Suppose the concentration of glucose inside a cell is 0.1 mM and the cell is suspended in a glucose solution of 0.01 mM.Part A) What would be the free energy change involved in transporting 10−6 mole of glucose from the medium into the cell? Assume T= 37 ∘C. Answer: 5.93×10−6 kJPart B) What would be the free energy change involved in transporting 10−6 mole of glucose from the medium into the cell if the intracellular and extracellular concentrations were 1 mM and 10 mM, respectively? Answer: -5.93×10−6 kJPart C) If the processes described in parts A and B were coupled to ATP hydrolysis, how many moles of ATP would have to be hydrolyzed in order to make each process favorable? (Use the standard free energy change for ATP hydrolysis.)

Upon addition of iron, the equilibrium will shift toward forward according to Le Chatelier’s principle in the reaction 4 Fe (s) + 3 O[tex]_2[/tex] (g) →2 Fe[tex]_2[/tex]O[tex]_3[/tex] (S)

Equilibrium is commonly characterized as a condition of rest in which no change occurs. A body in equilibrium will have no negative or positive energy exchanges.

The equilibrium state is defined differently in biology, physics, and chemistry. However, the underlying principle remains the same. External forces will have little effect on an organism that is in balance. Upon addition of iron, the equilibrium will shift toward forward according to Le Chatelier’s principle in the reaction 4 Fe (s) + 3 O[tex]_2[/tex] (g) →2 Fe[tex]_2[/tex]O[tex]_3[/tex] (S)

Therefore, upon addition of iron, the equilibrium will shift towards forward according to Le Chatelier’s principle.

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2.20×10²³ atoms are in 3.65 mol of titanium. Therefore, the correct option is option B among all the given options.

Titanium has the chemical symbol Ti and the atomic number 22. It is only found in nature as an oxide, but it may be reduced to form a beautiful transition metal with such a silver hue, low density, as well as high strength that is corrosion resistant in sea water, aqua regia, as well as chlorine.

number of atoms = number of mole× 6.022×10²³  

substituting all the given values in the above equation, we get      

number of atoms = 3.65 mol× 6.022×10²³  

                             = 2.20×10²³   atoms

Therefore, the correct option is option B.

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"Hydrogen bonds occur when partially positive hydrogen atoms attract partially negative atoms nearby. Examples include the bonds between water molecules, ammonia molecules, and DNA base pairs."

Hydrogen bonds are a type of intermolecular force that occurs when a hydrogen atom that is covalently bonded to an electronegative atom (such as nitrogen, oxygen, or fluorine) interacts with another electronegative atom nearby.

The hydrogen atom has a partial positive charge because it is less electronegative than the other atom it is bonded to, while the other atom has a partial negative charge because it is more electronegative.

Hydrogen bonds are important for many biological processes, including the structure of DNA and the properties of water. The bonds between water molecules, for example, are hydrogen bonds that contribute to the high boiling point, surface tension, and other unique properties of water.

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It is false that, At the atomic scale, elastic deformation corresponds to breaking of interatomic bonds whereas plastic deformation corresponds to stretching of interatomic bonds.

What is elastic deformation?

Elastic deformation is the temporary shape change that occurs when a material is subjected to a force. It is a reversible process that returns to its original shape when the force is removed. This type of deformation is seen in materials such as rubber, metal and wood.

Therefore, It is false that, At the atomic scale, elastic deformation corresponds to breaking of interatomic bonds whereas plastic deformation corresponds to stretching of interatomic bonds.

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If 0.8423 g of the ore yielded 0.307 g of MnO precipitate .The percent Mn in the ore is 24.1%.

To determine the percent Mn in the ore, we need to calculate the mass of Mn in the ore and then convert that to a percentage.

First, we'll calculate the mass of Mn in the MnO precipitate:

Mass of Mn = 0.307 g MnO * (1 mol MnO / 70.9 g MnO) * (1 mol Mn / 1 mol MnO) * (54.9 g Mn / 1 mol Mn)

Mass of Mn = 0.203 g Mn

Next, we'll divide the mass of Mn in the ore by the total mass of the ore and multiply by 100 to get the percentage:

Percentage = (0.203 g Mn / 0.8423 g ore) * 100

Percentage  = 24.1% Mn

Therefore the percent Mn in the ore is 24.1%.

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The reagent that can be used to convert nitrobenzene to m-nitrobenzenesulfonic acid is (A) H2SO3.

The conversion of nitrobenzene to m-nitrobenzenesulfonic acid involves the introduction of a sulfonic acid group (-SO3H) at the meta position of the benzene ring. This can be achieved by treating nitrobenzene with a sulfonating agent such as sulfuric acid (H2SO4) or sulfuryl chloride (SO2Cl2).

However, in the given options, only reagent (A) H2SO3 is a sulfonating agent. When nitrobenzene is treated with H2SO3, it undergoes sulfonation at the meta position to form m-nitrobenzenesulfonic acid. The reaction can be represented as follows:

NO2C6H5 + H2SO3 → NO2C6H4SO3H + H2O

None of the other reagents listed are capable of sulfonating nitrobenzene to form m-nitrobenzenesulfonic acid.

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Answer: I don't have an answer,

Explanation: You have terrible spelling and pronunciation

a) If the partial pressure of CO2 is increased, the equilibrium will tend to shift towards the formation of products (C6H12O6 and O2) to reduce the concentration of CO2.

(b) If the system is compressed, the equilibrium will tend to shift towards the formation of products (C6H12O6 and O2) to reduce the number of gas molecules.

What is Equilibrium?

In chemistry, equilibrium is a state in a chemical reaction where the rate of the forward reaction is equal to the rate of the reverse reaction. At equilibrium, the concentrations of the reactants and products remain constant over time, although the reactants are still being converted into products and vice versa.

When a system is at equilibrium, the concentrations of reactants and products are said to be in balance. This means that the concentrations of the reactants and products are no longer changing, even though the reaction is still ongoing. At equilibrium, the concentrations of reactants and products are related by a constant called the equilibrium constant (K), which depends on the specific reaction conditions such as temperature and pressure.

c) If the amount of H2O is increased, the equilibrium will tend to shift towards the formation of products (C6H12O6 and O2) to consume the excess water.

(d) If the temperature is increased, the equilibrium will tend to shift towards the formation of products (C6H12O6 and O2) because the reaction is endothermic and increasing the temperature favors the endothermic reaction.

(e) If some of the O2 is removed, the equilibrium will tend to shift towards the formation of products (C6H12O6 and O2) to compensate for the loss of O2.

(f) If water is added, the equilibrium will tend to shift towards the formation of reactants (CO2 and H2O) to consume the excess water.

(g) If the partial pressure of O2 is decreased, the equilibrium will tend to shift towards the formation of reactants (CO2 and H2O) to compensate for the loss of O2.

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Answer:

the Ka value for the weak acid HA is 1.18 x 10^(-7).

Explanation:

The pH of a weak acid solution can be related to the dissociation constant, Ka, of the acid through the following equation:

pH = pKa + log([A-]/[HA])

where pH is the measured pH of the solution, pKa is the negative logarithm of the acid dissociation constant, [A-] is the concentration of the conjugate base of the acid, and [HA] is the concentration of the undissociated acid.

In this problem, we are given the pH and the concentration of the weak acid, HA. We need to find the value of Ka.

First, we can rearrange the above equation to solve for pKa:

pKa = pH - log([A-]/[HA])

Next, we need to find the concentration of the conjugate base, [A-]. Since HA is a weak acid, we can assume that only a small fraction of it has dissociated into A- and H+ ions. At equilibrium, the concentration of A- can be assumed to be equal to the concentration of H+ ions produced by the dissociation of HA. We can calculate this concentration from the pH:

[H+] = 10^(-pH) = 10^(-3.65) = 2.24 x 10^(-4) M

Therefore, [A-] = 2.24 x 10^(-4) M.

We can now substitute the values we have calculated into the equation for pKa to obtain:

pKa = 3.65 - log(2.24 x 10^(-4)/0.30) = 3.65 + 2.47 = 6.12

Finally, we can calculate the Ka value from the pKa:

Ka = 10^(-pKa) = 10^(-6.12) = 1.18 x 10^(-7)

Therefore, the Ka value for the weak acid HA is 1.18 x 10^(-7).

Answer:

the Key value for the weak acid HA is 1.18 x 10^(-7).

Explanation:

The pH of a weak acid solution can be related to the dissociation constant, Key, of the acid through the following equation:

pH = pKa + log([A-]/[HA])

where pH is the measured pH of the solution, pKa is the negative logarithm of the acid dissociation constant, [A-] is the concentration of the conjugate base of the acid, and [HA] is the concentration of the UN dissociated acid.

