Suppose 2.00 V is applied to a parallel plate capacitor having plates of area 5.00 m2 that are separated by 0.121 mm of Teflon. Determine the charge stored in the capacitor. (Teflon κ=2.1)

Answers

Answer 1

The charge stored in the capacitor is 9.94 x 10^-10 C.

What is the charge stored in the capacitor?

The capacitance C of a parallel plate capacitor is given by the formula:

C = ε₀ε₁A / d

where ε₀ is the permittivity of free space (8.85 x 10^-12 C^2/Nm^2), ε₁ is the permittivity of the dielectric material (Teflon, with a value of 2.1 x 8.85 x 10^-12 C^2/Nm^2), A is the area of the plates (5.00 m^2), and d is the distance between the plates (0.121 mm = 0.121 x 10^-3 m).

Plugging in the values, we get:

[tex]C = ε₀ε₁A / d = (8.85 x 10^-12 C^2/Nm^2) (2.1) (5.00 m^2) / (0.121 x 10^-3 m) = 4.97 x 10^-10 F[/tex]

The charge stored in the capacitor is given by the formula:

Q = CV

where V is the voltage applied across the capacitor (2.00 V). Plugging in the values, we get:

[tex]Q = CV = (4.97 x 10^-10 F) (2.00 V) = 9.94 x 10^-10 C.[/tex]

So the charge stored in the capacitor is 9.94 x 10^-10 C.

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Related Questions

The change in velocity divided by the time over which the change occurs is the

a) speed
b) average acceleration
c) velocity
d) displacement

Answers

B, average acceleration

in a generator as the magnet spins opposite poles of the magnet push the electrons in opposite directions this back and forth movement of electrons is called

Answers

Answer: In a generator, the back and forth movement of electrons as the magnet spins and opposite poles of the magnet push the electrons in opposite directions is called Alternating Current (AC).

Explanation:

Answer:

alternating current and direct current

Explanation:

yall some of these questions arent that hard, use common sense

Which equation would you use to solve the following problem: A train
decreases speed from 30 m/s to 20 m/s while in 20s. What is the
displacement of the train?
O vf = vo+a*t
O x = 1/2* (vf+vo) * t
O x= vo*t + 1/2 *a* t^2
O we don't have an equation for this problem yet

Answers

The kind of equation that we can use to solve the problem is;   x = 1/2* (vf+vo) * t. Option B

What are the equations of motion?

Th equations of motion has to do with the equations that we cam be able to apply so as to solve the equations that are for the uniformly accelerated motion.

In the case of the problem that we have in this question, we have been told that A train decreases speed from 30 m/s to 20 m/s while in 20s. The formula that can be used to get the displacement of the train is  x = 1/2* (vf+vo) * t.

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What is an isolated system
?

Answers

Answer:

In physical science, an isolated system is either of the following: a physical system so far removed from other systems that it does not interact with them. a thermodynamic system enclosed by rigid immovable walls through which neither mass nor energy can pass

A skydiver jumps out of a helicopter and falls freely for 9.0 seconds before opening the parachute..

1. What is the the skydivers downward velocity when the parachute opens?
2. How far below the helicopter is the skydiver when the parachute opens?

Answers

The skydiver's downward velocity when the parachute opens can be calculated using the equation of motion:
vf = vi + g * t

where vf is the final velocity, vi is the initial velocity (0 m/s, since the skydiver is in free fall), g is the acceleration due to gravity (9.8 m/s^2), and t is the time (9.0 s).

vf = 0 + 9.8 m/s^2 * 9.0 s = 88.2 m/s

So, the skydiver's downward velocity when the parachute opens is 88.2 m/s.

The distance the skydiver falls during the 9.0 seconds can be calculated using the equation:
d = vi * t + 0.5 * g * t^2

where d is the distance, vi is the initial velocity (0 m/s), g is the acceleration due to gravity (9.8 m/s^2), and t is the time (9.0 s).

d = 0 * 9.0 s + 0.5 * 9.8 m/s^2 * 9.0 s^2 = 405 m

So, the skydiver is 405 meters below the helicopter when the parachute opens

The mid-ventral line divides the body into:

right and left.

front and back.

top and bottom.

north and south.

Answers

The mid-ventral line divides the body into right and left.

What is mid-ventral line?

Mid-ventral line -

The intersection between the ventral skin and the median plane.

Given is that the mid-ventral line divides the body.

Midline refers to the imaginary line that divides the body into symmetrical left and right halves.

Therefore, the mid-ventral line divides the body into right and left.

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A car slows from 22m/s to 3m/s with a constant acceleration of -2.1m/s². How long does it take?

Answers

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

Explanation:

Answer:

The car takes approximately 6.3 seconds to slow from 22m/s to 3m/s with a constant acceleration of -2.1m/s². This is calculated using the equation vf = vi + at, where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time

Explanation:

A spring oscillates with a frequency of 2.09 Hz. What is its period?
(Unit=s)

Answers

Time period of a wave is the inverse of its frequency. The period of the wave with a frequency of 2.09 Hz is 0.47 seconds.

What is frequency ?

Frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of the time period of the wave. Hence, it has the unit of s⁻¹ which is equivalent to Hz.

The higher frequency of a wave indicates more number of wave cycles in a short time. Frequency is directly proportional to the energy and inversely proportional to the  wavelength.

Given the time period of the wave = 2.09 Hz

then frequency = 1/2.09 Hz = 0.47 s.

Therefore, the time period  of the wave is 0.47 seconds.

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what is the formula for time dialation

Answers

Answer: γ = √(1 - v²/c²)

Explanation:

The formula for time dilation in Einstein's theory of special relativity is:

γ = √(1 - v²/c²)

What would the power (Watts) be for a speaker if it draws 3.0 Amps of current when connected to a 12.0 Volt source?

Answers

144 is the power if the current is 3.0 ampere.

What is Power?

Average power, or when tdelta, t in the equation for power is very large, is the power measured over a lengthy period of time. Finding the area under the power vs. time curve, which represents the total work completed, and dividing by the total time are two methods for calculating this.

Although calculus is typically the finest tool for this, it is frequently possible to estimate it very correctly only using geometry. Peak power is the highest value that an instantaneous amount of power can have in a given system over an extended period of time.

Systems that have the capacity to provide a peak power that is significantly greater than their rated average power include stereo systems and car engines.

Therefore, 144 is the power if the current is 3.0 ampere.

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Calculate the efficiency of a compact fluorescent light if a power input of 20 J/s gives an output power of 9 J/s.

Answers

The efficiency of the machine is 45%

What is efficiency?

Efficiency is a measure of how well a system, process, or machine uses resources to produce outputs compared to the inputs used. It indicates the extent to which time, effort, and resources are used effectively to achieve desired goals and minimize waste. The efficiency of a system can be improved by reducing inputs, increasing outputs, or a combination of both.

The efficiency is;

Output power/ Input power * 100/1

= 9/20 * 100/1

= 45%

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why is interpretation an important part of meteorology

Answers

Strong interpretation is an important thing in meteorology. Because, analyzing the climate level in each area and the factors affecting it with their visual representation is very important in weather forecast.

What is meteorology ?

Meteorology is a branch of science dealing with the weather in different regions. On interpreting data, forecasters are tasked with synthesizing available observations from multiple platforms (including surface observations, weather balloons, radar, and satellite), numerical guidance from computer model forecasts, scientific theory, and experience-based intuition to arrive at a forecast.  

The forecast process is often collaborative, with teams of meteorologists routinely integrating new information into the forecast as the event approaches.

Increasingly, forecasters are also responsible for effectively communicating the forecast and its anticipated impacts upon life and property to various stakeholders, including the public.

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A land yacht is a low mass three-wheeled wind-powered vehicle with a sail. Suppose you are in the desert, observing a land yacht race. Consider your location to be the origin. When a particular land yacht passes you, it is traveling 8 m/s in the −z direction. If the mass of the vehicle plus driver is 188 kg, and the net force on the vehicle remains constant at ‹ 0, 0, −26 › N, what is the position of the yacht 29 seconds after it passes you?

Answers

The position of the yacht 29 seconds after it passes you is 290.87 m.

What is the acceleration of the yatch?

The acceleration of the yatch is calculated by applying Newton's second law of motion as shown below.

F = ma

a = F / m

where;

F is the applied forcem is the mass of the yatcha is the acceleration

a = ( 26 N ) / ( 188 kg )

a = 0.14 m/s²

The distance travelled after 29 seconds is calculated as follows;

s = vt + ¹/₂at²

where;

v is the speed of the yatcht is the time of motiona is acceleration

s = ( 8 m/s x 29 s )  +   ¹/₂(0.14)(29)²

s = 290.87 m

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does the troposphere absorb more or less ultraviolet radiation than the thermosphere? why?

Answers

Aerosols in the troposphere, like dust and smoke, scatter UV-B radiation in addition to absorbing it, unlike clouds.

The effects of radiation on people

Our cells' DNA may become damaged by radiation. Acute Radiation Syndrome (ARS) or Cutaneous Radiation Injuries are potential side effects of high radiation doses (CRI). The long-term effects of high radiation doses may include cancer.

Is radiation a long-term contaminant in the body?

Certain radiation sources only briefly remain in the body. Some substances persist in the body permanently, such as seeds and radioactive medications. Yet as time passes, the radiation deteriorates and exhausts itself. You do temporarily become radioactive due to internal radiation.

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At a sports car rally, a car starting from rest accelerates uniformly at a rate of 9.0m/s² over a straight-line distance of 100m. The time to beat is 4.5s.

a Does the driver do it?
b. If not, what must the acceleration be to do so?

Answers

Answer:

The driver does not do it. The acceleration must be greater than 9.0m/s² in order to beat the time of 4.5s. The acceleration must be calculated using the equation a = (d/t)², where a is the acceleration, d is the distance, and t is the time. In this case, a = (100/4.5)², which is equal to approximately 27.78m/s². Therefore, the acceleration must be greater than 27.78m/s² in order to beat the time of 4.5s.

Explanation:

An athlete exerts 3000 W of power when he takes 10.2 s to run the race. How much WORK does the athlete do?

Answers

Answer:

30600 J

Explanation:

Work = Power* Time

         =30600 J

A bare helium nucleus has two positive charges and a mass of 6.64×10
−27
kg. What voltage would be needed to obtain the speed of 6.00×10
6
m/s ? 12.5×10
−2
V
0.0134×10
−4
V
120×10
−15
V

37.4×10
4
V 149×10
4
V 0.0803×10
2
V 239×10
−15
V 299×10
4
V

Answers

Answer:

Explanation:

The voltage needed to obtain the speed of 6.00 x 10^6 m/s for a bare helium nucleus is 149 x 10^4 V.

A car P was decelerating at 2.0 m/s^2 when it passes a stationary car Q, and speed was 20 m/s. At the same car Q from rest and accelerated at 2.5 m/s² along the same straight road.
(i) Find the time when car Q overtook car P.
(ii) How far was car Q from car P when car P came to a stop?​

Answers

(i)  The time when car Q overtook car P is 8 seconds.

(ii) The car Q was 32 meters away from car P when car P came to a stop.

What is the time when car Q overtook car P?

(i) To find the time when car Q overtook car P, we can use the formula for relative velocity:

v = u + at

where;

v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Let's call the time when car Q overtook car P as t. At that time, the velocity of car Q is equal to the velocity of car P, so:

20 = 0 + 2.5t

Solving for t, we get:

t = 8 seconds

(ii) To find the distance between the two cars when car P came to a stop, we can use the formula for distance traveled:

d = ut + (1/2)at^2

Let's call the distance between the two cars when car P came to a stop as d. Since car P was decelerating, its final velocity is 0 m/s. Substituting the known values into the formula, we get:

d = 20t + (1/2)(-2.0)(t^2)

d = 20 * 8 + (1/2)(-2.0)(8^2)

d = 160 - 128

d = 32 meters

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how are neutral atoms different than atoms that are positively charged????

Answers

Neutral atoms have an equal number of protons and electrons, which means their overall electric charge is zero. On the other hand, atoms that are positively charged, also known as cations, have lost one or more electrons and thus have a net positive charge. The loss of electrons changes the number of positive charges (protons) and negative charges (electrons) within the atom, altering its chemical and physical properties. The difference in charge also affects how these atoms interact with other atoms and molecules, leading to differences in reactivity and behavior.

What velocity must a car with a mass of 1370kg have in order to have the same momentum as a 2280kg pickup truck traveling at 21m/s to the east

Answers

The velocity of the car along east direction  must be 34.94 m/s.

What is momentum?

In physics momentum of any object can be defined as product of velocity and mass. As velocity is a vector quantity, momentum is also a vector quantity. So, to define momentum both magnitude and direction are required.  SI unit of momentum is kg-m/s.

Mass of the car = 1370 kg.

Mass of the   pickup truck a = 2280 kg

Momentum of the  pickup truck along east = 2280 kg × 21 m/s

= 47880 kg-m/s.

Hence, velocity of the car along east direction = (47880/1370) m/s

= 34.94 m/s.

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The mathematical relationship between three physical quantities is given by a =
b
If the dimension of b is: iT and the dimension
of cis [L]. Which one of the following choices is the dimension of a?

Answers

The dimensional formula of  physical quantity a is  [L]/[T²]. Hence, option (c) is correct.

What is dimensional formula?

The definition of the dimensional formula is the correct statement of the physical quantity in terms of its fundamental unit.

The relation between physical quantities a, b and c is:

a = b²/c

The dimensional formula of b is = [L]/[T] = [LT⁻¹]

The dimensional formula of c is = [L]

Hence, the dimensional formula of a is  = [LT⁻¹]²/[L]

= [L²T⁻²L⁻¹]

= [LT⁻²]

= [L]/[T²]

The dimensional formula of a is [L]/[T²]. Hence, option (c) is correct.

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Two balls with masses of 2.0kg and 6.0kg traveling at 12ms and 4.0 m/s, respectively. They have a head-on inelastic collision (not perfectly). The 2.0kg moves in the opposite direction with a speed of 8.0 m/s. a. Find the speed of the 6.0kg ball after the collision. B. Find the KE for each ball before and after the collision C. Find the amount of KE that is lost during the collision.​

Answers

Answer:

Explanation:

A. To find the speed of the 6.0 kg ball after the collision, we can use the principle of conservation of momentum. The total momentum of the system before the collision is equal to the total momentum after the collision.

Momentum before collision = Momentum after collision

m1v1 + m2v2 = (m1 + m2)vf

where:

m1 = 2.0 kg (mass of first ball)

m2 = 6.0 kg (mass of second ball)

v1 = 12 m/s (velocity of first ball)

v2 = 4.0 m/s (velocity of second ball)

vf = final velocity of the combined balls after collision

Since the 2.0 kg ball moves in the opposite direction with a speed of 8.0 m/s after the collision, and the total mass of the two balls is 8.0 kg, we can write:

vf = (m1v1 + m2v2) / (m1 + m2) = (2.0 kg x (-8.0 m/s) + 6.0 kg x 4.0 m/s) / 8.0 kg = 2.33 m/s

So the speed of the 6.0 kg ball after the collision is 2.33 m/s.

B. To find the KE for each ball before and after the collision, we can use the formula:

KE = 0.5mv^2

where:

m = mass of the ball

v = velocity of the ball

For the 2.0 kg ball, the KE before and after the collision is:

KE before = 0.5 x 2.0 kg x (12 m/s)^2 = 72 J

KE after = 0.5 x 2.0 kg x (8.0 m/s)^2 = 32 J

For the 6.0 kg ball, the KE before and after the collision is:

KE before = 0.5 x 6.0 kg x (4.0 m/s)^2 = 48 J

KE after = 0.5 x 6.0 kg x (2.33 m/s)^2 = 20.44 J

C. To find the amount of KE that is lost during the collision, we can subtract the total KE after the collision from the total KE before the collision:

KE lost = KE before - KE after = (72 J + 48 J) - (32 J + 20.44 J) = 40.56 J

So the amount of KE that is lost during the collision is 40.56 J.

What is the specific heat capacity of a silver medal if 55.0 grams of the metal absorbs 197.9 joules of heat and the temperature rises 15°C

Answers

The specific heat capacity of silver is 0.235 J/g°C.

What is the specific heat capacity of a silver medal?

The theory used in this question is the specific heat capacity equation, which states that the amount of energy required to raise the temperature of an object is proportional to the mass, specific heat capacity, and change in temperature.

The equation is Q = mcΔT, where Q is the amount of energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Explanations given below

Calculate the specific heat capacity of silver by dividing the energy absorbed (197.9 J) by the mass of the silver (55.0 g) and the temperature rise (15°C).

Divide 197.9 J by 825 g°C (55.0 g * 15°C).

             (197.9 J) / (55.0 g * 15°C) = 0.235 J/g°C

The result is 0.235 J/g°C, which is the specific heat capacity of silver.

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A baseball is thrown straight upward with an initial speed of 35m/s. compute:
a) The maximum height reached by the ball b) The time taken to reach that height
c) Its velocity 30s after it is thrown,

Answers

a) Maximum height reached by ball = 376 m ; b) Time taken to reach that height is 21.5 s and c) Velocity 30s after it is thrown is -13.9 m/s

What is velocity?

Velocity is vector expression of displacement that an object or particle undergoes with respect to the time.

Given:

y₀ = 0 m ; v₀ = 35 m/s

a) Find: y when v = 0 m/s.

As, v² = v₀² + 2a (y − y₀)

(0 m/s)² = (35 m/s)² + 2(-1.63 m/s²) (y − 0 m)

So, y = 376 m

Maximum height reached by ball, y = 376 m

b) Find: t when v = 0 m/s.

As, v = at + v₀

0 m/s = (-1.63 m/s²) t + 35 m/s

So, t = 21.5 s

Time taken to reach that height is, t = 21.5 s

c) Find: v when t = 30 s.

As, v = at + v₀

v = (-1.63 m/s²) (30 s) + 35 m/s

So, v = -13.9 m/s

Velocity 30s after it is thrown is, v = -13.9 m/s.

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An 112 kg man drops from rest on a diving board 3.0 m above the surface of the water and comes to rest 0.55 s after reaching the water. How fast was he going as he hit the water? (use units of measurement)​

Answers

こんにちは、質問が正しいことを願っていますが、答えはボールシムガファックです -translate it it’s the right answer

A bike rider accelerates constantly to a velocity of 7.5m/s during 4.5s. The bike's displacement is 19m. What was the initial velocity of the bike?

Answers

The initial velocity of the bike was 3.75 m/s.

What was the initial velocity of the bike?The initial velocity of the bike is determined by examining the displacement and the time elapsed. The equation for displacement is displacement = initial velocity (m/s) x time (s). Thus, the initial velocity can be calculated by rearranging the equation, initial velocity = displacement (m) / time (s).In this case, the displacement is 19m and the time is 4.5s. Thus, the initial velocity can be calculated by plugging in the values to the equation, initial velocity = 19m / 4.5s. This evaluates to 4.22m/s. This means that the bike rider's initial velocity was 4.22m/s before accelerating to the velocity of 7.5m/s in 4.5s.To break it down, the bike rider was initially travelling at 4.22m/s and then accelerated constantly to a velocity of 7.5m/s in a period of 4.5s. The resulting displacement was 19m. This can all be determined using the equation displacement = initial velocity x time. By rearranging the equation and plugging in the values, we can determine the initial velocity of the bike as 4.22m/s.

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The graph shows the maximum amount of water vapor that air can hold at different temperatures.

Line graph of maximum humidity on a coordinate plane. X-axis labeled Temperature (degrees Celsius). Y-axis labeled Water Vapor Density grams per cubic meter. Line starts at (0, 2) and gradually rises through (30, 30), 35, 40), (40, 50), (45, 62).

Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is
grams/cubic meter.

Answers

Beth’s hygrometer is reading a temperature of 30°C and a relative humidity of 65%. The humidity in the air is 19.5 grams/cubic meter.

What is the humidity?

The actual vapor density or humidity can be determined from the relative humidity value and the saturation vapor density.

The formula that relates the actual vapor density or humidity, the relative humidity, and the saturation vapor density is given below:

relative humidity = (actual vapor density / saturation vapor density) x 100%

Hence, the actual vapor density can be calculated as follows:

Actual vapor density or humidity = relative density * saturation vapor density / 100

From the graph;

saturation vapor density at 30°C = 30 g/cm³

relative humidity = 65%

Humidity = 65 * 30 / 100

Humidity = 19.5 g/cm³

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A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head-on collision with a 14.0 kg raft moving to the right at 16.0 m/s. After the collision, the raft moves to the left at 14.4 m/s. What is the velocity of the canoe after the collision?​

Answers

According to the law of conservation of momentum, the velocity of the canoe after the collision will be 17.79 meters per second.

What is the law of conservation of momentum?

The law of conservation of momentum states that the momentum of the system of objects remains constant before and after the collision unless an external force is applied.

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where, m₁ is the mass of one object and m₂ is the mass of second object,

u₁ and u₂ are initial velocities of object one and two,

v₁ and v₂ are the final velocities of object one and two.

16 × 12.5 + 14 × 16 = 12.5 × v₁ + 14 × 14.4

200 + 224 = 12.5v₁ + 201.6

424 = 12.5v₁ + 201.6

424 - 201.6 = 12.5v₁

222.4 = 12.5v₁

v₁ = 222.4/ 12.5

v₁ = 17.79 m/s

Therefore, the velocity of the canoe after the collision will be 17.79 meters per second.

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Rocket powered sleds are used to test the responses of humans to acceleration. Starting from rest, one sled can reach a speed of 444m/s in 1.80s and can be brought to a stop again in 2.15s.

a. What is its acceleration when braking?
b. After braking for 1s what is the velocity?

Answers

Answer:

to explain the work on the other one you said its this A) The speed of the truck at the end of the 20.0m distance can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration and s is the displacement. The initial velocity of the truck is 100m/s, the acceleration is 6.5m/s^2, and the displacement is 20.0m. Plugging in these values, we get v^2 = 100^2 + 2(6.5)(20.0). Solving for v, we get v = 36.6 km/h. B) The time elapsed can be calculated using the equation t = (v-u)/a, where t is the time elapsed, v is the final velocity, u is the initial velocity, and a is the acceleration. Plugging in the values, we get t = (36.6-100)/6.5, which gives us t = 3.03 seconds.

Explanation:

but for this problem

The acceleration when braking is -202m/s2. b. After braking for 1s, the velocity is 242m/s.

The acceleration when braking can be found by using the equation a = (Vf- Vi)/t, where Vf is the final velocity, Vi is the initial velocity, and t is the time. In this case, the initial velocity is 444m/s and the final velocity is 0m/s. The time is 2.15s. Plugging these values into the equation gives us a = -202m/s2. For the second question, we can use the equation Vf = Vi + at, where Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and t is the time. In this case, the initial velocity is 444m/s, the acceleration is -202m/s2, and the time is 1s. Plugging these values into the equation gives us Vf = 242m/s.

t = 3.03 seconds.

Explanation:

3) You observe a deep water (water depth> wave base) wave with a wavelength of 15 m and period of 3 seconds. What is the frequency and celerity of the wave?

Frequency:

Celerity:

4) what happens to wavelength as celerity increases? (see part 3)

Answers

The frequency of the wave is 0.33 Hz.

The celerity of the wave is wave is 4.95 m/s.

As the celerity of the wave increases, the wavelength increases.

What is the frequency of the wave?

The frequency of the wave is calculated by applying the following formula.

v = fλ

where;

f is the frequency of the waveλ is the wavelength of the wave

f = 1 / T

f = 1 / 3 s

f = 0.33 Hz

The celerity of the wave is wave is calculated as follows;

v = fλ

v = ( 0.33 Hz ) x ( 15 m )

v = 4.95 m/s

λ = v / f

Thus, from the above equation as the celerity of the wave increases, the wavelength increases.

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