Answer: 7/12 + 2/3q
Step-by-step explanation:
[tex]\frac{11}{12} - \frac{1}{6}q + \frac{5}{6}q - \frac{1}{3}[/tex] Combine like terms subtract 1/3 from 11/12 and add -1/6q and 5/6q.
[tex]\frac{11}{12} - \frac{1}{3} = \frac{7}{12}[/tex]
[tex]-\frac{1}{6}q + \frac{5}{6} q = \frac{4}{6}[/tex]q = 2/3 q
The distance round a rectangular cafe 35m,the ratio of the length of the cafe to it's width is 3:2 calculate the dimension of the cafe
Hey there! I'm happy to help!
Let's create a basic rectangle with this length to width ratio.
Two sides are 3 and two of them have a length of 2. This would give us a perimeter (distance around) of 10.
We want to find a rectangle with a perimeter of 35 meters with this same ratio. What we can do is multiply all of the dimensions of our first rectangle by 3.5 (to get our perimeter of 10 to 35, we multiply by 3.5).
3×3.5=10.5
2×3.5=7
If we simplify 10.5:7, we have 3:2, and the perimeter of a rectangle with a length of 10.5 and a width of 7 would equal 35 meters.
Have a wonderful day! :D
Explain how to identify if the graph of a relation is a function or not
Answer:
[see below]
Step-by-step explanation:
A function is a relation where one domain value is assigned to exactly one range.
An x-value in a function must not repeat.
One way to see if a graph is a function is to use a vertical line test. If the line passes trough the line twice, then it is not a function. On a table, check the x-value column or row. If any of the numbers repeat, then it is not a function. On a mathematical map, check to see if the arrows from a domain number points to one range value on the other side. If it points to two range numbers, then it is not a function.Hope this helps.
10. Which relation is a function?
la A (8, -4), (8, 4), (6, -3), (6, 3).
(0,0)
B (4,7), (8,5), (6,4), (5, 3), (4, 2)
C (0,0), (1, 1), (2, 2), (3, 3), (4,7)
D (0,0), (1,0), (1, 1), (2, 1), (1, 2)
Answer:
C. Why? No repeating x values.
Point Mis the midpoint of AB. AM = 3x + 3, and AB= 83 – 6.
What is the length of AM?
Enter your answer in the box.
units
Answer:
AM= Half of AB
or, 3x+3=(8x-6)/2
or, 6x+6=8x-6
or, 2x=12
Therefore,x=6
so,AM=3*6+3=21
So the units is 21
Answer:
[tex]\Huge \boxed{21}[/tex]
Step-by-step explanation:
AM = 3x + 3
AB = 8x - 6
Point M is the midpoint of AB.
So, AM = AB/2
3x + 3 = (8x - 6)/2
Multiplying both sides by 2.
2(3x + 3) = 8x - 6
Expanding brackets.
6x + 6 = 8x - 6
Subtracting 6x from both sides.
6 = 2x - 6
Adding 6 to both sides.
12 = 2x
Dividing both sides by 2.
6 = x
Let x = 6 for the length of AM.
3(6) + 3
18 + 3
21
The conjugate of 2+5 i (is) -2 -5 i
True or false
Answer:
False the conjugate of 2+5i is 2-5i .
Step-by-step explanation:
Hope it will help you :)
Which statement is true? Step by step.
Answer:
I believe the answer is A.
Step-by-step explanation:
If there are 13 daises per bouquet, that means one bouquet is all daises. The other bouquet has 30 flowers. 30-13 is 17 which means there are 17 other flowers rather than daises. 17 is greater than 13 by 4 which is not that much. Therefore I think the answer is letter A.
Answer:
The correct answer is A. The probability of randomly selecting a daisy from Bouquet S is less than the probability of randomly selecting a daisy from bouquet T.
Step-by-step explanation:
We are told that Bouquet S contains 30 flowers and 13 of those flowers are daisies. Therefore, the probability of selecting a daisy from Bouquet S can be modeled by:
13/30, which is greater than 1/3 but less than 1/2
We are also told that Bouquet T contains 13 flowers and 13 daises. From this information, we can conclude that all of the flowers in Bouquet T are daises, or the probability can be modeled by:
13/13 = 1
Therefore, because the probability of selecting a daisy from Bouquet S is 13/30 and the probability of selecting a daisy from Bouquet T is 1, we can conclude that, as option A states, the probability of selecting a daisy from Bouquet S is less than the probability of selecting a daisy from Bouquet T.
Hope this helps!
A quality control manager is concerned about variability of the net weight of his company’s individual yogurt cups. To check the consistency, he takes a random sample of sixteen 6-ounce yogurt cups and finds the mean of the sampled weights to be 5.85 ounces and the sample standard deviation to be 0.2 ounce. Test the hypotheses H0: µ ≥ 6 Ha: µ < 6 at the 5% level of significance. Assume the population of yogurt-cup net weights is approximately normally distributed. Based on the results of the test, will the manager be satisfied that the company is not under-filling its cups? State the decision rule, the test statistic, and the manager’s decision.
Answer:
Decision rule : The p-value < [tex]\alpha[/tex] so the null hypothesis is rejected
The test statistics is [tex]t = -2.8[/tex]
The manger will not be manager be satisfied that the company is not under-filling since the company is under-filling its cups
Step-by-step explanation:
From the question we are told that
The sample size is n = 16
The sample mean is [tex]\= x = 5.85[/tex]
The standard deviation is [tex]\sigma = 0.2[/tex]
The null hypothesis is [tex]H_o : \mu \ge 6[/tex]
The alternative hypothesis is [tex]H_a : \mu < 6[/tex]
The level of significance is [tex]\alpha = 0.05[/tex]
Generally the test statistics is mathematically represented as
[tex]t = \frac{ \= x - \mu }{ \frac{\sigma }{ \sqrt{n} } }[/tex]
=> [tex]t = \frac{ 5.86 - 6 }{ \frac{ 0.2}{ \sqrt{ 16} } }[/tex]
=> [tex]t = -2.8[/tex]
The p-value is obtained from the z-table the value is
[tex]p-value = P(Z < -2.8 ) = 0.0025551[/tex]
[tex]p-value = 0.0025551[/tex]
Given that the [tex]p-value < \alpha[/tex] we reject the null hypothesis
Hence there is sufficient evidence to support the concern of the quality control manager. and the manger will not be satisfied that since the test proof that the company is under-filling its cups
Star Wars land encompasses an area of 14.0 acres. [1.00 acre = 4046.86m2]. If Star Wars land were made into a circle, what would be the radius of Star Wars land?
Answer:
The answer is 134.29 mStep-by-step explanation:
First of all we need to convert 14.0 acres to m²
1.00 acre = 4046.86 m²
14.0 acres = 14 × 4046.86 = 56656.04 m²
Area of a circle = πr²
where
r is the radius
To find the radius substitute the value for the area into the above formula and solve for the radius
That's
[tex]56656.04 = \pi {r}^{2} [/tex]
Divide both sides by π
We have
[tex] {r}^{2} = \frac{56656.04}{\pi} [/tex]
Find the square root of both sides
[tex]r = \sqrt{ \frac{56656.04}{\pi} } [/tex]
r = 134.29139
r = 134.29 m to 2 decimal places
Hope this helps you
Answer:
we have no way of knowing
Step-by-step explanation:
it could be a jedi mind trick.
Find an equation of the vertical line passing through the point (-4, 2). x=
Answer:
x = -4
Step-by-step explanation:
This vertical line is x = -4. That's all we need here.
Based only on the information given in the diagram, which congruence
theorems or postulates could be given as reasons why JOY = LIM
Answer:
Option B
Option E
Step-by-step explanation:
By the use of following postulates we can prove the two right triangles to be congruent.
1). HA - [Equal hypotenuse and an cute angles]
2). LL - [Two legs should be equal]
3). LA - [One leg and one angle must be equal]
4). ASA - [Two angles and the side containing these angles should be equal]
In the given right triangles,
1). OJ ≅ IL
2). ∠O ≅ ∠I
3). ∠J ≅ ∠L
Therefore, two postulates HA, ASA will be applicable for the congruence of the two triangles given.
Options A and E will be the answer.
Answer:
asa, ha, aas
Step-by-step explanation:
Randomly selected 110 student cars have ages with a mean of 8 years and a standard deviation of 3.6 years, while randomly selected 75 faculty cars have ages with a mean of 5.3 years and a standard deviation of 3.7 years.
1. Use a 0.02 significance level to test the claim that student cars are older than faculty cars.
Is there sufficient evidence to support the claim that student cars are older than faculty cars?
A. Yes.
B. No.
2. Construct a 98% confidence interval estimate of the difference μ1âμ2, where μ1 is the mean age of student cars and μ is the mean age of faculty cars.
Answer:
1. Yes, there is sufficient evidence to support the claim that student cars are older than faculty cars.
2. The 98% confidence interval for the difference between the two population means is [1.432 years, 3.968 years].
Step-by-step explanation:
We are given that randomly selected 110 student cars to have ages with a mean of 8 years and a standard deviation of 3.6 years, while randomly selected 75 faculty cars to have ages with a mean of 5.3 years and a standard deviation of 3.7 years.
Let [tex]\mu_1[/tex] = mean age of student cars.
[tex]\mu_2[/tex] = mean age of faculty cars.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu_1 \leq \mu_2[/tex] {means that the student cars are younger than or equal to faculty cars}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu_1>\mu_2[/tex] {means that the student cars are older than faculty cars}
(1) The test statistics that will be used here is Two-sample t-test statistics because we don't know about the population standard deviations;
T.S. = [tex]\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)} {s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }[/tex] ~ [tex]t_n_1_+_n_2_-_2[/tex]
where, [tex]\bar X_1[/tex] = sample mean age of student cars = 8 years
[tex]\bar X_2[/tex] = sample mean age of faculty cars = 5.3 years
[tex]s_1[/tex] = sample standard deviation of student cars = 3.6 years
[tex]s_2[/tex] = sample standard deviation of student cars = 3.7 years
[tex]n_1[/tex] = sample of student cars = 110
[tex]n_2[/tex] = sample of faculty cars = 75
Also, [tex]s_p=\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }[/tex] = [tex]\sqrt{\frac{(110-1)\times 3.6^{2}+(75-1)\times 3.7^{2} }{110+75-2} }[/tex] = 3.641
So, the test statistics = [tex]\frac{(8-5.3)-(0)} {3.641 \times \sqrt{\frac{1}{110}+\frac{1}{75} } }[/tex] ~ [tex]t_1_8_3[/tex]
= 4.952
The value of t-test statistics is 4.952.
Since the value of our test statistics is more than the critical value of t, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we support the claim that student cars are older than faculty cars.
(2) The 98% confidence interval for the difference between the two population means ([tex]\mu_1-\mu_2[/tex]) is given by;
98% C.I. for ([tex]\mu_1-\mu_2[/tex]) = [tex](\bar X_1-\bar X_2) \pm (t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} })[/tex]
= [tex](8-5.3) \pm (2.326 \times 3.641 \times \sqrt{\frac{1}{110}+\frac{1}{75} })[/tex]
= [tex][2.7 \pm 1.268][/tex]
= [1.432, 3.968]
Here, the critical value of t at a 1% level of significance is 2.326.
Hence, the 98% confidence interval for the difference between the two population means is [1.432 years, 3.968 years].
the length of the shadow of a pole on level ground increases by 90m when the angle of elevation of the sun changes from 58 degree to 36 degree calculate correct to three significant figure the height of the pole
Step-by-step explanation:
(A) Let a triangle be formed with height of pole h, length of base b and angle of elevation 58°. (Due to lack of a figure).
Tan 58° = h / b = 1.6
(B) Let another triangle be formed with height of pole h, length of base (b + 90) and angle of elevation 36°. (Due to lack of a figure).
Tan 36° = h / (b + 90) = 0.72
(C) Simplifying the two equations :
1.6b = 0.72b + 64.8
b = 64.8 / 0.88 = 73.6 m
h (height of pole) = 1.6 * 73.6 = 117.76 m
A piece of rope falls out of a hot air
balloon from a height of 5,184 ft. If the
equation for height as a function of time
is h(t) = -16t2 - initial height where t is
time in seconds and h(t) is height in feet,
how many seconds will it take for the
piece of rope to hit the ground?
==========================================
Explanation:
The equation should be h(t) = -16t^2 + (initial height). If you subtract off the initial height, then you'll have a negative starting height, which is not correct. Try plugging t = 0 into h(t) = -16t^2 - (initial height) and you'll see what I mean.
The initial height is 5184. We want to find the t value when h(t) = 0. So we want to find the time value when the height is 0.
--------------
h(t) = -16t^2 + (initial height)
h(t) = -16t^2 + 5184
0 = -16t^2 + 5184
16t^2 = 5184
t^2 = 5184/16
t^2 = 324
t = sqrt(324)
t = 18
It takes 18 seconds for the rope to hit the ground.
A building company claims that 70% of all new houses they build are finished within 3 weeks. A study show that, over 45 new houses, only 20 have been done in 3 weeks. Does the company claim valid at a level of significance of 0.05 and 0.01
Answer:
Calculated z= 3.515
The Z∝/2 = ±1.96 for ∝= 0.05
The Z∝/2 = ± 2.58 for ∝= 0.01
Yes the company claims valid at a level of significance of 0.05 and 0.01
Step-by-step explanation:
Here p1= 70% = 0.7
p2= 20/45= 0.444 q= 1-p= 1-.444= 0.56
The level of significance is 0.05 and 0.01
The null and alternative hypotheses are
H0; p1= p2 Ha: p1≠p2
The test statistic used here is
Z= p1-p2/ √pq/n
Z= 0.7-0.44/ √ 0.44*0.56/45
z= 0.26/ √0.2464/45
z= 3.515
The Z∝/2 = ±1.96 for ∝= 0.05
The Z∝/2 = ± 2.58 for ∝= 0.01
For the significance level 0.05 reject null hypothesis
For the significance level 0.01 reject null hypothesis
Yes the company claims valid at a level of significance of 0.05 and 0.01
which symbol will make |-8|?|-10|
>
<
=
which property is shown by 4+(5+6)=(4+5)+6?
commutative property of addition
distributive property
additive Indentity
associative property of addition
Answer:
[tex]|-8|<|-10| \Longleftrightarrow 8 < 10[/tex]
[tex]\text{Which property is shown by } 4+(5+6)=(4+5)+6?[/tex]
[tex]\text{It is the associative property of addition}[/tex]
You can group the addends in any combination and it won't change the result.
Ms. Ironperson and Mr. Thoro are making Avenger posters to give children when they visit Avenger Academy. Ms. Ironperson has completed 12 posters and will complete 6 more per day. Mr. Thoro has not started yet but can make 12 per day. At some point Mr. Thoro will catch up and both will have finished the same number of posters. When this does happen, how many posters will each Avenger have completed? If x denotes the number of days and y denotes the number of posters, what are the equations needed to solve this problem? Group of answer choices
Answer:
The equations needed to solve this problem are:
y = 12 + 6x
y = 12x
The number of posters completed by each Avenger will be 24.
Step-by-step explanation:
The information provided are:
Ms. Ironperson has completed 12 posters and will complete 6 more per day.
Mr. Thoro has not started yet but can make 12 per day.
The variable x denotes the number of days and y denotes the number of posters.
So, after x day the number of poster completed by Ms. Ironperson will be:
y = 12 + 6x
And after x day the number of poster completed by Mr. Thoro will be:
y = 12x
Thus, the equations needed to solve this problem are:
y = 12 + 6x
y = 12x
Compute the value of x as follows:
12x = 12 + 6x
6x = 12
x = 2
The number of posters completed by each Avenger is:
y = 12x = 12 × 2 = 24
Thus, the number of posters completed by each Avenger will be 24.
Select the fraction with the largest value, 1/5, 1/8, or 3/4
Which ordered pairs are in the relation {(x, y) | x > y 1} on the set {1, 2, 3, 4}?
Answer:
R = { ( 3 , 1 ) , (4 , 1) , (4 , 2) }
Step-by-step explanation:
Which ordered pairs are in the relation {(x, y) | x > y + 1} on the set {1, 2, 3, 4}
Assuming that:
R should be the set of real numbers such that:
R = { (x,y) | x > y + 1} on the set {1, 2, 3, 4}
Then:
The ordered pairs for the relation can be computed as:
R = { ( 3 , 1 ) , (4 , 1) , (4 , 2) }
What is the value of x that makes the given equation true? x−3x=2(4+x)
Answer:
x = -2
Step-by-step explanation:
x−3x=2(4+x)
Distribute
x - 3x = 8 +2x
Combine like terms
-2x = 8+2x
Subtract 2x from each side
-2x-2x = 8+2x-2x
-4x = 8
Divide by -4
-4x/-4 = 8/-4
x = -2
Answer:
x-3x=2(4+x)
-2x=8+2x
-2x-2x=8
-4x=8
x=8/-4
x=-2
hope it helps budy x=2
mark me brainliest
Estimate the cost of painting a homecoming float if the area to be painted is 9 feet by 16 feet and a quart of paint that covers 53 square feet costs $11.99
Answer:
$32.58
Step-by-step explanation:
The area needed to be painted = 9 feet × 16 feet = 144 ft². The cost of painting a 53 ft² room is a quart of paint which costs $11.99, therefore the quart needed to paint 144 ft² area is:
[tex]Number\ of \ quart=\frac{144\ ft^2}{53\ ft^2} =2.717\ quart\\[/tex]
Since one quart cost $11.99, therefore the cost of 2.717 quart is:
Cost = 2.717 × $11.99 = $32.58
It would cost $32.58 to paint a 9 feet by 16 feet
Delilah drew 3 points on her paper. When she connects these points,must they form a triangle? Why or why not?
If the three points all fall on the same straight line, then a triangle will not form. Instead, a line will. We call these points to be collinear.
If the points aren't collinear, then a triangle forms.
Answer:
No.
Step-by-step explanation:
The points may be in a straight line, and that doesn't form a triangle.
I need help, I'm completely lost
Answer:
alpha = 2
beta = -6
Step-by-step explanation:
let everything inside the ln be 'a'
use the chain rule to to differentiate ln a with respect to a
since the differentiation of lnx is 1/x , the differentiation of lna will be 1/a
after the differentiation, you will get: [tex]\frac{1}{a}[/tex] X [tex]\frac{d[(x+1)^{2}X (2x-1)^{2} ] }{dx}[/tex]
you need to use the product rule to differentiate the second part, then multiply 1/a by both the equations being added
replace a with its actual value
you will get [tex]\frac{2}{x + 1}[/tex] and [tex]\frac{-6}{2x -1}[/tex]
by comparing it to the given equation, we get α = 2 and β = -6
anyone know this answer −4y−4+(−3)
Answer:
− 4 y − 7
Step-by-step explanation:
Remove parentheses.
− 4 y − 4 − 3
Subtract 3 from − 4
− 4 y − 7
.
On-the-Go Phone Company has two monthly plans for their customers. The EZ Pay Plan costs $0.15 per minute. The 40 to Go Plan costs $40 per month plus $0.05 per minute.
Write an expression that represents that monthly bill for x minutes on the EZ Pay Plan.
Answer:
Ok, the EZ plan can be written as:
C1(x) = $0.15*x
where x is the number of minutes used in the whole Month.
The 40 to Go Plan can be written as:
C2(x) = $0.05*x + $40.
So we have two linear relationships.
The Ez plan has a larger slope, but has no y-intercept.
So we now can find the number of minutes needed to have the exact monthly cost in each plan:
C1(x) = C2(x)
$0.15*x = $0.05*x + $40
($0.15 - $0.05)*x = $40
$0.10*x = $40
x = $40/$0.10 = 400.
So if in one month, you use exactly 400 minutes, you will pay exactly the same wich each plan.
Now, if you speak less than 400 minutes, is better to use the EZ Pay Plan, because it has o y-intercept, and is more efficient for lower values of x.
If you will use more than 400 minutes per month, then the 40 to Go Plan is better, because the slope is smaller.
lisa goes to school for 7 hours per day works 3 hours per day and sleeps 8 hours per day. what is the ratio of hours lisa works to hours lisa sleeps?
Answer:
ratio of hours lisa works to hours lisa sleeps= 3:8
Step-by-step explanation:
lisa goes to school for 7 hours per day lisa works 3 hours per day
Lisa sleeps 8 hours per day.
For the ratio of hours lisa works to hours lisa sleeps
ratio of hours lisa works to hours lisa sleeps= hours Lisa works/hours Lisa sleeps
ratio of hours lisa works to hours lisa sleeps= 3/8
ratio of hours lisa works to hours lisa sleeps= 3:8
. A normal population has a mean of 80.0 and a standard deviation of 14.0. a. Compute the probability of a value between 75.0 and 90.0. b. Compute the probability of a value of 75.0 or less. c. Compute the probability of a value between 55.0 and 70.0. 19. Suppose the Internal Revenue Service reported that the mean
Answer:
a. The probability of a value between 75.0 and 90.0 is 0.40173
b. The probability of a value of 75.0 or less is 0.35942
c. The probability of a value between 55.0 and 70.0 is 0.19712
Step-by-step explanation:
To solve for this we make use of the z score formula.
z = (x-μ)/σ,
where
x = raw score
μ = the population mean
σ = the population standard deviation.
a. Compute the probability of a value between 75.0 and 90.0.
When x = 75
μ =80.0 and σ = 14.0.
z = (x - μ)/σ
z = 75 - 80/ 14
z = -0.35714
z = -0.36 to 2 decimal places
Using the z score table to find the probability
P(x = 75) = P(z = -0.36)
= 0.35942
For x = 90
z = 90 - 80/14
z = 0.71429
z = 0.71 to 2 decimal place
Using the z score table to find the probability
P(x = 90) = P(z = 0.71)
= 0.76115
The probability of a value between 75.0 and 90.0 is:
75 < x < 90
= P( x = 90) - P(x = 75)
= 0.76115 - 0.35942
= 0.40173
Therefore, probability of a value between 75.0 and 90.0 is 0.40173
b. Compute the probability of a value of 75.0 or less.
For x = 75
From the question, we know that
mean of 80.0 and a standard deviation of 14.0.
z = (x - μ)/σ
z = 75 - 80/ 14
z = -0.35714
z = -0.36 approximately to 2 decimal places.
P-value from Z-Table:
P(x ≤ 75) = 0.35942
c. Compute the probability of a value between 55.0 and 70.0.
For x = 55
From the question, we know that
mean of 80.0 and a standard deviation of 14.0.
z = (x - μ)/σ
z = 55 - 80/ 14
z = -1.78571
z = -1.79 approximately to 2 decimal places
Using the z score table to find the probability
P(x = 55) = P(z = -1.79)
= 0.036727
For x = 70
z = 70 - 80/14
z = -0.71429
z = - 0.71 approximately to 2 decimal place.
Using the z score table to find the probability
P(x = 70) = P(z = -0.71)
= 0.23885
The probability of a value between 55.0 and 70.0 is:
55 < x < 70
= P( x = 70) - P(x = 55)
= P( z = -0.71) - P(z = -1.79)
= 0.23885 - 0.03673
= 0.19712
-3=9(5-2k)/5 Show your work
Answer:
K=3.333
Step-by-step explanation:
-3=9(5-2k)/5
-3=45-18k/5
-15=45-18k
18k=60
K=60/18
K=3.3333
What's the value of x in the figure? A) 78° B) 57° C) 76° D) 33°
A)78°
135°+a° =180°
a°=45°
57°+x°+a°=180°
57°+x°+45°=180°
102°+x°=180°
x°=180°-102°
x°=78°
Which of the following is the y-intercept of:
2 y = x-8 ?
(0.4)
(-4.0)
(4,0)
(0,4)
PLZ HELP I NEED THE ANSWER QUICK
[tex](0,-4)[/tex] fits the linear equation perfectly.
Hope this helps.
Answer:
the y-intercept is the point (0, -4) on the plane
Step-by-step explanation:
In order to find the y-intercept, write the equation in "slope intercept form" solving for "y":
[tex]2\,y=x-8\\y=\frac{x-8}{2} \\y=\frac{x}{2} -\frac{8}{2} \\y=\frac{x}{2} -4[/tex]
Recall now that the y-intercept is the value at which the line crosses the y-axis (when x = 0), therefore:
[tex]y=\frac{x}{2} -4\\y=\frac{0}{2} -4\\y=-4[/tex]
So the y-intercept is the point (0, -4) on the plane.
What is the value of 30-2(7+2)-1
Answer: 11
Step-by-step explanation:
30 - 2(7+2)- 1 Distribute or solve parentheses
30 - 14 -4 - 1
30 - 19 = 11