In this problem, we are given the pH and the concentration of the weak acid, HA. We need to find the value of Ka.

First, we can rearrange the above equation to solve for pKa:

pKa = pH - log([A-]/[HA])

Next, we need to find the concentration of the conjugate base, [A-]. Since HA is a weak acid, we can assume that only a small fraction of it has dissociated into A- and H+ ions. At equilibrium, the concentration of A- can be assumed to be equal to the concentration of H+ ions produced by the dissociation of HA. We can calculate this concentration from the pH:

[H+] = 10^(-pH) = 10^(-3.65) = 2.24 x 10^(-4) M

Therefore, [A-] = 2.24 x 10^(-4) M.

We can now substitute the values we have calculated into the equation for pKa to obtain:

pKa = 3.65 - log(2.24 x 10^(-4)/0.30) = 3.65 + 2.47 = 6.12

Finally, we can calculate the Ka value from the pKa:

Ka = 10^(-pKa) = 10^(-6.12) = 1.18 x 10^(-7)

Therefore, the Ka value for the weak acid HA is 1.18 x 10^(-7).

The chemical names are, K: Potassium, Mn: Manganese, Ge: Germanium, Kr: Krypton.

Chemical symbols are shorthand notations used to represent the chemical elements in a concise and standardized manner. They consist of one or two letters, usually derived from the name of the element, and are used in chemical formulas, equations, and other types of chemical notation.

For example, the symbol K represents the element potassium, which has an atomic number of 19 and a chemical symbol of K derived from its Latin name kalium. Similarly, Mn represents the element manganese, which has an atomic number of 25 and a symbol derived from its Greek name magnesia.

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--The complete question is, The chemical symbols of several elements are provided. Give the corresponding name of the element.

K

Mn

Ge

Kr--

Nitrogen is indeed a nonmetal as well as the lightest member of Periodic Table. 0.016mol of N[tex]_2[/tex] will be produced.

Nitrogen has the chemical symbol N and the atomic number 7. Nitrogen is indeed a nonmetal as well as the lightest member of Periodic Table Group 15, often known as the pnictogens. This is a common element inside the cosmos, with an estimated total abundance of sixth in the Milky Way.

NaNO[tex]_2[/tex](aq) + H[tex]_2[/tex]NSO[tex]_3[/tex]H(s) → NaHSO[tex]_4[/tex](aq) + N[tex]_2[/tex](g) + H[tex]_2[/tex]O(l)

moles of H[tex]_2[/tex]NSO[tex]_3[/tex]H = 1.627 /97.09=0.016mol

the mole ratio between H[tex]_2[/tex]NSO[tex]_3[/tex]H and N[tex]_2[/tex] is 1:1

moles of N[tex]_2[/tex] =0.016mol

Therefore, 0.016mol of N[tex]_2[/tex] will be produced.

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The given statement "A neutral atom of the element given by the symbol ca will to become an ion with a complete outer shell " is true because this is to complete the octet rule.

The atomic number of the calcium, Ca is 20. The neutral calcium atom, has the  20 protons and the 20 electrons, and it readily loses the two electrons. This will results in the cation with the 20 protons, the 18 electrons, with the charge of  2+ charge. Calcium has the same number of the electrons as the atoms of the preceding the noble gas, the argon, and the symbol is  Ca²⁺. The calcium ion is more stable than the calcium neutral atom.

Thus ca loose the 2 electrons and acquire the noble gas configuration to become more special.

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The 4 species below which specify the hydrogen bonding behavior are:

Water (H2O): both (acts as both donor and acceptor)

Methanol (CH3OH): both (acts as both donor and acceptor)

Ammonia (NH3): donor (acts as a donor only)

Carbon dioxide (CO2): neither (does not act as a donor or acceptor)

Hydrogen bonding is a type of intermolecular force that occurs between a hydrogen atom bonded to a highly electronegative atom such as nitrogen, oxygen, or fluorine, and an electronegative atom in a nearby molecule.

The hydrogen atom has a partial positive charge due to the electronegativity difference between the bonded atoms, and the electronegative atom in the nearby molecule has a partial negative charge. These opposite charges attract each other, forming a relatively strong electrostatic interaction called a hydrogen bond.

Hydrogen bonding is responsible for many important properties of substances, including the high boiling and melting points of water, the high heat of vaporization of water, and the unique structure and properties of biomolecules such as DNA and proteins.

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NaCl, KOH, C5H5, C6H24, KNO3, Na2SO4, CH2CH2OH are highly soluble in water and CHCl3, CH2OH, CCl4, CH2Cl2, CH3COOH, and CH3(CH2)5OH are either slightly soluble or insoluble in water.

The solubility of a compound in water refers to the ability of that compound to dissolve in water. Compounds that are highly soluble in water can easily dissolve in water, while those that are slightly soluble or insoluble cannot dissolve or dissolve only to a limited extent.

The solubility of a compound in water depends on several factors, including the chemical structure of the compound, the temperature and pressure of the solvent, and the presence of other solutes in the solvent.

Some common examples of highly soluble compounds in water include ionic compounds such as sodium chloride and potassium hydroxide, while nonpolar compounds such as chloroform and carbon tetrachloride are generally insoluble in water.

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24940 kcal ,calories of heat (energy) would it take to heat 23.0 g of water from 35.0 °C to 59.0 °C.

Calories are the amount of energy released when your body breaks down (digests and absorbs) food. The more calories a food has, the more energy it can provide to your body. When you eat more calories than you need, your body stores the extra calories as body fat.

Moderate aerobic exercise includes activities such as brisk walking, biking, swimming and mowing the lawn. Vigorous aerobic exercise includes activities such as running, heavy yardwork and aerobic dancing. Strength training. Do strength training exercises for all major muscle groups at least two times a week.

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The statement that is accurately describes the changes in the sample of copper when it is warmed from the room temperature to 95° Celsius is the correct option is c. The sample will expand.

The density is expressed as follows :

The Density = mass / volume

The density is define as the mass of the sample per unit volume. It is clear from the above equation that the density is directly proportional to the mass and the volume is inversely proportional to the density. Therefore the sample will expand if the density of the sample decreases as the temperature increases.

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This question is incomplete, the complete question is :

The density of copper decreases as temperature increases. Which statement accurately describes the changes in a sample of copper when it is warmed from room temperature to 95° Celsius?

a. The sample will become lighter.

b. The sample will become heavier.

c. The sample will expand.

d. The sample will contract.

1. The mass of magnesium oxide produced would be 6630.5 g.

2. The formula of the iron oxide would be Fe2O3.

1. Calculation of magnesium oxide produced:

The balanced chemical equation for the reaction of magnesium with oxygen is:

2 Mg + O2 → 2 MgO

For 2 g of magnesium:

Number of moles of Mg = mass / molar mass = 2 / 24.31 = 0.082 moles

According to the balanced equation, 2 moles of Mg produce 2 moles of MgO

Therefore, 0.082 moles of Mg will produce 0.082 moles of MgO

Mass of MgO = number of moles of MgO * molar mass of MgO = 0.082 * 40.31 = 3.29 g

For 10 g of magnesium:

Number of moles of Mg = mass / molar mass = 10 / 24.31 = 0.411 moles

According to the balanced equation, 2 moles of Mg produce 2 moles of MgO

Therefore, 0.411 moles of Mg will produce 0.411 moles of MgO

Mass of MgO = number of moles of MgO * molar mass of MgO = 0.411 * 40.31 = 16.54 g

For 4 kg of magnesium:

Number of moles of Mg = mass / molar mass = 4000 / 24.31 = 164.5 moles

According to the balanced equation, 2 moles of Mg produce 2 moles of MgO

Therefore, 164.5 moles of Mg will produce 164.5 moles of MgO

Mass of MgO = number of moles of MgO * molar mass of MgO = 164.5 * 40.31 = 6630.5 g or 6.63 kg

2. Calculation of formula of iron oxide produced:

The balanced chemical equation for the reaction between iron and oxygen is:

4 Fe + 3 O2 → 2 Fe2O3

According to the equation, 4 moles of Fe react with 3 moles of O2 to produce 2 moles of Fe2O3. Therefore, the molar ratio of Fe to O2 is 4:3.

Given that 0.4 moles of Fe react with 0.3 moles of O2, the ratio of Fe to O2 in the reaction is:

Fe:O2 = 0.4/0.3 = 4/3

This ratio is equivalent to the molar ratio in the balanced equation, which means that the reaction produces the stoichiometric amount of Fe2O3. Therefore, the formula of the iron oxide produced is Fe2O3.

