Answer:
[tex]Time = 11\frac{2}{3}\ min[/tex]
Step-by-step explanation:
Given
[tex]Security\ A = 2\ mins, 20\ secs[/tex]
[tex]Security\ B = 1\ mins, 40\ secs[/tex]
Required
After how many minutes, will they round together
First, convert the given time to minutes
[tex]Security\ A = 2\ mins, 20\ secs[/tex]
[tex]Security\ A = 2\ mins+ 20\ secs[/tex]
[tex]Security\ A = 2\ mins+ \frac{20}{60}\ min[/tex]
[tex]Security\ A = 2\ mins+ \frac{1}{3}\ min[/tex]
[tex]Security\ A = 2\frac{1}{3}\ min[/tex]
[tex]Security\ B = 1\ mins, 40\ secs[/tex]
[tex]Security\ B = 1\ mins+ 40\ secs[/tex]
[tex]Security\ B = 1\ mins+ \frac{40}{60}\ min[/tex]
[tex]Security\ B = 1\frac{2}{3}\ min[/tex]
So, we have:
[tex]Security\ A = 2\frac{1}{3}\ min[/tex]
[tex]Security\ B = 1\frac{2}{3}\ min[/tex]
List out the multiples of the time of both security personnel take round.
[tex]Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...[/tex]
[tex]Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...[/tex]
In the above lists, the common time is:
[tex]Time = 11\frac{2}{3}\ min[/tex]
This implies that they go on round after [tex]11\frac{2}{3}\ min[/tex]
Please Help asap!! I will give brainly to whoever answer correctly! I need to submit this answer by today!
Which statement best describes the expression 3y ÷ 8?
(answer choices-
A- 8 divided by 3 times y
B- 8 times y divided by 3
C- 3 divided by 8 times y
D- 3 times y divided by 8
Answer:
C or D
Step-by-step explanation:
Answer:
I think option D 3 times y divided by 8
Suppose that c is a number for which the equation c÷c = 1 is false. What is c?
Answer:
Hope it help
Mark me as brainliest
Step-by-step explanation:
Which figures can be precisely defined by using only undefined terms? Select three options.
angle
arc
circle
line segment
parallel lines
Answer:
Circle, angle, and line segment.
1.)20 is twice as much as 10 (True or False
2.)10 is twice as much as 20 (True or False)
3.)30 is double 15 (True Or False)
4.) 15 is double 30
(True or False)
The options that are true are (1), (3) and false ones are (2), (4).
What are arithmetic operations?The basis of all mathematical operations are the arithmetic operations. These operations include addition, subtraction, multiplication, and division.
The given options can be examined one by one as follows,
(1) The given number 20 may be expressed as a mathematical operation as follows:
20 = 10 × 2
Which implies it is two times that of 10.
Thus, it is true.
(2) The given number 10 may be expressed as a mathematical operation as follows:
10 = 20 ÷ 2
Which implies it is half of 20.
Thus, it is false.
(3) The given number 30 may be expressed as a mathematical operation as follows:
30 = 15 × 2
Which implies it is two times that of 15.
Thus, it is true.
(4) The given number 15 may be expressed as a mathematical operation as follows:
15 = 30 ÷ 2
Which implies it is half of 30.
Thus, it is false.
Hence, the true and false options are (1), (3) and (2), (4) respectively.
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5. Usa el método de cocientes parciales para hallar 1,032 ÷ 43.
the answer for the question is 24
.
A car is traveling along a test track in the desert at a constant rate of 85 feet per second The test track has a length of 10,000 feet, and the track is marked by foot for observation purposes. After 8 seconds, the car is at foot marker 1000 feet. At what foot marker was the car at time t= 0 seconds?
Answer:
foot marker 320 at t=0
Step-by-step explanation:
8 sec x 85 ft/s =680 ft
1,000ft - 680 ft = 320 ft
At t = 0 seconds the car was at a foot marker of 320 feet.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Given, A car is traveling along a test track in the desert at a constant rate of 85 feet per second.
After 8 seconds, the car is at foot marker 1000.
So, In those 8 seconds, the car has traveled (8×85) = 680 feet.
Therefore, Initially, the car was at (1000 - 680) feet.
= 320 feet.
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When traveling with the current, it takes Kamal 1 hour to travel 12 miles on a boat. It takes the boat 1.5 hours to travel the same 12 miles when traveling against the current. Assuming the boat travels at a constant speed during both trips, what is the speed of the boat and the speed of the current?
Answer:
the rate / speed of the boat is 10 miles per hour.
the rate / speed of the current is 2 miles per hour.
Step-by-step explanation:
r = rate of boat (speed of boat)
t = time
d = distance.
c = rate of current (speed of current)
with the current, the formula becomes (r + c) * t = d
against the current, the formula becomes (r - c) * t = d
going with the current, the boat takes 1 hour to travel 12 miles.
therefore:
(r + c) * t = d becomes (r + c) * 1 = 12
going against the current, the boat takes 1.5 hour to travel the same 12 miles.
therefore:
(r - c) * t = d becomes (r - c) * 1.5 = 12.
your two equations that need to be solved simultancously are:
(r + c) * 1 = 12
(r - c) * 1.5 = 12
divide both sides of the second equation by 1.5 and leave the first equaion as is to get:
r + c = 12
r - c = 8
add the equations together to get:
2 * r = 20
solve for r to get:
r = 20 / 2 = 10
(r + c) * 1 = 12 becomes (10 + c) * 1 = 12
simplify to get 10 + c = 12
solve for c to get c = 12 - 10 = 2
(r - c) * 1 = 8 becomes (10 - c) * 1 = 8
simplify to get 10 - c = 8
solve for c to get c = 10 - 8 = 2
you have:
r = 10
c = 2
that's your solution.
the rate / speed of the boat is 10 miles per hour.
the rate / speed of the current is 2 miles per hour.
HELLLLLLLP i beg youuu
Answer:
1.5
Step-by-step explanation:
4:6 = 1:1.5
Work out the equation of the line which has a gradient of 1/2 and
passes through the point (4, -2).
9514 1404 393
Answer:
y = 1/2x - 4
Step-by-step explanation:
The point-slope form of the equation for a line is a useful starting place when slope and point are given.
y -k = m(x -h) . . . . . . . line with slope m through point (h, k)
y -(-2) = 1/2(x -4) . . . . line with slope 1/2 through point (4, -2)
y = 1/2x - 4 . . . . . . . . eliminate parentheses, subtract 2
A college student completed some courses worth 3 credits and some courses worth 4 credits. The studentearned a total of 59 credits after completing 18 courses.How many courses worth 3 credits did the student complete?
Answer:
The student completed 13 courses worth 3 credits
Step-by-step explanation:
System of Equations
Let's assign the following variables:
x = number of courses worth 3 credits
y = number of courses worth 4 credits
Some student completed 18 courses thus:
x + y = 18 [1]
The student earned a total of 59 credits:
3x + 4y = 59 [2]
From [1]:
y = 18 - x
Substituting in [2]:
3x + 4(18 - x) = 59
Operating:
3x + 72 - 4x = 59
Simplifying:
-x = 59 - 72 = -13
x = 13
The student completed 13 courses worth 3 credits
A. f(x) = 2|2| is differentiable overf
X
B. g(x) = 2 + || is differentiable over
-f
Recall the definition of absolute value:
• If x ≥ 0, then |x| = x
• If x < 0, then |x| = -x
(a) Splitting up f(x) = x |x| into similar cases, you have
• f(x) = x ² if x ≥ 0
• f(x) = -x ² if x < 0
Differentiating f, you get
• f '(x) = 2x if x > 0 (note the strict inequality now)
• f '(x) = -2x if x < 0
To get the derivative at x = 0, notice that f '(x) approaches 0 from either side, so f '(x) = 0 if x = 0.
The derivative exists on its entire domain, so f(x) is differentiable everywhere, i.e. over the interval (-∞, ∞).
(b) Similarly splitting up g(x) = x + |x| gives
• g(x) = 2x if x ≥ 0
• g(x) = 0 if x < 0
Differentiating gives
• g'(x) = 2 if x > 0
• g'(x) = 0 if x < 0
but this time the limits of g'(x) as x approaches 0 from either side do not match (the limit from the left is 0 while the limit from the right is 2), so g(x) is differentiable everywhere except x = 0, i.e. over the interval (-∞, 0) ∪ (0, ∞).
Elena rode her bike 2 miles in 10 minutes. She rode at a constant speed. Complete the table to show the time it took her to travel different distances at this speed. Write your answer as a decimal.
Answer:
0.2
Step-by-step explanation:
2/10 or 1/5
Answer:
0.2
Step-by-step explanation:
You have a cell phone plan that allows you 800 free minutes and 800 free texts. The base plan costs $55.00. Overage charges are 2 cents per extra minute and 2 cents per extra text message. If you use 899 minutes of talking and 905 text messages, what will be the cost of your bill?
What is x? I’ll make you the brainliest
Answer:
48
Step-by-step explanation:
If EG=8, OE=4
x/12=4
x=4(12)
x=48
Simplify the following expression
4[7+2/3-2(3/5)]
Answer: Add 7+ [tex]\frac{2}{3}= \frac{7}{1} + \frac{2}{3} = \frac{7.3}{1.3} + \frac{2}{3} = \frac{21.2}{3} = \frac{23}{3}[/tex] For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(1, 3) = 3. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 1 × 3 = 3. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - seven plus two thirds = twenty-three thirds.
Multiple: 2 * [tex]\frac{3}{5} = \frac{2.3}{1.5} = \frac{6}{5}[/tex] Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(6, 5) = 1. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - two multiplied by three fifths = six fifths.
Subtract = [tex]\frac{23}{3} - \frac{6}{5} = \frac{23.5}{3.5} - \frac{6.3}{5.3} = \frac{115}{15} - \frac{18}{15} =\frac{115 - 18}{15}[/tex]For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of the both denominators - LCM(3, 5) = 15. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 3 × 5 = 15. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - twenty-three thirds minus six fifths = ninety-seven fifteenths.
Multiple: 4 Multiply both numerators and denominators. Result fraction keep to lowest possible denominator GCD(388, 15) = 1. In the next intermediate step the fraction result cannot be further simplified by canceling.
In words - four multiplied by ninety-seven fifteenths = three hundred eighty-eight fifteenths.
Step-by-step explanation:
hope this helps
A bicycle with 24-inch diameter wheels is traveling at 12 mi/h. Find the angular speed of the wheels in rad/min.
Answer:
1055.99 rad/min
Step-by-step explanation:
Given that,
The diameter of a bicycle, d = 24 inches
Radius, r = 12 inches
The bicycle is travelling at 12 mi/h.
We need to find the angular speed of the wheels in rad/min.
We know that,
1 mi/h = 0.0166667 mi/min
It means,
12 mi/h = 0.2 mi/min
Also,
12 inch = 0.000189394 miles
The angular speeds of the wheels is given by :
[tex]v=r\omega\\\\\omega=\dfrac{v}{r}\\\\\omega=\dfrac{0.2}{0.000189394}\\\\\omega=1055.99\ rad/min[/tex]
So, the angular speeds of the wheels is 1055.99 rad/min.
The side of the base of a square pyramid is increasing at a rate of 666 meters per minute and the height of the pyramid is decreasing at a rate of 111 meter per minute. At a certain instant, the base side is 333 meters and the height is 999 meters. What is the rate of change of the volume of the pyramid at that instant (in cubic meters per minute)
Answer:
[tex]105m^3/min[/tex]
Step-by-step explanation:
We are given that
Base side of square pyramid, a=3 m
Height of square pyramid, h=9m
[tex]\frac{da}{dt}=6m/min[/tex]
[tex]\frac{dh}{dt}=-1/min[/tex]
We have to find the rate of change of the volume of the pyramid at that instant.
Volume of square pyramid, V=[tex]\frac{1}{3}a^2h[/tex]
Differentiate w.r.t t
[tex]\frac{dV}{dt}=\frac{1}{3}(2ah\frac{da}{dt}+a^2\frac{dh}{dt})[/tex]
Substitute the values
[tex]\frac{dV}{dt}=\frac{1}{3}(2(3)(9)(6)+(3^2)(-1)[/tex]
[tex]\frac{dV}{dt}=105m^3/min[/tex]
Hence, the rate of change of the volume of the pyramid at that instant=[tex]105m^3/min[/tex]
Use the fact 26% of 78= 20.28 to find 13% of 78
Answer:10.14
Step-by-step explanation:
13x78=1014/100=10.14Write an equation of the parabola with focus (0, 10) and vertex at the origin
Answer:
f(x) = (1/10)x²
Step-by-step explanation:
This is the answer that I think it is but I am not sure if it is right...
Hope this helps!
Show the work for the answer
x=³√27
x = 3
Answer:
x = 3
Step-by-step explanation:
Given that,
[tex]x=\sqrt[3]{27}[/tex]
We need to show work to solve it.
We know that,
27 = 3×3×3
or
27 = (3³)
So,
[tex]x=\sqrt[3]{3\times 3\times 3}\\\\=(3^3)^{\dfrac{1}{3}}\\\\x=3[/tex]
Hence, this is the required solution.
peter has 6/7 of a stack of baseball cards left. If he is planning on splitting what he has left into stacks that are each 3/28 of a pack of cards, how man stacks can he make?
=======================================================
Work Shown:
Let's say there are 28 cards in a full stack.
6/7 = 24/28 after multiplying top and bottom by 4
Since he has 24/28 of a stack left, this means he has 24 cards left.
He wants to arrange the remaining cards into piles so that each pile consists of 3/28 of a full stack. In other words, he wants each pile to have 3 cards.
So this must mean he will get 24/3 = 8 piles
(8 piles)*(3 cards per pile) = 8*3 = 24 cards total
A fraction is a way to describe a part of a whole. The number of stacks that Peter has left into stacks that are each 3/28 of a pack of the left cards is 8.
What is a Fraction?A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.
Given that Peter has 6/7 of a stack of baseball cards left. Also, he makes small stacks from the left cards of size 3/28. Therefore, the number of stacks Peter made,
[tex]\text{Number of stacks Peter made} = \dfrac{\text{Stack of baseball cards left}}{\text{Size of small stack of cards}}\\\\\\\text{Number of stacks Peter made} = \dfrac{\frac{6}{7}}{\frac{3}{28}}\\\\\\\text{Number of stacks Peter made} = \dfrac{6 \times 28}{7 \times 3} = 8[/tex]
Hence, the number of stacks that Peter has left into stacks that are each 3/28 of a pack of the left cards is 8.
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The sides of a square garden are x? yards long. The area inside the garden is 49 square yards. What is the value of x?
Oa. 49 yards
Oc 77 yards
Ob. 7 yards
O d. 2 yards
Answer:
7 yards
Step-by-step explanation:
sqrt(49)=7
The value of the x is 7 yards. The correct option is b.
What is a square?Square is a polygon which has 4 sides. All four sides of the square are equal length and perpendicular to each other, that means the angle between two adjacent side is 90°.
Given shape is a square.
And side of the square is x yards.
The area inside the garden is 49 square yards.
Area is the amount of area occupied by an object's flat (2-D) surface or shape.
So, the area of the square = (side x side)
Substituting the values,
49 = (x)²
x = 7
Therefore, the side is 7 yards.
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ILL GIVE BRAINLIEST AND 50 POINTS PLS help
A cell phone company charges $50 connection fee plus $20 per line. Jake must spend under $140 on his family’s cell phone bill. How many cell phone lines can his family have? Write the linear inequaulity that models this situation then solve the problem
Answer: 2
bc 50+20=70
140 divided by 70 is 2
Step-by-step explanation:
Solve the system of linear equations below, using substitution method.
8x + 9y = 36
3x + 4y = 16
0 (0,4)
хо (57.6.-47.2)
0 (4.4137, 2.9396)
O (5.6842,-0.2632)
5
Answer:
The solution is (0,4).
Step-by-step explanation:
We are given the following system of equations:
[tex]8x + 9y = 36[/tex]
[tex]3x + 4y = 16[/tex]
Solving by substitution.
In the first equation, we have that:
[tex]8x + 9y = 36[/tex]
[tex]8x = 36 - 9y[/tex]
[tex]x = \frac{36-9y}{8}[/tex]
Replacing in the second equation:
[tex]3x + 4y = 16[/tex]
[tex]3\frac{36-9y}{8} + 4y = 16[/tex]
Multiplying everything by 7
[tex]3(36 - 9y) + 32y = 128[/tex]
[tex]108 - 27y + 32y = 128[/tex]
[tex]5y = 20[/tex]
[tex]y = \frac{20}{5}[/tex]
[tex]y = 4[/tex]
Now, with y, we can find x.
[tex]x = \frac{36-9*4}{8} = 0[/tex]
So the solution is (0,4).
I really need help please can you help I’ll give brainlest to first person (please hurry)
Answer: 1/3
Step-by-step explanation:
Half of the 14 brown eggs are cracked so there are 7 cracked eggs. There are 7+14=21 eggs in total so the probability of getting a cracked egg that is brown is 7/21=1/3
How do I decompose the fraction 4 2/5
Answer:
910293012
Step-by-step explanation:
it is nine thousand four billion atoms in one partial.
What is the HCF of 27 and 15
Answer:
3
Step-by-step explanation:
Answer: 3
Step-by-step explanation:
5x3=15 and 3x9=27 so it’s 3.
Need help ASAP Question 1 of 10
If g(x) = 4x2 - 16 were shifted 9 units to the right and 1 down, what would the
new equation be?
Answer:
4(x - 9)^2 - 17
Step-by-step explanation:
A horizontal shift to the right by 9 changes x^2 to (x - 9)^2.
A vertical shift down by 1 changes - 16 to -17.
Therefore, the new equation is:
4(x - 9)^2 - 17
Milly wants to buy this seated Elliptical for 169.99 (regularly 250.00)
What's the discount? What will be the total price afterwards?
Which ordered pair is on the graph of the function? (-6, 4) (-1, 2) (-2, -4) (6, -3)
Answer:
(-6,4) hope that helps you it's that in the y there is two 4