Solve for x in these two similar triangles

Answer:

A. 70°

Step-by-step explanation:

There are two ways to solve this problem:

(1) The sum of all the angles of a quadrilateral equals 360°.

The equation for this problem would be:

110° + 110° + 70° + m∠A = 360°

Simplify:

290° + m∠A = 360°

m∠A = 70°

(2) Trapezoid ABCD is an isosceles trapezoid, because m∠B and m∠C, opposite angles of the same base of the trapezoid, are congruent.

Therefore m∠A and m∠D must also be congruent.

m∠A = m∠D = 70°

Answer:

x = 25

Step-by-step explanation:

The angles in a triangle add up to 180°, so we can write an equation to model the situation:

55 + 75 + 2x = 180

Now, we can simplify and solve:

130 + 2x = 180

2x = 50

x = 25

Answer:

x = 25

Step-by-step explanation:

The angles in a triangle add up to 180 degrees.

Using this, create an equation:

55 + 75 + 2x = 180

Solve for x:

55 + 75 + 2x = 180

130 + 2x = 180

2x = 50

x = 25

So, x = 25

Answer:

Barb is correct she won by 10 points

Darius's=480

Barb=490

Answer:

1

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]6\sqrt{20} + 8\sqrt{5} -5\sqrt{45}[/tex]

[tex]12\sqrt{5} + 8\sqrt{5} -15\sqrt{5}[/tex]

[tex]5\sqrt{5}[/tex]

Answer:

Step-by-step explanation:

I imagine that you are simplifying this, since there is nothing else you can do with it. You are in the section in algebra where you're learning how to simplify radicals. ALWAYS think prime factorization when it comes to numbers. For example, the square root of 5...the prime factorization of 5 is simply 5 * 1. So we know that √5 is as simple as it can be. It would benefit us if we could simplify either of the other 2 radicals down to the same radicand so we could add or subtract them.

The prime factorization of 20 is

20--> 5   *   4

                  4--> perfect square (2×2). So the simplification of 6√20 is 6×2√5 which is 12√5.

The prime factorization of 45 is

45--> 5   *   9

                   9--> perfect square (3×3). So the simplification of 5√45 is 5×3√5 which is 15√5.

Put it all together to get

12√5 + 8√5 -15√5 which simplifies to

5√5

Answer:

The population of town A = 18,000

The population of town B = 15,000

The population of town C = 20,000

Step-by-step explanation:

Given;

A:B = 6:5

B:C = 3:4

total population = 53,000

A + B + C = 53,000

[tex]\frac{A}{B} = \frac{6}{5} \\\\A = \frac{6B}{5} \\\\\Also;\\\\\frac{B}{C} = \frac{3}{4} \\\\C = \frac{4B}{3} \\\\then;\\\\\frac{6B}{5} +B+ \frac{4B}{3} = 53,000\\\\multiply \ through \ by \ "15"\\\\18B + 15B + 20B = 795,000\\\\53B = 795,000\\\\B = \frac{795,000}{53} \\\\B = 15,000[/tex]

Now solve for A and C;

[tex]A = \frac{6 \times 15,000}{5} = 18,000\\\\C = \frac{4 \times 15,000}{3} = 20,000[/tex]

Answer:

a. P(x = 5) = 0.24

b. P(x ≥ 6) = 0.43

c. P(x < 4)= 0.14

Step-by-step explanation:

According to the Question,

⇒We use Binomial Probability Formula

[tex]P(X = x ) = \frac{n!}{x!((n-x)! } * p^{x} * (1-p)^{n-x}[/tex]

Where, p=0.52 & n=10

a. The probability that the number of U.S. adults who have very little confidence in newspapers is ​exactly​ five . So, (x=5)

Thus, [tex]P(X = 5 ) = \frac{10!}{5!((10-5)! } * 0.52^{5} * (1-0.52)^{10-5}[/tex]

On Solving Above Equation we get,

P(5)=0.2441 ≈ 0.24

b. The probability that the number of U.S. adults who have very little confidence in newspapers is at least 6 . So, (x≥6)

Then,

P(x≥6) = P(6)+P(7)+P(8)+P(9)+P(10)

P(x≥6) = [tex]\frac{10!}{6!((10-6)! } * 0.52^{6} * (1-0.52)^{10-6}[/tex] + [tex]\frac{10!}{7!((10-7)! } * 0.52^{7} * (1-0.52)^{10-7}[/tex] +[tex]\frac{10!}{8!((10-8)! } * 0.52^{8} * (1-0.52)^{10-8}[/tex] + [tex]\frac{10!}{9!((10-9)! } * 0.52^{9} * (1-0.52)^{10-9}[/tex]+[tex]\frac{10!}{10!((10-10)! } * 0.52^{10} * (1-0.52)^{10-10}[/tex]

On solving above equation we get,

P(x≥6) =  0.4270 ≈ 0.43

c. The probability that the number of U.S. adults who have very little confidence in newspapers is less than 4 . So, (x<4)

Then,

P(x < 4)=P(3) + P(2)+P(1)+P(0)

P(x<4) = [tex]\frac{10!}{3!((10-3)! } * 0.52^{3} * (1-0.52)^{10-3}[/tex] + [tex]\frac{10!}{2!((10-2)! } * 0.52^{2} * (1-0.52)^{10-2}[/tex]+ [tex]\frac{10!}{1!((10-1)! } * 0.52^{1} * (1-0.52)^{10-1}[/tex] + [tex]\frac{10!}{0!((10-0)! } * 0.52^{0} * (1-0.52)^{10-0}[/tex]

On solving we get,

P(x < 4)= 0.1410 ≈ 0.14  

Answer:

D = [tex]\sqrt{\frac{216W}{35L} }[/tex]

Step-by-step explanation:

From the given question, the expression showing the relationship among the weight, length and diameter of the metal bar is;

W [tex]\alpha[/tex] L[tex]D^{2}[/tex]

W = kL[tex]D^{2}[/tex]

where k is the constant of proportionality.

When W = 140, D = 4 and L = 54, then;

140 = k(54)[tex](4)^{2}[/tex]

      = 864k

k = [tex]\frac{140}{864}[/tex]

  = [tex]\frac{35}{216}[/tex]

k = [tex]\frac{35}{216}[/tex]

⇒ W = [tex]\frac{35LD^{2} }{216}[/tex]

So that;

35L[tex]D^{2}[/tex] = 216W

[tex]D^{2}[/tex] = [tex]\frac{216W}{35L}[/tex]

D = [tex]\sqrt{\frac{216W}{35L} }[/tex]

Answer:

9 pounds

Step-by-step explanation:

1 lb = 16 ounces

144/16 = 9 pounds

Answer:

all 3

Step-by-step explanation:

its not right or wrong you can do all 3 if you like

Answer:

Step-by-step explanation:

4/9 on the number line would be 0.44.

-7/9 on the number line would be -0.77

Answer:

175°

Step-by-step explanation:

If angle x = 058° and angle y = 127° then the bearing A from point O is 360 minus angle x plus angle y.

Solution:

360° - (058° + 127°) = 175°

This is because the complete turn from north to north is 360°.

Answer:

489.40 cm³

Step-by-step explanation:

Since the cross section is parallel to their respective bases, hence:

Area of the cylinder cross section = area of the circular base = πr²

where r is the radius of the cylinder base.

Area of other cross section = area of rectangle base = 3.8 cm * 8.1 cm

Since both cross sections have same area, hence:

Area of cylinder cross section = Area of rectangle base

πr² = 8.1 * 3.8

r² = 9.8

r = 3.1 cm

Volume of the cylinder = πr²h = π(3.1)²(15.9) = 489.40 cm³

Answer:

∠ BCD = 111°

Step-by-step explanation:

Since AB = BC then the triangle is isosceles and the 2 base angles are congruent.

∠ ACB = ∠ A = 69°

∠ ACB and ∠ BCD are adjacent angles and sum to 180° , that is

∠ BCD + ∠ ACB = 180°

∠ BCD + 69° = 180° ( subtract 69° from both sides )

∠ BCD = 111°

Answer:

(x + 4)(x + 3)

Step-by-step explanation:

x^2 + 7x + 12

In Quadratic Factorization using Splitting of Middle Term which is x term is the sum of two factors and product equal to last term. Factor each pair by finding common factors.

so we need two number that gives 12 when multiplied and 7 when added

4 and 3 are the numbers because 4*3 = 12 and 4+3 = 12

=x^2 + (4 + 3)x + 12

=x^2 + 4x + 3x + 12

=x(x + 4) + 3(x + 4)

take (x + 4) as common

=(x + 4) (x*1 + 3*1)

=(x + 4)(x + 3)

Step-by-step explanation:

4(2.8*4.5)=50.4

50.4/12= 4.2

4.2 means 5 tins of paint

£52.5 =price

Step-by-step explanation:

i have explained in the paper.

Goodluck

Answer:

A, C are both solutions

Step-by-step explanation:

B will not work because:

-1 = 4(-1/4)² + 4(-1/4) - 1

-1 = 1/4 - 1 - 1

-1 ≠ -1 3/4

D will not work because:

1 = 4(1/4)² + 4(1/4) - 1

1 = 1/4 + 1 - 1

1 ≠ 1/4

Never, B is the middle colinear point so it cant measure longer than AC which is the full line segment.

Answer:

Step-by-step explanation:

That exterior angle is equal to the sum of the remote interiors, specifically:

2x + 3 = 45 + x + 8 and

x = 50

So the angles inside the triangle...we already know one of them is 45. If x = 50, then x + 8 is 50 + 8 = 58. That means that the third angle is 180 - 45 - 58 which is 77.

Answer:

[tex]\text{C. }60[/tex]

Step-by-step explanation:

Question from image:

"The digits 1, 2, 3, 4, and 5 can be formed to arrange 120 different numbers. How many of these numbers will have the digits 1 and 2 in increasing order? For example, 14352 and 51234 are two such numbers."

Let's start by taking a look with the number 1. There are four possible places 1 could be, because there needs to be space for the 2 after it.

Checkmarks mark where the 1 can be, the x marks where it cannot be.

[tex]\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{\checkmark}\:\underline{X}[/tex]

Let's start with the first position:

[tex]\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}\:\underline{\#}[/tex]

There are four places the 2 can be. For each of these four places, we can arrange the remaining 3 digits in [tex]3!=6[/tex] ways. Therefore, there are [tex]4\cdot 6=\boxed{24}[/tex] possible numbers when 1 is the first digit of the number.

Continue this process with the remaining possible positions for 1.

Second position:

[tex]\underline{X}\underline{\checkmark}\:\underline{\#}\:\underline{\#}\:\underline{\#}[/tex]

There are three places the 2 can be, since the 2 must be behind the 1. For each of these three places, the remaining 3 digits can be arranged in [tex]3!=6[/tex] ways. Therefore, there are [tex]3\cdot 6=\boxed{18}[/tex] possible numbers when 1 is the second digit of the number.

The pattern continues. Next there will be 2 places to place the 2. For each of these, there are [tex]3!=6[/tex] ways to rearrange the remaining 3 digits for a total of [tex]2\cdot 6=\boxed{12}[/tex] possible numbers when 1 is the third digit of the number.

Lastly, when 1 is the fourth digit of the number, there is only 1 place the 2 can be. For this one place, there are still [tex]3!=6[/tex] ways to rearrange the remaining three numbers. Therefore, there are [tex]1\cdot 6=\boxed{6}[/tex] possible numbers when 1 is the fourth digit of the number.

Thus, there are [tex]24+18+12+6=\boxed{60}[/tex] numbers that will have the digits 1 and 2 in increasing order, from a set of 120 five-digit numbers created by the digits 1 through 5, where no digit may be repeated.

Answer:

take a break from social media , find a peaceful spot to study ,be engaged , take notes and listen during discussion make use of ur extra time wisely

hope it's helpful

Answer:

D

8x^2-12x+5

thanx for youer sug

Answer:

[tex]8x^2-12x+5[/tex]

Step-by-step explanation:

This is the same as saying h(g(x)). All you do is take the g(x) equation and plug that in for x in the h(x) equation.

h(x) = 4x+1                                           Plug in g(x) equation for x

h(g(x)) = [tex]4(2x^2-3x+1)+1[/tex]                Distribute the 4 and simplify

h(g(x)) = [tex]8x^2-12x+5[/tex]  

Answer:

7/5 is the scale factor

Step-by-step explanation:

Answer:

I don't know.

Answer:

It's (-3, -2)

I did the math, don't worry

Hope this helps

Answer:

£21

€28 = £21

Answer:

59 is prime ... 1 & 59 are the only factors

Step-by-step explanation: