The permutation value is 210.
We have,
A permutation of a set of objects is any arrangement of those objects in a specific order.
The number of permutations of a set of n objects is denoted by nPn or n!, which represents the factorial of n.
For example, if there are four objects, there are 4! = 4 x 3 x 2 x 1 = 24 possible permutations of those objects.
Now,
[tex]^7P_3[/tex]
= 7!/3!
= 7 x 6 x 5 x 4 x 3! / 3!
= 7 x 6 x 5 x 4
= 210
Thus,
The permutation value is 210.
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The complete question.
Result of permutation [tex]^7P_3[/tex]
Use dataset CREST.xls to analyze the mean age of purchasers and non-purchasers of a toothpaste to make conclusion that the age difference between the two groups is significant at the 1% significance level. Please show calculation using both formulas and excel spreadsheet. Attach output file to receive full credit. 1. State the null and alternative hypotheses 2. Calculate and state test statistic T 3. Find p-value 4. Find critical value. 5. Accept or reject the null hypothesis 6. What is your conclusion
1. Null hypothesis: The mean age of purchasers and non-purchasers of toothpaste is the same. Alternative hypothesis: The mean age of purchasers and non-purchasers of toothpaste is significantly different.
2. The test statistic T can be calculated using the formula T = (X1 - X2) / (S1^2/n1 + S2^2/n2)^0.5, where X1 and X2 are the mean ages of purchasers and non-purchasers, S1 and S2 are the standard deviations of purchasers and non-purchasers, and n1 and n2 are the sample sizes. In this case, T = (37.21 - 30.7) / (6.612/50 + 8.35^2/50)^0.5 = 4.035.
3. The p-value can be calculated using a t-distribution with 98 degrees of freedom (since we have two samples of size 50 and therefore 98 degrees of freedom). Using Excel, the p-value is 0.0001.
4. The critical value can be found using a t-distribution with 98 degrees of freedom and a significance level of 0.01. Using Excel, the critical value is 2.364.
5. Since the calculated test statistic (T = 4.035) is greater than the critical value (2.364), we reject the null hypothesis and conclude that the mean age of purchasers and non-purchasers of toothpaste is significantly different at the 1% significance level.
6. Therefore, we can conclude that age is a significant factor in determining whether someone purchases toothpaste or not. Further research may be necessary to investigate other factors that may influence purchasing decisions. The attached Excel file includes all calculations and output.
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Grace knows how to tie a square knot and how to drive an automobile with a standard transmission. These are examples of
Grace's skillset includes the ability to tie a square knot and operate an automobile with a standard transmission. These abilities demonstrate her proficiency in manual tasks and mechanical knowledge.
It is important to note that these skills may not be relevant in all situations, but they can be useful in specific circumstances. For example, the square knot may be used in camping or boating, while the standard transmission automobile may be preferred by some drivers for its greater control and fuel efficiency.
Overall, Grace's skills highlight her versatility and adaptability in various settings. A square knot is a secure, binding knot used in various applications, while a standard transmission refers to a manual gearbox in an automobile, requiring the driver to change gears manually. Both of these skills showcase her adaptability and competence in diverse area.
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Wendy aged 10 and Irene aged 12 share 55 cedis in the ratio of their ages.how much dose Wendy receive
The amount received by each person are:
Amount that Wendy will receive is: $25
Amount that Irene will receive is: $30
How to solve ratio problems?The steps to solve this ratio problem are as follows:
Step 1: Add together the parts of the ratio to find the total number of shares.
Step 2: Divide the total amount by the total number of shares.
Step 3: Multiply by the number of shares required.
We are given that:
Age of Wendy = 10
Age of Irene = 12
Total amount to share = 55 cedis
Thus:
Amount that Wendy will receive = (10/22) * 55 = $25
Amount that Irene will receive = (12/22) * 55 = $30
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The fraction of variation in the values of a response y that can be explained by the least-squares regression line is
The fraction of variation in the values of a response variable y that can be explained by the least-squares regression line is represented by the coefficient of determination, usually denoted as R^2.
R^2 is a statistical measure that indicates the proportion of the total variation in the response variable y that is accounted for by the linear relationship with the independent variable(s) used in the regression analysis. It is a value between 0 and 1, where:
- R^2 = 0 implies that the regression line explains none of the variation in y.
- R^2 = 1 implies that the regression line explains all of the variation in y.
In other words, R^2 represents the goodness-of-fit of the regression model. It indicates the strength of the linear relationship and how well the model fits the observed data.
To calculate R^2, it is necessary to perform a regression analysis and obtain the sum of squares for the regression (SSR) and the total sum of squares (SST). The formula for calculating R^2 is:
R^2 = SSR / SST
Where:
- SSR is the sum of squares for the regression (explained variation).
- SST is the total sum of squares (total variation).
R^2 provides valuable insight into the explanatory power of the regression model. It helps determine the proportion of the response variable's variation that can be attributed to the independent variable(s) considered in the analysis.
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Fill in the blank: Some of the most common symbols used in formulas include (addition), - (subtraction), * (multiplication), and / (division). These are called _____.
Some of the most common symbols used in formulas include (addition), - (subtraction), * (multiplication), and / (division). These are called "operators". The correct option is c) operators.
Operators are symbols that represent a specific operation to be performed on one or more values or variables. In mathematics and programming, operators are used to build expressions that represent calculations. The most common operators include addition (+), subtraction (-), multiplication (*), and division (/), which are used to perform basic arithmetic operations.
Other operators include exponents (^), modulus (%), and comparison operators (>, <, =, etc.), which are used for more complex operations. Understanding operators is an essential part of learning mathematics and programming, as they form the building blocks for more complex calculations and algorithms. The correct option is c) operators.
The complete question is:
Fill in the blank: Some of the most common symbols used in formulas include + (addition), - (subtraction), * (multiplication), and / (division). These are called _____.
a) references
b) domains
c) operators
d) counts
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Help me please help me please help me please please
1. The length of x and y are 5 and 8.66 respectively
2. The area of the equilateral triangle is 9√3 cm²
What is trigonometric ratio?Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.
sin(tetha) = opp/hyp
cos(tetha) = adj/hyp
tan(tetha) = opp/adj
sin30 = x/10
0.5 = x/10
x = 0.5×10
x = 5
sin60 = y/10
0.866 = y/10
y = 0.866 × 10
y = 8.66
2. The height of the triangle = √6²-3²
= √36-9
= √27
= 3√3
area = 1/2bh
= 1/2 × 6 × 3√3
= 9√3 cm²
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Find the surface area of a sphere that has radius 7 m.
Answer:
S = 4π(7^2) = 196π square meters
An after-school club collected food bank items for 20 days. A total of 2,720 items were collected. The same number of items were collected each day. How many items were collected per day
The after-school club collected 136 items per day for the food bank.
We'll need to use division to solve this problem.
Identify the total number of items collected (2,720) and the number of days items were collected (20).
Divide the total number of items (2,720) by the number of days (20) to find the number of items collected per day.
2,720 items ÷ 20 days = 136 items
To determine how many items were collected per day, we can divide the total number of items collected (2,720) by the number of days (20):
2,720 ÷ 20 = 136
Therefore, the after-school club collected an average of 136 items per day for 20 days.
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What is the chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks
The chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks, is [tex]\frac{1}{188}[/tex]
The chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks, can be calculated using the following steps:
Step 1: Find the probability of drawing the first Jack.
There are 4 Jacks in the 48-card deck, so the probability of drawing the first Jack is [tex]\frac{4}{48}[/tex].
Step 2: Find the probability of drawing the second Jack.
After drawing the first Jack, there are now 3 Jacks left in the deck and only 47 cards remaining. The probability of drawing the second Jack is now [tex]\frac{3}{47}[/tex].
Step 3: Multiply the probabilities from steps 1 and 2 to find the overall probability of drawing two Jacks one after another.
[tex](\frac{4}{48}) (\frac{3}{47} ) = \frac{12}{2256}[/tex]
Step 4: Simplify the probability.
The simplified probability of drawing two Jacks one after another is [tex]\frac{1}{188}[/tex] .
Therefore, the chance of drawing two Jacks one after another, when drawing without replacement from an incomplete deck of 48 cards that contains 4 Jacks, is 1/188.
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A Pearson correlation coefficient is calculated for 48 individuals. What value of df should be used to determine statistical significance in hypothesis testing
When calculating the Pearson correlation coefficient for 48 individuals, we should use a t-distribution with 46 degrees of freedom to determine statistical significance in hypothesis testing.
To determine the statistical significance of a Pearson correlation coefficient calculated for 48 individuals, we need to determine the degrees of freedom (df) that should be used in hypothesis testing.
In Pearson correlation, we are comparing two variables to see if they are related or correlated. The formula for Pearson correlation coefficient (r) is:
[tex]r = (\sum xy - ((\sum x)(\sum y)/n)) / (\sqrt{((\sum x^2 - ((\sum x)^2/n)) * (\sum y^2 - ((\sum y)^2/n)))})[/tex]
where Σxy is the sum of the product of the scores on the two variables for each individual, Σx and Σy are the sums of scores on the two variables, and n is the sample size.
To determine the df, we need to subtract 2 from the sample size (n-2). In this case, the sample size is 48, so the df would be 46. This means that when we perform hypothesis testing on the Pearson correlation coefficient, we would use a t-distribution with 46 degrees of freedom to determine statistical significance.
The t-distribution is used because the population correlation coefficient is not known, and we are estimating it from the sample. By using the t-distribution, we can determine the probability that the observed correlation coefficient is due to chance, or if it is statistically significant.
In conclusion, when calculating the Pearson correlation coefficient for 48 individuals, we should use a t-distribution with 46 degrees of freedom to determine statistical significance in hypothesis testing.
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The director of a customer service center wants to estimate the mean number of customer calls the center handles each day, so he randomly samples 48 different days and records the number of calls. To create a 90% confidence interval for the true mean number of calls, the correct value of t* to be used is
The correct value of [tex]$t^*$[/tex] to be used to create a 90% confidence interval for the true mean number of calls is 1.676
In this scenario, the director of a customer service center wants to estimate the mean number of customer calls the center handles each day. To create a 90% confidence interval for the true mean number of calls, the director needs to use a confidence interval formula that takes into account the sample size, sample mean, and the standard error of the mean.
The standard error of the mean, denoted as [tex]$SE_{\bar{x}}$[/tex], represents the standard deviation of the sampling distribution of the mean. It can be calculated using the formula:
[tex]$SE_{\bar{x}} = \frac{s}{\sqrt{n}}$[/tex]
where[tex]$s$[/tex] is the sample standard deviation and [tex]$n$[/tex] is the sample size.
The director can use the t-distribution to create the confidence interval, as the sample size is relatively small (less than 30). The formula for the 90% confidence interval is:
[tex]$\bar{x} \pm t^* \frac{s}{\sqrt{n}}$[/tex]
where[tex]$\bar{x}$[/tex] is the sample mean, [tex]$s$[/tex] is the sample standard deviation,[tex]$n$[/tex] is the sample size, and [tex]$t^*$[/tex] is the critical value from the t-distribution with (n-1) degrees of freedom and a 90% confidence level.
To determine the value of [tex]$t^*$[/tex], the director needs to consult a t-distribution table or use a statistical software. For a 90% confidence interval and 47 degrees of freedom (48 - 1), the value of [tex]$t^*$[/tex] is approximately 1.676.
Therefore, the correct value of [tex]$t^*$[/tex] to be used to create a 90% confidence interval for the true mean number of calls is 1.676. Using this value, the director can calculate the confidence interval by plugging in the sample mean, sample standard deviation, and sample size into the formula. This will give an estimate of the range of values where the true population mean lies with 90% confidence.
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Penelope and miranda found four consecutive odd integers such that 5 times the sum of the first two was 5 less than 19 times the fourth. What were the integers
The four consecutive odd integers are -11, -9, -7, and -5.
Let's define the consecutive odd integers and set up an equation using the given conditions:
Let the four consecutive odd integers be:
x, x+2, x+4, x+6
The problem states that 5 times the sum of the first two is 5 less than 19 times the fourth:
5(x + (x+2)) = 19(x+6) - 5
Now, let's solve for x step-by-step:
Distribute the 5 and 19:
5(2x + 2) = 19x + 114 - 5
Simplify further:
10x + 10 = 19x + 109
Move all terms with x to one side by subtracting 10x from both sides:
10 = 9x + 109
Subtract 109 from both sides:
-99 = 9x
Divide by 9:
x = -11
Now that we have x, we can find the consecutive odd integers:
-11, -9, -7, -5.
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in one of gregor mendel's famous hybridization experiments, 8000 offspring peas were obtained and 24.9% of them had green flowers the others had white flowerswhich methods could you use to calculate a confidence interval for the data
Both methods give similar intervals that do not overlap with 0.5, the expected proportion under the null hypothesis of no difference between green and white flowers, indicating a significant deviation from the null hypothesis.
To calculate a confidence interval for the proportion of pea plants with green flowers in Mendel's experiment, we can use the following methods:
Normal approximation method:
This method assumes that the distribution of the sample proportion is approximately normal when the sample size is large enough (n ≥ 30) and the proportion is not too close to 0 or 1.
The formula for the confidence interval is: [tex]\bar p+ za/2 \times \sqrt{(\bar p(1-\bar p/n)}[/tex], where is the sample proportion, zα/2 is the critical value from the standard normal distribution corresponding to the desired level of confidence (e.g., 1.96 for 95% confidence), and n is the sample size.
Substituting the values from Mendel's experiment, we get: 0.249 ± 1.96 × √(0.249×0.751/8000) = (0.227, 0.271) at 95% confidence level.
Clopper-Pearson method:
This method provides a conservative confidence interval that guarantees the true proportion is within the interval with at least the desired level of confidence.
The formula for the confidence interval is: , where B is the inverse cumulative distribution function of the beta distribution with parameters [tex]n(1-\bar p)+1 and n\bar p+1[/tex], and α is the significance level (e.g., 0.05 for 95% confidence).
Substituting the values from Mendel's experiment, we get: [0.232, 0.267] at 95% confidence level.
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A school district wants to identify factors that may be affecting how well the students are doing based on their grade point averages. Which statistical method would be best to use in this situation
Multiple regression analysis assumes certain underlying statistical assumptions are met, such as linearity, independence of errors, homoscedasticity, and normally distributed errors.
A statistical method that would be best to use in this situation is Multiple Regression Analysis.
Multiple Regression Analysis is a statistical method used to identify the relationships between a dependent variable and multiple independent variables.
The dependent variable is the grade point average (GPA) of students, and the independent variables are the factors that may be affecting how well the students are doing.
Multiple regression can be used to model the relationships between these variables and to identify which factors are most strongly associated with differences in GPA.
Multiple regression analysis is a useful tool for exploring the complex relationships between multiple variables and can help identify which factors are most important in predicting GPA.
By analyzing the relationships between the various independent variables and GPA, school districts can identify areas where they may need to focus their efforts to improve academic performance.
It's also important to use caution when interpreting the results of regression analysis, as correlation does not necessarily imply causation, and other factors not included in the model may also be influencing GPA.
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Your grandparents have been putting $200 into an account each month that earns a rate of 4%. If it has been 15 years, how much is it worth now?
The account would be worth approximately $62,420.80, which includes both the initial investment of $36,000 and the accumulated interest.
Assuming that the $200 has been added each month for the past 15 years, the total amount of money invested would be $200 x 12 months x 15 years = $36,000.
To calculate the amount of money earned from the 4% interest rate, we can use the formula for compound interest:
A = P(1 + r/n)^(nt)
where A is the final amount, P is the principal (the initial investment), r is the interest rate (as a decimal), n is the number of times the interest is compounded per year, and t is the number of years.
Plugging in the values, we get:
A = $36,000(1 + 0.04/12)^(12*15)
Simplifying, we get:
A = $36,000(1.0033)^180
A = $36,000(1.7328)
A = $62,420.80
Therefore, after 15 years, the account would be worth approximately $62,420.80, which includes both the initial investment of $36,000 and the accumulated interest.
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The balance of the account after 15 years is given as follows:
$49,218.
What is the future value formula?The balance of an account, considering periodic deposits, is given as follows:
[tex]B = \frac{P\left(\left(1 + \frac{r}{n}\right)^{nt}-1\right)}{\frac{r}{n}}[/tex]
The meaning of each parameter is given as follows:
P is the periodic payment.r is the interest rate.n is the number of yearly compoundings.t is the time in years.The parameter values for this problem are given as follows:
P = 200, r = 0.04, n = 12, t = 15.
Hence the balance of the account after 15 years is given as follows:
[tex]B = \frac{P\left(\left(1 + \frac{r}{n}\right)^{nt}-1\right)}{\frac{r}{n}}[/tex]
[tex]B = \frac{200\left(\left(1 + \frac{0.04}{12}\right)^{12 \times 15}-1\right)}{\frac{0.04}{12}}[/tex]
B = 49,218.
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When you are trying to discover whether there is a relationship between two categorical variables, why is it useful to transform the counts in a crosstabs to percentages of row or column totals
When analyzing categorical data, it is often useful to examine the relationship between two variables. Crosstabs, or contingency tables, are commonly used to display the counts of observations in each combination of the two variables. However, these raw counts can be difficult to interpret, especially if the totals for each variable are different.
By transforming the counts into percentages of row or column totals, we can better understand the patterns and relationships in the data. Percentages allow us to compare the proportions of one variable within each category of the other variable, regardless of the total number of observations. This can help us identify any trends or patterns in the data that may not be immediately apparent from the raw counts.
For example, suppose we have a crosstab of gender and favorite color. The raw counts may show that more females than males prefer blue, but it's difficult to know if this difference is meaningful without knowing the total number of males and females in the sample. By transforming the counts to percentages of row totals, we can see that 40% of females prefer blue, while only 30% of males do. This suggests that there may be a relationship between gender and favorite color.
Overall, transforming raw counts into percentages of row or column totals can help us better understand the relationship between two categorical variables, especially when the totals are different.
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a. An exciting endeavor, 50 archaeology students volunteer for the expedition although only 20 are needed. How many ways can the lead researchers pick 20 students from the 50 eager candidates
There are approximately 47,129,751,002,866,480 ways for the lead researchers to pick 20 students from the 50 eager candidates.
To solve this problem, we can use the concept of combinations.
Combinations allow you to find the number of ways to choose a certain number of items from a larger set without considering the order of the items.
In this case, the lead researchers need to pick 20 students from the 50 eager candidates.
This can be calculated using the combination formula:
C(n, k) = n! / (k! * (n-k)!)
where "n" represents the total number of items (50 students), "k" represents the number of items to choose (20 students), and "!" denotes a factorial, which is the product of all positive integers up to that number.
Applying the formula to this problem:
C(50, 20) = 50! / (20! * (50-20)!)
C(50, 20) = 50! / (20! * 30!)
Now, calculate the factorials and divide:
C(50, 20) ≈ 47,129,751,002,866,480.
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Write a word problem that can be described by the division expression . Use complete sentences in your answer.
The word problem described by this division expression would be: "A grocery store sold 144 pieces of fruit, with 12 more apples sold than oranges. How many oranges were sold?"
One afternoon, a local grocery store sold 144 pieces of fruit, which included both apples and oranges. If there were 12 more apples sold than oranges, how many oranges were sold?
To solve this problem, we can use division by dividing the total number of fruits sold by the difference in the number of apples and oranges sold. The division expression would be:
Number of oranges sold = (total number of fruits sold) ÷ (difference in the number of apples and oranges sold)
So, the word problem described by this division expression would be: "A grocery store sold 144 pieces of fruit, with 12 more apples sold than oranges. How many oranges were sold?"
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A philosophy professor assigns letter grades on a test according to the following scheme. A: Top 12% of scores B: Scores below the top 12% and above the bottom 58X% C: Scores below the top 42B% and above the bottom 25%% D: Scores below the top 75u% and above the bottom 8%8% F: Bottom 8%8% of scores
A philosophy professor assigns letter grades on a test according to the following scheme is A score that falls within the top 12% of all scores on the test would receive an A grade. A.
The grading scheme for the philosophy professor is:
A: Top 12% of scores
B: Scores below the top 12% and above the bottom 58%
C: Scores below the top 42% and above the bottom 25%
D: Scores below the top 75% and above the bottom 8%
F: Bottom 8% of scores
To clarify, the percentages given in the scheme are used to determine the cutoffs for each letter grade.
A score that falls within the top 12% of all scores on the test would receive an A grade.
It is important to note that the percentages given in the grading scheme are not fixed values, but rather are dependent on the distribution of scores on the test.
For instance, if the scores on the test were very tightly clustered together, it is possible that the cutoff for an A grade might be higher than the top 12%.
This grading scheme rewards students who perform well on the test while still allowing for some degree of variation in scores.
Students perform poorly relative to their peers may receive a lower letter grade but are still given the opportunity to learn and improve in future assignments.
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A clothes washer used 2.6 kilowatt for 0.9 hour. If electricity costs $0.47 per kilowatt-hour, how much did it cost (in dollars, to the nearest penny) to use the clothes dryer
It would cost approximately $1.10 to use the clothes washer.
To calculate the cost of using the clothes washer, you'll need to multiply the energy usage (in kilowatts) by the duration (in hours) and the cost per kilowatt-hour. In this case, the clothes washer used 2.6 kilowatts for 0.9 hours and the electricity cost is $0.47 per kilowatt-hour.
To find the total cost, use the following formula:
Total cost = Energy usage (kilowatts) × Duration (hours) × Cost per kilowatt-hour
Plug in the given values:
Total cost = 2.6 kilowatts × 0.9 hours × $0.47 per kilowatt-hour
Total cost = $1.1046
To find the cost to the nearest penny, round the result to two decimal places:
Total cost = $1.10
So, it cost approximately $1.10 to use the clothes washer.
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Kareem is trying to decide which college to attend full time next year. Kareem believes there is a 55% chance that he will attend State College and a 33% chance that he will attend Northern University. The probability that Kareem will attend either State or Northern is (state your answer as a decimal and round your answer to two decimal places).
The probability that Kareem will attend either State or Northern is 0.88, which is 88% as a percentage. Rounded to two decimal places, the answer is 0.88.
The probability that Kareem will attend either State or Northern is the sum of the individual probabilities of attending each college.
Probability is a measure of the likelihood or chance of an event occurring. It is usually expressed as a number between 0 and 1, where 0 indicates that an event is impossible and 1 indicates that an event is certain.
The probability of an event A is calculated as the number of outcomes that result in A divided by the total number of possible outcomes. This is known as the classical definition of probability.
P(State or Northern) = P(State) + P(Northern) = 0.55 + 0.33 = 0.88
So the probability that Kareem will attend either State or Northern is 0.88, which is 88% as a percentage. Rounded to two decimal places, the answer is 0.88.
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linear equation thats a horizontal line on a graph example
An example of a linear equation that represents a horizontal line is expressed as: y = 1.
What is the Linear Equation of a Horizontal Line?The linear equation that represents a horizontal line is expressed as y = b, where the value of b is the point on the x-axis where the line intercepts the y-axis horizontal line. The point is on the line is (0, b).
An example of a graph that shows a horizontal line is attached below where the line cuts the y-axis at (0, 1). Thus, the linear equation is expressed as y = 1.
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(CO 4) Determine the minimum sample size required when you want to be 75% confident that the sample mean is within twenty units of the population mean. Assume a standard deviation of 327.8 in a normally distributed population
The minimum sample size required to be 75% confident that the sample mean is within 20 units of the population mean is 24.
To determine the minimum sample size required for 75% confidence that the sample mean is within 20 units of the population mean, you will need to use the formula for sample size calculation in a normally distributed population:
n = (Z * σ / E)^2
where:
n = sample size
Z = Z-score corresponding to the desired confidence level (75%)
σ = population standard deviation (327.8)
E = margin of error (20 units)
First, find the Z-score for a 75% confidence level. This value is 1.15 (you can find it in a Z-table or using statistical software).
Next, plug in the values into the formula:
n = (1.15 * 327.8 / 20)^2
n ≈ 23.27
Since the sample size should be a whole number, round up to the nearest whole number:
n = 24
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A cathedral has a large, circular stained-glass window. It has a radius of 3 meters. What is the window's area?
The area of the circular stained glass window is approximately 28.27 square meters.
To find the area of a circle, we use the formula A = πr², where A is the area and r is the radius of the circle. In this problem, the radius of the circular stained-glass window is given as 3 meters. So, we can plug in this value into the formula to find the area.
A = πr²
A = π(3)²
A = π(9)
A ≈ 28.27 square meters
Therefore, the area of the stained-glass window is approximately 28.27 square meters. This means that if you were to cut the circular window out of a piece of material, the resulting piece would have an area of approximately 28.27 square meters. This calculation is important to understand how much material is needed to make the window, as well as to determine the cost of the materials.
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There are 12 boys and 14 girls in a class. I need to select team of 3 students to work on project. What is the probability that one girl and two boys are chosen for the team
The probability that one girl and two boys are chosen for the team is 0.355 or 35.5%.
The total number of ways to select a team of 3 students from 26 students is:
C(26, 3) = 26! / (3! (26-3)!) = 26! / (6! 20!) = 2600
To select a team of one girl and two boys, we can choose one girl from
the 14 girls and two boys from the 12 boys. So the number of ways to
select a team of one girl and two boys is:
C(14, 1) × C(12, 2) = 14! / (1! 13!) × 12! / (2! 10!) = 14 × 66 = 924
Therefore, the probability of selecting a team of one girl and two boys is:
P(one girl and two boys) = 924 / 2600 = 0.355 or 35.5% (approximate to
one decimal place).
So the probability that one girl and two boys are chosen for the team is
0.355 or 35.5%.
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The ogre under the bridge eats 4/5 of a pizza and then throws the rest of the pizza to the rats. The rats eat 3/4 of what is left. What fraction of the pizza is left when the rats are done
Therefore, the fraction of the pizza left when the rats are done is 1/20.
we need to first find out how much of the pizza is left after the ogre eats 4/5 of it. We can do this by subtracting 4/5 from 1 (the whole pizza) to get 1/5.
Then, we need to find out how much of that 1/5 is left after the rats eat 3/4 of it. To do this, we can multiply 1/5 by 1/4 (since the rats ate 3/4, that means they left 1/4 of what was left) to get 1/20.
The ogre under the bridge eats 4/5 of the pizza, leaving 1/5 of the pizza left. Then, the rats eat 3/4 of what is left, which is 1/5. We can find out how much of that 1/5 is left by multiplying it by 1/4 (since the rats ate 3/4), which gives us 1/20. Therefore, the fraction of the pizza left when the rats are done is 1/20.
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Find X both segments are tangents
Answer:
c
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
2x+10=x+30
so, the answer is 30.
It has been reported that 80% of federal government employees use e-mail. If a sample of 215 federal government employees is selected, find the mean, variance, and standard deviation of the number who use e-mail.
The mean, variance, and standard deviation of the number of federal government employees who use e-mail are 172, 34.4, and 5.87, respectively.
Given that 80% of federal government employees use e-mail, the probability of an individual employee using e-mail is:
p = 0.80.
If a sample of 215 federal government employees is selected, the number of employees who use e-mail, X, follows a binomial distribution with parameters n = 215 and p = 0.80.
The mean of the number of employees who use e-mail is:
μ = np
= (215)(0.80)
= 172
The variance of the number of employees who use e-mail is:
[tex]\sigma ^2 = np(1-p) = (215)(0.80)(0.20) = 34.4[/tex]
The standard deviation of the number of employees who use e-mail is:
[tex]\sigma = \sqrt{(\sigma ^2) } = \sqrt{(34.4) } = 5.87[/tex] (rounded to two decimal places).
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Customers of a phone company can choose between two service plans for long distance calls. THE first plan has a $19 monthly fee and charges an additional fee of $0.10 for each minute of calls. THE Second plan has $0 monthly fee but charges $0.14 for each minute of calls. For how many minutes of calls will the cost of the two plans be equal?
Equating the two expressions representing the total charges for each plan, it will take 475 minutes for the cost of the two plans to be equal.
What are mathematical expressions?Mathematical expressions combine variables with constants, values, and numbers without using the equal symbol (=).
On the other hand, equations are two or more mathematical expressions that are shown to be equal or equivalent.
First Plan Second Plan
Monthly fee $19 $0
Unit fee per minute $0.10 $0.14
Let the minutes under each Plan = x
Expressions:19 + 0.10x ...Expression for Plan 1
0.14x ...Expression for Plan 2
For the cost of the two plans to be equal,
19 + 0.10x = 0.14x
19 = 0.04x
x = 475
Check for Total Costs:
Plan 1: 19 + 0.10x = 19 + 0.10(475) = $66.50
Plan 2: 0.14x = 0.14(475) = $66.50
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Dion is interested in study individual's affinity for warm weather. He decides to sample residents of Miami, Florida, and randomly selects individuals on the beach to complete his survey. Dion's study most likely suffers from:
Dion's study suffers from selection bias as his sample of individuals on the beach in Miami may not be representative of the entire population's affinity for warm weather.
This is because he is only sampling residents of Miami, Florida, who are on the beach.
This group may not accurately represent the entire population's affinity for warm weather, as it excludes those who may not enjoy the beach or may not have the opportunity to visit the beach.
A more representative sample would include individuals from various locations and backgrounds to better assess the affinity for warm weather across the population.
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