Answer:
he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion
Explanation:
The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:
F = ma
0.65 N = 1.7 kg * a
a = 0.38 m/s^2
This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:
d = vit + 1/2 at^2
where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:
d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2
d = 1.78 meters
Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.
at a given instant in time, a red car is traveling at twice the velocity of a blue car. which of the following statements is correct? A. The red car has a higher acceleration than the blue car
B. The blue car has a higher acceleration than the red car
C. Both cars have the same acceleration
D. There is nothing we can say about the acceleration of either car
There is nothing we can say about the acceleration of either car
How does acceleration work?
The rate at which velocity changes is called acceleration. Acceleration typically indicates a change in speed, but not necessarily. An item that follows a circular course while maintaining a constant speed is still moving forward because the direction of its motion is shifting.
The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.
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A 10 kg dog is running in a circle around a tree, trying to catch a squirrel. The dog's speed is 7 m/s and the radius of the dog’s circular path is 3 meters. What is the centripetal force acting on the dog?
A.) 163 N
B.) 16.3 N
C.) 490 N
D.) 23 N
The centripetal force acting on the dog is 245 N (The options are wrong).
What is centripetal force?The formula for centripetal force is given by F = m × v² / r, where m is the mass of the object (in this case, the dog), v is the velocity of the object, and r is the radius of the circular path.
Plugging in the given values:
F = 10 kg × (7 m/s)² / 3 m = 245 N
So the centripetal force acting on the dog running around a tree is 245 N.
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a direct expansion-type evaporator is also called a . flooded evaporator dry-type evaporator multi-circuit evaporator stamped evaporator
A dry-type evaporator is another name for a direct expansion evaporator. An evaporator seems to be a container or platform that converts liquid into vapor.
Evaporator, what is it?In contrast to the condenser, the evaporator absorbs heat from the compartment's air while converting refrigerant liquid to gas. Due to the reduced pressure and heat dissipation, the liquid refrigerant is much cooler than for the fan air surrounding it when it reaches the evaporator.
What sort of evaporator is employed?One of the popular evaporators is the LTV. Basically, it is a liquid separator coupled to a shell and tube heat exchanger. The climbing film evaporator and the descending film evaporator are quite similar. It is the total opposite of something like a falling movie.
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a researcher wants to measure internal consistency in a test that measures two different constructs (self-esteem and depression) without subdividing the items into the two construct groupings. which of the following would be the best method to use in measuring internal consistency?
If the researcher wants to measure internal consistency in a test , then the best method to use in measuring the internal consistency is Split Half Reliability .
The Split Half Reliability is defined as a method which is used to measure the internal consistency of a test by splitting the test into two halves and then calculate the correlation between the scores on the two halves of the test .
In this case, the researcher wants to measure the internal consistency of a test that measures two different constructs (self-esteem and depression) without subdividing the items into the two construct groupings.
Since the test measures two different constructs, the split half reliability may not be able to provide an accurate estimate of internal consistency, because the correlation between the scores on the two halves may be influenced by the different constructs being measured.
The given question is incomplete , the complete question is
A researcher wants to measure internal consistency in a test that measures two different constructs (self-esteem and depression) without subdividing the items into the two construct groupings. What would be the best method to use in measuring internal consistency ?
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Part A
A sports car accelerates from rest to 94 km/h in 5.5 s.
What is its average acceleration in m/s².
Express your answer using two significant figures.
V
ΑΣΦ
?
Answer:
The average acceleration of the sports car is 16.9 m/s².
An object on a rough horizontal surface has a maximum possible static friction of 3 N and kinetic friction of 2 N. If the object is given a 4-N horizontal push, what is the magnitude of the net frictional force (static plus kinetic frictional forces) acting on the object?
The net frictional force acting on the object on a rough horizontal surface is 5 N.
This is because the maximum static frictional force is 3 N and the kinetic frictional force is 2 N. Therefore, the total of the two forces is 5 N.
