Simplify. Express your answer using positive exponents. w^3 x w^5

A function statement is contained within the function block. A function block is a set of instructions within a program that defines what the function should do when it is called.

It is generally surrounded by curly braces and contains one or more lines of code.

A function statement usually contains a formula and calculation. The formula is an expression that specifies the calculation that should be performed when the function is called. The calculation is the result of the formula, which is the value that will be returned when the function is called.

For example, if we have a function that calculates the area of a circle, the formula might be A = πr^2 and the calculation would be A = 3.14 * r^2. The formula describes how the area of a circle is calculated and the calculation is the result of that formula. When the function is called, the calculation will be performed and the result will be returned.

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a) basis is  [ p , q , r . r ]

b) the dimension. P-2q 9p +2r -2q +4r -6p 12r p, q, rin R is 3 for subspace

since the two given equation are in three variable and constants

2q -r= p -----(1)

r= q -s -----(2)

p= q +2r -----(3)

From (2):

r +s= q (+s on both sides)

s= q -r -----(4) (-r on both sides)

Substitute. (3) into (1):

2q -r= q +2r

2q -q= 2r +r

q= 3r -----(5)

Substitute (5) into (4):

s= 3r -r

s= 2r (proved)

hence subspace is [ p , q , r . r ]

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The magnitude of the net force is 149.33 N.

a) To illustrate the net force F1 + F2 as a geometric addition of the two force vectors, we can use the tail-to-tip method to add the vectors head-to-tail and then connect the tail of the first vector to the tip of the second vector to form the net force vector.

b) To compute the net force as the vector sum of the two force vectors, we can use the components of the two vectors to find the components of the net force. Using the trigonometric relationship between the angle and the components of a force vector, the x and y components of the force vectors can be calculated as follows:

F1x = F1 * cos(30) = 86.6025 N

F1y = F1 * sin(30) = 50 N

F2x = F2 * cos(45) = 35.3553 N

F2y = F2 * sin(45) = 35.3553 N

The x and y components of the net force are found by adding the corresponding components of the individual force vectors:

Fnetx = F1x + F2x = 86.6025 N + 35.3553 N = 122 N

Fnety = F1y + F2y = 50 N + 35.3553 N = 85.3553 N

c) To compute the magnitude of the net force, we use the Pythagorean theorem to find the magnitude from the components:

Fnet = √(Fnetx² + Fnety²) = √(122² + 85.3553²) = 149.33 N

So, the magnitude of the net force is 149.33 N.

Complete Question

Two forces are applied to an object, with magnitudes and directions shown in the image below:

(a) Illustrate the net form F1 + F2 as the geometric addition of the two force vectors.

(b) Compute the net force, the vector sum of the force vectors.

(c) Compute the magnitude of the net force. Include N (newton) for units of force.

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Answer:60

Step-by-step explanation:

10+5=15

15x4=60

The preparation of Company X's balance sheet as the current date is as follows:

Company X

As of current date

Cash                                 $8,250

Inventory                            1,225

Accounts Receivable          675  $10,150

Long-term investment  $1,000

Land and building          8,878

Equipment                      4,230    $14,108

Total Assets                               $24,258

Accounts Payable         $485

Short-term loan               500       $985

Long-term loan                         $9,982

Total liabilities                         $10,967

Initial capital           $12,000

Retained earnings       1,291  $13,291

Total liabilities and equity   $24,258

The balance sheet is a financial statement that shows the assets, liabilities, and equity balances of an entity at a point in time.

Assets describe the things owned by the entity while liabilities refer to its debts.  The difference between assets and liabilities is the equity (or the portion of assets belonging to the owners).

Initial investment = $12,000

Retained Earnings = $1,291

Long-term loan = $9,982 ($12,000 - $2,018)

Land and building = $8,878

Equipment = $4,230

Cash $8,250

Inventory = $1,225

Accounts Receivable = $675

Accounts Payable = $485

Short-term loan = $500

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Prepare Company X's balance sheet.

Answer:

17.6lbs

Step-by-step explanation:

If 1kg equals 2.2 lbs, therefore multiply the number of pounds per kg by 8:

2.2lbs * 8 = [17.6lbs]

The equation for Chloe's growth rate would be y = ax + b, where a is the rate of growth in cm/month and b is the height at age 0.

To predict Chloe's height at two years old, we can plug in x = 24 (representing two years, or 24 months) into the equation.

We would then get y = 24a + b,

Which is Chloe's predicted height at age two. This equation gives us a simple way to predict Chloe's height at any age, as long as we know her rate of growth and her height at age 0.

