be drawn :
Probability of winning ; P(winning) = required outcome / Total possible outcomes
Required outcome = {RR, RB, RW, PR, YR, GR} = 6
Total possible outcomes = S = 12
P(winning) = 6/12 = 1/2
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
Year Population
1750 790
1800 980
1850 1260
1900 1650
1950 2560
2000 6080
(a) Use the exponential model and the population figures for 1750 and 1800 to predict the world population in 1900 and 1950 1900 1950 million people million people
(b) Use the exponential model and the population figures for 1800 and 1850 to predict the world population in 1950 million people
(c) Use the exponential model and the population figures for 1900 and 1950 to predict the world population in 2000 million people
Answer:
A.) 1508 ; 1870
B.) 2083
C.) 3972
Step-by-step explanation:
General form of an exponential model :
A = A0e^rt
A0 = initial population
A = final population
r = growth rate ; t = time
1)
Using the year 1750 and 1800
Time, t = 1800 - 1750 = 50 years
Initial population = 790
Final population = 980
Let's obtain the growth rate :
980 = 790e^50r
980/790 = e^50r
Take the In of both sides
In(980/790) = 50r
0.2155196 = 50r
r = 0.2155196/50
r = 0.0043103
Using this rate, let predict the population in 1900
t = 1900 - 1750 = 150 years
A = 790e^150*0.0043103
A = 790e^0.6465588
A = 1508.0788 ; 1508 million people
In 1950;
t = 1950 - 1750 = 200
A = 790e^200*0.0043103
A = 790e^0.86206
A = 1870.7467 ; 1870 million people
2.)
Exponential model. For 1800 and 1850
Initial, 1800 = 980
Final, 1850 = 1260
t = 1850 - 1800 = 50
Using the exponential format ; we can obtain the rate :
1260 = 980e^50r
1260/980 = e^50r
Take the In of both sides
In(1260/980) = 50r
0.2513144 = 50r
r = 0.2513144/50
r = 0.0050262
Using the model ; The predicted population in 1950;
In 1950;
t = 1950 - 1800 = 150
A = 980e^150*0.0050262
A = 980e^0.7539432
A = 2082.8571 ; 2083 million people
3.)
1900 1650
1950 2560
t = 1900 - 1950 = 50
Using the exponential format ; we can obtain the rate :
2560 = 1650e^50r
2560/1650 = e^50r
Take the In of both sides
In(2560/1650) = 50r
0.4392319 = 50r
r = 0.4392319/50
r = 0.0087846
Using the model ; The predicted population in 2000;
In 2000;
t = 2000 - 1900 = 100
A = 1650e^100*0.0087846
A = 1650e^0.8784639
A = 3971.8787 ; 3972 million people
The Goodman Tire and Rubber Company periodically tests its tires for tread wear under simulated road conditions. To study and control the manufacturing process, 20 samples, each containing three radial tires, were chosen from different shifts over several days of operation; the data collected are shown below. Assuming that these data were collected when the manufacturing process was believed to be operating in control, develop the R and charts.
R Chart: (to 2 decimals)
UCL =
LCL =
Chart: (to 1 decimal)
UCL =
LCL =
Answer:
Range:
UCL = 4.73
LCL = 18.08
MEAN :
UCL = 27.115
LCL = 31.219
Step-by-step explanation:
Given the data:
The mean and range of each sample :
Sample __ Thread wear __ xbar __ R
1 ___31 __ 42 ___ 28 ____ 33.67 _14
2___ 26 _ 18 ____35____ 26.33 _17
3___25 __30 ___ 34____29.67 _ 9
4 __ 17 __ 25 ___ 21 _____ 21 ___ 8
5 __ 38 _ 29 ___ 35 _____ 34 __ 9
6 __ 41 __42 ___36 _____39.67_ 6
7 __ 21 __ 17 ___29 _____22.33 _12
8 __ 32 __26___28 ____ 28.67 _ 6
9 __ 41 __ 34 __ 33 ______ 36 __8
10__29___17___30 _____25.33_ 13
11 __26 __ 31 __ 40 _____32.33_ 14
12__23 __ 19 __ 45 _____12.33 __6
13 __17 __ 24 __ 32_____24.33__15
14 __43__ 35___17_____ 31.67 _ 26
15__18 ___25__ 29_____ 24 ___ 11
16__30___42___31 ____34.33__ 12
17__28___36 __ 32____ 32 ____8
18__40 __ 29 __ 31 ____33.33 __ 11
19__18 ___29__ 28____ 25 ____11
20_ 22 __ 34 __ 26 ___ 27.33 __12
Size per sample, sample size, n = 3
Number of samples, k = 20
We calculate the sample mean and range average :
Sample mean, x-- = Σxbar/n = 29.167
Range average, Rbar = ΣR/n = 11.4
The mean control limit :
x-- ± A2Rbar
From the x chart ;
A2 for n = 20 is A2 = 0.180
29.167 ± 0.180(11.40)
LCL = 29.167 - 0.180(11.40) = 27.115
UCL = 29.167 + 0.180(11.40) = 31.219
The Range control limit :
Rbar(1 ± 3(d3/d2))
From the R-chart :
d2 at n = 20 ; d2 = 3.735
d3 at n = 20 ; d3 = 0.729
LCL = 11.40(1 - 3(0.729/3.735)) = 4.725
UCL = 11.40(1 + 3(0.729/3.735)) = 18.075
write expanded notion of 752 863?
Answer:
7 hundred thousands, 5 ten thousands, 2 thousands, 8 hundreds, 6 tens, 3 ones
Step-by-step explanation:
to write a number in expanded notation all you need to do is write out the number in words.
Find the value of x. What is the value of x?
Answer:
x = 16
Step-by-step explanation:
The product of the lengths theorem is a property that can be sued to describe the relationships of the sides between the tangents and secants in a circle. One of these products states the following;
The distance between the point of tangency and its intersection point with the exterior secant squared is equal to the product of the exterior secant times the interior secant.
This essentially means the following equation can be formed;
[tex](AB)^2=(DC)(CB)[/tex]
Substitute,
[tex]12^2=x*9[/tex]
Simplify,
[tex]144=9x[/tex]
Inverse operations,
[tex]\frac{144}{9}=x\\\\16=x[/tex]
Answer:
[tex]\boxed{\sf x=7}[/tex]
Step-by-step explanation:
By Targent-secant theorem...
[tex]\sf 9(x + 9) = {12}^{2} [/tex]
Use the distributive property to multiply 9 by x+9.
[tex]\sf 9x+81= {12}^{2} [/tex]
Now, let calculate 12 to the power of 2 and get 144.
[tex]\sf 9x+81=144[/tex]
Subtract 81 from both sides.
[tex]\sf 9x=63[/tex]
Divide both sides by 9.
[tex] \sf \cfrac{ 9x}{9} = \cfrac{63}{9} [/tex]
[tex]\sf x=7[/tex]
A statistics class weighed 20 bags of grapes purchased from the store. The bags are advertised to contain 16 ounces, on average. The class calculated the 90% confidence interval for the true mean weight of bags of grapes from this store to be (15.875, 16.595) ounces. What is the sample mean weight of grapes, and what is the margin of error?
O The sample mean weight is 15.875 ounces, and the margin of error is 16.595 ounces.
O The sample mean weight is 16.235 ounces, and the margin of error is 0.360 ounces.
O The sample mean weight is 16.235 ounces, and the margin of error is 0.720 ounces.
O The sample mean weight is 16 ounces, and the margin of error is 0.720 ounces.
Answer:
The sample mean weight is 16.235 ounces, and the margin of error is 0.360 ounces
Step-by-step explanation:
To find the sample mean, we can find the mean of the confidence interval.
(15.875 + 16.595)/2 = 16.235
To find the margin of error, that is the difference between the mean and one of the edges of the confidence interval. 16.595 - 16.235 = 0.36
The sample mean weight is 16.235 ounces, and the margin of error is 0.360 ounces
Answer:
C. We are 90% confident that the interval from 15.875 ounces to 16.595 ounces captures the true mean weight of bags of grapes.
Step-by-step explanation:
f(x) = (x + 1)^2
Determine for each x-value whether it is in the domain of f
or not.
Answer:
All of them are in the domain.
Step-by-step explanation:
The function is f(x)= (x+1)^2. If you simplify this, you get y=x^2+2x+1=0. This is a quadratic that opens upwards. There are no gaps in the x values and no impossible values. The domain is all real numbers and all the answer choices are real numbers.
the slope of line is
Answer:
there is no file attached
Step-by-step explanation:
Cenntura was having fun playing poker she needed the next two cards out to be heart so she could make a flesh five cards of the same suit there are 10 cards left on the deck and three our hearts what is the probability that two cards doubt to Seterra without replacement will both be hearts answer choices are in percentage for format rounded to the nearest whole number
Answer:
7% probability that the next 2 cards are hearts.
Step-by-step explanation:
Cards are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
10 cards, which means that [tex]N = 10[/tex]
3 are hearts, which means that [tex]k = 3[/tex]
Probability that the next 2 cards are hearts:
This is P(X = 2) when n = 2. So
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 2) = h(2,10,2,3) = \frac{C_{3,2}*C_{7,0}}{C_{10,2}} = 0.0667[/tex]
0.0667*100% = 6.67%
Rounded to the nearest whole number, 7% probability that the next 2 cards are hearts.
The alternative hypothesis for a two-tailed test of a single population proportion might be?
A. Ha: P>0.4
B. Ha: P< 0.4
C. Ha: p~=0.4 (~means not equal to)
Answer:
tgis moght help
Step-by-step explanation:
https://opentextbc.ca/introbusinessstatopenstax/chapter/full-hypothesis-test-examples/