someone please help!!

The limit of (xy⁴)/(x⁴y⁴) is 0.

The limit squeeze theorem (also known as sandwich theorem) states that if a function f(x) lies between two functions g(x) and h(x) and the limits of each of g(x) and h(x) at a particular point are equal (to L), then the limit of f(x) at that point is also equal to L. This looks something like what we know already in algebra. If a ≤ b ≤ c and a = c then b is also equal to c. The squeeze theorem says that this rule applies to limits as well. We define the squeeze theorem mathematically as follows:

"Let f(x), g(x), and h(x) are three functions that are defined over an interval I such that g(x) ≤ f(x) ≤ h(x) and suppose lim ₓ → ₐ g(x) = lim ₓ → ₐ h(x) = L, then lim ₓ → ₐ f(x) = L".

Here:

The function f lies between g and h and hence they are lower and upper bounds of f respectively.

'a' doesn't necessarily need to be within I.

We have to find the limit of (xy⁴)/(x⁴y⁴).

After applying the limit squeeze theorem, we get

[tex]\lim_{x \to \infty} \frac{xy^{4} }{x^{4}y^{4} }\\ = \lim_{x \to \infty} \frac{1}{x^{3} } \\= 0[/tex]

Thus, the limit of (xy⁴)/(x⁴y⁴) is 0.

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Answer:

x = 15

Step-by-step explanation:

3/5x - 1/3x = 4

9/15x - 5/15x = 4

4/15x = 4

x = 15

The new coordinates for  P(-8,3) Q(-8,10) R(-4,2) are (3,-3) (10,-10) and (2,-2) .

What are coordinates ?

Coordinates can be defined as pair of numbers which are used to determine the position of a given point.

Given

to Write the coordinates of the vertices after a rotation 270° counterclockwise around the origin.

Given points are  P(-8,3) Q(-8,10) R(-4,2) .

we know that if (x,y) are rotated at an  θ, the new coordinates could be ,

x′=xcos(θ)−ysin(θ)   y′=xsin(θ)+ycos(θ).

So,

for p (-8,3)

x' = -8*cos270 - 3 * sin270

x' = 0 + 3

x' = 3

y' = -8*cos270 + 3 * sin270

y' = 0 - 3

y' = -3

(x' , y' ) = (3,-3)

similarly,

for q (-8,10)

x' = -8*cos270 - 10 * sin270

x' = 0 + 10

x' = 10

y' = -8*cos270 +  10* sin270

y' = 0 -10

y' = -10

(x' , y' ) = (10,-10)

similarly,

for q (-4,2)

x' = -4*cos270 - 2 * sin270

x' = 0 + 2

x' = 2

y' = -4*cos270 + 2 * sin270

y' = 0 -2

y' = -2

(x' , y' ) = (2,-2)

Therefore, The new coordinates for  P(-8,3) Q(-8,10) R(-4,2) are (3,-3) (10,-10) and (2,-2) .

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14.84 pounds of dried apricots were used and 10.16 pounds of dried prunes were used to produce 25 pounds of the dried fruit mixture.

Let's call the weight of dried apricots used in the mixture "x" (in pounds). Then the weight of dried prunes used in the mixture is 25 - x (in pounds).

The cost per pound of dried apricots is 3.25, and the cost per pound of dried prunes is 4.79. So the total cost of the mixture is:

3.25x + 4.79(25 - x) = 3.25x + 119.75 - 4.79x

Expanding both sides:

119.75 = 8.04x

Dividing both sides by 8.04:

x = 14.84 pounds

So 14.84 pounds of dried apricots were used in the mixture, and 25 - 14.84 = 10.16 pounds of dried prunes were used in the mixture.

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14.84 pounds of dried apricots were used and 10.16 pounds of dried prunes were used to produce 25 pounds of the dried fruit mixture.

Let's call the weight of dried apricots used in the mixture "x" (in pounds). Then the weight of dried prunes used in the mixture is 25 - x (in pounds).

The cost per pound of dried apricots is 3.25, and the cost per pound of dried prunes is 4.79. So the total cost of the mixture is:

3.25x + 4.79(25 - x) = 3.25x + 119.75 - 4.79x

Expanding both sides:

119.75 = 8.04x

Dividing both sides by 8.04:

x = 14.84 pounds

So 14.84 pounds of dried apricots were used in the mixture, and 25 - 14.84 = 10.16 pounds of dried prunes were used in the mixture.

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Answer:

332126

Step-by-step explanation:

333333+(5+6)-657-(564-3)=332126

The average speed of the whole journey is 24 kilometres per hour.

The average speed is the total distance travelled by the object in a particular time interval.

A car travels from X to Y at an average speed of 60km/h and returns to X at a speed of 40km/h.

Therefore, the average speed for the whole journey can be calculated as follows:

The total distance travelled is 120 km.

Hence,

total time = 120 / 60 + 120 / 40

total time = 2 + 3 = 5 hours

Therefore,

average speed = total distance / total time taken

average speed = 120 / 5

average speed = 24 km/hr

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Margin of Error is 0.0245, 0.8209 <= p <= 0.8264 and CI in (C) is 0.1291 to 0.1781 and in (d) is 0.8209 to 0.8264.

(a) The point estimate of the proportion of the population of respondents who do think that the country is headed in the right direction is 384 / 2500 = 0.1536.

(b) To find the margin of error for the proportion, we use the formula:

ME = 1.96 * sqrt(p * (1 - p) / n), where p is the point estimate and n is the sample size.

ME = 1.96 * sqrt(0.1536 * (1 - 0.1536) / 2500) = 0.0245

(c) The 95% confidence interval for the proportion of respondents who do think that the country is headed in the right direction is:

0.1536 - 0.0245 <= p <= 0.1536 + 0.0245

0.1291 <= p <= 0.1781

(d) To find the 95% confidence interval for the proportion of respondents who do not think that the country is headed in the right direction, we subtract the proportion from 1:

1 - 0.1536 - 0.0245 <= p <= 1 - 0.1536 + 0.0245

0.8209 <= p <= 0.8264

(e) The confidence interval in part (c) has a smaller margin of error because the sample proportion of respondents who do think that the country is headed in the right direction is closer to 0.5 (the midpoint of the interval) than the sample proportion of respondents who do not think that the country is headed in the right direction.

Confidence interval in part (c): 0.1291 to 0.1781

Confidence interval in part (d): 0.8209 to 0.8264

Therefore, Margin of Error is 0.0245, 0.8209 <= p <= 0.8264 and CI in (C) is 0.1291 to 0.1781 and in (d) is 0.8209 to 0.8264.

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Margin of Error is 0.0245, 0.8209 <= p <= 0.8264 and CI in (C) is 0.1291 to 0.1781 and in (d) is 0.8209 to 0.8264.

(a) The point estimate of the proportion of the population of respondents who do think that the country is headed in the right direction is 384 / 2500 = 0.1536.

(b) To find the margin of error for the proportion, we use the formula:

ME = 1.96 * sqrt(p * (1 - p) / n), where p is the point estimate and n is the sample size.

ME = 1.96 * sqrt(0.1536 * (1 - 0.1536) / 2500) = 0.0245

(c) The 95% confidence interval for the proportion of respondents who do think that the country is headed in the right direction is:

0.1536 - 0.0245 <= p <= 0.1536 + 0.0245

0.1291 <= p <= 0.1781

(d) To find the 95% confidence interval for the proportion of respondents who do not think that the country is headed in the right direction, we subtract the proportion from 1:

1 - 0.1536 - 0.0245 <= p <= 1 - 0.1536 + 0.0245

0.8209 <= p <= 0.8264

(e) The confidence interval in part (c) has a smaller margin of error because the sample proportion of respondents who do think that the country is headed in the right direction is closer to 0.5 (the midpoint of the interval) than the sample proportion of respondents who do not think that the country is headed in the right direction.

Confidence interval in part (c): 0.1291 to 0.1781

Confidence interval in part (d): 0.8209 to 0.8264

Therefore, Margin of Error is 0.0245, 0.8209 <= p <= 0.8264 and CI in (C) is 0.1291 to 0.1781 and in (d) is 0.8209 to 0.8264.

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By applying the debt concept, it can be concluded that:

A. He should pay $466.02 to pay off the balance on the account.

B. The balance on his account is $190.68

Debt is an obligation that requires one party, the debtor, to pay money or other agreed-upon value to another party, the creditor.

We have the following information:

Ahmad owes $382.45, and because he owes, it means this value is the debt, and we write it:

D = $382.45

Then he returns two items ($25. 10 & $34. 50) so that their values get credited into his accounts.

D = $382.45 - $25.10 - $34.50 = $322.85

Now after this, he makes another two purchases of $45 and $98.17, which increase his debt and makes:

D = $322.85 + $45 + $98.17 = $466.02

Part A: Since the debt or the account balance is $466.02, then he should pay $466.02 to pay off the balance on the account.

Part B: However, instead of paying off the balance, Ahmed makes a payment of $300 and he has to be charged $24.66. It means that his debt is not paid off:

D = $466.02 - $300 + $24.66 = $190.68

So, the balance on his account is $190.68.

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The sizes of the angles are: a = 112, b = 97, c = 85, d = 148

To calculate the sizes of the angles, we substract the given value from 180 (sum of angles on a straight line)

For a = 180 - 68 = 112( sum of angles on a straight line)

      b = 180 - 83 = 97( sum of angles on a straight line)

       c = 180 - 95 = 85( sum of angles on a straight line)

       d = 180 - 32 = 148( sum of angles on a straight line)

Hence, the sizes of the the angles a,b,c,d, are 112,97,85 and 148 respectively

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Categorical data is data that can be divided into different categories. Examples of categorical data include hair color, number of suitcases on a plane, tree height, and amount of rainfall.

Hair color would be classified as categorical data because it can be divided into categories such as black, brown, blonde, and red. Number of suitcases on a plane would also be classified as categorical data because the amount of suitcases can be divided into categories such as 0, 1, 2, 3, etc. Tree height would be classified as categorical data as it can be divided into categories such as small, medium, and large. Amount of rainfall would also be classified as categorical data as it can be divided into categories such as light rainfall, moderate rainfall, and heavy rainfall.

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The set S is linearly dependent and the matrix A has rank 3.

Sets are groups of well-defined objects or components in mathematics. A set is denoted by a capital letter, and the cardinal number of a set is enclosed in a curly bracket to indicate how many members there are in a finite set.

Set A, for instance, is a collection of all the natural numbers, with the form A = 1, 2, 3, 5, 6, 7, 8, etc.

The maximum number of linearly independent columns (or rows ) of a matrix is called the rank of a matrix. The rank of a matrix cannot exceed the number of its rows or columns.

Thus, The set S is linearly dependent and the matrix A has rank 3.

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The width of the sticker will be  8 3/4 inches.

The scale factor defines a variable in a ratio of two different measurements.

Sometimes drawings of large models are represented in a scale factor of a smaller unit.

Given, The given logo has a height of 2 inches and a width of 5 inches.

Bumper stickers usually have a height of 3 1/2 inches which has a

= (7/2)/2 = 7/4 scale factor.

Therefore, The width of the sticker will be,

= 5×(7/4).

= 35/4.

= 8 3/4 iches.

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Answer:

x=10

Step-by-step explanation:

5x+5=55

5x=55-5

5x=50

x=10

hth

Answer:

A data type is an attribute associated with a piece of data that tells a computer system how to interpret its value

Step-by-step explanation:

Data types categorize data and specify its nature, amount characteristics, and behavior. It decides how data is handled within a computer system in terms of storage and manipulation.

Data types categorize data and specify its nature, characteristics, and behavior. It is a crucial part of every data structure and computer language. Primitive data types and complex data types are the two basic divisions of data types. Basic types like numbers, characters, booleans, and strings are examples of primitive data types. Arrays, objects, and records are examples of sophisticated data types that are more complex. Data types specify how information is handled and stored by computer systems. Size, precision, and range are a few examples of the unique qualities that each data type possesses. The arithmetic, comparison, and logic operations that can be carried out on the data are also determined by the data types.

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The equivalent expression is 12h - 18/4

It is important to note that algebraic expressions are mathematical expression comprising of factors, constants, coefficients, variables and terms.

These algebraic expressions are also known to be made up of mathematical to arithmetic operations, such as;

From the information given, we have that;

3/4(4h – 6)

To simply this, we need to expand the bracket, we get;

12h - 18/4

Hence, the expression is 12h - 18/4

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Answer:

Frequency

Step-by-step explanation:

The heights of the bars of a histogram correspond to​ Frequency values.

Answer:

frequency​ values

Step-by-step explanation:

The bars are drawn adjacent to each other.

Adding parentheses to a regular expression can be used to capture specific information, such as the street number and apartment number in this example.

A regular expression is a pattern used to match and search for specific strings. To remember the street number "613" and apartment number "apt 57" but not the street name, we can add parentheses to the regular expression to create capturing groups. The parentheses will capture the desired information and allow us to reference it later if needed.

The regular expression would look something like this: (613) (apt 57)

The parentheses indicate that the information inside should be captured as a group. This regular expression will match a string that contains the street number "613" and the apartment number "apt 57", and capture these values in two separate groups.

For example, if we have the following address: "613 Main St, apt 57"

We can use the regular expression to match the desired information:

(613) (apt 57)

In this case, the two groups captured are "613" and "apt 57". The information inside the parentheses can be accessed and used for various purposes, such as formatting or validation.

In summary, adding parentheses to a regular expression can be used to capture specific information, such as the street number and apartment number in this example. This allows for more precise and flexible matching and extraction of information from strings.

Therefore, Adding parentheses to a regular expression can be used to capture specific information, such as the street number and apartment number in this example.

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Since n•u is not equal to 0, we conclude that the vector u is not in the plane spanned by the columns of A.

A vector u is in the plane spanned by the columns of a matrix A if and only if the dot product between u and the normal vector of the plane is equal to 0.

In this case, let A = [5 -2 1; -3 6 1]. To determine if u = [-12, 36, 8] is in the plane spanned by the columns of A, we can calculate the dot product between u and the normal vector of the plane, which can be found by taking the cross product of the two columns of A.

Since the cross product of two columns in A gives the normal vector of the plane spanned by the columns, we have:

n = (5, -2, 1) × (-3, 6, 1) = (18, -26, -11)

Next, we calculate the dot product of n and u:

n•u = (18, -26, -11) • [-12, 36, 8] = 18 * -12 - 26 * 36 - 11 * 8 = -816 - 936 - 88 = -1840

Since n•u is not equal to 0, we conclude that the vector u is not in the plane spanned by the columns of A. In other words, u is not orthogonal to the normal vector of the plane and therefore, is not in the plane.

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3/4(12a+8) =27.6

3/4 Multiplied by () + (multiply by 8) = ()

A = 2.4

Expanding the expression inside the parenthesis, we have:

3/4 (12a + 8) = 3/4 * 12a + 3/4 * 8 = 9a + 6

Setting this equal to 27.6 and solving for a:

9a + 6 = 27.6

9a = 21.6

a = 2.4

So, the value of a is 2.4

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Eval is a function that evaluates an expression and puts the resulting value into a new or existing field.

To calculate the value of an expression using Eval, you must use the correct syntax. The syntax for Eval is Eval(expression, optional_parameter). The expression can take the form of a mathematical equation or a logical expression. For example, if you wanted to calculate the sum of two numbers, you would use the following expression: Eval(A + B). The optional parameter allows you to specify a range of values to evaluate the expression against.

For example, if you wanted to calculate the sum of two numbers within a given range, you would use the following expression: Eval(A + B, range). The range parameter can be used to specify the starting and ending values that the expression should be evaluated against.

Using Eval to calculate an expression is a useful tool for quickly getting the desired value. It is also useful for quickly testing the accuracy of a complex expression before implementing it in your code.

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The distance the water balloon traveled over 1.5 seconds using the data georgia’s brother collected is attached below.

A distance-time graph, also known as a displacement-time graph or position-time graph, is a graphical representation that shows the relationship between the distance traveled by an object and the time it takes to travel that distance.

Using the information gathered by Georgia's brother, we can plot the points on a coordinate plane to graph the distance the water balloon travelled during a period of 1.5 seconds.

The data points provided are as follows:

Time (s)     Distance (m)

0.25              0.3

0.5                1.2

0.75              2.8

1.0                4.9

1.25              7.7

1.5               11.0

Plotting these points on a graph with time on the x-axis and distance on the y-axis, we get the graph attached.

The water balloon's route over 1.5 seconds is depicted on a graph. As time increases, the distance traveled by the balloon also increases. The graph shows a curved line, indicating that the distance traveled is not constant but increases at a varying rate.

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The interior volume of the tent where the cross sections are triangles is given is 120ft³.

There are two cross sectional triangles

The  one smaller triangle with the height and base of 2ft

The other bigger triangle has a base and height of 4 ft

And the total length of the Tent is given as 6 ft.

Therefore,

Area of smaller triangle = 2 x 2 = 4m²

Area of bigger triangle = 4 x 4 = 16 ft²

So the Volume of the tent is given by ,

Total length x (Area of smaller triangle + Area of bigger triangle)

= 6 x ( 4 + 16 )

=6 x ( 20 )

= 120 ft ³

A measurement of three-dimensional space is volume.  Numerous imperial or US customary units, as well as SI-derived units (such the cubic metre and litre), are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and length (cubed) have a symbiotic relationship. The capacity of a container is typically regarded to be its volume.

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30 students are taking none of the classes.

We can use the Principle of Inclusion-Exclusion (PIE) to determine the number of students taking none of the classes. The PIE states that the total number of elements in the union of several sets is equal to the sum of elements in each set, minus the sum of elements in the pairwise intersections, plus the sum of elements in the three-way intersections, and so on.

In this case, we want to find the number of students taking none of the classes, which is equal to the total number of students (100) minus the number of students taking at least one class.

So, we can apply PIE as follows:

students taking none of the classes = 100 - (students in prob. + students in la + students in comp - students in prob. & comp - students in la & comp - students in prob. & la + students in prob., comp & la)

Using the given information, we have:

students taking none of the classes = 100 - (65 + 45 + 40 - 25 - 20 - 30 + 10)

students taking none of the classes = 100 - (95 - 25)

students taking none of the classes = 100 - 70

students taking none of the classes = 30

Hence, 30 students are taking none of the classes.

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30 students are taking none of the classes.

We can use the Principle of Inclusion-Exclusion (PIE) to determine the number of students taking none of the classes. The PIE states that the total number of elements in the union of several sets is equal to the sum of elements in each set, minus the sum of elements in the pairwise intersections, plus the sum of elements in the three-way intersections, and so on.

In this case, we want to find the number of students taking none of the classes, which is equal to the total number of students (100) minus the number of students taking at least one class.

So, we can apply PIE as follows:

students taking none of the classes = 100 - (students in prob. + students in la + students in comp - students in prob. & comp - students in la & comp - students in prob. & la + students in prob., comp & la)

Using the given information, we have:

students taking none of the classes = 100 - (65 + 45 + 40 - 25 - 20 - 30 + 10)

students taking none of the classes = 100 - (95 - 25)

students taking none of the classes = 100 - 70

students taking none of the classes = 30

Hence, 30 students are taking none of the classes.

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The variance for this sample of 5 scores with the sum of squared errors (deviations)  20 is 5.

Variance is a measure of the spread of the data around the mean. It can be calculated from the sum of squared deviations (SSE) as follows:

Variance = SSE / (n - 1)

where n is the number of scores in the sample.

In this case, n = 5 and SSE = 20, so the variance is:

Variance = 20 / (5 - 1) = 20 / 4 = 5

So the variance for this sample is "5".

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The total number of different committees possible is 6 * 3 * 2 * 56 = 3456.

If 2 of the men refuse to serve together, then we have to choose the first man for the committee first and then choose the other two men one by one, making sure that the two men who refuse to serve together are not chosen together.

There are 6 possible choices for the first man. After the first man is chosen, there are 4 remaining men, and we have to choose 2 more men from these 4. However, one of these 2 men must be the one who refused to serve with the first man. So, there are only 3 possible choices for the second man. After the second man is chosen, there are only 2 possible choices for the third man.

Next, we have to choose 3 women from 8. There are C(8,3) = 56 ways to do this.

So, the total number of different committees possible is 6 * 3 * 2 * 56 = 3456.

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The total number of different committees possible is 6 * 3 * 2 * 56 = 3456.

If 2 of the men refuse to serve together, then we have to choose the first man for the committee first and then choose the other two men one by one, making sure that the two men who refuse to serve together are not chosen together.

There are 6 possible choices for the first man. After the first man is chosen, there are 4 remaining men, and we have to choose 2 more men from these 4. However, one of these 2 men must be the one who refused to serve with the first man. So, there are only 3 possible choices for the second man. After the second man is chosen, there are only 2 possible choices for the third man.

Next, we have to choose 3 women from 8. There are C(8,3) = 56 ways to do this.

So, the total number of different committees possible is 6 * 3 * 2 * 56 = 3456.

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The y-intercept of the line y = 2x - 4 is the point (0, -4), which means that the line crosses the y-axis at a point with a y-coordinate of -4.

What is the slope intercept?

The slope indicates the steepness of a line and the intercept indicates the location where it intersects an axis. The slope and the intercept define the linear relationship between two variables and can be used to estimate an average rate of change.

The equation y = 2x - 4 represents a straight line in a coordinate plane.

In this equation, y is the dependent variable and x is the independent variable.

The slope of the line is 2, meaning that the line rises 2 units vertically for every 1 unit it moves horizontally to the right.

The y-intercept is the point where the line crosses the y-axis, and can be found by setting x equal to zero and solving for y.

In this case, when x = 0, y = 2 * 0 - 4 = -4.

Hence, the y-intercept of the line y = 2x - 4 is the point (0, -4), which means that the line crosses the y-axis at a point with a y-coordinate of -4.

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Using commutative property of addition, a + b = b + a, Therefore, 39 + 67 = 67 + 39, Hence the missing number is 67.

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Answer:

50%

Step-by-step explanation:

7 nurses

3 doctors

4 offices

14 in total

7/14 or 50% is the probability

Answer:

0.50

Step-by-step explanation:

[tex]7 + 3 + 4 = 14[/tex]

So, the probability that the nurses are selected to attend the conference is,

[tex] \frac{7}{14} = \frac{1}{2} [/tex]

[tex] \frac{1}{2} = 0.50[/tex]

The system of equations is given by: y = -2/5x +2 and y = -3x - 4.

Choose two equation pairs at random from the system. Apply the Addition/Subtraction technique to each pair to remove the same variable. Use the Addition/Subtraction method to solve the two new equations as a system. Reintroduce the solution into one of the original equations and find the third variable there.

equations  is:-

y = -2/5x +2 and y = -3x - 4.

when x=0

y= -2/5(0) +2 = 2

y  = -3(0) - 4= 4

when y=0

0= -2/5x +2

x=.80

0= -3x - 4

x=13.33

so from the above value we come to conclusion that system of equations is given by: y = -2/5x +2 and y = -3x - 4.

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