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52.057g/mole is the average atomic mass of chromium. The correct option is option C among all the given options.

Meaning of Average Atomic Mass: To be more specific, the average atomic mass is defined as "the sum of the atomic masses of any and all isotopes of a particular element, each calculated by respective natural abundance on Earth." This is a straightforward explanation of average atomic weight.

The mass of such an atom is measured by its atomic weight (ma or m). Although the kilogram (symbol: kg) is the SI unit of mass, atomic mass is frequently stated inside the non-SI unit Dalton (symbol: Da) - equivalently, united atomic mass unit (u).

average atomic mass = 50×4.3 + 52×83.8 + 53×9.5 + 54×2.4= 52.057g/mole

Therefore, 52.057g/mole is the average atomic mass of chromium. The correct option is option C.

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The compound to be purified must be soluble in the hot solvent and insoluble in the cold solvent. This is because during recrystallization, the compound is dissolved in the hot solvent to remove impurities, and then cooled to allow the compound to crystallize out of solution. If the compound is insoluble in the cold solvent, it will form pure crystals while impurities remain in solution. So the correct option is D.

Choosing the right solvent for recrystallization is crucial to ensure that the process is effective in purifying the compound. The solvent must be able to dissolve the compound at high temperatures to remove impurities, but then allow the compound to crystallize out of solution as the solvent cools.

By selecting a solvent in which the compound is soluble at high temperatures but insoluble at low temperatures, pure crystals of the compound can be obtained.

The complete question is given below

"

Which statement below best describes the reasoning behind choosing the most

suitable solvent to purify a sold by recrystalization ? Clearly choose one answer.

a) The compound to be purified must be soluble in both the hot solvent and the

cold solvent.

b) The compound to be purified must be insoluble in both the hot solvent and

the cold solvent.

c) The compound to be purified must be insoluble in the hot solvent and

soluble in the cold solvent.

d) The compound to be purified must be soluble in the hot solvent and

insoluble in the cold solvent.

"

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The number of grams of Al2O3 that can be formed if 12.5 g of O2 reacts completely with aluminum is 26.6 g.

The balanced chemical equation for the reaction is:

4Al + 3O2 -> 2Al2O3

From above,

We can conclude that,

4 moles of Al react with 3 moles of O2 to produce 2 moles of Al2O3.

Now using the above expression for calculating the number of moles of Al2O3 that can be produced from 12.5 g of O2.

For finding the number of moles, converting the mass of O2 to moles using its molar mass:

molar mass of O2 = 32.00 g/mol

moles of O2 = mass / molar mass = 12.5 g / 32.00 g/mol = 0.391 mol

Next, using the mole ratio from the balanced chemical equation to determine the number of moles of Al2O3 that can be produced:

moles of Al2O3 = (2/3) * moles of O2 = (2/3) * 0.391 mol = 0.261 mol

Now converting the number of moles of Al2O3 to grams using its molar mass:

molar mass of Al2O3 = 101.96 g/mol

So, the value of mass of Al2O3 will be

= moles of Al2O3 * molar mass = 0.261 mol * 101.96 g/mol = 26.6 g

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If you do not quantitatively transfer the solution and there is still some in the graduated cylinder when you obtain the volume in Part D, the resulting calculated density will be too high.

This is because the volume you measure will be lower than the actual volume of the solution, but the mass will remain the same.

Since density is calculated by dividing mass by volume (density = mass/volume), a lower volume will result in a higher calculated density.

Therefore, it is important to accurately transfer and measure the solution in order to obtain an accurate calculation of density.

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The number of the valence electrons for each of the atoms :

B = 3

P = 5

O = 6

Ne = 8

The Valence electrons are the electrons that is in the outermost shell, or energy level, of an atom.  The  valence electron is the electron in the outer shell that is associated with the atom, and that will participate in the formation of the bonds and the compounds.

The atomic number of the boron is 3. The valence electrons are 3 electrons in the outermost shell. The  atomic number of the phosphorus is 5. The valence electrons are 5 electrons in the outermost shell.  atomic number of the oxygen is 6. The valence electrons are 6 electrons in the outermost shell.  The atomic number of the boron is 8. The valence electrons are 8 electrons in the outermost shell.

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From given options, A, B, C, and D are all valid responses because they are all circumstances that can impact an enzyme's activity.

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The false statement is, "Every methane molecule that reacts produces two water molecules." Option a is correct choice.

The balanced equation for the combustion of methane is CH₄ + 2O₂ → CO₂ + 2H₂O. This means that for every molecule of methane that reacts, only two molecules of water are produced, not two molecules of water for every methane molecule. Therefore, the statement that "every methane molecule that reacts produces two water molecules" is false.

Not every methane molecule that reacts produces two water molecules. Rather, for every methane molecule that reacts, two water molecules are produced. So the correct statement would be: For every molecule of CH₄ that reacts, two molecules of H₂O are produced.

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--The complete question is, Which one of the following statements about the following reaction is false? CH₄ + 2O₂ → CO₂ + 2H₂O.

a. Every methane molecule that reacts produces two water molecules.

b. If 32.0 g of oxygen reacts with excess methane, the maximum amount of carbon dioxide produced will be 22.0 g.

c. If 11.2 liters of methane react with an excess of oxygen, the volume of carbon dioxide produced at STP is (44/16)(11.2) liters.

d. If 16.0 g of methane react with 64.0 g of oxygen, the combined masses of the products will be 80.0 g.

e. If 22.4 liters of methane at STP react with 64.0 g of oxygen, 22.4 liters of carbon dioxide at STP can be produced.--

The amount of SO₂(g) in the reaction vessel has a lower value compared to its value at the original equilibrium. Option d is correct choice.

Injecting pure O₂(g) into the reaction vessel at a constant temperature will cause the system to shift towards the right side of the equation in order to consume the added O₂. This means that the amount of SO₂(g) in the reaction vessel will decrease, while the amount of SO₃(g) and O₂(g) will increase.

Since the reaction is exothermic, adding O₂(g) will not change the equilibrium constant (Keq) of the reaction, so (A) is not affected. However, the amount of O₂(g) in the reaction vessel will increase, so (C) has a higher value compared to its value at the original equilibrium.

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--The complete question is, 2SO(g) <-> 2SO₂(g) + O₂(g)

After the eq. represented above is established, some pure O₂(g) is injected into the reaction vessel at a constant temperature. After equilibrium is reestablished, which of the following has a lower value compared to its value at the original equilibrium?

A. Keq for the reaction

B. The amount of SO₃(g) in the reaction vessel

C. The amount of O₂(g) in the reaction vessel.

D. The amount of SO₂(g) in the reaction vessel.--

Answer:

Explanation:

To determine the amount of chlorine needed to make 75.0 grams of C2H2Cl4, we need to balance the chemical equation and then use the molar ratio between the reactants and product to find the amount of Cl2 needed.

The balanced equation is:

2 Cl2(g) + C2H2(g) -> C2H2Cl4(l)

Next, we can use the molar mass of C2H2Cl4 to find the number of moles of C2H2Cl4 produced:

75.0 g C2H2Cl4 x (1 mole C2H2Cl4 / 153.8 g C2H2Cl4) = 0.489 moles C2H2Cl4

Since the balanced equation has a 1:2 ratio of C2H2 to Cl2, this means that we need 2 moles of Cl2 for every mole of C2H2Cl4 produced. Therefore, we will need 2 x 0.489 moles = 0.978 moles of Cl2.

Finally, to find the volume of Cl2 at STP, we can use the ideal gas law:

PV = nRT

Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L-atm/mol-K), and T is the temperature in Kelvin (273 K).

Since the pressure is 1 atm and the temperature is 273 K, we can rearrange the equation to solve for volume:

V = nRT / P = 0.978 moles x 0.0821 L-atm/mol-K x 273 K / 1 atm = 17.1 L

Therefore, 17.1 liters of Cl2 at STP will be needed to make 75.0 grams of C2H2Cl4.

The theoretical yield of lead (II) nitrate obtained from the reaction is 0.50 grams

The theoretical yield of lead (II) nitrate obtained from the reaction can be obtained

PbCO₃ + 2HNO₃ -> Pb(NO₃)₂ + H₂O + CO₂

From the balanced equation above,

267.21 g of PbCO₃ reacted to produce 331.2 g of Pb(NO₃)₂

Therefore,

4.0 g of PbCO₃ will react to produce = (4 × 331.2) / 267.21 = 0.50 g of Pb(NO₃)₂

Thus, we can conclude that the theoretical yield of Pb(NO₃)₂ is 0.50 grams

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