Answer:
The length and width of the parking lot are [tex]\frac{46}{3}[/tex] meters and [tex]\frac{23}{2}[/tex] meters, respectively.
Step-by-step explanation:
The surface formula ([tex]A[/tex]) for the rectangular parking lot is represented by:
[tex]A = w\cdot l[/tex]
Where:
[tex]w[/tex] - Width of the rectangle, measured in meters.
[tex]l[/tex] - Length of the rectangle, measured in meters.
Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If [tex]A = 6\cdot x^{2}-19\cdot x -7[/tex], the factorized form is:
[tex]A = \left(x-\frac{7}{2}\,m \right)\cdot \left(x+\frac{1}{3}\,m \right)[/tex]
Now, let consider that [tex]w = \left(x-\frac{7}{2}\,m \right)[/tex] and [tex]l = \left(x+\frac{1}{3}\,m \right)[/tex], if [tex]x = 15\,m[/tex], the length and width of the parking lot are, respectively:
[tex]w =\left(15\,m-\frac{7}{2}\,m \right)[/tex]
[tex]w = \frac{23}{2}\,m[/tex]
[tex]l =\left(15\,m+\frac{1}{3}\,m \right)[/tex]
[tex]l = \frac{46}{3}\,m[/tex]
The length and width of the parking lot are [tex]\frac{46}{3}[/tex] meters and [tex]\frac{23}{2}[/tex] meters, respectively.
The within-subjects F is the non-independent groups equivalent of the one-way ANOVA. True or False?
Answer: True.
Step-by-step explanation:
The one-way analysis of variance usually (abbreviated as one-way ANOVA). is a method that is used to compare the means of two or more samples ( by make use of the F distribution). This method only applies to numerical response data, the "Y", usually one variable, and numerical or (usually) categorical input data, the "X", always one variable, hence the reason it’s know as "one-way" beca it takes it account one variae at a time.
Translate into an equation: y is 37% of x.
Answer:
soln,
y=37/100×x
or, 100y=37x.....is the answer
An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
The equation of y is 37% of x is
y = 0.37x
What is an expression?An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.
Example:
2 + 3x + 4y = 7 is an expression.
2 + 3 - 4 is an expression.
2x4 + 4x = 4 is an expression.
We have,
y is 37% of x.
This can be written as,
y = 37/100 of x
y = 0.37x
Thus,
The equation of y is 37% of x is
y = 0.37x
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True or false: If you re-word what an author says in your own work, you do not have to provide a citation. * 1 point True False
Answer:
False
Step-by-step explanation:
In an essay, you have to cite every source you use because
a) the teacher needs to KNOW you didn't copy
b) the teacher needs to know if you got your info from a reliable source
c) the teacher needs to see your ability to use info from a source to put into your essay
This may be different for books, but citation is always a rule of thumb for essays in school, so don't forget unless you want points to be taken off of your score.
Let F(x, y, z) = 3xi+ 2yj and let σ be the cube with opposite corners at (0, 0, 0) and (5, 5, 5), oriented outwards. Find the flux of the flow field F across σ.
Use the divergence theorem,
[tex]\displaystyle\iint_{\partial\sigma}\mathbf F(x,y,z)\cdot\mathrm d\mathbf S=\iiint_\sigma\mathrm{div}\mathbf F(x,y,z)\,\mathrm dV[/tex]
We have
[tex]\mathrm{div}\mathbf F(x,y,z)=\dfrac{\partial(3x)}{\partial x}+\dfrac{\partial(2y)}{\partial y}+\dfrac{\partial0}{\partial z}=5[/tex]
so that the flux across [tex]\sigma[/tex] is equal to 5 times the volume of the cube. The cube itself has edge length 5, so its volume is [tex]5^3=125[/tex], making the flux [tex]5^4=\boxed{625}[/tex].
The advertised weight of a Snickers Fun Size bar is 17 grams. What proportion of candy bars in this sample weigh less than advertised
Answer:
0.412
Step-by-step explanation:
Given the stem plot figure out which ones are below 17g.
So: 7g / 17g = 0.412 which is the proportion
Algebraic expressions
Evaluate
The dog is 4 years older than the cat. The cat is 7 years old. How old is the dog?
