Answer:
[tex] \boxed{ \boxed{ \bold{A = 4}}}[/tex]Explanation:
Given,
F = 100 , M = 25
Now, let's find the value of A
[tex] \sf{F = MA}[/tex]
plug the values
⇒[tex] \sf{100 = 25 A}[/tex]
Swap the sides of the equation
⇒[tex] \sf{25A = 100}[/tex]
Divide both sides of the equation by 25
⇒[tex] \sf{ \frac{25A}{25} = \frac{100}{25} }[/tex]
Calculate
⇒[tex] \sf{A = 4}[/tex]
Hope I helped!
Best regards!!
Given:-
Force,F = 100 NMass,m = 25 kgTo find out:-
Calculate the acceleration, a ?
Formula applied:-
F = m × a
Solution:-
We know,
[tex] \sf{F = m × a}[/tex]
Substituting the values of mass and acceleration,we get
[tex] \sf\implies \: 100 = 25 \times a[/tex]
[tex] \sf \implies a = \cancel \dfrac{100}{25} [/tex]
[tex] \sf \implies a = 4 \: ms {}^{ - 1} [/tex]
A spaceship far from all other objects uses its impulse power system to attain a speed of 104 m/s. The crew then shuts off the power. According to Newton's first law, what will happen to the motion of the spaceship from then on
Answer:
The spaceship will travel in a straight line at constant speed.
Explanation:
According to the Newton's First Law, the spaceship will have an uniform motion in a straight line, that is, the spaceship will travel in a straight line at constant speed.
The spaceship will travel in a straight line at constant speed.
Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.By applying Newton's First Law, when the spaceship attain a speed of 104 m/s . Then, spaceship will have an uniform motion in a straight line.
Hence, the spaceship will travel in a straight line at constant speed.
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a telescope is oriting on a spacecraft aroudn the earth. Speed of 3.25 x 10^5 mass 7500 kg. What is the de Broglie wavelength of the telescope. g
Answer:
2.72 x 10^-43 m
Explanation:
mass of the telescope = 7500 kg
speed of the telescope = 3.25 x 10^5 m/s
de Broglie's wavelength of the telescope is given as
λ = h/mv
where
λ is the wavelength of the telescope
h is the plank's constant = 6.63 × 10-34 m^2 kg/s
m is the mass of the telescope = 7500 kg
v is speed of the telescope = 3.25 x 10^5 m/s
substituting value, we have
λ = (6.63 × 10-34)/(7500 x 3.25 x 10^5)
λ = 2.72 x 10^-43 m
Assume that Earth is in circular orbit around the Sun with kinetic energy K and potential energy U, taken to be zero for infinite separation. Then, the relationship between K and U:
Answer:
K= -U/2
Explanation:
We know that K.E = 1/2mv²
And -GMm/r²= mv²/r
Thus K,E= 1/2(GMm/r)= 1/2(-P.E)
So
P.E = - GMm/r
So K= -U/2
A soft drink (mostly water) flows in a pipe at a beverage plant with a mass flow rate that would fill 220 0.355 - L cans per minute. At point 2 in the pipe, the gauge pressure is 152kPa and the cross-sectional area is 8.00cm2. At point 1, 1.35m above point 2, the cross-sectional area is 2.00cm2.
a. Find the mass flow rate.
b. Find the volume flow rate.
c. Find the flow speed at point 1.
d. Find the flow speed at point 2.
e. Find the gauge pressure at point
Answer:
A. To find the mass flow rate.
We use= 220 x 0.355/ 60
= 1.3kg/s
B. Volume flowrate is = mass flowrate / density
But density is 1000kg/m³
= 1.3kg/s/ 1000kg/m³
= 0.0013m³/s
C. Flow speead at 1
= 0.0013m³/s / (2 x 10-2m)²
= 6.5m/s
D.flow speed at 2
0.0013m³/s / (8x 10-2m)²
=1.63m/s
E. Gauge pressure at point 1
= 152+ 1/1000 ( 1.63)²- 6.5² + 1000( 9.8) ( 0-1.35)
= 119kpa
An electron and a proton are each accelerated from rest through a potential difference of 100 V. Afterward, which particle has the larger de Broglie wavelength?
Explanation:
The De-Broglie wavelength in terms of potential difference is given by:
[tex]\lambda=\dfrac{h}{\sqrt{2meV} }[/tex]
Where,
h is Planck's constant
m is mass of charged particle
V is potential difference
e is the amount of charge
It means that the De-Broglie wavelength is inversely proportional to the mass.
Since, the mass of the proton is more than the mass of the electron. So, the De- Broglie wavelength of the electron is larger than proton.
A ball rolls down a roof that makes an angle of 30.0 degrees to the horizontal. It rolls off the edge of the roof with a speed of 5.00 meters per second. The distance straight down to the ground from the edge of the roof is 7.00 meters. a) How long is the ball in the air
Answer:
0.97s
Explanation:
First of all solving the second equation of motion in the vertical direction we have
Vy= Vosinစ
= 5m x sin 30= 2.5m/s
So solving for t time in second equation of motion we will have
t= - Vy +or- √(Vy²- 4{g/2)- h)/ (2g/2)
Substituting 7m for h
We have
t = -2.5+or- √ 2.5²-4(4.9)-7/9.3
We have
t= 0.97s as the positive rational answer
An air track glider is attached to a spring. The glider is pulled to the right and released from rest at t=0 seconds. It then oscillates with a period of 2.40s and a maximum speed of 30.0 cm/s. What is the glider's position at t=0.300s?
Answer:
The glider's position at t=0.300s is 8.1 cm
Explanation:
Given;
maximum speed of the glider, [tex]v_{max}[/tex] = 30.0 cm/s = 0.3 m/s
period of the oscillation, T = 2.4 s
Maximum speed of oscillation is given by;
[tex]v_{max}[/tex] = ωA
Where;
A is the amplitude of the oscillation
ω is the angular speed
[tex]\omega = \frac{2\pi}{T} \\\\\omega =\frac{2\pi}{2.4}\\\\ \omega = 0.833 \pi[/tex]
The amplitude of the oscillation is given by;
[tex]A = \frac{v_{max}}{\omega} \\\\ A = \frac{0.3}{0.833\pi}\\\\ A = 0.1146 \ m[/tex]
The position of the particle is given by;
x(t) = A cosωt
x(0.3) = (0.1146)cos(0.833π x 0.3)
x(0.3) = (0.1146)cos(0.833π x 0.3)
x(0.3) = (0.1146)cos(45)
x(0.3) = 0.081 m
x(0.3) = 8.1 cm
Therefore, the glider's position at t=0.300s is 8.1 cm
PLEASE HELP WITH PHYSICS HOMEWORK ASAP
A radio wave transmits 34.5 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagation of the wave. Assuming the surface is a perfect absorber, calculate the radiation pressure on it.
Answer:
1.15*10^-7 N/m²
Explanation:
Radiation pressure is the pressure exerted on any surface, as a result of the exchange of momentum between the object and its electromagnetic field.
The formula to calculate radiation pressure on a perfect absorber is
P = s/c, where
P = radiation pressure
s = intensity of light
c = speed of light
Now, on substituting the values and plugging it into the equation, we have
P = 34.5 / 3*10^8
P = 1.15*10^-7 N/m²
therefore, radiation pressure is found to be 1.15*10^-7 N/m²
If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.
Answer:
The radius is [tex]R = 0.22 5 \ m[/tex]
Explanation:
From the question we are told that
The current is [tex]I = 61 \ A[/tex]
The magnetic field is [tex]B = 1.70 *10^{-4} \ T[/tex]
Generally the magnetic field produced by a current carrying conductor is mathematically represented as
[tex]B = \frac{\mu_o * I}{2 * R }[/tex]
=> [tex]R = \frac{\mu_o * I }{ 2 * B }[/tex]
Here [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]
=> [tex]R = \frac{ 4\pi * 10^{-7} * 61 }{ 2 * 1.70 *10^{-4} }[/tex]
=> [tex]R = 0.22 5 \ m[/tex]
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweezers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth.
Required:
a. What is the pressure on an atom if light from the tweezers is totally absorbed? ?
b. If this pressure were exerted on a tritium atom, what would be its acceleration?
Answer:
Explanation:
a )
If it is totally absorbed pressure is calculated as follows .
Pressure = I / c where I is intensity of light falling .
= 1000 / 3 x 10⁸
= 3.33 x 10⁻⁶ N / m²
b ) weight of tritium atom
= 3 x 1.67 x 10⁻²⁷ kg
acceleration = force / mass
= 3.33x 10⁻⁶ / 3 x 1.67 x 10⁻²⁷
= .6646 x 10²¹ m /s²
= 66.46 x 10¹⁹ m / s²
Multiply the number 4.48E-8 by 5.2E-4 using Google. What is the correct answer in scientific notation?
Answer:
[tex]2.32\times 10^{-11}[/tex]
Explanation:
First number is [tex]4.48\times 10^{-8}[/tex]
Second number is [tex]5.2\times 10^{-4}[/tex]
We need to multiply the two numbers.
[tex]4.48\times 10^{-8}\times 5.2\times 10^{-4}=(4.48\times 5.2)\times 10^{(-8-4)}\\\\=23.296\times 10^{-12}[/tex]
In scientific notation : [tex]2.32\times 10^{-11}[/tex]
Hence, this is the required solution.
For each statement about the nuclear force select True or False. In nuclei, it is stronger than the Coulomb force. It acts between a proton and an electron. Its strength goes as 1/distance2, like gravity. It acts between a proton and a neutron. It acts between an electron and a neutron. It acts between two neutrons and also between two protons.
Answer:
a) True. The Strong interaction is the strong Coulomb force
e) True. It acts between protons, neutrons and between a proton and a neutron
Explanation:
In this exercise you must answer if there are some statements about the nuclei, let's write some of their characteristics
* at the core there is an attractive force called Strong Interaction
* This interaction acts on protons and neutrons alike
* There is a Coulombian-type repulsive force that acts between protons.
Let's review the claims
a) True. The Strong interaction is the strong Coulomb force
b) False. It acts on the elements of the nucleus and here there are no electrons
c) False. It is much greater than gravity and generally described by an exponential
d) False. It acts between components of the nucleus and here there are no electrons
e) True. It acts between protons, neutrons and between a proton and a neutron
Which of the following statements about electromagnetic radiation is true?
A) It always travels at 3Ã108 m/s.
B) It consists of perpendicularly oscillating electric and magnetic fields, and the direction of propagation is perpendicular to both.
C) It consists of oscillating electric and magnetic fields that are parallel to one another and perpendicular to the direction of propagation.
D) The oscillating electric and magnetic fields are completely out of phase with one another
Answer:
The correct option is B: It consists of perpendicularly oscillating electric and magnetic fields, and the direction of propagation is perpendicular to both.
Explanation:
Electromagnetic radiation travels at the speed of light (c = 3x10⁸ m/s) only in a vacuum. In another propagation medium, the speed of electromagnetic radiation is less than c.
The oscillations of the waves of the electric and magnetic fields are perpendicular to each other, and the direction of propagation is also perpendicular to the two fields.
From all of the above, the correct option is B: It consists of perpendicularly oscillating electric and magnetic fields, and the direction of propagation is perpendicular to both.
I hope it helps you!
The true statement regarding electromagnetic radiation should be option B where it comprises of perpendicularly oscillating electric and magnetic fields.
What is electromagnetic radiation?It should be traveled when the speed of light i.e. (c = 3x10⁸ m/s) should be a vacuum. For the propagation medium, the speed with respect to the electromagnetic radiation should be lower than c. Also, the oscillations of the electric waves and the magnetic field should be perpendicular also the direction should be perpendicular
Hence, the option b is correct.
Learn more about radiation here: https://brainly.com/question/24301101
If we ignore air resistance, a falling body will fall 16t2 feet in t seconds. What is the average velocity between t
Answer:
262.4 m/s
Explanation:
The complete question is
If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.
The distance fallen s = 16t^2
The velocity v = [tex]\frac{ds}{dt}[/tex] = 32t
If we substitute the values of t into the velocity v, we'll have
at t = 8 s, V1 = 32 x 8 = 256 m/s
at t = 8.4 s, V2 = 32 x 8.4 = 268.8 m/s
Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = 262.4 m/s
How do you recognise a chemical
A thin, light wire 75.1 cm long having a circular cross section 0.555 mm in diameter has a 25.4 kg weight attached to it, causing it to stretch by 1.10 mm.
A) what is the stress of the wire.
B) what is the strain in the wire.
C) find the Young Modulus for the material of the wire.
Answer:
(a) 3.23×10⁸ N/m²
(b) 1.46×10⁻³
(c) 2.21×10¹¹ N/m²
Explanation:
(a) Stress = Force/Area.
Stress = F/A................ Equation 1
But,
F = mg................. Equation 2
Where m = mass, and g = acceleration due to gravity
A = πd²/4................. Equation 3
d = diameter of the circular cross section.
Substitute equation 2 and equation 3 into equation 1
Stress = 4mg/πd²............. Equation 4
Given: m = 25.4 kg, d = 0.555 mm = 0.000555 m
Constant: g = 9.8 m/s², π = 3.142
Substitute these values into equation 4
Stress = 4(25.4)(9.8)/(3.142×0.00555²)
Stress = 995.68/(3.08×10⁻⁶)
Stress = 3.23×10⁸ N/m²
(b)
Strain = ΔL/L.............. Equation 5
Where ΔL = extension, L = Length.
Given: ΔL = 1.1 mm = 0.0011 m, L = 75.1 cm = 0.751 m
Substitute into equation 5
Strain = 0.0011/0.751
Strain = 1.46×10⁻³.
(c)
Young modulus = Stress/Strain
Young modulus = 3.23×10⁸/ 1.46×10⁻³
Young modulus = 2.21×10¹¹ N/m²
in a closed energy system, energy is?
Answer:
Explanation:
A closed system can exchange energy but not matter, with its surroundings. An isolated system cannot exchange any heat, work, or matter with the surroundings, while an open system can exchange energy and matter.
Hope this helped you!
Describe an experiment to show that the pressure in a liquid increases with depth.
Answer:
Explanation:
Water pressure is the result of the weight of all the water above pushing down on the water below. As you go deeper into a body of water, there is more water above, and therefore a greater weight pushing down. This is the reason water pressure increases with depth.
What is the best use of an atomic model to explain the charge of the particles in Thomson’s beams?
Answer:
The interpretation of the subject in question is characterized in the discussion section below.
Explanation:
The atom seems to be the smallest particle of negatively charged electrons as well as positive. The negative particulates are comparatively small, as well as distant from both the considerably high beneficial particles. When the negative objects traveled away from the desired ones those who formed an intangible beam which was electrically charged.Thomson would use a closed glass globe with just a single positive and another negative electrode with extraordinarily low present pressure. He was forced to submit those other gases to quite a voltage level, and also that the rise in popularity of emission levels, which have been called cathode rays, must have been observed.As the negatives shifted away from those in the positives, an imaginary electrically conductive beam was formed. Not only that but the negative particles have been completely circumvented due to the extreme distance seen between positively and negatively particle size.Which contains the most moles: 10 g of hydrogen gas, 100 g of carbon, or 50 g of lead?
Answer:
Carbon
Explanation:
We know that
Number of moles = mass/molecular mass
So
Hydrogen: given as H2 with 10g an atomic number of 1 so MW( 1x 2= 2)
Number of moles = Weight/MW
= 10/2
= 5
Carbon: atomic number 12 C and mass 100
Number of moles = Weight/MW
= 100/12
= 8.33
Lead: atomic num 207 and mW 207 pb
Number of moles = Weight/MW
= 50/207
= 0.241
Therefore Carbon has the most moles.
An object has a mass of 120 kg on the moon what is the force of gravity acting on the object on the moon
Answer: i think it is An object has a mass of 120 kg on the Moon. The force of gravity acting on the object on the Moon is 196 N. Sol'n: force = mass * gravity; gravity on the moon is 1/6 that on the Earth = 9.807*(1/6)=1.6345; f = m*g; f = 120*1.6345 =196.14.
Explanation:
Answer:
Hey there!
W=mg, where m is the mass and g is the acceleration of gravity.
The acceleration of g on the moon is about 1.622 m/s^2, so plugging that in as a value gives us W, the force is equal to approximately 197 Newtons.
Let me know if this helps :)
Waves on a String: The speed of sound in steel is 5000 m/s. What is the wavelength of a sound wave of frequency 660 Hz in steel
Answer:
The wavelength of the sound wave is 7.58 m
Explanation:
Given;
speed of wave in steel, v = 5000 m/s
frequency of the wave in steel, f = 660 Hz
The wavelength of a sound wave is given by;
λ = v / f
where;
v is the speed of sound wave in steel
f is the frequency of sound wave in steel
λ is the wavelength of the sound wave in steel
λ = 5000 / 660
λ = 7.58 m
Therefore, the wavelength of the sound wave is 7.58 m
If you have two substances, one with a density of 2.0 g/cm3 and one with a density of 1.3 g/cm3 and you combined them, which one would float on top
other and why?
Explanation:
Assuming the substances are fluids that do not mix, the lighter substance (ρ = 1.3 g/cm³) will float on top of the heavier substance (ρ = 2.0 g/cm³). This is due to Archimedes' Principle, which explains buoyancy.
88. A child pulls a cart to the left along a rough surface. Which one of the free body diagrams correctly depicts all the forces acting on the carrito?
Answer:
Eje x
fr- F = m a
eje y
N-W =0
Explanation:
Para este ejercicio, debemos usar la segunda ley de Newton, donde se necesita fija un sistema de referencia el mas usado es un sistema horizontal y vertical para los ejes x e y
en el adjunto puede ver el diagrama de cuerpo libre correcto,
las fuerza son
Eje x
fr- F = m a
eje y
N-W =0
la ecuacion para la fuerza de roce es
fr = my N
hi guys this is my last points and i need some answers :)
1. what is a runoff?
A. A type of precipitation that falls as a mixture of ice and snow B.The water on the surface that soaks deep into the ground C.Tiny droplets of water that condense to form clouds D.Water that moves along the surface of Earth into the oceans
NEXT QUESTION
2.Which statement about oceans is incorrect?
A.Evaporation occurs when water is warmed by the sun.
B.Most evaporation and precipitation occur over the ocean.
C.97 percent of Earth's water is fresh water from the ocean.
D.Water leaves the ocean by the process of evaporation.
Answer:
Number 1: B Number 2: D
Explanation:
Answer:
Hello! Your answer would be D) for one and C) for two.
Explanation:
Run off is when water runs of of things into lakes oceans etc.
So with number two it would be C because not even 3% of our water is fresh.
Represent a vector of 100 N in North-East direction
Answer:
N 100N E
Explanation:
Check image uploaded for the solution
What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1 15 the speed of light
Answer:
Te wavelength is 3.66 x 10^-11 m
Explanation:
Question is
What is the de Broglie wavelength of an electron that strikes the back of the face of a TV screen at 1/15 the speed of light.
De Broglie's wavelength is gotten as
λ = h/mv
where
λ is the wavelength of the electron
h is the Planck's constant = 6.67 x 10^-34 J-s
m is the mass of an an electron = 9.109 x 10^-31 kg
v is the speed of the electron.
The speed of the electron is given as 1/15 of the speed of light
Speed of electron = 1/15 of 3 x 10^8 = 2.0 x 10^7 m/s
substituting values, we have
λ = (6.67 x 10^-34)/(9.109 x 10^-31)x(2.0 x 10^7) = 3.66 x 10^-11 m
Vittorio needs to clean the dusty mirror hanging on the wall beforehe can use it, but he would like to clean as little of the mirroras possible.
Vittorio would like to be able to see the logo on his shirt.Draw the incident and reflected raysshowing the light from the logo reflecting off the mirror into hiseyes. The rays should meet at the point on the mirror that needscleaning.
Answer:
The drawing is attached below.
Explanation:
According to the drawing, we can see that the point "0" marked on the mirror, is the point that allows the formation of an angle between Vittorio's eyes and the place where his shirt logo is. In summary, the point on the mirror that needs to be cleaned, so that Vittorio can see only the logo of his shirt, is the point that represents equal vertical distances between Vittorio's eyes and the shirt's logo, since these distances present the same angle.
A 50 kg laboratory worker is exposed to 30 mJ of neutron radiation with an RBE of 10. Part A What is the dose in mSv
Answer:
The dose is 6 mSV
Explanation:
The absorbed dose (in gray - Gy) is the amount of energy that ionizing radiation deposits per unit mass of tissue. That is,
Absorbed dose = Energy deposited / Mass
while Dose equivalent (DE) (in Seivert -Sv) is given by
DE = Absorbed dose × RBE (Relative biological effectiveness)
First, we will determine the Absorbed dose
From the question, Energy deposited = 30mJ and Mass = 50kg
From,
Absorbed dose = Energy deposited / Mass
Absorbed dose = 30mJ/50kg
Absorbed dose = 0.6 mGy
Now, for the Dose equivalent (DE)
DE = Absorbed dose × RBE
From the question, RBE = 10
Hence,
DE = 0.6mGy × 10
DE = 6 mSv
The dose will be 6 mSv. The absorbed dose (in gray - Gy) is the amount of energy that ionizing radiation deposits per unit mass of tissue.
What is the dose?A unit is a measurable quantity of a drug, vitamin, or pathogen provided in a single dose. A medication's dosage form is a blend of active and inactive ingredients used to give it.
The given devotion is;
[tex]D_a=[/tex]Absorbed dose
[tex]\rm E_D[/tex] = energy deposited
[tex]\rm D_E[/tex] is the dose equivalent
RBE= Relative biological effectiveness
The absorbed dose is found as;
[tex]\rm D_a = \frac{E_d}{m}\\\\ D_a = \frac{30 \ mJ}{50}\\\\ \rm D_a = 0.6 \ mGy[/tex]
The dose equivalent is found as;
[tex]\rm D_E=D_A \times RBE \\\\ D_E=0.6 \times 10 \\\\ \rm D_E=6 mSV[/tex]
Hence the dose will be 6 mSv.
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