Square root of 4489 by division method

Answer: y=2X-3

Step-by-step explanation:

1st u need to subtract the 6 on each side so your left with, -6+X=3y, then u divide the 3 on each side and your left with, -3+2X=y.

Answer:

None of them are

(4,-4)

Step-by-step explanation:

To find the value of x make y =0 then substitute into the formula. Therefore 0 = x-4 then make x the subject by adding 4 to the other side 4+0=x.

Then to find the value of y make x=0 then substitute it into the formula y=0-4 which is equal to - 4

I hope this helps

Answer:

B

Step-by-step explanation:

Since he needs to make 2 appetizers per person, the variable "p" needs to go with the "2".

Also, since he is making 20 ( 4 trays, 5 apps each) extra  appetizers for the beginning, we will need to add 20 to that number.

Answer:

6/7

Step-by-step explanation:

2/3X9/7

simplify 9 by 3

which equals:

2/1X3/7

=6/7

Answer:

[tex]\huge \boxed{2\sqrt{5} +\sqrt{35}}[/tex]

Step-by-step explanation:

[tex]\sqrt{5} (2+\sqrt{7} )[/tex]

Expand brackets.

[tex]\sqrt{5} (2)+\sqrt{5}(\sqrt{7} )[/tex]

[tex]2\sqrt{5} +\sqrt{5} \sqrt{7}[/tex]

Apply radical rule : [tex]\sqrt{a} \sqrt{b} =\sqrt{ab}[/tex]

[tex]2\sqrt{5} +\sqrt{5 \times 7}[/tex]

[tex]2\sqrt{5} +\sqrt{35}[/tex]

Answer:

Option A is the correct option.

Step-by-step explanation:

[tex] \sf{ \sqrt{5} \: (2 + \sqrt{7} )}[/tex]

Distribute √5 through the parentheses

⇒[tex] \sf{ \sqrt{5} \times 2 + \sqrt{5} \times \sqrt{7} }[/tex]

Calculate the product

⇒[tex] \sf{2 \sqrt{5} + \sqrt{5 \times 7} }[/tex]

⇒[tex] \sf{2 \sqrt{5} + \sqrt{35} }[/tex]

Hope I helped!

Best regards!

Answer:

[tex]3+2-16x9[/tex] is [tex]5-16x^9[/tex]         [tex]4-3+7(12-2)[/tex] is [tex]71[/tex]

Step-by-step explanation:

Answer:

269points

Step-by-step explanation:

112/5=22.4

22.4x12=268.8

268.8≈269

Answer:

3

Step-by-step explanation:

The question is incomplete. Here is the correct question.

If NL = 13, find NM. NM = X+15 ML = 2x+34

Using vector notation, NL = NM+ML

Substituting the given parameters into the equation;

13 = x+15+(2x+34)

13 = x+15+2x+34

Collect like terms.

x+2x+15+34 = 13

3x+49 = 13

3x = 13-49

3x = -36

x = -12

Given NM = x+15 and x = -12

NM = -12+15

NM = 3

Answer:

A) 12x + 10y

B) 118cm

Step-by-step explanation:

A) A fórmula para calcular o perímetro de um retângulo é dada como:

Perímetro de um retângulo = 2 (L + W)

= 2L + 2W

Onde

L = comprimento do retângulo

W = largura do retângulo

A) A pergunta nos diz que:

O comprimento de um retângulo é 6x e sua largura é 5y.

A expressão algébrica que representa o perímetro do retângulo =

Perímetro de um retângulo = 2 (L + W)

= 2L + 2W

L = 6x, W = 5y

= 2 (6x) + 2 (5y)

= 12x + 10y

A expressão algébrica que representa o perímetro do retângulo é

P = 12x + 10y

B) Se x = 4 cm e y = 7 cm, qual é o valor numérico desse perímetro.

P = 12x + 10y

x = 4cm

y = 7cm

Perímetro = 12 (4) + 10 (7)

Perímetro = 48cm + 70cm

Perímetro do retângulo = 118cm

Portanto, o valor numérico do perímetro é 118cm

1. Solve for y (complex solution)

y=−iln(x2−1​+x)+2πn1​, n1​∈Z

y=−iln(−x2−1+x)+2πn2​, n2​∈Z

2. Solve for y (Easier)

y=−arccos(x)+2πn1​, n1​∈Z

y=arccos(x)+2πn2​, n2​∈Z, ∣x∣≤1

Hi there! :)

Answer:

(a) ≈ 3.61 cm.

(b) = 2.77 cm².

Use the Pythagorean theorem to solve for the side-length of DC. Let "s" represent the side-lengths:

s² + s² = 26

2s² = 26

Divide both sides by 2 to simplify:

s² = 13

Take the square root of both sides:

s = √13 ≈ 3.61 cm.

------------------------------------------------------------------------------------------

Calculate the shaded region by subtracting the area of the arc from the area of the square. DC represents the radius of the circle that the arc is apart of. Therefore:

Area of arc AC = 1/4 (πr²)

Solve for the area:

AC = 1/4 (π · (3.61)²)

AC = 1/4 (40.92)

AC = 10.23 cm²

Subtract this area from the area of the square (A = s²)

A = (√13)²

A = 13 cm²

13 - 10.23 = 2.77 cm²

Therefore, the solutions are:

(a) ≈ 3.61 cm.

(b) = 2.77 cm².

Answer:

Hey there!

The perimeter of the triangle is the distance around it.

We can find the distance of two points using the distance formula, and add up all the distances to find the total distance.

-4, -6 to 3, 3 is 2

3, 3 to 7, 2 is 5

7, 2 to -4, -6 is about 5.4

2+5+5.39=12.4, which is closest to 12.36.

Let me know if this helps :)

Answer:

[tex]\huge \boxed{b=2}[/tex]

Step-by-step explanation:

[tex]5(2- b) = 0[/tex]

[tex]\sf Divide \ both \ sides \ by \ 5.[/tex]

[tex]2-b=0[/tex]

[tex]\sf Subtract \ 2 \ from \ both \ sides.[/tex]

[tex]-b=-2[/tex]

[tex]\sf Cancel \ negative \ signs.[/tex]

[tex]b=2[/tex]

Answer:

b = 2

Step-by-step explanation:

5(2-b) = 0

=> 5 x 2 - 5 x b = 0

=> 10 - 5b = 0

=> -5b = -10

=> -b = -10/5

=> -b = -2

=> b = 2

Let's check whether our answer is correct:

=> 5(2-2) = 0

=> 5 (0) = 0

=> 0 = 0

Answer:

Equation of given line: y=8x+61

See graph below for a visual of given straight line equation.

+graph%28+300%2C+300%2C+-10%2C+10%2C+-100%2C+100%2C+8x%2B61%29+

Vertical and passes through (-4,-2)

vertical slope means that the equation becomes: x=-4, (y does not matter)

hope it helps

Answer: Either the plane and the ray perfectly coincide in which case there is an infinity of solutions or the ray is away from the plane in which case there is no intersection. Generally in a C++ implementation, when the denominator is lower than a very small value, we simply return false (no intersection was found).

Step-by-step explanation:

Answer: 2079

Step-by-step explanation: 11 x 9 x 3 x 7 = 2079, there are 2079 possible combinations of outfits

Using the Fundamental Counting Theorem, it is found that 2079 different outfits can be made.

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, considering the options, we have that [tex]n_1 = 11, n_2 = 9, n_3 = 3, n_4 = 7[/tex].

Hence, the total number of options is given by:

N = 11 x 9 x 3 x 7 = 2079.

More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866

#SPJ2

Answer:

You can't graph inverse function on graphing calculator

Step-by-step explanation:

step 1 rewrite function f(x) --> y

step 2 change x and y's position

step 3 solve for y

step 4 replace Y with f-1(up to f) and (x)

Answer:

7°F

Step-by-step explanation:

We have the following information from the question;

Morning temperature = -10°F

Increase in temperate = 17°F

Afternoon temperature = the unknown

Since;

Increase in temperature = Afternoon temperature - morning temperature

Then;

Afternoon temperature = increase in temperature + morning temperature

Afternoon temperature = 17°F + (-10°F)

Afternoon temperature= 7°F

Answer:

7

Step-by-step explanation:

Your welcome!

Complete question :

There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.

Answer:

575 - 12t

Step-by-step explanation:

Given the following :

Total number of fireworks = 575

Number of shots per minute = 12

To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.

In algebraic terms

[total number of fireworks on display - (number of shots per minute × t)]

575 - 12t

[tex] &#128075 [/tex] Hello ! ☺️

Step-by-step explanation:

∫sec(x)dx =

∫ [tex]\frac{sec(x).(secx + tanx)}{secx + tanx}dx[/tex]

∫ [tex] \frac{sec {}^{2} (x) + secxtanx}{secx + tanx}dx [/tex]

u = secx + tanx

[tex] du = secx tanx + sec {}^{2}x \: dx[/tex]

[tex] ∫\frac{1}{u}du [/tex]

∫sec(x)dx= ln |u|

[tex]\boxed{\color{gold}{∫sec(x)dx= ln |secx +tanx| + C}} [/tex]

[tex]<marquee direction="left" scrollamount="2" height="100" width="150">&#x1F498;Mynea04</marquee>[/tex]

Answer:

[tex] = \ln( | \sec(x) + \tan(x) | ) + C[/tex]

Step-by-step explanation:

[tex] \int \sec(x) dx[/tex]

multiply and divide by sec x + tan x

[tex] = \int \frac{ \sec(x) ( \sec(x) + \tan(x) ) }{ \sec(x) + \tan(x) } dx[/tex]

let u = sec x + tan x

du = (sec x)(sec x + tan x) dx

[tex] = \int \frac{1}{u} du[/tex]

[tex] = \ln( |u| ) + C[/tex]

[tex] = \boxed{\color{green}{ \ln( | \sec(x) + \tan(x) | ) + C}}[/tex]

Answer:

1-1/4 = 3/4.

3/4-1/4 = 2/4 = 1/2.

1/2-1/9 = 9/18-2/18 = 7/18.

7x/18 = 8400

X = $21,600 = Net Jan. salary.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

Answer:

Step-by-step explanation:

The length is x2 while the width is x1.5

Therefore it cannot be a scaled copy

Answer: It is not scale copy (given)

Step-by-step explanation:

Rectangle B: 15 by 10

Rectangle C: 30 by 15

-------------------------------------

First way: Compare the ratio among themselves

Rectangle B: 15:10=3:2

Rectangle C: 30:15=2:1

Apparently, the two side ratios are not the same, thus it is not scale copy

--------------------------------------

Second way: Compare the ratio between the two.

Length: Rectangle B:Rectangle C=15:30=1:2

Width: Rectangle B:Rectangle C=10:15=2:3

1:2≠2:3

Thus, Rectangle C is not a scaled copy of Rectangle B

Answer:

a and c

Step-by-step explanation:

a. 9=x

b.2x-12=2x-12   ims

c.3x+6=2x-5

3x+11=2x

11=-1x

-11=x

d. ims

Answer:

4

Step-by-step explanation:

Plug in 7 for d:

y= 1/2(7+1)

y=1/2(8) .... Adding what's in the parenthesis (PEMDAS)

y=4 ..... Multiply 1/2 by 8

Hope this helps:)

Answer:

Step-by-step explanation:

[tex] \sf{Given}[/tex]

[tex] \sf{d = 7}[/tex]

Let's find the value of y:

[tex] \sf{y = \frac{1}{2} (d + 1)}[/tex]

plug the value of d

[tex] \sf{ = \frac{1}{2} (7 + 1)}[/tex]

Add the numbers

[tex] \sf{= \frac{1}{2} \times 8}[/tex]

Calculate

[tex] \sf{ = 4}[/tex]

Hope I helped!

Best regards!

Step-by-step explanation:

(i) Let x = 0 and x-2y=4

Put x = 0 in x-2y=4

0-2y=4

-2y=4

y=-2

If x = 0, the value of y is -2.

(ii) Let y=0 and x-2y=4

Put y = 0 in x-2y=4

x-2(0)=4

x=4

If y = 0, the value of x is 4.

Answer:

See below (I hope this helps!)

Step-by-step explanation:

Because odd numbers are always 1 greater than even numbers, we can call the two odd numbers x + 1 and y + 1 where x and y are even integers. Multiplying the two gives us:

(x + 1) * (y + 1)

= x * y + x * 1 + 1 * y + 1 * 1

= xy + x + y + 1

We know that x * y will be even because x and y are also even and the sum of two even numbers will be even, and we also know that x and y are even and that 1 is odd. Since the sum of even and odd numbers is always odd, the product of any two numbers is always odd.

*NOTE: I put a limitation on x and y in my proof (the limitation was that x and y must be EVEN integers) but you don't have to do that, you could make the odd integers 2x + 1 and 2y + 1 where x and y could be any integer from the set Z like mirai123 did. I simply gave this proof because it was the first thing that came to mind. While mirai123's proof and mine are different, they are still both correct.

Answer:

Prove that the product of any two odd numbers is always odd.

Examples:

[tex]3 \cdot 7 = 21 \text{ } \boxed{\text{odd}}\\5 \cdot 9 = 45 \text{ } \boxed{\text{odd}}\\83 \cdot 3 = 249 \text{ } \boxed{\text{odd}}[/tex]

Defining an odd number as:

[tex]u= 2k+1, k \in \mathbb{Z}[/tex]

[tex]u \cdot u = (2k+1)(2k+1)= 4k^2+4k+1[/tex]

[tex]\text{Is } \boxed{4k^2+4k+1} \text{ odd?}[/tex]

Yes, it is, because [tex]4k^2 \text{ and } 4k \text{ will always be even considering } k \in \mathbb{Z}[/tex]

An even number plus one is an odd number.

Answer:

= 59​

Step-by-step explanation:

5 - 2 * 3 + 6 (3² + 1)

= 5 - 2 * 3 + 6 * 10

= 5 - 6 + 6 * 10

= 5 - 6 + 60

= 59​

Answer:

Step-by-step explanation:

[tex]5-2\times \:3+6\left(3^2+1\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3^2+1\right)\::\quad 10\\\\=5-2\times \:3+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times \:3\::\quad 6\\=5-6+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:6\times \:10\::\quad 60\\\\=5-6+60\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5-6+60\:\\\\:\quad 59[/tex]

Answer:

x=881/110 =8^1/110 =8.009

Step-by-step explanation:

2.75(2x−14)=5.55

Divide both sides by 2.75.

2x-14=5.55/2.75

Expand  5.55/2.75 by multiplying both numerator and the denominator by 100.

2x−14= 555/275

Reduce the fraction  555/275 to lowest terms by extracting and canceling out 5.

2x−14= 111/5

Convert 14 to fraction  770/55 = 14

2x=111/55+770/55

Since 111/55 and 770/55 have the same denominator, add them by adding their numerators.

2x=111+770/5

Add 111 and 770 to get 881.

2x=881/55

Divide both sides by 2.

x= 881/55/2

Express 881/55/2 as a single fraction.

x= 881/55 x 2

Multiply 55 and 2 to get 110.

x = 881/110

Answer:

Step-by-step explanation:

[tex]2\frac{1}{4}[/tex] ÷[tex]\frac{1}{2}[/tex] = [tex]\frac{9}{4}[/tex] ÷ [tex]\frac{1}{2}[/tex]

        [tex]=\frac{9}{4}*\frac{2}{1}\\\\\\=\frac{9}{2}\\\\\\=4\frac{1}{2}[/tex]