Answer:
c 64 is your answer im pretty sure
Over the years, parking has become an issue during spring at MSU as more people bring cars to campus. The waiting time to find a parking spot at Wells Hall parking lot is normally distributed with an average of 9.60 minutes and a standard deviation of 2.60 minutes during peak hours (10 am - 5 pm).
1) What proportion of waiting times are between 8 and 10.8 minutes? Enter your answer to 4 decimal places.
2) What proportion of waiting times are less than 6.8 minutes? Enter your answer to 4 decimal places.
3) You reach Wells Hall parking lot and your class starts in 12 minutes. What is the chance that you are late to class, that is waiting time is at least 12 minutes?
4) Based on your unpleasant experiences in the past you know that your waiting time is in the top 4%. What is the cutoff for the top 4% of waiting times?
5) What is the waiting time for the 30th percentile?
Answer:
1) 0.4096 = 40.96% of waiting times are between 8 and 10.8 minutes.
2) 0.1401 = 14.01% of waiting times are less than 6.8 minutes.
3) 0.1788 = 17.88% probability that you are late.
4) The cutoff for the top 4% of waiting times is of 14.15 minutes.
5) The waiting time for the 30th percentile is of 8.235 minutes.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Average of 9.60 minutes and a standard deviation of 2.60 minutes during peak hours.
This means that [tex]\mu = 9.6, \sigma = 2.6[/tex]
1) What proportion of waiting times are between 8 and 10.8 minutes?
This is the pvalue of Z when X = 10.8 subtracted by the pvalue of Z when X = 8. So
X = 10.8
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{10.8 - 9.6}{2.6}[/tex]
[tex]Z = 0.46[/tex]
[tex]Z = 0.46[/tex] has a pvalue of 0.6772
X = 8
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{8 - 9.6}{2.6}[/tex]
[tex]Z = -0.62[/tex]
[tex]Z = -0.62[/tex] has a pvalue of 0.2676
0.6772 - 0.2676 = 0.4096
0.4096 = 40.96% of waiting times are between 8 and 10.8 minutes.
2) What proportion of waiting times are less than 6.8 minutes?
This is the pvalue of Z when X = 6.8.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{6.8 - 9.6}{2.6}[/tex]
[tex]Z = -1.08[/tex]
[tex]Z = -1.08[/tex] has a pvalue of 0.1401
0.1401 = 14.01% of waiting times are less than 6.8 minutes.
3) You reach Wells Hall parking lot and your class starts in 12 minutes. What is the chance that you are late to class, that is waiting time is at least 12 minutes?
This is 1 subtracted by the pvalue of Z when X = 12. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{12 - 9.6}{2.6}[/tex]
[tex]Z = 0.92[/tex]
[tex]Z = 0.92[/tex] has a pvalue of 0.8212
1 - 0.8212 = 0.1788
0.1788 = 17.88% probability that you are late.
4) Based on your unpleasant experiences in the past you know that your waiting time is in the top 4%. What is the cutoff for the top 4% of waiting times?
The cutoff for the top 4% of times is the 100 - 4 = 96th percentile, which is X when Z has a pvalue of 0.96. so X when Z = 1.75.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.75 = \frac{X - 9.6}{2.6}[/tex]
[tex]X - 9.6 = 1.75*2.6[/tex]
[tex]X = 14.15[/tex]
The cutoff for the top 4% of waiting times is of 14.15 minutes.
5) What is the waiting time for the 30th percentile?
This is X when Z has a pvalue of 0.3. So X when Z = -0.525.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.525 = \frac{X - 9.6}{2.6}[/tex]
[tex]X - 9.6 = -0.525*2.6[/tex]
[tex]X = 8.235[/tex]
The waiting time for the 30th percentile is of 8.235 minutes.
HELP PLS QUICK!MIGHT GIVE BRAINLIST IF TWO PEOPLE ANSWER!
Answer: A=bh to find the area of parallelograms.
Step-by-step explanation:
What is the measure of z?
Answer:
Please edit the question I can't see it completely
Find legit BD
I need help for my assignment
Answer:
BD = 4
Step-by-step explanation:
∆BAD is congruent to ∆CAD based on the AAS Congruence Theorem.
Therefore:
BD = CD
3x + 1 = 5x - 1 (substitution)
Collect like terms
3x - 5x = -1 - 1
-2x = -2
Divide both sides by -2
x = -2/-2
x = 1
✔️BD = 3x + 1
Plug in the value of x
BD = 3(1) + 1
BD = 3 + 1
BD = 4
two numbered cubes are rolled then a spinner with 4 different colors on it spun twice then two coins are flipped how many total possible outcomes are their(show you working out)
Answer: 12 possible outcomes in total
Step-by-step explanation:
If -5x-y=1 is a true equation, what would be the value of 5(-5x-y)?
Answer:
-25-5x-5y
Step-by-step explanation:
A process manufactures ball bearings with diameters that are normally distributed with mean 25.14 mm and standard deviation 0.08 mm. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. A particular ball bearing has a diameter of 25.2 mm. What percentile is its diameter on
Answer:
The diameter is in the 77th percentile.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
25.14 mm and standard deviation 0.08 mm.
This means that [tex]\mu = 25.14, \sigma = 0.08[/tex]
A particular ball bearing has a diameter of 25.2 mm. What percentile is its diameter on?
This is the pvalue of Z when X = 25.2. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{25.2 - 25.14}{0.08}[/tex]
[tex]Z = 0.75[/tex]
[tex]Z = 0.75[/tex] has a pvalue of 0.77.
The diameter is in the 77th percentile.
consider the absolute value functions c and d
which statement correctly describes these functions?
A.The maximum value of d is 5 less than the minimum value of c
B. The maximum value of d is 3 less than the maximum value of c.
C.The minimum value of d is 5 more than the maximum of c
D. The minimum value of d is 3 more than the maximum of value c.
What is the value of x?
A triangle. One angle is labeled 48 degrees. A second angle is labeled left parenthesis 6 x right parenthesis degrees. The third angle is labeled left parenthesis 9 x minus 3 right parenthesis degrees.
Enter your answer in the box.
x =
Answer:
x = 9
Step-by-step explanation:
6x + 9x - 3 + 48 = 180
15x= 180 -45
x = 135 / 15
x = 9
i hope my answer is correct and helps a little bit.
Answer:
x=9
Step-by-step explanation:
NO LINKS PLEASE and make sure it's correct
Answer: The answer is 20 3/16
Step-by-step explanation:.
Its B.
I need help plz math
Answer:
Q1 = 40
Step-by-step explanation:
Set up numbers from least to greatest
21, 40, 52, 58, 72, 75, 96
First, find the median,
Median is: 58
Now Q1 is all numbers before the median (without counting the median)
21, 40, 52
The median here is 40
Answer:
D/40
Step-by-step explanation:
The answer is D because if you were to put them in the correct order it would be
21, 40, 52, 58, 72, 75, 96
Q1 Q2 Q3
Q1 is quartile 1 so the answer is 40
Hope this helps!
what is the solution to the equation 5x = -4?
Answer:
x = -4/5
Step-by-step explanation:
Divide 5 on both sides to isolate x on one side. You get x = -4/5
Answer:
x=-4/5 hope this helps you out math is always hard
The nominal resistance of a wire is 0.15 Ohm. Random testing of the wire stock yields the following resistance data:
0.148 0.147 0.151 0.146 0.151 0.148 0.147 0.152
0.151 0.148 0.149 0.147 0.146 0.149 0.151 0.147
Does the sign test yield the conclusion, at the 5% significance level, that the median resistance is less than 0.15 Ohm?
Answer:
The median resistance of the wire is not small than 0,15 Ω at 0,05 of level of significance
Step-by-step explanation:
From data we get x ( sample mean ) s ( sample standard deviation) and n size of the sample
0.148 0.147 0.151 0.146 0.151 0.148 0.147 0.152
0.151 0.148 0.149 0.147 0.146 0.149 0.151 0.147
n = 16
x ≈ 0,1487
s = 0,00193
Test Hypothesis
1.-Null Hypothesis H₀ x = μ₀ = 0,15
Alternative Hypothesis Hₐ x < 0,15
We assume data follows normal distribution
as n = 16 we should use a t-student table
As the question is : "Is the median resistance less than 0,15 0hm " we must use one-tail-test ( to the left)
Then:
2.-Significance level α = 5 % α = 0,05
degree of freedom n = 16 df = n - 1 df = 15
From t-table we find t(c) = 1,7531 at the left is t(c) = - 1,7531
3.-t(s) = ( x - 0,15 ) / s / √n
t(s) = 0,1487 - 0,15 / 0,00193/√16
t(s) = - 0,0013 * 4 / 0,00193
t(s) = - 2,69
4.- Comparing t(s) and t(c)
|t(s) | > |t(c)| 2,69 > 1,753
Then t(s) is in the rejection region
5.- We reject H₀ . At 95 % of confidence Interval
Definition of rates
What is the measure of X?
154.3
A. 25.7°
Supplementary Angles: Two angles that
add to equal 180°
B. 180°
C. 64.3°
D. 26.3°
B
оооо
Answer:
A. 25.7°
Step-by-step explanation:
the sum of straight angle is 180°.
so, i subtract 154.3 from 180.
i get 25.7 °
An insurance office buys paper by the ream, 500 sheets, for use in the copier, fax, and printer. Each ream lasts an average of 4 days, with standard deviation 1 day. The distribution is normal, independent of previous reams. a. Find the probability that the next ream out- lasts the present one by more than 2 days. b. How many reams must be purchased if they are to last at least 60 days with probability at least 80%
Answer:
a) the probability that the next ream out- lasts the present one by more than 2 days is 0.0787
b) the number of reams that must be purchased is 19
Step-by-step explanation:
Given the data in the question;
Lets X₁ and X₂ be the two random variables that represents the first and second ream lasts
given that both random variables follow normal distribution with mean 4 and standard deviation 1.
a)
Find the probability that the next ream out- lasts the present one by more than 2 days.
P( X₂ - X₁ > 2 ) = P( [(X₂ - X₁ - E(X₂ - X₁)) / √(V(X₂ - X₁)] > [ (2-E(X₂ - X₁))/√(V(X₂ - X₁) ]
= 1 - P( Z ≤ [2-(μ₂ - μ₁)] / [√( V(X₂) + V(X₁) ) ] )
= 1 - P( Z ≤ [2-(4 - 4)] / [√( 1 + 1 )] )
= 1 - P = ( Z ≤ 2 / √2 )
= 1 - p( Z ≤ 1.4142 )
from excel; p( Z ≤ 1.41 ) = 0.9213
P( X₂ - X₁ > 2 ) = 1 - 0.9213
P( X₂ - X₁ > 2 ) = 0.0787
Therefore, the probability that the next ream out- lasts the present one by more than 2 days is 0.0787
b)
How many reams must be purchased if they are to last at least 60 days with probability at least 80%
total value is 4n
standard deviation is nσ
so
P(nX ≥ 60 ) = 0.80
P( nX-nμ /nσ ≥ 60-nμ/nσ) = 0.80
P( Z ≥ 60-4n/n) = 0.80
1 - P( Z ≥ 60-4n/n) = 0.80
P( Z < z ) = 0.20
now since z = 60-4n/n
from standard normal table
critical value of z corresponding to cumulative area of 0.20 is -0.841
so
z = - 0.841
60-4n/n = -0.841
60 - 4n = -0.841n
60 = -0.841n + 4n
60 = 3.159n
n = 60 / 3.159
n = 18.99 ≈ 19
Therefore, the number of reams that must be purchased is 19
You deposit $300 in an account. The account earns $54 simple interest in 4 years. What is the annual interest rate?
In his free time, Gary spends 11 hours per week on the Internet and 8 hours per week playing video games. If Gary has five hours of free time per day, approximately what percent of his free time is spent on the Internet and playing video games?
Answer:
Around 54% is what I would say.
Step-by-step explanation:
Rewrite the number in Standard form
1.2 x 107
Graph the inequality n > 1.8
Answer:
Open circle going right. <-- graphed
Step-by-step explanation:
1billion is the correct answerStep-by-step explanation:
Timothy earned $300 mowing lawns this summer. He budgets
$25 to spend each week. Write an equation to show the
relationship between the number of weeks, w, and the
amount of money Timothy has, r.
8 ^4 * 8^3
(YOU CANT GET A FRACTION!)
Answer:
8^(7), which is 2097152
Step-by-step explanation:
8^(4) × 8^(3)
= 8^(4+3)
= 8^(7)
= 2097152
Answer:
The answer is 2097152.
Step-by-step explanation:
1) Use the product rule: x^a x^b = x^ a + b.
[tex] {8}^{7} [/tex]
2) Simplify.
[tex]2097152[/tex]
Thus, the answer will be 2097152.
The age of a first-grader on September 1 at Garden Elementary School has the following distribution: f (x )space equals space 1 comma space space 5.8 less or equal than x less or equal than 6.8 We randomly select one first-grader from the class. Find the probability that she is over 6.5 years old. Round to one decimal place.
Answer:
lol
Step-by-step explanation:
lol
3x^2 -12x +11=0
How to complete the square
Answer:
Tiger shows you, step by step, how to solve YOUR Quadratic Equations 3x^2-x-11=0 by Completing the Square, Quadratic formula or, ...
A taxi charges 2.50 plus .50 fee for each mile. If the ride costs 7.50 how many miles did he travel
Answer: 10 miles
Step-by-step explanation:
Mile 1: 3.00
Mile 2: 3.50
Mile 3: 4.00
Mile 4: 4.50
Mile 5: 5.00
Mile 6: 5.50
Mile 7: 6.00
Mile 8: 6.50
Mile 9: 7.00
Mile 10: 7.50
I’ll give points and brainalist for answer / explanation
Answer:
A. 91 ft
Step-by-step explanation:
The path is 2ft wide and the pool's radius is 12.5ft (radius is half diameter, diameter is 25ft). This means that the radius of the circle created by the path is 14.5ft (2+12.5).
Knowing the radius, we can find the circumference.
Circumference = 2πr
Circumference = 2π(14.5) = 91.10618695ft ≈ 91ft
write an equation of the line that passes through the given point and has the given slope (6,4) slope -3/4
Answer:
Its slope is
m = -1/(1/2) = -2
y = -2x + b
Get b from the given point.
-4 = -2(6) + b
b = 8
y = -2x + 8
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given slope (m) = -3/4
and x1 = 6
and y1 = 4
Solve for b (y2) using x2 = 0.
m = -3/4 = (y2-y1)/(x2-x1)
-3/4 = (4-y1)/(6-0)
-3/4 = (4-y1)/6
-(3/4)*6 = 4 - y1
-18/4 = 4 - y1
y1 = b = 16/4 + 18/4 = 34/4 = 8 1/2
therefore the correct answer should be:
Equation of the line:
y = -3/4x + 8 1/2
Kalyan Singhal Corp. makes three products, and it has three machines available as resources as given in the following LP problem:
Maximize contribution = 5X1 + 4X2 + 3X3
Subject to: 1X1 + 7X2 + 4X3 <= 90 (hours on machine 1)
2X1 + 1X2 + 7X3 <= 96 (hours on machine 2)
8X1 + 4X2 + 1X3 <= 90 (hours on machine 3)
X1, X2, X3 >=0
Determine the optimal solution using LP software. the optimal achieved is
X1=
X2=
X3=
Answer:
Step-by-step explanation:
[tex]\text{Maximize p = 5X1 + 4X2 + 3X3 subject to;} \\ \\ 1X1 + 7X2 + 4X3 <= 90[/tex]
[tex]2X1 + 1X2 + 7X3 <= 96[/tex]
[tex]8X1 + 4X2 + 1X3 <= 90[/tex]
[tex]X1 > = 0[/tex]
[tex]X2 >= 0[/tex]
[tex]X3 >=0[/tex]
[tex]\text{USing LP software, The Optimal Solution: Maximum Contribution} = 90.547;}\\ \\ x1 = 7.07692, \\ \\ x2 = 5.62393, \\ \\ x3 = 10.8889[/tex]
132 beads is split into 96 beads and 36 beads. in simplest form , what is the ratio of the split
Answer:
16:6
Step-by-step explanation:
96:36
Highest common factor is 6
divide both sides by 6
16:6
If PQRS is a rhombus, find m
Answer:
m<PQR = 82°
Step-by-step explanation:
In a Rhombus, the diagonals bisect its angles. This means that they divide each the four angles into two equal parts.
Therefore:
(4x - 27)° = (2x + 7)°
Solve for x
4x - 27 = 2x + 7
Collect like terms
4x - 2x = 27 + 7
2x = 34
Divide both sides by 2
2x/2 = 34/2
x = 17
✔️m<PQR = (4x - 27) + (2x + 7)
Plug in the value of x
m<PQR = (4*17 - 27) + (2*17 + 7)
m<PQR = 41 + 41
m<PQR = 82°