Someone please help me ASAP!

Answer:

not sure what the O is there for?

if it is zero then Oy would make Oy=2(x+3) not correct

3x-y = 2

y=2(x+3)

Step-by-step explanation:

)

Answer:

(x + 3) (x - 3)

Step-by-step explanation:

[tex]a^{2} -b^2=(a+b)(a-b)[/tex] where a = x and b = 3

x^2 - 3^2 =

x^2 - 9 =

(x + 3)

(x - 3)

Answer:

Step-by-step explanation:

x²-9=x²-3²

Answer:

In a product like:

a*b = 0

says that one of the two terms (or both) must be zero.

Here we have our equation:

x^2 + 12 = 7x

x^2 + 12 - 7x = 0

Let's try to find an equation like:

(x - a)*(x - b) such that:

(x - a)*(x - b)  = x^2 + 12 - 7x

we get:

x^2 - a*x - b*x  -a*-b = x^2 - 7x + 12

subtracting x^2 in both sides we get:

-(a + b)*x + a*b = -7x + 12

from this, we must have:

-(a + b) = -7

a*b = 12

from the first one, we can see that both a and b must be positive.

Then we only care for the option with positive values, which is x =3 or x = 4

replacing these in both equations, we get:

-(3 + 4) = -7

3*4 = 12

Both of these equations are true, then we can write our quadratic equation as:

(x - 3)*(x - 4) = x^2 + 12 - 7x

The correct option is the last one.

Answer:

d

Step-by-step explanation:

Answer:

You have to equal the unit first,

as 1 Rupee = 100 paise,

so,

55paise: 100paise,

= 11:20

I hope it hepled : )

Answer:

The smaller angle will be "156°".

Step-by-step explanation:

According to the question,

Before 12, the minute hand at 48 minutes:

= [tex]60-48[/tex]

= [tex]12[/tex] (minutes to 12)

So,

= [tex]12 \ minutes+14 \ minutes[/tex]

= [tex]26 \ minutes[/tex]

hence,

The smaller angle will be:

= [tex]26\times 6^{\circ} \ each[/tex]

= [tex]156^{\circ}[/tex]

Answer:

The angle is 204 degree.

Step-by-step explanation:

The angle turned by minute hand in 1 minute is 6 degree

The angle turned by the hour hand in 1 hour is

For the hour hand :

The angle turned in 1 hour = 360/12 = 30degree

At 2 : 00 , the angle covered = 30 x 2 = 60 degree

In each minute the hour hand moves  = 30 degrees / hour  x  1 hour/60 min  

                              = 1/2 degree  

So at 2: 48   the hour hand is at    2*30  + 48 * 1/2 = 84 degrees

For the minute hand:

In each minute it turns = 6 degrees  

So, at 48 minutes the minute hand is at   48 x 6 = 288 degrees

So, the angle between them is 288 - 84 = 204 degrees  

Answer:

Stratified sampling

Step-by-step explanation:

Given

[tex]30 \to 21\ and\ above[/tex]

[tex]15 \to Under\ 21[/tex]

Required

The type of sampling method

From the question, we understand that, the sample are divided into two categories. This means that each person in each person do not have the same probability of being selected.

Such method is a stratified sampling

Answer:

x = 14

Step-by-step explanation:

45 = 3(x + 1)

Distribute the 3

3(x) = 3x

3(1) = 3

We now have 45 = 3x + 3

Subtract 3 from both sides

45 - 3 = 42

3 - 3 cancels out

We now have 42 = 3x

Divide both sides by 3

42/3 = 14

3x / 3 = x

We're left with x = 14

Answer:

x = 14

Step-by-step explanation:

45 = 3(x + 1)

Distribute

45 = 3x + 3

-3           -3

----------------

42 = 3x

----    ----

3       3

14   =  x

Answer:

40/30

Step-by-step explanation:

Since tan∅= o/a, 40 is opposite, and 30 is adjacent to angle A, 40/30 is the ratio for tanA.

Answer:40/30

Step-by-step explanation:

....

Answer:

The height of flag pole=8.3m

Step-by-step explanation:

We are given that

Height of boy=1.4 m

[tex]\theta=36^{\circ}[/tex]

Distance of boy from the flag pole=9.5 m

We have to find  the height of the flag pole​.

BCDE is a rectangle

BC=ED=1.4 m

CD=BE=9.5 m

In triangle ABE

[tex]\frac{AB}{BE}=tan36^{\circ}[/tex]

Using the formula

[tex]tan\theta=\frac{Perpendicular\;side}{base}[/tex]

[tex]\frac{AB}{9.5}=tan 36^{\circ}[/tex]

[tex]AB=9.5tan36^{\circ}[/tex]

AB=6.90 m

Height of flag pole=AB+BC=6.90+1.4

Height of flag pole=8.3m

Answer:

None of the above

Step-by-step explanation:

Distance is the difference between two positions. That is x1- x2  Since both numbers were negative, you would want the absolute value of one plus the other, because subtracting a negative results in a positive. For this example the distance would look more like this:

| -4.7 - ( -3.9 ) | = .8

Answer:

29

Step-by-step explanation:

43.25-7=36.25

36.25/1.25=29

Answer:

x ≈ 39.3°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{KL}{KM}[/tex] = [tex]\frac{6.5}{8.4}[/tex] , then

x = [tex]cos^{-1}[/tex] ([tex]\frac{6.5}{8.4}[/tex] ) ≈ 39.3° ( to the nearest tenth )

Step-by-step explanation:

Cos theta =Base/hypotenuse

Base=KL= 6.5

Hypotenuse=KM=8.4

Cos X=

[tex] \frac{6.5}{8.4} \\ [/tex]

X=

[tex] {cos}^{ - 1} \frac{6.5}{8.4} [/tex]

X=39.30 (2decimal)

Brainliest please~

Answer:Monday, Wednesday and Friday.

Step-by-step explanation:

It’s the other weekdays.

Answer:

3,750 cars.

Step-by-step explanation:

We are given that the equation:

[tex]y=9000-2.4x[/tex]

Models the relationsip between y, the number of unfilled seats in the stadium, and x, the number of cars in the parking lot.

We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.

When there are no unfilled seats in the stadium, y = 0. Thus:

[tex]0=9000-2.4x[/tex]

Solve for x. Subtract 9000 from both sides:

[tex]-2.4x=-9000[/tex]

Divide both sides by -2.4:

[tex]x=3750[/tex]

So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.

Answer:

49.4 liters

Step-by-step explanation:

we have the basic ratio between liters of petrol (gasoline) and distance driven :

19/50

now, the same ratio has to apply, when we talk about 130 km instead of just 50.

so,

19/50 = x/130

x = 130×19/50 = 13×19/5 = 49.4 liters

if I may add, this is a very bad or at least very, very big car based on today's standards ...

Answer:

2√10 km

Step-by-step explanation:

By Pythagoras theorem,

x^2 + 9^2 = 11^2

x^2 + 81 = 121

x^2 = 121 - 81

x^2 = 40

= 4 x 10

x^2 = 2^2 x 10

x = 2√10 km

Answer:

= r²−4r+3

Step-by-step explanation:

(r - 3) (r - 1)

(r x r) + (r x -1) + (-3 x r) + (-3 x -1)

r² + - r - 3r + 3

= r²−4r+3

Answer:

4

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

When we divide fractions, we are essentially multiplying by the reciprocal of the fraction.

2/3 ÷ 1/6

= 2/3 × 6

= 12/3

= 4

Answer:

x=13

y= -9

(13, -9)

Step-by-step explanation:

If we are solving using the substitution method, we can take the first equation and set it to y so y=4-x.

Then, we can take that equation and plug it into the bottom one so

3x+4(4-x)=3

Simplify:

3x+16-4x=3

-x=-13

x=13

We can then plug 13 into any of the two given equations (I am just going to plug it into the top one)

So, 13+y=4 which y= -9

Answer:

66

Step-by-step explanation:

Use the PEMDAS order. Multiplication comes before addition so it simplifies to 6(8)+(6)3

=48+18

=66

Answer:

[tex]Pr = \frac{1}{6}[/tex]

Step-by-step explanation:

Given

[tex]S = \{1,2,3,4,5\}[/tex]

[tex]n = 5[/tex]

Required

Probability the third term is 3

First, we calculate the possible set.

The first must be prime (i.e. 2, 3 and 5) --- 3 numbers

[tex]2nd \to 4\ numbers[/tex]

[tex]3rd \to 3\ numbers[/tex]

[tex]4th \to 2\ numbers[/tex]

[tex]5th \to 1\ number[/tex]

So, the number of set is:

[tex]S = 3 * 4 * 3 * 2 * 1[/tex]

[tex]S = 72[/tex]

Next, the number of sets if the third term must be 2

[tex]1st \to 2[/tex] i.e. 1 or 5

[tex]2nd \to 3\ numbers[/tex] ---- i.e. remove the already selected first term and the 3rd the compulsory third term

[tex]3rd \to 1\ number[/tex] i.e. the digit 2

[tex]4th \to 2\ numbers[/tex]

[tex]5th \to 1\ number[/tex]

So

[tex]r = 2 * 3 * 1 * 2 * 1[/tex]

[tex]r = 12[/tex]

So, the probability is:

[tex]Pr = \frac{r}{S}[/tex]

[tex]Pr = \frac{12}{72}[/tex]

[tex]Pr = \frac{1}{6}[/tex]

Answer:

B. -9

Step-by-step explanation:

The equation would be f(-3)=-3^2

3*3 is 9

Add the - back on, and you get -9

I hope this helps!

Answer:

b + 24

Step-by-step explanation:

b and 24 would be b + 24

Answer:

We can first, determine two points on the line:

For:

x

=

0

y

=

0

−

6

y

=

−

6

or

(

0

,

−

6

)

For:

x

=

6

y

=

6

−

6

y

=

0

or

(

6

,

0

)

Next, we can plot these two points on the grid:

graph{(x^2+(y+6)^2-0.125)((x-6)^2+y^2-0.125)=0 [-20, 20, -10, 10]}

Now, we can draw a line through the two points to graph the line for the equation:

graph{(x^2+(y+6)^2-0.125)((x-6)^2+y^2-0.125)(y-x+6)=0 [-20, 20, -10, 10]}

Answer:

Step-by-step explanation:

Take two points on the line and find the slope.

(1 , 2)  ; (4 , 4)

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\[/tex]

          [tex]=\frac{4-2}{4-1}\\\\=\frac{2}{3}[/tex]

m = 2/3  & (1 , 2)

Slope point form : y - y1 = m(x-x1)

[tex]y - 2 = \frac{2}{3}*(x - 1)\\\\y - 2 =\frac{2}{3}x - \frac{2}{3}\\\\y =\frac{2}{3}x-\frac{2}{3}+2\\\\y = \frac{2}{3}x-\frac{2}{3}+\frac{2*3}{1*3}\\\\y=\frac{2}{3}x-\frac{2}{3}+\frac{6}{3}\\\\y=\frac{2}{3}x+\frac{4}{3}\\\\Multiply \ equation \ by \ 3\\\\3y = 2x + 4\\\\2x - 3y + 4 = 0[/tex]