the ability of organism to sense changes in its body is an example of

Answer:

9.36 g

Explanation:

The equation of the reaction is;

C8H18(g) + 25/2 O2(g) ----> 8CO2(g) + 9H2O(g)

Number of moles of octane = 10.3g/ 114 g/mol = 0.09 moles

1 mole of octane yields 9 moles of water

0.09 moles of octane yields 0.09 × 9/1 = 0.81 moles of water

Number of moles of oxygen = 23g/32g/mol = 0.72 moles

12.5 moles of oxygen yields 9 moles of water

0.72 moles of oxygen yields 0.72 × 9/12.5 = 0.52 moles of water

Hence oxygen is the limiting reactant;

Maximum mass of water produced = 0.52 moles of water × 18 g/mol = 9.36 g

Answer:

1920 Joules

Explanation:

* means multiply

^ means exponent

kinetic energy is in Joules or J

kinetic energy = 1/2 * mass * (velocity)^2

kinetic energy = 1/2 * 60 * (8)^2

kinetic energy = 1/2 * 60 * (8*8)

kinetic energy = 1/2 * 60 * (64)

kinetic energy = 1920 Joules or 1920 J

Answer:

KE = 1920 J

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

Explanation:

Step 1: Define

[Given] m = 60 kg

[Given] v = 8 m/s

Step 2: Find KE

Topic: AP Physics 1 Algebra-Based

Unit: Energy

Answer:

The answer is Iron.

Explanation:

I hope this helps you out. Have a nice day!

Answer:

x = (-4 + √30) / 2, or x = (-4 – √30) / 2

Explanation:

x = (-b ± √b² – 4ac) / 2a →

y = ax² + bx + c

given

y = 2x² + 8x – 7 →

x = (-(8) ± √(8)² – 4(2)(-7)) / 2(2) →

x = (-8 ± √64 + 56) / 4 →

x = (-8 ± √120) / 4 →

x = (-8 ± 2√30) / 4 →

x = (-4 ± √30) / 2 →

x = (-4 + √30) / 2, or x = (-4 – √30) / 2

Explanation:

High carbon concentration in the deep ocean means increased absorption of carbon to the atmosphere resulting to even greater and harmful amounts of carbon in the atmosphere. Therefore we need to keep a close eye of the deep ocean in the quest to monitor and pump out excess carbon from this part of marine life.

Answer:

d.

Explanation:

H2 + Cl2 = 2HCL

From the equation 2g hydrogen combine with 71g of chlorine.

So 35.5 g Cl2 combines with 1g of H2

There are 100g of Cl2 so this will, by proportion, react with 100/35.5 g hydrogen.

This is 2.8 g hydrogen so the mass of HCl formed = 102.8 g.

The true statement is that d. between 100 and 190 g of HCl is produced.

To find mass of HCL:

H2 + Cl2 = 2HCL

From the equation, 2g of hydrogen combines with 71g of chlorine.

So 35.5 g Cl2 combines with 1g of H2

There are 100g of Cl2 so this will, by proportion, react with 100/35.5 g of hydrogen.

This is 2.8 g hydrogen so the mass of HCl formed = 102.8 g.

Hydrogen chloride may be formed by the direct combination of chlorine (Cl2) gas and hydrogen (H2) gas.

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Answer:

The set of quantum numbers is not valid

Explanation:

There are four sets of quantum numbers;

1) Principal quantum number (n) which takes on integer values from n = 1,2,3 .......

2) Azimuthal quantum number (l) which takes on values 1, 2, ....(n - 1)

3) Magnetic quantum numbers (ml) which takes on values from (-l) to (+l)

4) spin quantum number (ms) which takes on values of ±1/2.

From the above, we can see that m can not have a value of 3 when l =2 because m has values between (-l) to (+l). Thus, the sets of quantum numbers is not valid.

Answer:

.

Explanation:

Answer:

See explanation and image attached

Explanation:

Thiocyanic acid is made made up of hydrogen, sulphur, carbon and nitrogen atoms. Carbon is the central atom in the molecule.

The molecule has a total of sixteen valence electrons as shown in the image attached. There are no formal charges in the structure of the molecule as shown.

The molecule is linear in shape.

Answer:

1.99 L

Explanation:

Given that,

A reaction produces 3.0 mol of gas, which occupies 1.46 L.

We need to find the volume of the product when 4.1 mol are produced at constant temperature and pressure.

We know that,

PV = nRT

i.e.

[tex]V\propto n\\\\\dfrac{V_1}{V_2}=\dfrac{n_1}{n_2}\\\\V_2=\dfrac{V_1n_2}{n_1}\\\\V_2=\dfrac{1.46\times 4.1}{3}\\\\V_2=1.99\ L[/tex]

So, the new volume is 1.99 L.

