[tex]HOLA!![/tex]
Answer:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{3n}{3^n \: n!}=e^{\frac{1}{3} } }}[/tex]
Explanation:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{3n}{3^n \: n!}=}}[/tex]
For this we have to take into account:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{x^{n} }{n!} =e^{x} }}[/tex]
Using the properties of factorials and exponents we have:
[tex]n!=(n-1)n![/tex] Also. [tex]\frac{n^{x} }{ n^{y} }=n^{x-y}[/tex]
We replace:
[tex]{\boxed{ \sum_{n=1}^{\infty}\ \frac{1}{3^{n-1}.(n-1)! } }}[/tex]
Shape it:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{(\frac{1}{3} )^{n-1} }{(n-1)!} }}[/tex]
Finally:
[tex]{\boxed{ \sum_{n=1}^{\infty}\frac{(\frac{1}{3} )^{n-1} }{(n-1)!} =e^{\frac{1}{3} } }}[/tex]
Does crime pay? The FBI Standard Survey of Crimes showed that for about 80% of all property crimes (burglary, larceny, car theft, etc.), the criminals are never found and the case is never solved.† Suppose a neighborhood district in a large city suffers repeated property crimes, not always perpetuated by the same criminals. The police are investigating nine property crime cases in this district.
Answer:
The appropriate answer is "11 crimes".
Step-by-step explanation:
Let,
The number of crimes be "n".
Now,
⇒ [tex]P(solved \ at \ least \ one) = 1-P(solved \ none \ of \ n)[/tex]
or,
⇒ [tex]1-(0.8)^n>0.9[/tex]
⇒ [tex](0.8)^n<0.1[/tex]
By taking log both sides, we get
⇒ [tex]n>=\frac{log(0.1)}{log(0.8)}[/tex]
By putting the values, we get
⇒ [tex]n>=10.31[/tex]
[tex]n=11 \ crimes[/tex]
Find the volume of a sphere with a surface area of 400 square feet.
Answer:
V≈752.25ft
Step-by-step explanation:
please mark me brain list
Answer: the volume of the sphere would be precicely be 752.25278
Step-by-step explanation: yeah, i guess this is just a run and search kind of question, the formula to find it was:
A=4πr2
V=4
3πr3
Solving forV
V=A3/2
6π=4003/2
6·π≈752.25278
find the interior angle of a regular polygon with 20 sides. What is the size of exterior angle
Answer: 18
Step-by-step explanation:
360/20 = 18
một nhà máy có 3 phân xưởng, tỉ lệ là 20%, 30%, 50%. tỉ lệ sản phẩm loại một của các phân xưởng lần lượt là 90%, 85%, 80%
lấy ngẫu nhiên 1 sản phẩm của nhà máy, tính xác suất để được sản phẩm loại một
Answer:
83.5%
Step-by-step explanation:
90% × 20% + 85% × 30% + 80%× 50%
Write a ratio for the following description: For every 6 cups of the flour in a bread recipe, there are two cups of milk.
Trình bày phương pháp tìm ma trận nghịch đảo bằng phép biến đổi sơ cấp. Áp dụng tìm ma trận nghịch đảo của ma trận
Answer:
bukhayung saging my faborito
There are 17 books on a shelf. 8 of these books are new. the rest of them are used. (GIVING BRAINLEST TO BEST ANSWER) what is the ratio?
In a random sample of 150 customers of a high-speed internet provider, 63 said that their service had been interrupted one or more times in the past month. Find a 95% confidence interval for the proportion of customers whose service was interrupted one or more times in the past month.
Answer:
The correct answer is "0.3410, 0.4990".
Step-by-step explanation:
Given values are:
[tex]n=150[/tex]
[tex]p=\frac{63}{150}[/tex]
[tex]=0.42[/tex]
At 95% confidence interval,
C = 95%
z = 1.96
As we know,
⇒ [tex]E=z\sqrt{\frac{p(1-p)}{n} }[/tex]
By substituting the values, we get
[tex]=1.96\sqrt{\frac{0.42\times 0.58}{150} }[/tex]
[tex]=1.96\sqrt{\frac{0.2436}{150} }[/tex]
[tex]=0.0790[/tex]
hence,
The confidence interval will be:
= [tex]p \pm E[/tex]
= [tex]0.42 \pm 0.079[/tex]
= [tex](0.3410,0.4990)[/tex]
This question is mildy difficult and i need some help would anyone please help me
Answer:
30 and 45 degrees
Step-by-step explanation:
m26 is (2x - 5) and m_8 is (x + 5)º
What is m 3?
