Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations.
x + y - z = -2
2x - y + 3z = 9
x - 4y - 2z = 1

Step-by-step explanation:

sum of 5 times a number and -2, + 8n

becomes:

5n + (-2) + 8n, or

5n -2 +8n, or. 13n - 2

Diagram A and Diagram B do not form a triangular prism

Answer:

1059

Step-by-step explanation:

33 · 32 + 12 ÷ 4

PEMDAS

Multiply and divide first from left to right

1056 + 3

Then add

1059

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{33\times32+12\div4}\\\\\mathsf{33\times32= \boxed{\bf 1,056}}\\\\\mathsf{\bold{1,056}+12\div4}\\\\\mathsf{12\div4=\boxed{\bf 3}}\\\\\mathsf{1,056+\bf 3}\\\mathsf{= \boxed{\bf 1,059}}\\\\\\\boxed{\boxed{\large\textsf{Answer: \huge \bf 1,059}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite40:)}[/tex]

Answer:

90

Step-by-step explanation:

Let the whole number be x.

100% is to x as 70% is to 63

100/x = 70/63

10/x = 10/9

10x = 90 * 10

x = 90

Answer: 90

Step-by-step explanation:

0.7x = 63, x = 63/0.7 = 90

Answer:

14

Step-by-step explanation:

sqrt(25) = 5

sqrt(81) = 9

5 + 9 = 14

Answer:

5.83095189485

Step-by-step explanation:

Its so long

Answer:

mean of data is 141.2

Step-by-step explanation:

mean of data = sum of data / no of data

=98 + 208 + 189 + 94 + 117 / 5

=706 / 5

=141.2

Answer:

Step-by-step explanation:

98 + 208 +189 +94 +1117 =709

706/5 = 141.2

Hope this helps!

Answer:

by using middle term break method

Step-by-step explanation:

9x^2 + 12x + 4

9x^2+ (6 + 6)x + 4

9x^2 + 6x + 6x + 4

3x(3x + 2) + 2(3x + 2)

(3x + 2)(3x + 2)

(3x + 2)^2

Answers:

===========================================================

Explanation:

We're given these three clues

Clue 3 is what we'll start with. Since Mrs. Gray is a doctor, this means that the doctor owns either a white horse or a brown horse. The doctor can't own a gray horse because the names can't match up (eg: the last name Gray with gray horse), due to clue 1.

If Mrs. Gray owned a brown horse, then she'd be a teacher (clue 2). But clue 3 says she's a doctor. We have a contradiction if Mrs. Gray owns the brown horse. Therefore, Mrs. Gray owns the white horse.

----------------

After we concluded the last section, we now know the following:

In short, we've just crossed "Mrs. Gray", "doctor", and "white horse" from the list.

Based on clue 1, we know that Mrs. Brown cannot possibly own the brown horse. Therefore, she must own the gray horse. So Mrs. White must own the brown horse.

Since Mrs. White owns the brown horse, she must be the teacher (clue 2). That leaves "lawyer" as the last profession, and that's assigned to Mrs. Brown.

----------------

Side note: I apologize for being a bit wordy, but I wanted to be very careful in the logical sense as to approach this problem. There's probably a much quicker efficient way to do this.

Answer:

last step is (2x + 5)(2x + 1)

Step-by-step explanation:

4x^2 + 12x + 5

4x^2 + (10 + 2)x + 5

4x^2 + 10x + 2x + 5

2x(2x + 5) +1(2x + 5)

(2x + 5)(2x + 1)

Answer:

H0 : μ ≥ 350

H1 : μ < 350

Step-by-step explanation:

It is claimed that the mean is atleast 350 psi ;

10 such pipes were experimentally sampled ;

Here, the null hypothesis is the claim ; this means that the alternative hypothesis will be the opposite of the claim.

The hypothesis

H0 : μ ≥ 350

H1 : μ < 350

Step-by-step explanation:

[tex]\huge\mathfrak\pink{Answer}[/tex]

Total number of students= y

(25/100) xy= 200

25 xy = 200 x 100

25y 20000

y = 20000/25

y 800

total number of students = 800

Step-by-step explanation:

[tex]\mathfrak\pink{Answer}[/tex]

Total number of students= y

(25/100) xy= 200

25 xy = 200 x 100

25y 20000

y = 20000/25

y 800

total number of students = 800

Answer:

Because we know that here we have an oscillation, we can model this with a sine or cosine function.

P = A*cos(k*t) + M

where:

k is the frequency

A is the amplitude

M is the midline

We know that at t = 0, we have the lowest population.

We know that the mean is 129, so this is the midline.

We know that the population oscillates 25 above and below this midline,

And we know that for t = 0 we have the lowest population, so:

P = A*cos(k*0) + 129 = 129 - 25

P = A + 129 = 129 - 25

A = -25

So, for now, our equation is

P = -25*cos(k*t) + 129

Because this is a yearly period, we should expect to see the same thing for t = 12 (because there are 12 months in one year).

And remember that the period of a cosine function is 2*pi

Then:

k*12 = 2*pi

k = (2*pi)/12 = pi/6

Finally, the equation is:

P = -25*cos(t*pi/6) + 129

Now we want to find the lowest population was in April instead:

if January is t = 0, then:

February is t = 2

March is t = 3

April is t = 4

Then we would have that the minimum is at t = 4

If we want to still use a cosine equation, we need to use a phase p, such that now our equation is:

P = -25*cos(k*t + p) + 129

Such that:

cos(k*4 + p) = 1

Then:

k*4 + p = 0

p =  -k*4

So our equation now is:

P = -25*cos(k*t  - 4*k) + 129

And for the periodicity, after 12 months, in t = 4 + 12 = 16, we should have the same population.

Then, also remembering that the period of the cosine function is 2*pi:

k*12 - 4*k = 2*pi

k*8 = 2*pi

k = 2*pi/8 = pi/4

And remember that we got:

p = -4*k = -4*(pi/4) = -pi

Then the equation for the population in this case is:

P = -25*cos( t*pi/4 - pi) + 129

Answer:

CosC

Step-by-step explanation:

EDG

Answer:

y = 5x - 7

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 5, then

y = 5x + c ← is the partial equation

To find c substitute (2, 3) into the partial equation

3 = 10 + c ⇒ c = 3 - 10 = - 7

y = 5x - 7 ← equation of line

Answer:

a) 0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b) 0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c) 0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 8.1 minutes and a standard deviation of 2.0 minutes.

This means that [tex]\mu = 8.1, \sigma = 2[/tex]

a. between 5 and 10 min

This is the p-value of Z when X = 10 subtracted by the p-value of Z when X = 5.

X = 10

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{10 - 8.1}{2}[/tex]

[tex]Z = 0.95[/tex]

[tex]Z = 0.95[/tex] has a p-value of 0.8289

X = 5

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{5 - 8.1}{2}[/tex]

[tex]Z = -1.55[/tex]

[tex]Z = -1.55[/tex] has a p-value of  0.0606

0.8289 - 0.0606 = 0.7683

0.7683 = 76.83% probability that a randomly selected emergency call is between 5 and 10 minutes.

b. less than 5 min

p-value of Z when X = 5, which, found from item a, is of 0.0606

0.0606 = 6.06% probability that a randomly received emergency call is of less than 5 min.

c. more than 10 min

1 subtracted by the p-value of Z when X = 10, which, from item a, is of 0.8289

1 - 0.8289 = 0.1711

0.1711 = 17.11% probability that a randomly received emergency call is of more than 10 min.

Equations:

x + y = 50

x = y - 18

-------------------

Add and solve for "x"::

2x = 32

x = 16

-----

Solve for "y"::

16 + y = 50

y = 34

ANSWERS ARE IN BOLD

Answer:

6x^3+x^2+3x-6

Step-by-step explanation:

f(x) = 4x² + 3x - 2

g(x) = 6x³ - 3x²-4

(f +g) (x)​ =4x² + 3x - 2+6x³ - 3x²-4

Combine like terms

             =6x^3+4x^2-3x^2+3x-2-4

             =6x^3+x^2+3x-6

Answer:

It's answer is 93i +558....

Answer:

(-2, 3)

Step-by-step explanation:

Answer:

294 in.²

Step-by-step explanation:

I believe this figure is a rectangular prism.

------------------------------------------------------------------------------------

Explain:

To find the surface area of a rectangular prism, use this formula:

[tex]SA=2lw+2lh+2wh[/tex]

              or

[tex]SA=2(lw+lh+wh)[/tex]

[tex]l-length[/tex]

[tex]w-width[/tex]

[tex]h-height[/tex]

A phrase I use to help remember this formula is:

LISA WILSON LOST HER WITCH HAT TWICE (2)

------------------------------------------------------------------------------------

Solve:

The length of this rectangular prism is 9 in.

This width is 10 in.

The height is 3 in.

Now, I will plug the numbers into the first formula.

[tex]SA=(2*9*10)+(2*9*3)+(2*10*3)=294 in.^2[/tex]

------------------------------------------------------------------------------------

Conclude:

I, therefore, believe the area of this rectangular prism is 294 in.²

Answer:

x = 82.1º

Step-by-step explanation:

tan = opp/adj

tan75 = x/22

multiply both sides by 22

22 * tan75 = x

use calculator

82.1051177665153 = x

Rounded

x = 82.1º

9514 1404 393

Answer:

  26 square units

Step-by-step explanation:

Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...

  AB = √(2²+3²) = √13

We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.

  AC = √(6² +4²) = √52 = 2√13

Then the area is ...

  A = LW

  A = (2√13)(√13) = 2·13 = 26 . . . square units

Step-by-step explanation:

the answer is in the image above

Answer:

The height is 8cm

Step-by-step explanation:

Given

[tex]L_A = 240cm^2[/tex] --- lateral area

[tex]a = 12cm[/tex] --- base lengths

Required

The height of the pyramid

The lateral area of a square pyramid is:

[tex]L_A = a\sqrt{a^2 + 4h^2[/tex]

So, we have:

[tex]240 = 12\sqrt{12^2 + 4h^2[/tex]

[tex]240 = 12\sqrt{144 + 4h^2[/tex]

Divide both sides by 12

[tex]20 = \sqrt{144 + 4h^2[/tex]

Square both sides

[tex]400 = 144 + 4h^2[/tex]

Collect like terms

[tex]4h^2 = 400 - 144[/tex]

[tex]4h^2 = 256[/tex]

Divide by 4

[tex]h^2 = 64[/tex]

Take square roots

[tex]h = 8[/tex]

Answer:

The answer is "Option a".

Step-by-step explanation:

Dispute C comes under factual dispute because the words Vacaville or Victorville are two different places and they are arguing about the fact that's why option a is correct.

Answer: See explanation

Step-by-step explanation:

From the information given, the following can be deduced:

Let rate of jet in still air be J

Let rate of wind be W

The formula for distance:

d = rt

Therefore, r = d/t

When, flying against the wind, then the Jet flies at a rate of J - W which will be:

= 1590mi/3hrs

= 530mph

When flying with the wind the jet will fly at a rate of J+W which will be:

= 8240mi/8hrs

= 1030 mph

Their average rate will be:

J = (530+1030)/2

= 1560/2

J = 780 mph

Since J - W = 530

Therefore, so

780 - W = 530

W = 780 - 530

W = 250 mph

The Jet in still air flies at a rate of 780 mph and the wind speed is 250 mph

Answer:

it's the first one where X is greater or equals to -1 and X is less or equals to positive 7

The compound inequality in x : -1 ≤ x ≤ 7

The correct graph is A .

Given, inequality: -4 ≤ 3x -1 and 2x + 4 ≤ 18 .

First inequality:

-4 ≤ 3x -1

Take -2 from RHS to LHS .

-4 + 1 ≤ 3x

-3 ≤ 3x

x ≥ -1

X will have values greater than equal to -1 .

Second inequality:

2x + 4 ≤ 18

take 4 from LHS to RHS.

2x ≤ 18 - 4

2x ≤ 14

x ≤ 7

x will have values less than equals to 7.

Combined result of both inequalities: -1 ≤ x ≤ 7 .Thus graph A is correct.

Know more about inequality,

https://brainly.com/question/28823603

#SPJ3

[tex]\Huge \bf \over \rightarrow\mid\mathcal {\underline{ \orange{12 \: : \: 00}}} \mid[/tex]

Answer:

I think 10:45 is the nearest quarter hour.