The frictional force is always a resistive force between two surfaces in contact that opposes their relative motion. It is a non-conservative force, meaning it does not obey the laws of conservation of energy. The magnitude of the frictional force is dependent on a number of factors, including the nature of the two surfaces in contact, the normal force between them, the speed of the relative motion, and the coefficient of friction between them.
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A compass needle tends to
A. line up randomly to a magnetic field
B. line up parallel to a magnetic field
C. line up perpendicular to a magnetic field
D. line up with the geographic poles of the earth
E. None of these
The required compass needle tends to line up parallel to a magnetic field. Option B is correct.
What is a magnetic field?A magnetic field is a field that surrounds a magnetic object and exerts a force on other magnetic objects within the field. It is a type of field generated by moving electric charges or by magnetic materials.
Here,
A compass needle tends to line up parallel to a magnetic field. The compass needle is a magnet and the magnetic field from the Earth causes it to align in a north-south direction, with the North end of the needle pointing towards the magnetic North Pole.
Thus, the required compass needle tends to line up parallel to a magnetic field. Option B is correct.
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12. Consider the falling and rolling motion of the 2.0 kg ball in the following two resistance-free
situations. In one situation, the ball falls off the top of the platform to the floor. In the other situation,
the ball rolls from the top of the platform along the staircase-like pathway to the floor. Fill in answer
for each the blanks lettered A-K.
PE=100J
KE=0J
PE= F J
KE- GJ
v=__H_m/s
PE=50J
KE-A J
V= B_m/s
PE=_C_J
KE=D J
v=__E__m/s
Answer the questions using logic and a little bit of arithmetic.
Top & Bottom:
1. What is the PE of the ball at the very top of the diagram above?
2.
What is the KE of the ball at the very top of the diagram above?
3. What is the PE of the ball the location shown as I on the diagram above?
4. What is the KE of the ball the location shown as J on the diagram above?
5.
What is the velocity of the ball the location shown as K on the diagram above?
requires a little mental math - but you can use a calculator if you need it.
6. What is the PE of the ball the location shown as F on the diagram above as the ball hits the ground?
10
PE=IJ
KE J J
v=K_m/s
8. What is the velocity of the ball the location shown as H on the diagram above?
your previous answers-don't solve the velocity equation.
7. What is the KE of the ball the location shown as G on the diagram above as the ball hits the ground?
Rolling down the ramp:
9. What is the KE of the ball the location shown as A on the diagram above?
This one
Use logic &
10. What is the velocity of the ball the location shown as B on the diagram above? Use logic & your previous
answers-don't solve the velocity equation.
11. What is the PE of the ball the location shown as C on the diagram above?
12. What is the KE of the ball the location shown as D on the diagram above?
13. What is the velocity of the ball the location shown as E on the diagram above? Use logic & your previo
answers-don't solve the velocity equation.
The PE (potential energy) of the ball at the very top of the diagram is 100 J.
The KE (kinetic energy) of the ball at the very top of the diagram is 0 J.
The PE of the ball the location shown as I on the diagram is 50 J.
The KE of the ball the location shown as J on the diagram is 50 J.
What is friction?Friction is a force that acts between two objects that are in contact with each other and opposes their relative motion.
The velocity of the ball the location shown as B on the diagram can be calculated by the equation KE = 0.5 * m * v^2, where m is the mass of the ball (2 kg) and KE is the kinetic energy (50 J). Solving for velocity, we get v = sqrt(KE / (0.5 * m)) = sqrt(50 / (0.5 * 2)) = 7 m/s.
The PE of the ball the location shown as F on the diagram as the ball hits the ground is 0 J.
The KE of the ball the location shown as G on the diagram as the ball hits the ground can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball (calculated in #5 as 5 m/s). Solving for KE, we get KE = 0 + 0.5 * 2 * 5^2 = 50 J.
Using the equation KE = 0.5*m*v2, the velocity can be determined to be 7.07 m/s for B and E and 10 m/s for H and K.
The 100 J of original mechanical energy is present at each position. So the KE for A is 50 J.