Answer:
11 years old
Step-by-step explanation:
Because the dog is 4 years older, add 7+4
I need help with this
Answer:
x = 16
Step-by-step explanation:
Step 1: We know DF - DE = EF
9x - 39 - 47 = EF
Step 2: Simplify
9x - 86 = EF
Step 3: Set the equation equal to 3x + 10
9x - 86 = 3x + 10
6x = 96
x = 16
Therefore x is equal to 16
Answer:
58
Step-by-step explanation:
DE + EF = DF
47+ 3x+10 = 9x-39
Combine like terms
57 +3x = 9x-39
Subtract 3x from each side
57+3x-3x = 9x-3x-39
57 = 6x-39
Add 39 to each side
57+39 = 6x-39+39
96 = 6x
Divide by 6
96/6 = 6x/6
16 =x
We want the length of EF
EF = 3x+10
= 3*16 +10
= 48+10
= 58
Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x/6x^2 + 1 f(x) = sigma^infinity_n = 0 (-1)^n x^2n+1 6^n Determine the interval of convergence. (Enter your answer using interval notation.)
Looks like your function is
[tex]f(x)=\dfrac x{6x^2+1}[/tex]
Rewrite it as
[tex]f(x)=\dfrac x{1-(-6x^2)}[/tex]
Recall that for [tex]|x|<1[/tex], we have
[tex]\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n[/tex]
If we replace [tex]x[/tex] with [tex]-6x^2[/tex], we get
[tex]f(x)=\displaystyle x\sum_{n=0}^\infty\frac(-6x^2)^n=\sum_{n=0}^\infty (-6)^n x^{2n+1}[/tex]
By the ratio test, the series converges if
[tex]\displaystyle\lim_{n\to\infty}\left|\frac{(-6)^{n+1} x^{2(n+1)+1}}{(-6)^n x^{2n+1}}\right|=6|x^2|\lim_{n\to\infty}1=6|x|^2<1[/tex]
Solving for [tex]x[/tex] gives the interval of convergence,
[tex]|x|^2<\dfrac16\implies|x|<\dfrac1{\sqrt6}\implies -\dfrac1{\sqrt 6}<x<\dfrac1{\sqrt 6}[/tex]
We can confirm that the interval is open by checking for convergence at the endpoints; we'd find that the resulting series diverge.
The interval of the convergence is (-1/√6 < x < 1/√6). We can confirm that the interval is open by checking for convergence at the endpoints.
What is a function?The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.
The given function is
[tex]\rm f(x) = \dfrac{x}{6x^2 + 1} \\\\or \\\\f(x) = \dfrac{x}{1 - (-6x^2)}[/tex]
For |x| < 1, we have
[tex]\rm \dfrac{1}{1-x} = \Sigma_{n=0}^{\infty} \ x^n[/tex]
If x is replaced with -6x², then we have
[tex]\rm f(x)= \Sigma_{n=0}^{\infty} (-6x^2 )^n = \Sigma_{n=0}^{\infty} (-6)^n x^{2n+1}[/tex]
Then by the ratio test, the series converges if
[tex]\displaystyle \lim_{n \to \infty} \left| \dfrac{(-6)^{n+1}x^{2(n+1)+1}}{(-6)^{n}x^{2n+1}} \right|=6|x^{2}| \displaystyle \lim_{n \to \infty }1=6|x^{2}| < 1[/tex]
Solving for x, the interval of convergence will be
[tex]|x^2| < \dfrac{1}{6} \\\\|x| < \dfrac{1}{\sqrt6} \\\\-\dfrac{1}{\sqrt6} < x < \dfrac{1}{\sqrt6}[/tex]
We can confirm that the interval is open by checking for convergence at the endpoints.
More about the function link is given below.
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Simplify 3x + 3 + 2.
3x + 5
5x + 3
8x
Answer:
3x + 5
Step-by-step explanation:
We are doing variables and simplifying.
You have two types of numbers here, you have a coefficient, and you have regular numbers. Now do keep in mind that you can never add a regular number to a coefficient. So the only thing in this problem you will add is 3 and 2. Because 3x is different
3x + (3 + 2)
3x + 5
The simplified form of the expression is 3x + 5.
Option A is the correct answer.
We have,
Expression:
3x + 3 + 2
Add like terms.
3x + (3 + 2)
3x + 5
This is the simplest simplified form of the expression.
Thus,
The simplified form of the expression is 3x + 5.
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WY bisects UV at Y. If UV=x-7 and YV = 3x-29, find UV
Answer:
3.2 units
Step-by-step explanation:
Given that:
WY bisects UV at Y.
[tex]UV=x-7[/tex] and
[tex]YV = 3x-29[/tex],
To find: UV = ?
Solution:
First of all, let us draw the diagram of the given dimensions and bisector line WY of UV.
