Select the correct answer. What does a mechanical engineer do? O A. Designs buildings. OB. Designs roads. C. Designs consumer products. D. Designs machines,​

Answer:

90 degrees

Explanation:

In the case when the sheer stress acts in the one plane of an element so it should be equal and opposite also the shear stress acted on a plan i.e. 90 degrees from the plane

Therefore as per the given situation it should be 90 degrees from the plane

hence, the same is to be considered and relevant too

Answer:

Technician B says that the reading is determined by where a dial points on a scale.

Explanation:

A refractometer is a devise used by scientists to gauge a liquids index of refraction.

The refractive index of a liquid is the ratio of light velocity of a specific wavelength in air to its velocity in the substance in evaluation.

The steps of reading a measurement are;

Answer:

C - Prototype model

Explanation:

I believe it's C but Hope this Helps!

Answer:

See how many inches are in a foot

measure width and hight of places

Nail grabbing

Explanation:

Answer:

1. Vgs<0.7

2. Vgs>2.5

3. 0.7<vgs<2.5

Explanation:

The information below was used to answer to answer this question.

Vds = 1.8V

Vt = 0.7V

1.

The cutoff region

Vgs < Vt

= Vgs < 0.7 volts

This the cut off region

2.

Linear region

Vds < Vgs - Vt

When we put in the values

1.8V < Vgs - 0.7V

1.8V+0.7V < Vgs

2.5Volts < Vgs

This is the linear region when Vgs > 2.5 volts

3.

The saturation region

Vds > Vgs - Vt

When we put in the values we have:

1.8V > Vgs - 0.7V

2.5V > Vgs

And 0.7 < Vgs

Then the saturation region is:

0.7V < Vgs < 2.5 V

Answer:gears

Explanation:

Although mechanical brakes are equally crucial in manufacturing, material handling, and other power transmission applications, most people are only aware with vehicle brakes. Thus, option A is correct.

A rotating cylinder is slowed down by the brake pad pushing outward in mechanical drum brakes. Friction is used by the cylinder to stop. For your off-road vehicle, a mechanical brake system is a high-quality braking option. Your cars' durability and effectiveness can both be improved by mechanical drum brakes.

One of the earliest and most popular varieties of mechanical brakes is the drum brake. The brake pad is fastened to a curved bracket known as a shoe. There are typically two shoes inside the drum, and when they are engaged, they press on the interior of the drum to reduce its rotation.

Therefore, Early drum brakes systems were mechanically operated by all the Gears.

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Answer:

[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]

[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]

Explanation:

Given

[tex]Weight=2000lb[/tex]

[tex]Area = 160ft^2[/tex]

Required

Determine the wing loading (W)

Wing loading is calculated using:

[tex]W = \frac{Weight}{Area}[/tex]

Substitute values for Weight and Area

[tex]W = \frac{2000lb}{160ft^2}[/tex]

[tex]W = 12.5\ lb/ft^2[/tex]

The answer can also be converted to N/m^2

[tex]1\ lb = 4.4482216153N[/tex]

[tex]1ft^2 = 0.092903m^2[/tex]

So, we have:

[tex]W = \frac{12.5 * 4.4482216153N}{0.092903m^2}[/tex]

[tex]W = \frac{55.6027701912N}{0.092903m^2}[/tex]

[tex]W = 598.503N/m^2[/tex]

Hence, the wing loading is:

[tex]W = 12.5\ lb/ft^2[/tex] --- in [tex]lb/ft^2[/tex]

[tex]W = 598.503N/m^2[/tex] --- in [tex]N/m^2[/tex]

Answer:

The greatest mass, that the weight C can have such that block A does not move is approximately 23.259 kg

Explanation:

The given parameters are;

The mass of the block A= 58 kg

The coefficient of static friction between the block and the surface, [tex]\mu _s[/tex] = 0.300

The coefficient of static friction between the rope and the fixed peg, B [tex]\mu _B[/tex] = 0.310

Let T represent the tension in the rope

Therefore, when the rope is static, T = The normal reaction at the peg, B, [tex]N_B[/tex]

The angle of inclination of the rope holding the block A = arctan(3/4) ≈ 36.87°

The length of the rope = √(0.4² + 0.3²) = 0.5

∴ sin(θ) = 3/5 = 0.6

cos(θ) = 4/5 = 0.8

The vertical component of the tension in the rope = T × sin(θ) = 0.6·T

The horizontal component of the tension in the rope = T × cos(θ) = 0.8·T

The friction force = μ×(W - 0.6·T) = 0.300×(58×9.8 - 0.6·T) = 170.52 - 0.18·T

The block will start to move when we have;