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Answer:

On Monday, the baker makes 36 blueberry muffins, so the total number of muffins she makes that day is 36/0.4 = 90.

On Tuesday, the baker makes a total of 60 muffins, so the number of blueberry muffins she makes that day is 60*0.4 = 24.

Answer: ez, the answer is Parallel

Step-by-step explanation:

because ab and cd are parallel lines
AB is formed by (3,7) and (-6, 1)
CD is formed by (-6,-5) and (0,-1)
testing the two lines are parallel or perpendicular or neither, is done by determining their gradients
Triangle AB = Gradient of AB = Triangle Y over triangle X = 1-7 over -6-3 = -6 over -9 = 2/3
Triangle CD = Gradient of Triangle CD = Triangle Y over Triangle X = -1 - -5 over 0 - -6 = 1 + 5 over 0 + 6 = 4 over 6 = 2/3

So the two lines AB and CD  have the same gradient and thus the two lines are PARALLEL to each other.

Answer:

x = 70 , x = 24

Step-by-step explanation:

the measure of a secant- tangent and a tangent- tangent angle is half the difference of the measures of the intercepted arcs.

9

24 = [tex]\frac{1}{2}[/tex] (118 - x) ← multiply both sides by 2 to clear the fraction

48 = 118 - x ( subtract 118 from both sides )

- 70 = - x ( multiply both sides by - 1 ) , then

x = 70

10

61 = [tex]\frac{1}{2}[/tex] (10x + 1 - (5x - 1) ) ← multiply both sides by 2 to clear the fraction

122 = 10x + 1 - 5x + 1

122 = 5x + 2 ( subtract 2 from both sides )

120 = 5x ( divide both sides by 5 )

24 = x

The true statements bout Gretchen's adjusted data set are (1), (4), and (5).

Statistics is a mathematical tool defined as the study of collecting data, analysis, understanding, representation, and organization. Statistics is described as the procedure of collecting data, classifying it, displaying that in a way that makes it easy to understand, and analyzing it even further.

It is given that:

Which statements are true about Gretchen's adjusted data set:

The options are:

The data set is approximately symmetric.

The center moved farther from the center of Manuel's data set.

The center moved closer to the center of Manuel's data set.

The spread values are closer to the spread values of Manuel's data set.

The data set is skewed left.

The spread values are farther from the spread values of Manuel's data set.

As we know,

The spread values are more similar to Manuel's data set's spread values, and the data set is roughly symmetric and tilted to the left.

The true statements are:

The data set is approximately symmetric.

The spread values are closer to the spread values of Manuel's data set.

The data set is skewed left.

Thus, the true statements bout Gretchen's adjusted data set are (1), (4), and (5).

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In case of (a) Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search. And in (b) 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

a. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who use social media in their job search, we need to set up the null and alternative hypotheses:

H0: p = 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is equal to the proportion of the population that use social media in their job search)

Ha: p > 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is greater than the proportion of the population that use social media in their job search)

Where p is the true proportion of 22- to 30-year-old job seekers who use social media.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as: z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 310/370 = 0.838 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.838 - 0.79) / sqrt(0.79 * (1 - 0.79) / 370) = 3.41

Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search.

b. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume, we need to set up the null and alternative hypotheses:

H0: p = 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is equal to 70%)

Ha: p > 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is greater than 70%)

Where p is the true proportion of 22- to 30-year-old job seekers who have electronically submitted a resume.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as:

z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 275/370 = 0.743 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.743 - 0.70) / sqrt(0.70 * (1 - 0.70) / 370) = 2.01

Since 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

Therefore, In case of (a) Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search. And in (b) 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

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In case of (a) Since 3.41 > 1.64485,  job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search. And in (b) 2.01 > 1.64485,  the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

a. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who use social media in their job search, we need to set up the null and alternative hypotheses:

H0: p = 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is equal to the proportion of the population that use social media in their job search)

Ha: p > 0.79 (the proportion of 22- to 30-year-old job seekers who use social media is greater than the proportion of the population that use social media in their job search)

Where p is the true proportion of 22- to 30-year-old job seekers who use social media.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as: z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 310/370 = 0.838 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.838 - 0.79) / sqrt(0.79 * (1 - 0.79) / 370) = 3.41

Since 3.41 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding the proportion of 22- to 30-year-old job seekers who use social media in their job search exceeds the proportion of the population that uses social media in their job search.

b. To conduct the hypothesis test for the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume, we need to set up the null and alternative hypotheses:

H0: p = 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is equal to 70%)

Ha: p > 0.70 (the proportion of 22- to 30-year-old job seekers who have electronically submitted a resume is greater than 70%)

Where p is the true proportion of 22- to 30-year-old job seekers who have electronically submitted a resume.

We can use a one-sided z-test for proportions to test the hypothesis. The test statistic is calculated as:

z = (p1 - p) / sqrt(p * (1 - p) / n)

where p1 = 275/370 = 0.743 and n = 370.

Using a significance level of 0.05, we can find the critical value from the standard normal distribution table to be 1.64485.

If the calculated z-value is greater than the critical value, we reject the null hypothesis.

z = (0.743 - 0.70) / sqrt(0.70 * (1 - 0.70) / 370) = 2.01

Since 2.01 > 1.64485, we reject the null hypothesis and conclude that the results of the survey justify concluding that more than 70% of 22- to 30-year-old job seekers have electronically submitted a resume to an employer.

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The required probability is 0.953.

We know that the mean μ is:

μ = 4:30 p.m.

The standard deviation  is:

σ = 0:15 minutes

The Z-score is: Z = (x-μ)/σ

We seek to find probability P(4:00 p.m. < x < 5:00 p.m.)

The Z-score is:

Z = (x-μ)/σ = 4:00 - 4:30/0:15 = -2

The score of Z =-2 means that 4:00 p.m. is -2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35% and

Z = (x-μ)/σ = 5:00 - 4:30/0:15 = 2

The score of Z =2 means that 11:00 p.m. is 2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35%.

∴ P(4:00 p.m. < x < 5:00 p.m.) = 100% - 2.35% - 2.35%

= 95.3% = 0.953

Thus, the required probability is 0.953.

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The required probability is 0.953.

We know that the mean μ is:

μ = 4:30 p.m.

The standard deviation  is:

σ = 0:15 minutes

The Z-score is: Z = (x-μ)/σ

We seek to find probability P(4:00 p.m. < x < 5:00 p.m.)

The Z-score is:

Z = (x-μ)/σ = 4:00 - 4:30/0:15 = -2

The score of Z =-2 means that 4:00 p.m. is -2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35% and

Z = (x-μ)/σ = 5:00 - 4:30/0:15 = 2

The score of Z =2 means that 11:00 p.m. is 2 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the condition of 2 deviations from the mean has percentage of 2.35%.

∴ P(4:00 p.m. < x < 5:00 p.m.) = 100% - 2.35% - 2.35%

= 95.3% = 0.953

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Answer:

I believe the answer is b??

The solution to the initial value problem is:y(t) = (10 - (12/7))e^(t) cos(2t) + (12/7)e^(-t) cos(2t).

The characteristic equation of this linear second order ordinary differential equation is:

m^2 - 2m + 5 = 0

The roots of this characteristic equation are m = 1 ± 2i, which means the general solution to the homogeneous equation is:

y(t) = c1e^(t) cos(2t) + c2e^(t) sin(2t)

To find the particular solution, we can use the method of undetermined coefficients and guess that yp(t) = Ae^(-t) cos(2t) + Be^(-t) sin(2t).

Substituting this into the differential equation, we get:

2Ae^(-t) cos(2t) - 2Ae^(-t) sin(2t) + 5Ae^(-t) cos(2t) - 5Be^(-t) sin(2t) = 12e^(-t) cos(2t)

Comparing coefficients, we have:

2A - 2A + 5A = 12

7A = 12

A = 12/7

-5B = 0

B = 0

So the particular solution is:

yp(t) = (12/7)e^(-t) cos(2t)

The general solution to the non-homogeneous equation is then:

y(t) = c1e^(t) cos(2t) + c2e^(t) sin(2t) + (12/7)e^(-t) cos(2t)

Using the initial conditions, we can find the values of c1 and c2:

y(0) = 10 = c1 + (12/7)

c1 = 10 - (12/7)

y'(0) = 0 = c2e^(0) sin(0)

c2 = 0

Therefore, the solution to the initial value problem is: y(t) = (10 - (12/7))e^(t) cos(2t) + (12/7)e^(-t) cos(2t)

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Solving the provided question, we can say that the highest number bouquets she can make without having any flowers left is calculated by Highest Common Factor so, HCF of 56, 48 and 16 is 8

In mathematics, the highest positive integer that divides the corresponding integers is known as the greatest common divisor of two or more non-zero integers. The greatest common factor (HCF) of two or more numbers is the sum of those two or more numbers. As a result, it is frequently referred to as the largest common divisor (GCF). Take the prime factors of the two (or more) integers and determine the shared prime factors to determine the greatest common divisor. Following that, the sum of common prime factors is the greatest common divisor. A specified number divided by the biggest integer results in the greatest common divisor.

the highest number bouquets she can make without having any flowers left is calculated by Highest Common Factor so, HCF of 56, 48 and 16 is 8

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The minimum amount of number of divisions made by Euclid's algorithm among all inputs 1 to 10 is 0, as the greatest common divisor of any two numbers between 1 and 10 must be 1. The maximum number of divisions made by Euclid's algorithm among all inputs 1 to 10 is 19, as the greatest common divisor of 8 and 10 requires 19 divisions.

Euclid's algorithm is an efficient method for finding the greatest common divisor (GCD) of two integers. It works by repeatedly dividing larger numbers by smaller numbers until the remainder is 0. The GCD of two integers is then equal to the smaller number. The minimum number of divisions made by Euclid's algorithm among all inputs 1 to 10 is 0, as the GCD of any two numbers between 1 and 10 must be 1. This is because any two numbers between 1 and 10 have only 1 as their common divisor. On the other hand, the maximum number of divisions made by Euclid's algorithm among all inputs 1 to 10 is 19, as the GCD of 8 and 10 requires 19 divisions. This is due to the fact that 8 and 10 have no common divisors except for 1, so the algorithm must divide 8 by 10 repeatedly until the remainder is 0. Thus, the maximum number of divisions made by Euclid's algorithm among all inputs 1 to 10 is 19.

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The perimeter of the triangle is (30+x) cm

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices. A triangle is also a polygon.

Perimeter is the distance around the edge of a shape.

To find the perimeter of a triangle , we add all the sides together.

Two sides are 22 cm and 8cm

Represent the other sides of the triangle by x

therefore the perimeter will be calculated as:

22+8+x

P = (30+x)cm

therefore the perimeter of the triangle is( 30+x)cm for any value of x

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For circular motion on a circle of radius r, linear speed equals angular speed divided by r. This statement is false.

What is angular speed?

The definition of angular speed is the rate at which angular displacement changes, and it is written as follows -

ω = θ/t

where θ is the angular displacement, t is the time and ω is the angular speed.

The statement says that for circular motion on a circle of radius r, linear speed equals angular speed divided by r.

Consider that an object moves around a circle of radius r at a constant speed v.

If s is the distance travelled in time t around the circle then linear speed v is defined as v = s/t.

Also if θ is the angle swept out by this object in time t then the angular speed is defined as ω = θ/t.

Thus, there is some relationship between linear speed and angular speed -

Linear speed = v = s/t

= rθ/t = r(θ/t) = rω

where is ω measured in radians per unit time and for a circle of radius r, a central angle of radians subtends an arc whose length s is s = rθ.

Hence, notice that linear speed is equal angular speed multiplied, not divided, by r.

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Answer:

The girl who completed 42 push-ups in 6 minutes did more push-ups than the girl who completed 24 push-ups in 3 minutes.

Step-by-step explanation:

Answer:

-1 degrees

Step-by-step explanation:

The average = sum of all values/# of values = sum of all temperatures/# of days=

(-3+0+2-1-3)/5=  -1

When talking about a figure, you can say "on average" when you are discussing a measure of central tendencies, such as the mean, median, or mode.

This is because these measures represent the "average" point in the data set. For example, if you are looking at a figure that consists of the average monthly temperatures for a given region, the mean would be the average temperature (on average) for that region.

Similarly, if you are looking at a figure that consists of the average daily prices of a certain stock, the mean would be the average daily price (on average) for that stock. In either case, the mean is the "average" point in the data set.

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Answer:324234

Step-by-step explanation:

Answer:

The mean of the data set is 7.

2 + 9 + 10 + 6 + 8

= 35

35 ÷ 5

= 7

Step-by-step explanation:

You're welcome

1. (a) An equation that estimates the population t years after 2016 is

P = [tex]88({4t)[/tex].

b. The population of the town in 2023 is 2564.

2. log x + 2log y - log 23 - 3 log z is equal to log (x + y²)/log (23 + z³).

3. (a) An equation to represent the amount of money in the account as a function of time in years is A = 500(1 + 7/100)ⁿ.

(b) The amount of time it takes for the account balance to reach 1 million

is  112.5 years approximately.

The formula for exponential growth is [tex]y = y_0e^{(kt)}.[/tex]

The formula for exponential decay is [tex]y = y_0e^{(-kt)}.[/tex]

1. Given, The population of a town was 88 in 2016. The population quadruples every year.

Therefore, The exponential model of this situation is P = [tex]88({4t)[/tex].

Now, From 2016 to 2023 it is 7 years.

Therefore, P = [tex]88({4\times7})[/tex].

P = 2564.

2. Given, log x + 2log y - log 23 - 3 log z.

= log x + log y² - log 23 - log z³.

= log x + log y² - (log 23 + log z³).

= log (x + y²) - log (23 + z³).

=  log (x + y²)/log (23 + z³).

3. Given,  A savings account is started with an initial deposit of $500. The account earns 7% interest compounded annually.

We know the formula for compound interest is, A = P(1 + r/100)ⁿ.

a. A = 500(1 + 7/100)ⁿ.

b. 1000000 = 500(1 + 7/100)ⁿ.

2000 = (1 + 7/100)ⁿ.

2000 = 1.07ⁿ.

log_1.07 2000 = n.

n = 112.5 years approximately.

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The correct option is C) [tex]\frac{1}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

Vectors, in Math's, are objects which have both, magnitude and direction. Magnitude defines the size of the vector.

It is represented by a line with an arrow, where the length of the line is the magnitude of the vector and the arrow shows the direction.

According to the given conditions,

[tex]c1^{2}+c2^{2} +c3^{2} = 1, a.c =0, b.c=0[/tex]

and [tex]cos\frac{π}{6} = \frac{\sqrt{3} }{2} =\frac{a1b1+a2b2+a3c3}{\sqrt{a1^{2} +a2^{2} +a3^{2} } \sqrt{x=b1^{2} +b2^{2} +b3^{2} } }[/tex]

thus, a1c1+a2c2+a3c3=0 , b1c1+b2c2=b3c3=0

and [tex]\frac{\sqrt{3} (a1^{2}+a2^{2} +a3^{2} )^{1/2} (b1^{2}+b2^{2} +b3^{2} )^{1/2} }{2}[/tex] = a1b1+a2b2+a3b3

Now,

[tex]\left[\begin{array}{ccc}a1&b1&c1\\a2&b2&c2\\a3&b3&c3\end{array}\right]^{2}[/tex]

= [tex]\left[\begin{array}{ccc}a1&a2&a3\\b1&b2&b3\\c1&c2&c3\end{array}\right][/tex]  [tex]\left[\begin{array}{ccc}a1&b1&c1\\a2&b2&c2\\a3&b3&c3\end{array}\right][/tex]

= [tex](a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} ) - (a1b1+a2b2+a3b3)^{2}[/tex]

= [tex](a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} ) -\frac{3}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

= [tex]\frac{1}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

Therefore, The correct option is C) [tex]\frac{1}{4} (a1^{2} +a2^{2} +a3^{2} )(b1^{2} +b2^{2} +b3^{2} )[/tex]

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The probability that the number will be more than 7 or odd is 7/10.

The number more than 7 or odd is 1, 3, 5, 7, 8, 9, 10

So probability of 7 number is,

P(A) = number of favorable outcomes of an event /  total number of events occurring in a sample

P(A) = 7/10

Probability is a way to gauge how likely something is to happen. Many things are difficult to forecast with absolute confidence. Using it, we can only make predictions about the likelihood of an event happening, or how likely it is. Probability can range from 0 to 1, with 0 denoting an impossibility and 1 denoting a certainty. For pupils in Class 10, probability is a crucial subject because it teaches all the fundamental ideas of the subject. One is the probability of every event in a sample space.

The total values provided in a datasheet must be added, and the sum must be divided by the total number of values in order to determine the mean. When all of the values are organized in ascending order, the Median is the median value of the given data. While the number in the list that is repeated a maximum of times is the mode.

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The vat rate is 13%

Vat rate is a consumption tax assessed on the value added in each production stage of a good or service.

Given:

MP = 2080

Discount = d%

VAT = (d-2)%

Cost = 1997.84

Apply discount:

Add VAT:

d² - 2d + 195 = 0

Solving the quadratic equation we get:

d = 15

Then

VAT rate = 15 - 2 = 13%

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Answer: 63.125

Step-by-step explanation: I got it correct ;)

Answer:

Rylan earns $12.50 per hour

Step-by-step explanation:

1. First start by writing the given its always easier when you're able to see the problem.

   $200 = 16 hrs

   $  x    = 1 hr

2. Next divide

        [tex]\frac{200}{16}[/tex] = 12.50

Answer: dunno, maybe try using your brain?

Step-by-step explanation: