Suppose you are pushing a stalled car. As the car gets going, you need less and less force to keep it going. For the first 15 m, your force decreases at a constant rate from 210.0 N to 40.0 N. How much work did you do on the car

The work you do when pushing a shopping cart twice as far while applying double the force is twice as much as force.

A push or pull that an object experiences as a result of interacting with another item is known as a force. Every time two items interact, a force is exerted on each of the objects. The force is no longer felt by the two objects when the interaction ends.

Contact forces are the kinds of forces that develop when two objects interact and appear to be in physical contact with one another. Frictional forces, tensional forces, normal forces, air resistance forces, and applied forces are a few examples of contact forces.

Forces that come from action at a distance.

Therefore, The work you do when pushing a shopping cart twice as far while applying double the force is twice as much as force.

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The acceleration which is acting on the object which is moving on the ramp is same for both the motion whether is going upwards or moving downwards.

Rolling motion happens when an object roll over from a ramp or any other sloppy surface whether it is rough or smooth. many forces act on it at the same moment. also in many forces rolling tangential force and gravitational force is also acting on it at the same moment. in which the gravitational force is acting on it at a bigger pace and plays an important role in rolling of the object from the ramp or any other sloppy surface. here we can see that the only force that is making impact on the object is the gravitational force. Hence, by this information we consider that the  acceleration which is acting on the object which is moving on the ramp is same for both the motion whether is going upwards or moving downwards.

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When a single note is kept for a long time, it seems very soft to him. This is because he is standing at a point where the rarefactions of the sound wave from one speaker meet the compressions of the sound wave from the other speaker.

A longitudinal wave propagates by means of compressions and rarefactions. When a vibrating object motions forward, it shoves and compresses the air in a veneer of it building a region of high pressure. When a sound wave travels through a medium, say air, the particles of the medium disturb in the same fashion, i.e. compression and rarefaction. Compression is illustrated for the longitudinal waves in which the particles come nearer such that it is at high pressure.

Rarefaction is specified for the longitudinal waves in which the particles move apart such that it has low pressure.

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Phase states and abrupt changes in temperature. If the temperature it is exposed to changes drastically, a substance may go through a phase shift, changing from a solid to a gas or from a gas to a solid.

A solid can sublimate, or phase transition from a solid to a gas without ever existing as a liquid, if the temperature around it rises very quickly.

When bonds between molecules or atoms are created, disrupted, or both, chemical changes result. This implies that a substance with a particular set of properties such as melting point, colour, flavor, etc. becomes a substance with a different set of characteristics.

Physical alterations can often be reversed more easily than chemical changes. The condition in which a substance is in can be substantially influenced by its temperature. Matter might be in a solid, liquid, or gaseous form. Every material in the universe has a specific temperature threshold that, when crossed, causes a phase transition that alters the state of the substance. When matter absorbs or loses energy, its states change.

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To start and stop an item in motion, according to Newton's First Law of Motion, requires a force.

Newton's first law encapsulates the idea that an object's velocity only changes in response to a force. Unless acted upon by a net external force, Newton's first law states that an object at rest will remain at rest and an object in motion will continue to move at a constant speed.

Unless acted upon by a net external force, Newton's first law states that an object at rest will remain at rest and an object in motion will continue to move at a constant speed.

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A heavier object go down a ramp at a same pace as a lighter object go down a ramp because of gravitational force acting on it in a major form and the rolling tangential force acting on it in a smaller manner..

Rolling motion happens when an object roll over from a ramp or any other sloppy surface whether it is rough or smooth. many forces act on it at the same moment. also in many forces rolling tangential force and gravitational force is also acting on it at the same moment. in which the gravitational force is acting on it at a bigger pace and plays an important role in rolling of the object from the ramp or any other sloppy surface. hence, by this information we can firmly consider that a heavier object go down a ramp at a same pace as a lighter object go down a ramp because of gravitational force acting on it in a major form.

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The speed a satellite fall towards Earth compares to the speed it is moving forward If the speed drops, it will fall toward the earth.

We can say that satellite speed has a significant impact on satellite motion because if a satellite's speed is reduced by half, it will fall towards the earth because it is drawn in by the earth's gravitational pull. However, if a satellite's speed is doubled, it will travel into space because the earth's gravitational pull will no longer hold it in orbit.

When a satellite is moving quickly, the force of gravity may not be able to hold it in orbit. If it moves slowly, it won't make enough progress to resist gravity's pull and collide with the object it is orbiting.

Rockets are used to put the majority of satellites into orbit. When the pull of Earth's gravity and the satellite's speed are equal, the satellite circled the planet. Without this equilibrium, the satellite would either fall back to Earth or shoot off into space in a straight path.

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Two physics concepts that interact with one another to keep a satellite in orbit are the gravitational force and the centrifugal force.

The apparent outward force that a rotating mass experiences is known as centrifugal force. Imagine a ball being whirled around on a string or the outward motion you experience when driving around a curve. Since the system is not rotating in an inertial frame, there is no outward acceleration. The ball or your body just continues to go in the same direction that they did at first. However, they seem to be accelerating away in the rotating reference frame of the string or the car. The direction of centrifugal force is always outward and away from the axis because the Earth revolves around a fixed axis. Thus, in the equator and at the poles of the Earth, it is the opposite of the direction of gravity.It is zero at the poles of the Earth.

One of the four fundamental forces of the universe is gravity. A centripetal force is necessary in nonlinear motions like the planetary motion. In the study of disciplines like astronomy, physics, space exploration, cosmology, and many others, both of these forces are crucial.

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If Jada has 25 dimes, she has 10 quarters .

Dime is a coin from the United States or Canada which has value of ten cents.

And. quarter is a coin from the United States or Canada which has value of twenty five cents.

Jada has 25 dimes .

Now, we know that 1 dime is equals to 10 cents.

Hence, Jada has = 25 × 10 cents = 250 cents.

Again we know that 1 quarter is worth 25 cents.

So, Jada has = (250 ÷ 25) quarters

= 10 quarters.

Hence, she has 10 quarters.

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A low bandwidth will result in a high ping (delay) and, most likely, lag while you're playing. It will also affect how quickly data is delivered and then received.

Because of the temporal lag caused by high latency, gaming might be much less enjoyable. It is essential because low latency allows for more fluid gameplay. Typically, a latency (or ping) of 40–60 milliseconds (ms) or less is considered to be acceptable.

Your website resources will load more quickly if server latency is reduced, which will also improve the time it takes for visitors to load all of your pages.

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The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of the Barbie = 0.23 kg.

Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.

Acceleration due to gravity: g = 32.17 ft/s²

Hence, the speed of the Barbie at the bottom of the path = √(2gh)

= √( 2 × 32.17 ×11.92) ft/s

= 27.69 ft/s.

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Answer:

Explanation:

Gases move from high-pressure areas to low-pressure areas. And the bigger the difference between the pressures, the faster the air will move from the high to the low pressure. That rush of air is the wind we experience.

Answer:

points are needed

Explanation:

The magnitude of the net acceleration of the pillow is 3.333 m/s^2 .

To determine the magnitude of the net acceleration of the pillow, we can use Newton's Second Law of Motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration:

Fnet = ma

where

Fnet = net force acting on the pillow

m = mass of the pillow (0.30 kg)

a = acceleration of the pillow

Fnet = FStephanie - FEileen = 10 N - 11 N = -1 N

So, the net force acting on the pillow is -1N

Now, we can use Newton's Second law to find the acceleration of the pillow

a = Fnet/m = -1 N / 0.3 kg = -3.333 m/s^2

Therefore, the magnitude of the net acceleration of the pillow is 3.333 m/s^2 .

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The distance between the Naval Navigator and the sunken cargo was found to be 2175 m by using sonar with 120kHz frequency and a wavelength of 3mm.

Sonar is largely used by NOAA scientists to create nautical charts, find underwater navigational hazards, find and map things on the bottom like shipwrecks, and map the actual seafloor. Sonar comes in active and passive varieties.

Speed of sound in water  =1450m/s

Time lag between transmission and reception of Sonar waves =3 s

sound waves travel a distance is twice the distance between the navigator and cargo (2S) in this time lag.

Time taken for the sound to reach the submarine  = 1/2 ×3 = 1.5s

Distance between the Navigator and the sunken cargo, S=1450×1.5s =2175m.

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Answer:

Magnitude of the change in momentum = 0.45kgms-1

Force exerted = 1.13N

Explanation:

The magnitude of the change in momentum of the fly can be calculated using the equation Δp = mv, where m is the mass of the fly and v is the velocity of the fly. In this case, the fly has a mass of 0.30g and an initial velocity of 1.5ms-1. Therefore, the change in momentum of the fly is

Δp = (0.30g) x (1.5ms-1) = 0.45kgms-1.

The average force exerted by the web on the fly can be calculated using the equation F = Δp/Δt, where F is the average force, Δp is the change in momentum of the fly, and Δt is the time taken for the fly to come to rest. In this case, the change in momentum of the fly is 0.45kgms-1 and the time taken for the fly to come to rest is 0.40s. Therefore, the average force exerted by the web on the fly is

F = (0.45kgms-1)/(0.40s) = 1.13N.

According to Ohm's Law, the total current flowing through a circuit with a resistance of 1200 ohms and a 12 V power supply is equal to 0.01 ampere.

Electric current is inversely correlated with resistance according to Ohm's Law and proportionate to voltage. 'The law can be expressed mathematically as V = IR, in which 'V' is the voltage variation 'I' is the flowing current in amps, & the resistance (R) in ohm.

Given data :

Resistance = 1200 ohm

power supply = 12 V

By using Ohm's law

V = I × R

I = V / R

I = 12 / 1200

I = 0.01 ampere.

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The changes in the momentum of the ball and the time over which that change occurs. The formula for average force is: average force = change in momentum/time.

Given: The ball's mass is 0.144 kilogram.

speed v = 38 m/s, shift in momentum presently

P = m v- ( - mv) ( - mv)= 2 mv

=2 x (0.144) x (38) (38)

= 10.944 kg-m/s

t Impulse J=F.

The impulse is equivalent to the change in momentum.

J = 10.944 kg-m/s

Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two different objects combined.

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Pitch a baseball horizontally at 38.0 m/s weighing 0.144 kg. The baseball moves in the opposite direction and at the same speed after being struck by the bat. What is the ball's change in momentum? What kind of impetus does the bat deliver? What was the average force the bat applied to the ball during the 0.80 milliseconds that they were in contact?

We know that momentum is defined as the product of mass and velocity, hence p = 0.025 kg x 0.1 m/s or p = 0.0025 kg m/s. Therefore, the bullet's momentum is equal to 0.0025 kg/s.

The ability of a gun to cause such substantial damage is due to the momentum that the gun imparts to the projectile. An object's momentum is equal to its mass times its velocity. Making a thing more large or moving more quickly can increase its momentum and, thus, its capacity for destruction. The force acting on both is therefore the same, but the rifles have smaller recoils since their mass is higher than that of the bullet, which results in a reduced recoil compared to the bullet's speed.

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The total kinetic energy gained by the object when accelerating a 20-n object from rest across a horizontal frictionless table is 10.0 J.

To determine the total kinetic energy gained by the object, we can use the work-energy principle, which states that the work done on an object is equal to the change in kinetic energy of the object.

Work done = change in kinetic energy

W = Kf - Ki

where

W = work done (10.0 J)

Kf = final kinetic energy

Ki = initial kinetic energy (0 J, since the object is at rest)

Given the information provided, we know that a total of 10.0 J of work is done in accelerating the 20-n object from rest.

So,

Kf = W + Ki

Kf = 10.0 J + 0 J

Kf = 10.0 J

Therefore, the total kinetic energy gained by the object is 10.0 J

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The battery current is I=9.14A

As per the details share in the above question are as bellow,

The details provided are,

Let us suppose that the current I is flowing through the battery.

The resistor are connected in parallel. i.e

[tex]$3 \Omega$[/tex] and [tex]$5 \Omega$[/tex].

