Rewrite the integrand substituting u and du for their equivalent expressions. (8x3 + 16)424x2 dx = lu du

The integral can be written as:

∫ (8x^3 + 16)4(4x^2) dx = u^5/10 + 16u^3 + C,

where u = 4x^2 and du/dx = 8x.

We can start by making the substitution u = 4x^2. Then, taking the derivative of both sides with respect to x gives du/dx = 8x. Solve for dx, we get dx = du/(8x).

Substituting these expressions

∫ (8x^3 + 16)4(4x^2) dx

= 4∫ (2x^2 + 4)(4x^2) dx

= 4∫ (8x^4 + 16x^2) dx

= 4(8/5 x^5 + 16/3 x^3) + C

= 128/5 x^5 + 64/3 x^3 + C

Substituting back u = 4x^2, we have:

128/5 x^5 + 64/3 x^3 + C = 128/5 (u^5/256) + 64/3 (u^3/16) + C

= u^5/10 + 16u^3 + C

Therefore, the integral can be written as:

∫ (8x^3 + 16)4(4x^2) dx = u^5/10 + 16u^3 + C, where u = 4x^2 and du/dx = 8x.

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PROCEDIMIENTO:

​

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b. 20,000

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HELPPPPPP
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Let CC represent the total cost, in dollars, of producing pp phones in a given day.

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Determine the fixed cost for rent and equipment.

P C
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2
7
8
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2 cm
2 cm
2 cm
2 cm
2 cm
2 cm
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