As UV is bisected i.e. divided in two equal parts at Y by the line WY
Therefore, UY = YV
UV = UY+YV
OR
UV = 2 YV
Now, let us put the given values to solve for [tex]x[/tex]:
[tex]x-7=2 \times (3x-29)\\\Rightarrow x-7=2 \times 3x-2 \times 29\\\Rightarrow x-7=6x-58\\\Rightarrow 6x-x=58-7\\\Rightarrow 5x=51\\\Rightarrow \bold{x =10.2 }[/tex]
Now, we are given that:
[tex]UV=x-7[/tex]
Putting value of [tex]x[/tex] as solved in above step to get the value of UV:
[tex]UV=10.2-7\\\Rightarrow \bold{UV=3.2}[/tex]
So, answer is UV = 3.2 units
PLEASE HELP ME, I DON'T UNDERSTAND THIS! :(
Hello, please consider the following.
x is obviously different from 0 and then, dividing by x is legit.
For the first 105 miles the speed is x, so the time spent is
[tex]\dfrac{105}{x}[/tex]
For the second part, the speed is 1.4 x, so the time spent is
[tex]\dfrac{105}{1.4x}=\dfrac{75}{x}[/tex]
In total, the time she spent driving is
[tex]\dfrac{105}{x}+\dfrac{75}{x}\large \boxed{=\dfrac{180}{x}}[/tex]
Thank you.
the time difference between London and New York is -5 hours. The time difference New York and San Francisco is -3 hours. If it is 11:32 in London, what is the time in San Francisco
Answer:
found this on the web. hopefully it helps
Find an equation of a line with slope -7 and y-intercept 2. y=
Answer:
y = -7x + 2
Step-by-step explanation:
Use the slope-intercept form y = mx + b.
Substitute -7 for m, 0 for x and 2 for y. Then
2 = (-7)(0) + b, so b must be 2.
The desired equation is y = -7x + 2.
What is “35 is 60% of what number?”
Answer:
58.33
Step-by-step explanation:
35 isn't exactly 60% of an number but by rounding you will get 58.33
Approximate the sum of the series by using the first six terms. (See Example 4. Round your answer to four decimal places.) [infinity] (−1)n + 1n 2n n = 1
Answer:
0.1875
Step-by-step explanation:
The well formatted expression for the series has been attached to this response.
Each term in the series is govern by the rule, Tₙ
Where
n = term position
Tₙ = [tex]\frac{(-1)^{n+1}n}{2^n}[/tex]
To get the first six terms, we substitute n = 1 through 6 into Tₙ as follows:
When n = 1, we have;
T₁ = [tex]\frac{(-1)^{1+1}(1)}{2^1} = \frac{1}{2}[/tex] = 0.50000
When n = 2, we have;
T₂ = [tex]\frac{(-1)^{2+1}(2)}{2^2} = \frac{-2}{4} = \frac{-1}{2}[/tex] = -0.50000
When n = 3, we have;
T₃ = [tex]\frac{(-1)^{3+1}(3)}{2^3} = \frac{3}{8}[/tex] = 0.37500
When n = 4, we have;
T₄ = [tex]\frac{(-1)^{4+1}(4)}{2^4} = \frac{-1}{4}[/tex] = -0.25000
When n = 5, we have;
T₅ = [tex]\frac{(-1)^{5+1}(5)}{2^5} = \frac{5}{32}[/tex] = 0.15625
When n = 6, we have;
T₆ = [tex]\frac{(-1)^{6+1}(6)}{2^6} = \frac{-6}{64} = \frac{-3}{32}[/tex] = -0.09375
Therefore, the approximate sum of the series using the sum of the first six terms is
=> T₁ + T₂ + T₃ + T₄ + T₅ + T₆
=> 0.50000 + -0.50000 + 0.37500 + -0.25000 + 0.15625 + -0.09375
=> 0.1875
What is the sum of the three solutions? (find the values for x, y, and z, then add the answers)
2x + 3y − z = 5
x − 3y + 2z = −6
3x + y − 4z = −8
Answer:
Once we got
[tex]x=-1[/tex]
[tex]y=3[/tex]
[tex]z=2[/tex]
[tex]\boxed{\text{The sum is 4}}[/tex]
Step-by-step explanation:
Given the linear system:
[tex]\begin{cases} 2x + 3y-z = 5 \\ x- 3y + 2z = -6 \\ 3x + y - 4z = -8 \end{cases}[/tex]
Let's solve it using matrices. I will use Cramer's rule
[tex]M=\left[\begin{array}{ccc}2&3&-1\\1&-3&2\\3&1&-4\end{array}\right][/tex]
Considering determinant as D.
