Sick computers: Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm.
Suppose P(V) = 0.47, P (W) = 0.34, P (V and W) = 0.07
(a) Find the probability that the computer contains either a virus or a worm or both.
(b) Find the probability that the computer does not contain a virus.

Answers

Answer 1

(a) The probability that the computer contains either a virus or a worm or both can be found using the formula:

P(V or W) = P(V) + P(W) - P(V and W)

Substituting the given values, we get:

P(V or W) = 0.47 + 0.34 - 0.07

P(V or W) = 0.74

Therefore, the probability that the computer contains either a virus or a worm or both is 0.74.

(b) The probability that the computer does not contain a virus can be found using the complement rule:

P(not V) = 1 - P(V)

Substituting the given value, we get:

P(not V) = 1 - 0.47

P(not V) = 0.53

Therefore, the probability that the computer does not contain a virus is 0.53.

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Answer:

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Step-by-step explanation:

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Answers

Answer:

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