Answer:When carbon atom tends to form single bonds then its hybridization is , when carbon atom tends to form double bond then its hybridization is and when a carbon atom is attached to a triple bond or with two double bonds then its hydridization is sp.
For example, in HCN molecule there is a triple existing between the carbon and nitrogen atom.
So, hybridization of carbon in this molecules is sp. Moreover, nitrogen atom is also attached via triple bond and it also has a lone pair of electrons. Hence, the hybridization of nitrogen atom is also sp.
Thus, we can conclude that s and p type of orbitals overlap to form the sigma bond between C and N in H−C≡N:
Explanation:
28
If it takes 1,697 m to stop a car initially moving at 46 m/s, what distance is required to stop a car moving at a quarter
of the initial speed under the same conditions?
Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
How to find velocity from acceleration time graph.
Answer:
We can only find the change in velocity by the area under the acceleration time graph by calculating the area under the curve to the given time. Then by the formula of the difference in the final and initial velocity you can find the final velocity of the object in the given time period.
Every atom contains a
.............. which is positively charged
Answer:
Proton
Explanation:
The nucleus has an overall positive charge as it contains the protons. Every atom has no overall charge (neutral). This is because they contain equal numbers of positive protons and negative electrons.
What is the acceleration as an object goes from +20 m/s to +26 m/s over 1.4 s?
Answer:
4.3 m/s^2
Explanation:
a = vf - vi / t
26 - 20 / 1.4
= 4.28 ( round your numbers)
A narrow slit is illuminated with sodium yellow light of wavelength 598 nm. If the central maximum extends to latex: \pm30^\circ± 30 â, how wide is the slit?.
Answer:
because of the gravity of the earth
PLEASE HELP!!!!!
How does the law of conservation of energy apply to an object rolling down different surfaces?
Answer:
it states that energy can either be gained or lost but it only changes its form.
Explanation:
for example:as a ball is still on the table it posses a potential energy of 100j and a k.e of 0j,as it falls it gains k.e so the midpoint the p.e is equal to the k.e (50j equally) as it approches the ground it completely gains k.e (100j) and the p.e is 0j.
total energy is 100j so it has been converted from p.e to k.e.
hope u have understood.
How to find average velocity on a graph.
Answer:
Answer is below….
Explanation:
The velocity is represented by the slope of a position-time graph. The faster the motion changes, the steeper the slope. The change in position divided by the corresponding change in time may be used to compute average velocity from a position-time graph.
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(hope this helps can I pls have brainlist (crown)☺️
Dave and Alex push on opposite ends of a car that has a mass of 875 kg. Dave pushes the car to the right with a force of 250 N, and Alex pushes to the
left with a force of 315 N. Assume there is no friction.
What is the net force on the car in the x-direction? Help meee please
The net force acting on the car is 65 N to the left
The net force acting on an object is simply defined as the resultant force acting on the object.
From the question given, we obtained the following data:
Force applied to the right (Fᵣ) = 250 NForce applied to the left (Fₗ) = 315 NNet force (Fₙ) =?The net force acting on the car can be obtained as follow:
Fₙ = Fₗ – Fᵣ
Fₙ = 315 – 250
Fₙ = 65 N to the leftTherefore, the net force acting on the car is 65 N to the left
Learn more on net force: https://brainly.com/question/19549734
Since there is no friction, the net force on the car in the x - direction will be 65 Newtons
Given that Dave and Alex push on opposite ends of a car that has a mass of 875 kg.
Dave pushes the car to the right with a force of 250 N, which is positive direction and Alex pushes to the left with a force of 315 N which is negative direction. Since there is no friction, only the horizontal forces will be considered.
To calculate the net force on the car in the x-direction, we will find the difference between the two forces because of their directions are opposite to each other.
Net force = 315 - 250
Net force = 65 Newtons
Therefore, the net force on the car in the x - direction will be 65 Newtons
Learn more about resolution of forces here: https://brainly.com/question/11556949
What factors determine climate?
Answer:
here
Explanation:
Climate is determined by the temperature and precipitation characteristics of a region over time. The temperature characteristics of a region are influenced by natural factors such as latitude, elevation and the presence of ocean currents.
A bullet of mass 6.00 gg is fired horizontally into a wooden block of mass 1.20 kgkg resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.190. The bullet remains embedded in the block, which is observed to slide a distance 0.270 mm along the surface before stopping.
(a) What was teh initial speed of the bullet?(b) What kind of collision took place between the bullet and the block? Explain your answer comparing the values of the kinetic energy before and after the collision.(c) Calculate the impulse of the block from the moment just after the impact to his final position. Analyze the result.
Answer:
A 5.00-g bullet is fired horizontally into a 1.20-kg wooden block resting on a horizontal surface. The coefficient of kinetic friction between block and surface is 0.20. The bullet remains embedded in the block, which is observed to slide 0.230 m along the surface before stopping.
Explanation:
if a car travels around a circular track with a radius of 100 m once every 10s what will its average angular velocity around the track be?
Answer:
0.628 radians per second
Explanation:
Angular velocity
= 2pi/T
= 2(3.14159)/10
= 0.628 radians per second
The average angular velocity around the track is 62.8 m/s, using the circumference of the track as the total distance.
Average angular velocity:What information do we have?
Radius of track = 100 m
Time taken = 10s
Circumference of track = 2πr
Circumference of track = 2(3.14)(100)
Circumference of track = (2)(314)
Circumference of track = 628 m
Average angular velocity around the track = Circumference of track / Time taken
Average angular velocity around the track = 628 / 10
Average angular velocity around the track = 62.8 m/s
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If you drag a 50kg block across the floor which has a coefficient of friction of .30, what is
the force needed to accelerated it at 2.0m/s^2 ?
Answer:
750 Newton
Explanation:
force=mass(acceleration)
Evidence of liquid water in mars' distant past suggests that it had a substantial atmosphere compared to what it has presently. What happened to its water vapor?.
Answer:
The atmosphere has frozen out into the polar ice caps and permafrost as Mars has cooled.
Explanation: Good luck box BrokenTag27
two objects are sitting 6m apart, one object has a mass of 100kg and the other has a mass of 200kg. what is the gravitational attraction between them
Which type of electromagnetic radiation is commonly used for long-distance communications?
A. infrared radiation
B. radio waves
C. ultraviolet radiation
D. gamma rays
Answer:
B. Radio waves
Explanation:
Radio waves are transmitted easily through air. They do not cause damage if absorbed by the human body, and they can be reflected to change their direction. These properties make them ideal for communications.
Hope this helps!!
Answer:
B
Explanation:
Radio Waves
What is carbon dating?
Answer:
Im pretty sure its number 2
Explanation:
The first one a scientific way of finding the age of something that is very old (such as a dinosaur bone) by measuring the amount of certain forms of carbon in it
find the impulse of a 20.0 KG object accelerates to8.1 M/S from 2.3 M/S
Answer:
116 N•s
Explanation:
change in momentum = mvf-mvi
= m(Vf - Vi)
= 20( 8.1-2.3)
change in momentum= 116 kg•m/s
: .impulse is 116 N•s
A guitar string has a fundamental frequency f. The tension in the string is increased by 1.70%. Ignoring the very small stretch of the string. How does the fundamental frequency change?
The characteristics of the speed of the waves in strings and the resonance allows to find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀
The speed of the chord wave is given by the relationship between the tension and the density of the medium.
[tex]v= \sqrt{\frac{T}{\mu } }[/tex]
Where v is the velocity of the wave, T the tension of the string and μ the density
In a rope held at the ends, a process of standing waves occurs, two at the point where it is attached we have a node and a anti-node in the center.
2L = n λ
Where L is the length of the chord and call the wavelength
Wave speeds are related to wavelength and frequency.
v = λ f
We substitute.
[tex]\sqrt{\frac{T}{\mu } } = \frac{2L}{n} \ \ f[/tex]
For the fundamental frequency n = 1
f₀ = [tex]f_o = \sqrt{\frac{T}{\mu } } \ \ \frac{1}{2L}[/tex]
They indicate that the tension increases 1.70%
T = T₀ + 0.17 T₀
T = 1.17 T₀
We substitute.
[tex]f = \sqrt{1.17 } \ \sqrt{\frac{T_o}{\mu } } \ \ \frac{1}{2L}[/tex]
f = ra1.17 f₀
f = 1.08 f₀
In conclusion, using the characteristics of the velocity of the waves in strings and the resonance we can find the change in the fundamental frequency when changing the tension is:
The change in fundamental frequency is: f = 1.08 f₀Learn more about string resonance here: brainly.com/question/16010929
Why does the blue force have a negative sign?
-20 N
50 N
Because 50 is smaller than 20
Because 20 is smaller than 50
Because it is pointing to the left
Because it is blue
HELP PLEASE : )
IT'S SCIENCE
Answer:
1. A and C are balanced forces as all the forces get cancelled by the opposite and equal force.
2. B and D as in B the Net force is 5N to the right and in D the Net force is 20N to the right.
3. This would be all the unbalance forces which are B and D
4. B would be moving 5N to the right and D would move 20N to the right.
what are the slight fluctuations seen in maps of the cosmic background radiation?
The beginning of the formation of galaxies and clusters of galaxies are the slight fluctuations seen in maps of the cosmic background radiation. So, the correct option is C.
What is Cosmic background radiation?The cosmic background radiation is defined as the microwave radiation that fills all of space which is a remnant that provides an important source of data on the early universe. With a standard optical telescope, the background space between stars and galaxies is almost completely dark.
It is also called the Cosmic Microwave Background (CMB) or electromagnetic radiation filling the universe which is a residual effect of the Big Bang that happened 13.8 billion years ago. The beginning of the formation of galaxies and clusters of galaxies are the slight fluctuations seen in maps of the cosmic background radiation.
Therefore, the correct option is C.
Learn more about Cosmic Background radiation, here:
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Your question is incomplete, most probably the complete question is:
What are the slight fluctuations seen in maps of the cosmic background radiation?
a. uncertainties in the map
b. variations in the instrument's sensitivity
c. the beginning of the formation of galaxies and clusters of galaxies
d. dark matter
e. none of the above
please help me solve all of them ( a, b, c and d ) thankiew !!
I’m also kind of in a rush
Answer:
a-
V= IR
9V = I ×( 12+6)
I = 9/ 18 A = 0.5 A
b
V=IR
240 = 6 A ×( 20 + R)
40 = 20 + R
R = 20 ohm
c
resultant resistance of the 2 parallel resistances= Ro
1/Ro = 1/ 5 + 1/ 20
1/Ro =( 20+5)/100
= 1/Ro = 1/4
Ro= 4 ohm
V=IR
V = 2A × ( 1+ 4 OHM)
V = 10V
d
equivalent resistance = Ro
1/Ro = 1/(2+8) + 1/(5+5)
1/Ro = 1/10 +1/10
2/10 = 1/ Ro
Ro= 10/2 = 5 ohm
V = IR
12V = I × 5Ohm
I=2.4 A
Why are saturn's rings so noticeable?.
Answer:
Why are Saturn's rings so noticeable? They are made of lots of fresh, bright icy particles from a recent breakup.
Explanation:
How does water temperature affect density?
¿Cuál es la densidad de un metal si una muestra tiene una masa de 63.5 g cuando se mide en el aire y una masa aparente de 55.4 g cuando está sumergida en agua?. Considere la densidad del agua como 1000 kg/m3.
La densidad del metal como se requiere en la pregunta es 7.8 * 10 ^ 3 Kg / m ^ 3.
Sabemos que ese empuje hacia arriba = peso en aire - peso en líquido
Peso en el aire = 63,5 * 10 ^ -3 Kg * 10 m / s ^ 2 = 0,635 N
Peso en líquido = 55,4 * 10 ^ -3 Kg * 10m / s ^ 2 = 0,554 N
Empuje hacia arriba = 0,635 N - 0,554 N = 0,081 N
Pero ;
Empuje hacia arriba = Volumen * densidad del fluido * aceleración debido a la gratitud
volumen = empuje hacia arriba / densidad del fluido * aceleración debido a la gratitud
volumen = 0.081 N / 1000 * 10
Volumen = 8.1 * 10 ^ -6 m ^ 3
Densidad = masa / volumen
Densidad = 63,5 * 10 ^ -3 Kg / 8,1 * 10 ^ -6 m ^ 3
= 7,8 * 10 ^ 3 kg / m ^ 3
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explain the production of current with the help of a magnet and describe which device works on this phenomena
Answer:
Explanation:
The properties of magnets are used to make electricity. Moving magnetic fields pull and push electrons. ... Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current.
what is radiation?....
Answer:
the emission of energy as electromagnetic waves or as moving subatomic particles, especially high-energy particles which cause ionization.
is called radiation
Answer:
Radiation is energy that comes from a source and travels through space at the speed of lightExplanation:
I hope it's help u
light of wavelength 520 nm falls on a slit that is 3.20 um wide. Estimate how far the first bright-sh difrrection fringe is
Answer:
because of the gravity of the earth
How does the diameter of a black hole (size of the event horizon) depend on the mass inside the black hole
Answer:
The greater the mass, the greater is the diameter
Explanation:
The greater the mass, the greater is the diameter. almost all galaxies contain supermassive black holes.
pease HELP Me out with this science problem no point of answering a fake question cause it will be deleted and brainly will give you a BANN WARNING!!
Answer: Increasing the amount of sugar.
Explanation: Increasing the amount of reactants increases the rate of the reaction. This is given by the collision theory, which states that a chemical reaction must involve the collisions of particles together, as well as with the walls of the container it is in. By increasing the amount of reactant in the container you are increasing the collision frequency, and the rate of the reaction is dependant on the collision frequency multiplied by the fraction of collisions that are effective. Increasing the temperature increases the collision frequency as well as the fractions of collisions that are effective, so it’s definitely not that one. Hope this helped:)