[tex]D=\begin{vmatrix}2&3&-1\\1&-3&2\\3&1&-4\\\end{vmatrix}=40[/tex]
[tex]M_x = \left[\begin{array}{ccc}5&3&-1\\-6&-3&2\\-8&1&-4\end{array}\right] \implies D_x = \begin{vmatrix}5&3&-1\\-6&-3&2\\-8&1&-4\\\end{vmatrix}=-40[/tex]
[tex]M_y = \left[\begin{array}{ccc}2&5&-1\\1&-6&2\\3&-8&-4\end{array}\right] \implies D_y = \begin{vmatrix}2&5&-1\\1&-6&2\\3&-8&-4\\\end{vmatrix}=120[/tex]
[tex]M_z = \left[\begin{array}{ccc}2&3&5\\1&-3&-6\\3&1&-8\end{array}\right] \implies D_z= \begin{vmatrix}2&3&5\\1&-3&-6\\3&1&-8\\\end{vmatrix}=80[/tex]
So, we have
[tex]$x=\frac{D_x}{D} =\frac{-40}{40}=-1 $[/tex]
[tex]$y=\frac{D_y}{D} =\frac{120}{40}=3$[/tex]
[tex]$z=\frac{D_z}{D} =\frac{80}{40}=2 $[/tex]
Determine if the following table represents a quadratic function. X 1 2 3 4 5 Y 13 22 37 58 85
Answer:
Yes, the table represents quadratic function.
[tex]Y = 3X^2+10[/tex]
Step-by-step explanation:
Given that table of values:
[tex]\begin{center}\begin{tabular}{ c c}X & Y \\ 1 & 13 \\ 2 & 22 \\ 3 & 37 \\ 4 & 58 \\ 5 & 85 \\\end{tabular}\end{center}[/tex]
To find:
Whether the given table represents a quadratic?
Solution:
First of all, let us plot the given values on the coordinate xy plane.
Kindly refer to the attached image for the graph of given values.
The graph seems parabolic in nature which is the graph of a quadratic equation.
Now, let us try to find the equation from the given set of values from hit and trial.
Let Quadratic equation be:
[tex]y=ax^{2} +b[/tex]
If the coefficient a = 1
[tex]f(1) = 13 = 1^2+12[/tex]
[tex]f(2) = 22 = 2^2+18[/tex]
[tex]f(3) = 37= 3^2+28[/tex]
[tex]f(4) = 58 = 4^2+42[/tex]
[tex]f(5) = 85 = 5^2+60[/tex]
value of b is not same in each case.
Now, let us try coefficient a = 3
[tex]f(1) = 13 = 3 \times 1^2+10[/tex]
[tex]f(2) = 22 = 3\times 2^2+10[/tex]
[tex]f(3) = 37= 3\times 3^2+10[/tex]
[tex]f(4) = 58 = 3\times 4^2+10[/tex]
[tex]f(5) = 85 =3\times 5^2+10[/tex]
Value of b = 10
So, we can clearly say that the given table represents a quadratic equation.
and the quadratic equation is:
[tex]Y = 3X^2+10[/tex]
Please help. I’ll mark you as brainliest if correct!
Answer:
-2°F
Step-by-step explanation:
So on Sunday night, the temperature was -10°F.
And by Monday morning, the temperature has increased by 8°F.
In other words, to find the temperature on Monday morning, we just have to add 8 to -10. Therefore:
[tex](-10)+(8)=-2[/tex]
The temperature on Monday morning is -2°F
Answer:
-2 degrees F.
If you have -10, you have to add positive 10 just to get to 0.
add or subtract
7 + 3 + (-7)
Answer: 3
Step-by-step explanation: you add 7+3 which is 10 - 7 =3
Emma jogs 2 miles along the beach in 1 3 of an hour. If she travels at a constant rate, how far will she jog in an hour? 1. Use the known information to write a rate.
Answer:oufonsrgonsrgnrsosgnsogwo0on93rhskgv oaoef
Step-by-step explanation:
iaeiuaefiaef ebf efa fcade emma jog 123e oefofoinsfnfsaefosefnhsfnalnfaogh
Suppose a ball is thrown upward to a height of h0 meters. Each time the ballâ bounces, it rebounds to a fraction r of its previous height. Let hn be the height after the nth bounce and let Sn be the total distance the ball has traveled at the moment of the nth bounce. Complete parts a. and b below. h0 = 9, r = o.4Find the first four terms of the sequence (Se).
Answer:What if you were asking this question? How would you explain it to yourself?
Step-by-step explanation:
Dajia bought 5 shirts online, and in turn receives a 15% discount. She
must pay an additional 4.99 for shipping. Write an algebraic expression
to represent the total cost of the shirts with the discount, if x represents
the cost of each shirt.
Graph y=-1/3x+5. Plsss help hurry
Two example that show two positive rational number is greater then either factor True?
Answer:
true
Step-by-step explanation:
Find the values for k so that the intersection of x=2k and 3x+2y=12 lies in the first quadrant.
Answer:
Values of k can be 0, 1, or 2 such that intersection of the given lines lie in the 1st quadrant.
Step-by-step explanation:
Given two lines:
[tex]x=2k[/tex] and
[tex]3x+2y=12[/tex]
To find:
Values of 'k' such that the intersection of given two lines lie in the first quadrant.
Solution:
In 1st quadrant, the values of [tex]x[/tex] and [tex]y[/tex] both are positive.
So, let us find out intersection of the two lines.
Intersection of the two lines can be found by solving the two equations for the values of [tex]x[/tex] and [tex]y[/tex].
Given that [tex]x=2k[/tex] to be in the first quadrant, the value of k must be positive.
Let us put [tex]x=2k[/tex] in the equation [tex]3x+2y=12[/tex] to find the intersection point.
[tex]3 \times 2k + 2y=12\\\Rightarrow 6k+2y=12\\\Rightarrow 2y=12-6k\\\Rightarrow \bold{y=6-3k}[/tex]
For y to be positive:
[tex]6 - 3k \geq 0\\\Rightarrow 3k \leq 6\\\Rightarrow k \leq 2[/tex]
So, values of k can be 0, 1, or 2 such that intersection of the given lines lie in the 1st quadrant.
Find the scale ratio for the map described below 1 mm (map) = 50 km (actual) The scale ratio is 1 to ?
Answer:
1 : 50,000,000
Step-by-step explanation:
The given scale (with units) is ...
1 mm : 50 km
If we convert both units to meters, so we can give the scale as a pure number, then we have ...
10^-3 m : 5×10^4 m = 1 : 5×10^7 = 1 : 50,000,000
the question is below, 20 is not the correct answer
Answer:
20
Step-by-step explanation:
Given:
m∠JKL = 3x + 5As per the picture:
m∠JKL = m∠JKM + m∠MKL = 45 + xComparing the two equations above:
3x+5 = 45 + x3x - x = 45 - 52x = 40x = 40/2x = 20x = 20 is the correct answer for this question
Otherwise something is wrong with the question.
Simplify (1-√3) (1÷3+√3) leaving your answer in the form p+q√3
Answer:
[tex]1-\dfrac{2}{3}\sqrt{3}[/tex]
Step-by-step explanation:
Maybe you want to simplify ...
[tex](1-\sqrt{3})\dfrac{1}{3+\sqrt{3}}[/tex]
Multiply numerator and denominator by the 'conjugate' of the denominator:
[tex](1-\sqrt{3})\dfrac{1}{3+\sqrt{3}}\cdot\dfrac{3-\sqrt{3}}{3-\sqrt{3}}=\dfrac{(1-\sqrt{3})(3-\sqrt{3})}{9-3}=\dfrac{3-4\sqrt{3}+3}{6}\\\\\boxed{1-\dfrac{2}{3}\sqrt{3}}[/tex]
( 6m + 3 )( m - 2 ) A) 4m 2 - 2m - 20 B) 4m 2 - 20 C) 4m 2 + 18m + 20 D) 6m 2 - 9m - 6
Answer:
D
Step-by-step explanation:
So we have the expression:
[tex](6m+3)(m-2)[/tex]
Use the distributive property and distribute:
[tex]=(6m+3)(m)+(6m+3)(-2)[/tex]
Distribute:
[tex]=(6m^2+3m)+(-12m-6)[/tex]
Combine like terms:
[tex]=6m^2+3m-12m-6\\=6m^2-9m-6[/tex]
The correct answer is D
Edit: Typo
Conjecture: How many solutions do x3 - 5x2 + 28 = 0 have? Find the real solution(s) of the equation. Then use polynomial long division to find the other solution(s).
Answer: the real solution: x = - 2
Find the attached file for the remaining solution
Step-by-step explanation:
The equation given is:
x3 - 5x2 + 28 = 0
Let assume that -2 is one of the root of the equation. Substitute -2 for x
(-2)^3 - 5(-2)^2 + 28
-8 - 20 + 28 = 0
Therefore, -2 is one of the root of the equation since the equation tend to zero.
If x = -2, then x+2 is one of the factors of the equation. Therefore, the real solution is x = -2
Please find the attached file for the remaining solution.