12
9
3 4
56
78
Answer:
12
Step-by-step explanation:
12 is the coefficient
can someone help asap!!
7/9÷4/9=7/4
= 1/3/4
Hence, a=1, b=3, c=4.
hope it helps:)))
A farmer makes a rectangular enclosure for his animals.
He uses a wall for one side and a total of 72 metres of fencing for the other three sides.
The enclosure has width x metres and area A square metres.
Show that A = 72x - 21.
Answer:
Remember that, for a rectangle of length L and width W, the area is:
A =L*W
And the perimeter is:
P = 2*(L + W)
In this case, we know that:
W = x
Let's assume that one of the "length" sides is on the part where the farmer uses the wall.
Then the farmer has 72 m of fencing for the other "length" side and for the 2 wide sides, then:
72m = L + 2*x
isolating L we get:
L = (2x - 72m)
Then we can write the area of the rectangle as:
A = L*x = (2x - 72m)*x
A = 2*x^2 - 72m*x
(you wrote A = 72x - 21, I assume that it is incorrect, as the area should be a quadratic equation of x)
Answer these questions about the right triangle.
What is the area of the square of the leg 6?
What is the area of the square of the leg 8?
What is the area of the hypotenuse square?
What is the length of the hypotenuse?
9514 1404 393
Answer:
366410010Step-by-step explanation:
The area of a square is the square of the side length. Then the side length is the square root of the area.
6² = 36 . . . area of the square of leg 68² = 64 . . . area of the square of leg 836+64 = 100 . . . sum of the two leg squares = area of hypotenuse square√100 = 10 . . . hypotenuse lengthSolve the simultaneous equations.
Show all your working.
3x + 4y = 14
5x+2y=21
Step-by-step explanation:
hear is your answer in attachment
These marbles are placed in a bag and two
of them are randomly drawn.
What is the probability of drawing two pink
marbles if the first one is placed back in the
bag before the second draw?
Give your answer as a ratio, reduced to
simplest terms.
[?]
Hint: Multiply the probability of the 1st Event by the
probability of the 2nd Event to get your answer.
Enter
========================================================
Explanation:
There are 3 pink marbles out of 10 total (we can see that 2 yellow + 3 pink + 5 blue = 10 total)
The fraction 3/10 represents the probability of pulling out a pink marble at random. Since the first one is put back, this means the fraction 3/10 stays the same on the second draw as well.
We use the idea mentioned in the hint to multiply the fractions:
(3/10)*(3/10) = (3*3)/(10*10) = 9/100
The probability of pulling two pink marbles in a row is 9/100, where the first marble is put back.
Effectively, if you were given 100 tries at doing this, you should expect about 9 of those times you get 2 pink marbles in a row.
Is AABC-ADEP? If so, identify the similarity postulate or theorem that
applies.
B
16
105°
5-105
4
36
A
C
D
9
F
I
Answer:
D. cannot be determined
Step-by-step explanation:
that is kind of a trick question.
right based on the given information none of the 3 methods can be applied.
we don't have all 3 sides for SSS
we don't have 2 angles for AA
and we don't have 2 sides with their included angle for SAS.
but it can still be determined (they ARE similar), as this is a special case of SSA, where it is clear that the corresponding congruent angles are located at the same position relatively to the corresponding similar lines.
you can discuss this with your teacher, if you are interested.
AND - we can easily determine any of the other missing pieces (side and angles). these missing pieces then will correspond exactly to their counterparts in the other triangle (the 2 angles in ABC are equal to the 2 angles in DEF, the missing sides file the same scaling factor as the other known sides). and then any of the 3 methods can be applied.
so, this is actually tricky ...
Y= abx that goes through points (0,13) and (2,325)
Answer:
[tex]y = 13(5)^x[/tex]
Step-by-step explanation:
We are given the following exponential function:
[tex]y = ab^x[/tex]
(0,13)
This means that when [tex]x = 0, y = 13[/tex]. So
[tex]y = ab^x[/tex]
[tex]13 = ab^0[/tex]
[tex]a = 13[/tex]
Then
[tex]y = 13b^x[/tex]
(2,325)
This means that when [tex]x = 2, y = 325[/tex] We use this to find b. So
[tex]y = 13b^x[/tex]
[tex]13b^2 = 325[/tex]
[tex]b^2 = \frac{325}{13}[/tex]
[tex]b^2 = 25[/tex]
[tex]b = 5[/tex]
Thus
[tex]y = 13(5)^x[/tex]
The quadratic function y = -x2 + 10x - 8 models the height of a trestle on a bridge. The x-axis represents ground level.
To find where the section of the bridge meets ground level, solve 0 = -x2 + 10x - 8.
Where does this section of the bridge meet ground level?
Answer: 0.876, 9.123
Step-by-step explanation:
The function is [tex]y=-x^2+10-8[/tex]
It meets the ground level when [tex]y[/tex] is 0
[tex]\Rightarrow -x^2+10x-8=0\\\Rightarrow x^2-10x+8=0\\\\\Rightarrow x=\dfrac{10\pm \sqrt{(-10)^2-4(1)(8)}}{2}\\\\\Rightarrow x=\dfrac{10\pm \sqrt{68}}{2}\\\\\Rightarrow x=5\pm \sqrt{17}\\\Rightarrow x=0.876,\ 9.123[/tex]
Thus, it touches the ground at two points given above
WILL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST
Answer:
height = (3x + 3)
Step-by-step explanation:
area of rectangular prism = length *breadth
2x^2 + 3x = length*breadth
volume of a rectangular prism = length * breadth *height
6x^3 + 13x^2 + 6x = (2x^2 + 3x) *height
x(6x^2 + 13x + 6) = x(2x + 3) *height
a nd x gets cancel . So,
(6x^2 + 13x + 6) = (2x + 3) *height
6x^2 + (9 + 4)x + 6 = (2x + 3) *height
6x^2 + 9x + 4x + 6 = (2x + 3) *height
3x(2x +3) +2(2x +3) = (2x + 3) *height
(3x + 2)(2x + 3) = (2x + 3)*height
(3x + 2)(2x + 3) / (2x + 3) = height
(2x + 3 ) of numerator and (2x + 3) of denominator gets cancel
(3x + 3) / 1 = height
(3x + 3) = height
Chung has 6 trucks and 5 cars in his toy box. Brian has 4 trucks and 5 cars in his toy box.
Which is the correct comparison of their ratios of trucks to cars?
StartFraction 6 Over 4 EndFraction less-than StartFraction 5 Over 5 EndFraction
StartFraction 6 Over 4 EndFraction greater-than StartFraction 5 Over 5 EndFraction
StartFraction 6 Over 5 EndFraction less-than StartFraction 4 Over 5 EndFraction
StartFraction 6 Over 5 EndFraction greater-than StartFraction 4 Over 5 EndFraction
Given:
Chung has 6 trucks and 5 cars in his toy box.
Brian has 4 trucks and 5 cars in his toy box.
To find:
The correct comparison of their ratios of trucks to cars.
Solution:
The ratio of trucks to cars is defined as:
[tex]\text{Ratio}=\dfrac{\text{Number of trucks}}{\text{Number of cars}}[/tex]
Chung has 6 trucks and 5 cars in his toy box. So, the ratio of trucks to cars is:
[tex]\text{Ratio}=\dfrac{6}{5}[/tex]
Brian has 4 trucks and 5 cars in his toy box.
[tex]\text{Ratio}=\dfrac{4}{5}[/tex]
We know that,
[tex]6>4[/tex]
[tex]\dfrac{6}{5}>\dfrac{4}{5}[/tex]
Therefore, the correct option is D.
Answer:
what the guy above me said
Step-by-step explanation:
so yeah he is right points
If you become a. . what Will you do
Answer:
if you becomes a.. what is this mean
Answer:
i have no idea
Step-by-step explanation:
i dont think turning into a virtual period will let me do anything. If you can clarify please let us know!
Pls help I really need help beg you you
Answer:0,5
Step-by-step explanation:
Choose the conditional statement that can be used with its converse to form the following biconditional statement: "It is a leap year if and only if the year has 366 days."
