At STP, 32 grams of O2 would occupy the same volume as:
At STP 32 g of O₂ would occupy by the same volume as 4 g of He
Further explanationComplete question
At STP 32 g of O₂ would occupy by the same volume as:
4.0 g of He8.0 g of CH₄64 g of H₂32 g of SO₂Standard Conditions
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So the gas will have the same volume if the number of moles is the same
mol of 32 grams of O₂ :
[tex]\tt \dfrac{32}{32}=1[/tex]
He[tex]\tt mol=\dfrac{4}{4}=1[/tex]
CH₄[tex]\tt mol=\dfrac{8}{16}=0.5[/tex]
H₂[tex]\tt mol=\dfrac{64}{2}=32[/tex]
SO₂[tex]\tt mol=\dfrac{32}{64}=0.5[/tex]
So mol of 4 g He = mol of 32 g O₂
STP is the standard temperature and pressure of the gas to compare with the experimental data. At STP 32 gm of oxygen is equivalent to 4 gm of helium.
What is STP?STP is the standard temperature and pressure of 0 degrees Celsius and 1 atm. At this temperature and pressure, the volume of the gas is 22.4 L/mol.
So, if the moles of the 32 gm oxygen are the same as the other element then the volume will also be the same. Here, the moles of oxygen are 1 mol.
Moles of 4 gm helium is 1, 8 gm methane is 0.5 mol, 64 gm dihydrogen is 32 mol, and 32 gm sulfur dioxide is 0.5 mol.
Therefore, the mole of 4 gm helium is equivalent to the mole of 32 gm oxygen.
Learn more about STP here:
https://brainly.com/question/25705287
Globular proteins play a critical role in virtually all chemical processes.
True or false
Answer:
True
Explanation:
A 0.700 g unknown mixture with CaCl2 reacts with aqueous sodium phosphate to give 0.425 g Ca3(PO4)2. Show calculation for the percentage CaCl2?
The percentage CaCl₂ : 65.14%
Further explanationA reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Reaction
3CaCl₂+2Na₃PO₄⇒Ca₃(PO₄)₂ + 6NaCl
mol Ca₃(PO₄)₂(MW=310.18 g/mol) :
[tex]\tt \dfrac{0.425}{310.18}=0.00137[/tex]
mol ratio CaCl₂ : Ca₃(PO₄)₂ = 3 : 1, so mol CaCl₂ :
[tex]\tt \dfrac{3}{1}\times 0.00137=0.00411[/tex]
mass CaCl₂ (MW=110.98 g/mol) :
[tex]\tt 0.00411\times 110.98=0.456~g[/tex]
The percentage CaCl₂ :
[tex]\tt \%CaCl_2~in~mixture=\dfrac{0.456}{0.7}\times 100\%=65.14\%[/tex]
Calculate the total Calories in one cup of watermelon containing 0.9 g protein, 0.2 g fat, and 11 g carbohydrat
Answer:
49.4 cal
Explanation:
Step 1: Given data
Composition of 1 cup of watermelon: 0.9 g protein, 0.2 g fat, and 11 g carbohydrate.
Step 2: Calculate the calories provided by 0.9 g of protein
1 g of protein yields 4 cal.
0.9 g × (4 cal/1 g) = 3.6 cal
Step 3: Calculate the calories provided by 0.2 g of fat
1 g of fat yields 9 cal.
0.2 g × (9 cal/1 g) = 1.8 cal
Step 4: Calculate the calories provided by 11 g of carbohydrate
1 g of carbohydrate yields 4 cal.
11 g × (4 cal/1 g) = 44 cal
Step 5: Calculate the total number of calories
3.6 cal + 1.8 cal + 44 cal = 49.4 cal
Determine the differences In electronegativity ionic radius atomic radius and first ionization energy for oxygen and beryllium
Answer:
Electronegativity = 1.87.
Ionic radius = 109 pm.
Atomic radius = -39 pm
First ionization energy = 410 kJ/mol
Explanation:
Hello!
In this case, since electronegativity, ionic radius, atomic radius and first ionization energy are periodic properties that have specific trends, we can summarize it by realizing that oxygen and beryllium belong the same period 2 and differ in group, 6A and 2A respectively.
In such a way, the required comparison is written below:
Electronegativity = 3.44 (oxygen) - 1.57 (beryllium) = 1.87.
Ionic radius = 140 pm (oxygen)- 31 pm (beryllium) = 109.
Atomic radius = 73 pm (oxygen) - 112 pm (beryllium) = -39 pm
First ionization energy = 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium) = 410 kJ/mol
It means that electronegativity, ionic radius and first ionization energy increases from left to right whereas the atomic radius from right to left.
Best regards!
Oxygen and Beryllium are the elements that pertain to the same period and different groups 6A and 2A.
Ionic radius, atomic radius, electronegativity and first ionization energy are periodic qualities that have selective trends.
Differences in the trends are:
Ionic radius = 109 pmAtomic radius = -39 pmElectronegativity = 1.87First ionization energy = 410 kJ/molThis can be explained as:
Ionic radius:= 140 pm (oxygen)- 31 pm (beryllium)
= 109.
Atomic radius:= 73 pm (oxygen) - 112 pm (beryllium)
= -39 pm
Electronegativity:= 3.44 (oxygen) - 1.57 (beryllium)
= 1.87
First ionization energy:= 1310 kJ/mol (oxygen) - 900 kJ/mol (beryllium)
= 410 kJ/mol
Therefore, these data tell that ionic radius, electronegativity and first ionization energy increases from left to right in a period whereas, the atomic radius increases from right to left in a period.
To learn more about periodic trends follow the link:
https://brainly.com/question/12074167
What is the acceleration of gravity on Saturn if your mass is 75 kg and your weight is 800n
Answer:
The answer is 10.67 m/s²Explanation:
The acceleration of gravity of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{800}{75} = \frac{32}{3} \\ = 10.666666...[/tex]
We have the final answer as
10.67 m/s²Hope this helps you
How many moles are in 1.2 x 1023 Rps?
CHEMWORK The preparation of NO2(g) from N2(g) and O2(g) is an endothermic reaction: N2(g) + O2(g) + NO2(g) (unbalanced) The enthalpy change of reaction for the balanced equation (with lowest whole-number coefficients) is AH = 67.7 kJ. If 304 ml N2 (9) at 100ºC and 3.32 atm and 410 ml 0,(9) at 100°C and 3.32 atm are mixed, what amount of heat is necessary to synthesize the maximum yield of NO2(g) ?
Heat required : 1.523 kJ
Further explanationReaction
N₂+2O₂⇒2NO₂ AH = 67.7 kJ
mol of N₂:(use Pv=nRT)
[tex]\tt n=\dfrac{3.32\times 0.304}{0.082\times 373}=0.033[/tex]
mol of O₂:
[tex]\tt n=\dfrac{3.32\times 0.41}{0.082\times 373}=0.045[/tex]
Limiting reactant :
N₂ : O₂
[tex]\tt \dfrac{0.033}{1}\div \dfrac{0.045}{2}=0.033:0.0225[/tex]
Limiting reactant : O₂(smaller ratio)
mol NO₂ = mol O₂ = 0.045
2 mol ⇒ 67.7 kJ, so for 0.045 mol, heat required :
[tex]\tt \dfrac{0.045}{2}\times 67.7=1.523~kJ[/tex]
The heat required to produce the maximum yield of NO2 is 1.52 kJ.
The balanced reaction equation is;
N2(g) + 2 O2(g) -> 2 NO2(g)
The number of moles of each gas is obtained from the ideal gas equation as follows;
For N2;
P = 3.32 atm
V = 304 ml or 0.304 L
T = 100ºC + 273 = 373 K
n = ?
