Answer:
Hence the total number of possible options available to a person who calls the 800 number is 216.
Step-by-step explanation:
Given that the caller 10 800 telephone system has six options. For each of these four options, three more options are available. For each of these three options, another three options are presented.
Hence the total number of possible options available to a person who calls the 800 number = [tex]6 \times 4 \times 3 \times 3 = 216[/tex].
PLEASE ANSWER MY QUESTION AND EXPLAIN RIGHT
Answer:
$ 1943
Step-by-step explanation:
You two congruent trapezoids.
Find the area of one and multiply by 2.
A = [tex]\frac{base_{1} + base_{2} }{2}[/tex] x h
= [tex]\frac{28+39}{2}[/tex] x 14.5
= [tex]\frac{67}{2}[/tex] x 14.5
= 33.5 x 14.5
= 485.75
= 485.75 x 2 (Two trapezoids)
= 971.50
= 971.50 x 2 (two dollars a square foot)
= 1943.00
Okay, let's calculate the year end adjustment for overhead. Based on the data below, determine the amount of the year end adjustment to cost of goods sold due to over or under allocated manufacturing overhead during the year
Answer:
the adjustment made to the cost of goods sold is -$2,014
Step-by-step explanation:
The computation of the adjustment made to the cost of goods sold is given below:
Total actual overhead expenses $110,822
Less: Total overheads allocated -$112,836
Adjustment made to the cost of goods sold -$2,014
Hence, the adjustment made to the cost of goods sold is -$2,014
The same should be considered
Which of the following expressions has a Value of 6.18???
Answer:
B. -21.012÷ -3.4
its yr correct ans.
hope it helps
stay safe healthy and happy.Someone help me please
9514 1404 393
Answer:
A = (0, 1)B = (3, -2)area = 4.5 square unitsStep-by-step explanation:
Rewriting the equations to make x the subject, we have ...
x = y² -1 . . . . . [eq1]
x = 1 - y . . . . . .[eq2]
At the points of intersection, the difference will be zero.
y² -1 -(1 -y) = 0
y² +y -2 = 0
(y -1)(y +2) = 0
The y-coordinates of points A and B are 1 and -2.
The corresponding x-coordinates are ...
x = 1 -{1, -2} = {1 -1, 1+2} = {0, 3}
Then A = (0, 1) and B = (3, -2).
__
A differential of area can be written ...
(x2 -x1)dy = ((1 -y) -(y² -1))dy = (2 -y -y²)dy
Integrating this over the interval y = [-2, 1] gives the area.
[tex]\displaystyle A=\int_{-2}^1(2-y-y^2)\,dy=\left.(2y-\dfrac{1}{2}y^2-\dfrac{1}{3}y^3)\right|_{-2}^1\\\\=\left(2-\dfrac{1}{2}-\dfrac{1}{3}\right)-\left(2(-2)-\dfrac{(-2)^2}{2}-\dfrac{(-2)^3}{3}\right)=\dfrac{7}{6}+4+2-\dfrac{8}{3}\\\\=\boxed{4.5}[/tex]
The area of the shaded region is 4.5 square units.
In ABC, if CB AC≅ , m∠A = 3x + 18, m∠B = 7x – 58, and m∠C = 2x – 8, find x and the measure of each angle.
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Answer:
x = 19
A = 30°
B = C = 75°
Step-by-step explanation:
In an isosceles triangle, the angles opposite the congruent sides have the same measures.
A = B
3x +18 = 7x -58
76 = 4x . . . . . . . . add 58-4x
19 = x . . . . . . . . . divide by 4
Then the equal angles measure ...
A = B = 3(19) +18 = 75
C = 2(19) -8 = 30
Angles A, B, C measure 75°, 75°, 30°, respectively.
_____
Alternate solution
The sum of angles in a triangle is 180°, so you could write ...
(3x +18) +(7x -58) +(2x -8) = 180
12x = 228 . . . . . add 48
x = 19 . . . . . divide by 12
Solve for y.
5y – 10 = 10
y = [?]
What is y?
Answer:
y = [ 4 ]
Step-by-step explanation:
5y - 10 = 10
+10 +10
5y = 20
/5 /5
y = 4
hope this helps ! ^^
Answer:
[tex]5y-10=10[/tex]
[tex]Add ~10[/tex]
[tex]5y=10+10[/tex]
[tex]5y=20[/tex]
[tex]divide ~by ~5[/tex]
[tex]y=4[/tex]
[tex]ANSWER: y=4[/tex]
-----------------------------
HOPE IT HELPS
HAVE A GREAT DAY!!
At the Fidelity Credit Union, a mean of 5.8 customers arrive hourly at the drive-through window. What is the probability that, in any hour, more than 5 customers will arrive
Answer:
0.5217
Step-by-step explanation:
P(more than 5 customer arrive):
P(X>=6)=1-P(X<=5)= 1-∑x=0x e-λ*λx/x!= 0.5217
In what ratio of line x-y-2=0 divides the line segment joining (3,-1) and (8,9)?
[tex] \large{ \tt{❁ \: USING \: INTERNAL \: SECTION \: FORMULA: }}[/tex]
[tex] \large{ \bf{✾ \: P(x \:, y \: ) = ( \frac{m_{1}x_{2} + m_{2}x_{1}}{m_{1} + m_{2}} \: ,\: \frac{m_{1}y_{2} + m_{2}y_{1}}{m_{1} + m_{2}}) }}[/tex]
[tex] \large{ \bf{⟹ \: ( \frac{8m + 3n}{m + n} , \: \frac{9m -n}{m + n}) }}[/tex]
Since point P lies on the line x - y - 2 = 0 ,[tex] \large{ \bf{ ⟼\frac{8m + 3n}{m + n} - \frac{9m - n}{m + n} - 2 = 0 }}[/tex]
[tex] \large{ \bf{⟼ \: \frac{8m + 3n - 9m + n}{m + n} - 2 = 0 }}[/tex]
[tex] \large{ \bf{⟼ \: \frac{4n - m}{ m + n} - 2 = 0 }}[/tex]
[tex] \large{⟼ \: \bf{ \frac{4n - m}{m + n }} = 2} [/tex]
[tex] \large{ \bf{⟼ \: 4n - m = 2m + 2n}}[/tex]
[tex] \large{ \bf{⟼ \: 4n -2 n = 2m + m}}[/tex]
[tex] \large{ \bf{⟼2n = 3m}}[/tex]
[tex] \large{ \bf{⟼ \: 3m = 2n}}[/tex]
[tex] \large{ \bf{⟼ \: \frac{m}{n} = \frac{2}{3} }}[/tex]
[tex] \boxed{ \large{ \bf{⟼ \: m : \: n = 2: \: }3}}[/tex]
Hence , The required ratio is 2 : 3 .-Hope I helped! Let me know if you have any questions regarding my answer and also notify me , if you need any other help! :)
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In rural Ireland, a century ago, the students had to form a line. The student at the front of the line would be asked to spell a word. If he spelled it correctly, he was allowed to sit down. If not, he received a whack on the hand with a switch and was sent to the end of the line. Suppose the student could spell correctly 60% of the words in the lesson. What is the probability that the student would be able to sit down before receiving four whacks in the hand?
Answer:
The answer is "0.9102"
Step-by-step explanation:
P(student spell correct) = 0.6
P(student spell incorrect)=1-0.6=0.4
X=the pupil will be allowed to sit down after receiving three slaps on the hand Thus, X would assume Value
X=0 (student sit sans getting whacks)
X=1 (student sit down without receiving 1 whack) (student sit down without receiving 1 whack)
X=2 (student take a seat before receiving 2 whacks)
X=3 (student sit down after receiving 3 punches)
[tex]\to P(X)=0.6 \times 0.4^0 +0.6 \times 0.4 + 0.6 \times 0.4 ^2 + 0.6 \times 0.3^3[/tex]
[tex]=0.6 \times 1+0.24 + 0.6 \times 0.09 + 0.6 \times 0.027\\\\=0.6 +0.24 + 0.054 + 0.0162\\\\=0.9102\\\\[/tex]
Which of the following best describes the relationship between angle a and angle bin the image below?
Can you please help me solve this step by step?