The KE of the ball the location shown as A on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2, where m is the mass of the ball (2 kg) and v is the velocity of the ball. The KE at A will be 50J.
The PE of the ball the location shown as C on the diagram can be calculated by conserving energy, meaning that the initial PE at the top of the ramp plus any work done by friction must equal the final KE at this location. This can be expressed as PE + work done by friction = KE, where work done by friction is equal to friction force times distance. So, at C, PE=50J and the KE of the ball the location shown as D on the diagram can be calculated by the equation KE = PE + 0.5 * m * v^2 So, KE for D will be50J.
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A girl tosses a stone into the air with an initial upward velocity of 8.00 meters/second and hears the splash when it hits the water 4.20 seconds later. How deep is the water level in the well below where she tossed the stone
Deep is the water level in the well below where she tossed the stone is 52.92 m.
Consider the equation of motion s = ut + 0.5 at²
Take the upward direction as positive,
Initial velocity, u = 8 m/s
Acceleration, a = -9.81 m/s²
Time, t = 4.20 s
Substituting
s = ut + 0.5 at²
s = 8 x 4.20 + 0.5 (-9.81) x 4.20²
s = -52.92 m
Depth of well = 52.92 m
The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.
Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.
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A geologist finds that a moon rock whose mass is 8.88 kg has an apparent mass of 5.97 kg when submerged in water. What is the density of rock?
The Density of rock=(6315 kg/m^3)
It is a universal fact that the mass of an object remains constant whether measured on earth or on the moon.
Mass of rock on moon/earth = 7.2
Loss in weight =7.02 - five.88 = 1.14 kg = 1140g
As we know that water has a density of 1g/cm^3 (1000kg/m^3)
The volume of water = volume of the rock
= Mass/density;
=1140 cm^3
density of rock = mass/extent = 7200/1140 = 6.315 g/cm^3
Density of rock=(6315 kg/m^3)
Density (volumetric mass density or particular mass) is the substance's mass in line with a unit of extent. The symbol most usually used for density is ρ (the decreased case Greek letter rho), despite the fact that the Latin letter D also can be used. Mathematically, density is described as mass divided with the aid of volume.
The density of fabric varies with temperature and stress. this variation is usually small for solids and drinks but a whole lot greater for gases. increasing the strain on an object decreases the quantity of the object and therefore will increase its density. increasing the temperature of a substance (with some exceptions) decreases its density via increasing its quantity. In most materials, heating the bottom of fluid outcomes in convection of the warmth from the bottom to the pinnacle, due to the lower density of the heated fluid, which motivates it to rise relative to denser unheated material.
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Complete question:
A geologist finds that a moon rock whose mass is 7.2 kg has an apprant mass 5.88kg when submerged in water what is the density of rock.
which of these would increase if a second traffic light were attached to the first? assume the cables do not change their lengths.(select all that apply)
a.the tension T1
b.The angle of the cable with tension T2
c. The angle of the cable with tension T1
d.tension t2
Out of the following statement, a.the tension T1 and d.tension t2 would increase if a second traffic light were attached to the first.
The addition of a second traffic light increases the tension in both cables, when two traffic lights are connected, the cable connected to the first light T1 will increase in tension due to the added weight of the second light. The additional weight creates a greater force that must be resisted and so the tension in the cable will increase, similarly the cable connected to the second light, T2 will also increase in tension due to the added weight of the first light.
The angle of the cable with tension T2 will also increase due to the additional force created by the tension in T1. This increase is due to the additional force created by tension inT1, this increase in tension and angle can be seen in the physical world as the cables connected to the two traffic lights stretch and bend to accommodate the additional weight, the increase in tension and angle helps to ensure that the two lights stay secure and remain in the proper position.
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The equation of a wave traveling in a horizontal direction is expressed as y = 5sin(60t - x)
What's the phase angle
(a)90° (b)180° (c)270° (d)360° (e)0°
Answer:
The equation of a transverse wave traveling along a very long string is y=6.0sin(0.020πx+4.0πt), where x and y are expressed in centimeters and t is in seconds. Determine (a) the amplitude, (b) the wavelength, (c) the frequency, (d) the speed, (e) the direction of propagation of the wave, and (f) the maximum transverse speed of a particle in the string. (g) What is the transverse displacement at x=3.5 cm when t=0.26s?/(a) The amplitude is y
m
=6.0 cm.
(b) We find λ from 2π/λ=0.020π⋅λ=1.0×10
2
cm.
(c) Solving 2πf=ω4.0π, we obtain f=2.0 Hz.
(d) The wave speed is v=λf=(100 cm)(2.0 Hz)=2.0×10
2
cm/.s
(e) The wave propagates in the −x direction, since the argument of the trig function is kx+ωt instead of kx−ωt
(f) The maximum transverse speed (found from the time derivative of y) is
u
max
=2πfy
m
=(4.0πs
−1
)(6.0 cm)=75 cm/s
(g) y(3.5 cm,0.26 s)=(6.0 cm)sin[0.020π(3.5)+4.0π(0.26)]=2.0 cm.
The position x of a bowling ball rolling on a smooth floor as a function of time t is given by: x(t)=v0t+x0x(t)=v0t+x0, where v0=2.5m/sv0=2.5m/s and x0=−5.0mx0=−5.0m. The polynomial relationship between position and time for the bowling ball is _______________. O cubic O inverse exponential O quadratic linear
The bowling ball's position and time are related by a linear equation.
What is linear equation?A linear equation is a mathematical formula that depicts the proportionate relationship between two or more variables, i.e., how changes in one variable cause predictable changes in the others.
The equation x(t) = v0t + x0, where v0 is the starting velocity of the ball (2.5 m/s) and x0 is the initial position of the ball, explains how the position of a bowling ball moving over a smooth surface change with time t. (-5.0 m).
In other words, the ball's position is proportional to the amount of time that has passed, with the beginning velocity, v0, serving as the proportionality constant. Since the ball's velocity is constant, its position advances linearly with time.
As a result, the bowling ball's polynomial relationship between location and time can be represented by a linear equation. Since cubic and inverse exponential equations are often non-linear and have more complicated forms, it is not one of those.
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(D) A water tank located at a depth of 8 m from ground level is half full of water. This water is pumped up by a water pump in the basement and drilled at 2 mis' access. 10 minutes until the water in the tank is finished 0: The power of the motor is 1 kW and the cross-sectional area of the tank is 2m. ii) Determine the useful work (output) done by the equation/x, (ii) Find the energy required for friction, (iii) Find the efficiency of the pump. (iv) Suggest a way to increase the value of (iii) above. (Density of water = 1000 kgm ]
The output by the equation and energy required for friction is 160,000 J. Efficiency is 0.267 or 26.7% and this efficiency can be improved by friction reduction.
What should be the method to calculate the output, friction and efficiency?The weight of the water pushed and the height it is lifted can be multiplied to determine the beneficial work done by the pump. The volume of water in the tank multiplied by its density yields the weight of the water therein. The tank's total volume, which can be determined by multiplying the tank's cross-sectional area by its height, is equal to half of the amount of water in the tank (8 m). The water therefore weighs:
Volume is calculated as cross-sectional area times height (2 m x 8 m = 16 m3).
Weight is equal to volume times density, or 16 m3 times a density of 1000 kg/m3 equals 16,000 kg.
Useful work=Weight x Height = 16,000 kg x 10 m = 160,000 J for useful work.
A proportion of the useful work can be used to estimate the amount of energy needed for friction. This proportion is influenced by the pump's design, the water's viscosity, and other elements. The energy needed for friction can be computed using a 10% friction loss as follows:
Frictional energy equals 0.1 x 160,000 J, or 16,000 J.
The ratio of the pump's useful work to its energy input can be used to calculate the pump's efficiency. The energy input can be estimated as the motor's power (1 kW) times how long it runs for (10 minutes, or 600 seconds). So, the efficiency can be determined as follows: Energy input is calculated as follows: 1 kW x 600 sec = 600,000
Efficiency is calculated as follows: 160,000 J of useful work per 600,000 J of energy input, or 26.7%.
The friction loss can be decreased, the pump's design can be improved to reduce energy losses, or the motor's power can be increased to increase the pump's efficiency. As the beneficial work performed by the pump is directly proportional to the height the water is lifted, increasing the height the water is lifted is another alternative.
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list two characteristics sound that are affected by the medium through which the sound passes and two characteristics that are not affected
The frequency of a sound wave remains constant when it moves through one medium to another, whereas the wave's temperature, velocity, and wavelength all change.
A frequency is defined.Frequency is the number of waves that pass through a specific spot in a defined amount of time. A wave has a frequency of 2 per second if it goes though within less than one second. if the time required becomes a hundredth of either an hour.
What does the frequency of a wave mean?The frequency of a recurrent occurrence, such as a wave, over a given time period is measured using this unit. A cycle is a single instance of the regular pattern. only waves that are moving and have different positions.
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If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1-A7)?
a. 3 A, 1A, 2A, 1A, 2A, 1A, 3A
b. 3 A, 2A, 1A, 1A. 1A, 1A, 2A
c. 3 A, 2A, 1A, 1A. 1A, 1A, 2 A
d. 3 A, 2A, 1A, 1A, 1A, 1A, 3A
If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1-A7), 3 A, 1A, 2A, 1A, 2A, 1A, 3A. so, option (a) is correct.
What is ammeter ?
A shunt and a gadget known as a galvanometer are parallelly linked within the ammeter. Shunts are resistances that let measured current flow through an ammeter and provide a complete readout. A sensitive current detector is the galvanometer.
What is power ?
Work is done at a certain rate according to power. P=Wt. The watt (W), which is equal to 1 joule per second (1J/s), is the SI unit of power. Power is the rate at which energy is used up since power is the transfer of energy. For instance, a 60-W light bulb uses about 60 J of energy every second.
Therefore, If a 100 V power supply is connected in the circuit below, what are the possibly correct readings on the ammeters clockwise from the upper left (A1-A7), 3 A, 1A, 2A, 1A, 2A, 1A, 3A. (a).
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Suppose a car's velocity is to the left, and its acceleration is to the right. Which of the following describes this car's motion? A) The car is speeding up. B) The car is slowing down. C) The car is moving at a constant speed.
The correct answer is B) The car is slowing down.
What is velocity?Velocity is a vector quantity that measure the rate and direction of the change. Velocity is an object position it is equal to distance traveled devide by time.
This is because when the velocity is to the left and the acceleration is to the right, the acceleration is in the opposite direction of the velocity.
This means that the car is experiencing a deceleration, or a slowing down of its velocity. Since the acceleration is to the right, the car is slowing down with respect to the right.
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true/false. a complete circuit is left on for several minutes, causing the connecting copper wire to become hot. as the temperature of the wire increases, the electrical resistance of the wire
The copper wire that connects the circuit is left on for a number of minutes before becoming heated. False, the wire becomes hotter as it gets hotter. Thus, it is false.
What is the electrical resistance of the wire?A complete circular path through which electricity flows is known as a circuit in electronics. A simple circuit consists of a current source, conductors, and a load.
The term “circuit” can broadly be used to describe any ongoing path via which electricity, data, or a signal might go.
Closed circuit, open circuit, short circuit, series circuit, and parallel circuit are the main varieties of electric circuits. The movement of electric charge or current has a conductive channel thanks to electric circuits.
Therefore, it is false that if a complete circuit is left on for a number of minutes, the copper wire that connects the devices gets warm. When the wire's temperature rises, so does its electrical resistance.
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2. A person standing at the edge of a cliff throws one ball straight up and another ball
straight down, each at the same initial speed. Neglecting air resistance, which ball hits the
ground below the cliff with the greater speed?
Answer:
the ball that is thrown down
Explanation:
due to force
b) By what factor does the fundamental frequency change when the mass per unit length of a guitar string increases by a factor of 3.50?
The fundamental frequency change when the mass per unit length of a guitar string increases by a factor of 3.50 is, 3.5ⁿ
What is frequency ?Frequency definition states that it is the number of complete cycles of waves passing a point in unit time, the SI unit of frequency is Hertz(Hz),
The frequency of a sinusoidal wave as the number of complete oscillations made by any wave element per unit of time.
The frequency of vibration of a string depends on the length L between the nodes,
the tension F in the string and its mass per unit length m.
Frequency,
f ∝ [Lᵃ] ... (1)
f ∝ [Fᵇ] ...(2)
f ∝ [Mⁿ] ...(3)
Combining equation (1) (2) and (3) we can say:
f₀ = k[Lᵃ x Fᵇ x Mⁿ]
So, when the mass per unit length increases by a factor of 3.50
Then, the new frequency is,
f = k[Lᵃ x Fᵇ x( 3.5M)ⁿ]
= 3.5ⁿ x k[Lᵃ x Fᵇ x Mⁿ]
f = 3.5ⁿ f₀
Hence, the frequency will increase by a factor of 3.5ⁿ
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In which circumstance would hypnosis be most effective and appropriate?
A golf ball (lighter) is fired at a bowling ball (heavier) initially at rest and bounces back elastically. Compared to the bowling ball, the golf ball after the collision has
a) less momentum but more kinetic energy
b) more momentum but less kinetic energy
c) more momentum and more kinetic energy
d) less momentum and less kinetic energy
Compared to the bowling ball, the golf ball after the collision has a) less momentum but more kinetic energy.
The bowling ball's velocity and, consequently, its kinetic energy are significantly lower than those of the golf ball because its mass is significantly greater than that of the latter.
Why is the kinetic energy of a bowling ball greater than that of a golf ball?
First off, heavier objects in motion have more kinetic energy than lighter ones. For example, a bowling ball travelling at 10 m/s (the equivalent of a very fast sprint) has a lot more kinetic energy than a golf ball travelling at the same speed.
How does a collision between a bowling ball and bowling pins alter their kinetic energy?
When two objects collide, some of the kinetic energy is converted during the collision to another form of energy, this is known as an inelastic collision. A portion of the kinetic energy from the bowling ball is transferred to the pins when it strikes them, as evidenced by the way bowling balls and pins scatter and bounce after impact.
Which ball has more inertia, a golf ball or a bowling ball?
As a result of having more mass than a golf ball, a bowling ball will have a higher moment of inertia.
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2) Three positive charges are located as shown in the diagram below q1 1cm q3 q1 1cm q2 find the size of electrostatic force exerted by charge q3.
A 238.8 g sample of water at 17.5°C is heated to steam at 118.9°C. How much heat was absorbed?
Answer:
535.3 kJ heat was absorbed.
Explanation:
The heat absorbed by the water can be calculated using the equation:
Q = mLf
where Q is the heat absorbed, m is the mass of the water, Lf is the heat of vaporization, and Lf is the amount of heat required to vaporize a substance at a constant temperature.
The heat of vaporization of water at 100°C is 40.7 kJ/mol. Since 1 mol of water has a mass of 18.02 g, the heat of vaporization per gram of water is 40.7 kJ/mol / 18.02 g/mol = 2.257 kJ/g.
So the heat absorbed by the 238.8 g of water can be calculated as:
Q = 238.8 g * 2.257 kJ/g = 535.3 kJ.
This is the amount of heat energy absorbed by the water to convert from a liquid at 17.5°C to a gas at 118.9°C.
A cannon is fired horizontally with a velocity of 125 m/s from a castle wall that is 250 m tall. a) How far from the wall does the cannon ball land?
b) With what velocity (v f and θ) does the cannon ball hit the ground?
c) What is the acceleration of the cannon ball just before it hits the ground?
(a) The horizontal distance traveled is 1940 m.
(b) The final velocity and the angle with which the cannon hits the ground are of the cannon is 180.07 m/s and 63.4⁰ respectively.
