Answers
Answer:
Explanation:
For an ideal spring over a frictionless horizontal surface, stored energy is only a function of the spring constant k and the distance of compression. The mass of the block doing the compressing is irrelevant
Energy stored in the first example is
Em = ½kd²
Energy stored in the second example is
E₂m = ½k(2d)² = 4(½kd²) = 4Em
So the second situation has four times as much stored spring potential energy as the first situation
4 Em is correct
Good job!
Related Questions
What is an element?
1. A substance made of more than one type of atom.
2. A substance that is made of water.
3. A substance that is made of no atoms.
4. A substance made of only one type of atom.
Answers
Answer:
Hey Friend...
Explanation:
This is ur answer.....
4. A substance made of only one type of atom.Hope it helps!
Brainliest pls!
Follow me! :)
Answer:
4
Explanation:
element is a substance that cannot be broken down into any other substance which means every element is made up of its own type of atom
1. An airplane flies with an airspeed (speed relative to the air) of 215
km/h. The wind is blowing at 45.0 km/h. Find the velocity of the
plane (relative to the ground) if the plane is pointed straight west and
the wind is:
A. blowing toward the
west (3 points)
B. blowing toward the east (3 points)
C. blowing toward the south (4 points)
(For part C be sure to calculate the angle as well.)
Answers
Answer:
Explanation:
A) 215 + 45.0 = 260 km/h West
B) 215 - 45.0 = 170 km/h West
C) √(215² + 45.0²) = 219.6588... 220 km/h
θ = arctan(45.0/215) = 11.8214... 11.8° S of W
The airplane's ground velocity is westward at 170 km/h regardless of wind direction. The south wind does not affect the plane's westward velocity in component C.
Vector addition will determine each scenario's plane velocity relative to the ground. We'll simplify by assuming a consistent horizontal breeze.
Let's divide the airplane's velocity and wind velocity into westward (negative) and eastward (positive) components.
Data: Plane airspeed = 215 km/h.
45 km/h wind.
A. West wind:
The airplane's westward (negative) ground velocity:
West aeroplane velocity = -215 km/h
-45 km/h west wind.
Find Vg when the wind blows west:
Vg (west) = Aeroplane velocity + Wind velocity (west)
Vg(west) = -215 km/h - (-45 km/h)
Vg (west)=-170 km/h
B. East wind: 2. Westward (negative) aeroplane velocity relative to the ground:
West aeroplane velocity = -215 km/h
Wind velocity (east) = 45 km/h (because the wind is blowing eastward)
Find Vg when the wind blows east:
Vg (west) = Aeroplane velocity (west) + Wind velocity (east).
Vg (west) = -215 + 45 km/h
Vg (west)=-170 km/h
C. Southerly wind: 3. Westward (negative) aeroplane velocity:
West aeroplane velocity = -215 km/h
Wind velocity (south) = 0 km/h (no effect since wind is not moving westward)
Find Vg when the wind blows south:
Vg (west) = Aeroplane velocity (west) + Wind velocity (south).
Vg (west) = -215 + 0 km/h.
Vg (west)=-215 km/h
All resultant velocities are westward and 170 km/h.
Part C's plane's westward velocity is unaffected by the south wind. The plane's ground velocity remains -215 km/h (westward). Since the heading is westward, no angle is needed.
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explain the different conditions that can result in hot and cold lahars, and explain how lahars change the earth's surface?
Answers
) Water flows through the system shown below. Estimate the volumetric flow rate if friction
losses are negligible.
Answers
The volumetric flow rate if friction is negligible = 0.00197 m³/sec
Given data :
P₁ = 7 atm = 709.275 kPa
P₂ = 1.5 atm = 151.988 kPa
d₁ = 0.74 cm = 0.0074 m
d₂ = 1.20 cm = 0.0120 m
h = 82 m
density of water ( p ) = 1000 kJ/m³
Estimate the volumetric flow rate
given that friction losses are negligible
V₁² - V₂² = [tex]\frac{2(P_{2} - P_{1}) }{p} + 2g(h )[/tex]
= 2( 151.988 - 709.275 ) + 2 * 9.81 * 82
= 2 ( - 557.287 ) + 1608.84
= - 1114.574 + 1608.84 = 494.266
∴ V₁² - V₂² = 494.266 ----- ( 1 )
Also given that:
volumetric flow rate ( Q ) = A₁V₁ = A₂V₂
= π / 4 ( 0.0074 )² * V₁ = π / 4 ( 0.0120 )² * V₂
= 0.000043 V₁ = 0.000113 V₂
∴ V₁ = 2.63 V₂
Back to equation ( 1 )
( 2.63 v₂ )² - V₂² = 494.266
V₂² = ( 494.266 ) / 1.63
∴ V₂ = √303.23 = 17.41 m/sec
Therefore the volumetric flow rate ( Q )
Q = A₂V₂
= π / 4 * ( 0.0120 )² * 17.41
= 0.00197 m³/sec
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A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth of the bottom end of the cylinder
Answers
Answer:
Explanation:
I will ASSUME that the cylinder floats with the axis through the center of its flat ends is perpendicular to the water surface.
The cylinder will displace it's mass in water.
water density has a value of 1000 kg/m³
if the depth of the bottom is "h" in meters
1.80 kg = π(0.018² m²)(h m)(1000) kg/m³
h = 1.768388256...
or about 1.77 m
The ability to do work and cause change is called
Answers
Answer:
I am pretty sure it is called energy.
.
A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 80 m during the next 40 s.
What is the average speed of the object?
Answers
Answer:
Explanation:distance-time =speed
a,V =s/t
V=2m/2s
V=1m/s
b,v=s/t
V=80m/40s
V= 2m/s
The average speed is 2m/s
Write down the condition required for the thermonuclear fusion.
Answers
Answer:
The main condition necessary for a controlled thermonuclear fusion:
The ions must be held together in close proximity at high temperature with a confinement time long enough to avoid cooling.
URGENTLY NEED HELP
This is a 2 part question
42) You pull downward with a force of 28 N on a rope that passes over a disk-shaped pulley of mass 1.2 kg and radius 0.075 m. The other end of the rope is attached to a 0.67-kg mass. (a) Is the tension in the rope the same on both sides of the pulley? If not, which side has the greater tension? (b) Find the tension in the rope on both sides of the pulley.
Answers
Answer:
The net force on the hanging mass is thus
2 T Mg 18 6.6 N 11.4 N
, enough to accelerate it upward at
17 m/s2
. The angular acceleration of the pulley is thus
2 2
Explanation:
The tension in the rope on both sides of the pulley 20.21N.
To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:
(a) Is the tension in the rope the same on both sides of the pulley?
No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.
(b) Find the tension in the rope on both sides of the pulley:
Calculate the gravitational force on each mass:
Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).
Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.
Calculate the net force on the pulley:
Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.
Apply Newton's second law to the pulley:
For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.
Use the relationship between linear acceleration and angular acceleration:
α = a / r.
Equate the torque due to the tension to the moment of inertia times the angular acceleration:
τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.
Substitute the expression for α and solve for the net tension:
Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).
Now, substitute the expression for a from step 3 and solve for the net tension:
Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).
Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:
Tnet = (1/2 * Fnet).
Now, you can find the tensions on each side of the pulley:
Tleft = Tnet + Fhanging
Tright = Tnet - Fpulle
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Andy Petite pitches a 0.8 kg baseball with a velocity of 67 m/s. Josh Hamilton
hits the ball back at a velocity of -44 m/s. Determine the impulse Josh
Hamilton's bat delivered to the baseball and enter to the nearest kg-m/s with
the correct sign.
Answers
The Impulse delivered to the baseball is 89 kgm/s.
To solve the problem above, we use the formula of impulse.
⇒ Formula:
I = m(v-u)................. Equation 1Where:
I = Impulse delivered to the baseballm = mass of the baseballv = Final velocity of the baseballu = initial speed of the baseballFrom the question,
⇒ Given:
m = 0.8 kgu = 67 m/sv = -44 m/s⇒ Substitute these values into equation 1
I = 0.8(-44-67)I = 0.8(-111)I = -88.8I ≈ -89 kgm/sNote: The negative tells that the impulse is in the same direction as the final velocity and therefore can be ignored.
Hence, The Impulse delivered to the baseball is 89 kgm/s.
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What is the significance of Isaac's name? What is the significance of Isaac's name?
Answers
Answer:
Isaac is one of the three patriarchs of the Israelites and is an important figure in the Abrahamic religions, including Judaism, Christianity, and Islam. Isaac's name means "he will laugh", reflecting the laughter, in disbelief, of Abraham and Sarah, when told by God that they would have a child.Hope this helps !!Explanation:
Itz Deepika Here to help ~ .
Note:- If you have more questions then let me know !!
. Boa constrictor snakes have tiny pelvic girdles and leg bones within their bodies. Since these structures are not functional, they are called *
a. vestigial
b. analogous
c. maladaptive
d. homologous
Answers
Those organic structures that do not seem to play any important biological function in the organism that possesses them are known as vestigial structures.
What is a vestigial structure?A vestigial structure is one that has atrophied or lost its original function throughout the course of evolution.
It generally refers to those organic structures that were useful at some point, but are now practically or totally useless.These structures are preserved as an inheritance of the evolutionary process, because at some point an ancestor of the current species had that structure, which was functional, but it ceased to be important and would end up atrophy.Therefore, we can conclude that vestigial structures are structures that some organisms still conserve as an inheritance from their ancestors but that, for some reason or another, are no longer useful for the functioning of the same.
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Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!
Answers
Answer:
Decant it.
Explanation:
Pour the water/sugar solution off the sand. When the sand wants to start coming out as well, Stop and add fresh water to the beaker, stir to rinse the remaining solution into a less concentrated solution and decant again.
Repeat the dilution process until the mix is essentially sand and water, then drive the remaining water from the sand by drying.
A crane is lifting a 500 lb piano with a velocity of 2fts''. Express the power of the crane in hp. (1 hp = 550ft-lbs)
Answers
Answer:
goalindia
goalindiaGiven:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kg
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 W
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s
goalindiaGiven:Mass of car, m = 500 lb = 500 × 0.4536 = 226.8 kgPower output of crane, P = 1.82 hp = 1.82 × 746 = 1357.72 WTo Find:The velocity of the car.Calculation:- The Power can be given by the formula:P = F × v⇒ v = P/F⇒ v = P/mg⇒ v = 1357.72/(226.8 × 9.8)⇒ v = 1357.72/2222.64⇒ v = 0.61 m/s- So, the velocity of the car will be 0.61❤
As a truck rounds a curve, a box in the bed of the truck slides to the side farthest from the center of the curve. This movement of the box is a result of
Answers
Answer:
inertia
Explanation:
the mass of the box will want to continue on its straight line motion.
As centripetal force on the wheel treads causes the truck to turn, frictional force between the box and truck bed is insufficient to keep the box turning at the same rate that the truck turns, so relative velocity occurs between box and bed until the centripetal force is increased by contact with the truck side wall farthest from the center of curvature.
while spinning in a centrifuge a 70.0 kg astronaut experiences an acceleration of 5.00 g, or five times the acceleration due to gravity on the earth. what is the centripetal force acting on her
Answers
Answer:
Explanation:
70.0(5.00)(9.81) = 3,433.5 = 3430 N
To solve this we must be knowing each and every concept related to centripetal force and its calculations. Therefore, the centripetal force acting on her is 3430 N.
What is centripetal force?The term centripetal relates to a propensity to gravitate toward the center. Centripetal refers to moving in the direction of the center. The force that maintains an item moving in a circular direction and helps it stay on the path is referred to as centripetal force.
Furthermore, centrifugal force is indeed the tendency of things to deviate from a circular route and fly in a straight line. People frequently confuse centripetal force with centrifugal force.
Mathematically,
F = m a
= 70 acceleration
= 70 × 5 × 9.81
= 3430 N
Therefore, the centripetal force acting on her is 3430 N.
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17. The shape of a river is determined by which of the following? (Choose all that
apply)
A Erosion
B. Deposition
C. Weathering
D. water speed
Answers
Answer:
Water speed Plays a key role In determining The shape of it
An accessory such as a coupling that performs a mechanical rather than an electrical function is called?
Answers
23 A 2-kg rock is moving at a speed 6 m/s, What constant force is needed to stop the rock in 7x10-52
Answers
Answer:
Explanation:
Do you mean 7 x 10⁻⁵² seconds? Who can even measure that small a time period?
If that time is incorrect, just redo the math with the correct time to get the force.
An impulse will cause a change of momentum
FΔt = mΔv
F = mΔv/Δt
F = 2(0 - 6)) / (7 x 10⁻⁵² - 0)
F = - 1.7 x 10⁵² N
The magnitude of that force would pretty much crush any rock it hit.
SOMEONE PLEASE HELP MEEEEEEE
Answers
Answer:
The movement of Tectonic plates.
Explanation:
A constant force of 12 N in the positive x direction acts on a 4.0-kg object as it moves from the origin to the point 6i-8j m. How much work is done by the given force during this displacement
Answers
Answer:
Explanation:
Only force in the direction of motion does work
The force acts in the x direction
The x change of position was 6 m
W = Fd = 12(6) = 72 J
The work done by the given force during this displacement is determined as 120 J.
Work done on the objectThe work done on the object is calculated as follows;
W = Fd
where;
d is the displacement of the objectd = √(6² + 8²)
d = 10 m
W = 12 x 10
W = 120 J
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Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answers
Answer:
over 50% power ability
Explanation:
I believe it's half and half chance that The Offspring or the child will have that trait
The diagram below shows a child pulling a 50.-kg friend on a 20 kg sled by applying a 300. newton force on the sled rope at an angle of 40 degrees with the horizontal. The sled moves at constant velocity as the person pulls with the 300 N force.
Answers
The vertical component of the applied force on the sled is 192.84 N.
The given parameters:
Mass of the friend, M = 50 kgMass of the sled, m = 20 kgApplied force, F = 300 NInclination of the force, θ = 40 ⁰The vertical component of the 300 N force is calculated as follows;
[tex]F_y= F \times sin(\theta)\\\\F_y = 300 \times sin(40)\\\\F_y = 192.84 \ N[/tex]
Thus, the vertical component of the applied force on the sled is 192.84 N.
Your question is not complete, the missing part of the question is below:
The vertical component of the 300 N force is approximately?
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You are pulling a sled with a constant velocity using a rope held horizontally in
the snow. Using a spring scale attached to the rope, you measure the tension
to be 0.96 N. The sled's mass is 0.58 kg. Write the surface force the ground
exerts on the sled in component form, and determine its magnitude.
Answers
Answer:
Explanation:
if you are pulling in the positive direction and Upward is also positive.
F = -0.96i + 0.58(9.8)j
F = -0.96i + 5.7j
F = √(-0.96² + 5.7²) = 5.8 N
You are pulling a sled with constant velocity by using a rope then the surface force the ground exerts on the sled will be 5.8 N.
What is tension?The pulling force conveyed axially by a string, cable, chain, or another analogous object, or by either end of a rod, truss member, or another such three-dimensional object, is referred to as tension in physics. Another way to think of tension is as the action-reaction pair of forces acting at each end of the previous elements. Perhaps tension is the polar opposite of compression.
A restoring force may cause what is also referred to as tension when atoms or molecules are torn apart from one another at the atomic level and build up potential energy.
If you are moving upward and pushing in a positive way,
F = -0.96 i + 0.58(9.8) j
F = -0.96 i + 5.7 j
F = [tex]\sqrt{(-0.96^2 + 5.7^2)}[/tex]
F= 5.8 N
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In this image F1 is equal to 100 N and F2 is equal to 50 N. What is the net force?
Answers
Answer:
net force would be 50 N right
Explanation:
A ball has the energy to move 30 m/s with the mass of 5. What is the energy
Answers
In my work I used the formula for kinetic energy to answer your question. Hope this helps.
An object in free fall has a velocity of 5m/s in the upward direction. What is the instantaneous velocity of the object one second later?
Answers
Answer:
Explanation:
Near the earth's surface where gravity is approximately 10 m/s² downward
v = u + at
v = 5 + (-10)(1) = -5 m/s
so it has the same speed but in the opposite (downward) direction.
The instantaneous velocity of the object is -4.8 m/s and is directed downwards.
What is meant by instantaneous velocity ?Instantaneous velocity is defined as the rate of change of position for a given interval of time. And it also represents the direction.
Here,
The object is freely falling.
So, the acceleration of the object is the acceleration due to gravity.
a = g = 9.8 m/s²
Initial velocity of the object, u = 5 m/s (upward velocity)
Time given, t = 1
Using the first equation of motion,
v = u + at
v = 5 + (-9.8) x 1
( negative sign is due to it is directed downwards which is opposite to u)
v = -4.8 m/s
That means the instantaneous velocity is directed downwards.
Hence,
The instantaneous velocity of the object is -4.8 m/s and is directed downwards.
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The block in the figure below has a mass of 5.1 kg and it rests on an incline of angle . You pull on the rope with a force F = 34 N. Assume the incline is smooth and determine the angle of the incline if the block moves with constant speed.
Answers
42.9°
Explanation:
Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:
[tex]x:\;\;\;\;F - mg\sin{\theta} = 0\;\;\;\;[/tex]
[tex]\Rightarrow mg\sin{\theta} = F[/tex]
Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at [tex]\theta.[/tex] Solving for the angle, we get
[tex]\sin{\theta} = \dfrac{F}{mg}[/tex]
or
[tex]\theta = \sin^{-1}\left(\dfrac{F}{mg}\right)[/tex]
[tex]\;\;\;= \sin^{-1}\left[\dfrac{34\:\text{N}}{(5.1\:\text{kg})(9.8\:\text{m/s}^2)}\right][/tex]
[tex]\;\;\;=42.9°[/tex]
PLEASE HELP ASAP
I need help understanding this question, form my guess I’m thinking it’s C but I’m not to sure
Answers
Answer:
Explanation:
Without the diagram, we have to bracket our answers.
Total energy is constant, so we eliminate options A and B.
C is correct if position 1 is closer to the star than position 2
D is correct if position 2 is closer to the star than position 1
ur mom walked into a store and got milk
Answers
Answer:
is there any questions
Answer:
What is your question???
Explanation: