Suppose that for a graduating class of seniors at a local high school, the average GPA is 3.21. The expected mean of the sampling distribution would be 3.21.
What is the average GPA?Generally, This is because the sampling distribution of the mean is a probability distribution of the means of all possible samples of the same size from the same population.
The mean of the sampling distribution is equal to the population mean, in this case, 3.21.
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(2x + 1) (x - 1) solve for X
Put brackets equal 0
(2x + 1) (x - 1) = 0
(2x + 1) = 0
-1, then ÷2
x = - 1/2 or - 0.5
(x - 1) = 0
+1
x = 1
So, x = - 0.5 & x = 1
Hope this helps!
Answer:
x = -0.5
x = 1
Step-by-step explanation:
Hello!
We can set each factor to 0 and solve for x in both.
(2x + 1) = 0There are 2 solutions for x, -0.5 and 1.
A closed box has a square base with side length ll feet and height hh feet. Given that the volume of the box is 29 cubic feet, express the surface area of the box in terms of ll only.
The surface area of the closed box in terms of l only, which has the square base is,[tex]2l^2 + \frac{116}{l}[/tex]
How to determine the surface areaThe volume of cuboid or box can be given as,
Volume = l × b × h
Here, (l) is the length, (b) is the width of the box and (h) is the height of the box.
A closed box has a square base with side length l feet and height h feet. Therefore, the length and width will be the same.
Then the volume of the box is 29 cubic feet. Thus,
29 = l × l × h
29 = [tex]l^2 h[/tex]
[tex]h = \frac{l^2}{29}[/tex]
The surface area of the square base box is,
Area = [tex]2l^2 + 4lh[/tex]
Substitute the value of h
Area = [tex]2l^2 + 4l\frac{29}{l^2}[/tex]
Area = ,[tex]2l^2 + \frac{116}{l}[/tex]
Therefore, the surface area of the closed box in terms of l only, which has the square base is,[tex]2l^2 + \frac{116}{l}[/tex]
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f(x)=2^x. What is g(x)?
The function g(x) is g(x)= (3x)^2
How to solve for g(x)?The complete question is in the image
From the graph in the image, we have:
f(x) = x^2
The function f(x) is stretched by a factor of 3 to form g(x).
This means that:
g(x) = f(3x)
So, we have:
g(x)= (3x)^2
Hence, the function g(x) is g(x)= (3x)^2
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Which of the following lists is in order from smallest to largest? 5/8, 0.6, 6.2%, 2/3, 2/3, 5/8, 0.6, 6.2% 6.2%, 0.6, 5/8, 2/3, 0.6, 6.2%, 5/8, 2/3
Answer:
6.2%, 0.6, 5/8, 2/3
Step-by-step explanation:
For some reason, you have written the same numbers over and over. It looks like there are only really 4 numbers.
I changed each number into a decimal and then compared them.
6.2% to change a percent to a decimal, move the decimal 2 places to the left so 6.2% equals 0.062.
0.6 is already in decimal form
5/8 you divide 5 by 8. Put in your calculator 5 the division symbol and then 8 to get 0.625.
2/3 is 0.6 repeating or 0.66666 forever.
Now compare:
62% = 0.62
0.6
5/8 = 0.625
2/3 = 0.66666...
What can you say about the y-values of the two functions f(x) = 3x² -3 and
g(x) = 2* - 3?
A. g(x) has the smallest possible y-value.
B. The minimum y-value of g(x) approaches -3.
C. f(x) and g(x) have equivalent minimum y-values.
D. f(x) has the smallest possible y-value.
The y-values of the two functions f(x) = 3x² -3 and g(x) = 2* - 3 has the minimum y-value of g(x) approaches -3 and f(x) contains the smallest possible y-value.
What is a function?It exists described as a special kind of relationship and they contain a predefined domain and range according to the function every value in the domain exists connected to just one value in the range.
Given: f(x) = 3x² -3
As we can see in the graph the first term exists 3x² and exists still positive for all x.
The range for f(x) ∈ [-3, ∞)
When x = 0 then f(x) = -3
The above value exists as the smallest possible value on the y-axis.
Given: [tex]g(x) = 2^x - 3[/tex]
[tex]2^x[/tex] exists also a positive quantity and it exists as an exponential function.
The range for the g(x) ∈ (-3, ∞)
It signifies that g(x) never touches the y-axis at -3.
We can express the minimum value of g(x) approaches -3.
Therefore, the correct answer is option B. The minimum y-value of g(x) approaches -3 and option D. f(x) has the smallest possible y-value.
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1
10 ft
Cone 1
2.5 ft
8 ftl
2 ft
Cone 2
Simplify the following
Answer is 6
Firstly changing mixed fraction.
[tex] \frac{3}{2} - \frac{5}{4} + \frac{23}{4} [/tex]
By taking the LCM
[tex] \frac{6 - 5 + 23}{4} [/tex]
-5 + 23 (-) (+) = (-)
[tex] \frac{6 + 18}{4} [/tex]
[tex] \frac{24}{4} [/tex]
[tex]6[/tex]
Hope it helps you, any confusions you may ask!
Answer:
6 (work below)
Step-by-step explanation:
1 1/2 = 3/2
1 1/4 = 5/4
5 3/4 = 23/4
The least common multiple of the denominators is 4, so 3/2 will become 6/4.
6/4 - 5/4 = 1/4 + 23/4 = 24/4 = 6
Brainliest, please :)
please help!!!!!!nnnn
Similar: yes
Similarity statement: [tex]ADCB \sim SVUT[/tex]
Scale factor: 1/3
the radius of the base is 4 inches and its height is 6 inches what is the surface area of the cylinder in terms of pi
find the product xy if
2^(x)+3^(y)=5,
2^(x+2)+3^(y+1)=18
The solution to the system of equation is (0, 1)
System of equationsGiven the following system of equation as shown below
2^(x)+3^(y)=5,
2^(x+2)+3^(y+1)=18
Rewrite
2^(x)+3^(y)=5,
2^x*2^2 + 3^y*3^1 = 18
___________
2^(x)+3^(y)=5,
4(2^x) + + 3(3^y) = 18
Let a = 2^x and b = 3^y
Substitute
a + b = 5
4a + 3b = 18
a = 5 - b
Substitute
4(5-b) + 3b = 18
20 - 4b + 3b = 18
-b = -2
b = 2
since a = 5 - b
a = 5 - 2
a = 3
Recall that a = 2^x and b = 3^y
2^x = 2
x = 0
Similarly
3^y = 3
y =1
Hence the solution to the system of equation is (0, 1)
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Find the constant of variation when t varies directly as the square of s, and t = 64 when S = 4.
Answer:
The constant of variation is 4
Step-by-step explanation:
We are looking for the constant of variation when t varies directly as the square of s
t = k s^2 where k is the constant of variation
t = 64 and s = 4
64 = k 4^2
64 = k * 16
Divide each side by 16
64/16 = k * 16/16
4 = k
The constant of variation is 4
Suppose that the breaking strength of a rope (in pounds) is normally distributed, with a mean of 100 pounds and a standard deviation of 16. What is the probability that a certain rope will break before being subjected to 120 pounds? (You may need to use the standard normal distribution table. Round your answer to four decimal places.)
The probability that a certain rope will break before being subjected to 120 pounds is 89.4%.
What is the probability that a certain rope will break before being subjected to 120 pounds?The probability is calculated as follows:
Mean = 100
Standard deviation = 16
The probability is obtained from the z-score.
x = mean + z-score * standard deviation
120 = 100 + z-score * 16
z-score = 20/16
z-score = 1.25
From normal distribution table, the probability with a z-score of 1.25 is 89.4%
In conclusion, the probability is obtained from the z-score.
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A tower is composed of a prism with a square base and a pyramid. The base length is 20 meters, and the height of the prism is 40 meters, while the slant height of the pyramid is 10√2 meters. What is the total surface area, including the bottom base? 400√2 + 3,600 m2 200√2 + 3,600 m2 400√2 + 400 m2 4000√2 m2
The total surface area of the tower composed of a prism with a square base and a pyramid is 3600 + 400√2 m²
How to find the surface are of a composite figure?Total surface area of the tower = area of the base + 4(area of the rectangular surface) + 4(area of the triangular surface)
Therefore,
area of the base = 20² = 400 m²
4(area of the rectangular surface) = 4(40 × 20) = 3200 m²
4(area of the triangular surface) = 4(1 / 2 × 10√2 × 20) = 4(100√2) = 400√2 m²
Therefore,
total surface area = 400 + 3200 + 400√2
total surface area = 3600 + 400√2 m²
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Answer:
a)400V2 plus 3,600 m2
Step-by-step explanation:
Circles A circular device has a diameter of 4.5 inches. What is the radius of the device? Choose one 2 points O2.25 inches O4.5 inches O 4.5 inches O 2.25 inches 10 CO D
Answer: 2.25 inches
Step-by-step explanation:
The radius of a circle is half the diameter.
Please tell me fast I am on a time crunch
Assume that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12. Compute the probability P(X < 105).
The probability P(X < 105), assuming that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12 is calculated to be 0.8944.
When a random variable X is normally distributed, with the mean as μ, and standard deviation as σ, then the probability P(X < x) is calculated using the Z-score table, as the probability P(Z < z), where z is calculated using the formula, z = (x - μ)/σ.
In the question, we are asked to find the probability P(X < 105), assuming that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12.
We calculate as follows:
P(X < 105)
= P(Z < (105-90)/12)
= P(Z < 1.25)
Now we check the z-score table for the value of z as 1.25.
On the left column we choose the value 1.2.
On the top row, we choose the value .05.
The intersection of these, gives us the value,
P(Z < 1.25) = 0.8944.
Thus, the probability P(X < 105), assuming that the random variable X is normally distributed, with mean μ = 90 and standard deviation σ = 12 is calculated to be 0.8944.
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x is directly proportional to y. When x = 4, y = 7. Work out the value
of y when x = 12
Answer:
y = 21
Step-by-step explanation:
When x is directly proportional to y:
When x increases, y also increases.
In this case, it is so you write,
1. Write down the formula: y=kx
k being the constant.
Let's use "When x = 4, y = 7" to work out the constant.
2. Substitute the 'when' values: 7=k×4
3. Rearrange to find the constant: 7÷4=k
4. Find k: k=1.75
Now let's see the new problem, 'what is y when x = 12'.
5. Substitute the values now but keep the constant: y = 1.75 × 12
6. Rearrange if needed.
7. Find the missing value: y = 21
Hope this helped and if you require further assistance from me please comment below! :)
Ps: If it was inversely proportional then the formula would be y = k / x
with k still being the constant.
A party platter contains 38 cupcakes: 13 chocolate, 11 yellow, and 14 lemon. You randomly select one cupcake, eat it, then randomly select another cupcake. Find the probability of selecting from the platter a chocolate cupcake and then a yellow cupcake.
The probability of selecting from the platter a chocolate cupcake and then a yellow cupcake is 0.10.
What is the probability?Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
The probability of selecting a chocolate cupcake and then a yellow cupcake = (number of chocolate cupcake / total number of cupcakes) x (number of yellow cupcakes / total number of cupcakes - 1)
(13 / 38) x (11 / 37) = 0.10
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Which function below has the following domain and range?
Domain: {-9, - 5, 2, 6, 10}
Range: { -2, 0, 8}
O {(-9, 10), (-2,8)}
O ((-9, -2), ( – 5, 0), (2, 8), (6, 5), (10, 9))}
O ((-2,-5), (8, 10), (0, 6), (-2, -9), (0, 2)}
O {(2,0), (-5, -2), (10, 8), (6, 0), (-9, -2)}
{(2,0),(-5,-2),(10,8),(6,0),(-9,-2)} is the correct answer (D)
Answer:
(d) {(2, 0), (-5, -2), (10, 8), (6, 0), (-9, -2)}
Step-by-step explanation:
The domain is the list of x-values. The range is the list of y-values. You are looking for the set that matches the given lists.
ChoicesA.The list of x-values is {-9, -2}. The list is too short.
B.The list of x-values is {-9, -5, 2, 6, 10}. This matches the required domain.
The list of y-values is {-2, 0, 8, 5, 9}. The list is too long.
C.The list of x-values is {-2, 8, 0, -2, 0}. The list does not match the given domain list.
D.The list of x-values is {2, -5, 10, 6, -9}. This matches the given domain.
The list of y-values is {0, -2, 8, 0, -2}. This matches the given range.
The function of interest is ...
{(2, 0), (-5, -2), (10, 8), (6, 0), (-9, -2)}
Determine an approximate value for y if the coordinate (-0.5387 ,y) is on the unit circle
Answer:
y = 0.8425 or y = -0.8425
Step-by-step explanation:
All points in the Cartesian coordinate system have an x and y coordinate, defined by two perpendicular measurements.
If the point is on the unit circle, then the radius of the circle is defined to be 1 unit, and the corresponding right triangle follows the Pythagorean Theorem.
[tex]a^2+b^2=c^2[/tex]
For a unit circle:
[tex]x^2+y^2=1^2[/tex]
Substituting the known value for x, and simplifying...
[tex](-0.5387)^2+y^2=(1)^2[/tex]
[tex]0.29019769+y^2=1[/tex]
Subtracting 0.29019769 from both sides to begin to isolate "y"...
[tex]y^2=1-0.29019769[/tex]
[tex]y^2=0.70980231[/tex]
Applying the square root property...
[tex]\sqrt{y^2}=\pm \sqrt{0.70980231}[/tex]
[tex]y=\pm 0.8424976171...[/tex]
So, (to 4 decimal places), the y coordinate could be either 0.8425 or -0.8425.
With only the given information, either result is a valid answer.
On average, an American hummingbird flaps its wings about 3,180 times per minute.
About how many times per second does it flap its wings?
Enter your answer in the box.
times
Answer:
53 times per second
Step-by-step explanation:
There are 60 seconds in 1 minute, so divide the 3180 flaps per minute into 60 equal parts.
3180 / 60 = 53
what is the sum of .74+.19+3.09+1.98=
Answer:
6
Step-by-step explanation:
no calculator at hand ?
really ? you are using us a simple calculator ?
Answer:
6
Step-by-step explanation:
what is the sum of .74+.19+3.09+1.98=
0.74+
0.19+
3.09+
1.98=
-----------------
6
0.1in has 4 threads how many threads are in 1 inch?
Answer:
40
Step-by-step explanation:
Set up a proportion
Inch/ threads = inch to threads
.1/4 = 1/x Cross multiple
.1x = 4 Divide both sides by .1
x = 40
5. a. The area of an isosceles triangle is 60cm² and its base is 10cm. Find the length of its equal side.
Answer:
H = 12cm
b
I hope I was able to help
What is the slope of the line containing (-2, 5) and (4,-4)?
A. 2
OB.
mle
O C. - /3/20
D. -2
Answer:
-1.5
Step-by-step explanation:
To work out the gradient of the line, we use this equation:
[tex] \frac{y2 - y1}{x2 - x1} [/tex]
Substituting in, we get:
[tex] \frac{5 - ( - 4)}{ - 2 - 4} [/tex]
Which simplifies to:
[tex] \frac{9}{ - 6} = \frac{3}{ - 2} = - \frac{3}{2} = - 1.5[/tex]
Suppose that the functions p and q are defined as follows. p(x)=x+1
q(x)=2x^2-2
The value of (p*q)(5) and (q*p)(5) is 288
How to determine the composite functions?The functions are given as:
p(x)=x+1
q(x)=2x^2-2
Calculate p(5) and q(5)
p(5)=5+1 = 6
q(5)=2(5)^2-2 = 48
The functions are then calculated as:
(p*q)(5) = p(5) * q(5)
(p*q)(5) = 6 * 48
(p*q)(5) = 288
Also, we have:
(q*p)(5) = (p*q)(5)
(q*p)(5) = 288
Hence, the value of (p*q)(5) and (q*p)(5) is 288
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Complete question
Suppose that the functions p and q are defined as follows. p(x)=-x-1 q(x)=-2x^2-2 Find the following. (p*q)(5) (q*p)(5)
What is the midpoint of the line segment graphed below?
Answer:
(4, 7/2)
Step-by-step explanation:
midpoint = x values/2, y values/2
the domain a function g(x) is x > 3, and the range is y> 1. What are the The domain of
domain and range of its
inverse function, g
(x)?
The domain of a function is the range of its inverse, and vice versa.
So, the domain is [tex]x > 1[/tex] and the range is [tex]y > 3[/tex].
Help me please!!!!!!!!
Answer:
The ratios are not equal, so this is not a dilation.
Step-by-step explanation:
4/3 is the first ratio
3/4 is the second ratio
Since these ratios are not equal there is not a dilation.
Which of the following graphs includes the possible values for the number of people who still need to sign up for the team?
Number line with closed circle on 5 and shading to the left
Number line with closed circle on 5 and shading to the right.
Number line with open circle on 5 and shading to the left.
Number line with open circle on 5 and shading to the right.
The graph that includes the possible values for the number of people who still need to sign up for the team is:
Number line with closed circle on 5 and shading to the right.
What is the situation and which inequality models it?Researching this problem on the internet, a team currently has 4 players, and needs at least 9.
When x players are signed, the number of players will be of 4 + x. Since the team needs at least 9 players, the inequality is:
[tex]4 + x \geq 9[/tex]
The solution is:
[tex]x \geq 9 - 4[/tex]
[tex]x \geq 5[/tex]
Which is represented as follows:
Number line with closed circle on 5 and shading to the right.
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