(c) The acceleration of the cannon ball just before it hits the ground is 29.44 m/s².
What is the time of flight of the cannon?The time of flight or time of motion of the cannon is calculated as follows;
t = √ ( 2h / g )
where;
h is the height g is acceleration due to gravityt = √(2 x 250 / 9.8 )
t = 15.6 s
The horizontal distance traveled can be found using the velocity and time of flight,
Horizontal distance (d) = vt
d = 125 m/s x 15.6 s
d = 1940 m
The final velocity of the cannon is calculated as ;
Vertical velocity (v fy ) = gt
v = 9.8 x 15.6 s
v = 153.68 m/s
v f = √(Vx² + Vy²)
vf = √ (125² + 153.68²)
vf = 180.07 m/s
θ = arc tan ( Vy / Vx )
θ = arc tan (153.68 m/s / 125 m/s)
θ = 63.43°
The acceleration of the cannon ball just before it hits the ground can be calculated using the final velocity and the time of flight,
a = (v f² - v i²) / (2t)
a = (180.07² - 0²) / (2 x 15.6 s)
a = 29.44 m/s²
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A man pushes a lawn mower on a level lawn with a force of 186 N. If 26% of the force is directed horizontally, how much work is done by the man in pushing the mower 6.5 m?
Answer:
W = 48.36 x 6.5 = 314.34 J.
Explanation:
The work done by the man in pushing the mower is the force multiplied by the displacement. Since 26% of the force is directed horizontally, we can calculate the amount of force that is directed horizontally as 0.26 x 186 N = 48.36 N. The work done is then calculated as W = F x s, where F is the horizontal force and s is the displacement. Therefore, the work done by the man in pushing the mower 6.5 m is W = 48.36 x 6.5 = 314.34 J.
Answer:
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Explanation:
ITS DUE IN 5 MINSSSSSSs Through his investigation, Nathanial identified when equal forces are applied to an object, the motion of the object does not change. He started a data table to record the evidence from his investigation. Which further evidence can Nathanial use to support his findings? (ANSWER RIGHT NOW, ITS DUE LITERALLY IN 10 MINS)
67 N in row one and 110 N in row two
120 N in row one and 67 N in row two
115 N in row one and 65 N in row two
100 N in row one and 65 N in row two
Answer:
Explanation:
2nd choice: 120 N in row one and 67 N in row two
Applied forces have to be equal in magnitude and opposite in direction to cancel each other out and result in no change to the object's motion
Choose: The opposite figure shows a mercury barometer. If the height of the mercury column in the barometer was (h) when the atmospheric pressure was 1.01 x 105 N/m² the value of pressure at point x equals a) 1.01 x 105 N/m² b) 6.73 x 104 N/m² c) 2.52 x 104 N/m² d) 7.58 x 104 N/m² Vacuum Mercury
The pressure at the point x is atmospheric pressure was . Option A
What is the pressure in the arms of the barometer?
We know that the barometer is a kind of device that can be used in the measurement of the pressure of the substance. We have to note that the barometr does have two arms.
The image of the barometer is not shown in this question but we know that the pressure does become equilibrated between the two arms of the barometer that have been shown such that the have the same pressure.
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O FIND THE MOMENT OF INERTIA IF MASS is 20kg and radius 2m
The moment of inertia (I) of the given object is 40 kg m².
The moment of inertia of the given body having the mass of 20 kg and radius 2 m can be calculated using the formula:
I = (1/2)× m × r²
where 'm' is the mass of the body and 'r' is the radius.
Putting the values in the above equation :
I = (1/2) × 20 kg × 2m × 2m
I = (1/2) × 20 kg × 4 m²
I = 40 kg m²
So, the moment of inertia of the object given is 40 kg m².
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HELP ME QUICKLYYYYY!!! TYYY
Listed in the Item Bank are some important labels for sections of the image below. Drag and drop each label to the corresponding area it identifies in the image.
1: cell membrane
2: nucleus
3: DNA
4: cytoplasm
5: ribosome
Answer:
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Explanation: