Answer:
if these gases existed in Titan, this n in solid form, by which its absence in the atmosphere is understood.
Explanation:
Each gas and chemical compound has a defined temperature for changes of state, specifically for the change from gaseous to liquid and from liquid to solid state we have
gas gas → liquid liquid → solid
(ºC) (ºC)
H₂0 (Water) 100 0
CO₂ -56.6 (P> = 5.2 bar) <-56.6
The temperature of the Titan satellite is - 180ºC
From the above, if these gases existed in Titan, this n in solid form, by which its absence in the atmosphere is understood.
A stone is dripped into the well 44 meter dip the spalash in heard in 3.12 s find speed of sound in air.
Answer:
The speed of sound is 366.67 m/s.
Explanation:
height, h = 44 m
total time, T = 3.12 s
Let the time taken by the stone to hit the water is t.
use second equation of motion
[tex]h = u t + 0.5 gt^2\\\\44 = 0.5\times 9.8 t^2\\\\t = 3 s[/tex]
Time taken by sound to g up
t'=T - t = 3.12- 3 = 0.12 s
The speed of sound is
[tex]v = \frac{h}{t'}\\\\v = \frac{44}{0.12}\\\\v = 366.7 m/s[/tex]
What is matter made of.
Answer:
Matter is made up of atoms
Answer:
Mater is made up of atoms.
Explanation:
Atoms come together to form molecules,which are the building blocks for all types of matter.
Clothes are flung to the sides of a round tub during the spin-cycle of a washing machine.If the tub's period of rotation is 0.2s and the tub's radius is 35cm,answer the related qestions below: (a)The frequency of roation (b)The circumference of rotation (c)The spinning of speed (d)The centripetal acceleration (e)The centripetal force of rotation if total mass rotated is 30kg (f)The power of washing machine
Answer:
Explanation:
First I need to tell you that I used .20 s for the period of rotation instead of just .2, and I used 30.0 kg for the mass instead of just 30. The reason being that both those numbers as stated in the problem only have 1 significant digit and that's not generally enough to get the accuracy you're looking for. Adding a 0 to the ends of each of those numbers doesn't change the value of the numbers, only the number of sig fig's in each. Beginning with a:
a. [tex]f=\frac{1}{T}[/tex] so [tex]f=\frac{1}{.2}[/tex] and f = 5.0 Hz
b. The circumference is the distance around the outside of the washer's drum. We need to find that, but before we do, I'm going to state the radius in meters instead of cm. 35 cm = .35 m. Therefore,
C = 2(3.1415)(.35) so
C = d = 2.2 m
c. The speed of the washer is found in d = rt, where r is the rate and our velocity and d is the distance around the outside of the drum (circumference). Therefore,
2.2 = v(.20) so
v = 11 m/s
d. The centripetal acceleration has an equation
[tex]a_c=\frac{v^2}{r}[/tex] so
[tex]a_c=\frac{(11)^2}{.35}[/tex] and
[tex]a_c=\frac{121}{.35}[/tex] so
[tex]a_c=350\frac{m}{s^2}[/tex]
e. The centripetal force has an equation
[tex]F_c=\frac{mv^2}{r}[/tex] and
[tex]F_c=\frac{(30.0)(11)^2}{.35}[/tex] and
[tex]F_c=[/tex] 1.0 × 10⁴ N
f. The equation for Power is
[tex]P=\frac{W}{t}[/tex] where W is work and W = FΔx (force times displacement). Therefore,
[tex]P=\frac{(1.0*10^4)(2.2)}{.20}[/tex] so
P = 1.1 × 10⁵ Watts
Please help me. Please help me.
Answer:
Make a nice powerpoint and think about the question
Explanation:
Its easier than you think :)
3.00 m^3 of water is at 20.0°C.
If you raise its temperature to
60.0°C, by how much will its
volume expand?
Water
ß = 207•10-6C-1
(Unit = m^3)
Answer:
9m^3
Explanation:
Given data
volume v1= 3m^3
volume v2= ???
Temperature T1= 20.0°C.
Temperature T2= 60.0°C.
Applying the relation for temperature and volume
V1/T1= V2/T2
substitute
3/20= V2/60
3*60= V2*20
180= 20*V2
180/20= V2
V2= 9m^3
Hence the final volume is 9m^3
According to Coulomb’s Law, what happens to the force when the distance increase between 2 particles?
Answer:
The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.
Explanation:
Coulomb’s law, mathematical description of the electric force between charged objects. Formulated by the 18th-century French physicist Charles-Augustin de Coulomb, it is analogous to Isaac Newton’s law of gravity.
Both gravitational and electric forces decrease with the square of the distance between the objects, and both forces act along a line between them. In Coulomb’s law, however, the magnitude and sign of the electric force are determined by the electric charge, rather than the mass, of an object. Thus, charge determines how electromagnetism influences the motion of charged objects. Charge is a basic property of matter. Every constituent of matter has an electric charge with a value that can be positive, negative, or zero.
Coulomb's Law says that the force between 2 charges is proportional to the product of the quantities of charge on each and inversely proportional to the square of the distance between them. The formula for Coulomb's Law is [tex]F=k\frac{q_{1}q_{2} }{r^{2} }[/tex].
[tex]F[/tex] is the force.
[tex]k[/tex] is the Coulomb's constant ([tex]8.987*10^{9} \frac{Nm^{2} }{C^{2} }[/tex]).
[tex]q_{1}[/tex] is the electric charge of object 1.
[tex]q_{2}[/tex] is the electric charge of object 2.
[tex]r[/tex] is the distance between the two charges.
Electric force is inversely proportional to ([tex]r^{2}[/tex]) instead of ([tex]r[/tex]). As the distance between charges increases, the electric force decreases by a factor of [tex]\frac{1}{r^{2} }[/tex].
An object is moving with an initial velocity of 9 m/s. It accelerates at a rate of 1.5 m/s2
over a time of 20 s. What is its new velocity?
Answer:
39 m/s²
Explanation:
initial Velocity (u) = 9m/s
acceleration (a) = 1.5m/s²
time(t) = 20s
V=u + at
V=9 + 1.5(20)
V=9 + 30
V=39m/s
If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate its acceleration.
Answer:
5m/s²
Explanation:
Initial Velocity= 40m/s
Final Velocity=60m/s
Time = 4s
a=(v-u)/t
a=60-40/4
a=20/4
a=5m/s²
12.
A solar heater uses energy from the Sun to heat water. The panels of the heater are painted black.
Why is this?
Answer:
Solar water heaters are devices that use energy from the sun to heat water. ... This metal surface, placed in contact with the water, will heat the water. Black-painted surfaces that receive the sun's heat become hotter than surfaces of any other color. The black metal plate is called a collector.
A ball of mass 0.175 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.805 m. What impulse was given to the ball by the floor
Answer:
The impulse received by the ball is - 1.561 kg.m/s
Explanation:
Given;
mass of the ball, m = 0.175 kg
initial displacement of the ball, h₁ = 1.25 m
final displacement of the ball, h₂ = 0.805 m
Assumptions:
let the downward direction of the ball be positive
let the upward direction of the ball be negative
The following equation of motion will be used to determine the final velocity of the ball at each displacement.
v² = u² ± 2gh
The final velocity of the ball when it is dropped downwards to 1.25 m;
v² = u² + 2gh
v² = 0 + 2gh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 1.25)
v = 4.95 m/s
The final velocity of the ball when it rebounds from the floor to 0.805 m;
vf² = u² - 2gh
vf² = 0² - 2gh
vf² = -2gh
vf = -√2gh
vf = - √(2 x 9.8 x 0.805)
vf = -3.97 m/s
The impulse received by the ball is calculated as;
J = ΔP = mΔv = m(vf - v)
= 0.175(-3.97 - 4.95)
= - 1.561 kg.m/s
The negative sign indicates upward direction of the impulse.
Una grúa eleva un tubo de concreto de
400 kg, con Movimiento rectilíneo uniforme,
con el
cable ABC. Determine la tensión que pueden
soportar los cables AB, BC y BD, sabiendo
que los cables AB=BC y la tensión que
soporta el cable AB es de 150 N.
Explanation:
Hydraulic Pressure-Control, On-Off Deluge Valve
FP-400Y-5DC
The BERMAD model 400Y-5DC is an elastomeric, hydraulic line pressure operated deluge valve, designed specifically for advanced fire protection systems and the latest industry standards. The 400Y-5DC is activated by a hydraulically operated relay valve, through which opening and closing of the valve can be controlled either with a remote hydraulic command or with a wet pilot line with closed fusible plugs. An integral pressure reducing pilot valve ensures a precise, stable, pre-set downstream water pressure. The optional valve position indicator can include a limit switch suitable for Fire & Gas monitoring systems. The 400Y-5DC is ideal for systems that combine a remote wet pilot line with a high pressure water supply.
A sample from of water is heated with 5000 J of energy and its temperature goes up by 6 K. What is the mass of the sample?
Answer:
mass= 0.1993 kg
Explanation:
Using the formula c = Q / (mΔT)
State Newton’s second law of motion. Derive this law mathematically. A 1000 kg vehicle moving with a speed of 20m/s is brought to rest in a distance of 50 metres. Find the acceleration and calculate the force acting on the vehicle.
Answer:
-4000 N
Explanation:
newton second law F=ma
m=1000kg
vi=20m/s
vf=0
d=50 m
vf^2=vi^2+2ad
0=20^2+2a×50
100 a= -400
a= -4 m/S2
F=ma = 1000×-4 = -4000 N
at which point is the Kinetic energy the lowest?
Answer:
the lowest kinetic energy point is option D
A steer must eat at least 100 pounds of grain to gain less than 10 pounds of muscle tissue. This illustrates Group of answer choices the second law of thermodynamics. that some energy is destroyed in every energy conversion. the first law of thermodynamics. that energy transformations are typically 100% efficient.
Answer:
the second law of thermodynamics. that some energy is destroyed in every energy conversion.
Explanation:
According to the second law of thermodynamics, energy conversion is never 100% efficient. Some energy is always lost as it is being converted from one form to the other.
The fact that a steer must eat at least 100 pounds of grain to gain less than 10 pounds of muscle tissue shows that not all the energy taken up from the grain is channelled towards building the muscle tissue. Some energy from the grains are lost on the way according to the second law of thermodynamics.
A box slides down a 28.0 degree ramp with an acceleration of 1.25 m/s2. Determine the coefficient of kinetic friction between
Answer:
[tex]\mu=0.39[/tex]
Explanation:
From the question we are told that:
Angle [tex]\theta=28[/tex]
Acceleration [tex]a=1.25m/s^2[/tex]
Generally the equation for Frictional force is mathematically given by
[tex]F=\muN[/tex]
Where
[tex]N=mgcos \theta[/tex]
[tex]N=mgcos 28[/tex]
Since
Friction force is acting against move of box
Therefore
[tex]mgsin(28) - 1.25m = \mu mgcos(28)[/tex]
[tex]\mu=\frac{gsin(28) - 1.25}{gcos(28)}[/tex]
[tex]\mu=0.39[/tex]
A 6 m/s vector pointing North is added to a 2 m/s vector pointing East. What are the magnitude and direction of the resultant?
Answer:
A + B = C Ax = 2 Ay = 0 Bx = 0 By = 6
Ax + Bx = Cx = 2
Ay + By = Cy = 6
C = (2^2 + 6^2)^1/2 = 6.32
Tan Cy / Cx = 6 / 2 = 3
Cy at 71.6 deg
How do space probes make it past the asteroid belt without crashing into asteroids?
Answer:
The thing is space is really vast like really big so even though the asteroid belt looks really cramped it isn't. There's a lot of space between asteriods and using simple navigation and maneuvering, space probes can easily make it through without the threat of crashing.
Explanation:
How are molecules composed of atoms held together?
through gravity
through friction
through chemical bonding
through hydrogen bonding
Answer:
Chemical Bonding
Explanation:
When should a line graph be used?
define regular body in science
Answer:
All the sides and inner angles of a regular form must be equal. The sides and angles of an irregular form aren't the same. An equilateral triangle, for example, is a regular form because all of its sides and angles are the same length.
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A car travelling an unbanked curve of radius 200 ft notices a truckstopped on the road ahead. The driverimmediately applies brakes causing the speed of the carto decrease at the rate of 10 ft/s2. If at that instant, the stationary truckis 100 ft ahead (the distance is measured along the path) and the car is travelling at a speed of 40ft/s, whatis the magnitude of the relative velocity ofthe truck perceived by the driver of the car (i.e. from the moving frame of referenceof the car).
Answer:
u = - 40 ft / s
Explanation:
The Galilean relation for the relative velocity is
v ’= v + u
where u is the speed between the two reference frames, v is the speed of the fixed system and v 'the speed of the mobile system.
In this case the truck has a speed with respect to the ground (fixed system) 0 m / s (it is stopped), the car has a speed with respect to the ground of v = 40 ft / s,
u = v'- v
u = 0 - 40
u = - 40 ft / s
the speed perceived by the car if the system is fixed on it is -40 ft / s
4. Thousands of which solar system bodies orbit the sun between Mars and Jupiter?
Asteroids
Comets
Meteorites
Meteors
help
Answer:
asteroids
Explanation:
There is an asteroid belt between Mars and Jupiter
Na + Cl2 → 2NaCl
The equation is
because the number of
atoms is
on both sides of the arrow.
Answer:
what do u want to ask ????
TRUE OR FALSE. if an object covers equal distance at equal intervals of time, then it is moving at constant speed and not accelerating
Answer:
True
Explanation:
Speed = distance/time
If distance and time are the same, then the right hand side of the equation remains the same, causing us to solve the left to the same value
As the distance is the same (say 50m) and the time is the same (say 50s) then the speed must be the same (1m/s)
your initial speed is zero. if you increased your speed by 4 m/s after only 2 seconds and continue to accelerate at the same rate, what will your speed be after 10 seconds?
Answer:
20 m/ s
Explanation:
change in velocity = 4m/ s
[tex]acceleration = \frac{rate \: of \: change \: of \: velocity}{time} [/tex]
[tex]acc = \frac{4}{2} \\ = 2[/tex]
initial velocity = 0m/ s
let velocity after 10s be v[tex]2 = \frac{v - 0}{10} [/tex]
cross multiplying
[tex]20 = v[/tex]
so the velocity after 10s will be 20m/s
Your mass is 80 kg on Earth. What would your MASS
be on Planet Roethler, which has twice as much
gravity as on Earth?
40 kg
160 kg
80 kg
Mass doesn't change. It doesn't matter where you are.
If your mass is 80 kg when you're on Earth, then your mass is 80 kg. It doesn't matter where you are, where you used to be, or where you're going tomorrow.
An acceleration of 2m/s^2 is produced on a body by applying an effort of 50N. calculate mass of the body
Answer:
25 kg
Explanation:
Given,
Acceleration ( a ) = 2 m/s^2
Force ( F ) = 50 N
To find : Mass ( m ) = ?
Formula : -
F = ma
m = F / a
= 50 / 2
m = 25 kg
So, the mass of the body is 25 kg.
While visiting the beach, you enjoy the warm ocean water, but the sand burns your feet. That night you walk along the beach and notice that the sand is colder than the ocean water. Why?
Group of answer choices
It takes a long time for sand to heat up, but it cools down very quickly. Water takes a short time to heat up and cool down.
Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.
Water is naturally colder than sand.
Sand is naturally colder than water.
The answer would be B..
Since sand can heat up quickly, it will also cool off quickly. But water takes a long time to heat up and cool down.
Priya is responsible for collecting canned food along three different streets for her school's annual Thanksgiving Food Drive. She walks 300 m [N] along Oak Road, 500 m [E] along Second Street, and then 150 m [S45°W] along Cross Ave. She completes the journey in 10 minutes.Calculate her total distance, displacement, speed, and velocity.
As per the details given, Priya's total distance traveled is 950 meters, displacement is approximately 410.52, speed is 95 meters per minute, and velocity is 41.05 meters per minute.
To calculate Priya's total distance:
Total distance = 300 m + 500 m + 150 m = 950 m
So, Priya's total distance traveled is 950 meters.
To calculate Priya's displacement, we need to find the straight-line distance and direction from her starting point to her ending point.
Displacement = √((Δx)² + (Δy)²)
For Δx:
Δx = 500 m - 150 m × cos(45°)
Δx = 500 m - 150 m × 0.707
Δx = 500 m - 106.05 m
Δx = 393.95 m
For Δy:
Δy = 150 m × sin(45°)
Δy = 150 m × 0.707
Δy = 106.05 m
Displacement = √((393.95 m)² + (106.05 m)²)
Displacement ≈ 410.52 m
So, Priya's displacement is approximately 410.52 meters in a direction of approximately N36°W.
To calculate Priya's speed, we use the formula:
Speed = Total distance ÷ Time
Speed = 950 m ÷ 10 min
Speed = 95 m/min
So, Priya's speed is 95 meters per minute.
To calculate Priya's velocity:
Velocity = Displacement ÷ Time
Velocity = 410.52 m ÷ 10 min
Velocity = 41.05 m/min
Thus, Priya's velocity is 41.05 meters per minute in a direction of N36°W.
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