A. If it is not a leap year, then it does not have 366 days.
B. If it is a leap year, then the year has 366 days.
C. If a leap year has 366 days, then this is a leap year. D. If a year does not have 366 days, then it is not a leap year
Given the biconditional statement: "It is a leap year if and only if the year has 366 days.", the converse to form it is "If the year has 366 days, then this is a leap year". (Right choice: C)
How to determine the propositional form of a sentence
According to logics, propostions are truth bearers that makes sentences true or false. In linguistics, propositions are the meaning of declarative sentences. There are simple and composite propositions, the latter are formed by one simple proposition at least and logic connectors. There are five logic connectors:
Conjuction X ∧ Y ("and" operator)Disjunction X ∨ Y ("or" operator)Negation ¬ X ("not" operator)Implication/Conditional X ⇒ Y ("if-then" operator)Double implication/Biconditional X ⇔ Y ("if-only if" operator)By logic rules we know that the double implication/biconditional is commutative operator:
(X ⇔ Y) ⇔ (Y ⇔ X)
In addition, a double implication/biconditional has the following equivalence:
(X ⇒ Y) ∧ (Y ⇒ X)
Where Y ⇒ X is the converse of X ⇒ Y.
Therefore, the converse to form the statement "It is a leap year if and only if the year has 366 days" is Y ⇒ X: "If the year has 366 days, then this is a leap year".
To learn more on propositions: https://brainly.com/question/14789062
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Simplify the expression
Answer:
6
Step-by-step explanation:
3 sqrt(20) / sqrt(5)
We know that sqrt(a) /sqrt(b) = sqrt(a/b)
3 sqrt(20/5)
3 sqrt(4)
3 *2
6
What is the answer plz help!!!
9514 1404 393
Answer:
B. horizontal stretch by a factor of 3
Step-by-step explanation:
Replacing x by x/k in a function causes its graph to be stretched horizontally by a factor of k. (This makes sense because it means x needs to be k times as large to give the same argument to the function.)
Here, the value of k is 3, so the function graph is horizontally stretched by a factor of 3.
Which equation represents a line that passes through (5, 1) and has a slope of ?
O y-5 = {(x-1)
Oy- } = 5(x –1)
Oy-1 = {(x–5)
Oy - 1 = 5(x-)
Answer:
y - 1 = 5(x - 5)
Step-by-step explanation:
Given the following data;
Points (x, y) = (5, 1)
Slope = ?
From the question, the value of the slope is missing. Hence, let's assume a value of 5.
Mathematically, the equation of a straight line is given by the formula;
y = mx + c
Where;
m is the slope.
x and y are the points
c is the intercept.
To find the equation of line, we would use the following formula;
y - y1 = m(x - x1)
Substituting into the formula, we have;
y - 1 = 5(x - 5)
y - 1 = 5x - 25
y = 5x - 25 + 1
y = 5x - 24 = mx + c
Solve (2x-1)^2=8 using the quadratic formula
Step-by-step explanation:
The given equation is :
[tex](2x-1)^2=8[/tex]
or
[tex](2x-1)=\sqrt{8}\\\\2x-1=\pm 2\sqrt2\\\\2x=\pm 2\sqrt2 +1\\\\x=\dfrac{2\sqrt2 +1}{2}\\\\x=\pm (\sqrt 2+\dfrac{1}{2})\\\\or\\\\x=\sqrt2+\dfrac{1}{2},-\sqrt2-\dfrac{1}{2}[/tex]
Hence, this is the required solution.
The sum of two numbers is 12 The product of the smaller
umber and 3 is -6. Find
the numbers
Answer:
-2 and 14
Step-by-step explanation:
-2×3=-6-2+14=12The numbers are -2 and 14
What is algebraic expression?A number, a variable, or a mix of numbers, variables, and operation symbols make up an expression. Two expressions joined by an equal sign form an equation. Word illustration: The product of 8 and 3. Word illustration: The product of 8 and 3 is 11
given
Let smaller number be x and larger number be y
x * 3 = -6
x = -6/3 = -2
x+y = 12
-2 + y = 12
y = 12+2 = 14
to learn more about algebraic expression refer to:
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The graph of g(x) = (x + 2)2 is a translation of the graph of f(x) by units.
1. Left 2. 2 units
3. Right 4. 3 units
EDGE 21
Answer:
Left 2 units
Step-by-step explanation:
Without knowing what f(x), it is impossible to answer this question. I'll answer assuming a parent function of [tex]f(x)=x^2[/tex].
In the function [tex]y=(x-c)^2[/tex], [tex]c[/tex] represents the phase shift from parent function [tex]f(x)=x^2[/tex]. If [tex]c[/tex] is positive (e.g. [tex](x-3)^2[/tex]), then the function shifts to the right however many units [tex]c[/tex] is. If [tex]c[/tex] is negative (e.g. [tex](x+5)^2[/tex]), the function shifts to the left however many units the absolute value of [tex]c[/tex] is.
In the function [tex]g(x)=(x+2)^2[/tex], let's find out the value of [tex]c[/tex]:
Format: [tex]y=(x-c)^2[/tex]
[tex]g(x)=(x+2)^2=(x-(-2))^2[/tex]
Therefore, [tex]c=-2[/tex].
Since [tex]c[/tex] is negative, the function must shift to the left. To find out how many units it shifts to the left, take the absolute value of [tex]c[/tex]:
[tex]|-2|=\boxed{2\text{ units to the left}}[/tex].
Thus, the graph of [tex]g(x)=(x+2)^2[/tex] is a translation of the graph [tex]f(x)=x^2[/tex] by 2 units to the left.
*Note: Once again, this answer is assuming [tex]f(x)=x^2[/tex] as it is not clarified in the question. If [tex]f(x)\neq x^2[/tex] and is already shifted, you will need to account for shift. If you believe this is the case, feel free to let me know in the comments.
Business Weekly conducted a survey of graduates from 30 top MBA programs. On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 181000 dollars. Assume the standard deviation is 31000 dollars. Suppose you take a simple random sample of 60 graduates.
Find the probability that a single randomly selected policy has a mean value between 172595.6 and 196608.1 dollars.
P(172595.6 < X < 196608.1) =
(Enter your answers as numbers accurate to 4 decimal places.)
Find the probability that a random sample of size
n
=
60
has a mean value between 172595.6 and 196608.1 dollars.
P(172595.6 < M < 196608.1) =
(Enter your answers as numbers accurate to 4 decimal places.)
Answer:
0.2979 = 29.79 probability that a single randomly selected policy has a mean value between 172595.6 and 196608.1 dollars.
0.982 = 98.2% probability that a random sample of size 60 has a mean value between 172595.6 and 196608.1 dollars.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
On the basis of the survey, assume the mean annual salary for graduates 10 years after graduation is 181000 dollars. Assume the standard deviation is 31000 dollars.
This means that [tex]\mu = 181000, \sigma = 31000[/tex]
Find the probability that a single randomly selected policy has a mean value between 172595.6 and 196608.1 dollars.
This is the p-value of Z when X = 196608.1 subtracted by the p-value of Z when X = 172595.6. So
X = 196608.1
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{196608.1 - 181000}{31000}[/tex]
[tex]Z = 0.5[/tex]
[tex]Z = 0.5[/tex] has a p-value of 0.6915
X = 172595.6
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{172595.6 - 181000}{31000}[/tex]
[tex]Z = -0.27[/tex]
[tex]Z = -0.27[/tex] has a p-value of 0.3936
0.6915 - 0.3936 = 0.2979
0.2979 = 29.79 probability that a single randomly selected policy has a mean value between 172595.6 and 196608.1 dollars.
Sample of 60:
This means that [tex]n = 60, s = \frac{31000}{\sqrt{60}}[/tex]
Now, the probability is given by:
X = 196608.1
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{196608.1 - 181000}{\frac{31000}{\sqrt{60}}}[/tex]
[tex]Z = 3.9[/tex]
[tex]Z = 3.9[/tex] has a p-value of 0.9999
X = 172595.6
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{172595.6 - 181000}{\frac{31000}{\sqrt{60}}}[/tex]
[tex]Z = -2.1[/tex]
[tex]Z = -2.1[/tex] has a p-value of 0.0179
0.9999 - 0.0179 = 0.982
0.982 = 98.2% probability that a random sample of size 60 has a mean value between 172595.6 and 196608.1 dollars.