Answer:
need points srr
Explanation:
Five resistors, each 10 Ω, are connected in parallel to a voltage source. What is the equivalent resistance of the circuit?
A: 5 Ω
B: 50 Ω
C: 2 Ω
D: 20 Ω
Answer:
So the answer is C: 2 Ω.
Explanation:
The equivalent resistance of a parallel circuit is given by the formula:
1/R_equiv = 1/R1 + 1/R2 + ... + 1/Rn
In this case, there are 5 resistors each with a resistance of 10 ohms, so:
1/R_equiv = 1/10 + 1/10 + 1/10 + 1/10 + 1/10 = 5/10 = 0.5
And the equivalent resistance is:
R_equiv = 1 / 0.5 = 2 ohms
So the answer is C: 2 Ω.
what is the radius of the first null in the diffraction pattern at the moon? recall the formula for diffraction from a circular aperture from chapter q3.
The radius of the first null in the diffraction pattern at the moon would be approximately 9.64 mm
The radius of the first null in the diffraction pattern at the moon can be calculated using the formula for diffraction from a circular aperture. The formula for the radius of the first null, or the first dark fringe, is given by:
r = λ × D / a,
where λ is the wavelength of light, D is the distance from the aperture to the screen, and a is the radius of the circular aperture. In the case of diffraction at the moon, the aperture is the diameter of the moon, and the screen is the observer's eye or a detector. The diameter of the moon is approximately 3,476 kilometers, and the distance from the moon to the Earth is approximately 384,400 kilometers. The wavelength of light used for observation can vary, but for visible light, it is typically in the range of 400 to 700 nanometers.
By substituting these values into the formula, we can calculate the radius of the first null in the diffraction pattern at the moon.
Let's assume a wavelength of 550 nm (visible light) and use the average value for the diameter of the moon (3,476 km) as the radius (1,738 km) in the calculation.
r = λ × D / a
= (550 × [tex]10^{-9}[/tex] m) × (384,400 × [tex]10^{3}[/tex] m) / (1,738 × [tex]10^{3}[/tex] m)
= 0.000964 m = 9.64 mm
So, the radius of the first null in the diffraction pattern at the moon would be approximately 9.64 mm when observed with a wavelength of 550 nm and the average diameter of the moon as the radius of the circular aperture.
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please help with this problem
Answer:
option d
it is possible in the case of roller only
Explanation:
Current is defined (mathematically) by the equation I is equal to start fraction delta Q over delta t end fraction (for average current) or I is equal to start fraction dQ over dt end fraction (for instantaneous current, using calculus). using whichever definition you are confortable with, when considering current in a wire, this can be stated (conceptually) as which of the following?
Current is the rate at which charge passes a certain place in the wire.
Thus option D is correct.
What does the term "electric current" mean?
The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure. These electrons can be held loosely or securely depending on the situation.
Electric current in a wire, where electrons serve as the charge carriers, is a measurement of the amount of charge that moves through any point of the wire in a given amount of time. Electric charge motion is occasionally reversed in alternating current but not in direct current.
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Complete question:
Current is defined (mathematically) by the equation I is equal to start fraction delta Q over delta t end fraction (for average current) or I is equal to start fraction dQ over dt end fraction (for instantaneous current, using calculus). Using whichever definition you are comfortable with, when considering current in a wire, this can be stated (conceptually) as which of the following?
A. Current is distance times charge (d times Q) divided by distance times time (d times t).
B. Current is the amount of charge in a wire, divided by the time it takes to fill the wire with charge.
C. Current is the rate at which the total charge within the wire is changing.
D. Current is the rate at which charge passes a certain place in the wire.
Two spacecraft
and
are traveling directly towards each other, intending to meet to dock together. Mission control on Earth initially sees spacecraft
moving with a speed of 154.5 m/s and spacecraft
moving with a speed of 133.0 m/s. Each spacecraft will need to come to a complete stop when they meet, and each will slow down using its rockets. The rockets on spacecraft
cause it to slow down at a constant rate of 17.1 m/s2, and the rockets on spacecraft
cause it to slow down at a constant rate of 22.2 m/s2. Spacecraft
turns on its rockets first.
At what distance
from spacecraft
should spacecraft
turn on its rockets in order for the two spacecraft to meet, have zero velocity relative to the Earth, and arrive at the same time?
A spaceship is a machine or vehicle built to travel through space.
What is Spacecraft?Spacecraft are a form of artificial satellite used for a wide range of tasks, such as communications, Earth observation, meteorology, navigation, space colonization, planetary exploration, and cargo and person transfer.
A spacecraft that is performing a sub-orbital spaceflight launches into space and then lands without gaining enough momentum or energy to complete a full orbit of the Earth. Spacecraft enter confined orbits around the Earth or other celestial bodies for orbital spaceflights.
Only humans are carried on human spacecraft either as crew or guests from launch or while in orbit (space stations).
Therefore, A spaceship is a machine or vehicle built to travel through space.
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12. Consider the falling and rolling motion of the 2.0 kg ball in the following two resistance-free
situations. In one situation, the ball falls off the top of the platform to the floor. In the other situation,
the ball rolls from the top of the platform along the staircase-like pathway to the floor. Fill in answer
for each the blanks lettered A-K.
PE=100J
KE=0J
PE= F J
KE- GJ
v=__H_m/s
PE=50J
KE-A J
V= B_m/s
PE=_C_J
KE=D J
v=__E__m/s
Answer the questions using logic and a little bit of arithmetic.
Top & Bottom:
1. What is the PE of the ball at the very top of the diagram above?
2.
What is the KE of the ball at the very top of the diagram above?
3. What is the PE of the ball the location shown as I on the diagram above?
4. What is the KE of the ball the location shown as J on the diagram above?
5.
What is the velocity of the ball the location shown as K on the diagram above?
requires a little mental math - but you can use a calculator if you need it.
6. What is the PE of the ball the location shown as F on the diagram above as the ball hits the ground?
10
PE=IJ
KE J J
v=K_m/s
8. What is the velocity of the ball the location shown as H on the diagram above?
your previous answers-don't solve the velocity equation.
7. What is the KE of the ball the location shown as G on the diagram above as the ball hits the ground?
Rolling down the ramp:
9. What is the KE of the ball the location shown as A on the diagram above?
This one
Use logic &
10. What is the velocity of the ball the location shown as B on the diagram above? Use logic & your previous
answers-don't solve the velocity equation.
11. What is the PE of the ball the location shown as C on the diagram above?
12. What is the KE of the ball the location shown as D on the diagram above?
13. What is the velocity of the ball the location shown as E on the diagram above? Use logic & your previo
answers-don't solve the velocity equation.
Gravity is the only force that is active. The overall mechanical energy is preserved since it is an inner or conservative force. As a result, each location has the 100 J of initial mechanical energy. So, 50 J is the KE for A.
The KE is 50 J because the PE at the exact same stairstep is Fifty J (C) (D).
The PE is 0 J at zero height (F and I). As a result, there is 100 J of velocity just at bottom of the hill (G and J).
The velocity may be calculated as 7.07 m/s for B and E as well as 10 m/s for H and K using the formula KE = 0.5*m*v2.
The answers provided here for the speed numbers are based on the assumption that 100% of the ball's kinetic energy is present as translational kinetic energy. The kinetic energy really would take some of the form of rotating kinetic energy. The real speed figures would thus be a little bit lower than those reported. (Torque and angular velocity is not covered in this tutorial for the physics classroom.)
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A boat with initial speed v0 is launched on a lake. The boat is slowed by the water by a force F = −αeβv. (a) Find an expression for the speed v(t). (b) Find the time and (c) distance for the boat to stop.
The gap the boat travels earlier than slowing down is 2.303m/[tex]αe^2[/tex] v0 ln(10)
How to find an expression for the speed v(t)?The equation of movement for the boat is given through:
m dv/dt = -[tex]αe^2v[/tex]
in which m is the mass of the boat, v is the rate of the boat, and α is a steady that relies upon at the residences of the water.
To resolve for the rate of the boat as a feature of time, we are able to separate the variables and combine each facets of the equation:
[tex]m \int\limits v0^v dv / (v*√(1/v)) = -αe^2 ∫ zero^t dt[/tex]
Simplifying the left-hand aspect the usage of the substitution u = 1/v and [tex]du = -dv/v^2[/tex], we get:
[tex]-m ∫ 1/v0^1/v du = -αe^2 t\\-m ln(v/v0) = -αe^2 t\\ln(v/v0) = αe^2 t / m\\v(t) = v0 * e^(-αe^2 t / m)[/tex]
To discover the time at which the boat stops, we are able to set v(t) identical to 0 and resolve for t:
[tex]v(t) = v0 * e^(-αe^2 t / m) = zero\\e^(-αe^2 t / m) = zero\\-αe^2 t / m = -∞\\t = ∞[/tex]
v = zero.1v0 We can resolve for t in this example through putting v(t) = zero.1v0:
[tex]v(t) = v0 * e^(-αe^2 t / m) = zero.1v0\\e^(-αe^2 t / m) = zero.1\\-αe^2 t / m = ln(zero.1)\\t = -m/αe^2 ln(zero.1)[/tex]
Finally, to discover the gap the boat travels earlier than it slows down, we are able to combine the rate equation from v0 to zero.1v0:
∫ [tex]x0^x dt = ∫ zero^t v(t) dt[/tex]
in which x0 is the preliminary function of the boat. Substituting for v(t), we get: ∫[tex]x0^x dx / v(x) = -m/αe^2 ln(zero.1)[/tex]
Using the substitution u = v/v0, we get: ∫ [tex]1^zero.1 du / u = -m/αe^2[/tex]ln(zero.1)
[tex]ln(10) = -m/αe^2 ln(zero.1)\\x - x0 = -m/αe^2 ln(zero.1) * ln(10) / v0\\x - x0 = 2.303m/αe^2 v0 ln(10)[/tex]
Therefore, the gap the boat travels earlier than slowing down is 2.303m/[tex]αe^2[/tex] v0 ln(10).
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A point is located in a polar coordinate system by the coordinates r = 4.6 m and = 10°. Find the x- and y-coordinates of this point, assuming that the two coordinate systems have the same origin
Point on Cartesian plane,
x-coordinate = 4.53
y - coordinate = 0.8
What are Polar and Cartesian coordinates?In the Cartesian system the coordinates are perpendicular to one another with the same unit length on both axes. A Polar coordinate system is determined by a fixed point, a origin or pole, and a zero direction or axis. Each point is determined by an angle and a distance relative to the zero axis and the origin.
Given,
Polar coordinates of point (r , θ)
r = 4.6
θ = 10°
Cartesian coordinates of point (x , y)
x = r cosθ
⇒ x = 4.6 × cos 10°
⇒ x = 4.6 × 0.9848
⇒ x = 4.53
y = r sinθ
⇒ y = 4.6 × sin 10°
⇒ y = 4.6 × 0.174
⇒ y = 0.8
Hence, Cartesian coordinates of the point (4.53 , 0.8)
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if the expression for the electric potential due to a small sphere of charge q at point p that is a distance d from the center of a small sphere is kqd , then the electric potential at a point o that is a distance 2d from the center of the small sphere is?
The potential at P is now if twice as much of this charge is uniformly distributed on the surface of a hollow sphere with a radius of 4r and a centre at point A.
What is the electric potential due to a small sphere?Sphere, The collection of points in three dimensions that are all the same distance from the centre (the radius) or the outcome of rotating a circle around one of its diameters.
Because there is no field inside the shell, the potential there is always the same as the potential outside the shell.
They are round, just like the Earth, which is why they are called spheres. The four spheres are the atmosphere, which contains all the gases that surround Earth, the hydrosphere, Which contains all the water on Earth.
Therefore, A sphere's parts and characteristics are comparable to those of a circle.
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in the proton-proton chain select all that apply a.no neutrinos are produced.
b.energy is released because a helium nucleus has a greater mass than a hydrogen nucleus.
c.no photons are produced.
d.carbon serves as a catalyst for the nuclear reaction.
e.energy is produced in the form of gamma rays and the velocity of the created nuclei.
The proton-proton chain is a series of nuclear reactions that take place in the cores of stars and are responsible for producing energy through fusion.
Option b and e will apply for the proton-proton chain.
In the chain, hydrogen nuclei (protons) collide and combine to form helium nuclei, releasing energy in the process.
b. Energy is released because the mass of the helium nucleus formed from the combination of two hydrogen nuclei is less than the total mass of the two individual hydrogen nuclei.
This difference in mass is converted into energy according to Einstein's equation, [tex]E=mc^2[/tex], where E is energy, m is mass and c is the speed of light.
e. Energy is produced in the form of gamma rays and the velocity of the created nuclei. The high-energy gamma rays and fast-moving helium nuclei carry away the energy released in the reaction.
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A thin circular disk of radius R = 30 cm is oriented in the yz-plane with its center as the origin. The disk carries a total charge Q = +3 mu C distributed uniformly over its surface. Calculate the magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis. 4.98 times 10^5 N/C 2.49 times 10^5 N/C 3.32 times 10^5 N/C 9.95 times 10^5 N/C 1.99 times 10^5 N/C
The magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis is approximately 2.99 x 10⁶ N/C. Rounded to two significant figures, the answer is 3.0 x 10⁶ N/C.
What is the magnitude?The magnitude of a physical quantity is a measure of the size of that quantity, and is usually expressed using an appropriate unit of measurement. Magnitude is a way of expressing the size of something without specifying its exact size. For example, when referring to the magnitude of an earthquake, one might say "it was a magnitude 7 earthquake".
To calculate the electric field at a point on the x-axis due to a uniformly charged disk, we can use the formula:
[tex]\mathrm{E = (1/4\pi \p \epsilon_0) \times Q / r^2 \times sin(\theta)}[/tex]
where ε₀ is the permittivity of free space,
Q is the total charge on the disk, r is the distance from the center of the disk to the point where we want to calculate the electric field,
and θ is the angle between the normal to the disk and the line connecting the center of the disk to the point where we want to calculate the electric field.
In this problem, the disk is oriented in the yz-plane, so the normal to the disk is in the x-direction. The distance from the center of the disk to the point where we want to calculate the electric field is 15 cm.
The angle θ is the angle between the normal to the disk and the line connecting the center of the disk to the point where we want to calculate the electric field.
Since the disk is centered at the origin, the line connecting the center of the disk to the point on the x-axis is also in the x-direction, so θ = 0.
We can therefore simplify the formula to:
[tex]\mathrm{E = (1/4\pi \p \epsilon_0) \times Q / r^2 }[/tex]
Substituting the given values, we get:
[tex]\mathrm{E = (1/4\pi \p \epsilon_0) \times (3\mu C) / (0.15)^2 }[/tex]
We can calculate the value of 1/4πε₀ as 9 so:
[tex]\mathrm{E = (9.0 \times 10^9 \ N \cdot m^2/C^2) \times (3\mu C) / (0.15)^2 }[/tex]
E = 2.99 x 10⁶ N/C
Therefore, the magnitude of the electric field due to the disk at the point x = 15 cm along the x-axis is approximately 2.99 x 10⁶ N/C. Rounded to two significant figures, the answer is 3.0 x 10⁶ N/C.
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Two pans of a balance are 33.6 cm apart. The fulcrum of the balance has been shifted 1.35 cm away from the center by a dishonest shopkeeper. By what percentage is the true weight of the goods being marked up by the shopkeeper? Assume the balance has negligible mass. Answer in units of %.
The true weight of the goods being marked up by 8.3% by the shopkeeper.
What is bending moment?A bending moment is the reaction that occurs in a structural element as a result of an external force or moment that causes the element to bend, as defined by solid mechanics. The beam is the most prevalent or most basic structural component that experiences bending moments.
Calculated the bending moment about the balance:
P₁(33.6 + 1.35) = P₂ ( 33.6 - 1.35)
P₂ = 1.083 P₁
Hence, percentage change = (P₂-P₁)/P₁ × 100% = 8.3 %
So, the true weight of the goods being marked up by 8.3% by the shopkeeper.
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When you leap down from a high perch, you have a gentler landing with less force if you bend your knees as you land. Use the principles of impulse and momentum to explain why this approach reduces the force on you.
It is better to land with the knees bent while leaping from a substantial height since it prolongs the time it takes to halt, lessens the impact, and causes less pain.
The equation for impulse-momentum:
Δp = F Δt
Where,
Δp = momentum
F = force
t = time
The equation is referred to as the impulse-momentum theorem. The impulse is defined as the average net external force multiplied by the time it takes for that force to act. It is comparable to the shift in momentum. The strength, duration, and length of action of a force all have an impact on how it affects an object. The idea of impulse is useful since it measures the effect of a force. A strong force operating quickly, as the force of a tennis racket striking the ball, can have a considerable impact on an object's momentum.
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An astronaut floating alone in outer space throws a baseball. If the ball moves away at 20 m/s, the
astronaut will
a. move in the opposite direction at 20 m/s.
b. move in the opposite direction at a lower speed.
c. move in the opposite direction at a higher speed.
d. none of the above
Throwing a baseball while floating alone in space is an astronaut. The astronaut will move in the opposite direction at a slower speed if the ball is moving away at 20 m/s (option B)
Since there is no gravity in space, the ball is not subject to the effects of gravity. When a ball is hurled upward into space, it rises steadily until it collides with an obstruction in its path.
A thrown ball will travel in a straight line and the person tossing the ball will also travel in a straight line in the opposite direction in deep space, which is far enough away from massive objects like stars and planets that gravity may be disregarded.
There is no longer any force exerted on the thing after it is out of your hand (at least in a vacuum). As a result, the object won't accelerate and will continue moving at the same speed as when it first left your hand.
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The water in a tank is pressurized by air,and the pressure is measured by a multifluid manometer as shown in the Fig. The tank is located on a mountain at an altitude of 1400 m where the atmospheric pressure is 85.6 kPa. Determine the air pressure in the tank if â„Ž1 = 0.1 m, â„Ž2 =0.2 m, and â„Ž3 = 0.35 m. Take the densities of water, oil, and mercury to be1000 kg/m3, 850 kg/m3, and 13,600 kg/m3
, respectively?
Air is used to pressurize water in a tank, and the pressure is then measured. by a multifluid manometer so Consequently, the air pressure in the tank is 129.45KPa.
In the physical sciences, pressure is defined as either the stress at a place within a confined fluid or the perpendicular force per unit area. The weight of the atm is atmospheric pressure, which is approximately 15 pounds per square inch at sea level. Each square meter of the Earth's surface is under pressure from the atmosphere.
atmospheric pressure ([tex]P_{atm[/tex])=85.6kPa
[tex]P_{atm[/tex]=85600Pa
density of water=[tex]\rho =[/tex]1000 kg/[tex]m^3[/tex]
density of oil([tex]\rho_0[/tex])=850kg/[tex]m^3[/tex]
density of mercury([tex]\rho_{m[/tex])=13600 kg/[tex]m^3[/tex]
height of water column([tex]h_1[/tex])= 0.1m
height of oil column from water level([tex]h_2[/tex])=0.2m
height of mercury column ([tex]h_3[/tex])=0.35m
pressure at point B
[tex]P_B=P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \: \rightarrow(1)[/tex]
[tex]P_B=P_{atm} +\:\rho_mgh_3\: \rightarrow(2)[/tex]
[tex]P_{air} +\:\rho_0gh_1\: +\rho_wgh_2 \:=P_{atm} +\:\rho_mgh_3\:[/tex]
[tex]P_{air} =\:-\rho_0gh_1\: -\rho_wgh_2 \:+P_{atm} +\:\rho_mgh_3\:\rightarrow(3)[/tex]
[tex]\rho _mgh_3[/tex]=13600x9.8x0.35=46648 Pa
[tex]\rho _0gh_1[/tex] =850x9.8x0.1=833 Pa
[tex]\rho _wgh_2[/tex] =1000x9.8x0.2=1960 Pa
By putting the value in eq.3
[tex]P_{air[/tex]=85600+46648−833−1960 = 129455Pa
therefore pressure of air in the tank is 129.45KPa
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T or F: The definition of boundary layer refers to the region of flow in which both the temperature gradients are significant and frictional effects are important.
The statement "The definition of boundary layer refers to the region of flow in which both the temperature gradients are significant and frictional effects are important" is true because when a fluid is in direct contact with a solid surface and its temperatures are different, a thermal boundary layer forms.
As long as the temperatures of the solid surface and the fluid are different, a thermal boundary layer forms when a fluid is in direct contact with the solid surface, according to the classical theory of heat transfer. In fluid mechanics, a boundary layer is a thin layer of a moving gas or liquid in contact with a surface, like the inside of a pipe or the wing of an airplane. Shear forces act on the fluid in the boundary layer.
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Use the approximation that vavg = pf/m for each time step.
A paddle ball toy consists of a flat wooden paddle and a small rubber ball that are attached to each other by an elastic band (figure). You have a paddle ball toy for which the mass of the ball is 0.011 kg, the stiffness of the elastic band is 0.925 N/m, and the relaxed length of the elastic band is 0.255 m. You are holding the paddle so the ball hangs suspended under it, when your cat comes along and bats the ball around, setting it in motion. At a particular instant the momentum of the ball is <−0.02, −0.01, −0.02> kg · m/s, and the moving ball is at location <−0.2, −0.61, 0> m relative to an origin located at the point where the elastic band is attached to the paddle. Define this instant as t = 0.
(a) Determine the position of the ball 0.1 s later, using a Δt of 0.1 s. (Express your answer in vector form.)
(b) Starting with the same initial position <−0.2, −0.61, 0> m and momentum <−0.02, −0.01, −0.02> kg · m/s, determine the position of the ball 0.05 s later. (Express your answer in vector form.)
(c) Using the position and momentum at t= 0.05 s, determine the position of the ball at t= 0.1 s. (Express your answer in vector form.)
Thank you.
Answer:(a) For the first time step, using Δt = 0.1s:
pf = m * vavg
vavg = pf/m
vavg = (<−0.02, −0.01, −0.02> kg · m/s) / 0.011 kg
To find the position at t = 0.1 s, we need to find the average velocity over the time interval, and multiply it by the time interval:
position = initial position + vavg * Δt
position = <−0.2, −0.61, 0> m + vavg * 0.1 s
(b) To find the position at t = 0.05s, repeat the same steps as in (a) but with Δt = 0.05s.
(c) To find the position at t = 0.1s, starting from the position and momentum at t=0.05s, repeat the same steps as in (a) and (b) with the new initial position and momentum value
Explanation:
A hydraulic jack uses hydrostatic pressure forces to leverage a small applied force to generate a large resulting force (alternatively you can think of it as a type of manometer). A force of magnitude, Fapp = 25 lb is applied to the left side of the jack (which has a square cross-section of side d=2.5 in). The right side of the jack also has a square cross-section but each of side D=10 in. The specific gravity of the oil in the jack is soil = 0.8. The weights of the bearing blocks can be neglected. Note that the surfaces of the bearing blocks on both sides of the jack are horizontala. What is the magnitude of the weight, W, that can be supported by the right side of the jack for the given difference in elevation, 2.4 ft as shown?b. The vertical right side of the right side of the jack is a total height of Htot =2.6 ft (and length into the page of D=10 in ). What is the magnitude of the force due to the hydrostatic pressure on that vertical side? Note that this vertical surface is rectangular in geometry and is of height Htot and length, D, into the page.
92.16 lb is the magnitude of the weight that can be supported by the right side of the jack.
Hydraulic jacks are devices that leverage applied force to generate a larger force. In this case, a 25 lb force is applied to the left side of the jack with a square cross-section of side d = 2.5 in.
The right side of the jack is also square with a cross-section of side D = 10 in and has a difference in elevation of 2.4 ft.
To calculate the magnitude of weight, W, that can be supported by the right side of the jack, we need to calculate the pressure due to the hydrostatic force on the vertical side of the jack.
This vertical side is a rectangular shape of height Htot = 2.6 ft and length D = 10 in. Taking into account the specific gravity of the oil in the jack as soil = 0.8, the hydrostatic pressure on the vertical side is equal to the difference in elevation multiplied by the weight of the oil.
W = 2.4 ft x 0.8 x 62.4 lb/ft³ = 92.16 lb. This is the magnitude of the weight that can be supported by the right side of the jack.
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If the magnitude of the resultant force acting on the bracket is to be 430 N directed along the positive u axis, determine the magnitude of F. (Figure 1) Express your answer with the appropriate units. - LHẢ * * 0 Ea ? F1 - 480.5 N Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining Review your calculations, you may have made a rounding error or used the wrong number of significant figures. Part B Determine the angle o Express your answer with the appropriate units. < 1 of 1 > CHAO ? $ = 8.619 30° F = 200 N Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Review your calculations, you may have made a rounding error or used the wrong number of significant figures. F; 260 N
If the magnitude of the resultant force acting on the bracket is to be 430 N directed along the positive u-axis, the magnitude of F is as follows:
The vector components should be drawn which is acting on the bracket as follows.
The x and y components of each force are represent by the dashed arrows. Force, (in blue) is along the x-axis, thus it has no y-component.
Now, the resultant force is drawn (as stated in the question) and its components also.
After this, can now write the x and y component values of each force.
(F1)x = F1 sinϕ
(F1)y = F1 cosϕ
(F2)x =200N
(F2)y = 0
(F3)x = 260(5/13)=100N
(F3) y =260( 12/13 )=240N
(FR)x =450 cos 30 =389.71N
(FR) y =450 sin 30 =225N
Next is to sum the forces along the x and y axes. To do this, we will establish the positive sides. Pick the forces acting up, and forces acting to the right to be positive.
+→∑(FR) x =∑(Fx)
389.71= F1 sinϕ+200+100
F1 sinϕ=89.71———————————(1)
+↑∑(FR)y=∑(Fy)
225 = F1 cosϕ−240
F1 cosϕ=465———————————(2)
The last step is to solve equations (1) and (2) simultaneously. To do so, remember the identity, sinθ/cosθ = tanθ
Solving gives us:
ϕ=10.9 and F1 = 474N
Therefore, the ϕ=10.9 and F1 = 474N
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From shortest to longest wavelength, which of the following correctly orders the different categories of electromagnetic radiation?
A.gamma rays, X rays, ultraviolet, visible light, infrared, radio
B. infrared, visible light, ultraviolet, X rays, gamma rays, radio
C. gamma rays, X rays, visible light, ultraviolet, infrared, radio
D. radio, infrared, visible light, ultraviolet, X rays, gamma rays
The following correctly orders the different categories of electromagnetic radiation; Radio, infrared, visible light, ultraviolet, X rays, gamma rays.
What is the ultraviolet?Ultraviolet (UV) radiation is a type of electromagnetic radiation emitted from the sun. It is a form of energy that is invisible to the human eye, but it can cause damage to living organisms. UV radiation is divided into three categories: UVA, UVB, and UVC. UVA radiation has the longest wavelength and is the least hazardous form of UV radiation. UVB radiation has a shorter wavelength and is more dangerous. UVC radiation has the shortest wavelength and is the most dangerous form of UV radiation. Exposure to UV radiation can cause sunburns, premature skin aging, and an increased risk of skin cancer.
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question which of the following affect the speed and direction of your vehicle? a. responses momentum b. momentum kinetic energy c. kinetic energy safety belts d. safety belts gravity
e. gravity potential energy f. potential energy inertia g. inertia
The correct answers format are:
a. Responses momentum
b. Momentum kinetic energy
f. Potential energy inertia
g. Inertia
How the factors that affect vehicle speed and direction?A. Momentum - A vehicle's momentum is the product of mass and velocity. The greater the momentum, the more difficult it is to change the speed or direction of the vehicle.
B. Kinetic Energy – A vehicle's kinetic energy is the energy it has as a result of its motion. The greater the kinetic energy, the faster the vehicle and the harder it is to turn.
D. Seat Belts - Seat belts are used to restrain occupants during sudden vehicle stops and collisions. Seating occupants reduces the risk of injury and can affect vehicle speed in the event of an accident.
G. Inertia - Inertia is the impulse of an object to continue changes in its state of motion. The more inertia a vehicle has, the more difficult it is to change speed or direction.
So the correct options to affect the speed and direction of the vehicle are: reaction dynamics, b. momentum kinetic energy, i. seat belt gravity and g. inertia.
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In which one of the following situations does the car have an acceleration that is directed due north? a) A car travels northward with a constant speed of 12 ms. b) A car is traveling southward as its speed increases from 12 ms to 23 m/s c) A car is traveling southward as its speed decreases from 18 ms to 12 m/s d) A car is traveling northward as its speed decreases from 24 ms to 12 m/s e) A car travels southward with a constant speed of 24 mis.
A car is traveling southward as its speed decreases from 18 m/s to 12 m/s have an acceleration that is directed due north.
What is acceleration?
If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both.
Since the speed is decreasing, the acceleration will be in the opposite direction hence option c.
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a trian traveling at 20kmph is accelerated at the rate of 0.5meters squared . what is the distance travelled by the train in 12 second's
Answer:
The distance traveled by train in 12 seconds is 66.72 meters.
Explanation:
The acceleration rate given is in meters per second squared, so we need to convert the velocity of the train to meters per second.
20 km/hr = (20 x 1000)/(60 x 60) = 5.56 m/s
Now we can use the formula for displacement with constant acceleration:
d = v₀t + 0.5at²
where
v₀ = initial velocity = 5.56 m/s
t = time = 12 s
a = acceleration = 0.5 m/s²
Substituting the values, we get:
d = 5.56 x 12 + 0.5 x 0.5 x 12²
d = 66.72 m
What is the value of the electric potential at the center of the triangle if q1 = 4.1 μC , q2 = 3.4 μC , q3 = -3.5 μC ?
Answer:
triangle if q1 = 4.1 μC , q2 = 3.4 μC , q3 = -3.5 μC ?
suppose that a ball is dropped from the upper observation deck of a building, 300 m above the ground. (a) what is the velocity of the ball after 2 seconds? (b) how fast is the ball traveling when it hits the ground? solution we will need to find the velocity both when t
The velocity of the ball is 19.6 m/s and when the ball lands, it is moving at a speed of 77.134 m/s.
What is gravity?All objects with mass are subject to gravity, which is a fundamental force of nature. It is the force that pulls everything toward the core of a planet or other entity.
How do you determine it?(a) The equation can be used to determine the velocity of a dropped ball.
v = v0 + a * t
where a is the acceleration caused by gravity (9.8 m/s2), v0 is the beginning velocity (0 in this case because the ball is dropped from rest), and t is the amount of time that has passed.
Therefore, if t = 2 seconds, the ball's velocity at that time would be:
v = 0 + 9.8 * 2 = 19.6 m/s
(b) The ball's final velocity is identical to its velocity when it lands. The following equation can be used to determine how long it takes the ball to touch the ground:
t = √(2h / a)
where a is the acceleration brought on by gravity (9.8 m/s2) and h is the height (in this case, 300 m) from which the ball is dropped.
Thus, the duration of time required for the ball to touch the ground is:
t = √(2 * 300 / 9.8) = √(600 / 9.8) = √(61.22) = 7.83 s
The formula: can be used to determine the ball's velocity when it lands.
v=v0 + a*t = 0 + 9.8 * 7.83 = 77.134 m/s
So, when the ball lands, it is moving at a speed of 77.134 m/s.
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A 1825 kg plane in a shallow dive accelerates at 7.6 m/s^2. What is the drag force on the plane if the forward force of gravity and thrust add up to 15,000 Newtons?
Answer:
5996667544211123345678
the electric field everywhere on the surface of a thin, spherical shell of radius 0.730 m is of magnitude 875 n/c and points radially toward the center of the sphere.(a) What is the net charge within the sphere's surface? (b) What can you conclude about the nature and distribution of the charge inside the spherical shell?
The net charge within the sphere's surface is 2.36 x 10^-7 C and it can be deduced that the charge within the spherical shell is positively charged and uniformly distributed on its surface.
(a) To ascertain the net charge enclosed within the boundaries of the spherical shell of radius 0.730 meters, we must delve into the intricacies of the electric field and its correlation with the charge distribution on a conductor.
The electric field on the surface of a conductor can be mathematically represented as E = kσ, where k stands for the Coulomb constant and σ symbolizes the surface charge density.
The surface area of a spherical shell can be calculated as 4π[tex]r^2[/tex], where r signifies the radius of the sphere. By fusing these two equations, we can determine the surface charge density as follows:
σ = E / (k) = (875 n/C) / (9 x 10^9 Nm^2/C^2) = 9.72 x 10^-10 C/m^2
The charge contained within the sphere can then be computed as:
Q = σ * 4πr^2 = (9.72 x 10^-10 C/m^2) * 4π * (0.730 m)^2 = 2.36 x 10^-7 C
(b) The electric field, exhibiting a radially inward direction, implies that the charge within the spherical shell is positively charged.
The proportionality between the electric field's magnitude and the net charge within the spherical shell suggests that the charge is distributed uniformly on the surface of the sphere.
In conclusion, it can be deduced that the charge within the spherical shell is positively charged and uniformly distributed on its surface.
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In order to compute a power of two, you can take the next-lower power and double it. For example, if you want to compute 211 and you know that 210 = 1024, then 211 = 2 × 1024 = 2048. Based on this observation, write a recursive function int pow2(int n) where n is the exponent. If the exponent is negative, return -1.
To compute [tex]2^3[/tex], the function first calls itself with [tex]n=2,[/tex] which computes[tex]2^2 = 4[/tex]. Then, the function doubles this result to get [tex]2^3 = 8.[/tex]
Here is the pseudo-code for the pow2 function:
function pow2(n):
if n < 0:
return -1
if n == 0:
return 1
else:
prev_power = pow2(n-1) # Compute 2^(n-1) recursively
return prev_power * 2 # Double the result to get [tex]2^n[/tex]
The base case for the recursion is when n is 0, in which case the function returns 1 since [tex]2^0 = 1.[/tex]
The function recursively calls itself with smaller values of n until it reaches the base case. The recursive calls build up the power of 2 by doubling the previous power.
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When the bottom string is pulled slowly in the heavy-ball-and-strings demonstration (Figure 4.8 in your book), tensiona. is about the same in both strings.b. in the bottom string is zero.c. in the top string is due to your pull plus the weight of the ball.
In the heavy ball and string demonstration, if you pull the bottom string slowly, the tension c) The top string is due to your pull and the weight of the ball.
About stress/tensionWhen a force is applied to an elastic object, the object will stretch to a certain size. The amount of stress is the ratio of the tensile force acting on the cross-sectional area of the body. If the area of a bar is A, then both ends of the bar are subjected to a tensile force of equal magnitude and opposite direction F. The rod should be under tension.
Looking at a cross-section perpendicular to the length of the rod, the tensile force F is evenly distributed over the cross-sectional area A. Stress is therefore defined as the ratio of the magnitude of the force F to the cross-sectional area. . Cross-sectional area of A. The stress is expressed as σ (sigma) and its unit is Nm-².
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Two balls are rolling directly toward each other. One, of mass 0.25 kg, has a speed of 1.7 m/s; the other has a mass of 0.18 kg and a speed of 2.5 m/s. After the collision, the 0.25 kg ball has reversed its direction and has a speed of 0.10 m/s. What is the velocity (magnitude and direction) of the other ball?
m/s direction:
(same/opposite) direction of initial motion for ball
The velocity of the balls that rolling directly toward each other. One, of mass 0.25 kg, has a speed of 1.7 m/s; the other has a mass of 0.18 kg and a speed of 2.5 m/s. After the collision, the 0.25 kg ball has reversed its direction and has a speed of 0.10 m/s = 0 (zero)
The linear momentum of a system of interacting objects equals the linear momentum of the system after the interaction if the net force acting on the system of interacting objects is zero.
The equation:
p = mv
Where,
p = momentum
m = mass of the object
v = the velocity of the object.
p₁ = p₂
(mv + mv)₁ = (mv + mv)₂
(0.25 x 1.7) = (0.25 x (-0.10)
v₂ = 0
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