Answer:
2/3
Step-by-step explanation:
[tex]2 \frac{1}{4} : \frac{1}{2}[/tex] = [tex]\frac{9}{4} : \frac{1}{2}[/tex]
[tex]\frac{\frac{9}{4} }{\frac{1}{2} }[/tex] = [tex]\frac{3}{x}[/tex]
3 * 1/2 = 9/4x
3/2 = 9/4 x
x = 3/2 ÷ 9/4 = 3/2 * 4/9 = 12/18 = 6/9 = 2/3
You want to be able to withdraw the specified amount periodically from a payout annuity with the given terms. Find how much the account needs to hold to make this possible. Round your answer to the nearest dollar. Regular withdrawal: $1200 Interest rate: 2.5% Frequency monthly Time: 26 years
what is the account balance?
Step-by-step explanation:
principal=?. interest=$1200. rate =2. 5%. time=26 NOW, principal=I×100/T×R= $1200×100/26×2. 5=1846. 15
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Answer:
$275,098.25
Step-by-step explanation:
The principal amount can be found using the annuity formula.
A = P(r/12)/(1 - (1 +r/12)^(-12t))
where A is the monthly payment, P is the principal amount, r is the annual interest rate, and t is the number of years.
Solving for P, we have ...
P = A(12/r)(1 -(1 +r/12)^(-12t)) = 1200(12/0.025)(1 -(1 +.025/12)^(-12·26))
= $275,098.25
The account balance needs to be $275,098.25.
Which statement is true about quadrilateral ABCD with vertices A(2, 8), B(3, 11), C(4, 8), and D(3, 5)?
Answer:
The quadrilateral is a rhombus
Step-by-step explanation:
Given
[tex]A = (2, 8)[/tex]
[tex]B = (3, 11)[/tex]
[tex]C = (4, 8)[/tex]
[tex]D=(3, 5)[/tex]
Required
The true statement
Calculate slope (m) using
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Calculate distance using:
[tex]d= \sqrt{(x_2 - x_1)^2 + (y_2 -y_1)^2}[/tex]
Calculate slope and distance AB
[tex]m_{AB} = \frac{11 - 8}{3 - 2}[/tex]
[tex]m_{AB} = \frac{3}{1}[/tex]
[tex]m_{AB} = 3[/tex] -- slope
[tex]d_{AB}= \sqrt{(3 - 2)^2 + (11 -8)^2}[/tex]
[tex]d_{AB}= \sqrt{10}[/tex] -- distance
Calculate slope and distance BC
[tex]m_{BC} = \frac{8 - 11}{4 - 3}[/tex]
[tex]m_{BC} = \frac{- 3}{1}[/tex]
[tex]m_{BC} = -3[/tex] -- slope
[tex]d_{BC} = \sqrt{(4-3)^2+(8-11)^2[/tex]
[tex]d_{BC} = \sqrt{10}[/tex] --- distance
Calculate slope CD
[tex]m_{CD} = \frac{5 - 8}{3 - 4}[/tex]
[tex]m_{CD} = \frac{- 3}{- 1}[/tex]
[tex]m_{CD} = 3[/tex] -- slope
[tex]d_{CD} = \sqrt{(3-4)^2+(5-8)^2}[/tex]
[tex]d_{CD} = \sqrt{10}[/tex] -- distance
Calculate slope DA
[tex]m_{DA} = \frac{8 - 5}{2 - 3}[/tex]
[tex]m_{DA} = \frac{3}{- 1}[/tex]
[tex]m_{DA} = -3[/tex] -- slope
[tex]d_{DA} = \sqrt{(2-3)^2 + (8-5)^2}[/tex]
[tex]d_{DA} = \sqrt{10}[/tex]
From the computations above, we can see that all 4 sides are equal, i.e. [tex]\sqrt{10}[/tex]
And the slope of adjacent sides are negative reciprocal, i.e.
[tex]m_{AB} = 3[/tex] and [tex]m_{CD} = -3[/tex]
[tex]m_{CD} = 3[/tex] and [tex]m_{DA} = -3[/tex]
The quadrilateral is a rhombus
Using the simple spinner below what is the probability of landing on either 2, 4, or 7?
Answer:
3/10
Step-by-step explanation:
Total possibilities = 10
favourable possibilities = 3
Answer:
A
Step-by-step explanation:
There is a 1 out of 10 chance that it will land on 2.
There is a 1 out of 10 chance that it will land on 4.
There is a 1 out of 10 chance that it will land on 7.
[tex]\frac{1}{10}\cdot3=\frac{3}{10}[/tex] so the anwser is A.
The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.
Answer:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x + 1[/tex]
Required
Complete the table (see attachment)
When x = -5
[tex]f(-5) = 5 * -5 + 1 = -24[/tex]
When x = -1
[tex]f(-1) = 5 * -1 + 1 = -4[/tex]
When x = 2
[tex]f(2) = 5 * 2 + 1 = 11[/tex]
When x = 3
[tex]f(3) = 5 * 3 + 1 = 16[/tex]
When x = 4
[tex]f(4) = 5 * 4 + 1 = 21[/tex]
So, the table is:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
ok i think you guys can do it
[tex] {64}^{ \frac{2}{3} } \div {27}^{ \frac{5}{3} } \times 54 \\ = > \: {({2}^{3} )}^{ \frac{2}{3} } \div ({{3}^{3}})^{ \frac{5}{3} } \times 54 \\ = > \: {2}^{2} \div {3}^{5} \times 54 \\ = > \: 4 \div 243 \times 54 \\ = > \: 4 \div 13122 \\ = > \: \frac{4}{13122} \\ = > \: \frac{2}{6561} [/tex]
Hope it helps!!!!!!!!!!
What is center of a circle whose equation is x2
Answer:
I think it is 160 x2 so you would probably divide 160 by x2 which would 144
Step-by-step explanation:
Urgent help!!!
*Picture included
Answer:
3x+4
Step-by-step explanation:
When you factor 9x^2+24x+16, it factors to (3x+4)^2
Factoring 9x^2 - 16 factors to (3x+4)(3x-4)
Therefore the common factor is 3x+4
I hope this helps!
In an international film festival, a penal of 11 judges is formed to judge the best film. At last two films FA and FB were considered to be the best where the opinion of judges got divided. Six judges where in favor of FA whereas five in favor of FB. A random sample of five judges was drawn from the panel. Find the probability that out of five judges, three are in favor of film FA.
Answer:
The answer is "0.4329 ".
Step-by-step explanation:
P( three in favor of FA)
Select 3 out of 6 FA supporters then select 2 out of 5 FB supportive judges
[tex]=\frac{^{6}_{C_{3}}\times ^{5}_{C_{2}}}{^{11}_{C_{5}}}\\\\=\frac{\frac{6!}{3!(6-3)!}\times \frac{5!}{2!(5-2)!}}{\frac{11!}{5!(11-5)!}}\\\\=\frac{\frac{6!}{3! \times 3!}\times \frac{5!}{2! \times 3!}}{\frac{11!}{5! \times 6!}}\\\\=\frac{\frac{6 \times 5 \times 4 \times 3!}{3 \times 2 \times 1\times 3!}\times \frac{5 \times 4 \times 3!}{2 \times 1 \times 3!}}{\frac{11 \times10 \times 9 \times 8 \times 7 \times 6! }{5 \times 4 \times 3 \times 2 \times 1 \times 6!}}\\\\[/tex]
[tex]=\frac{ (5 \times 4) \times(5 \times 2)}{(11 \times 3 \times 2 \times 7 )}\\\\=\frac{ 20 \times 10 }{(11 \times 42)}\\\\=\frac{ 200 }{462}\\\\=\frac{100 }{231}\\\\=0.4329[/tex]
Which of the following shows the graph of y=-(2)^3 – 1?
Answer:
The first graph
Step-by-step explanation:
Given
[tex]y = -(2)^x - 1[/tex]
Required
The graph
Set the exponent part to get the minimum/maximum of the graph
So, we have:
[tex]y = 0 - 1[/tex]
[tex]y = - 1[/tex]
The above implies that the curve passes through the y-axis at [tex]y = - 1[/tex].
By comparing the two graphs, we can conclude that the first represents [tex]y = -(2)^x - 1[/tex] because it passes through [tex]y = - 1[/tex]
Which proportion resulted in the equation 3a = 7b?
StartFraction 3 over a EndFraction = StartFraction 7 over b EndFraction
StartFraction 3 over b EndFraction = StartFraction 7 over a EndFraction
StartFraction a over b EndFraction = StartFraction 3 over 7 EndFraction
StartFraction 3 over 7 EndFraction = StartFraction 3 over b EndFraction
Answer:
The correct one is 3 over b equals 7 over a
Answer:
3/b = 7/a
Step-by-step explanation:
I took it on Edge
I need help solving this problem. Thanks
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Answer:
f = 2T/(v1 +v2)
Step-by-step explanation:
Multiply by the inverse of the coefficient of f.
[tex]T=f\cdot\dfrac{v_1+v_2}{2}\\\\f=\dfrac{2T}{v_1+v_2}[/tex]
There are four different colored balls in a bag. There is equal probability of selecting the red, black, green, or blue ball.What is the expected value of getting a green ball out of 20 experiments with replacement?
Answer:
The expected value is of 5 green balls.
Step-by-step explanation:
For each experiment, there are only two possible outcomes. Either it is a green ball, or it is not. Since there is replacement, the probability of a green ball being taken in an experiment is independent of any other experiments, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
20 experiments
This means that [tex]n = 20[/tex]
There is equal probability of selecting the red, black, green, or blue ball.
This means that 1 in 4 are green, so [tex]p = \frac{1}{4} = 0.25[/tex]
What is the expected value of getting a green ball out of 20 experiments with replacement?
[tex]E(X) = np = 20*0.25 = 5[/tex]
The expected value is of 5 green balls.
The expected value of getting a green ball out of 20 experiments with replacement is 5.
What is a binomial distribution?The binomial probability distribution of the number of successes in a sequence of n independent experiments is the binomial distribution with parameters n and p.
As it is given that the probability of all the balls coming out of the bag is equal. Therefore, the probability of a green ball coming can be written as,
[tex]\text{Probability of Green Ball} = 0.25[/tex]
Also, we can write the probability of not getting a green ball can also be written as,
[tex]\rm Probability(\text{Not coming Green Ball}) = P(Red\ ball)+P(Black\ ball)+P(Blue\ ball)[/tex]
[tex]=0.25+0.25+0.25\\\\=0.75[/tex]
Now, as there are only two outcomes possible, therefore, the distribution of the probability is a binomial distribution. And we know that the expected value of a binomial distribution is given as,
[tex]\rm Expected\ Value, E(x) = np[/tex]
where n is the number of trials while p represents the probability.
Now, substituting the values, we will get the expected value,
[tex]\rm Expected\ Value, E(Green\ ball) = 20 \times 0.25 = 5[/tex]
Hence, the expected value of getting a green ball out of 20 experiments with replacement is 5.
Learn more about Binomial Distribution:
https://brainly.com/question/12734585
How do you solve this problem and what did you do to gain the answer 1/64+5/8-3/32=?
Answer:
the answer is 35/64(in fraction) but in decimals it's 0.55
The probability that a tennis set will go to a tiebreaker is 13%. In 120 randomly selected tennis sets, what is the mean and the standard deviation of the number of tiebreakers
Answer:
[tex]\mu = 15.6[/tex]
[tex]\sigma =3.684[/tex]
Step-by-step explanation:
Given
[tex]p =13\%[/tex]
[tex]n = 120[/tex]
Solving (a): The mean
This is calculated as:
[tex]\mu = np[/tex]
So, we have:
[tex]\mu = 13\% * 120[/tex]
[tex]\mu = 15.6[/tex]
Solving (b): The standard deviation
This is calculated as:
[tex]\sigma = \sqrt{\mu * (1 - p)[/tex]
So, we have:
[tex]\sigma = \sqrt{15.6 * (1 - 13\%)[/tex]
[tex]\sigma = \sqrt{15.6 * 0.87[/tex]
[tex]\sigma =\sqrt{ 13.572[/tex]
[tex]\sigma =3.684[/tex]
Which choice is equivalent to √3 *√8*√5
A. 2√30
B. 4√30
C. 10√12
D. 24√5
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { A. \:2 \sqrt{30} }}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:EXPLANATION:}}}[/tex]
[tex] = \sqrt{3} \times \sqrt{8} \times \sqrt{5} [/tex]
[tex] = \sqrt{3 \times 2 \times 2 \times 2 \times 5} [/tex]
[tex] = \sqrt{ ({2})^{2} \times 2 \times 3 \times 5} [/tex]
[tex] = 2 \sqrt{2 \times 3\times 5} [/tex]
[tex] = 2 \sqrt{30} [/tex]
Note:[tex] \sqrt{ ({a})^{2} } = a[/tex]
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
Answer:
A. 2√30
Step-by-step explanation:
[tex] \small \sf \: \sqrt{3} \times \sqrt{8} \times \sqrt{5} \\ [/tex]
split √8
[tex] \small \sf \leadsto \sqrt{3 × 2 × 2 × 2 × 5} [/tex]
[tex] \small \sf \leadsto \: 2 \sqrt{2 \times 3 \times 5} [/tex]
[tex] \small \sf \leadsto \: 2 \sqrt{30} [/tex]
SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi/h. At what rate is the distance between the cars increasing two hours later
Answer:
The rate at which the distance between the cars increasing two hours later=52mi/h
Step-by-step explanation:
Let
Speed of one car, x'=48 mi/h
Speed of other car, y'=20 mi/h
We have to find the rate at which the distance between the cars increasing two hours later.
After 2 hours,
Distance traveled by one car
[tex]x=48\times 2=96 mi[/tex]
Using the formula
[tex]Distance=Time\times speed[/tex]
Distance traveled by other car
[tex]y=20\times 2=40 mi[/tex]
Let z be the distance between two cars after 2 hours later
[tex]z=\sqrt{x^2+y^2}[/tex]
Substitute the values
[tex]z=\sqrt{(96)^2+(40)^2}[/tex]
z=104 mi
Now,
[tex]z^2=x^2+y^2[/tex]
Differentiate w.r.t t
[tex]2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}[/tex]
[tex]z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}[/tex]
Substitute the values
[tex]104\frac{dz}{dt}=96\times 48+40\times 20[/tex]
[tex]\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}[/tex]
[tex]\frac{dz}{dt}=52mi/h[/tex]
Hence, the rate at which the distance between the cars increasing two hours later=52mi/h
A boy had 3 apples and lost one, how many does he have now
Step-by-step explanation:
i would love to say 2 but the word had shows that he does not have 3 apples anymore so the answer is either
0 or -1
The number of apples left after taking the 1 apple from 3 apples by a person is 2 apples.
What is subtraction?Subtraction stands for the resultant number, which exists acquired by taking the difference of a number from another number.
Let a number be subtracted from the number b. Then the consequent number after subtracting b from a will be,
d = b - a
Here, (a, b) exists the real numbers.
It exists given that there exist 3 apples. 1 apple stand was taken. Let's assume after taking the 3 apples, that there exist x apples remaining.
As there exist a total of 3 apples and 1 apple stand taken, then to estimate the number of apples left, we must subtract 1 apple from 3 apples.
Therefore, the total apples left exist,
x = 3 - 1
x = 2
To learn more about subtraction operation
https://brainly.com/question/26883387
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Which of the following is NOT true of a perpendicular bisect or?
Answer:
The forth option
It forms a right angle with the segment.
Two cell phone companies charge a flat fee plus an added cost for each minute or part of a minute used. The cost is represented by C and the number of minutes is represented by t.
Call-More: C = 0.40t + 25 Talk-Now: C = 0.15t + 40
Answer:
The call more is cheaper than talk-now.
Step-by-step explanation:
The companies charge a flat fee plus an added cost for each minute or part of a minute used for two companies are as follows :
Call-More: C = 0.40t + 25 Talk-Now: C = 0.15t + 40
We need to find which company is cheaper if a customer talks for 50 minutes.
For call more,
C = 0.40(50) + 25 = 45 units
For talk-now,
C = 0.15(50) + 40 = 47.5 units
So, it can be seen that call more is cheaper than talk-now.