Sodium hydride (NaH) can be used as a drying agent for many organic solvents. Explain how it works

Answers

Answer 1

Sodium hydride (NaH) is a powerful drying agent that is commonly used to remove traces of water from various organic solvents.

NaH reacts vigorously with water to form hydrogen gas (H2) and sodium hydroxide (NaOH), thereby effectively removing any water present in the solvent.

NaH is a solid that is white in appearance and has a strong reducing property. It is a highly reactive compound that can easily react with any substance that contains water. When NaH comes into contact with a solvent containing water, it rapidly removes the water molecules from the solvent, which results in the formation of hydrogen gas and NaOH.The mechanism of action of NaH is based on its reaction with water. NaH is an extremely strong base that readily accepts protons (H+) from water molecules. When NaH reacts with water, hydrogen gas is produced, and sodium hydroxide is formed. This reaction is exothermic, which means that it releases heat.

The use of NaH as a drying agent for organic solvents is essential in many chemical reactions because it prevents the formation of unwanted side products that can result from the presence of water. Water can react with many organic molecules, and it can also affect the solubility and reactivity of various compounds. Therefore, it is important to remove all traces of water from organic solvents before using them in chemical reactions.

In conclusion, sodium hydride (NaH) is a powerful drying agent that can remove traces of water from organic solvents. Its mechanism of action is based on its reaction with water, which results in the formation of hydrogen gas and sodium hydroxide. The use of NaH as a drying agent is crucial in many chemical reactions because it prevents the formation of unwanted side products that can result from the presence of water.

To learn more about Sodium hydride, refer:-

https://brainly.com/question/30887886

#SPJ11


Related Questions

Part A Using the data from Table 9.2, calculate ??' of the following reaction: 2 C2H2(g) + 5?2(g) ? 4 CO2(g) + 2 H2O(g) View Available Hint(s) -863 kJ Cannot calculate without AHP f of O2(g) 2512 kJ -2512 kJ Submit

Answers

To calculate ??' of the given reaction, we need to use the standard enthalpy of formation (AHP) values of the reactants and products. However, the AHP value of O2(g) is not provided in the given data, so we cannot calculate the enthalpy change without it.

AHP is the enthalpy change that occurs when one mole of a compound is formed from its constituent elements in their standard states under standard conditions. We can use AHP values to calculate the enthalpy change of a reaction using Hess's law.
To answer this question, we need to obtain the AHP value of O2(g) and then use it to calculate ??' of the reaction. This value can be found in a standard enthalpy of formation table.
In conclusion, without the AHP value of O2(g), we cannot calculate the enthalpy change of the given reaction. It is essential to have all the necessary AHP values to perform such calculations.

To know more about AHP visit:

https://brainly.com/question/9444545

#SPJ11

Enter your answer in the provided box. How many electrons does it take to fill a σ2p*MO?

Answers

A σ2p* MO can hold a maximum of two electrons. This orbital is the antibonding orbital that results from the overlap of two p atomic orbitals with opposite spins.

It is higher in energy than the σ2p bonding orbital, which is the result of the overlap of the same two p atomic orbitals with the same spin. When two electrons are added to a σ2p* MO, the molecule becomes unstable and is more likely to dissociate.

Therefore, in most cases, the σ2p* MO remains empty. However, in some cases, such as in the molecule F2, the σ2p* MO is populated by electrons to form a bond.

To know more about the σ2p* MO refer here :

https://brainly.com/question/29589751#

#SPJ11

why isn't pentanol (ch3ch2ch2ch2ch2oh) very soluble in water?

Answers

You asked why pentanol (CH3CH2CH2CH2CH2OH) isn't very soluble in water. The solubility of a compound in water is determined by its ability to form hydrogen bonds with water molecules.

Pentanol is an alcohol with five carbon atoms and one hydroxyl (-OH) group. The hydroxyl group can form hydrogen bonds with water molecules,

but the long hydrocarbon chain (CH3CH2CH2CH2CH2) is nonpolar and hydrophobic, meaning it doesn't interact favorably with water.



The hydrocarbon chain has weak van der Waals forces, which are weaker than the hydrogen bonds formed between water molecules.

As a result, when pentanol is mixed with water, the water molecules would rather remain bonded to each other through stronger hydrogen bonds than interact with the nonpolar hydrocarbon chain of pentanol.

This preference for self-association leads to the poor solubility of pentanol in water.



In summary, pentanol is not very soluble in water because its long hydrocarbon chain is nonpolar and hydrophobic, which doesn't interact favorably with the polar water molecules.

The water molecules prefer to remain bonded to each other through stronger hydrogen bonds, leading to the poor solubility of pentanol in water.

To know more about hydrogen bonds refer here

https://brainly.com/question/30885458#

#SPJ11

the following two half-reactions take place in a galvanic cell. at standard conditions, what species are produced at each electrode? sn2 2e– → sn e° = –0.14 v cu2 2e– → cu e° = 0.34 v

Answers

At the cathode, Sn will be produced and at the anode, Cu will be produced.

In a galvanic cell, the species that is reduced will be produced at the cathode, while the species that is oxidized will be produced at the anode.

The half-reaction: [tex]Sn^{2}[/tex]+ + 2[tex]e^{-}[/tex] → Sn has a standard reduction potential (E°) of -0.14 V. Since the reduction potential is negative, this half-reaction is oxidizing and the species Sn^2+ is being reduced to Sn. Therefore, Sn will be produced at the cathode.

The half-reaction: [tex]Cu^{2}[/tex]+ + 2[tex]e^{-}[/tex] → Cu has a standard reduction potential (E°) of 0.34 V. Since the reduction potential is positive, this half-reaction is reducing and the species [tex]Cu^{2}[/tex]+ is being oxidized to Cu. Therefore, Cu will be produced at the anode.

Overall, the cell reaction can be written as:

Sn^2+ + Cu → Sn + Cu^2+

At the cathode, Sn will be produced and at the anode, Cu will be produced.

Know more about     here:

#SPJ11

Determine the molar solubility of mg(oh)2 in a solution buffered at a ph of 4.5.

Answers

To determine the molar solubility of Mg(OH)2 in a solution buffered at a pH of 4.5, we need to use the solubility product constant (Ksp) for Mg(OH)2 and the pH-dependent solubility product constant (Ksp') for the hydrolysis of Mg2+.

The balanced equation for the dissolution of Mg(OH)2 is:

Mg(OH)2(s) ⇌ Mg2+(aq) + 2OH-(aq)

The Ksp expression for this equilibrium is:

Ksp = [Mg2+][OH-]^2

At a pH of 4.5, the concentration of H+ ions is relatively high, which can lead to the hydrolysis of Mg2+ ions according to the following reaction:

Mg2+(aq) + 2H2O(l) ⇌ Mg(OH)2(s) + 2H+(aq)

The equilibrium constant for this reaction is given by:

K = [Mg(OH)2][H+]^2 / [Mg2+]

The Ksp' for Mg(OH)2 at a pH of 4.5 is related to Ksp and K by the equation:

Ksp' = Ksp / K

We can use the Henderson-Hasselbalch equation to calculate the concentration of H+ ions at pH 4.5:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant of the buffer, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

Since the problem does not provide information about the buffer used, we cannot use this equation directly. However, we can assume that the buffer has a pKa close to 4.5, which means that [A-] ≈ [HA]. Thus, we can simplify the equation to:

pH = pKa + log(1) = pKa

Therefore, we can assume that the concentration of H+ ions at pH 4.5 is 10^-4.5 M = 3.16×10^-5 M.

We can now use this concentration, along with K and Ksp, to calculate Ksp':

K = [Mg(OH)2][H+]^2 / [Mg2+]

Ksp = [Mg2+][OH-]^2

Ksp' = Ksp / K = [OH-]^2 / [H+]^2

Since Mg(OH)2 dissolves completely in water, we can assume that [Mg2+] = 2[OH-]. Substituting this into the expression for Ksp' and solving for [OH-], we get:

Ksp' = [OH-]^2 / [H+]^2 = (2[OH-])^2 / [H+]^2 = 4Ksp / [Mg2+][H+]^2

[OH-] = sqrt(4Ksp / [Mg2+][H+]^2) = sqrt(4 × 1.8×10^-11 / (2 × 3.16×10^-5)^2) = 1.76×10^-6 M

Since [Mg2+] = 2[OH-], we get:

[Mg2+] = 2 × 1.76×10^-6 M = 3.52×10^-6 M

Therefore, the molar solubility of Mg(OH)2 in a solution buffered at a pH of 4.5 is 3.52×10^-6 M.

To determine the molar solubility of Mg(OH)2 in a solution buffered at a pH of 4.5, we need to use the solubility product constant (Ksp) for Mg(OH)2 and the pH-dependent solubility product constant (Ksp') for the hydrolysis of Mg2+.

The balanced equation for the dissolution of Mg(OH)2 is:

Mg(OH)2(s) ⇌ Mg2+(aq) + 2OH-(aq)

The Ksp expression for this equilibrium is:

Ksp = [Mg2+][OH-]^2

At a pH of 4.5, the concentration of H+ ions is relatively high, which can lead to the hydrolysis of Mg2+ ions according to the following reaction:

Mg2+(aq) + 2H2O(l) ⇌ Mg(OH)2(s) + 2H+(aq)

The equilibrium constant for this reaction is given by:

K = [Mg(OH)2][H+]^2 / [Mg2+]

The Ksp' for Mg(OH)2 at a pH of 4.5 is related to Ksp and K by the equation:

Ksp' = Ksp / K

We can use the Henderson-Hasselbalch equation to calculate the concentration of H+ ions at pH 4.5:

pH = pKa + log([A-]/[HA])

where pKa is the acid dissociation constant of the buffer, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

Since the problem does not provide information about the buffer used, we cannot use this equation directly. However, we can assume that the buffer has a pKa close to 4.5, which means that [A-] ≈ [HA]. Thus, we can simplify the equation to:

pH = pKa + log(1) = pKa

Therefore, we can assume that the concentration of H+ ions at pH 4.5 is 10^-4.5 M = 3.16×10^-5 M.

We can now use this concentration, along with K and Ksp, to calculate Ksp':

K = [Mg(OH)2][H+]^2 / [Mg2+]

Ksp = [Mg2+][OH-]^2

Ksp' = Ksp / K = [OH-]^2 / [H+]^2

Since Mg(OH)2 dissolves completely in water, we can assume that [Mg2+] = 2[OH-]. Substituting this into the expression for Ksp' and solving for [OH-], we get:

Ksp' = [OH-]^2 / [H+]^2 = (2[OH-])^2 / [H+]^2 = 4Ksp / [Mg2+][H+]^2

[OH-] = sqrt(4Ksp / [Mg2+][H+]^2) = sqrt(4 × 1.8×10^-11 / (2 × 3.16×10^-5)^2) = 1.76×10^-6 M

Since [Mg2+] = 2[OH-], we get:

[Mg2+] = 2 × 1.76×10^-6 M = 3.52×10^-6 M

Therefore, the molar solubility of Mg(OH)2 in a solution buffered at a pH of 4.5 is 3.52×10^-6 M.

To know more about refer Mg(OH)2 here

brainly.com/question/15018148#

#SPJ11

Consider the reaction A → products. Will the half life of this reaction increase, decrease, or stay the same over time if the reaction is the following order?
0 order, first order, second order

Answers

The half life of the reaction A → products will decrease over time if the reaction is 0 order, stay the same over time if the reaction is first order, and increase over time if the reaction is second order.

For the reaction A → products, the half-life behavior will depend on the reaction order:
0 order: The half-life will decrease over time, as it is inversely proportional to the initial concentration of A.
1st order: The half-life will stay the same over time, as it is independent of the concentration of A.
2nd order: The half-life will increase over time, as it is directly proportional to the concentration of A.

To know more about half life visit:

https://brainly.com/question/31666695

#SPJ11

The ionization constant for water (Kw) is 1.69 ✕ 10−13 at 72°C. Calculate [H3O+ ] (in M), [OH− ] (in M), pH, and pOH for pure water at 72°C.

Answers

At 72°C, the concentration of [tex]H_{3}O[/tex] and OH- ions in pure water is 1.30 x 10^-7 M, and the pH and pOH of pure water are both 6.89.

The ionization constant for water (Kw) is defined as the product of the concentrations of H3O+ and OH- ions in water at a given temperature:

[tex]KW = [H_{3}O +][OH-][/tex]

At 72°C, the value of Kw is 1.69 x 10^-13. Since pure water is neutral, the concentration of H3O+ and OH- ions must be equal. Therefore, we can write:

[tex][H_{3}O+] = [OH-] = x[/tex]

Substituting this into the expression for Kw, we get:

[tex]Kw = x^2 = 1.69 x 10^-13[/tex]

Solving for x, we get:

[tex]x = √(1.69 x 10^-13) = 1.30 x 10^-7 M[/tex]

Therefore, the concentration of H3O+ and OH- ions in pure water at 72°C is 1.30 x 10^-7 M.

The pH is defined as the negative logarithm of the concentration of H3O+ ions in water:

[tex]pH = -log[H_{3}O+][/tex]

Substituting the value of [H3O+] into this equation, we get:

[tex]pH = -log(1.30 x 10^-7) = 6.89[/tex]

Therefore, the pH of pure water at 72°C is 6.89.

The pOH is defined as the negative logarithm of the concentration of OH- ions in water:

[tex]pOH = -log[OH-][/tex]

Substituting the value of [OH-] into this equation, we get:

[tex]pOH = -log(1.30 x 10^-7) = 6.89[/tex]

Therefore, the pOH of pure water at 72°C is also 6.89.

Since pH + pOH = 14 at all temperatures, we can verify that the sum of the pH and pOH values obtained above is indeed equal to 14.

For such more question on concentration:

https://brainly.com/question/28564792

#SPJ11

The concentration of [H3O+] and [OH-] in pure water at 72°C is [tex]1.30 × 10^-7 M[/tex]. The pH and pOH of pure water at 72°C are both 6.89. This is calculated using the ionization constant for water (Kw) of [tex]1.69 × 10^-13.[/tex]

The ionization constant for water (Kw) at 72°C is [tex]1.69 × 10^-13.[/tex]

Kw = [H3O+][OH-]

At 72°C, the concentration of H3O+ and OH- ions in pure water can be assumed to be equal.

[H3O+] = [OH-]

Let x be the concentration of H3O+ and OH- ions in pure water.

[tex]Kw = x^2 = [H3O+]^2[/tex]

[tex]x = sqrt(Kw) = sqrt(1.69 × 10^-13) = 1.30 × 10^-7 M[/tex]

[tex][H3O+] = [OH-] = 1.30 × 10^-7 M[/tex]

[tex]pH = -log[H3O+] = -log(1.30 × 10^-7) = 6.89[/tex]

[tex]pOH = -log[OH-] = -log(1.30 × 10^-7) = 6.89[/tex]

Therefore, the concentration of [tex][H3O+] is 1.30 × 10^-7 M[/tex], the concentration of [tex][OH-] is 1.30 × 10^-7 M[/tex], the pH is 6.89, and the pOH is 6.89 for pure water at 72°C.

learn more about ionization here:

https://brainly.com/question/28385102

#SPJ11

The isoelectric point of asparagine is 5.41 ; glycine , 5.97 .
During paper electrophoresis at pH 6.5 , toward which electrode does asparagine migrate? _________ (Chose: positive or negative)
During paper electrophoresis at pH 7.1 , toward which electrode does glycine migrate? _________ (Chose: positive or negative)

Answers

During paper electrophoresis at pH 6.5, asparagine migrates toward the positive electrode.

During paper electrophoresis at pH 7.1, glycine migrates toward the negative electrode.

Which electrode does asparagine migrate towards?

At pH 6.5, asparagine migrates towards the positive electrode due to its lower isoelectric point (5.41) compared to the pH value.

The isoelectric point (pI) is the pH at which a molecule carries no net electrical charge. When the pH is higher than the pI, the molecule tends to be negatively charged and migrates towards the positive electrode during electrophoresis.

Conversely, glycine migrates towards the negative electrode at pH 7.1 as its isoelectric point (5.97) is higher than the pH value, resulting in a positive charge.

The migration of amino acids during electrophoresis depends on the pH of the medium and the pI of the specific amino acid.

Learn more about asparagine

brainly.com/question/30907989

#SPJ11

one mole of f 2 gas at stp would take up twice the volume of one mole of ar gas at stp.

Answers

one mole of [tex]F_2[/tex]  gas at stp would take up twice the volume of one mole of at gas at stp. This statement is false.

According to Avogadro’s law, at the same temperature and pressure, equal volumes of gases contain an equal number of moles.  At STP (standard temperature and pressure), which is defined as 0 degrees Celsius and 1 atmosphere of pressure, one mole of any ideal gas occupies a volume of approximately 22.4 liters. This is known as the molar volume of a gas.

Therefore, regardless of the type of gas, whether it is fluorine gas or argon gas (Ar), one mole of either gas at STP would occupy the same volume of approximately 22.4 liters. The molar volume is a property that is independent of the specific gas and depends only on the temperature and pressure conditions.

Learn more about Avogadro’s law here:

https://brainly.com/question/1964205

#SPJ11

Two students are given 3-oxobutanoic acid below and asked to prepare 2-methyl-3-oxobutanoic acid.
The first student recognizes this as the first step of the acetoacetic ester synthesis. He treats the starting material with sodium methoxide followed by methyl iodide. He isolates compound A, but 1H NMR analysis shows this is not the desired material. Elemental analysis shows it has the same molecular formula as the 2-methyl-3-oxobutanoic acid. What is compound A?
The second student recognizes an extra step is needed first. She treats the starting material with diazomethane and isolates compound B. She then treats compound B with sodium methoxide followed by methyl iodide and isolates compound C. Draw compounds B and C.
Compound C can be converted to the 2-methyl-3-oxobutanoic acid using what reagent?

Answers

Compound A is likely the enol form of 3-oxobutanoic acid, also known as acetoacetic acid. The treatment with sodium methoxide and methyl iodide leads to the formation of the methyl ester of acetoacetic acid, which is compound A.

Compound B is likely the methyl acetoacetate, formed by the reaction of 3-oxobutanoic acid with diazomethane.

Compound C is likely the ethyl 2-methyl-3-oxobutanoate, formed by the reaction of methyl acetoacetate with sodium methoxide and methyl iodide.

Compound C can be converted to the 2-methyl-3-oxobutanoic acid using acidic hydrolysis, such as treatment with dilute hydrochloric acid or sulfuric acid.


Compound A is an isomer of the desired 2-methyl-3-oxobutanoic acid. The first student's reaction with sodium methoxide and methyl iodide likely resulted in a methylation at the wrong position, forming 4-methyl-3-oxobutanoic acid instead.

For the second student, treating the starting material (3-oxobutanoic acid) with diazomethane (CH2N2) results in the formation of the corresponding methyl ester, which is compound B: methyl 3-oxobutanoate.

Next, treating compound B with sodium methoxide followed by methyl iodide forms compound C: methyl 2-methyl-3-oxobutanoate.

To convert compound C to the desired 2-methyl-3-oxobutanoic acid, you need to hydrolyze the ester group. This can be achieved by treating compound C with an aqueous solution of a strong acid, such as hydrochloric acid (HCl). This hydrolysis reaction will convert the ester group back to a carboxylic acid, resulting in the formation of 2-methyl-3-oxobutanoic acid.

To know more about  acetoacetic acid visit:-

https://brainly.com/question/31630187

#SPJ11

Arrange the following molecules from least to most polar (largest net dipole at the bottom): a) SF2. b) CHF3. c) OCl2. d) Cse2.

Answers

The molecules can be arranged from least to most polar as follows: d) CSe2 (least polar), c) OCl2, a) SF2, and b) CHF3 (most polar).

To arrange the molecules SF2, CHF3, OCl2, and CSe2 from least to most polar, we need to compare their net dipole moments. The net dipole moment depends on the molecular structure and electronegativity of the atoms involved.

a) SF2 - In this molecule, sulfur has two fluorine atoms and two lone pairs. The presence of the highly electronegative fluorine atoms creates a dipole moment. Due to the bent molecular shape, the dipole moments do not cancel out, leading to a polar molecule.

b) CHF3 - This molecule has carbon surrounded by three fluorine atoms and one hydrogen atom. The fluorine atoms are highly electronegative, and due to the tetrahedral molecular shape, the dipole moments do not cancel out. This results in a polar molecule with a significant dipole moment.

c) OCl2 - In this molecule, oxygen is bonded to two chlorine atoms. Oxygen is more electronegative than chlorine, which generates a dipole moment. The molecular shape is bent, preventing the dipole moments from canceling out. This leads to a polar molecule with a moderate dipole moment.

d) CSe2 - In this molecule, carbon is bonded to two selenium atoms. The electronegativity difference between carbon and selenium is small, resulting in a weak dipole moment. The molecular shape is linear, causing the dipole moments to cancel out, resulting in a nonpolar molecule with no net dipole moment.

In summary, the molecules can be arranged from least to most polar as follows: CSe2 (least polar), OCl2, SF2, and CHF3 (most polar).

Learn more about dipole at: https://brainly.com/question/19296764

#SPJ11

a periodic karman vortex street is formed when

Answers

A periodic Karman vortex street is formed when a fluid flow, such as air or water, encounters an obstacle, typically a cylindrical or bluff body.

This phenomenon occurs due to the separation of fluid layers around the object, which creates alternating low-pressure regions on each side. The fluid flow begins to shed vortices in a periodic manner, generating a pattern known as a Karman vortex street, these vortices are formed at regular intervals, creating a distinct street-like pattern downstream of the obstacle. The shedding of vortices is influenced by the Reynolds number, which determines the fluid flow regime. In low Reynolds number conditions, the flow is laminar, and no vortex street is formed. However, as the Reynolds number increases, the flow transitions to a turbulent regime, leading to the formation of the Karman vortex street.

The presence of a Karman vortex street can have various consequences on structures, such as increased vibrations and dynamic loads. In engineering applications, understanding and mitigating the effects of vortex shedding is crucial to ensure structural stability and prevent failures. To reduce the impact of a Karman vortex street, engineers may implement design modifications or use devices such as vortex breakers or flow control techniques to alter the flow characteristics around the object. So therefore when a fluid flow, such as air or water, encounters an obstacle, typically a cylindrical or bluff body, a periodic Karman vortex street is formed.

To learn more about fluid here:

https://brainly.com/question/29654184

#SPJ11

Vinylcyclopropane reacts with H2O in H2SO4 to yield a rearranged alcohol. Show the structure of the initial carbocation intermediate (2 pts) and the second carbocation intermediate after rearrangement (2pts). Draw all the curved arrows for each elementary step needed to make the product (6pts):

Answers

The initial carbocation intermediate formed upon reaction of vinylcyclopropane with H2O in H2SO4 is a secondary carbocation.

The second carbocation intermediate formed after rearrangement is a tertiary carbocation.The reaction mechanism proceeds via protonation of the vinylcyclopropane to form a carbocation intermediate, followed by nucleophilic attack of water to form a protonated alcohol. The alcohol then undergoes a Wagner-Meerwein rearrangement to form the final rearranged alcohol product.The curved arrow mechanism for the reaction involves the movement of electron pairs to show the flow of electrons in each elementary step. The first step involves the protonation of the alkene to form a secondary carbocation intermediate. The second step involves the nucleophilic attack of water to form a protonated alcohol. The third step involves the migration of a hydride ion from the adjacent carbon to the carbocation, resulting in the formation of the tertiary carbocation intermediate. The final step involves the deprotonation of the protonated alcohol by the conjugate base of the sulfuric acid to yield the rearranged alcohol product.Overall, the reaction mechanism involves a series of protonation, nucleophilic attack, and rearrangement steps that lead to the formation of the desired product.

Learn more about intermediate here:

https://brainly.com/question/14584799

#SPJ11

Which ionic species, when added to pure water, would result in a change in pH? I KHCOO II NaF III Ba(NO3)2 IV. CH3NH3Br A. I and II B. I and IV C. I, II and IV D. I, II, III and IV

Answers

The ionic species, when added to pure water, would result in a change in pH is A. I and II

The addition of ionic species to pure water can result in a change in pH due to their ability to either donate or accept protons. In this case, the ionic species that can cause a change in pH are those that contain a weak acid or a weak base. Option I, KHCOO, is a weak acid salt and can undergo hydrolysis in water, resulting in the formation of H+ ions and therefore a decrease in pH. Option II, NaF, is a salt of a weak base and a strong acid. It will not have a significant effect on the pH of pure water.

Option III, Ba(NO³)², is a salt of a strong acid and a strong base, and it will also not have a significant effect on the pH of pure water. Option IV, CH³NH³Br, is a salt of a weak base and a strong acid and can undergo hydrolysis in water, resulting in the formation of OH⁻ ions and therefore an increase in pH. Therefore, the correct answer is A. I and II, as only KHCOO and CH³NH³Br can cause a change in pH when added to pure water.

Learn more about strong acid at

https://brainly.com/question/29796621

#SPJ11

What is the role of the filter paper in the salt bridge? Do you think the bridge would work as well without the filter paper?

Answers

The filter paper acts as a barrier to prevent the mixing of solutions in the salt bridge.

The filter paper is a crucial component in the salt bridge as it separates the two half-cells and prevents the mixing of their respective solutions.

It allows ions to pass through it and establish a connection between the half-cells, enabling the flow of electrons in the external circuit.

Without the filter paper, the solutions in the two half-cells would mix, causing an irreversible chemical reaction that would render the salt bridge useless.

Therefore, the filter paper is necessary for the proper functioning of the salt bridge and the overall electrochemical cell.

For more such questions on salt, click on:

https://brainly.com/question/20835655

#SPJ11

The filter paper in a salt bridge is used to prevent mixing of the two half-cells while allowing the ions to pass through.

The bridge would not work as effectively without the filter paper, as it would allow unwanted mixing and potentially interfere with the flow of ions. The filter paper in a salt bridge serves as a barrier that prevents the two half-cells from mixing while allowing the ions to pass through. It is essential to maintain the integrity of the two half-cells, as any unwanted mixing can interfere with the redox reaction and affect the accuracy of the results. The filter paper is typically made of a porous material, such as cellulose or glass fiber, that allows the ions to move freely but prevents any physical mixing of the solutions. Without the filter paper, the salt bridge would not work as effectively as it would allow unwanted mixing and interfere with the flow of ions. This could result in a slower reaction or an incomplete reaction, leading to inaccurate results. Therefore, the filter paper is an essential component of the salt bridge and plays a crucial role in ensuring the success of the redox reaction.

Learn more about salt bridge here:

https://brainly.com/question/13860909

#SPJ11

What is the pressure of CL2 if 1. 4 moles is contained in a 10L bottle at 300K?

Answers

The pressure of Cl2 in a 10L bottle containing 1.4 moles at 300K is approximately 4.76 atmospheres (atm).

To determine the pressure of [tex]Cl_{2}[/tex] in the given scenario, we can use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the volume from liters to cubic meters:

10 L * (1 [tex]m^{3}[/tex] / 1000 L) = 0.01 m^{3}

Next, we convert the temperature from Celsius to Kelvin:

300 K = 273.15 + 300 K = 573.15 K

Now, we can substitute the values into the ideal gas law equation:

P * 0.01 m^{3} = 1.4 moles * (8.314 J/(mol·K)) * 573.15 K

Simplifying the equation, we can solve for P:

P = (1.4 moles * 8.314 J/(mol·K) * 573.15 K) / 0.01 m^{3}

Calculating this expression, we find that the pressure of Cl_{2} is approximately 4.76 atm. Therefore, the pressure ofCl_{2}in a 10L bottle containing 1.4 moles at 300K is approximately 4.76 atmospheres (atm).

Learn more about moles here: https://brainly.com/question/29367909

#SPJ11

Calculate the ph of a 0.2 m solution of an amine that has a pka of 9.5

Answers

The pH of a 0.2 M solution of an amine with a pKa of 9.5 is 9.5.

To calculate the pH of a 0.2 M solution of an amine with a pKa of 9.5, we first need to determine the concentration of the conjugate base of the amine (i.e., the amine with a proton removed).

Since the pKa is 9.5, the pH at which half of the amine molecules will be protonated (i.e., NH3+) and half will be deprotonated (i.e., NH2) is 9.5. This means that at pH 9.5, the concentration of the conjugate base and the amine will be equal.

Using the Henderson-Hasselbalch equation:

pH = pKa + log([conjugate base]/[amine])

We can rearrange this equation to solve for [conjugate base]:

[conjugate base] = [amine] x 10^(pH - pKa)

Plugging in the values given in the question, we get:

[conjugate base] = 0.2 M x 10^(pH - 9.5)

Since at pH 9.5, [conjugate base] = [amine], we can set these two expressions equal to each other:

[conjugate base] = [amine]

0.2 M x 10^(pH - 9.5) = 0.2 M

Dividing both sides by 0.2 M, we get:

10^(pH - 9.5) = 1

Taking the logarithm of both sides:

pH - 9.5 = 0

Solving for pH, we get:

pH = 9.5

Therefore, the pH of a 0.2 M solution of an amine with a pKa of 9.5 is 9.5.

Learn more about amine here,

https://brainly.com/question/29204285

#SPJ11

Draw the major product of this reaction. Ignore inorganic byproducts and CO2. o 1. KMnO4, OH- (warm) 2. H3O+

Answers

The given reaction involves the oxidation of an organic compound by potassium permanganate (KMnO4) in basic medium (OH-). The intermediate formed in this step is an unstable compound that further reacts with H3O+ in acidic medium to form the final product.


To draw the major product of the reaction with the given reagents, follow these steps:
1. The reactant undergoes oxidation using KMnO4 and OH- under warm conditions. This step involves the cleavage of any carbon-carbon double bonds and converting them into carbonyl groups (C=O).
2. The addition of H3O+ in the next step results in the hydration of carbonyl groups, forming geminal diols (two -OH groups on the same carbon).
The major product formed in this reaction is a carboxylic acid. The exact compound formed will depend on the starting material. The reaction of KMnO4 with a primary alcohol forms a carboxylic acid as the major product.
Therefore, the answer to the question "Draw the major product of this reaction. Ignore inorganic byproducts and CO2. o 1. KMnO4, OH- (warm) 2. H3O+" is a carboxylic acid. Without knowing the exact structure of the starting material, I cannot provide a specific structure for the major product. However, the general outcome of the reaction involves the conversion of carbon-carbon double bonds to geminal diols.

To know more about potassium permanganate visit:

https://brainly.com/question/30636651

#SPJ11

how many grams of co2 are contained in a 1.00 l flask if the pressure is 1.91 atm and the temperature is 26.5°c?

Answers

3.43 grams of CO2 are contained in a 1.00 L flask at 1.91 atm pressure and 26.5° c temperature,

The Ideal Gas Law equation: PV = nRT. This equation relates the pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T) of a gas.

We can rearrange this equation to solve for the number of moles of gas (n) using the formula:

n = PV/RT

where P is the pressure in atm, V is the volume in liters, R is the gas constant (0.08206 Latm/molK), and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15:

T = 26.5 + 273.15 = 299.65 K

Next, we can plug in the given values:

n = (1.91 atm) x (1.00 L) / (0.08206 Latm/molK x 299.65 K)

n = 0.0778 mol CO2

Finally, we can calculate the mass of CO2 using its molar mass:

mass = n x M

where M is the molar mass of CO2, which is approximately 44.01 g/mol.

mass = 0.0778 mol x 44.01 g/mol

mass = 3.43 g CO2

Therefore, there are approximately 3.43 grams of CO2 in the 1.00 L flask at a pressure of 1.91 atm and a temperature of 26.5°C.

Know more about Ideal Gas Law here:

https://brainly.com/question/27870704

#SPJ11

consider the following half reaction: na⁺(aq) e⁻ → na(s). for this reaction, e°(red) = -2.7 v. if this reaction is tripled so that 3 na⁺ ions are reduced to 3 na atoms, what is the new e°(red)?

Answers

The new E°(red) for the tripled reaction is still -2.7 V.

The given half-reaction is:

Na⁺(aq) + e⁻ → Na(s)

The standard reduction potential, E°(red), for this half-reaction is given as -2.7 V.

When the reaction is tripled, the balanced chemical equation becomes:

3 Na⁺(aq) + 3 e⁻ → 3 Na(s)

The overall reaction is still a reduction reaction and involves the same number of electrons. Therefore, the new E°(red) for the tripled reaction is the same as the original E°(red) value:

E°(red) = -2.7 V

Click the below link, to learn more about Standard Reduction potential:

https://brainly.com/question/23881200

#SPJ11

how many grams of magnesium are needed to completely react with 54.5 ml of oxygen gas at stp? be sure to balance the equation.

Answers

The balanced chemical equation for the reaction between magnesium and oxygen is Therefore, approximately 0.0295 grams of magnesium are needed to completely react with 54.5 mL of oxygen gas at STP.

Magnesium is a chemical element with the symbol Mg and atomic number 12. It is a shiny, grayish-white metal that is relatively soft and lightweight. Magnesium is the eighth most abundant element in the Earth's crust and is essential to many biological processes.Magnesium is highly reactive and burns brightly when heated in air or oxygen, producing a bright white light. It is commonly used in flares, fireworks, and photographic flashbulbs due to its high reactivity and bright light emission.

To know more about Magnesium visit :

https://brainly.com/question/1533548

#SPJ11

86. What attracts or directs the synthesis enzyme to the template in Translation? a. Start Codon b. 5'-cap c. Primer d. Promoter e. Poly-A Tail
92. Which of the following is the description for Catabolic Reactions? a. the energy of movement b. the breaking down of complex molecules into simpler ones c. energy converted from one form to another d. energy is neither created nor destroyed e. the linking of simple molecules to form complex molecules

Answers

86. The element that attracts or directs the synthesis enzyme to the template in Translation is a. Start Codon. The start codon is a specific sequence of nucleotides that signals the beginning of the translation process. 92. The description for Catabolic Reactions is b. the breaking down of complex molecules into simpler ones. These reactions release energy by breaking down complex molecules and are involved in processes like digestion and cellular respiration.

For the first question (86), the long answer is that the synthesis enzyme is attracted and directed to the template in Translation by the start codon. The start codon, which is usually AUG in eukaryotic cells, signals to the synthesis enzyme that it should begin the process of synthesizing a protein. The start codon is located at the beginning of the messenger RNA (mRNA) sequence, and once the synthesis enzyme recognizes it, it begins to read the codons that follow and assemble the corresponding amino acids to form the protein. For the second question (92), the long answer is that catabolic reactions are the breaking down of complex molecules into simpler ones. These reactions release energy that can be used for cellular processes. Catabolic reactions are the opposite of anabolic reactions, which involve the linking of simple molecules to form complex molecules and require energy input. The energy released from catabolic reactions can be converted from one form to another and used for activities such as movement, transport, and chemical reactions.

To know more about enzyme visit :-

https://brainly.com/question/29990904

#SPJ11

The average tire pressure for an automobile is 38.5 psi which is how many atmospheres of pressure? a) 1.77 x 10-3 atm. b) 566 atm. c) 2.62 atm.

Answers

The average tire pressure for an automobile is 38.5 psi which is how many atmospheres of pressure is 2.62 atm. The correct answer is option c) 2.62 atm.

To convert the average tire pressure of an automobile, 38.5 psi, to atmospheres of pressure, we can use the following conversion factor: 1 atm = 14.696 psi.

Here is a step-by-step explanation:

1. Write down the given pressure in psi: 38.5 psi
2. Identify the conversion factor: 1 atm = 14.696 psi
3. Set up a proportion to find the pressure in atmospheres: (38.5 psi) * (1 atm / 14.696 psi)
4. Cancel the units (psi) and perform the calculation: (38.5) * (1 / 14.696)
5. Calculate the result: 2.62 atm

So, the average tire pressure of 38.5 psi is equivalent to 2.62 atmospheres of pressure, which corresponds to option c) 2.62 atm.

Learn more about automobile here:

https://brainly.com/question/29058573

#SPJ11

[100 PTS!] Suppose a substance has a heat of fusion equal to 45 cal/g and a specific heat of 0. 75 cal/g°C in the liquid state. If 5. 0 kcal of heat are applied to a 50-g sample of the substance at a temperature of 24°C, will its new temperature be? What state will the sample be in? (melting point of the substance = 37°C; specific heat of the sold = 0. 48 cal/g°C; boiling point of the substance = 700°C) Show your work

Answers

The sample substance will reach a temperature of 37°C and will be in a partially melted state.

When heat is applied to the substance, the first step is to use the heat of fusion to melt the solid.

This requires 45 cal/g x 50 g = 2250 cal. The temperature of the substance will remain at 0°C until all the solid is melted. The next step is to use the specific heat of the liquid to raise the temperature.

This requires 0.75 cal/g°C x 50 g x (37°C - 0°C) = 1406.25 cal. The total heat required to complete the process is 2250 cal + 1406.25 cal = 3656.25 cal = 3.65625 kcal.

Since 5.0 kcal are applied, the substance will be in a partially melted state at a temperature of 37°C, which is its melting point.

Learn more about fusion here.

https://brainly.com/questions/31756416

#SPJ11

A 0. 661 L vessel contains 0. 0112 mol of a gas at 741 torr.


What is the temperature of the gas?

Answers

We found the temperature of the gas is approximately 5456.9 Kelvin, using the ideal gas law equation, which states: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

To find the temperature of the gas, we can use the ideal gas law equation, which states: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Given:

Pressure (P) = 741 torr

Volume (V) = 0.661 L

Number of moles (n) = 0.0112 mol

The ideal gas constant (R) depends on the units of pressure and volume being used. In this case, since the pressure is given in torr and the volume is given in liters, we will use the value R = 0.0821 L·atm/(mol·K).

Rearranging the ideal gas law equation to solve for T: T = (PV) / (nR)

Substituting the given values:

T = (741 torr * 0.661 L) / (0.0112 mol * 0.0821 L·atm/(mol·K))

Simplifying the expression:

T = 49764.06 / 0.0091112

T = 5456.9 K

Therefore, the temperature of the gas is approximately 5456.9 Kelvin.

LEARN MORE ABOUT temperature  here: brainly.com/question/11464844

#SPJ11

hypothesis may be positive or negative towards the scientific results

Answers

Yes, that is correct. A hypothesis is a proposed explanation or prediction for a phenomenon or set of phenomena. It can be either positive or negative towards the scientific results.

A positive hypothesis is one that proposes a relationship or correlation between variables, or a potential explanation for observed phenomena. For example, "increasing the amount of fertilizer applied to plants will result in increased plant growth."

On the other hand, a negative hypothesis proposes that there is no relationship or correlation between variables, or that there is no explanation for observed phenomena. For example, "increasing the amount of fertilizer applied to plants will not result in increased plant growth."

Regardless of whether a hypothesis is positive or negative, it is an important starting point for scientific inquiry, as it helps guide the design of experiments and the collection of data to test the hypothesis.

For more question on hypothesis click on

https://brainly.com/question/31330789

#SPJ11

(2 points) what is the systematic (iupac) name of the following molecule? bonus (2 points) what is the final product of the following reaction sequence? o oh o

Answers

The systematic (IUPAC) name of the given molecule is 2-hydroxybenzoic acid. It is also known as salicylic acid.

The IUPAC name is derived by first identifying the parent hydrocarbon, which in this case is benzene. Then, we add the hydroxy group as a substituent at the second carbon atom of the benzene ring. Finally, we add the carboxylic acid functional group as a suffix.

Regarding the bonus question, the reaction sequence is not provided, so it is impossible to determine the final product. Additional information is needed to solve the problem. Please provide more details about the reaction sequence, such as the reagents, conditions, and expected outcome.

For more such questions on molecule

https://brainly.com/question/24191825

#SPJ11

NOTE- The question seems to be incomplete, The complete question isn't available on the search engine.

how the sequences of DNA are used in transcription and translation the determine the structure and functions of protein in hydrophobic

Answers

The sequences of DNA are used in transcription and translation to determine the structure and functions of proteins in hydrophobic environments through a complex process that involves multiple steps.

Transcription: Translation & Protein Folding and Function

Transcription

The first step in protein synthesis is transcription, where the DNA sequence is copied into a single-stranded RNA molecule. The RNA molecule carries the genetic information from the DNA to the ribosome, where it is translated into a protein.

During transcription, the DNA is unwound and one of the DNA strands serves as a template for RNA synthesis.

The RNA molecule is synthesized in a 5' to 3' direction by RNA polymerase, using nucleotides that are complementary to the DNA template.

The sequence of nucleotides in the RNA molecule is determined by the sequence of nucleotides in the DNA template. The RNA molecule is then processed by splicing, capping, and polyadenylation to form the mature mRNA molecule.

Translation:

In the second step of protein synthesis, translation, the genetic information carried by the mRNA molecule is used to synthesize a protein. The ribosome reads the mRNA molecule in codons, which are groups of three nucleotides that code for specific amino acids.

The ribosome then matches each codon with a complementary tRNA molecule, which carries the corresponding amino acid. The amino acids are joined together by peptide bonds to form a polypeptide chain.

The sequence of amino acids in the polypeptide chain is determined by the sequence of codons in the mRNA molecule.

Protein Folding and Function:

Once the polypeptide chain is synthesized, it folds into a specific three-dimensional shape, which is determined by the sequence of amino acids in the chain. The hydrophobic and hydrophilic properties of the amino acids in the chain determine how the protein will fold and how it will interact with its environment.

In hydrophobic environments, hydrophobic amino acids tend to be buried in the interior of the protein, while hydrophilic amino acids tend to be exposed on the surface of the protein. The three-dimensional structure of the protein determines its function.

Proteins can act as enzymes, receptors, transporters, or structural components, among other functions, depending on their three-dimensional structure.

In summary, the sequence of nucleotides in DNA is transcribed into RNA and then translated into a polypeptide chain. The sequence of amino acids in the polypeptide chain determines the three-dimensional structure of the protein, which in turn determines its function in hydrophobic environments.

For more question on DNA click on

https://brainly.com/question/25731821

#SPJ11

protein binds to a ligand with a kd of 1.0 10-5 m. at what concentration does equal 0.5?

Answers

The concentration of protein that binds to a ligand with a kd of 1.0 10-5 m at which the binding is half-saturated, or equal to 0.5, is also known as the dissociation constant or Kd.

To calculate Kd, we can use the formula Kd = [ligand][protein] / [ligand-protein complex]. When the ligand-protein complex is half-saturated, the concentration of the ligand-protein complex equals the concentration of the free protein, which is equal to the concentration of the free ligand.

Therefore, we can substitute [ligand-protein complex] with [protein][ligand] / Kd in the formula and solve for Kd to find the concentration at which the binding is half-saturated. The concentration of the free protein that binds to the ligand with a Kd of 1.0 10-5 m at which the binding is half-saturated is 5.0 10-6 m.

To know more about saturated  refer to

https://brainly.com/question/30550270

#SPJ11

When a protein binds to a ligand with a Kd (dissociation constant) of 1.0 x 10^-5 M, it means that half of the protein is bound to the ligand at that concentration. Therefore, to achieve an equal binding ratio of 0.5, the concentration of the ligand should be equal to the Kd value, which is 1.0 x 10^-5 M.

To answer this question, a bit of background information is needed. Kd is the dissociation constant, which measures the strength of binding between a protein and a ligand. It represents the concentration of ligand at which half of the protein binding sites are occupied by the ligand. In this case, the Kd value is 1.0 x 10^-5 M, which means that at a concentration of 1.0 x 10^-5 M, half of the protein binding sites will be occupied by the ligand. To find the concentration at which half of the protein binding sites are occupied, we can use the following equation: Fractional saturation = [L] / (Kd + [L]). Where [L] is the concentration of ligand and Kd is the dissociation constant.
0.5 = [L] / (1.0 x 10^-5 M + [L])
0.5 x (1.0 x 10^-5 M + [L]) = [L]
[L] = 1.0 x 10^-5 M.

To know more about protein visit :-

https://brainly.com/question/19891933

#SPJ11



how many hydrogen atoms exist in an alkane compound with eight carbon atoms

Answers

Answer: the answer is 18 hydrogen atoms

Explanation:

In an alkane compound, each carbon atom is bonded to four other atoms, including other carbon atoms and hydrogen atoms, in a tetrahedral arrangement. Therefore, the number of hydrogen atoms in an alkane can be calculated using the formula:

H = 2n + 2 - C

where H is the number of hydrogen atoms, n is the number of carbon atoms, and C is the number of other heteroatoms (such as oxygen or nitrogen) in the molecule.

For an alkane with eight carbon atoms, the formula becomes:

H = 2(8) + 2 - 8 = 18

Therefore, there are 18 hydrogen atoms in an alkane compound with eight carbon atoms.

Other Questions
Saved According to Coulomb's law, which ionic compound A-D has the largest electrostatic potential energy (i.e., largest in magnitude)? CaCl2 AlCl3 CoCl2 All have the same potential energy because the chloride anions all have -1 charges which of the four basic shapes predominates in the human figure? Discuss how python lists are similar to arrays and how they differ? Regarding Network Security, which of the following is an example of a zombie?Select one:a. A computer that is infected with some form of malware that allows remote control from a malicious userb. A computer without a userc. A computer that is not known to a networkd. A computer that is so out of date that it is described as shambling along Let f : R R be given byf(x) = { -1, x0{ 1, x>0(i) Prove that f is not continuous using the method of Example 5.1.6. (ii) Find f^-1(1) and, using Proposition 5.1.9, deduce that f is not continuous. a resistor with 750.0 is connected to the plates of a charged ca) What is the energy initially stored in the capacitor?b) What is the electrical power dissipated in the resistor just after the connection is made?c) What is the electrical power dissipated in the resistor at the instant when the energy stored in the capacitor has decreased to half the value calculated in part (A)?apacitor with capacitance 4.26 f. just before the connection is made, the charge on the capacitor is 8.60 mc. an announcement by the government that they will decrease corporate marginal tax rates in the future would increase the attractiveness of macrs depreciation. true or false the goal of managing cholesterol levels to reduce cardiovascular risks may be achieved by Sherry owns a car business. She just received a shipment of Volkswagen SUVs. She paid $60,000 for each vehicle and wants to make 25% on each car sale. What is Sherry's selling price?First convert the markup percentage to decimal by dividing (25 / 100 = 0. 25)Then multiply it by the cost of the vehicle to get the Additional MarginAdditional Margin = $60,000 x 0. 25 = Second, add the Cost Price and the Additional Margin to get the Selling Price. Hint: Do not forget to include the comma to separate the digits and to type the $ symbol! Example: $15,100 Snake StoryBecky moved off of the porch slowly, backing through the door and into the house. She slammed the sliding glass door shut and stood for a moment, relieved to have something solid between her and the snake on the porch.The glass was cool under her hands despite her pounding heart. She tried to slow her breathing. She was safe, at last, inside. Or was she? How had that snake gotten into the screened-in and walled-up back porch. If it could get in there, it's possible it could get inside where she was as well.Becky wasn't someone who was normally skittish about wild things. She'd handled snakes before, picked up lizards many times, caught frogs in the garage and let them go. But snakes seemed to always catch her off guard. They would turn up when least expected. She would see them out of the corner of her eye and just the surprise of it would make her jump; her adrenalin would pump, her heart would thump, and her panic would take over.What was she going to do? She couldn't just stand there waiting for the snake to decide to leave. What if it were venomous? It didn't look like a viper, but it could be. She would need to get out there soon to water the plants."What this requires is some advanced planning," she said out loud to her cat, Louie. "And, I will probably have to go 'once more into the fray' kitty," she said, looking in the cat's direction for emphasis."First things first, though," she said. The cat meowed back. It often did that, having become used to being talked to. "Let's look that fellow up," Becky said walking to her bookshelf."Let's see, snakes," she said, thumbing through her reptile and amphibian identification book. "It's brown and gray, with some black. With a pattern that looks ... there it is," she said thumping the page so hard that Louie jumped. "Not venomous," she said, triumphantly."It's an oak snake, Louie," she returned the book and strode over to her closet. "Not venomous, but I am still not taking chances," she said.She reached into the closet and pulled out her heaviest jacket. It was lined and stuffed thick with lots of padding. Then she found her mittens and a pair of rubber boots. She knew even non-venomous snakes would sometimes threaten to strike when scared. "And that threat would work on me," Becky said aloud again, though Louie had no idea what she was talking about."It's 90 degrees outside, Louie," she said, "so get the iced lemonade ready for when I return."It wasn't much of a plan, but it was the best she could come up with. With her armor on, she was already sweating when she slowly pushed open the sliding glass door and stepped back on to the porch.She was pretty sure the snake would slither away from her presence. She propped open the outside door, and hoped she could shoo the snake in that direction.Sweat dampened her arms and collected on her face. She spread her arms out, and took a few steps toward the snake. There was so much for it to hide beneath. Becky regretted the rocking chairs and all the plant stands between where the snake was in the corner and the door to the outside.At first it seemed like the snake was just going to remain where it was, flicking its tongue every now and then. Becky waved her arms, lunged in its direction, and stomped her feet. It sat there, coiled in the corner, as if perfectly happy to remain there. In a fit of desperation, she picked up one side of the rocking chair the snake was under and let it drop. The snake jumped, raised its head like it was going to strike, and then stayed right where it was."Snake," Becky said, "This is not how it works. You have got to go." The snake moved its head back and forth, swaying a bit, and that gave Becky an idea.She had read somewhere that snakes can "hear" thanks to the ability to process vibrations through the bone in their jaw. This awareness of vibrations in the ground was one reason it was very hard to sneak up on snakes. She quickly realized that getting the snake out was going to be a lot easier than she had thought.Becky turned on the radio she kept on the porch and lowered it to the ground, pointing in the snake's direction. She adjusted the controls so that the bass was as high as it could go. Then, she cranked up the volume. She envisioned the snake swaying to the sounds of "Dancing Queen," by Abba, and then leaving the porch and going far, far away.Coming back into the house, she began peeling off the now damp armaments she had put on earlier. "Louie, there is more than one way to skin a snake," she said laughing. She watched as the snake uncoiled and moved cautiously in the direction of the door. Bending down to pick up Louie, Becky sighed and stroked his head. "'Cause no one ever wants to skin a cat, sweetie."Review the narrative "Snake Story" and answer the question below:How does Louie the cat help develop the character of Becky? Use evidence from the text to support your answer. (5 points) A sample of an ancient sedimentary rock contains slightly less of the isotope carbon-13 than found in inorganic material. One possible explanation for this is that guangdong province faces the _________________. sea ocean gulf sea (sea of japan) china sea Peter Eisenman believes the architect should be: Group of answer choices A client-focused professional An elite intellectual A social reformer A skilled builder. being central to a communication network may result in increased ______________. group of answer choices A. power B. social loafingC. job performance D. distraction an imbalance with the neurotransmitter norepinephrine in the ______ is involved in panic attacks. Which of the following theories of ethical management argues that officers will treat inmates the way they perceive they are being treated by management?a.) "trickle down" theoryb.) "eyeforaneye" theoryc.) "payback" theoryd.) "hierarchical" theory A car wash has two stations, 1 and 2. Assume that the serivce time at station i is exponentially distributed with rate li, for i = 1, 2, respectively. A car enters at station 1. Upon completing the service at station 1, the car proceeds to station 2, provided station 2 is free; otherwise, the car has to wait at station 1, blocking the entrance of other cars. The car exits the wash after the service at station 2 is completed. When you arrive at the wash there is a single car at station 1. (a) Let X; be the service time at station i for the car before you, and Y be the service time at station i for your car, for i = 1, 2. Compute Emax{X2, Y1}. Hint: you may need the formula: max{a,b} = a +b - min{a,b}Previous question In 3 to5 sentences explain how industry led to and supported unbanization The ___________ table determines which users can access which databases from which hosts.a) db. b) sys. c) priv. d) proxies mbti stands for: group of answer choices more better team initiative. make beds turn inventory. meghan brad trainor initiative. myers-briggs type inventory.