R = 0.082 atmLK-1mol-1
From;
PV = nRT
n = PV/RT
n = 3.32 atm × 0.304 L/0.082 atmLK-1mol-1 × 373 K
n = 0.033 moles
For O2;
PV = nRT
n = PV/RT
V = 410 ml or 0.410 L
P = 3.32 atm
R = 0.082 atmLK-1mol-1
T = 100°C + 273 = 373 K
n = 3.32 atm × 0.410 L/0.082 atmLK-1mol-1 × 373 K
n = 0.045 moles
1 mole of N2 reacts with 2 moles of O2
0.033 moles of N2 reacts with 0.033 moles × 2 moles/1 mole
= 0.066 moles
2 moles of O2 yields 2 moles of NO2
0.045 moles O2 yields 0.045 moles × 2 moles/2 moles = 0.045 moles
If 2 mole of NO2 requires 67.7 kJ
0.045 moles of NO2 requires 0.045 moles × 67.7 kJ/2 mole
= 1.52 kJ
Learn more: https://brainly.com/question/9743981
If the earth were to spin half as fast as it does now, how many hours would be in one day?
Answer:
48 hours
Explanation:
Because if the world would spin regularly, then it would take 24 hours. But if it spins half as fast, then it would be 2x more.
What is a chemical change?
A change in matter from one form to another that doesn't result in a different substance
A gravitational pull that results in a different substance
A reaction or change in a substance that creates more of the same substance
A reaction or change in a substance that results in a different substance
Answer:
D. A reaction or change in a substance that results in a different substance
Explanation:
Chemical changes occur when a substance combines with another to form a new substance, called chemical synthesis or, alternatively, chemical decomposition into two or more different substances.
Jet streams generally flow toward the
a. north
b. south
c. east
d. west
please answer thank you
Answer:
The major jet streams on Earth are westerly winds that flow west to east.
A gas with a volume of 525 mL at a temperature of -25°C is heated to 175°C.
What is the new volume, in milliliters, of the gas if pressure and number of moles
are held constant?
Answer:
Volume V2 = 948.13 ml
Explanation:
Given:
Volume V1 = 525 ml
Temperature T1 = -25°C + 273.15
Volume V2 = ?
Temperature T1 = 175°C + 273.15
Computation:
V1 / T1 = V2 / T2
525 / [-25°C + 273.15] = V2 / [175°C + 273.15]
Volume V2 = 948.13 ml
The new volume, in milliliters, of the gas is 948 L
From the question,
We are to determine the new volume of the gas.
From Charles' law which states that the volume of a fixed mass of gas is directly proportional to the temperature (in Kelvin) provided that the pressure remains constant.
That is,
V ∝ T
Then,
V = kT
Therefore, we can write that
[tex]\frac{V_{1} }{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]
Where [tex]V_{1}[/tex] is the initial volume
[tex]T_{1}[/tex] is the initial temperature
[tex]V_{2}[/tex] is the final volume
and [tex]T_{2}[/tex] is the final temperature
From the given information,
[tex]V_{1} = 525 \ mL[/tex]
[tex]T_{1} = -25 ^{\circ}C = -25 + 273.15 \ K = 248.15 \ K[/tex]
[tex]T_{2} = 175 ^{\circ} C = 175 +273.15 \ K =448.15 \ K[/tex]
Putting the values into the formula, we get
[tex]\frac{525}{248.15} = \frac{V_{2} }{448.15}[/tex]
∴ [tex]V_{2} = \frac{525 \times 448.15}{248.15}[/tex]
[tex]V_{2} = \frac{235278.75}{248.15}[/tex]
[tex]V_{2} = 948.13 \ L[/tex]
V₂ ≅ 948 L
Hence, the new volume, in milliliters, of the gas is 948 L
Learn more here: https://brainly.com/question/12717895
can a water cycle ever end
Answer:
No It cannot.
Explanation:
A water cycle does not have an end as it moves all around the earth
The process:
A water cycle can start by water evaporating through the sun's heat from a water bed, such as: Ocean, sea, pond etc.
The heat from the sun will turn the water into water vapour and will go up into the atmosphere.
The water vapor gets together with other vapors and forms clouds.
These clouds will move around the earth, once they are so full of water they drop the water to Earth in some form of precipitation. It could be rain, snow, sleet, or hail.
These water will form ponds or go back in the ocean and the process wil repeat again.
Can a closed system gain particles
According to the ideal gas law, a 10.68 mol sample of methane gas in a 0.8295 L container at 501.9 K should exert a pressure of 530.3 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure
Answer:
The answer is "152.28%".
Explanation:
Formula for ideal gas:
PV=nRT
equation:
[tex]\to (P+\frac{an^2}{v^2})(v-nb)=nRT \\\\a=2.253 \frac{L^2 atm}{mol^2}\\\\b=4.278 \times 10^{-2} \frac{L}{mol}\\\\n=10.68 \ mol\\\\v= 0.8295 \ L\\\\\to (P+\frac{an^2}{v^2})= \frac{nRT}{(v-nb)}\\\\\to (P)= \frac{nRT}{(v-nb)} - \frac{an^2}{v^2} \\\\[/tex]
[tex]= \frac{10.68 \times 0.0082 \times 501.9}{0.8295 - (10.68 \times 4.278 \times 10^{-2})} - \frac{2.253 \times 10.68^2}{0.8295^2}\\\\=\frac{43.9543944}{0.4568904} - \frac{256.982587}{0.68807025}\\\\ = 96.2033661- 373.483067\\\\=-277.279701 \\\\ =-277.279701 \ atm[/tex]
The pressure of gas:
[tex]= (530.3 + 277.279701) \ atm\\\\= 807.579701 \ atm \\\\[/tex]
Calculating the pressure percentage:
[tex]=\frac{807.579701}{530.3} \times 100\\\\= 152.28 \%[/tex]
which of the following requires the most energy to break a bond? a. breaking cl-br bond. b. breaking a n-p bond. c. breaking a o-o bond. d. none of the above.
A. Breaking a Cl-Br bond
2. A green laser pointer emits light at 554 nm. Calculate the frequency of this light and the energy of a photon of this light.
Answer:
Explanation:
Wavelength (λ) = speed/frequency
(λ) = c/f
Where;
c = speed (3× 10^8m/s)
f = frequency (Hz)
(
Calculate the molar solubility of mercury (I) bromide, Hg2Br2, in 1.0 M KBr. The Ksp for Hg2Br2 is 5.6 X 10−23. (Hint: How would the Br− concentration from the sparingly soluble compound itself compare to the Br− concentration that comes from the KBr?
Answer:
The correct answer is 5.6 × 10⁻²³ M.
Explanation:
As a highly soluble salt, KBr dissolves easily in water, while Hg₂Br₂ is very less soluble in comparison to KBr.
Let the solubility of Hg₂Br₂ is S mol per liter.
Therefore,
KBr (s) (1.0 M) ⇒ K⁺ (aq) (1M) + Br⁻ (aq) (1M)
Hg₂Br₂ (s) (1-S) ⇔ Hg₂⁺ (aq) (S) + 2Br⁻ (aq) (2S)
Net [Br-] = (2S + 1) M
Ksp = S (2S + 1)²
Ksp = S (4S² + 1 + 4S)
Ksp = 4S³ + S + 4S²
As the solubility is extremely less, therefore, we can ignore S² and S³. Now,
Ksp = S = 5.6 × 10⁻²³ M
Hence, the solubility of Hg₂Br₂ is 5.6 × 10⁻²³ M.
2-methyl-butanamide hydrolysis with NaOH
2-methyl-butanamide hydrolysis with NaOH forms a carboxyllic acid, sodiun salt of 2-methyl butanoic acid and ammonia
Explanation:
Chlorine dioxide is used as a disinfectant and bleaching agent. In water, it reacts to form chloric acid (HClO3), according to the following balanced equation: 6 ClO2 + 3 H2O → 5 HClO3 + HCl If excess ClO2 is mixed with 18.0 mL of H2O (d = 0.998g/1ml ) how many grams of HClO3 are formed?
would be very helpful if the answer was explained with steps
Answer:
b
Explanation:
b
Would someone mind helping me? I really need this answer but I'm so confused. I would appreciate any help :) and if you get the answer right, ill give you brainliest.
Answer:
A
Explanation:
liquids thake the shape of what holds them so shape is changing and volume is the same
which 2 organ systems work together to break down and deliver food molecules to cells
A. Cardiovascular and immune
B. Nervous and muscular
C. Digestive and cardiovascular
D. Respiratory and cardiovascular
PLEASE HURRY I NEED THIS ANSWER
Answer:
C
Explanation:
The stomach digests the food (Digestive System) are the nerves and they send the protein etc.
Calculate the mass of Na2O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction.
4NA + O2 ⟶ 2Na2O
Answer:
The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.
Explanation:
You know the balanced reaction:
4 NA + O₂ ⟶ 2 Na₂O
By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) react and are produced:
Na: 4 molesO₂: 1 moleNa₂O: 2 molesBeing:
Na: 23 g/oleO: 16 g/molethe molar mass of the compounds participating in the reaction is:
Na: 23 g/moleO₂: 2*16 g/mole= 32 g/moleNa₂O: 2*23 g/mole +16 g/mole= 62 g/moleThen by stoichiometry of the reaction they react and are produced:
Na: 4 moles* 23 g/mole= 92 gO₂: 1 mole*32 g/mole= 32 gNa₂O: 2 moles* 62 g/mole= 124 gThen you can apply the following rule of three: if 92 grams of Na produce 124 grams of Na₂O, 4 grams of Na, how much mass of Na₂O does it produce?
[tex]massofNa_{2}O =\frac{4 grams of Na*124 gramsofNa_{2}O }{92 grams of Na}[/tex]
mass of Na₂O=5.39 g
The mass of Na₂O that can be produced by the chemical reaction of 4.0 grams of sodium with excess oxygen in the reaction is 5.39 grams.
Scientists use models to help them represent things in nature that they cannot observe directly. They can also use models to make predictions. For example, scientists use Bohr models of atoms to predict chemical reactions between atoms, You can use models in the same way, but you must first understand what each model component represents. Which element is represented by this Bohr model?
A. chlorine (Cl)
B.oxygen (O)
C. selenium (Se)
D. sulfur (S)
Answer:
I think it’s chlorine (Cl)
Explanation:
I’m literally doing the same question right now
How much kilometers is in 6 m
Answer: 0.006 km
Explanation:
divide the length value by 1000
so 6/1000 = 0.006
hhhheeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeelllllllllllllllllllllllllllllllppppppppppppppppppp
Answer:
What do you need help with?
Explanation:
3 moles of hydrogen occupy a volume of 67.20 L, at standard temperature and pressure (STP, 0 ˚C and 760 mmHg). What is the density of hydrogen at STP?
Answer:
The correct answer is 0.089 g/L ≅ 0.09 g/L
Explanation:
Density is defined as: mass/volume.
From the problem we have:
number of moles = n = 3 mol
volume = V = 67.20 L
We have to calculate the mass. For this, we need the molar mass (MM) of the gas. That is easily calculated from the molar mass of the element hydrogen (H), as we know that hydrogen gas has the molecular formula H₂:
MM(H₂) = 2 x molar mass H = 2 x 1 g/mol = 2 g/mol
Now, we multiply n by MM to obtain the mass (m) of the gas:
m = n x MM(H₂) = 3 mol x 2 g/mol = 6 g
Finally, we calculate the density from the mass and volume:
density = m/V = 6 g/(67.20) = 0.089 g/L ≅ 0.09 g/L
If I have an unknown quantity of gas at STP with a volume of 41 liters, how many moles of gas do
have?
Answer:1 mol
Explanation:
the conversion from mol to volume of gas at STP is 22.4L, meaning that the amount of mols in a gas of volume 22.4L at STP is one mol.
(7th grader sorry if its wrong)
If a cell is 80% water and the outside environment is 90% water. What is likely to happen?
A. water will rush into the cell
B. net movement of water will be equal
C. water will not move into or out of the cell
D. water will rush out of the cell
If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be person’s acceleration?
Answer:
a = 4 ms⁻²
Explanation:
Given data:
Mass of person = 60 Kg
Mass of sled = 15 kg
Applied force = 300 N
Acceleration = ?
Solution:
Formula:
F = ma
F = force
m = mass
a = acceleration
now we will put the values in formula.
300 N = (60 Kg+ 15 kg) × a
300 N = 75 Kg × a
a = 300 N/ 75 Kg
N = kgm/s²
a = 4 ms⁻²