Solve the following system of equations graphically on the set of axes below.
y= x+2
y= -1/2x+8

Answer:

77 boxes

Step-by-step explanation:

Take the total number of boxes to be sold and divide by the number of girls in the troop

1000/13

76.92307692

Round up

77

Each girl must sell 77

77*13 =1001

The length of the shorter piece is 15.55 feet.

Thus, the length of the shorter piece is 15.55 feet.

As none of the options matches the answer, all options are incorrect.

Learn more about Ratio & Proportion here:

https://brainly.com/question/12182733

#SPJ2

Answer:

-2 and -2

Step-by-step explanation:

Answer:

Below,

Step-by-step explanation:

The exponent part is done first

7 x 2^3

= 7 * 8

= 56.

You use the acronym PEMDAS:-

( E ( exponential) comes before  M (multiply))

Answer:

The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]

Step-by-step explanation:

Equation of a line:

The equation of a line has the following format:

[tex]y = mx + b[/tex]

In which m is the slope and b is the y-intercept.

Slope:

Having two points, the slope is given by the change in y divided by the change in x. Points (2,4) and (7,2)​, so:

Change in y: 2 - 4 = -2

Change in x: 7 - 2 = 5

Slope: [tex]m = \frac{-2}{5} = -\frac{2}{5}[/tex]

So

[tex]y = -\frac{2}{5}x + b[/tex]

(2,4)

This means that when [tex]x = 2, y = 4[/tex]. So

[tex]y = -\frac{2}{5}x + b[/tex]

[tex]4 = -\frac{2}{5}(2) + b[/tex]

[tex]b = 4 + \frac{4}{5} = \frac{20}{5} + \frac{4}{5} = \frac{24}{5}[/tex]

The equation of the line is [tex]y = -\frac{2}{5}x + \frac{24}{5}[/tex]

the answer is in the picture

Answer:

Completing the square

Step-by-step explanation:

The proof is lengthy, and I don't think you came here to see that whole proof. Here it is anyway to show you the process of completing the square.

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratic-functions-equations/x2f8bb11595b61c86:more-on-completing-square/a/quadratic-formula-proof-review

Answer:

Step-by-step explanation:

Given

[tex]5v - 1/2 = 4 + 3/2v[/tex]

Required

Solve

We have:

[tex]5v - 1/2 = 4 + 3/2v\\[/tex]

Collect like terms

[tex]5v - 3/2v = 4 + 1/2[/tex]

Express fractions as decimals

[tex]5v - 1.5v = 4 + 0.5[/tex]

[tex]3.5v = 4.5[/tex]

Make v the subject

[tex]v= \frac{4.5}{3.5}[/tex]

Divide by .5

[tex]v= \frac{9}{7}[/tex]

Answer:

t = -1

c = 6

s = 8.2 or 8 1/5 (same thing just different notation)

Step-by-step explanation:

3(t+4) = 9

3t + 12 = 9

3t = -3

t = -1

-(c-6) = 0

-c + 6 = 0

-c = -6

c = 6

-10(s+4) = -122

-10s - 40 = -122

-10s = -82

10s = 82

s = 82/10 = 8.2 or 8 2/10 or 8 1/5

Step-by-step explanation:

câu trả lời là trong bức ảnh trên

Answer:

Step-by-step explanation:

Pythagorean theorem states, square of longer is equal to the sum of square of other sides.

That is, c² = a² + b²

           [tex]50^2 = 48 ^2 + 14^2\\\\2500 = 2304 + 196\\\\2500 = 2500[/tex]

Therefore, the lengths satisfies Pythagorean Theorem.

If the sides of a triangle satisfies Pythagoras Theorem, then the triangle is right triangle.

Answer:

y³ + x³ = 1

First, differentiate the first time, term by term:

[tex]{3y^{2}.\frac{dy}{dx} + 3x^{2}} = 0 \\\\{3y^{2}.\frac{dy}{dx} = -3x^{2}} \\\\\frac{dy}{dx} = \frac{-3x^{2}}{3y^{2}} \\\\\frac{dy}{dx} = \frac{-x^{2}}{y^{2}}[/tex]

↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

[tex]3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\[/tex]

[tex]3y^{2}.\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 6xy^{3} - 6x^{4} }{3y^{2}. y^{3}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{- 2xy^{3} - 2x^{4} }{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (y^{3} + x^{3})}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x (1)}{y^{5}} \\\\\frac{d^{2} y}{dx^{2}} = - \frac{-2x}{y^{5}}[/tex]

Hope it's help you

Answer:

Option (3)

Step-by-step explanation:

By applying the property of inscribed angle and intercepted arc in the given circle,

"Measure of an inscribed angle is half the measure of the intercepted arc"

[tex]m(\angle LKJ)=\frac{1}{2}m(\text{arc LJ})[/tex]

[tex]85=\frac{1}{2}(20x+10)[/tex]

[tex]170=20x+10[/tex]

[tex]20x=160[/tex]

[tex]x=8[/tex]

Therefore, Option (3) is the correct option.

Answer:

352

Step-by-step explanation:

512 - 256 + 128 - 64 + 32 = 352

Answer:

[tex]x = 24.75[/tex]

Step-by-step explanation:

Required

Find x

To find x, we have:

[tex]\angle PQR + \angle RPQ + \angle QRP = 180[/tex] -- angles in a triangle

Because [tex]\bar {PR}[/tex] is extended to S, then:

[tex]\angle QRS = \angle QRP[/tex]

So, we have:

[tex]2x + 6 + x - 7 + 5x -17 = 180[/tex]

Collect like terms

[tex]2x + x + 5x = 180 + 17 + 7-6[/tex]

[tex]8x = 198[/tex]

Divide by 8

[tex]x = 24.75[/tex]

Answer:

(a) - 3/2

(b) - 78/25

Step-by-step explanation:

According to the trigonometry, the tangent of any angle is the ratio of rise to the run of the right angle triangle .

The sine of an angle is the ratio of rise to the hypotenuse of the right angle triangle.

The cosine of an angle is the ratio of run to the hypotenuse of the right angle triangle.

(a)

[tex]tan\beta = \frac{3}{-2} = \frac{-3}{2}[/tex]

(b)

[tex]13 sin\beta cos \beta = 13\times \frac{3}{\sqrt{3^2+2^2}}\times\frac{-2}{\sqrt{3^2+2^2}}\\\\13 sin\beta cos\beta = \frac{- 78}{25}[/tex]

Answer:

I NOT 100% SURE BUT I THINK ITS .B)

Step-by-step explanation:

Answer:

I think choose (1)

[tex]125 ^{ \frac{1x}{3} } [/tex]

Answer:

We want to find the graph of:

|x| = 3

Remember how the absolute value function works:

|x| = x  if x ≥ 0

|x| = -x if  x < 0

Then for the equation:

|x| = 3

We have two possible values of x:

x = 3

|3| = 3

and x = -3

|-3| = -(-3) = 3

Then the graph of this equation is two vertical lines, one at:

x = 3

and another at:

x = -3

The graph can be seen below:

Answer:

2/3

Step-by-step explanation:

2/3 is 66 2/3%

Answer:

7 x 1/10 = 7/10

Step-by-step explanation:

There are 7 "bumps" on the number line, and each "bump" moves the line 1/10.

This can also be modeled as

1/10 + 1/10 + 1/10 +1/10 +1/10 +1/10 +1/10 = 7/10

Answer:

The answer is 5284.35 using the conversion

Answer:

5284.4

Explanation:

Tbh if you have a conversion table then see the conversion for what 1 oz is equal to in mL and do the math like that… •_•

Hope this helps, have a good day!

Answer:

94%

Step-by-step explanation:

4,700/5,000 x 100%

0.94 x 100% = 94%

Answer:

94%

Step-by-step explanation:

Answer:

See explaation

Step-by-step explanation:

Given

Represent the balls with the first letters

[tex]W =1[/tex]

[tex]R =2[/tex]

Solving (a): P(F) --- White balls twice

The event of F is:

[tex]F = \{(W,W)\}[/tex]

So:

[tex]P(F) = P(W) * P(W)[/tex]

[tex]P(F) = \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(F) = \frac{1}{3} * \frac{1}{3}[/tex]

[tex]P(F) = \frac{1}{9}[/tex]

Solving (b): P(G) --- two different colors

The event of G is:

[tex]G = \{(W,R),(R,W)\}[/tex]

So:

[tex]P(G) = P(W) * P(R) + P(R) * P(W)[/tex]

[tex]P(G) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(R)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(G) = \frac{1}{3} * \frac{2}{3} + \frac{2}{3} * \frac{1}{3}[/tex]

[tex]P(G) = \frac{2}{9} + \frac{2}{9}[/tex]

[tex]P(G) = \frac{4}{9}[/tex]

Solving (c): P(H) --- White picked first

The event of H is:

[tex]H = \{(W,R),(W,W)\}[/tex]

So:

[tex]P(H) = P(W) * P(R) + P(W) * P(W)[/tex]

[tex]P(H) = \frac{n(W)}{n} * \frac{n(R)}{n} + \frac{n(W)}{n} * \frac{n(W)}{n}[/tex]

[tex]P(H) = \frac{1}{3} * \frac{2}{3} + \frac{1}{3} * \frac{1}{3}[/tex]

[tex]P(H) = \frac{2}{9} + \frac{1}{9}[/tex]

[tex]P(H) = \frac{3}{9}[/tex]

[tex]P(H) = \frac{1}{3}[/tex]

Solving (d): F and G, mutually exclusive?

We have:

[tex]F = \{(W,W)\}[/tex]

[tex]G = \{(W,R),(R,W)\}[/tex]

Check for common elements

[tex]n(F\ n\ G) = 0[/tex]

Hence, F and G are mutually exclusive

Solving (e): G and G, mutually exclusive?

We have:

[tex]G = \{(W,R),(R,W)\}[/tex]

[tex]H = \{(W,R),(W,W)\}[/tex]

Check for common elements

[tex]n(G\ n\ H) = 1[/tex]

Hence, F and G are not mutually exclusive