Select the correct answer. Using synthetic division, find (2x4 + 4x3 + 2x2 + 8x + 8) ÷ (x + 2). A. B. C. D.

Answers

Answer 1

Step-by-step explanation:

If you use synthetic division, you get,

[tex]2x {}^{3} + 2x + 4 + \frac{0}{x + 2} [/tex]

Which is,

[tex]2x {}^{3} + 2x + 4[/tex]

Answered by GAUTHMATH

Answer 2

Answer:

The correct answer is:

2x^3+2x+4

Step-by-step explanation:

I got it right on the Plato test.


Related Questions

Ms.James shared 5/8 of the candies she had in a bag and had 15 left.How many candies did she have before sharing?​

Answers

Answer:

40

Step-by-step explanation:

If you take 15, and divide it by the 3 out of the 3/8 left, you get 5. You then multiply 5 by 8 to get the full amount of candies she had before sharing, 40.

I hope this helped!

Thanks!

Your friend in answering,

~Steve

Answer:

40.

Step-by-step explanation:

If 15 candies are the rest of 3/8, then the total candies were 40.

21(2-y)+12y=44 find y​

Answers

Answer: y= -2/9
Explanation:
21(2-y)+12y=44
42-21y+12y=44
42-9y=44
-9y=2
y=-2/9

Answer:

[tex]\textbf{HELLO!!}[/tex]

[tex]21\left(2-y\right)+12y=44[/tex]

[tex]42-21y+12y=44[/tex]

[tex]~add ~similar\:elements[/tex]

[tex]42-9y=44[/tex]

[tex]Subtract~42~from~both~sides[/tex]

[tex]42-9y-42=44-42[/tex]

[tex]-9y=2[/tex]

[tex]Divide\:both\:sides\:by\:}-9[/tex]

[tex]\frac{-9y}{-9}=\frac{2}{-9}[/tex]

[tex]y=-\frac{2}{9}[/tex]

----------------------

hope it helps...

have a great day!

PLEASE HELP ME WITH THIS ONE QUESTION
If Linda is at the store and can buy any two fruits (the store sells apples, oranges, pears, bananas, and kiwis), how many combinations of fruit can she choose?
A) 25
B) 3
C) 10
D) 15

Answers

Answer:

option C

Step-by-step explanation:

Total number of items = 5

Number of items to choose = 2

Therefore, the number of combinations is

                                                       [tex]5C_2 = \frac{5 \times 4}{1 \times 2} = 10[/tex]

Use the Law of Sines to write an expression that represents the angle measure x.

Answers

Answer:

Step-by-step explanation:

Law of sines says that the length of sides are proportional to the sine of the opposing angle.

Using the sine rule,

sin(x)/2.5 = sin(28)/3

therefore

sin(x) = 2.5 * sin(28) / 3

or

here we have

x = asin (2.5*sin(28) / 3)

so

box 1 = 2.5

box 2 = 28°

box 3 = 3

pls help! show your work!
(3sqrt4)/(3sqrt5)

Answers

Answer:

3sqaure root 100/5

Step-by-step explanation:

It would look like this picture Below

Part 3: The Space Inside! 1. Find the volume of the shipping box using the two methods and show your work: 2. Using the volume formula

3. Explain how both methods provide the same measurement of volume for the shipping box.

Answers

9514 1404 393

Answer:

  36 9/16 cubic feet

Step-by-step explanation:

1.

Volume formula

  V = LWH

  V = (3 3/4 ft)(3 ft)(3 1/4 ft) = (15/4)(3)(13/4) ft³ = 585/16 ft³

  V = 36 9/16 ft³ . . . the volume of the shipping box

__

Packing cubes

Each cube measures 1/4 ft on a side. In terms of cubes, the dimensions of the box are ...

  3 3/4 ft = 15/4 ft = 15×(1/4 ft)   ⇒   15 cubes

  3 ft = 12/4 ft = 12×(1/4 ft)   ⇒   12 cubes

  3 1/4 ft = 13/4 ft = 13×(1/4 ft)   ⇒   13 cubes

This means 15 cubes can be lined up along the bottom front of the box. 12 such lines can make one layer of cubes covering the bottom of the box, and 13 such layers will fill the box.

The total number of cubes in the box is ...

  15 × 12× 13 = 2340 . . . . fish food cubes

Each cube has a volume of (1/4 ft)³ = 1/64 ft³, so the volume of the shipping box is ...

  (2340 cubes)×(1/64 ft³/cube) = 2340/64 ft³

  = 36 9/16 ft³ . . . shipping box volume

__

2.

Using the volume formula, the volume is 36 9/16 ft³

Using the packing cubes method, the volume is 36 9/16 ft³

__

3.

If you consider the math used in the packing cubes method, you see it looks like ...

  V = (15)(12)(13) × (1/64 ft³)

  = (15)(12)(13)×(1/4 ft)³ = (15×1/4 ft)(12×1/4 ft)(13×1/4 ft)

  = (3 3/4 ft)(3 ft)(3 1/4 ft)

  = LWH

That is, the "packing cubes method" is simply a rearrangement of the volume formula product using the commutative and associative properties of multiplication. The same numbers are used to compute the product, but in a different order. Hence the result must be the same.

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

Weights of Dogs in Shelter A
2 box plots. The number line goes from 6 to 30. For the weights of dogs in shelter A, the whiskers range from 8 to 30, and the box ranges from 17 to 28. A line divides the box at 21. For shelter B, the whiskers range from 10 to 28, and the box ranges from 16 to 20. A line divides the box at 18.
Weights of Dogs in Shelter B

Which is true of the data in the box plots? Select three choices.
The median weight for shelter A is greater than that for shelter B.
The median weight for shelter B is greater than that for shelter A.
The data for shelter A are a symmetric data set.
The data for shelter B are a symmetric data set.
The interquartile range of shelter A is greater than the interquartile range of shelter B.

Answers

Answer:

The median weight for shelter A is greater than that for shelter B.

The data for shelter B are a symmetric data set.

The interquartile range of shelter A is greater than the interquartile range of shelter B.

Step-by-step explanation:

The median weight for shelter A is greater than that for shelter B.

The median of A = 21 and the median of B = 18  true

The median weight for shelter B is greater than that for shelter A.

The median of A = 21 and the median of B = 18   false

The data for shelter A are a symmetric data set.

False, looking at the box it is not symmetric

The data for shelter B are a symmetric data set.

true, looking at the box it is  symmetric

The interquartile range of shelter A is greater than the interquartile range of shelter B.

IQR = 28 - 17 = 11 for A

IQR for B = 20 -16 = 4  True

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.
Calculate the cyclist's average speed in mph.

Answers

Answer:

v = 15 mph

Step-by-step explanation:

Given that,

A cyclist travels 3 miles in 15 minutes and then a further 7 miles in 25 minutes without stopping.

Total distance, d = 3 + 7 = 10 miles

Total time, t = 15 + 25 = 40 minutes = 0.6667 hours

Average speed,

[tex]v=\dfrac{d}{t}[/tex]

Put all the value,

[tex]v=\dfrac{10}{0.6667}\\\\= $$14.99\ mph[/tex]

or

v = 15 mph

So, the required average speed is equal to 15 mph.

What is the volume of a sphere with a radius of 20 m? 10,666.67π m3 6,000π m3 85,333.33π m3 533.33π m3

Answers

Answer:10,666,66 [tex]\pi[/tex]m^3

Step-by-step explanation:

V=[tex]\frac{4}{3} \pi r^{3}[/tex]

[tex]\frac{4}{3} \pi 20^{3} \\ V=10,666.66 \pi[/tex]


A jet travels 5192 miles against a jetstream in 8 hours and 6072 miles with the jetstream in the same amount of time. What
is the rate of the jet in still air and what is the rate of the jetstream?

Answers

the answer is in the picture

CollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollege

Answers

CollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollege

CollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollegeCollege

Solve the Inequality: [tex]\frac{b}{3} \geq -1[/tex]

Answers

[tex] \frac{b}{3} \geq - 1 \\ = 3 \times \frac{b}{3} \geq \times ( -1 ) \\ = b \geq3 \times ( - 1) \\ = b \geq - 3 \times 1 \\ \\ = b \geq - 3[/tex]

Step By Step Explanation:

Multiply both sides of the inequality by 3Reduce the numbers with the greatest common factor 3Multiplying a positive and a negative equals a negative Any expression multiplied by 1 remains the same

☆彡Hanna

#CarryOnLearning

Please answer the following.

Answers

Answer:

[tex] \sqrt{4 \times 5 + \sqrt{4 \times 9} } [/tex]

help with algebra 1 equation pls help

Answers

Answer:

b.    [tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Step-by-step explanation:

[tex] l = 14j + 3k [/tex]

Switch sides.

[tex] 14j + 3k = l [/tex]

Subtract 14j from both sides.

[tex] 3k = l - 14j [/tex]

Divide both sides by 3.

[tex] \blue{k = \dfrac{l - 14j}{3}} [/tex]

Solve for H.[tex]V = \pi r^{2} h[/tex]

Answers

Answer:

h = [tex]\frac{V}{\pi r^2}[/tex]

Step-by-step explanation:

Given

V = πr²h ( isolate h by dividing both sides by πr² )

[tex]\frac{V}{\pi r^2}[/tex] = h

According to records, the amount of precipitation in a certain city on a November day has a mean of inches, with a standard deviation of inches. What is the probability that the mean daily precipitation will be inches or less for a random sample of November days (taken over many years)

Answers

Answer:

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is mean amount of inches of rain and [tex]\sigma[/tex] is the standard deviation.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex]

n days:

This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]

Applying the Central Limit Theorem to the z-score formula.

[tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

What is the probability that the mean daily precipitation will be of X inches or less for a random sample of November days?

The probability that the mean daily precipitation will be of X inches or less for a random sample of n November days is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is mean amount of inches of rain and [tex]\sigma[/tex] is the standard deviation.

sum of 15,-2 and 7 is​

Answers

Answer:

20

Step-by-step explanation:

15+(-2)+7=13+7=20

[tex]\longrightarrow{\blue{20}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]\:15 + ( - 2) + 7[/tex]

➺ [tex] \: 15 - 2 + 7[/tex]

➺ [tex] \: 22 - 2[/tex]

➺ [tex] \: 20[/tex]

Note:-

[tex]\sf\pink{PEMDAS\: rule.}[/tex]

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}[/tex]

John, Jack, and Jill have 159 marbles altogether. John has 2 more marbles than Jack, and if Jill gave 5 marbles to Jack, Jack would have the same number of marbles as Jill. How many marbles does each of them have?

Answers

Answer:

someone else tell me to thank you

pls I have limited time left pls help​

Answers

Answer:

2B+5C

Step-by-step explanation:

Multiply them out....

2B=2*(4i-j) = 8i-2j

5C=5*(2i+3j) = 10i+15j

2B+5C= 8i-2j+10i+15j =18i+13j = A

9514 1404 393

Answer:

  a)  2B +5C

Step-by-step explanation:

It is probably easiest to simply try the answer choices. You find the first one works, which means it is the one you want.

  2B +5C = 2(4i -j) +5(2i +3j) . . . . choice (a)

  = 8i -2j +10i +15j

  = 18i +13j = A

__

In general, you can solve for the coefficients p and q that make ...

  pB +qC = A

  p(4i -j) +q(2i +3j) = 18i +13j

  (4p+2q)i +(-p +3q)j = 18i +13j

Equating the coefficients of i and j gives us 2 equations in p and q.

  4p +2q = 18

  -p +3q = 13

Adding 2 times the second equation to 1/2 the first, we get ...

  1/2(4p +2q) +2(-p +3q) = 1/2(18) +2(13)

 7q = 35

 q = 5

Using the second equation to find p, we get ...

  p = 3q -13 = 3(5) -13 = 2

These coefficients tell us ...

  A = 2B +5C . . . . . . . matches choice (a)

How much is 13,200 feet in miles

Answers

Answer:

2.5 miles

Step-by-step explanation:

What is the length of each leg of the triangle below?
459
22
90°
45
O A. 11.12
B. 1
C. 15
D. 11
ET
F. 22

Answers

Answer:

option A

Step-by-step explanation:

since the given triangle is an isosceles triangle it's two remaining sides are equal

let the length of missing side be x

using pythagoras theorem

a^2 + b^2 = c^2

x^2 + x^2 = 22^2

2x^2 = 484

x^2 = 484/2

x = [tex]\sqrt{242}[/tex]

x = [tex]11\sqrt{2}[/tex]

How to find the account balance

Answers

9514 1404 393

Answer:

  $163,002

Step-by-step explanation:

If you're working problems of this sort, you have been shown formulas and examples. Use the appropriate formula with the numbers of this problem.

For the formula below, you have d=3000, r=0.045, k=4, N=11

  P = (3000)(1 -(1 +0.045/4)^(-11·4))/(0.045/4) ≈ 163,002

The account needs to hold about $163,002 to make this possible.

For the following right triangle find the side length x

Answers

Step-by-step explanation:

everything can be found in the picture

Answer:

x=15

Step-by-step explanation:

Hi there!

We're given a right triangle with the measures of the 2 legs (sides that make up the right angle). We're also given the measure of the hypotenuse (the side opposite to the right angle) as x

We need to find x

The Pythagorean Theorem states that if a and b are the legs and c is the hypotenuse, then a²+b²=c²

Let's label the values of a, b, and c to avoid any confusion first

a=12

b=9

c=x

now substitute into the theorem

12²+9²=x²

raise everything to the second power

144+81=x²

add 144 and 81 together

225=x²

take the square root of 225

15=x (note: -15=x is technically also an answer, but since lengths cannot be negative, it's an extraneous solution in this case)

Therefore, the side length of x is 15

Hope this helps! :)

Jordan has more than 25 coins in his collection.
Which inequality shows the number of coins in Jordan's collection?

Answers

Answer:

x + 25 is an expression, not an inequality.

Jordan has more than 25 coins, so this means that the > symbol will be used.

The answer with this symbol is B. x>25.

Step-by-step explanation:

When traveling to work, Cherise averages 60 miles per hour.Because of heavy traffic in the evening, she averages only 40 miles per hour. If the distance from home to work is 80 miles, how much longer does it take Cherise to make the drive home?

Answers

Answer:  40 minutes

============================================================

Explanation:

The distance traveled is d = 80 miles.

When going to work, her speed is r = 60 mph. She takes t = d/r = 80/60 = 4/3 hours which converts to 80 minutes. Multiply by 60 to go from hours to minutes.

Notice how the '80' shows up twice (in "80 miles" and "80 minutes"). This is because traveling 60 mph is the same as traveling 1 mile per minute.

-----------------

Now as she's coming home, her speed becomes r = 40 and she takes t = d/r = 80/40 = 2 hours = 120 minutes.

The difference in time values is 120 - 80 = 40 minutes.

Her commute back home takes 40 more minutes compared to the morning drive to work.

The ratio of girls to boys in a particular classroom is 4:3. What fraction of the total number of students are boys?

The ratio of boys to the total number of students in a particular classroom is

Answers

Answer:

3:7

Step-by-step explanation:

We know that there are 4 girls and 3 boys and 4+3=7.

PLEASE HELP! I'm lost. :(

In 2005, 1,475,623 students heading to college took the SAT. The distribution of scores in the math section of the SAT follows a normal distribution with mean
µ = 520 and population standard deviation = 115.

What math SAT score is 1.5 standard deviations above the mean? Round answer to a whole number.

Answers

Answer:

A math SAT score of 693 is 1.5 standard deviations above the mean

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean µ = 520 and population standard deviation = 115.

This means that [tex]\mu = 520, \sigma = 115[/tex]

What math SAT score is 1.5 standard deviations above the mean?

This is X when [tex]Z = 1.5[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]1.5 = \frac{X - 520}{115}[/tex]

[tex]X - 520 = 1.5*115[/tex]

[tex]X = 693[/tex]

A math SAT score of 693 is 1.5 standard deviations above the mean

according to a salad recipe each serving requires 4 teaspoons of vegetable oil and 12 teaspoons of vinegar. if 14 teaspoons of vegetable oil were used how many teaspoons of vinegar should be used

Answers

Answer:

42 teaspoons of vinegar

Step-by-step explanation:

Given

[tex]x \to vegertable[/tex]

[tex]y \to vinegar[/tex]

[tex]x : y = 4 :12[/tex]

Required

Find y when [tex]x = 14[/tex]

[tex]x : y = 4 :12[/tex] implies that:

[tex]14 : y = 4 : 12[/tex]

Express as fraction

[tex]\frac{y}{14} = \frac{12}{4}[/tex]

[tex]\frac{y}{14} = 3[/tex]

Multiply by 3

[tex]y = 14* 3[/tex]

[tex]y = 42[/tex]

Rafael ate one-fourth of a pizza and Rocco ate one-third of it. What fraction of the pizza did they eat?

They ate

Answers

Answer:

7/12

Step-by-step explanation:

They ate  1/4  and 1/3

1/4 +1/3

Get a common denominator

1/4 *3/3 + 1/3 *4/4

3/12 + 4/12

7/12

please help me Solve the following equations simultaneously:
solve for x and y

x+3y =6 and 2x+8y=-12​

Answers

Answer:

x+3y =6

2x+8y=-12​

The solutions to your equations are:

x= 42 and y= -12

lets check this

42+-36 =6

84+-96=-12​

Hope This Helps!!!

Other Questions
if cos A= 9\13 find csc A tell whether or not the measurements below form a triangle: 1. 4, 5, 10 2. 12, 26, 20 3. 2, 3, 5 Why is cotyledon the biggest part of a seed? When Napoleon seized the Spanish throne and replaced it with a French king, criollos in Latin America two possible advantages of both print media and electronic media for creating awareness of human right violation What is hydroelectric power?(I know if you copy it from the internet) Label the lettered phases of the cell cycle according to the diagram in Figure. 1-1.Figure 1-1A = B = C = D = 2020 people formed a line. In one move, you are allowed to exchange the positions of two people, separated by one other person. Can you always sort the people form tallest to shortest using these moves? Question 7 of 27Which of the following is an element in the sample space for first rolling anumber cube and then tossing a coin? Find the value of x in the triangle .Please show work What are some of the key terms of Marxs theory of religion, and what do they mean? What are some of the examples Marx uses to illustrate and support his theories? when deos electricity flow an a circuitpa hellp po plss Economic growth and public policy Suppose an American buys stock issued by an Argentinian corporation. The Argentinian firm uses the proceeds from the sale to build a new office complex. This is an example of foreign investment in Argentina. Which of the following policies are consistent with the goal of increasing productivity and growth in developing countries?a. Provide tax breaks and patents for firms that pursue research and development in health and sciences. b. Give families cash payments on the condition that their children show up for school and medical exams. c. Increase taxes on income from savings. d. Protect property rights and enforce contracts. Can someone help I dont understand the question Caroline is going to invest in an account paying an interest rate of 5.2% compounded continuously. How much would Caroline need to invest, to the nearest dollar, for the value of the account to reach $940 in 6 years? Use Lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. f(x,y)= e^xy; X^3+y^3=16 Can i get some help with this! REVIEW: A website with advertisements indicates that the site has sponsors which means the information could be biased.Group of answer choicesTrueFalse Please help me Thank you. Which expression is represented by the model?