Hence,

[tex]3 \Omega \| 5 \Omega & =\frac{3 \Omega \times 5 \Omega}{3 \Omega+5 \Omega}[/tex]

Further solving it we get,

[tex]& =\frac{15}{8} \Omega[/tex]

The resistor are connected in parallel. i.e

[tex]$3 \Omega$[/tex] and [tex]$1 \Omega$[/tex] .

Hence,

[tex]3 \Omega \| 1 \Omega & =\frac{3 \Omega \times 1 \Omega}{3 \Omega+1 \Omega}[/tex]

Further solving it we get,

[tex]& =\frac{3}{4} \Omega[/tex]

The series sum of the total equivalent resistance is  [tex]\frac{15}{8}[/tex]Ωand [tex]$\frac{3}{4} \Omega$[/tex] resistors.

[tex]R_{e q} & =\frac{15}{8} \Omega+\frac{3}{4} \Omega \\[/tex]

Adding the rational number we get,

[tex]& =\frac{15+6}{8}[/tex]

Further solving it we get,

[tex]& =\frac{21}{8} \Omega[/tex]

Identify the battery current value.

[tex]& \mathrm{I}=\frac{V}{R_{e q}}[/tex]

Substitute the value in above equation we get,

[tex]& \mathrm{I}=\frac{24}{\left(\frac{21}{8}\right)}[/tex]

Further solving it we get,

I=9.14A

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Note: The diagram of the question is added bellow,

According to the kinetic theory of matter, changes in heat energy allow for phase transitions between solids, liquids, and gases.

When something is heated, the particles inside move faster and have more energy. When an object warms up, its atoms and molecules gain kinetic energy. When something is heated, its constituent atoms or molecules accelerate in their motion. Matter's kinetic energy can be quickly and easily increased.

When an object warms up, its atoms and molecules gain kinetic energy. The atomic or molecular motions of matter increase with temperature. Lifting a particle's kinetic energy is a breeze. When a substance absorbs heat, the inter-particle bonds in it weaken and break, resulting in a phase transition. If the particles aren't moving faster, there can't be any more heat. 

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1.7×10^2 m

The student was 1.7×10^2 m far from the speaker.

The distance that sound waves travel is mostly influenced by the temperature and pressure of the ocean, even though sound travels through water at a far faster rate than it does through air.

The change in pressure that a sound wave causes when it is measured at a particular location is related to the amplitude of the wave. If the amplitude grows, the sound is heard as louder, and if it drops, it is heard as quieter.

The pace at which a wave moves has nothing to do with its amplitude. Waves A and B move forward at the same speed. Only changes in the characteristics of the medium a wave travels through can change its speed.

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To calculate the distance between the loudspeaker and the student, we can use the speed of sound in air, which is approximately 340 meters per second (m/s) at standard temperature and pressure (STP).

The formula to calculate distance is:

distance = speed x time

where distance is the distance between the loudspeaker and the student, speed is the speed of sound in air, and time is the delay that was observed between the time the sound wave left the loudspeaker and the time it reached the student.

distance = 340 m/s x 0.50 s

distance = 170 m

So, the distance between the loudspeaker and the student is 170 meters.

This answer corresponds to (2) 91.7 x 102m.

It's worth mentioning that sound speed can be affected by temperature, humidity, and atmospheric pressure which can cause slight variations from the standard 340 m/s at STP.

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W=mg=(3)(9.8)=29.4N is the balance measurement for an airborne body. Scales of this kind include spring balances and newtons meters. They are frequently used to gauge the amount of force applied to an object.

The spring balance operates according to Hooke's law. According to Hooke's law, a material's strain will increase in direct proportion to its applied stress up to its elastic limit.

A straightforward and affordable way of measuring mass is offered by spring balances. The mass is suspended from a spring, and the spring's bending caused by the mass's downward gravitational pull is gauged against a scale.

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According to reports, the biggest meteorite with lunar origin weighs 19 g. If the meteorite placed on a scale whose spring constant is 83 N/m, 0.22 m is the compression of the spring.

We can use Hooke's Law to calculate the compression of the spring caused by the meteorite. Hooke's Law states that the force exerted on a spring is directly proportional to the spring's compression or extension.

= F

= k * x

where F is the force (in newtons), k is the spring constant (in N/m), and x is the compression (in meters).

Given the mass of the meteorite is 19 g and the spring constant is 83 N/m, the force exerted on the spring can be calculated as

= F

= (mass of the meteorite) * g

= (19 g) * (9.8 m/s^2)

The compression of the spring can be found by rearranging Hooke's Law and substituting in the force and spring constant

x = F/k

x = (19 * 9.8) / 83

x = 0.22 m

The compression of the spring caused by the meteorite is 0.22 m.

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The work performed by a battery is 310 J according to the formula W= Pt and the provided data.

The formula for the electrical work is W = Q V. In this case, the electric potential, V, is expressed in volt, the electric charge, Q, is expressed in coulombs, and the work done, W.

The work performed in an electronic circuit may be computed using the formula

W=Pt,

where P=IV is the supplied electrical power and t is the time.

W= Pt =I V t=V²t/ Req

= V²t/ R + r

therefore

W= (12.0V)²(60s)/21.0Ω+3.00Ω

= 310 J

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Arc bursts, electrical burns, and electric shock are the three basic categories of electrical risks (the effect of blasts).

Live wire contact can result in electric shock and burns.

fires caused by poor wiring.

circuits that are overloaded

Leave electrical components unprotected.

due to a lack of PPE, electrocution or burns.

explosive and flammable materials causing explosions and fires.

exposure to electricity wires above.

A reaction to an electric current running through the body is shock.

Burns are brought on by arc flashes and blasts of strong light.

Old wiring, wires, and switches can cause fires, as can malfunctioning outlets.

When explosive substance in the air is ignited by electricity, an explosion occurs.

The primary concerns connected to them are: contact with exposed live parts causing electric shock and burns (for example, exposed leads or other electrical equipment coming into contact with metal surfaces like metal flooring or roofs); and failures that could result in fires.

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According to the above statement, 15800 N of tension is required to draw a cable at 3.0 m/s² of acceleration.

A force known as tension is connected here to tugging of an item like the a rope, cord, or chain. It resembles elastic potential energy a lot. When a thing is pulled out and brought under tension, as soon as that force is removed, it will naturally recover to its relaxed length.

F = ma

  = 2000 kg × 3.0 m/s²

  = 6000 N.

The body's weight and the load are added to create the tension force.

Thus T = w + ma

T = 9800 N + 6000 N

  = 15800 N.

As a result, 15800 N of tension is required to draw a wire at 3.0 m/s² of acceleration.

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The complete question is-

A 2000 kg elevator is accelerated upward at a rate of 3.0 m/s2. What is the tension in the cable pulling the elevator upward when it experiences this acceleration?

The types of microscopes that reveals the surface features of small molecules is an atomic force microscope.

The Atomic Force Microscope (AFM) is useful for imaging the surface topography of living, soft materials in their natural settings. It can be used to examine the inherent elastic modulus and receptor-ligand interactions of cells and extracellular matrix, among other mechanical properties. SEM pictures can investigate surface features that are several tenths of a nanometer in size, but AFM resolution is less than 0.1 nm. As a result, AFM can discern objects on flat surfaces with molecular dimensions.

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Two spherical objects have masses of 8000 KG and 1500 KG their centers are separated by a distance of 1.5 M, the gravitational attraction between them is 3.56 × 10⁻⁴N.

The gravitational force, also known as gravity, pulls objects with mass in the same direction. We frequently think about the Earth's gravitational pull. This force is firmly holding your body in place. But every mass-bearing object attracts other mass-bearing objects toward it through gravity.

Using the formula of gravitational attraction

F = G× M₁M₂/d²

where G = 6.67 × 10⁻¹¹ Nm²Kg⁻²

M₁ = 8000Kg

M₂ = 1500 Kg

F =  6.67 × 10⁻¹¹ × 8000 × 1500 / (1.5)²

F = 3.56 × 10⁻⁴ N

The gravitational force of attraction between them is 3.56 × 10⁻⁴ N.

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