A) If A and B are Hermitian, then AB is not Hermitian unless A and B commute.
B) A product of unitary matrices is unitary.
A) Proof:
Let A and B be Hermitian matrices. Then, A and B are defined as A* = A and B* = B.
We know that the product of two Hermitian matrices is not necessarily Hermitian, unless they commute. This means that AB ≠ BA.
Thus, if A and B do not commute, then AB is not Hermitian.
B) Proof:
Let U and V be two unitary matrices. We know that unitary matrices are defined as U×U=I and V×V=I, where I denotes an identity matrix.
Then, we can write the product of U and V as UV = U*V*V*U.
Since U* and V* are both unitary matrices, the product UV is unitary as U*V*V*U
= (U*V*)(V*U)
= I.
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(A) If A and B are Hermitian matrices that do not commute, AB is not Hermitian.
(B) The product of two unitary matrices, UV, is unitary.
Let's begin with statement (A):
(A) If A and B are Hermitian, then AB is not Hermitian unless A and B commute.
To prove this statement, we will use the fact that for a matrix to be Hermitian, it must satisfy A = A^H, where A^H denotes the conjugate transpose of A.
Assume that A and B are Hermitian matrices. We want to show that if A and B do not commute, then AB is not Hermitian.
Suppose A and B do not commute, i.e., AB ≠ BA.
Now let's consider the product AB:
(AB)^H = B^H A^H [Taking the conjugate transpose of AB]
Since A and B are Hermitian, we have A = A^H and B = B^H. Substituting these in, we get:
(AB)^H = B A
If AB is Hermitian, then we should have (AB)^H = AB. However, in general, B A ≠ AB unless A and B commute.
Therefore, if A and B are Hermitian matrices that do not commute, AB is not Hermitian.
Now let's move on to statement (B):
(B) A product of unitary matrices is unitary.
To prove this statement, we need to show that the product of two unitary matrices is also unitary.
Let U and V be unitary matrices. We want to show that UV is unitary.
To prove this, we need to demonstrate two conditions:
1. (UV)(UV)^H = I [The product UV is normal]
2. (UV)^H(UV) = I [The product UV is also self-adjoint]
Let's analyze the two conditions:
1. (UV)(UV)^H = UVV^HU^H = U(VV^H)U^H = UU^H = I
Since U and V are unitary matrices, UU^H = VV^H = I. Therefore, (UV)(UV)^H = I.
2. (UV)^H(UV) = V^HU^HU(V^H)^H = V^HVU^HU = V^HV = I
Similarly, since U and V are unitary matrices, V^HV = U^HU = I. Therefore, (UV)^H(UV) = I.
Thus, both conditions are satisfied, and we conclude that the product of two unitary matrices, UV, is unitary.
In summary:
(A) If A and B are Hermitian matrices that do not commute, AB is not Hermitian.
(B) The product of two unitary matrices, UV, is unitary.
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A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39). which are the equations of the directrices? x = ± y = ± x = ± y = ±
The equation of directrix is D. y=± 432/13.
Definition of hyperbola -
A plane curve generated by a point so moving that the difference of the distances from two fixed points is a constant . A curve formed by the intersection of a double right circular cone with a plane that cuts both halves of the cone.1. The vertex i at (0, 36) and a focus at (0, 39), then you have:
a=36
a²=1296
2. The equation of directrix is:
y = a² =c
c = 39
y = 1296/39
y = 432/13
Therefore, the answer is the option D, which is: D. y=± 432/13
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The complete question is -
A hyperbola centered at the origin has a vertex at (0, 36) and a focus at (0, 39)
Which are the equations of the directrices ?
A. x= ±12/13
B. y=±12/13
C. x=±432/13
D. y=± 432/13
Answer: Correct
Step-by-step explanation:
1. The midpoint of KL is M(5, -7). One endpoint is K(9,-7). Find the coordinates of the other endpoint L.
O
O
O
(7.-7)
(1.-7)
(1,0)
Answer:
L (1, - 7 )
Step-by-step explanation:
give endpoints (x₁, y₁ ( and (x₂, y₂ ) then the midpoint is
( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )
here (x₁, y₁ ) = K (9, - 7 ) and (x₂, y₂ ) = L (x, y )
use the midpoint formula and equate to corresponding coordinates of M
[tex]\frac{9+x}{2}[/tex] = 5 ( multiply both sides by 2 to clear the fraction )
9 + x = 10 ( subtract 9 from both sides )
x = 1
and
[tex]\frac{-7+y}{2}[/tex] = - 7 ( multiply both sides by 2 )
- 7 + y = - 14 ( add 7 to both sides )
y = - 7
Then L = (1, - 7 )
If the table of the function contains exactly two potential turning points, one with an input value of -1, which statement best describes all possible values of m?
The statement (inequality) which best describes all possible values of m is: -12 < m < 4.
What is an inequality?An inequality is a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following:
Less than (<).Greater than (>).Less than or equal to (≤).Greater than or equal to (≥).The table indicates two local extremes or potential turning points at x = 1 and x = -1. Thus, the value of m can't exceed f(-3) = -12.
In conclusion, the statement (inequality) which best describes all possible values of m is: -12 < m < 4.
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the function, B (x), models the estimated tuition cost where x is the number
The expression that completes the function b(x) is b(x) = 33741 * (1.028)^x
How to determine the expression of b(x)?The given parameters are:
Initial value, a = 33741
Rate, r = 2.8%
The cost of tuition each year since 2015 is represented as
B(x) = a * (1 + r)^x
This gives
B(x) = 33741 * (1 + 2.8%)^x
Evaluate
b(x) = 33741 * (1.028)^x
Hence, the expression that completes the function b(x) is b(x) = 33741 * (1.028)^x
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Complete question
A study estimates that the cost of tuition at a university will increase by 2.8% each year. The cost of tuition at the University in 2015 was $33,741 the function b(x) , models the estimated tuition cost , where x is the number of years since 2015.
Find the expression that completes the function b(x)
What is the partial fraction decomposition of startfraction 7 x squared minus 6 x + 9 over 3 x (4 x squared + 9) endfraction?
Answer:
A:(1/3x)+(x-2/4x^2+9)
Step-by-step explanation:
Edg2022
7(x^2 y^2)dx 5xydyUse the method for solving homogeneous equations to solve the following differential equation.
I'm guessing the equation should read something like
[tex]7(x^2+y^2) \,dx + 5xy \, dy = 0[/tex]
or possibly with minus signs in place of +.
Multiply both sides by [tex]\frac1{x^2}[/tex] to get
[tex]7\left(1 + \dfrac{y^2}{x^2}\right) \, dx + \dfrac{5y}x \, dy = 0[/tex]
Now substitute
[tex]v = \dfrac yx \implies y = xv \implies dy = x\,dv + v\,dx[/tex]
to transform the equation to
[tex]7(1+v^2) \, dx + 5v (x\,dv + v\,dx) = 0[/tex]
which simplifies to
[tex](7 + 12v^2) \, dx + 5xv\,dv = 0[/tex]
The ODE is now separable.
[tex]\dfrac{5v}{7+12v^2} \, dv = -\dfrac{dx}x[/tex]
Integrate both sides. On the left, substitute
[tex]w = 7+12v^2 \implies dw = 24v\, dv[/tex]
[tex]\displaystyle \int \frac{5v}{7+12v^2} \, dv = -\int \frac{dx}x[/tex]
[tex]\displaystyle \dfrac5{24} \int \frac{dw}w = -\int \frac{dx}x[/tex]
[tex]\dfrac5{24} \ln|w| = -\ln|x| + C[/tex]
Solve for [tex]w[/tex].
[tex]\ln\left|w^{5/24}\right| = \ln\left|\dfrac1x\right| + C[/tex]
[tex]\exp\left(\ln\left|w^{5/24}\right|\right) = \exp\left(\ln\left|\dfrac1x\right| + C\right)[/tex]
[tex]w^{5/24} = \dfrac Cx[/tex]
Put this back in terms of [tex]v[/tex].
[tex](7+12v^2)^{5/24} = \dfrac Cx[/tex]
Put this back in terms of [tex]y[/tex].
[tex]\left(7+12\dfrac{y^2}{x^2}\right)^{5/24} = \dfrac Cx[/tex]
Solve for [tex]y[/tex].
[tex]7+12\dfrac{y^2}{x^2} = \dfrac C{x^{24/5}}[/tex]
[tex]\dfrac{y^2}{x^2} = \dfrac C{x^{24/5}} - \dfrac7{12}[/tex]
[tex]y^2= \dfrac C{x^{14/5}} - \dfrac{7x^2}{12}[/tex]
[tex]y = \pm \sqrt{\dfrac C{x^{14/5}} - \dfrac{7x^2}{12}}[/tex]
The graph of is the widest.
By critically observing and comparing the functions for the given graphs, we can logically deduce that the widest graph is: "Function 1: y = 0.25x²."
How to determine the widest graph?In Geometry, a graph which has the smallest positive coefficient of x² in absolute value is generally considered as the widest graph while the graph with the largest positive coefficient of x² in absolute value is the narrowest graph.
By critically observing and comparing the functions for the given graphs, we can logically deduce that "Function 1: y = 0.25x²" is the widest.
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Complete Question:
Compare the graphs of the functions listed below.
Function 1: y = 0.25x²
Function 2: y = 4x²
Function 3: y = -½x²
Function 4: y = -16x²
The graph of ______ is the widest?
Help me please with this question
Answer:
[tex]y = \sqrt{ \frac{\pi \: x - A {}^{} }{\pi} } [/tex]
Step-by-step explanation:
To make y subject of formular, we place y in terms of other variables.
[tex] A = \pi \: x {}^{2} - \pi \: y {}^{2} \\ making \: y \: subject \\ A + \pi \: y {}^{2} = \pi \: x {}^{2} \\ \pi \: y {}^{2} = \pi \: x {}^{2} - A \\ Dividing \: bothsides \: by \: \pi \\ y {}^{2} = \frac{\pi \: x { - A}^{} }{\pi} \\ Squarerooting \: bothsides \\ y = \sqrt{ \frac{\pi \: x - A {}^{} }{\pi} } [/tex]
Figure ABCD is a rhombus. Rhombus A B C D is shown. Angle A is (5 x 25) degrees and angle D is (7 x minus 1) degrees. What is the value of x
Answer: 18
Step-by-step explanation:
Opposite angles of a rhombus are congruent, so
[tex]5 \times 25=7x-1\\\\125=7x-1\\\\126=7x\\\\x=18[/tex]
Instructions: Find the circumference of the circle and round to the nearest tenth. 4 yrds
The circumference of the circle and round to the nearest tenth is 25.1 yds
Circumference of a circleThe formula for calculating the circumference of a circle is expressed as:
C = 2πr
Given the following
radius r = 4yds
Substitute
C = 2(3.14)(4)
C = 25.12 yds
Hence the circumference of the circle and round to the nearest tenth is 25.1 yds
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Rhombus LMNO is shown with its diagonals.
Rhombus L M N O is shown. Diagonals are drawn from point M to point O and from point L to point N and intersect at point P. All sides are congruent.
Angle MLO measures 112°. What is the measure of angle MLP?
45°
56°
68°
90°
The angle m∠MLP in the rhombus is 56 degrees.
How to find the angle of a rhombus?A rhombus has all its sides equal to each other. The diagonals of a rhombus are angle bisectors.
Therefore,
m∠MLP = m∠MLO / 2
m∠MLO = 112°
m∠MLP = 112 / 2
Therefore,
m∠MLP = 56 degrees.
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Answer:
B. 56
Step-by-step explanation:
trust
An object has a kinectic energy of 25j and a mass of 34kg,how fast is the object moving
v = 1.21 m/s is the answer
Kinetic energy of object = 25 J
Mass of object = 34 kg
The formula for the kinetic energy of an object is given by
K.E. = 1/2 m v2.
25 = 1/2 *34* v2.
v2= 25/17
v2 = 1.47
v = 1.21 m/s
In physics, the kinetic energy of an object is the energy that the object has due to its motion. This is defined as the work required to accelerate an object of a given mass from a stationary state to a specified velocity. After the body gains this energy during acceleration, it retains this kinetic energy unless the velocity changes
Everything that moves at home is an example of kinetic energy. This could be a cue ball rolling on a pool table, a fan that circulates air on warm days, or a glass that shatters on the floor after falling off the counter. Electrical equipment that is turned on uses kinetic energy, much like people move around the house.
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A maker of folding tables estimates that 1 in 40 tables is returned due to a manufacturer's defect.
for each table not returned, the manufacturer makes a profit of $4.50, but for each table
returned, it loses $48. what is the manufacturer's long-term average profit on this product?
Answer:
$127.50
Step-by-step explanation:
The average profit is found by adding up the profits from both scenarios.
39(4.5) + 1(-48)
= $127.50
Brainliest, please :)
Please help answer now please
Answer:
- 4/7 , -1/9, 7/4
Step-by-step explanation:
You know that 7/4 is the largest number because it is the only positive number. To compare the two negative numbers you need common denominators. The common denominator would be 133 (19 x 7). Now make equivalent fractions.-4/7 = x/133 133 divided by 7 is 19. Multiple the -4 by 19 to get -76/133. Next, make an equivalent fraction for -1/19. The new denominator will be 133. If I divide 133 by 19, I will get 7, so I multiple -1x7 and get -7 and the new fraction -7/133.
I have two fractions to compare -7/133 and -76/133. -76/133 if farthest from 0 so it has the least value.
In his first month of training,Landon biked 3.1 miles and ran 0.75 miles each workout. He completed 18 workouts that month. What is the total distance that he biked in his first month of training?
Taking into account the change of units, the total distance that he biked in his first month of training is 55.8 miles.
Rule of threeIn first place, the rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.
That is, what is intended with it is to find the fourth term of a proportion knowing the other three.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied.
To solve a direct rule of three, the following formula must be followed, being a, b and c known data and x the variable to be calculated:
a ⇒ b
c ⇒ x
So: [tex]x=\frac{cxb}{a}[/tex]
Total distance that he biked in his first month of trainingIn his first month of training,Landon biked 3.1 miles and ran 0.75 miles each workout. He completed 18 workouts that month.
So you can apply the following rule of three: if for each workout Landon biked 3.1 miles, in 18 workouts he biked how far?
1 workout ⇒ 3.1 miles
18 workouts ⇒ total distance
So: [tex]total distance=\frac{18 workoutsx3.1 miles}{1 workout}[/tex]
Solving:
total distance= 55.8 miles
In summary, the total distance that he biked in his first month of training is 55.8 miles.
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Rick received better results for his Maths test than for his English test. If the sum of his two marks is 163 and the difference is 31, find the mark for each subject.
Answer:
Math = 97
English = 66
Step-by-step explanation:
Let the score of the Math test be x, and the score of the English text be y
Then we have the two equations
[tex]x+y = 163\\x-y = 31[/tex]
To solve for x and y there are multiple ways, one of the easy ways is just to add the two equations together because that would cancel out the y:
[tex]x + x + y -y = 163 +31\\2x = 194\\x = 97\\[/tex]
Then using the x, we can find y by doing
[tex]x+y = 163\\97 + y = 163\\(97 + y) - 97 = (163) - 97\\y = 66[/tex]
Therefore, we have a math score of 97, and an English score of 66.
Part E
Considering the probability you found in part D, which option makes more sense for Jake to choose?
Explain your reasoning.
The option which makes more sense for Jake to choose is option (1) He can accept the tie, and the game is over.
How to determine the best option to choose?The complete question is added as an attachment
From the complete question, the probability in part D is
Probability = 33.5%
The options to choose one from are:
Option 1: He can accept the tie, and the game is over.Option 2: He can make one more throw. Jake wins if he earns at least 30 points on the throw, but he loses if he earns less than 30 points.The calculated probability is less than 0.5.
This means that Jake is more likely to lose than win
So, the best option for Jake is option (A) walk away
Hence, the option which makes more sense for Jake to choose is option (1) He can accept the tie, and the game is over.
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Jack is in a helicopter and looking down at two friends’ homes. The angle of depression to the first home is 72°. The angle of depression to the second home is 49°. If the homes are 420m apart, what is the distance between the helicopter and the first home?
The distance between the helicopter and the first home is 369. 87 m
How to solve the distance using the angle of depression?The distance between the helicopter and the first home can be found using sine law,
Hence,
180 - 72 - 49 = 59 degrees.
Therefore,
420 / sin 59 = A / sin 49°
where
A = distance form the first home to the helicopter.cross multiply
420 sin 49 = A sin 59°
A = 420 sin 49 / sin 59
A = 316.978023694 / 0.8571673007
A = 369.869339199
A = 369. 87 m
Therefore, the distance between the helicopter and the first home is 369. 87 m
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How many triangles are there?
Answer:
20
Steps-by-step explanation:
sorry mistake
Answer:
12
Explanation: I just counted them! :) and there was 6 in the middle and on the outside so 6 + 6 = 12! :)
The airspeed of an airplane is 850 km/hr, and there is a wind blowing southwest at 30 km/hr.
If the airplane needs to head due south, at what angle does the pilot need to fly the plane?
Answer:
α = αG − αZL
thos is the equation for the absoulute angle of attack
Martin is saving money to buy a new phone that costs $1,000 by selling trees. he is using an app to manage his sales, but it keeps a fraction of each sale. his net pay is modeled by the function p(x) = x2 20x – 196, where x represents the number of sales. how many sales does martin need to make to earn $1,000? 10 sales 26 sales 46 sales 1,296 sales
Answer:
26
Step-by-step explanation:
You want to know the value of x that makes y=1000. You can plug the equation in to your calculator or desmos. Look at the table for when y=1000. X is 26.
To check, plug in 26 for x. 26^2 + 20(26) - 196 = 1000.
Answer: 26 sales
Step-by-step explanation:
which of the following is equivalent to the logarithmic equation below?
Answer:
A
Step-by-step explanation:
using the rule of logarithms
[tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex] , then
[tex]log_{2}[/tex] 8 = 3 ⇒ 2³ = 8
Answer:
A
Step-by-step explanation:
loga(b)=x
a^x=b
since the answer to log2(8)=3
a^3=8
b=8
a=2
so 2^3=8
I hope this helped!
It has been determined that 15% of all cars tested emit excessive hydrocarbons, 12% emit excessive CO, and 8% emit excessive amounts of both. Find the probability that emissions of both hydrocarbons and CO are excessive. Round your answer to 2 decimal places.
The probability that emission of both CO and hydrocarbon is in excess is 0.8.
What is probability?The proportion of favorable cases to all possible cases used to determine how likely an event is to occur.
Let, A be the event in which cars are emitting excess CO:
P(A) = 0.12
Let, B be the event in which cars are emitting excess hydrocarbons:
P(B) = 0.15
The cars which emit both CO and Hydrocarbons in:
P(A∩B) = 0.8
The probability that emission of both CO and hydrocarbon is in excess is 0.8.
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Find the sum: 5/8+3/10
Answer:
37/70
Step-by-step explanation:
5/8 + 3/10 = (5 × 5)/ (8 × 5) + (3 × 4)/ (10 × 4) =
25/40 + 12/40 = 37/40
Carmen is planning rail lines for a new train station. Help her find m1. Explain how you found that solution.
m<1 =163 degrees
163,17,163,17 (all in degrees)
163,17,163,17 (all in degrees)
I have reproduced and attached a diagram (in figure 1) of the problem.
For ease of understanding, I have attached a second diagram which is labelled.
On line a
17+<CBE=180 (Linear Pair Postulate)
m<2=<CBE=180-17=163 degrees
<ABG=<CBE=163 degrees (Vertically Opposite Angles)
<ABE=<GBC= 17 degrees(Vertically Opposite Angles)
On line b
m<1=<DEB=<ABG=163 degrees (Corresponding Angles)
<BEF=<GBC= 17 degrees (Corresponding Angles)
<HEF=<DEB=163 degrees (Vertically Opposite Angles)
<DEH=<BEF=17 degrees (Vertically Opposite Angles)
Therefore:
m<1 =163 degrees
Clockwise from top left, the angles formed with line a are: 163 degrees, 17 degrees, m<2=163 degrees and 17 degrees.
Clockwise from top left, the angles formed with line b are: m<1=163 degrees, 17 degrees, 163 degrees, and 17 degrees.
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Determine whether side-side-angle (SSA) is a valid means for establishing triangle congruence. In this case, you know the measure of two adjacent sides and the angle opposite to one of them. If it is a valid criterion, explain why. If it is not valid, use GeoGebra to create a counterexample demonstrating that it doesn’t work and give an explanation. (Hint: Try constructing a triangle where the known angle is opposite to the shortest known side.) If you construct a counterexample, take a screenshot of your work, save it, and insert the image in the space below.
The illustration to determine whether side-side-angle (SSA) is a valid means for establishing triangle congruence is given below.
How to illustrate the information?Congruence of triangles means that two triangles are said to be congruent if all three corresponding sides are equal and all the three corresponding angles are equal in measure.
In this case, these triangles can be slides, rotated, flipped and turned to be looked identical. If repositioned, they coincide with each other.
To illustrate the question, this will be:
Step 1: Draw a line segment AB
Step 2:Draw an acute angle (let's say 45° ) at A as AX
Step 3: From B draw an altitude on AX BY ⊥ AX
Step 4 Using suitable compass width and taking Y as center cut AX on both sides at C and D
Now BC = BD as BY is perpendicular bisector
Now compare ΔABC and ΔABD. Using suitable compass width and taking B as center cut AX at 2 points C & D directly so BC = BD.
This can illustrate that SSA is not a valid means for establishing triangle congruence.
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Answer:
Below is an example to show whether side-side-angle (SSA) is a legitimate method for proving triangle congruence. How should the information be illustrated? Triangle congruence refers to the property that two triangles are congruent if their three corresponding sides and their three corresponding angles are both equal in size. In this instance, the triangles can be moved around, rotated, flipped, and turned to have a same appearance. They are in alignment with one another when moved. This can serve as an example of why SSA cannot be used to prove triangle congruence.
Step-by-step explanation:
In the figure pq is parallel to Ed the length of to is 4 cm the length of pt is 16 the length of qt is 20 what is the length of sq
By applying the basic proportionality theorem (BPT), the length of side SQ is equal to 5 cm.
How to calculate the length of side SQ?In order to determine the length of side SQ, we would apply basic proportionality theorem (BPT) as follows:
Since PQ ǁ RS, PT = 16
PT/RP = QT/SQ
16/4 = 20/SQ
Cross-multiplying, we have:
16SQ = 20 × 4
SQ = 80/16
SQ = 5 cm.
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Complete Question:
In the figure, PQ is parallel to RS. The length of RP is 4 cm; the length of PT is 16 cm; the length of QT is 20 cm. What is the length of SQ?
ProblemSolving One leg of an isosceles
right triangle has endpoints (1, 1) and (6, 1). The other
leg passes through the point (6, 2). Draw the triangle
5 on the coordinate plane below. Then show how you
can use the Distance Formula to find the length of the
hypotenuse. Round your answer to the nearest tenth.
The length of the hypotenuse of the isosceles triangle is 7.1 units.
We can use the distance formula to find the length of ST (base) and TU(perpendicular). Further, using these lengths, we can find the hypotenuse of the isosceles triangle.
The distance formula is given as follows,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Here, d is the distance between the two points (x₁, y₁) and (x₂, y₂)
As shown in the drawn isosceles triangle STU,
The length of the base ST is given as,
ST = √(x₂ - x₁)² + (y₂ - y₁)²
Here,
x₁ = 1 and y₁ = 1
x₂ = 6 and y₂ = 1
∴ ST = √(6-1)² + (1-1)²
ST = √5²
ST = 5 units
Similarly, for TU as the other leg passes through the point(6,2) and is of length 5 units ( STU being isosceles triangle), we have,
x₁ = 6 and y₁ = 1
x₂ = 6 and y₂ = 6
Also, TU = 5 units
Now, using Pythagoras Theorem,
(hypotenuse)² = (base)² + (perpendicular)²
(SU)² = (ST)² + (TU)²
(SU)² = (5)² + (5)²
(SU)² = 50
SU = √50
SU = 7.071 units
SU ≈ 7.1 units (after rounding of to the nearest tenth)
hence, the hypotenuse of the isosceles triangle is of 7.1 units.
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Find the equation of the line which passes through the point ( 3,-2) and parallel to 2y - x = 3
The equation of the parallel line is 2y-x=-7
A parallel line will have the same slope, but different intercept. Let's assume C in the intercept of this parallel line. Therefore, equation of the parallel would be,
2y-x=C, coefficients of x and y remain the same, since parallel lines.
This line passes through (3, -2). Therefore, substituting those values, we will get value of C.
2.(-2) -3=C
C=(-7)
The equation of the parallel line is therefore 2y-x=-7
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Explain step by step please!! Find f’(x) for f(x)=sin^3(3x^2)
Answer:
Step-by-step explanation:
g(x) = [tan( 4x-1)]2