) Solve t + t + t = 12

The Davenports' medical expenses contribute to their total itemized deductions are $375 (7.5% for 2019).

The costs you incurred for state and local income or sales taxes, real estate taxes, personal property taxes, mortgage interest, and disaster losses are all included in itemised deductions. You can also count charitable donations and a portion of your out-of-pocket medical and dental costs.

Currently for the 2019 (due 2020), you can deduct medical expenses that exceed 7.5% of your AGI, but back then in 2019, the threshold was 7.5%, not 10%.

So the Davenports can only deduct

$5,250 - ($65,000 x 7.5%) = $375

if they decided to itemize their deductions.

The threshold will increase back to 10% starting 2020 (due 2021) tax returns.

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The cylindrical has a surface area of 414 square units due to its 9-unit radius and 14-unit height.

A cylinder is a three-dimensional geometric form made up of two circular bases that are parallel to one another and are joined by a curved lateral surface. It can be pictured as a solid item with a constant circular cross-section along its entire length. The measurements of a cylinder, such as the radius and height of the circular bases, affect its characteristics. The surface area, volume, and horizontal surface area of a cylinder are some of its typical characteristics. Mathematical formulas can be used to determine these properties.

given

The following algorithm determines a cylinder's surface area:

[tex]A = 2\pi r^2 + 2\pi rh[/tex]

where r is the cylinder's base's radius, h is the cylinder's height, and (pi) is a mathematical constant roughly equivalent to 3.14.

Inputting the numbers provided yields:

[tex]A = 2\pi (9)^2 + 2\pi (9)(14)\\[/tex]

A = 2π(81) + 2π(126) 

A = 162π + 252π

A = 414π

The cylindrical has a surface area of 414 square units due to its 9-unit radius and 14-unit height.

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The probability of landing on yellow is 0.2, probability of component is 0.8, and sum of event and complement is 1.

On assuming that the pie is evenly divided into 5 parts,

So, the probability of landing on yellow is = 1/5 = 0.2,

The complement of landing on yellow is the probability of not landing on yellow, which is the probability of landing on any of the other 4 parts of the pie.

So, the probability of the complement is = 4/5 = 0.8,

The sum of the event (landing on yellow) and the complement (not landing on yellow) is equal to the probability of the entire sample space, which is 1.

⇒ P(Yellow) + P(Not Yellow) = 1

⇒ 0.2 + 0.8 = 1

So, the sum of the event and the complement is 1 or 100%.

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The given question is incomplete, the complete question is

A circular pie is divided in 5 parts , Green , Yellow, Blue Black and Red.

Find the probability of landing on yellow, the probability of complement, and the sum of the event and the complement.

The value of error term E(x,y) = 8x^2 - 8x - 56.

The definition of differentiability states that a function f(x,y) is differentiable at a point (a,b) if there exists a linear function L(x,y) such that:

f(x,y) - f(a,b) = L(x,y) + E(x,y)

where E(x,y) is an error term that approaches 0 as (x,y) approaches (a,b).

In the case of the function f(x,y) = 8x^2 - 8y, we want to find E(x,y) at the point (-1,-7).

First, we need to calculate f(-1,-7):

f(-1,-7) = 8(-1)^2 - 8(-7) = 56

Next, we need to find the linear function L(x,y) that approximates f(x,y) near (-1,-7). To do this, we can use the gradient of f(x,y) at (-1,-7):

∇f(-1,-7) = (16,-8)

The linear function L(x,y) is given by:

L(x,y) = f(-1,-7) + ∇f(-1,-7) · (x+1, y+7)

where · denotes the dot product.

Substituting the values, we get:

L(x,y) = 56 + (16,-8) · (x+1, y+7)

= 56 + 16(x+1) - 8(y+7)

= 8x - 8y

Finally, we can calculate the error term E(x,y) as:

E(x,y) = f(x,y) - L(x,y) - f(-1,-7)

= 8x^2 - 8y - (8x - 8y) - 56

= 8x^2 - 8x - 56

Therefore, the error term E(x,y) for the function f(x,y) = 8x^2 - 8y at the point (-1,-7) is E(x,y) = 8x^2 - 8x - 56.

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The three angles are= angleMCD + angleCMD + angleGMF= 180.

Two lines intersect at a location, creating an angle.

An "angle" is the term used to describe the width of the "opening" between these two rays. The character is used to represent it.

Angles are frequently expressed in degrees and radians, a unit of circularity or rotation.

In geometry, an angle is created by joining two rays at their ends. These rays are referred to as the angle's sides or arms.

An angle has two primary components: the arms and the vertex. T

he two rays' shared vertex serves as their common terminal.

According to our question-

angleM= 127

angleC=27

angleG=26

127+27+26

180

Hence, The three angles are= angleMCD + angleCMD + angleGMF= 180.

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Answer: <MCD, <CMD, and <GMF

Step-by-step explanation:

Answer: it represents half of the students in 1 class

Step-by-step explanation:

1/2 divided by s

Answer:

1/2s would then represent one half (or 50%) of the students in the singular class stated.

The function rule for this graph is  y = -1/2(x) + 2.

In Mathematics, the point-slope form of a straight line can be calculated by using the following mathematical expression:

y - y₁ = m(x - x₁) or [tex]y - y_1 = \frac{(y_2- y_1)}{(x_2 - x_1)}(x - x_1)[/tex]

Where:

At data point (0, 2), a linear equation in slope-intercept form for this line can be calculated by using the point-slope form as follows:

[tex]y - y_1 = \frac{(y_2- y_1)}{(x_2 - x_1)}(x - x_1)\\\\y - 2 = \frac{(0- 2)}{(4 -0)}(x -0)[/tex]

y - 2 = -1/2(x)

y = -1/2(x) + 2.

In this context, we can reasonably infer and logically deduce that an equation of the line that represents this graph in slope-intercept form is y = -1/2(x) + 2.

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The set of ordered pair that does not represent a function is option 1 {(4,0), (8, -8), (4,1), (5,8)}.

A function in mathematics is a relationship between two sets in which every element of the first set (referred to as the domain) is connected to exactly one element of the second set (called the range). A function is typically represented by the symbol f(x), where x is a domain element and f(x) is a corresponding range element.

We know that, a set of ordered pairs represents a function if each input is associated with only one output.

From the given options we observe that, {(4,0), (8, -8), (4,1), (5,8)}, does not represent a function.

Hence, the set of ordered pair that does not represent a function is option 1 {(4,0), (8, -8), (4,1), (5,8)}.

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Answer:

12/2652

Step-by-step explanation:

First, the probability of drawing a king for the first time is 4/52. The chance of drawing another is 3/51. Multiplying, we get the 3rd answer choice, 12/2652

Step-by-step explanation:

(a) Experimental probability of rolling an even number = (number of rolls for 2, 4, and 6) / (total number of rolls) = (4 + 5 + 6) / 40 = 0.375

(b) Theoretical probability of rolling an even number = number of even outcomes / total number of outcomes = 3 / 6 = 0.5

(c) Statement 2 is true: With a small number of rolls, it is not surprising when the experimental probability is much greater than the theoretical probability.

Answer:

True

Step-by-step explanation:

Vertical angles are right angle that is 90°

A supplementary angle is an angle that forms up by 2 angles with the sum of 180°.

It is true because 2 vertical angles form a supplementary angle.

Answer:

Answer:

To solve for r, we can start by simplifying the equation:

1475/2pi = (3/4r^2pi) + (1/4pi*(r-15)^2) + (1/4pi(r-25)^2)

Multiplying both sides by 2*pi:

1475 = 3/4r^2pi2 + 1/4pi*(r-15)^22 + 1/4pi*(r-25)^2*2

1475 = 3/2r^2pi + 1/2pi(r-15)^2 + 1/2pi(r-25)^2

Multiplying both sides by 2:

2950 = 3r^2pi + pi*(r-15)^2 + pi*(r-25)^2

Distributing pi:

2950 = 3r^2pi + pir^2 - 30pir + 225pi + pir^2 - 50pir + 625pi

Combining like terms:

2950 = 5r^2pi - 80pir + 850*pi

Rearranging:

5r^2pi - 80pir + 850*pi - 2950 = 0

Simplifying:

5r^2pi - 80pir + 675*pi = 0

Dividing both sides by 5*pi:

r^2 - 16*r + 135 = 0

This is a quadratic equation, which can be solved using the quadratic formula:

r = (-(-16) ± sqrt((-16)^2 - 4(1)(135))) / (2(1))

r = (16 ± sqrt(256 - 540)) / 2

r = (16 ± sqrt(284)) / 2

r ≈ 1.7321 * 16 or r ≈ 8.2679

Since r represents the distance from the center of the octagon to a vertex, only the larger value of r makes sense in this context.

Therefore, r ≈ 8.2679 feet.

To find the area of the region in which the cow can graze, we can divide the octagon into eight congruent isosceles triangles with base 25 feet and height equal to the distance from the center to a side (which is equal to r).

The area of each triangle is (1/2)bh = (1/2)(25)(8.2679) = 103.3494 square feet.

Multiplying by 8 to account for all eight triangles:

8 * 103.3494 = 826.7952 square feet.

Rounding to the nearest square foot:

The area in which the cow can graze is approximately 827 square feet

Step-by-step explanation:

The balance will be the initial deposit ( p = 3000)  plus the interest earned for two years  p r t     where r = decimal interest per year   t = 2 years

Balance = $   3000  +    3000 * .025 * 2  = $ 3150.00

There are 500 odd numbers between 1 and 999.

We can solve this problem using the arithmetic sequence formula, which is

an = a1 + (n - 1)d

where

an is the nth term of the sequence

a1 is the first term of the sequence

n is the number of terms in the sequence

d is the common difference between consecutive terms

In this case, a1 = 1, the common difference is 2, and we want to find the value of n such that an = 999. So we have

999 = 1 + (n - 1)2

Simplifying this equation, we get

998 = 2(n - 1)

499 = n - 1

n = 500

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The Monotone Convergence Theorem can be demonstrated by considering the decreasing sequence {a_n} = 1/n, which is bounded below by zero and converges to zero.

Consider the sequence of real numbers {a_n} defined as a_n = 1/n. We want to show that the sequence converges to zero.

First, notice that the sequence is decreasing since a_n+1 = 1/(n+1) < 1/n = a_n for all n ≥ 1. Moreover, the sequence is bounded below by zero since a_n > 0 for all n. Thus, the sequence {a_n} is a decreasing bounded sequence and by the Monotone Convergence Theorem, it must converge to some limit L.

Let's now calculate the limit L. Since the sequence is decreasing and bounded below by zero, its limit L must be greater than or equal to zero. Furthermore, for any ε > 0, there exists an N such that 1/n < ε for all n > N, since the sequence converges to zero. Therefore, we have

|a_n - 0| = |1/n - 0| = 1/n < ε for all n > N.

This shows that the limit of the sequence is zero, i.e., lim (n → ∞) 1/n = 0.

Thus, we have demonstrated that the Monotone Convergence Theorem applies to the sequence {a_n}, which is decreasing and converges to zero.

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I have solved the question in general, as the given question is incomplete.

The complete question is:

Give an example to show that the Monotone Convergence Theorem?

A = {u + 2v, -3} is the basis for subspace U given that the set A is now linearly independent and that U = span(A).

Since U = span(S), and the set S is linearly independent, let S = {u, v} be the basis of the subspace U.

Now determine whether or not the set A = {u + 2v, -3v} is linearly independent.

A set of vectors must all have linear combinations that add up to zero in order for them to be considered linearly independent. Let a and b represent any scalars so that,

a(u + 2v) + b(-3v) = 0

Simplify the obtained equation.

au + 2av - 3bv = 0

au + v(2a - 3b) = 0

Make 2a - 3b = A.

Rewrite the equation that was found using this.

Now because u and v are linearly independent, a and A must be zero, and as a result, the constant b is also zero.

Set A is hence linearly independent.

Also, au + Av ∈ U, so, U = span(A).

Considering that the set A is now linearly independent and that U = span(A), the basis for subspace U is A = {u + 2v, -3}.

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The complete question is:

If {u, v} is a basis for the subspace U, show that {u + 2v, −3v} is also a basis for U.

The probability of obtaining a reading between 0.59°C and 0.88°C is 0.7224 and 0.8106.

The sum of all possible values, weighted by the chance of each value, is equal to the mean of a discrete probability distribution of the random variable X. Each possible number of X must be multiplied by its probability P(x) before being added as a whole to determine the mean. In statistics, the mean is one measure of central trend in addition to the mode and median. The mean is simply the average of the numbers in the specified collection. It suggests that values in a specific data gathering are evenly distributed. In order to find the mean, the total values given in a datasheet must be added, and the result must be divided by the total number of values.

In this question, using the formula,

z-score = (x – μ) / σ

where:

x: individual data value

μ: population mean

σ: population standard deviation

for x=0.59

μ= 0

σ= 1

z-score= 0.59

Probability=0.7224

for x=0.88

z-score= 0.88

Probability=0.8106

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Answer:

Yes. If you are asking if the duration between those two times is a total of 12 hours, the answer is yes.

Step-by-step explanation:

9:45am is 12 hours away from 9:45pm. This applies to all times and their am/pm counterparts such as 12am/12pm.

Using differentiation, the area of the triangle is decreasing at the given time.

The formula for the area of a triangle is:

A = (1/2)bh

where b is the base and h is the height.

Differentiating both sides of the equation with respect to time t, we get:

[tex]\frac{dA}{dt} = (1/2)[(\frac{db}{dt}) h + b(\frac{dh}{dt}) ][/tex]

Substituting the given values, we get:

[tex]\frac{dA}{dt} = (1/2)[(1)(10) + (5)(-2.5)] = (1/2)(10 - 12.5) = -1.25[/tex]

Since the derivative of the area with respect to time is negative (-1.25), the area of the triangle is decreasing at the given instant.

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Answer: 10 is two units from 0 on the number line, so there are six numbers that are 10 units from 0.

Step-by-step explanation:

let me have brainliest real quick

To solve the equation -12x + 24 = 0, we want to get x by itself on one side of the equation.

First, we can subtract 24 from both sides:

- 12x + 24 - 24 = 0 - 24

This simplifies to:

- 12x = -24

Next, we can divide both sides by -12:

- 12x / -12 = -24 / -12

This simplifies to:

x = 2

Therefore, the solution to the equation -12x + 24 = 0 is x = 2.

The Born exponent or interatomic potential energy for Rbl is 11 ( approximately). The correct option is D).

The Born exponent for RbI can be calculated using the relationship between the Born exponent and the interionic distance. The Born exponent is defined as the ratio of the repulsive to attractive contributions to the interatomic potential energy, and it depends on the charges and sizes of the ions.

For Rb+ and I-, the Born exponents are 10 and 12, respectively. This means that the repulsive interaction between Rb+ and I- is weaker than the attractive interaction, as the repulsion is proportional to Rb+^10 and the attraction is proportional to I^-12. Therefore, the attractive interaction dominates.

For RbI, we can use the relationship between the Born exponent and the interionic distance to calculate the Born exponent. This relationship is given by:

B = (1/d) * ln[(l1 + l2)/|l1 - l2|]

where B is the Born exponent, d is the interionic distance, and l1 and l2 are the ionic radii of the cation and anion, respectively.

Assuming the ionic radii of Rb+ and I- are additive, we have:

l1 + l2 = l(RbI) = l(Rb+) + l(I-) = 1.52 + 1.81 = 3.33 Å

|l1 - l2| = |l(Rb+) - l(I-)| = |1.52 - 1.81| = 0.29 Å

Substituting these values into the equation for B, we get:

B = (1/d) * ln[(l1 + l2)/|l1 - l2|] = (1/d) * ln[3.33/0.29] ≈ 11.02

Therefore, the Born exponent for RbI is approximately 11.02.

The correct answer is D).

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The probability of obtaining a reading less than 0.35° C is approximately 35%.

Accοrding tο the prοbability fοrmula, the likelihοοd οf an event οccurring is equal tο the ratiο οf the number οf favοurable οutcοmes tο the tοtal number οf οutcοmes. Prοbability οf an event οccurring P(E) = The number οf favοurable οutcοmes divided by the tοtal number οf οutcοmes.

The readings at freezing οn a set οf thermοmeters are nοrmally distributed, with a mean (x) οf 0°C and a standard deviatiοn (μ) οf 1.00°C. We want tο knοw hοw likely it is that we will get a reading that is less than 0.35°C.

To solve this problem, we must use the z-score formula to standardise the value:

[tex]$Z = \frac{x - \mu}{\sigma}[/tex]

Z = standard score

x = observed value

[tex]\mu[/tex] = mean of the sample

[tex]\sigma[/tex] = standard deviation of the sample

Here

x = 0.35° C

[tex]\mu[/tex] = 0° C

[tex]\sigma[/tex] = 1.00°C

Using the values on the formula:

[tex]$Z = \frac{0.35 - 0}{1}[/tex]

Z = 0.35

The probability of obtaining a reading less than 0.35° C is approximately 35%.

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There is a vertical asymptote at x = 2 and the slope and intercept of the oblique asymptote are 2 and - 1, respectively.

In this problem we find the definition of a rational function:

f(x) = (2 · x² - 5 · x + 3) / (x - 2)

The vertical asympote correspond to the vertical line at the x-value where the function is undefined. And the oblique asymptote is defined by a equation of the form:

y = m · x + b

Where:

And the slope and the intercept of the asymptote can be found by means of the following equation:

Slope

[tex]m = \lim_{x \to \pm \infty} \left[\frac{f(x)}{x}\right][/tex]

Intercept

[tex]b = \lim_{x \to \pm \infty} [f(x) - m \cdot x][/tex]

First, factor and simplify the rational equation to determine whether any zero is evitable:

f(x) = (2 · x² - 5 · x + 3) / (x - 2)

f(x) = (2 · x - 3) · (x - 1) / (x - 2)

The discontinuity at x = 2 is not evitable. Then, the equation for the vertical asymptote is x = 2.

Second, determine the slope and the intercept of the oblique asymptote:

[tex]m = \lim_{x \to \pm \infty} \left[\frac{2\cdot x^{2}-5\cdot x + 3}{x^{2} - 2\cdot x} \right][/tex]

m = 2

[tex]b = \lim_{x \to \pm \infty} \left[\frac{2\cdot x^{2}-5\cdot x + 3}{x - 2} - 2 \cdot x\right][/tex]

[tex]b = \lim_{x \to \pm \infty} \left[\frac{2\cdot x^{2}-5\cdot x + 3-2 \cdot x^{2}+4\cdot x}{x-2}\right][/tex]

[tex]b = \lim_{x \to \pm \infty} \left[\frac{3 - x}{x-2} \right][/tex]

b = - 1

The slope and the intercept of the oblique asymptote are 2 and - 1, respectively.

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The percentage of students earned a B in the statistics course is 22.5%. So, the correct option is B).

To find the percentage of students who earned a B in the course, we need to determine the total number of students who took the course and the number of students who earned a B.

Using the information given in the bar chart, we can determine that there were a total of 40 students who took the statistics course. The number of students who earned a B is given as 9 in the bar chart. Therefore, the percentage of students who earned a B is (9/40) x 100%, which simplifies to 22.5%.

The total number of students who took the statistics course is:

Y = A + B + C + D + F = 5 + 9 + 11 + 8 + 7 = 40

The percentage of students who earned a B is:

(B/Y) x 100% = (9/40) x 100% = 22.5%

Therefore, the correct answer is (B) 22.5%.

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Answer: y = 4(x² − 1)(x² − 4).

Step-by-step explanation:

We need to find the equation of the curve that passes through the point (2, 0).

We start by separating the variables dy/dx and y and integrating both sides:

(2x² - 5) dy/dx = 8x(y + 9)

dy/(y + 9) = (4x/(2x² - 5)) dx

Integrating both sides:

ln|y + 9| = 2ln|2x² - 5| + C

where C is the constant of integration.

Rewriting in exponential form:

|y + 9| = e^(2ln|2x² - 5| + C)

|y + 9| = e^(ln|2x² - 5|² + C)

|y + 9| = k(2x² - 5)²

where k is the constant of integration.

Since the curve passes through the point (2, 0), we can substitute these values into the equation above to find k:

|0 + 9| = k(2(2)² - 5)²

9 = k(36)

k = 1/4

Substituting this value of k back into the equation, we get:

|y + 9| = (1/4)(2x² - 5)²

y + 9 = (1/4)(2x² - 5)² or y + 9 = -(1/4)(2x² - 5)²

Simplifying the right-hand side of each equation, we get:

y + 9 = (1/4)(4x⁴ - 20x² + 25)

or

y + 9 = -(1/4)(4x⁴ - 20x² + 25)

Expanding and simplifying, we get:

y = 4x⁴/4 - 5x²/2 + 25/4 - 9 or y = -4x⁴/4 + 5x²/2 - 25/4 - 9

y = x⁴ - 5x² + 19/4 or y = -x⁴/4 + 5x²/2 - 41/4

Thus, the equation of the curve passing through the point (2, 0) with the given gradient is y = 4(x² − 1)(x² − 4).

Answer:

From the given information, we know that the area to the left of c under the standard normal distribution curve is 0.0166.

Using a standard normal distribution table or calculator, we can find the corresponding z-score for this area.

A z-score represents the number of standard deviations away from the mean. For a standard normal distribution, the mean is 0 and the standard deviation is 1.

Looking up the area of 0.0166 in the z-table, we find that the corresponding z-score is approximately -2.06.

Therefore, we have:

P(z < c) = 0.0166

P(z < -2.06) = 0.0166

So, c = -2.06.

Answer:

Using a standard normal distribution table, we can find the z-score corresponding to a probability of 0.0166:

z = -2.07

Therefore, c = -2.07.

Step-by-step explanation:

Answer: Area: 460.48 ft^2         Perimeter: 90.12 ft

Step-by-step explanation:

The area is 1/2 * 3.14 * (16 / 2)^2 (area of semicircle)

+ 10 * 12 / 2 (area of triangle)

+ 20 * 15 (area of rectangle)

= 460.48

The perimeter is 1/2 * 16 * 3.14 (perimeter of semicircle)

+ 10 (perimeter of triangle)

+ 20 + 15 + 20 (perimeter of rectangle)

= 90.12

Using the correct order of operations, the value is 13

PEDMAS is simply described as a mathematical acronym that represents the different arithmetic operations in order from least to greatest of application.

The alphabets represents;

From the information given, we have;

15-(4-3)2

solve the parentheses first

15 - (1)2

Multiply the values

15 - 2

Subtract the values

13

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The complete question:

Solve using the correct order of

operations of PEMDAS

15 - (4-3)2

The values or variables listed in the function declaration are called formal parameters to the function.

They are used to store the data that is passed into the function when it is called. The formal parameters are local variables, meaning that the values stored in them are only available within the function.

The arguments are the values passed to the function when it is called. These values are then assigned to the formal parameters and are used within the function to perform the desired task.

Formal arguments are produced at function entry and removed at function exit, behaving similarly to other local variables inside the function.

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