Answer:

C. K

i took this class before

Answer: The largest element is K

Explanation: As K has the largest radius among O,He and H

Answer:

643(%=:(¥75 )(:7$"8"),"7$"()9_/"¥?:

Answer:

antimony-121 has the highest percent natural abundance

Explanation:

percent natural abundance;

121.76 = 120.90 x + 122.90 (1 - x)

121.76 = 120.90 x + 122.90 - 122.90x

121.76 = -2x + 122.90

121.76 - 122.90 = -2x

x= 121.76 - 122.90/ -2

x= 0.57

Where x and 1 - x refers to the relative abundance of each of the isotopes

Percent natural abundance of antimony-121 = 57 %

Percent natural abundance of antimony-123 = (1 - 0.57) = 43%

Let us remember that isotopy refers to a phenomenon in which atoms of the same element have the same atomic number but different mass numbers. This results from differences in the number of neutrons in atoms of the same element.

We can clearly see that antimony-121 has the highest percent natural abundance.

Answer:

0.1 L

Explanation:

From the question given above, the following data were obtained:

Concentration of stock solution (C₁) = 1.25 M

Volume of diluted solution (V₂) = 0.5 L

Concentration of diluted solution (C₂) = 0.25 M

Volume of stock solution needed solution (V₁) =?

The volume of the stock solution needed can be obtained as follow:

C₁V₁ = C₂V₂

1.25 × V₁ = 0.25 × 0.5

1.25 × V₁ = 0.125

Divide both side by 1.25

V₁ = 0.125 / 1.25

V₁ = 0.1 L

Therefore, the volume of the stock solution needed is 0.1 L

In a flame test electrons are excited to higher energy levels and their emissions are observed. Therefore, option A is correct.

The flame test is used to visually identify the identity of an unknown metal or metalloid ion based on the properties color the salt turns in the flame of a bunsen burner.

The color of light emitted depends on the energy emitted by an electron returning to its original state.

The flame's heat converts metal ions into atoms, which become excited and emit visible light. In a flame test electrons are excited to higher energy levels and their emissions are observed.

Thus, option A is correct.

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The question is incomplete, the complete question is;

Suppose 0.377g of potassium acetate is dissolved in 250.mL of a 57.0mM aqueous solution of ammonium sulfate.

Calculate the final molarity of acetate anion in the solution. You can assume the volume of the solution doesn't change when the potassium acetate is dissolved in it.

Round your answer to 3 significant digits.

Answer:

0.0152 M

Explanation:

The equation of the reaction is;

2CH3COOK(aq) + (NH4)2SO4(aq)------> K2SO4(aq) + 2CH3COONH4(aq)

Number of moles of potassium acetate = 0.377g/98.15 g/mol = 0.0038 moles

Number of moles of ammonium sulphate = 250/1000L × 57 × 10^-3 = 0.014 moles

2 moles of potassium acetate yields 2 moles of ammonium acetate

Hence;

0.0038 moles of potassium acetate yields 0.0038 moles of ammonium acetate

Also

1 mole of potassium sulphate yields 2 moles of ammonium acetate

0.014 of potassium sulphate yields 0.014 × 2/1 = 0.028 moles of ammonium acetate

So potassium acetate is the limiting reactant.

Since 0.0038 moles of ammonium acetate is produced, the final concentration of potassium acetate is = 0.0038 moles of ammonium acetate/0.25L = 0.0152 M

Hence final concentration of acetate ions =0.0152 M

Answer:

C

Explanation:

an impure substance made through chemical process

ANSWER IS ABOVE

THE METHANOIC ACID

Answer:

Explanation:

Using the formula below to calculate the heat absorbed in each trial:

Q = m × c × ∆T

Where;

Q = amount of heat absorbed (J)

m = mass of substance (g)

c = specific heat of water (4.184J/g°C)

∆T = change in temperature (°C)

Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0 °C.

Q = 30 × 4.184 × (40 - 0)

Q = 30 × 4.184 × 40

Q = 5,020.8J

Trial 2: Heat 40.0 grams of water at 10.0 °C to a final temperature of 40.0 °C.

Answer:

The same amount of heat is absorbed in both the experiments because the product of mass, specific heat capacity, and change in temperature are equal for both.

Explanation:

Explanation:

Using the formula below to calculate the heat absorbed in each trial:

Q = m × c × ∆T

Trial 1: Heat 30.0 grams of water at 0 °C to a final temperature of 40.0 °C.

Q = 30 × 4.184 × (40 - 0)

Q = 30 × 4.184 × 40

Q = 5,020.8J

Trial 2: Heat 40.0 grams of water at 10.0 °C to a final temperature of 40.0 °C.

Q=40*4.184*30

Q=5020.8J

Answer:

The hot water dissolves the flavor and color components.

Explanation:

Caffeine can be extracted from the tea leaves into hot water because the hot water dissolves the flavor and color components away from the solid vegetable. This is an example of a solid-liquid extraction. We can extracted the aqueous solution and isolated the crude caffeine by converting the components of caffeine into their calcium salts which are insoluble in water. Then the caffeine can be extracted from the water by using methylene chloride.

Answer:

sp3 hybrid orbitals

Explanation:

The formula of a molecule gives us an idea of its structure and the nature of hybrid orbitals that are involved in the formation of the molecule.

AX4 corresponds to tetrahedral geometry. If a molecule is in tetrahedral geometry, it is most likely sp3 hybridized as usual.

Hence, a molecule with the formula AX 4 uses sp3 hybrid orbitals to form its bonds

Answer:

A metal M readily forms water-soluble sulphate MSO4, water-insoluble hydroxide M(OH)2 and oxide MO. The oxide and hydroxide are soluble in NaOH. The M is:

Explanation:

[tex]here \: is \: your \: explanation : - \\ \\ given \: balanced \:equation \: = > \\ \\ 2 A=>C \: + \: 4D \\ \\ by \: this \: equation \: we \: get \: \\ \\ 2 \: moles \: of \: A \: produce \: 4 \: moles \: \\ \\ of \: D \\ \\ hence \: . \: 1 \: mole \: can \: produce \: = 4 \div 2 \\ \\ = > 2 \: moles \: \\ \\ so \: if \: 6 \: moles \: of \: A \: used \: then \: \\ \\ amount \: of \: D \: produced \: = (6 \times 2) \\ \\ = > 12 \: moles \: of \: D \\ \\ \mathcal\blue{ Hope \: it \: helps \: you \: (. ❛ ᴗ ❛.) }[/tex]

Answer:

(NH4)2SO4 (aq) + Ba(C2H302)2 (aq) - BaSO4(s) + 2 NH4C2H3O2 (aq).

Explanation:

In balancing redox reaction equations, the rule of thumb is that the number of atoms on the left hand side of the reaction equation must be equal to the number of atoms of the same element on the left hand side of the reaction equation.

To ensure this, the correct coefficients are written in front of each of the reactants/products and the number of atoms of each element is counted to ensure that the equation is balanced.

If all these procedures are meticulously carried out, the balanced equation for the reaction between aqueous ammonium sulfate and aqueous barium acetate is:

(NH4)2SO4 (aq) + Ba(C2H302)2 (aq) - BaSO4(s) + 2 NH4C2H3O2 (aq).

Answer:

3.88 atm

Explanation:

We'll begin by calculating the number of mole of CO₂ in each case. This can be obtained as follow:

For 2.50 g of CO₂:

Mass of CO₂ = 2.5 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mole of CO₂ =?

Mole = mass / molar mass

Mole of CO₂ = 2.5 / 44

Mole of CO₂ = 0.06 mole

For 0.42 g of CO₂:

Mass of CO₂ = 2.5 g

Molar mass of CO₂ = 44 g/mol

Mole of CO₂ =?

Mole = mass / molar mass

Mole of CO₂ = 0.42 / 44

Mole of CO₂ = 0.010 mole

Finally, we shall determine the new pressure. This can be obtained as follow:

Initial mole (n₁) = 0.06 mole

Initial pressure (P₁) = 4.65 atm

Final mole (n₂) = 0.06 – 0.010 = 0.05 mole

Final pressure (P₂) =?

NOTE: Temperature and volume is constant.

P₁ / n₁ = P₂ / n₂

4.65 / 0.06 = P₂ / 0.05

Cross multiply

0.06 × P₂ = 4.65 × 0.05

0.06 × P₂ = 0.2325

Divide both side by 0.06

P₂ = 0.2325 / 0.06

P₂ = 3.88 atm

Thus, the new pressure is 3.88 atm.

The internal energy of system is raised by 3 times

Answer:

C. The enthalpy of the products is higher than that of the reactants

Explanation:

An endothermic process is any process with an increase in the enthalpy of the system

The enthalpy of the products is higher than that of the reactants describes an endothermic process. Therefore, option (C) is correct.

An endothermic process can be described as any thermodynamic process with an increase in the enthalpy H of the system. In such a process, a closed system commonly absorbs thermal energy from its surroundings.

An endothermic reaction leads to an increase in the temperature of the system and a decrease temperature of the surroundings. A physical process, such as the melting of ice cubes is an endothermic process.

Whether a process can take place spontaneously depends not only on the enthalpy change but also on the entropy change and absolute temperature.

An endothermic process commonly needs a favorable entropy increase  (∆S > 0) in the system. In an endothermic process, the energy of the products is higher than that of the reactants.

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Answer:

He chose pea plants because they were easy to grow, could be bred rapidly, and had several observable characteristics, like petal color and pea color.

Explanation:

Answer:

Object: To demonstrate phototropism

equipments: A black box, window with light source, a well watered potted plant.

Experiment: A wellwatered potted plant is placed inside a darkened black  box that is having a small window on one side. This is called as phototropic chamber. Window is remain closed for a day the plant shows normal growth.

Whereas if window is opened atwo days it will be found that shoot tip bends and grows towards light proving that it is positively phototropic.