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Contact injury happens when a person is holding an object that is directly hit or splashed by lightning.

To find answer, we need to know more about the lightning and injuries.

Thus, we can conclude that, contact injury occurs when a person is holding an object that is directly hit or splashed by lightning.

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When someone is holding something that has been struck or splashed by lightning, contact damage occurs.

We need additional information concerning lightning and injuries in order to identify the solution.

In light of this, we can say that contact injuries happen when a person is holding an object that has been struck by lightning or splashed by it.

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The minimum initial velocity of the rock is V = 8.56 m/sec.

According to the rule of conservation of energy, energy can only be transformed from one form of energy to another and cannot be created or destroyed. This indicates that unless energy is added from the outside, a system always has the same quantity of energy.

Calculate the rock's minimal initial velocity in meters/second as it exits the slingshot at a distance of 6 feet [tex]$\left(h_{2}=6\right.ft.)[/tex] above the ground.

Using the provided information, the net height of the limb is calculated as shown below.

[tex]$$h &=h_{1}-h_{2}$$[/tex]

h = 18.3 - 6

h = 12.3

Now, using the conservation of energy the minimum initial velocity of the rock is computed as shown below,

Kinetic energy of the rock = Potential energy the rock

[tex]$$\begin{aligned}\frac{1}{2} m V^{2} &=m g h \\\frac{1}{2} V^{2} &=g h \\\frac{1}{2} V^{2} &=\left(32.1 \mathrm{ft} / \mathrm{s}^{2}\right)(12.3 \text { feet }) \\V &=\sqrt{2\left(32.1 \mathrm{ft} / \mathrm{s}^{2}\right)(12.3 \mathrm{feet})}\end{aligned}$$[/tex]

V = 28.10 [tex]\frac{ft}{s}[/tex].

The minimal initial velocity in meter/second is 8.56.

Therefore, the minimum initial velocity of the rock is 8.56 m/sec

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If l and m both are doubled then the period becomes √2*T

what is a simple pendulum?

It is the one which can be considered to be a point mass suspended from a string or rod of negligible mass.

A pendulum is a weight suspended from a pivot so that it can swing freely.

Here,

A certain frictionless simple pendulum having a length l and mass m

mass of pendulum = m

length of the pendulum = l

The period of simple pendulum is:

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

Where k is the constant.

Now the length and mass are doubled,

m' = 2m

l' = 2l

[tex]T' = 2\pi \sqrt{\frac{2l}{g} }[/tex]

[tex]T' = \sqrt{2}* 2\pi \sqrt{\frac{l}{g} }[/tex]

[tex]T' = \sqrt{2} * T[/tex]

Hence,

If l and m both are doubled then the period becomes √2*T

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Answer:

W1 L1 = W2 L2        equation for balancing torques

M1 g L1 = M2 L2 g

Or M2 = M1 * 1.75 / 1.22 = 1.43 M1 = 32.1 kg

The limiting reagent in this procedure is the substance that is completely used in the reaction. The substance which is not completely used is called excess.

The beginning cloth in a chemical reaction is known as the reactant. each chemical response could have one or more reactants.

In a chemical response limiting reagent is the reactant this is fed on first and prevents any similar reaction from happening. the quantity of product shaped during the response is decided by means of the limiting reagent. as an example, allow us to recall the response of solution and chlorine

Materials used during the manufacture of the lively substance (e.g., tradition media, growth factors, and so on) and that are not meant to form a part of the active substance shall be taken into consideration as raw substances. cloth forming a critical part of the lively materials element shall be considered as the beginning substance.

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The element of a valid contract which is established by getting the signatures of all parties is mutual agreement

An element of a valid contract simply refers to that promise made between two or more parties that which allow the courts to make judgement.

Some elements of valid contract are:

So therefore, the element of a valid contract which is established by getting the signatures of all parties is mutual agreement

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The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.

Hence;

Vertical component = 40 m/s sin 15 degrees = 10.35 m/s

Horizontal component = 40 cos 15 degrees = 38.6 m/s

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In a dry pipe sprinkler system, pressurized air or nitrogen, rather than water, is used to fill the pipes. This air maintains the closed position of a remote valve, also referred to as a dry pipe valve.

The dry-pipe valve, which is situated in a hot area, keeps water from flowing into the pipe until a fire triggers the operation of one or more sprayer. When this occurs, the dry pipe valve releases and the air leaves. After that, water enters the pipe and pours onto the flames through open sprinklers.

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The combined momentum of the passengers is 5000 kgm/s.

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

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The acceleration of the body is found to be -4.05 m/s^2

We define the acceleration as the rate of change of the velocity with time. Hence, we can write that;

a = (μcosθ - sinθ)g

a = acceleration

μ = coefficient of kinetic friction

θ = angle of inclination

g = acceleration due to gravity

Thus;

a = (0.10cos 30 - sin 30) 9.8

a = -4.05 m/s^2

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Halfway between the like poles of two magnets, because the field lines bend away and do not enter this area.

How does a magnetic field diagram show where the field is strongest?

Where is magnetic field the strongest and weakest on a magnet?

Which two locations on the magnet would have the greatest attractive forces?

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Answer:

St. Elmo's Fire - well known to old time sailors

Work done will be 825 N*m

Given:

mass of crate = 44.0 kg

horizontal force = 150 N

distance moved by crate = 5.50 m

To Find:

Work done

Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

First we want to find the work, it is given by the force applied times the distance moved, so the work is just:

W = Force x displacement

W = 150N*5.50m

W = 825 N*m

So, work done will be 825 N*m

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The velocity of the photo electron is 6.11 × 105 ms

Given :

Supplied energy, Es = 5.3 x 10-19 J

Minimum energy of the electron to escape from the metal, E. = 3.6 x 10-19 J

To Find :

Velocity of photoelectron

Solution : The energy supplied by the photon is equal to the sum of minimum escape energy and the kinetic energy of the escaping electron. So

5.3 × 10^-19 J = 3.6 × 10^-19 J + K

K = 5.3 x 10^-19 - 3.6 x 10^-19

K = 1.7 × 10^-19 J

The formula of kinetic energy is given by:

K = 1/2 mv^2

v = √2K/m

= √2 x 1.7 x 10^-19

√ 9.1 x 10^-31

v = 6.11 x 10^5 m/s

So, the velocity of the photo electron is 6.11 x 10^5 m/s

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The equivalent focal length of this combination-lenses should be +50 cm.

Given:

Focal length of convex lens, f₁ = +25 cm

Focal length of concave lens, f₂ = -50 cm

Calculation:

We know that the power of a lens is given as:

P = 1 / f

where, f is the focal length of lens

Now, the power of convex lens can be calculated as:

P₁ = 1/f₁

  = 1/(25×10⁻² m)

  = 100/25

  = +4 D

Similarly, the power of concave lens can be calculated as:

P₂ = 1/f₂

    = (1/-50×10⁻² m)

    = -100/50

    = -2 D

Thus, the power of the combined lenses can be calculated as:

P₍₁₊₂₎ = P₁ + P₂

       = +4 D - 2 D

       = +2 D

Now, the combined focal length of the lens can be calculated as:

f₍₁₊₂₎ = 1 / P₍₁₊₂₎

      = 100 / 2 D

      = +50 cm

Therefore, the equivalent focal length of this combination-lenses will be +50 cm.

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Astronomers thought that a nova was a new star, appearing for the first time in the heavens, today we know that it is as a binary star system.

A binary star system is known to be one where one star is known to be called a white dwarf and there is a mass that is said to be transferred to it

A binary star is known to be a kind of a system that is composed of two stars that are known to be gravitationally held together to and in orbit near each other.

Note that Binary stars in the night sky are ones that are often seen as a single object and thus Astronomers thought that a nova was a new star, appearing for the first time in the heavens, today we know that it is as a binary star system.

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Two worlds in the outer solar system that seem remarkably similar to each other are: Triton and Pluto

The outer solar system comprises the next four planets and everything beyond the planet Neptune but within the gravitational pull of the Sun. The Kuiper Belt and the Oort Cloud are also parts of the outer region.

Triton is only slightly larger than Pluto. Both worlds have similar surface materials, such as nitrogen, methane and carbon monoxide. Their diameters, masses and densities are also similar. Both Triton and Pluto may also have originated within the Kuiper Belt. Triton is thought to be originally a Kuiper Belt Object that was captured by Neptune's gravity.

Because Triton and Charon-Pluto are both from the Kuiper belt they are both made of similar materials such as nitrogen, methane, carbon dioxide and water ice. Both  have large cores that are made primarily of rock with mantles of water ice and crusts made of frozen nitrogen. Neither of them have a magnetic field.

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The focal plane  is a plane perpendicular to the optic axis through the focal point.

What is  focal plane?

What is focal plane and lens?

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The decreasing order of the momenta are b>a=d=e>c.

Solution: The momentum of all the options are mentioned below according to the formula:

a. p = 20 × 1 = 20gm/s

b. p = 20 × 2 = 40gm/s

c. p =10 × 1 = 10gm/s

d. p = 10 × 2 = 20 gm/s

e. p =200 × 0.1 = 20gm/s

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Question:

I hope you are trying to ask the question below:

Rank in order, from largest to smallest, the momenta a to e of the objects

a. 20 g & 1 m/s

b. 20 g & 2 m/s

c. 10 g & 1 m/s

d. 10 g & 2 m/s

e. 200 g & 0.1 m/s

If the efficiency of technology was to be improved in other to reduce electrical power consumption, the sectors which would be chosen is referred to as residential and commercial.

This is defined as the application of science to the practical aims and activities of human life. Power on the hand is defined as the amount of energy which is transferred per unit time and the S.I unit is referred to as Watts.

It can be inferred that electric power consumption is most abundant in residential and commercial sectors due to the number of appliances and hours which are present and used in this area.

It is therefore appropriate to focus on these two sectors so as to achieve the aim of an efficient technology in reduction of electrical power consumption.

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Velocity of Deidre and her dog is 2.11m/s.

=2.11m/s

Thus , we can conclude that the velocity of Deidre and her dog is 2.11 m/s towards north .

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Cart A has the greatest momentum.

The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion. Mass and velocity are two factors that affect momentum. According to an equation, an object's momentum is determined by multiplying its mass by its velocity.

                                                        p = mv

p = momentum

m = mass

v = velocity

Cart A

m₁ = 200 kg

v₁ = 4.8 m/s

p₁ = 200 × 4.8

p₁ = 960 kg-m/s

Cart B

m₂ = 200 + 20 = 220 kg

v₂ = 4 m/s

p₂ = 220 × 4

p₂ = 880 kg-m/s

Cart C

m₃ = 200 + 40 = 240 kg

v₃ = 3.8 m/s

p₃ = 240 × 3.8

p₃ = 912 m/s

Cart D

m₄ = 200 + 60 = 260 kg

v₄ = 3.5 m/s

p₄ = 260 × 3.5

p₄ = 910 kg-m/s

Hence concluded, cart A has the greatest momentum.

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Force constant = k = 6811 N/m

Given:

mass = m = 69.5 kg

L(initial) = ideal spring length = 12 cm= 0.120 m

L(final) = final spring length = 13 cm= 0.130 m

Two forces acting on the object is k*x and mg

so,

kx-mg=0

kx = mg

k = mg/x

We know that x= displacement = L(final)- L(initial)

0.130-0.120=0.10

k= 69.5×9.8/0.10

k =6811 N/m

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Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.

Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.

The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.

The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.

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Answer:

b

Explanation:

The work is done by the 50 N force is 200 J.

Work done = Fd

where;

Work done = 50 N x 4 m = 200 J

Thus, the work is done by the 50 N force is 200 J.

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The acceleration lasted for 0.007s.

To find the answer, we need to know about the Newton's equation of motion.

Newton's equations are

V= final velocity, U= initial velocity, a= acceleration, t= time and S = distance

60²-0= 2a×0.2= 0.4a

Thus, we can conclude that the acceleration of the fireshell lasted for 0.007s.

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