The 10 largest bird wingspans are 9.1, 9.8, 9.2, 9.8, 11.8, 11, 8.2, 8.2, 11, and 11.8 inches. What are the range, interquartile range, and standard deviation of the wingspans?

Answer:

x=2

Step-by-step explanation:

To find the axis of the simmetry of parabola ( the curve of the quadratic function) we have to find the x of the top point of the parabola.

The x= -12/-(2*3)= 2

So the axis of the symmetry is the line x=2

Rachel will have ran 114 miles in six weeks.

There's five weekdays in a week: (3.2 x 5) = 16 miles

There's two days in a weekend: (1.5 x 2) = 3 miles

16 [weekday] + 3 [weekend] = 19 miles [7-day week]

(19 x 6) = 114 miles

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Answer:

m = 2

(0, 4)

General Formulas and Concepts:

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

Step 1: Define

y = 2x + 4

Step 2: Break function

Slope m = 2

y-intercept b = 4

Answer:

2/15

Step-by-step explanation:

10 = 2 * 5

6   = 2 * 3

LCM of 10 , 6 =  2 * 3 * 5 = 30

[tex]\frac{3}{10}-\frac{1}{6}=\frac{3*3}{10*3} - \frac{1*5}{6*5}[/tex]

          [tex]= \frac{9}{30} - \frac{5}{30}\\\\=\frac{9-5}{30}\\\\=\frac{4}{30}\\\\=\frac{2}{15}[/tex]

Answer:

his mistake is that he switched 7 and 12

Step-by-step explanation:

7 should have gone inside while 12 went on the outside

the answer should be .583333 (repeated)

Answer:

y = 3/7x - 6

General Formulas and Concepts:

Pre-Algebra

Algebra I

Slope-Intercept Form: y = mx + b

Step-by-step explanation:

Step 1: Define

Slope m = 3/7

Point (14, 0)

Step 2: Find y-intercept b

Step 3: Write linear equation

y = 3/7x - 6

Answer:

All x-values larger than or equal to 5 ([tex]x\geq 5[/tex])

Step-by-step explanation:

Notice that the graph of

[tex]f(x)=-\sqrt{x}[/tex]

is defined for all real x-values larger than or equal to zero, since the square root is defined only for such values.

When we shift the graph to the right 5 units, the function becomes:

[tex]f(x)=-\sqrt{x-5}[/tex]

then the radicand x-5 must be larger than or equal to 0 in order to render real values. Then we have:

[tex]x-5\geq 0\\x\geq 5[/tex]

which means that now the Domain becomes the following set (in set builder notation):

[tex]Domain=\left \{ x\,|\,x\geq 5 \right \}[/tex]

Answer:

check your commments

Step-by-step explanation:

Answer:

$59768.28

Step-by-step explanation:

5.5*36=198

3.25*36=117

117*198=23166

23166*2.58= thats a big room, let alone a lot of money

Answer:

3:5 and 50:100

that should be the answer

Answer:

Trick question, either 8 legs because of the two chairs or none.

Step-by-step explanation:

The dogs and everything aren't on the ground. I think the anwser is either 8 or none.

Answer:

The number of legs on the ground are 10.

Step-by-step explanation:

Given information:

2 dogs , 4 horses and 1 giraffe and a duck are laying on the bed.

3 chickens are flying over two chairs .

Now, in the riddle the specific type of leg is not mentioned but the information is given about the bed and chair.

So, one need to consider the legs of bed and chair too, also the person entering in the room is on the ground so the legs of the person will also be counted.

Hence, total number of legs on the ground will be:

legs of (1 bed + 2 chairs + 1 person)

Hence

Number of legs (N) = 4+8+2

N=10

Hence, the number of legs on the ground are 10.

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Answer:

392 liters of synthetic oil is needed

Answer:

If your doing 4 thousand and some hundreds then the answer is 19 hundred, But if your doing just hundreds the answer is 59 hundreds.

Step-by-step explanation

5900/100 = 59

Answer:

1

Step-by-step explanation:

any number to the power 0 is 1

Answer:

1

Step-by-step explanation:

Answer:

X=19

Step-by-step explanation:

7x-8=6x+11

x=19

Answer:

Use the quadratic formula --> follow the steps from there

Step-by-step explanation:

Message me if you do not know how to use the quadratic formula :)

Answer:

320904

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given that:

The differential equation; [tex](x^2-4)^2y'' + (x + 2)y' + 7y = 0[/tex]

The above equation can be better expressed as:

[tex]y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0[/tex]

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

[tex]p(x) = \dfrac{(x+2)}{(x^2-4)^2} \[/tex]

[tex]p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \[/tex]

[tex]p(x) = \dfrac{1}{(x+2)(x-2)^2}[/tex]

Also;

[tex]q(x) = \dfrac{7}{(x^2-4)^2}[/tex]

[tex]q(x) = \dfrac{7}{(x+2)^2(x-2)^2}[/tex]

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

[tex]\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}[/tex]

[tex]\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}[/tex]

[tex]\implies \dfrac{1}{16}[/tex]

[tex]\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}[/tex]

[tex]\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}[/tex]

[tex]\implies \dfrac{7}{16}[/tex]

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

Answer:

yes u can but i dont know how to show u becuase i cant move them round

Step-by-step explanation: