Solid sodium reacts with liquid water to form hydrogen gas according to the equation 2 Na(s) + 2 H₂O(l) → 2 NaOH(aq) + H₂(g) What is the pressure of hydrogen gas in the 20.0 L headspace of a reactor vessel when 3.34 kg sodium is reacted with excess water at 50.0°C?

Answer:

Amount of water in mL = 1.75⁹ × 10 ml (Approx)

Explanation:

Given:

Length of pool = 34 m

Width of pool = 31 m

Height of pool = 4.98 ft

Find:

Amount of water in mL

Computation:

1 ft = 0.3048 m

Height of pool = 4.98 (0.3048)

Height of pool = 1.5179 m

Volume of pool = (34)(31)(1.5179)

Volume of pool = 1,754.70 m³

1 m³ = 10⁶ ml

Amount of water in mL = 1,754.70 × 10⁶ ml

Amount of water in mL = 1.75⁹ × 10 ml (Approx)

Answer:

From the most resources to the least, it is 3, 4, 2, 1.

Explanation:

Pork is a large animal but not as much as a cow but it also does not produce as much meat as a cow. In terms of land required and total meat produced, pork is the highest on this list so it is option B.

The most amount of land and resources are taken up by cows, but they also produce a lot more meat than porks so they are in the second place on this list.

Chickens require a small amount of space but produce little meat.

If we guess that each egg weighs 60 grams, 1 kg of eggs equals to almost 17 eggs which a single chicken can produce easily. So the eggs require the least resources which means that they are option A.

I hope this answer helps.

Answer:

Option C:

1s2 2s2 2p6 3s1 3p4

Explanation:

At a ground level, Phosphorous has an electronic configuration of 1s2 2s2 2p6 3s2 3p3 (using the spdf notation).

Once the atom becomes excited, an electron from the 3s sub-level will gain energy and jump over to the 3p sub-level, making the configuration 1s2 2s2 2p6 3s1 3p4.

The number of electrons at the 3p sub-level will now become 4 because of the addition of the new electron while the number of atoms at the 3S sub-level will reduce to 1 because an electron left this sub-level.

The question is incomplete, the complete question is;

Consider the following reaction at 298K.

2 H+(aq) + 2 Cr2+(aq) =H2(g) + 2 Cr3+(aq)

Which of the following statements are correct?

Choose all that apply.

K > 1

ΔGo < 0

Eocell < 0

n = 2 mol electrons

The reaction is reactant-favored.

Answer:

K > 1

ΔGo < 0

n = 2 mol electrons

Explanation:

If we look at the reaction; 2 H+(aq) + 2 Cr2+(aq) -----> H2(g) + 2 Cr3+(aq), we will notice that the reaction is a spontaneous reaction because E°cell= 0-(-0.41) = 0.41 V

If the reaction is a spontaneous electrochemical process, we expect it to be product favoured with K>1. Also, a spontaneous reaction must have ∆G<0.

Lastly, we can see that two electrons were transferred according to the balanced equation for the electrochemical reaction.

Answer:

[tex]m=406.26g[/tex]

Explanation:

Hello,

In this case, since the density is defined as the degree of compactness of a substance and it mathematically defined as the ratio of the mass and volume:

[tex]\rho = \frac{m}{V}[/tex]

By knowing that its density is 1.11 g/mL, the mass in 366 mL is:

[tex]m=\rho V=366mL*1.11\frac{g}{mL}\\ \\m=406.26g[/tex]

Regards.

Answer:

37.1 mL

Explanation:

To accurately read the measurement using a cylinder, we read the measurement at the meniscus i.e measurement under the curve as shown in the diagram above.

The meniscus i.e the measurement under the curve as shown above is 37.1 mL.

Therefore, the volume of the liquid as obtained from the cylinder is 37.1 mL

Answer:

37.1 ml

Explanation:

a graduated cylinder's measurement is taken at the bottom of the meniscus

Answer:

option a. Temperature is equal to 273 k. Is the correct one

A boils when its vapour pressure is equal to, or greater than, the external pressure pushing on it. Therefore, option (b) is correct.

A boiling point of a liquid can be defined as the temperature at which the vapour pressure becomes equal to the atmospheric pressure of the liquid. The liquid is converted into a vapour at this temperature.

With the addition of heat that the liquid changes into vapour without any increase in temperature. The vapour pressure increases until it is equal to the pressure of the gas surrounding it as a liquid is heated. Bubbles of vaporized liquid are formed within the liquid and rise to the surface.

At the boiling temperature, the vapour inside the bubble will exert enough pressure to prevent the bubble from collapsing. The molecules of a liquid will able to overcome the forces of attraction between molecules to create vapour.

Therefore, at boiling point, the vapour pressure is equal to, or greater than, the external pressure pushing on it.

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Answer:

[tex]Q=108.55kJ[/tex]

Explanation:

Hello,

In this case, we can compute the required heat by using the following equation:

[tex]Q=mCp(T_2-T_1)[/tex]

Thus, by considering the given mass, specific heat and both initial and final temperature, we obtain:

[tex]Q=500g*1.67\frac{J}{g\°C} *(150.0\°C-20.0\°C)*\frac{1kJ}{1000J} \\\\Q=108.55kJ[/tex]

Regards.

Answer:

The correct answer is 84.81 °C.

Explanation:

Based on the given information, the volume or mass of coffee is 250 ml, and the mass of metal spoon is 80 grams. The specific heat capacity of metal spoon is 0.80 J/g °C, and the specific heat capacity of coffee is 4.18 J/g °C. In the given case, heat is lost from the coffee and is gained by the spoon.  

For finding the final temperature of the coffee, the formula to be used is Q = msΔT, here m is the mass, s is the specific heat, and ΔT is the change in temperature.  

Heat lost from the coffee = Heat gained by the spoon

250 × 4.18 (90 - T2) = 80 × 0.8 (T2 - 0)

1045 (90 - T2) = 64 (T2 -0)

94050 - 1045 T2 = 64 T2

94050 = 1045 T2 + 64 T2

94050 = 1109 T2

T2 = 84.84 °C

Answer:

B. Colloid

Explanation:

Colloid is a mixture that is made up of very small homogeneous particles, thus can not be separated into fractions. Its particles do not settle as other solution, but are evenly dispersed in the medium. Some examples are: liquid milk, jelly, rubber etc

Since colloid is a solution, thus it is made up of two parts; its particles and dispersing medium.

Answer:

See figure 1

Explanation:

For this question, we can analyze each molecule:

-) (E)-5-Methyl-2-hexene

In this case, we have a carbon chain of 6 carbons. We have a double bond between carbons 3 and 2. Also, we have a methyl group is placed on carbon 5. Finally, the "E" configuration makes reference to the double bond,  the groups on each side of the double bond must have an opposite configuration.

-) 2,5-Diethyl-1-methylcyclohexanol

In this molecule, we have a carbon chain of 2 carbons. In carbon 2 we have two chlorine atoms. In carbon 1 we have a fluorine atom and a chlorine atom. The "S" configuration makes reference to carbon 1 (the chiral carbon), so we have to assign the priorities for each group bonded to carbon 1:

1 = Chlorine

2 = Fluorine

3 = Carbon 2

4 = Hydrogen

If we need an "S" configuration the priorities must be placed in such a way that we have a counterclockwise orientation.

-) 2,5-Diethyl-1-methylcyclohexanol

In this molecule, we have a cyclic carbon chain of 6 carbons. In carbon 1 we have an "OH" group and a methyl group. In carbon s 2 and 5, we have ethyl groups.

See figure 1

I hope it helps!

Answer:

[tex]1.53~moles~CH_2Cl_2[/tex].

Explanation:

We can start with the reaction, if we know the formula for each compound:

-) Methane: [tex]CH_4[/tex]

-) Carbon tetrachloride: [tex]CCl_4[/tex]

-) Dichloromethane: [tex]CH_2Cl_2[/tex]

With this in mind, we can write the reaction:

[tex]CH_4~+~CCl_4~->~CH_2Cl_2[/tex]

Now, we can balance the reaction:

[tex]CH_4~+~CCl_4~->~2CH_2Cl_2[/tex]

After this, we have 2 carbon atoms on each side, 4 hydrogen atom on each side, and 4 chlorine atoms on each side.

If we want to know how many moles of [tex]CH_2Cl_2[/tex] would be produced with .766 moles of [tex]CH_4[/tex], we have to check the balanced reaction and use the molar ratio. In this case, the molar ratio is 1 mol [tex]CH_4[/tex] will produce 2 moles of [tex]CH_2Cl_2[/tex] (1:2). So:

[tex]0.766~moles~CH_4\frac{2~moles~CH_2Cl_2}{1~mol~CH_4}=1.53~moles~CH_2Cl_2[/tex]

We wil have [tex]1.53~moles~CH_2Cl_2[/tex].

I hope it helps!

Answer:

Hey!I think I can help....

Simple Distillation cannot be used to separate a mixture of two or more miscible liquids Fractional Distillation is used to separate such a mixture into its component parts or fractions. The fractions distil over in ascending order of their boiling points,starting with the fraction with the lowest boiling points. For efficient fractional distillation,the difference in the boiling points between successive fractions must be more than 10°C.In the laboratory,the apparatus for fractional distillation is same as the apparatus for simple distillation, except that a fractioning column is introduced between the distillation flask and the condenser.The fractionating column is packed with glass beads,and does the actual separation. The upper part of the column is at a lower temperature than the lower part .Only the vapour with the same temperature as the upper part of the fractionating column passes on the condenser.(This is the fraction with the lowest boiling point)Vapours with higher boiling points condense as they enter the upper part of the fractionating column and the flow back into the distillation flask.This process is repeated until the fraction with the lowest boiling point is distilled over completely. Then,the temperature in the upper part of yhe column rises until the boiling point of the next fraction is reached. This fraction then starts distilling over.The fractional distillation process continues until Al the component fractions in the mixture distil over.Crude oil or petroleum contains many important natural products such as petrol,kerosene,diesel, heavey oil,natural gases and bitumen.Each of these products can be recovered in its pure form by fractional distillation. The fractional distillation plant is made up of two maim parts----boiler,where the crude oil is kept boiling, and the fractionating tower,where yhe actual separation takes place.The fractions with the lower boiling points will emerge near the top part of the tower while those with higher boiling points will come out near the lower part of the tower..... Thank you for the question, I hope it helps you...Thank you.

Answer:

The correct answer is 0.058

Step-by-step explanation:

The mole fraction of KI (X) in the solution is the number of moles of KI divided into the total number of moles of the solution (nt):

X= moles KI/nt

First we have to calculate the molecular weights of the components of the solution: KI and water (H₂O):

Molecular weight (Mw) of KI:

Mw(KI)= 39 g/mol + 127 g/mol = 166 g/mol

Molecular weight of H₂O:

Mw(H₂O)= (1 g/mol x 2) + 16 g/mol = 18 g/mol

Then, we calculate the number of moles there is of each component in the solution by dividing the mass into Mw:

Moles of KI= mass KI/Mw(KI) = 3.4 g/166 g/mol = 0.020 mol KI

Moles of H₂O= mass H₂O/Mw(H₂O)= 5.8 g/18 g/mol = 0.322 mol H₂O

Thus, the total moles of solution will be:

nt= moles KI + moles H₂O= 0.020 mol + 0.322 mol = 0.342 mol

Finally, we divide the moles of KI into the total moles of solution (nt) to obtain the mole fraction (X):

X= moles KI/nt = 0.020 mol/0.342 mol = 0.058

Answer:

1. HEAT OF SOLUTION IS 1149.47 J

2. HEAT OF SOLUTION PER MOLE OF NaOH IS 41989.77 J/MOL OR 41.989 KJ/MOL

3. THE REACTION IS EXOTHERMIC

Explanation:

Mass of water = 150 g

Mass of NaOH = 1.095 g

Change in temperature = 25.32 - 23.50 = 1.82 C

Total mass of the mixture = 150 + 1.095 = 151.095 g

Specific heat capacity of water = 4.18 J/ g C

So to calculate the heat of solution, we have:

1. Heat of solution = mass * specific heat * change in temperature

Heat of solution = 151.095 * 4.18 * 1.82

Heat of solution = 1149.47 J

The heat of solution is therefore 1149.47 J or 1.15 kJ

2. Heat of solution per mole

1.095 g of NaOH produces 1149.47 J of heat

1 mole of NaOH contains 40 g

In other words:

1.095 g = 1149.47 J

40 g = x J

xJ = 40 * 1149.47 / 1.095

xJ = -41989.77 J

The heat of solution per mole of NaOH is -41.989 kJ / mol

3. The reaction is exothermic that is heat is evolved from the reaction. This is indicated by the negative sign.

Answer:

NHCOR

Explanation:

In electrophilic aromatic substitution, certain substituents on the aromatic ring such as

-NHCOR are known to enhance ortho-para substitution. These ortho-para activating groups stabilizes the intermediate cation.

These ortho-para activating groups usually consists of species that donate electron density towards the reaction centre thereby stabilizing the carbocation and making the reaction faster.

Answer:

90%

Explanation:

it will be 81/90 ×100/1

81 over 90 × 100 over 1

Answer:

Cu(NO3)2(aq)+Pb(s) ⇌ Pb(NO3)2(aq)+Cu(s)

Explanation:

If we look at the both reactions closely, we will quickly discover that the reaction CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) involves PbSO4.

The compound PbSO4 is insoluble in water and sinks to the bottom of the reaction vessel. When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.

On the other hand, Pb(NO3)2 is soluble in water hence the cell voltage in this case is higher than the former.

In the case when we look at both reactions so here we discovered that the reaction of

CuSO4(aq)+Pb(s) ⇌ PbSO4(s)+Cu(s) includes PbSO4.

The compound PbSO4 should be insoluble in water and sinks to the bottom of the reaction vessel. At the time When this occurs, the concentration of Pb^2+ becomes low. This will bring about a low voltage in the cell.

On the other hand, Pb(NO3)2 is soluble in water so the cell voltage in this case is more than the former.

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Answer: [tex]T_{f}[/tex] = -29.96 °C

Explanation: A solution has a lower freezing point compared to the pure solvent, due to the solute lowering the vapor pressure of the solvent.

The "new" freezing point is calculated as:

[tex]\Delta T_{f} = K_{f}.m[/tex]

[tex]K_{f}[/tex] is the molal freezing-point depression constant

m is molality concentration, i.e., moles of solute per kilogram of solvent

Before calculating freezing point, let's find moles of ethylene glycol ([tex]C_{2}H_{6}O_{2}[/tex]) in the solution:

Molar mass [tex]C_{2}H_{6}O_{2}[/tex] = 62.08 g/mol

For 500 g:

[tex]n = \frac{500}{62.08}[/tex]

n = 8.05 moles

The molality concentration for 0.5kg of water:

m = [tex]\frac{8.05}{0.5}[/tex]

m = 16.11

The freezing point will be:

[tex]\Delta T_{f} = K_{f}.m[/tex]

[tex]\Delta T_{f} = -1.86*16.11[/tex]

[tex]\Delta T_{f} = -29.96[/tex]

Freezing point of a solution of Ethylene Glycol and Water is -29.96°C

Answer:

The answer to your question is given below.

Explanation:

When there is an adequate supply of oxygen available to react with the fuel of a bunsen burner, the flame produce is a non luminous bunsen flame.

This flame i.e non luminous flame produced is much hotter than the luminous and three zones can be seen in the flame. This zones are

1. The zone of unburnt gas.

2. The luminous zone.

3. The outermost non luminous zone.

When an adequate supply of oxygen is available to react with the fuel of a Bunsen burner, there is complete combustion of the fuel and a non-luminous flame is produced.

Complete combustion occurs where there is plentiful supply of oxygen. During the reaction, more heat energy is produced as the flame is non-luminous and less soot is produced.

A non-luminous flame is a flame which produces less light but more heat energy. It is usually blue in color and consists of three zones. These zones are:

1. The zone of unburnt gas.

2. The luminous zone.

3. The outermost non luminous zone.

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Answer:

He studied the way in which the elements combined during chemical reactions

Explanation:

Which method did Dalton use to develop his atomic theory?

D.) He studied the way in which elements combined during chemical reactions.

Answer: It’s D

Explanation:

Answer:

An aerosol is a colloidal A. liquid suspended in a C. gas.

Explanation:

Hence an aerosol is a colloidal solid or liquid suspended in a gas Smoke or fog, for example.

Aerosol is a system of equally dispersed, finely divided liquid or solid particles passing through a gas, often air. Dust and other aerosol particles, which serve as the nuclei for condensation and freezing, are crucial to the precipitation process.

Secondary aerosols develop when gas is converted into a particle, whereas primary aerosols are made up of particles that are added directly to the gas. Key aerosol categories include sulfates, organic carbon, black carbon, nitrates, mineral dust, and sea salt. These substances typically clump together to create complicated mixtures.

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Answer:

Hey there!

10000 gallons would be 37.85 cubic meters.

Let me know if this helps :)

Answer: 37.8501 m³

Explanation:

 10000.0 gal × 1 m³/264.2 gal

=37.8501 m³ (significant digits)

Answer:

HCl.

Explanation:

Of all the type of bond, Ionic bonds are the strongest. Among all the compounds in the options only HCl has ionic bond, rest have covalent bonds. So, the strongest intermolecular forces is in HCl.  Ionic bond are formed with the transfer of electrons, one atom is donor and the other is acceptor.

Answer:

A federal taxes

Explanation:

because these are taxes paid to the federal government of a state

Answer:

Hey there!

As the name suggests, you pay Federal Taxes to the government.

Let me know if this helps :)

Answer:

0.119 moles

Explanation:

Given that,

Mass measured by Nurse Antonio is 7 grams of NaCl

To find,

The no of moles of NaCl

Solution,

The number of moles is given by

[tex]n=\dfrac{m}{M}[/tex]

m is given mass

M is molar mass

For NaCl, molar mass is 23+35.5 = 58.5 grams

So,

[tex]n=\dfrac{7}{58.5}\\\\n=0.119\ \text{moles}[/tex]

Therefore, there are 0.119 moles of NaCl.

Answer:

Explanation:

Dispersion force is caused by weak Van der Waals attraction between molecules.

Because chloroamine and water are both polar solvents, dipole-dipole force of attraction exists between them. There is also hydrogen bonding present from the water molecules.

Answer: The forces present include;

1. Hydrogen bonding

2. Dispersion bonding

3. Dipole to Dipole bonding.

Explanation:

1. Hydrogen bonding is an electrostatic force that occur between atoms of hydrogen which is covalently bonded to electronegative atoms.

2. Dispersion force is type of force that occur between molecules which is caused by weak Van der Waals attraction between molecules.

3. Dipole -Dipole force occur when atoms with partial charges within a molecule attract themselves with another opposite opposite partial charge that is around the molecule.

Therefore,

Because chloroamine and water are both polar solvents, hydrogen bond, dispersion force and dipole-dipole force of attration occur between them. The hydrogen bonding occur between the water molecules.

Answer:

5.99 moles of [tex]UF_6[/tex]

Explanation:

In this case, we can start with the decomposition of [tex]UF_6[/tex], so:

[tex]UF_6~->~U~+~3F_2[/tex] (Reaction 1)

The [tex]F_2[/tex] can react with carbon to produce [tex]CF_4[/tex]:

[tex]CF_4~+~2F_2~->~CF_4[/tex] (Reaction 2)

If we 8.99 mol of [tex]CF_4[/tex], we can calculate the moles of [tex]F_2[/tex] that we need. In reaction 2 we have a molar ratio of 1:2 (2 moles of [tex]F_2[/tex] will produce 1 mol of [tex]CF_4[/tex]):

[tex]8.99~mol~CF_4\frac{2~mol~F_2}{1~mol~CF_4}~=~17.98~mol~F_2[/tex]

With this value and using the molar ratio in reaction 1 (3 moles of [tex]F_2[/tex] are producing by each mol of [tex]UF_6[/tex]), so:

[tex]17.98~mol~F_2\frac{1~mol~UF_6}{3~mol~F_2}~=~5.99~mol~UF_6[/tex]

So, we will need 5.99 moles of [tex]UF_6[/tex] to produce 8.99 mol of [tex]CF_4[/tex].

I hope it helps!

Answer:

Explanation:

We are to write a chemical equation for the reaction that occurs in the following cell: Cu|Cu2+(aq)||Ag+(aq)|Ag.

And to determine which one of the two metals, (copper and silver) is the anode and which is the cathode?

The chemical equation for the reaction is as follows:

[tex]\mathbf{Cu + 2Ag^+ \to Cu^{2+}+2Ag}[/tex]

The atoms of the Copper electrodes undergo oxidation and loses two electrons each to form copper II ions [tex](Cu^{2+})[/tex] which go into the solution. The copper then becomes negatively charged and functions as the negative electrode i.e the anode

The oxidation half reaction is:

[tex]\mathsf{Cu \to Cu^{2+} + 2e^-}[/tex]

The silver ions [tex]Ag^+[/tex] becomes reduced by gaining  two electrons each from the metallic copper which was deposited into the silver electrode. The  silver electrode thus becomes positively charged and functions as the positive electrode. i.e the cathode.

The reduction half reaction is:

[tex]\mathtt{Ag^+ + 1 e^- \to Ag}[/tex]

Answer:

There are 6

Explanation:

The significant figures in that number are  5 4 0 0 4 7

Hope this helps:)