Answer:
Sue candy = 13 - x
Tony candy = 9 + 1/2x
Step-by-step explanation:
Sue candy = 18
Tony candy = 18
Let x = some candy gives to tony
Sue candy = 18 - x
Tony candy = 18 + x
sue then eats five of hers
Sue candy = 18 - x - 5
= 13 - x
tony eats half of his
Tony candy = 1/2(18 + x)
= 18/2 + x/2
= 9 + 1/2x
Expressions for the number of pieces candy sue and tony now have:
Sue candy = 13 - x
Tony candy = 9 + 1/2x
what is the product of -8(9)
show your work to the problem
Answer:
-72
Step-by-step explanation:
-8×-9
=-72
hope it helps you..
Express the trigonometric ratios sinA in term of cosA
Answer:
sinA = ± [tex]\sqrt{1-cos^2A}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²A + cos²A = 1 ( subtract cos²A from both sides )
sin²A = 1 - cos²A ( take the square root of both sides )
sinA = ± [tex]\sqrt{1-cos^2A}[/tex]
BRAINLIEST FOR ANSWER WITH EXPLANATION
JUST ONE QUESTION ATTACHED BELOW:
Answer:
m=16
Step-by-step explanation:
(6+6)/m=6/8
12/m=6/8
M=16
Answer:
16
Step-by-step explanation:
This triangle has been dialated; ILM is a dialated version of IJK. We know that dialations are by scale factors, and we also know the length of two corresponding sides.
IM is 6 m long, and IMK is 6+6 m long, so 12 m. So using simple ratios, we know the dialation factor from ILM to IJK is 2. The corresponding side for JK (m) is LM, which we know is 8 m. So side m is 16 because of the scale factor (2).
Maybe you thought we were solving for "m", as in a varriable all the sides are multiplied by, but I think that's just bad labeling. Hope this helps!
Two particles have positions at time t given by s1=4t-t^2 and s2=5t^2-t^3. Find the velocities
Step-by-step explanation:
Given that,
The positions of the first particle,[tex]s_1=4t-t^2[/tex]
Velocity,
[tex]v_1=\dfrac{ds_1}{dt}\\\\v_1=\dfrac{d(4t-t^2)}{dt}\\\\v_1=4-2t[/tex]
Position,
[tex]s_2=5t^2-t^3[/tex]
[tex]v_2=\dfrac{ds_2}{dt}\\\\v_2=\dfrac{d(5t^2-t^3)}{dt}\\\\v_2=10t-3t^2[/tex]
Hence, this is the required solution.
when x^2 - 3x +2k is divided by x+2, the remainder is 7. find the value of k.
Answer:
let's find the zeros of the divisor
x+2=0
x=-2
let x²-3x+2k =f(x)
Now f(-2)=(-2)²-3(-2)+2k=7
4+6+2k=7
2k=7-10
2k=-3
k=-3/2
please help!
factor f(x)=6x^2-x-2
Hi there!
[tex]\large\boxed{(3x - 2)(2x + 1) }[/tex]
6x² - x - 2
To solve, we must factor into the following format:
(ax - b)(cx - d)
The following conditions must be met:
a · c = 6
da + bd = -1
b · d = -2
By guessing and checking, we get:
(3x - 2)(2x + 1)
Answer for Acellus:
(2 x + 1) (3 x - 2)
Step-by-step explanation:
i checked the equation on an online calculator, and it came up with it switched (compared to the other answer that is posted) like so...
I put the answer in and it said it was right for Acellus.
Hope this helps :))
If A = [tex]\left[\begin{array}{ccc}cosx&-sinx\\sinx&cosx\end{array}\right][/tex], then show that [tex](A^{-1} )^{-1}[/tex]
Given:
The matrix is:
[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
To show:
[tex](A^{-1})^{-1}=A[/tex]
Solution:
If a matrix is:
[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]
Then,
[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]
We have,
[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
Using the above formula, we get
[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]
Now, the inverse of [tex]A^{-1}[/tex] is:
[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]
[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]
[tex](A^{-1})^{-1}=A[/tex]
Hence proved.
Does this graph show a function? Explain how you know.
• A. No; there are yvalues that have more than one x-value.
O B. No; the graph fails the vertical line test.
O C. Yes; there are no yvalues that have more than one x-value.
O D. Yes; the graph passes the vertical line test.
HELP PLSS
Word problem One of the citizens has 97 silver coins. How many bronze coins would it take to equal this amount
Given: Given that a citizen have 97 silver coins.
To find : Here we need to find that how many bronze coins would it take to equal this amount.
Solution: We know, 1 silver coin=10 bronze coin
So, 97 silver coin=10×97 bronze coin
=970 bronze coin
Therefore, 970 bronze coins would it take to equal this amount.
Someone tell me where everyone is going right please !!
Answer:
1min = 0.25miles
5.25miles / 0.25miles = 25 = 25minutes
Step-by-step explanation:
Hope this is right I'm not the best at worded time/distance math questions.
9514 1404 393
Answer:
0 ≤ t < 52.5 minutes
Step-by-step explanation:
Riko will be behind Yuto until her distance traveled matches his. That is, she will be behind for ...
0.35t < 5.25 +0.25t
0.10t < 5.25
t < 52.5
Riko will be behind Yuto on the interval 0 ≤ t < 52.5 minutes.
_____
Additional comment
distance = speed × time
Here, time is measured from when Riko starts riding. In addition to the 5.25 miles that Yuto has already gone, his distance will be the product of his speed (0.25 mi/min) and the travel time (t min). Then Yuto's total distance is 5.25+0.25t miles. The speed×time product is also used to find Riko's distance traveled. In her case, it is 0.35t miles.
Heya Kitties!
What is the value of x?
18x−16=−12x−4
x =
Answer:
2/5
Step-by-step explanation:
18x+12x=-4+16
30x=12
x=2/5
Answer:
18x-16=-12x-4
18x+12x=-4+16
30x=12
x=12/30
x=2/5
Which number line model represents the expression 3.5+(-5)
Answer:
D.
Step-by-step explanation:
.
Does the point (0, 37) satisfy the equation y = 79x - -37? yes no
Answer:
yes
Step-by-step explanation:
y = 79x - -37
37 = 79(0) - - 37
37 = 0 - - 37
37 = 37
PLEASE ANSWER ASAPPP
Answer:
the answer is 2035.75 cm³
Step-by-step explanation:
comment if you want explanation
Here is a Venn diagram.
a) Write down the numbers that are in set
А.
B
16
(i) AUB 8,14, 17, 16, 9, 15
8
14
9
(ii) A B 14,17
17
15
13
12
10
11
One of the numbers in the diagram is
chosen at random.
b) Find the probability that the number is in
set A, giving your answer as a decimal.
Answer:
0.7
Step-by-step explanation:
.
Answer: b) 0.7
Just copy that into mathswatch :>
Given f(x) = 1 - 2x with the range {-3, -5, -7 }, find the domain.
Answer:
{2,3,4}
Step-by-step explanation:
The range are simply the f(x) values
The range are the x values
To get the x values, we simply get x from each f(x)
So we have;
1-2x = -3
1+ 3 = 2x
2x = 4
x = 4/2
x = 2
Secondly;
1-2x = -5
1 + 5 = 2x
2x = 6
x = 6/2
x = 3
lastly;
1-2x = -7
1 + 7 = 2x
2x = 8
x = 8/2
x = 4
So the domain values are;
{2,3,4}
what is the value of b?
Answer: The b-value is the middle number, the number next to the X
The number of clicks for a search text ad is 50 and the number of impressions is 5000. The CTR would be Group of answer choices 1% 2% 5% 10%
Given:
Clicks = 50
Impressions = 5000
To find:
The CTR percentage.
Solution:
We know that,
[tex]CTR=\dfrac{\text{Clicks}}{\text{Impressions}}\times 100[/tex]
Substituting the given values, we get
[tex]CTR=\dfrac{50}{5000}\times 100[/tex]
[tex]CTR=\dfrac{1}{100}\times 100[/tex]
[tex]CTR=1\%[/tex]
Therefore, the correct option is A.
which points lie in the second quadrant? check all that apply.
Point F
Point E
These lie in the second quadrant.
15. ABCD is a cyclic quadrilateral in which
AB = BC and ABC = 70°.
AD produced meets BC produced at the
point P, where APB = 30°.
Calculate
a) ADB
b) ABD
Answer:
a) ∠ADB is 55°
b) ∠ABD is 45°
Step-by-step explanation:
a) In the cyclic quadrilateral ABCD, we have;
Segment AB = Segment BC
∠ABC = 70°
Therefore, ∠ADC = 180° - 70° = 110° (Opposite angles are supplementary)
∠ADC + ∠CDP = 180° (Sum of angles on a straight line)
∴ ∠CDP = 180° - ∠ADC
∠CDP = 180° - 110° = 70°
∠DCP = 180° - 70° - 30° = 80°, (Angle sum property)
Similar to ∠DCP = ∠DAB = 80° (Exterior angle of a cyclic quadrilateral)
∠CAB = ∠ACB = (180° - 70°)/2 = 55° (Base angles of isosceles triangle ΔABC)
∠ADB = ∠ACB = 55° (Inscribed angle of a circle subtended by the same chord)
∠ADB = 55°
b) ∠ABD = 180° - ∠DAB - ∠ADB
∴ ∠ABD = 180° - 55° - 80° = 45°
∠ABD = 45°
if a real estate company gives 3% commission on to it's agents. if an agent sold a piece of land for 12,50,000, how much cccommision did the agent get ?
Answer:
37500
Step-by-step explanation:
3% of 1250000
That is (3/100)*1250000
The answer is 37500
Find the measure of the indicated angle
Answer:
x = 70°Step-by-step explanation:
Given is the isosceles triangle as two sides marked equal.
The missing angles measure the same.
Since the sum of interior angles of a triangle is 180°, we have:
40° + 2x = 180°2x = 140°x = 70°It is an isosceles triangle,
The marked 2 sides of triangle are equal.
Now we have to,
find the measure of indicated angle.
General formula,
→ Sum of all sides of triangle = 180°
Then the value of x is,
→ 2x + 40° = 180°
→ 2x = 140°
→ x = 140/2
→ x = 70°
Therefore, 70° is the value of x.
A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pound. If the distribution of weights for the small size packages of ground meat is approximately normally distributed, what is the best estimate of the probability that a randomly selected small size package has a weight less than 0.9 pound? Explain how you found your answer.
Answer:
15.87 %
Step-by-step explanation:
z = (.9-1)/.1 = -1
z score of -1 = .1587
The probability that a randomly selected small size package has a weight of less than 0.9 pounds is 15.87 %
We have given that,
A store sells ground meat in small, medium, and large sizes. The weights of the small size packages have a mean weight of 1 pound and a standard deviation of 0.1 pounds. If the distribution of weights for the small-size packages of ground meat is approximately normally distributed
What is the formula for the z-score?[tex]Z = \frac{x - \mu}{\sigma}[/tex]
Z = standard score
x = observed value
[tex]\mu[/tex] = mean of the sample
[tex]\sigma[/tex] = standard deviation of the sample
z = (0.9-1)/0.1 = -1
z of -1 = 0.1587
Therefore the value of the z-score is 0.1587.
To learn more about the Z-score visit:
https://brainly.com/question/25638875
#SPJ2
Tommy went to the shop where there was a 20% off sale taking place
The shirt he wanted to buy was originally £20
How much money does he save in the sale?
Answer:
4 pounds
Step-by-step explanation:
take 20% off the original price. 20(0.20)= 4
So that's a discount of 4 pounds and the sale price is 16 pounds.
The savings is 4 pounds on 1 shirt.
identify an equation in point slope form for the line perpendicular to y=-1/3x-6 that passes through (-1,5)
someone please help me ASAP!
Answer:
214°
Step-by-step explanation:
The measure of an arc that sees the center angle of the circle is equal to the very same angle that it sees
Since the measure of circle is 360° and arc AB is given as 146° the measure of arc ACB should be 360 - 146 = 214°
Can someone help me with this math homework please!
Answer:
Question 1: (C) Step 3
Question 2: (B) The 2nd graph from the left
Question 3: (A, B, D)
Question 4: (D) Subtract 1.1j from both sides
Question 5: (C) x <= 3
Question 6: (D) y = 10
Step-by-step explanation:
Question 1:
Step 3 is where Rahul added 1/4 to both sides. This is the only time he used the addition property of equality.
Question 2:
This questions requires you to have knowledge on how to graph lines.
g(x) = -1 is already graphed correctly on all of the answer choices, so we only have to focus on f(x) = -1/2x - 2.
The y-intercept for f(x) is -2, and only answers B & D have that intercept. However, only B has the correct slope of -1/2.
Question 3:
A is correct because they added 3/5x and x, which is still equal to the original equation.
B is correct because they multiplied all the terms to have a denominator of 30, then multiplied both sides by 30 to eliminate the fractions.
C is wrong because it's supposed to 30x, not just a regular x from the original equation.
D is correct because as you solve the equation for x, you end up adding 18x, 6x, and 30x, which is 54x. 24x + 30x in this answer choice also equals 54x.
E is wrong because they subtracted instead of adding the 6x.
Question 4:
All of the answer choices are wrong except for D because the other choices either use a wrong term (like 4j, which doesn't exist) or the wrong property of equality.
Question 5:
Use basic algebra to sovle the inequality:
2(4 + 2x) >= 5x + 5
(distribute 2 to the (4 + 2x))
8 + 4x >= 5x + 5
(subtract 5 from both sides)
3 + 4x >= 5x
(subtract 4x form both sides)
3 >= x
x <= 3
Question 6:
Use basic algebra to solve for y:
2.8y + 6 + 0.2y = 5y - 14
(subtract 6 from both sides)
2.8y + 0.2y = 5y -20
(add like terms)
3y = 5y - 20
(subtract 5y from both sides)
-2y = -20
(divide both sides by -2)
y = 10
Hope it helps (●'◡'●)
Which of the following statements considered as always true?
A. All intersecting lines are perpendicular.
B. All parallel lines cut by a transversal line.
C. All perpendicular lines are intersecting line.
D. All transversal line is for parallel lines only
Find the equation of the line through point (2,2) and parallel to y=x+4. Use a forward slash (i.e.”/“) for fractions (e.g. 1/2 for
Answer:
The equation of the line is, y = x
Step-by-step explanation:
The constraints of the required linear equation are;
The point through which the line passes = (2, 2)
The line to which the required line is parallel = y = x + 4
Two lines are parallel if they have the same slope, therefore, we have;
The slope of the line, y = x + 4 is m = 1
Therefore, the slope of the required line = 1
The equation of the required lime in point and slope form becomes;
y - 2 = 1 × (x - 2)
∴ y = x - 2 + 2 = x
The equation of the required line is therefore, y = x
Answer thi question plz
Answer:
Q.5
Step-by-step explanation:
(2x)^3+3×(2x)^2×3y+3×2x×(3y)^2+(3y)^3
8x^3+3×4x^2 × 3y + 3×2x×9y^2 + 27y^3
8x^3 + 36x^2 × y + 54xy^2 + 27y^3