The horizontal component of the tension in the rope = The friction force

∴ 0.8·T = 170.52 - 0.18·T

0.8·T + 0.18·T = 170.52

0.98·T = 170.52

T = 170.52/0.98 = 174

Therefore, the tension in the rope = T = 174 N = The normal reaction at the peg, B [tex]N_B[/tex]

The frictional force at the peg, [tex]F_B[/tex] = [tex]\mu _B[/tex] × [tex]N_B[/tex] = 0.310 × 174 N = 53.94 N

The weight of the mass, [tex]m_c[/tex], [tex]W_c[/tex] = The frictional force at the peg, [tex]F_B[/tex]  + The tension in the rope

∴ The weight of the mass, [tex]m_c[/tex], [tex]W_c[/tex] = 53.94 N + 174 N = 227.94 N

Weight, W = Mass, m × The acceleration due to gravity, g, from which we have;

m = W/g

Where;

g = 9.8 m/s²

∴ [tex]m_c[/tex] = [tex]W_c[/tex]/g = 227.94 N/(9.8 m/s²) ≈ 23.259 kg.

The greatest mass, that the weight C can have such that block A does not move = [tex]m_c[/tex] ≈ 23.259 kg.

Answer:D

Explanation:

All the options given regarding the hazard communication standard are correct except option D "prepare and post a list of employees who handle hazardous and toxic substances in the workplace".

The main requirements of employers that use hazardous chemicals are:

• ensure that chemicals are properly labelled.

• provide safety data sheets.

• train employees.

• create a written hazard communication program.

It should be noted that preparing and posting a list of employees who handle hazardous and toxic substances in the workplace is incorrect.

Therefore, the correct option is D.

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Answer:

10 ohms Ω

Explanation:

V = IR

120 = I(12)

120/12 = 10Ω

Answer:

The amperage draw of the condensing unit will be low.

Explanation:

A condensing unit is made up of a compressor and condenser, while an evaporating unit is made up of an evaporator coil.

A split AC system is a type of air conditioner system that has a condensing unit which is placed separately from the evaporative coil unit. Then the two units are connected to each other via a copper tube containing refrigerants.

The liquid line connects the condenser to the evaporator, and if this liquid line is restricted, the amp consumed by the condensing unit will be low.

Answer:

0,285 is the answer

Explanation:

Answer:

Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:

u = [tex]\frac{C1}{r }[/tex] + C2

u = [tex]\frac{\frac{-320}{3} }{r}[/tex] + [tex]\frac{320}{3}[/tex]

Explanation:

Solution:

Note: This question is incomplete and lacks necessary data to solve this question. But I have found a similar question and will try to solve it.

This question has this following part missing:

"If the temperature of the outer sphere is maintained at 80 degrees and the inner sphere at 0 degrees.

Now, this question is complete.

Let's find out the steady state temperature distribution.

As, we know the spherical symmetric heat equation:

[tex]\frac{du}{dt}[/tex] = [tex]\frac{k}{r^{2} }[/tex] [tex]\frac{D}{Dr}[/tex] ([tex]r^{2}[/tex] [tex]\frac{Du}{Dr}[/tex])

Where, small (d) represents the partial differentiation and Capital D represents simple derivative.

And the ordinary differential equation (ODE) for steady state temperature distribution is:

[tex]\frac{k}{r^{2} }[/tex] [tex]\frac{D}{Dr}[/tex]([tex]r^{2}[/tex] [tex]\frac{Du}{Dr}[/tex]) = 0

So it can be said that:

[tex]r^{2}[/tex] [tex]\frac{Du}{Dr}[/tex]

Consequently,

[tex]\frac{Du}{Dr}[/tex] = [tex]\frac{C1}{r^{2} }[/tex]

Taking derivative of the above equation we get:

u = -[tex]\frac{C1}{r }[/tex] + C2

Solution of the ordinary differential equation

u = [tex]\frac{C1}{r }[/tex] + C2 (Consuming the negative sign into C1 constant)

As, it is given in our question that our boundary conditions are: 1 and 4

So,

Putting the boundary conditions into the variable (r) to find the constants we get:

u1 = [tex]\frac{C1}{1} }[/tex] + C2 = 0 (degrees)

u1 = C1 + C2 = 0 (degrees)  equation (1)

Similarly,

u4 = [tex]\frac{C1}{4}[/tex] + C2 = 80 (degrees)

u4 = [tex]\frac{C1}{4}[/tex] + C2 = 80 (degrees)  equation (2)

Solving for C1, we get:

Equation 1 - Equation 2

(C1 - C2 = 0) - ([tex]\frac{C1}{4}[/tex] + C2 = 80)

[tex]\frac{-3}{4}[/tex]C1 = 80

Solving for C1

C1 = -[tex]\frac{320}{3}[/tex]

With the help of value of C1, we get value of C2

Put the value of C1 in equation (1) to get value of C2

C1 + C2 = 0

-[tex]\frac{320}{3}[/tex] + C2 = 0

Solving for C2

C2 = [tex]\frac{320}{3}[/tex]

Hence, the steady state temperature distribution between concentric spheres with radii 1 and 4 is:

u = [tex]\frac{C1}{r }[/tex] + C2

Plugging in the values of C1 and C2

u = [tex]\frac{\frac{-320}{3} }{r}[/tex] + [tex]\frac{320}{3}[/tex]

Answer: I'm pretty sure your taking a W.

your getting a W, lucid isn't that bad to trade, you can probably flip lucid for more shiny's and getting a better offer because omen has bad demand and you can tell someone to switch it for something better you can flip lucid and get better pets ok so accept and trade lucid unless you wanna keep it.

Explanation:

Answer:

gg's if you did it cause w

Explanation:

Answer:

The distance between the station A and B will be:

[tex]x_{A-B}=55.620\: km[/tex]  

Explanation:

Let's find the distance that the train traveled during 60 seconds.

[tex]x_{1}=x_{0}+v_{0}t+0.5at^{2}[/tex]

We know that starts from rest (v(0)=0) and the acceleration is 0.6 m/s², so the distance will be:

[tex]x_{1}=\frac{1}{2}(0.6)(60)^{2}[/tex]

[tex]x_{1}=1080\: m[/tex]

Now, we need to find the distance after 25 min at a constant speed. To get it, we need to find the speed at the end of the first distance.

[tex]v_{1}=v_{0}+at[/tex]

[tex]v_{1}=(0.6)(60)=36\: m/s[/tex]

Then the second distance will be:

[tex]x_{2}=v_{1}*1500[/tex]

[tex]x_{2}=(36)(1500)=54000\: m[/tex]        

The final distance is calculated whit the decelerate value:

[tex]v_{f}^{2}=v_{1}^{2}-2ax_{3}[/tex]

The final velocity is zero because it rests at station B. The initial velocity will be v(1).

[tex]0=36^{2}-2(1.2)x_{3}[/tex]

[tex]x_{3}=\frac{36^{2}}{2(1.2)}[/tex]  

[tex]x_{3}=540\: m[/tex]

Therefore, the distance between the station A and B will be:

[tex]x_{A-B}=x_{1}+x_{2}+x_{3}[/tex]  

[tex]x_{A-B}=1080+54000+540=55.620\: km[/tex]  

I hope it helps you!

Answer:

1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS

Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).

2. SLOW DOWN AND PULL OFF THE ROAD

Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.

3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE

The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.

4. STAY IN YOUR VEHICLE

If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.

5. BE VISIBLE

Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.

6. SET UP FLARES OR TRIANGLES

Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.

7. CALL FOR HELP

Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.

Hope this helps :)

Answer:

B. 26 rpm

Explanation:

The sprocket has a diameter of 10 in

The back wheel has a diameter of 6.5 in

One complete revolution formula is : 2πr -------where r is radius

For the sprocket , one revolution = π * D where D=2r

π * 10 = 31.4 in

For the back wheel, one revolution = π* 6.5 = 20.42 in

The pedaling rate is : 40 rpm

Finding the ratio of revolutions between the sprocket and the back tire.

In one revolution; the sprocket covers 31.4 in while the back tire covers 20.42 in so the ratio is;

20.42/ 31.4 = 0.65

So if the speed in the sprocket is 40 rpm then that in the back tire will be;

40 * 0.65 = 26 rpm

Answer:

Explanation:

Rust is quite simply hydrated Iron oxide because it is as a result of iron allows coming into contact with oxygen(air) and water.

The resulting reaction gives off rust as a product. The chemical reaction is:

                                  4Fe + 3O₂ + 6H₂O → 4Fe(OH)₃.

You can see from above how rust is formed from Iron alloys, Oxygen and water.

As iron is a widely used components in the production of many things such as cars, rust presents a problem because in dissolving away iron, the object produced is compromised and this can lead to serious consequences if left unchecked.

Answer:

A. How the driver understands and processes the things his or her eyes receive.

Explanation:

When driving, visual interpretation occurs in two things;

Proper vision is vital while driving. There is the central vison and the peripheral vision. The central vision is what the driver sees in front through the windshield straight ahead. The Peripheral vision is what is seen at the corners of the eyes.

In driving, visual interpretations are important as it entails what the driver sees and A. How the driver understands and processes the things his or her eyes receive.

It's important for drivers to have proper vision when driving. A driver should be able to interpret what the driver sees around him or her passively.

Also, it's important for the drive to be able to understand and processes the things his or her eyes receive. This is vital in order to prevent accidents.

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Answer:

A) Batch shop production

B) Batch shop production

C) Job shop production

D) production line

Explanation:

A)The preferred production system here will be  Batch shop production because the manufacturer produces different styles of clothing and sells to small specialty stores hence producing in Batches can help meet up the needs

B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches

C) Job shop production

D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production

Answer:

Divide the first number by the second.

Explanation:

~55%

Answer:

About 54-55% It depends on if you need to round.

Explanation:

Answer:

It is created from deposition from flow into a lake or an ocean like the Missisippi delta

Explanation:

Answer:

C: deposition from flow into a lake or an ocean

Explanation:

deposition from rivers creates a variety of features, delta deposits created by flow into lake or ocean, is one of them.

Answer:

Weld root

Explanation:

Weld root is the point where the back of a weld intersects with the base metal surfaces.

The weld root determines the penetration of the weld and the fusion to form a joint that is rigid.

Answer:

The Bailey family has flourished during its business’ 110-year history. But Bailey Nurseries’ leaders still operate with the belief that the family doesn’t always know best. The company has grown from a one-man operation selling fruit trees and ornamental shrubs to one of the largest wholesale nurseries in the United States, thanks to insights from those who are family and those who aren’t.

“For a business to thrive, you have to ask for outside help,” says Terri McEnaney, president of the Newport-based company and a fourth-generation family member. “We get an outside perspective through family business programs, advisors and our board, because you can get a bit ingrained in your own way of thinking.”

When Bailey Nurseries chose its current leader in 2000, it brought in a facilitator who gathered insights from key employees, board members and owners. Third-generation leaders (and brothers) Gordie and Rod Bailey picked Rod’s daughter McEnaney, who had experience both inside and outside the company.

Explanation:

Answer:

The power dissipated by a resistor will be: 0.4 watt

Explanation:

Given

To determine

Using the formula to determine the power dissipated by a resistor

Power = I²R

           = (0.02)² × (1000)

           = 0.0004  × 1000

           = 0.4 watt

Therefore, the power dissipated by a resistor will be: 0.4 watt

Answer:

$199.87

Explanation:

Just take $253 times 0.21 to get $53.13. This is how much lower the bill was. Next take 253 - 53.13 to get 199.87, which is the total bill amount for September.

Answer:

1.1⁰C

Explanation:

Width W = 5mm = 0.005

Thickness t = 1 mm = 0.001

K = thermal conductivity = 150W/m.K

P = q = heat transfer rate = 4W

We are to find the steady state temperature between the back and the front surface

We have to make these assumptions:

1. There is steady state conduction

2. The heat flow is of one dimension

3. The thermal conductivity is constant

4. The heat dissipation is uniform

We have:

∆t = t*P/k*W²

= (0.001m x 4W)/150x(0.005)²

= 0.004/0.00375

= 1.06667

This is approximately,

1.1⁰C

Thank you!

Answer: The mass of the substance is 20 g

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml  = 250 ml   [tex](1cm^3=1ml)[/tex]

moles of [tex]NaOH[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{xg}{40g/mol}[/tex]

Now put all the given values in the formula of molality, we get

[tex]2=\frac{x\times 1000}{40\times 250}[/tex]

[tex]x=20g[/tex]

Therefore, the mass of the substance is 20 g

Answer:

true

Explanation: