Sushil and Fiona win some money and share it in the ratio 3:5. Sushil gets £42. How much did they win in total?


Help please!!

Answer:

52 ft squared

Step-by-step explanation:

1. Draw the picture with measurements

2. Decompose each shape

3. Find the area of each (l*w)

4. Add each measurement up

Answer:

x=4.5

Step-by-step explanation:

8x-3=33

8x=36

x=4.5

Answer:

4.5

Step-by-step explanation:

8x-3=33

8x-3+3=33+3

8x=36

8x/8=36/8

x=4.5

Hope this helps! Pls give brainliest!

Answer:

7 ft

Step-by-step explanation:

Answer:

D. [tex]\displaystyle 8[/tex]

Step-by-step explanation:

[tex]\displaystyle -6 + 6n = 42 \hookrightarrow \frac{48}{6} = \frac{6n}{6} \\ \\ \boxed{8 = n}[/tex]

*We add six to both sides, then divide the remaining result by six, to get eight.

I am joyous to assist you at any time.

Hey there!

-6 + 6n = 42

6n - 6 = 42

ADD 6 to BOTH SIDES

6n - 6 + 6 = 42 + 6

CANCEL out: -6 + 6 because it gives you 0

KEEP: 42 + 6 because it help solve for the n-value

NEW EQUATION: 6n = 42 + 6

SIMPLIFY IT!

6n = 48

DIVIDE 6 to BOTH SIDES

6n/6 = 48/6

CANCEL out: 6/6 because it give you 1

KEEP: 48/6 because it help solve for the n-value (it actually give you the n-value)

NEW EQUATION: n = 48/6

SIMPLIFY IT!

n = 8

Therefore, your answer is: Option D. 8

Good luck on your assignment & enjoy your day!

~Amphitrite1040:)

Answer:

https://brainly.com/question/26947898?answering=true&answeringSource=feedPublic%2FhomePage%2F1

Step-by-step explanation:

if its wrong then this

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Answer:8 5/9 meters

Step-by-step explanation:

If you get a common denominator and add, 2 4/18 + 2 1/18 + 2 1/18 + 2 4/18 you get 8 10/18 which is 8 5/9 when simiplified.

The Brian paid amount of every quarter is $ 4287.79.

We have given that Brian took eight years to pay off his $ 71,900 loan, had an interest rate of 8.16%, compounded quarterly,

we have to determine, if Brian paid quarterly and made the same payment every time, how much was each payment that he made,

P=71900

r=8.16

[tex]r=\frac{8.16}{100}=0.0816[/tex]

[tex]i=\frac{r}{n}=\frac{0.0816}{4}= 1.0204[/tex]

for eight years

[tex]4\times 8=32[/tex]

[tex]monthly payment=P((1+i)^n/n)[/tex]

Where p=present value

r=interest rate

m=number of compounding periods

n=m(t)

t=times in years

i=r/m

Therefore by using the formula we get,

[tex](71900 \times (1 + 0.0816 / 4) ^ {4\times8}) / (8 \times 4) = X[/tex]

[tex](71900 \times 1.0204 ^ {32}) / 32 = X[/tex]

[tex](71900 \times 1.9083) / 32 = X[/tex]

[tex]137209.2177 / 32 = X[/tex]

[tex]4287.79 = X[/tex]

Therefore, Brian paid $ 4287.79 every quarter.

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Answer:

3081.54

Step-by-step explanation:

took test 20 mins ago

Answer:

First, plug-in x and y as 3sin​​θ-2 and 3cos​​​θ+4 into the equation, respectively:

[tex]((3\sin (\theta)-2)+2)^2 + ((3\cos (\theta)+4)-4)^2 = 9[/tex]

Then, +2 and -2 cancel out and +4 and -4 cancel out as well, leaving you with:

[tex](3\sin(\theta))^2+(3\cos(\theta))^2=9[/tex]

We can factor out 3^2 = 9 from both equations:

[tex]9(\sin(\theta)^2+cos(\theta)^2) = 9[/tex]

We know from a trigonometric identity that [tex]\sin(\theta)^2+cos(\theta)^2 = 1[/tex], meaning we can reduce the equation to:

[tex]9(1) = 9[/tex]

[tex]9=9[/tex]

And therefore, we have shown that (x+2)^2 + (y-4)^2 = 9, if x=3sin​​θ-2 and y=3cos​​​θ+4.

Hope this helped you.

Answer:

answer c

Step-by-step explanation:

Answer:

h = 15 ft

Step-by-step explanation:

using the 2 similar triangles in the diagram then the ratios of corresponding sides are in proportion.

let h be the height of the tree

[tex]\frac{h}{5}[/tex] = [tex]\frac{24}{8}[/tex] = 3 ( multiply both sides by 5 )

h = 15 ft

Answer:

you havent given the object co ordinates but i hope this helps

Step-by-step explanation:

(A,B) under rotation 180 degrees about a given point lets say (h,k)

is marked onto point (2h-A, 2k-B)

Answer:

I believe it would be steepness only.

Please let me know if I'm incorrect :)

Answer:

incorrect is They have a sum of -14

Answer:

There should be 6 gaps and 5 of which are filled in.

Here is the situation

Answer:

c. zero product rule

Step-by-step explanation:

apex

5a+2 =2 (4+a)

Simplifying

5a + 2 = 2(4 + a)

Reorder the terms:

2 + 5a = 2(4 + a)

2 + 5a = (4 * 2 + a * 2)

2 + 5a = (8 + 2a)

Solving

2 + 5a = 8 + 2a

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-2a' to each side of the equation.

2 + 5a + -2a = 8 + 2a + -2a

Combine like terms: 5a + -2a = 3a

2 + 3a = 8 + 2a + -2a

Combine like terms: 2a + -2a = 0

2 + 3a = 8 + 0

2 + 3a = 8

Add '-2' to each side of the equation.

2 + -2 + 3a = 8 + -2

Combine like terms: 2 + -2 = 0

0 + 3a = 8 + -2

3a = 8 + -2

Combine like terms: 8 + -2 = 6

3a = 6

Divide each side by '3'.

a = 2

Simplifying

a = 2

Answer:

The simple interest accumulated

on a principal of $ 10,000.00

at a rate of 3.875% per year

for 5 years is $ 1,937.50.

Step-by-step explanation:

I = $ 1,937.50

Equation:

I = Prt

Calculation:

First, converting R percent to r a decimal

r = R/100 = 3.875%/100 = 0.03875 per year,

then, solving our equation

I = 10000 × 0.03875 × 5 = 1937.5

I = $ 1,937.50

Answer:

The answer should be 1,1125,000 because 10,000x 15 x7.5= 1,1125,000.

[tex]x^{2} -2x-8=0\\(x-4)(x+2)=0[/tex]

Hope that helps!

Answer:

80.5

Step-by-step explanation:

to find average you need to first added all your number then divide by how much numbers you added

[tex]\textit{volume of a pyramid}\\\\ V=\cfrac{Bh}{3}~~ \begin{cases} B=\stackrel{base's}{area}\\ h=height\\[-0.5em] \hrulefill\\ B=\stackrel{11.3~\times~ 11.3}{127.69}\\ h=11.8 \end{cases}\implies \begin{array}{llll} V=\cfrac{(127.69)(11.8)}{3} \\\\\\ V\approx 502.2~m^3 \end{array}[/tex]

Answer:

not that hard just think about it really hard

Step-by-step explanation:

Answer:

s = 41 cm

Step-by-step explanation:

Since all the sides on a square are equal, we can use this formula for perimeter:  P = 4s

Plugging in 164 gives us 164 = 4s, where solving for s gives us s = 41

Answer: 8 8 4

Step-by-step explanation:the first one is 8 then 8 and then 4

The answers will be ;

a) No. of customers , one employee can help at restaurant is 5.

b) No. of customers , one employee can help at grocery store is 12.

c) The grocery rate of customer per employee is 7 more than restaurant's rate.

A graph for restaurant is given and a table for grocery store is given which represents relation of no. of employees per customer.

We have to solve the subparts of the given question.

What will be the rate if there are 12 customers per 2 employee at a shop ?

The rate at the shop will be 12 ÷ 2 or 6 customers per employee.

As per the question ;

Graph for restaurant is given and a table for grocery store is given.

a)

At restaurant ;

For 2 employees , no. of customers = 10

For 4 employees , no. of customers = 20

So ,

With increase of 2 in number of employees , no. of customers increases by 10.

⇒ No. of customers , one employee can help at restaurant is ;

= 10 ÷ 2

= 5 customers

b)

At grocery store ;

For 2 employees , no. of customers = 24

For 4 employees , no. of customers = 48

So ,

With increase of 2 in number of employees , no. of customers increases by 24.

⇒ No. of customers , one employee can help at grocery store is ;

= 24 ÷ 2

= 12 customers

c)

So ,

The restaurant rate of customers per employee = 5 customers/employee

The grocery store rate of customers per employee = 12 customers / employee

And

The grocery rate of customer per employee is more than restaurant rate by ;

= 12 - 5

= 7

Thus , the answers will be ;

a) No. of customers , one employee can help at restaurant is 5.

b) No. of customers , one employee can help at grocery store is 12.

c) The grocery rate of customer per employee is 7 more than restaurant's rate.

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Answer:

2 x 2 x 3 x 7

Step-by-step explanation:

2x2=4

4x3=12

12x7=84

Answer:

The answer is D: "y, because Triangle JHK is similar to triangle LMK".

Step-by-step explanation:

Answer:

the answer is y, because Triangle JHK is similar to triangle LMK

R=diameter/2=12/2= 6 inches

Area=πr²

Area=3.14×6²

Area=3.14×36

Area=113.04 inches²