Hi!
i think We can set up a proportion to solve this
\frac{3}{12} \frac{x}{16}
12
3
16
x
Cross multiply
3 x 16 = 48
48/12 = 4
The answer is 4
Hope this helps! :)
A 95% confidence interval is (70,110). what is the margin for error? A. 19 B.38 C.20 D.40
Answer:
C.20
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
The margin of error is the difference between the two bounds, divided by 2.
In this question:
Lower bound: 70
Upper bounf: 110
Margin of error:
[tex]M = \frac{110 - 70}{2} = \frac{40}{2} = 20[/tex]
Thus the correct answer is given by option C.
6x - 5y= 70
7x + 2y=66
I need a answer in words step by step please help!!
Answer:
x = 10
y = -2
Step-by-step explanation:
Elimination method:
6x - 5y = 70 -----------------(I)
7x + 2y = 66 -----------------(II)
Multiply equation (I) by 2 and equation (II) by 5 and add. So, y will be eliminated and you can now find the value of x
(I)*2 12x - 10y = 140
(II)*5 35x + 10y = 330 {Now add}
47x = 470
x = 470/47
x = 10
Plugin x = 10 in equation (II)
7*10 + 2y = 66
70 + 2y = 66
Subtract 70 from both sides
2y = 66 - 70
2y = -4
Divide both sides by 2
y = -4/2
y = - 2
every evening Jenna empties her pockets and puts her change in a jar. At the end of the week she counts her money. One week she had 38 coins, all of them being quarters and dimes. When she added them up she had a total of $6.95. Let d=number of dimes and q= number of quarters. How many dimes did Jenna have?
d = dimes
q = quarters
d+q = 38 coins
q=38-d
0.25q + 0.10d=6.95
0.25(38-d)+0.10d=6.95
9.5-0.25d+0.10d=6.95
-015d=-2.55
d=-2.55/-0.15 = 17
q=38-17 =21
21*0.25 =5.25
17*0.10 = 1.70
5.25+1.70 = 6.95
she had 21 quarters and 17 dimes
lines a and b are parallel m<2 = ?°
Answer:
50 degrees
Step-by-step explanation:
50 degrees because angle 2 is its vertical angle
solve for x and y x+y/ху=1 and x-y/xy = 5
Answer:
(x, y) = (-1/2, 1/3)
Step-by-step explanation:
Given the simultaneous equation
x+y/ху=1. ...1
x-y/xy = 5 .... 2
From 1; x+y = xy ...3
From 2; x - y = 5xy ...4
Substituting 3 into 4
x - y = 5(x+y)
x - y = 5x + 5y
x - 5x = 5y + y
-4x = 6y
-2x = 3y
x = -3y/2 ... 4
Add 3 and 4
2x = 6xy
2 = 6y
y = 2/6
y = 1/3
x = -3(1/3)/2
x = -1/2
Hence (x, y) = (-1/2, 1/3)
in a sale, normal prices are reduced by 10%
nathalie bought a pair of shoes in the sale for £54
what was the original price of the shoes
in a sale, normal prices are reduced by 10%
nathalie bought a pair of shoes in the sale for £54
what was the original price of the shoes
Answer[tex]x = 60[/tex]
Explanation
[tex] \sf based \: on \: the \: given \: conditions \: write : x = \frac{54}{ 1 - 01} [/tex]
[tex] \sf calculate \: the \: sum \: difference: x = \frac{54}{0.9} [/tex]
convert decimal to fraction: x= 54 / 9 / 10
[tex] \sf \: divide \: a \: fraction \: by \: multiplying \: its \: reciprosal : x = 54 \times \frac{10}{9} [/tex]
[tex] \sf \: write \: as \: a \: single \: fraction : x = \frac{54 \times 10}{9} [/tex]
[tex] \sf \: reduce \: fraction \: to \: the \: lowest \: term \: by \: cancelling \: the \: greatest \: [/tex]
[tex] \sf \: common \: factor : x = 6 \times 10[/tex]
[tex] \sf \: calculate \: the \: product \: or \: quotient : x = 60 [/tex]
[tex] \sf{ \boxed{answer : x = 60}}[/tex]
Michael is going to the amusement park, where he has to pay a set price of admission
and another price for tickets to go on each of the rides. The total amount of money
Michael will spend is given by the equation y = 3x + 28, where y represents the
total amount of money, in dollars and cents, and a represents the number of rides
Michael goes on. What could the number 3 represent in the equation?
In parallelogram QRST if m∡TQR=50∘ find m∡STQ.
Find the area of this triangle.
17 cm
10 cm
8 cm
21 cm
A = [ ? ] cm2
Answer:
84 cm^2
Step-by-step explanation:
8 * 21/2=84
Express in simplest form -45%
Answer: hello, your answer is -0.45
Hi guys pls answer this it’s easy tbh
Answer:
this is the accurate answer of your questions
Find the different between compound interest payable anually and half anually for a amount Rs14000 at the rate of 12•\•per annum for 2 yrs.
Answer:
$113.08
Step-by-step explanation:
The formula for calculating future value:
FV = P (1 + r/m)^mn
FV = Future value
P = Present value
R = interest rate
N = number of years
m = number of compounding
14,000(1.12)^2 = 17,561.60
14,000 ( 1 + 0.12/2)^(2x2) = 17674.68
Difference : 17674.68 - 17,561.60 = $113.08
Find the greatest number of student among whom 120 oranges and 130 apples can be divided equally.
Answer:
10
Step-by-step explanation:
We need to find the greatest number of student among whom 120 oranges and 130 apples can be divided equally.
It means we need to find the HCF of 120 and 130.
HCF is highest common factor.
The HCF of 120 and 130 is 10.
So, the greatest number of student is 10.
Find the values of a and b that make the second expression equivalent to the first expression. Assume that x > 0 and y ≥ 0.
Answer:
a= 16
b= 2
Step-by-step explanation:
edge 2021
Answer:
a=16 and b=2
Step-by-step explanation:
next one is B.
10. Volume =
pls help me i wanna go home ;(
Answer:
1248 cm^2
Step-by-step explanation:
Volume = Length · Width · Height
Volume = 24 · 6 · 5
Volume = 720 cm^2
Volume = Length · Width · Height
Volume = 8 · 6 · 11
Volume = 528 cm^2
528 + 720 = 1248
Answer:
1248 cm³
Step-by-step explanation:
V = lwh
V = 24 cm × 6 cm × 5 cm
V = 720 cm³
V = lwh
V = 8 cm × 6 cm × 11 cm
V = 528 cm³
720 cm³ + 528 cm³
1248 cm³
Identify the coefficient(s) of the variable in the expression below.
25 - 6z
A
z
B
1
C
6
D
25 and 6
Answer:
D
Step-by-step explanation:
25 and 6
Coefficient is the number in front of the unknown variable
Identify the coefficient(s) of the variable in the expression below.
25 - 6z
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {C. \:6}}}}}}[/tex]
Explanation:
Coefficients are numbers that are attached to variables. In the expression "25 - 6z", 6 is the coefficient since it is attached to the variable z.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]
Work out m and c for the line:2y+3x=5
Answer:
[tex]{ \tt{2y + 3x = 5}} \\ { \tt{2y = - 3x + 5}} \\ { \tt{y = - \frac{3}{2} x + \frac{5}{2} }} \\ { \boxed{ \bf{general \: equation : { \tt{y = mx + c}}}}} \\ by \: relation : \\ { \tt{m = - \frac{3}{2} }} \\ \\ { \tt{c = \frac{5}{2} }} \\ \\ { \underline{ \blue{ \tt{becker⚜jnr}}}}[/tex]
The profit for a car company can be represented by the function P=−0.5 x² +4 x+ 12,
where P is the profit in hundred thousands of dollars and x represents the number of cars sold in thousands. What is the maximum profit the company can make?
Answer:
3x+12
Step-by-step explanation:
-0.5x*2+4x+12
Multiply 0.5x*2=x
= -x+4x+12
Add similar elements -x+4x+12
= 3x+12
Answer 2 questions about equations A and B.
A. 5x−2+x=x-4
B. 5x+x=x−4
1) How can we get Equation BBB from Equation AAA?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Add/subtract a quantity to/from only one side
(Choice B)
B
Add/subtract the same quantity to/from both sides
(Choice C)
C
Rewrite one side (or both) using the distributive property
(Choice D)
D
Rewrite one side (or both) by combining like terms
2) Based on the previous answer, are the equations equivalent? In other words, do they have the same solution?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
Yes
(Choice B)
B
No
Step-by-step explanation:
Given that,
Two equations,
A. 5x−2+x=x-4
B. 5x+x=x−4
1.
The RHS of both the equations is same. To make them equal we need to remove the difference.
If we add 2 to the left side of equation A, then we get equation B.
The correct option is (A) i.e. Add/subtract a quantity to/from only one side.
2.
As the equations are not same, they will have different solutions. The answer choice is (b) "No".
Hey There Answer Add/subtract a quantity to/from only one side
And No
Step-by-step explanation:
Give answer to the Nearest degrees
Answer:
[tex]\theta = 79.9^{\circ}[/tex]
Step-by-step explanation:
Given hypotenuse = x , opposite = 1.7 , adjacent = 0.3
Using trigonometric ratios :
[tex]sin \theta = \frac{opposite}{hypotenuse}\\\\cos \theta = \frac{adjacent}{hypotenuse}\\\\tan \theta = \frac{opposite}{adjacent}[/tex]
[tex]tan \theta = \frac{1.7}{0.3} = \frac{17}{3} = 79.9^{\circ}[/tex]
Find the sum difference 104 - (-92)
Answer:
12
Step-by-step explanation:
The volume (v) of water stored in an open tank varies due to evaporation as v=x^4-50x^2+700 where v is expressed in gallons and x is number of months elapsed. If January correspond to x=0 what will the volume of water (in gallons) in the tank be in june
A.700
B.1200
C.75
D.100
Answer:
C) 75
Step-by-step explanation:
If January corresponds to x=0 then June corresponds to x=5.
Knowing this we can replace all values of x with 5.
[tex]v=x^4-50x^2+700[/tex]
[tex]v=5^4-50(5)^2+700[/tex]
[tex]v=625-1250+700[/tex]
[tex]v=75[/tex]
Which choice is equivalent to the product below? √2 x √5 x √8
A. 16√5
B. 4√20
C. 4√5. <-- correct answer
D. 8√10
[tex]\longrightarrow{\green{ C. \:4 \sqrt{5} }}[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] = \sqrt{2} \times \sqrt{5} \times \sqrt{8} [/tex]
[tex] = \sqrt{2 \times 5 \times 8} [/tex]
[tex] = \sqrt{2 \times 5 \times 2 \times 2 \times 2} [/tex]
[tex] = \sqrt{(2 \times 2) \times (2 \times 2) \times 5} [/tex]
[tex] = \sqrt{ {2}^{2} \times {2}^{2} \times 5} [/tex]
[tex] = \sqrt{ {2}^{2} } \times \sqrt{ {2 }^{2} } \times \sqrt{5} [/tex]
[tex] = 2 \times 2 \sqrt{5} [/tex]
[tex] = 4 \sqrt{5} [/tex]
[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}[/tex]
[tex]\sf Q) \sqrt{2} \times \sqrt{5} \times \sqrt{8}[/tex]
[tex]\sf\implies \sqrt{2 \times 5 \times 8}[/tex]
[tex]\sf\implies \sqrt{2 \times 5 \times 2 \times 2 \times 2}[/tex]
[tex]\sf\implies \sqrt{(2 \times 2) \times (2 \times 2) \times 5}[/tex]
[tex]\sf\implies \sqrt{ {2}^{2} \times {2}^{2} \times 5}[/tex]
[tex]\sf\implies \sqrt{ {2}^{2} } \times \sqrt{ {2 }^{2} } \times \sqrt{5}[/tex]
[tex]\sf\implies 2 \times 2 \sqrt{5}[/tex]
[tex]\sf\implies 4 \sqrt{5}[/tex]
which numbers are the extremes of the proportion shown below [tex]\frac{4}{7} =\frac{20}{35}[/tex]
9514 1404 393
Answer:
4 and 35
Step-by-step explanation:
Written as 4/7 = 20/35, the extremes are the outside numbers: 4 and 35.
So sánh √144 và √169
Answer:
Step-by-step explanation:
√144 < √169
Answcăn169
Step-by-step explanat
ion:cvăn 144
Based on your observations, what conclusion can you draw about the lengths of AB DB AE EC
Answer:
The ratio of AD to DB is equal to the ratio of AE to EC. In other words, the pairs of lengths are proportional.
Step-by-step explanation:
Sample answer from plato
x^{2} -(3+\sqrt{3} )x +\sqrt{3} -2=0
Answer:
[tex]{ \tt{ {x}^{2} -( 3 + \sqrt{3} ) x + \sqrt{3} - 2 = 0}} \\ \\ x = 4.8 \: \: and \: \: - 0.05[/tex]
Find the mode of the data.
Weight (in ounces) of puppies in litter:
17, 15, 19, 18, 17, 16, 22
Mode: [?] oz
Enter
Mode=17
Step-by-step explanation:
Mode is to find the number which reoccurs/keeps on appearing.
Hope this helps u
Question 37 of 55 James buys headphones that cost $10.00. He pays 6% sales tax. How much does he pay for the headphones with tax?
A. $11.60
B. $10.60
C. $12.00
D. $6.00
Find the missing side. Round to the nearest tenth.
A.7.4
B.4.4
C.6.4
D.5.4
Answer:
option D
Step-by-step explanation:
take 39 degree as reference angle
using cos rule
cos 39 = adjacent / hypotenuse
0.77 = x / 7
x = 7*0.77
x = 5.39
x = 5.4
Answer:
D. 5.4
Step-by-step explanation:
Using trigonometric ratio
cos 39 = x/7
cross multiple
x = cos39(7)
x=5.4