TAKING 100 PONTS!!! PLEASE SOMEONE HELP.JUST LOOK THE PICTURE​

Answer:

1000 Hz

Explanation:

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Answer:

im not sure maybe viberation

Explanation:

Answer:

X-ray waves are transmitted by ....... body tissues with very little absorption

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Answer:

W=45J

Explanation:

W=Fd

W=15(3)=45

W=45J

95000kg is the mass of the airplane.

A property of a moving body that the body has by virtue of its mass and motion and that is equal to the product of the body's mass and velocity.

It is also known as the property of a moving body that determines the length of time required to bring it to rest when under the action of a constant force.

Mathematically ,

p = mv

According to the question,

Momentum of airplane =  8.55 x 10⁷ kg.m/s

Velocity of airplane =  900 km/h

Computing the values in the formula,

p = mv

8.55 x 10⁷ kg.m/s =  m x  900 km/h

m =[tex]\frac{8.55 * 10^7 kg.m/s}{900 km/h}[/tex]

m = 95000 kg

Therefore ,

The mass of the airplane 95000 kg

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Answer:

THE CORRECT ANSWER FOR THIS KS

Explanation:

STOP USING THIS APP FOR ANSWERS U KNOW NOTHING

Answer:

i need help with the same question

Explanation:

Answer:

[tex]2.4375\ \text{m/s}[/tex]

Explanation:

[tex]m_1[/tex] = Mass of cannon ball = 39 kg

[tex]m_2[/tex] = Mass of performer = 65 kg

[tex]u_1[/tex] = Initial horizontal component of cannon ball's velocity = 6.5 m/s

[tex]u_2[/tex] = Initial horizontal component of performer's velocity = 0

v = Velocity of combined mass

As the momentum of the system is conserved we have

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{39\times 6.5+0}{39+65}\\\Rightarrow v=2.4375\ \text{m/s}[/tex]

The speed of the performer immediately after catching the cannon ball is [tex]2.4375\ \text{m/s}[/tex].

Answer:

)Give the definition of poverty line as defined by the World Bank.

Answer:

I know theirs South American coast he was there a lot

Answer:

Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. This postulate is known as the law of inertia.

Explanation:

Answer:

A. Protons

Explanation:

Atomic number is an indicator of how many protons an element possesses in its nucleus. We use atomic number to identify an element. For example, carbon has 6 protons and an atomic number of 6.

Answer:

(a) The change in momentum is 12.04 kg-m/s

(b) The force exerted by the bat is 1003.33 N

Explanation:

Given that,

The mass of a ball, m = 0.14 kg

Initial speed of the ball, u = 40 m/s

Final speed of the ball, v = -46 m/s

(a) The change in momentum of the ball during the collision with the bat is given by :

[tex]\Delta p=m(v-u)\\\\=0.14(-46-40)\\\\=-12.04\ kg-m/s[/tex]

(b) Time for collision, t = 0.012 s

Now the force can be calculated as follows :

[tex]F=\dfrac{\Delta p}{t}\\\\F=\dfrac{12.04}{0.012}\\\\=1003.33\ N[/tex]

Hence, this is the required solution.

Answer:

a. = 12.04 kg*m/s

b. = 1,003.3N

Explanation:

The answer above is correct.

Answer: 6611.715 joules

Explanation:

Q = MxCxdeltaT = 6959.7 which is 100%

95% = 6611.715

Answer:

True

Explanation:

"a process by which someone is deprived of normal external stimuli such as sight and sound for an extended period of time, especially as an experimental technique in psychology."

Quote by G o o g l e

Answer:

160.43 meters

Explanation:

T=(2*pi*r)/v

840=(2*pi*r)/1.2

1008=2*pi*r

504=pi*r

160.43=radius

The distance around the circular track is equal to its circumference. If it takes840 s  to complete the path with a velocity of 1.20 m/s then the radius of the path will be 160 m.

Velocity is a physical quantity measuring the distance traveled by unit time. It is a vector quantity thus, characterized by its magnitude and direction. Velocity is usually expressed in m/s.

Velocity is the ratio of distance to the time taken to complete the travel. Thus, greater distance within short time indicates greater velocity.

Given that the time take to complete the circular path = 840 s

velocity = 1.20 m/s

distance = circumference of the circular path = 2πr.

distance = time × velocity

2πr = 840 s × 1.20 m/s

      = 1008 m.

Therefore, the radius r of the circular path  = 1008 m/ 2 π = 160 m.

Hence, the radius of the circular path 160 m.

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Answer:

An object is considered to be in motion only when its position changes over time with reference to a point which will be known as orgin

Answer:

a)      N = 7.90 10³ N,  b) N = -1.04 10⁴ N

Explanation:

a) For this exercise we can use Newton's second law

             N -W = m (-a)

The relationship is centripetal, the negative sign of the acceleration is because it points towards the center of the circle

              a = v² / r

we substitute

             N = mg -m v² /r  

             N = m (g - v² /r)

let's calculate

v = 8.7 m / s

             N = 1240 (9.81 - 8.7²/22)

             N = 7.90 10³ N

b) v = 20 m / s

             N = 1240 (9.81 - 20²/22)

             N = -1.04 10⁴ N

Answer:

0.204 kg

Explanation:

6/(9.8*3)

6/29.4=0.204

9.8 represents gravity

Answer:

λ = 5.434 x 10⁻⁷ m = 543.4 nm

Explanation:

To solve this problem we can use the formula provided by Young's Double Slit experiment:

[tex]\Delta x = \frac{\lambda L}{d}\\\\\lambda = \frac{\Delta xd}{L}[/tex]

where,

λ = wavelength of light = ?

Δx = distance between adjacent bright fringes = 1.6 cm = 0.016 m

d = slit separation = 0.18 mm = 0.00018 m

L = Distance between slits and screen = 5.3 m

Therefore,

[tex]\lambda = \frac{(0.016\ m)(0.00018\ m)}{5.3\ m}[/tex]

λ = 5.434 x 10⁻⁷ m = 543.4 nm

Given values are:

Speed,

Time,

As we know,

→ [tex]Acceleration = \frac{Speed}{Time}[/tex]

or,

→                   [tex]a = \frac{v}{t}[/tex]

By substituting the values,

                       [tex]= \frac{30}{3}[/tex]

                       [tex]= 10 \ m/s^2[/tex]

Thus the above solution is correct.    

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