The study conducted in the scenario above is an experimental study because the subjects were given treatment.
Observational study involves monitoring the relationship between variables through observation without giving any treatment during the course of the study.
Experimental study on the other hand involves the introduction of a treatment or intervention in other to study the cause and effect or relationship between the variables.
In the scenario above, the research intends to demonstrate the effectiveness of a treatment(magnets) for back pain. The presence of a treatment in this research study makes it an experimental study.
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Write each rate as a fraction in lowest terms
15 feet in 20 seconds
feet/sec
Answer:
3/4 ft / second
Step-by-step explanation:
15 ft / 20 seconds
Divide the top and bottom by 5
3/4 ft / second
Answer:
[tex] \frac{3}{4} [/tex]ft/sec
Step-by-step explanation:
[tex] \frac{feet}{sec} = \frac{15}{20} [/tex]
[tex] \frac{15}{20} \frac{ \div 5}{ \div 5} = \frac{3}{4} [/tex]
which equation is the inverse of the y=7×^2-10?
Answer:
option B
Step-by-step explanation:
Given :
[tex]y = 7x^2 - 10[/tex]
Replace x and y :
[tex]x = 7y^2 - 10 \\[/tex]
Now solve for y :
[tex]x = 7y^2 - 10 \\\\x + 10 = 7y^2 - 1 0+ 10[/tex] [tex][ \ adding \ 10 \ on \ both \ sides \ ][/tex]
[tex]x + 10 = 7y^2\\\\\frac{x + 10 }{7 } = \frac{7y^2}{7}[/tex] [tex][ \ dividing\ by \ 7 \ on \ both \ sides \ ][/tex]
[tex]\frac{x+ 10}{7} = y^2\\\\\pm \ \sqrt{\frac{x+ 10}{7}} = y[/tex]
I think the choose (2)
[tex]y = - + \sqrt{ \frac{x + 10}{7} } [/tex]
Find the slope and y-intercept of the line.
y=7/4x-10
Answer
-10;7/4
Answer:
The slope is 7/4 and the y intercept is -10
Step-by-step explanation:
y=7/4x-10
This equation is written is slope intercept form
y = mx+b where m is the slope and b is the y intercept
The slope is 7/4 and the y intercept is -10
Which of the following is next in the series
Answer:
a
Step-by-step explanation:
blue red blue red like this
A) Which inequality is shown on this graph
B) which graph shows the inequality
Image attached
A stamp collection is purchased for $1,000. Twenty years later, the owner is told that the collection is worth quite a bit of money! If the rate of return on the stamp collection is 4% per year, what is the current value of the stamp collection? In your final answer, include all of your calculations.
Answer:
The current value of the stamp collection is of $2,191.
Step-by-step explanation:
Compound interest:
The compound interest formula is given by:
[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]
Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.
A stamp collection is purchased for $1,000.
This means that [tex]P = 1000[/tex]
The rate of return on the stamp collection is 4% per year
This means that [tex]n = 1, r = 0.04[/tex]
So
[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]
[tex]A(t) = 1000(1 + 0.04)^{t}[/tex]
[tex]A(t) = 1000(1.04)^{t}[/tex]
What is the current value of the stamp collection?
This is A(20). So
[tex]A(20) = 1000(1.04)^{20} = 2191[/tex]
The current value of the stamp collection is of $2,191.
Answer:
Step-by-step explanation:
y = 1000(1+0.04)^20
y = 1000(1.04)^20
Rounded to the nearest hundredth
y = 1000(2.19)
y = $2190
its the number 7 can u guys help me
Answer:
54
Step-by-step explanation:
Angle 2 and Angle 3 are vertical angles
Vertical angles are congruent ( equal to each other )
So if angle 2 = 54 then angle 3 also equals 54
Answer:
∠3 = 54°
Step-by-step explanation:
54° and ∠3 are vertical angles, which means they are equal .
54° = ∠3
step by step..............
Answer:
............Ans..............
Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals:________
a. 0.09
b. 9
c. 6
d. 3
Answer:
c. 0.6
Step-by-step explanation:
A student cannot receive an A or a B simultaneously, so [tex]P(A \cap B) = 0[/tex].
Grade of A equals .30 and the probability of receiving a grade of B equals .30.
This means that [tex]P(A) = P(B) = 0.3[/tex]
The probability that a randomly selected student from this class will receive either an A or a B equals:
This is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.3 + 0.3 - 0 = 0.6[/tex]
So the probability is 0.6, and the correct answer is given by option c.
Find the rate, or percent, for each of the following items. Round your answers to the nearest 0.1%.
Base 72; percentage 12
Percentage 28; base 224
Base 20; percentage 40
Base 44; percentage 99
Percentage 126; base 8400
Answer:
(last part)
25%
27.8%
290%
300%
67%
Step-by-step explanation:
13 52
— = —
6 X
Solve for x please answer quickly
Answer:
1/24
Step-by-step explanation:
13/6x = 52
1/6x = 52/13
1/6x = 4
1 = 4(6x)
1 = 24x
24x = 1
x = 1/24
what is the range and domain of (-3,-22) (-2,-8) (-1,2) (0,8)) (1,10) (2,8) (3,2)
Answer:
Step-by-step explanation:
domain is x component so
domain = {-3 , -2 , -1 , 0 , 1 , 2 , 3 }
range is y component so
range = { -22 , -8 , 2 , 8 , 10 , 2 }
note : repeated element can be written only one time. For eg here in range 8 is 2 times but we can write only one time because it is the rule for lisying range and domain.
Carson is going to see a movie and is taking his 2 kids. Each movie ticket costs
$14 and there are an assortment of snacks available to purchase for $3.50
each. How much total money would Carson have to pay for his family if he
were to buy 2 snacks for everybody to share? How much would Carson have
to pay if he bought x Snacks for everybody to share?
Total cost with 2 snacks:
Total cost with x sn
acks:
49 dollars
Step-by-step explanation:
14 times 3 is 42 and 3.50 times 2 is 7, so 42 plus 7 is 49.
Total cost with 2 snacks = $35
Total cost with x snacks = 28+3.50x
Given :
Carson is going to see a movie and is taking his 2 kids. Movie ticket costs $14 and snacks cost $3.50.
Explanation :
Carson buys 2 snacks . we need to find the total cost that Carson have to pay where he buy 2 snacks.
Total cost = cost of ticket (2 kids) + cost of 2 snacks
[tex]Total \; cost = 14(2) + 2(3.50)=35[/tex]
Total cost with 2 snacks = $35
Total cost with x snacks = cost of ticket (2 kids) + cost of x snacks
[tex]Total \; cost = 14(2) + 3.50(x)\\Total \; cost = 28+3.50x[/tex]
Total cost with x snacks = 28+3.50x
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Find the selling price of a $32 item after a 50% markup.
The selling price is $
Answer:
The new price is 48
Step-by-step explanation:
First find the markup
50% of 32
.5 * 32 = 16
Add the markup to the original price
16+32 = 48
The new price is 48
Answer:
$48
Step-by-step explanation:
32 * 0.50 = 16
32 + 16 = 48
Hope this is helpful
Raj is travelling to another country.
He flies for 5 hours at an average speed of 950 km/h on one plane.
He then flies for 6 hours 30 minutes at an average speed of 830 km/h on a second plane.
What is the total distance, in km, he travelled by plane?
Answer:
10145
Step-by-step explanation:
5 times 950 equals 4750
and 6.5 times 830 equals 5395
add first and second value
4750 + 5395 equals 10145
there is no arguing
Answer:
10145 km
Step-by-step explanation:
Time x speed = Distance
5 x 950 = 4750
6.5 x 830 = 5395
add together = 10145
Descent, Inc., produces a variety of climbing and mountaineering equipment. One of its products is a traditional three-strand climbing rope. An important characteristic of any climbing rope is its tensile strength. Descent produces the three-strand rope on two separate production lines: one in Bozeman and the other in Challis. The Bozeman line has recently installed new production equipment. Descent regularly tests the tensile strength of its ropes by randomly selecting them to various tests. The most recent random sample of ropes, taken after the new equipment was installed at the Bozeman plant, revealed the following:
Bozeman; x1= 7,200 lbs
S1=425 n1=25,
Challis;x2=7,087
lbs, S2=415, n2=20
Required:
Conduct the appropriate hypothesis test at the 0.10 level of significance.
Solution :
Assuming [tex]$\sigma_1^2=\sigma_2^2$[/tex]
We have to test
[tex]$H_0:\mu_1=\mu_2$[/tex]
Against [tex]H_a: \mu_1 \neq \mu_2[/tex]
Level of significance, [tex]$\alpha = 0.05$[/tex]
[tex]$s_p=\sqrt{\frac{(n_1-1)s_1^2+ (n_2-1)s_2^2}{n_1+n_2-2}}$[/tex]
[tex]$s_p=\sqrt{\frac{(25-1)(425)^2+ (20-1)(415)^2}{25+20-2}}$[/tex]
= 420.6107
Under [tex]H_0[/tex], the t-statistics is as follows:
[tex]$t=\frac{(\overline{x_1} - \overline{x_2})}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}} \sim $[/tex] [tex]$\text{t with }(n_1+n_2-2) \ DF$[/tex]
[tex]$t=\frac{(7200-7087)}{(420.6107)\sqrt{\frac{1}{25}+\frac{1}{20}}}$[/tex]
= 0.90
DF = (25 + 20 - 2)
= 43
P-value of the test = 0.375
Since the p value is more than 0.05, we fail to reject our null hypothesis.
There is no difference between then mean tensile strength of the ropes that is produced in the Bozeman and Challis.
What is the best estimate of the perimeter of the figure on the grid if each square has side lengths of 1 mm?
Answer:
the ans of this question is 30cm².
Triangle X Y Z is shown. Angle X Y Z is a right angle and angles Y Z X and Z X Y are 45 degrees. The length of side Y X is 9 centimeters.
The length of segment XY is 9 cm. Which statements regarding triangle XYZ are correct? Select two options.
YZ = 9 cm
XZ = 9 cm
XZ = 9 StartRoot 2 EndRoot cm
XZ = 2(XY)
YZ is the longest segment in △XYZ.
The side YZ=9 cm of the right angle
We have given that,
Triangle X Y Z is shown. Angle X Y Z is a right angle and angles Y Z X and Z X Y are 45 degrees. The length of side Y X is 9 centimeters.
The length of segment XY is 9 cm.
We have to determine the statements regarding triangle XYZ are correct.
What is the right angle triangle?A right triangle or right-angled triangle, or more formally an orthogonal triangle, formerly called a rectangle triangle, is a triangle in which one angle is a right angle or two sides are perpendicular.
The right angle with angles 45-45-90 has two side same.
Therefore the side YZ=9 cm bc of the right angle
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To complete a task in 30 days a company needs
4 people each working for 7 hours per day.
The company decides to have
5 people each working for 6 hours per day.
Assuming that each person works at the same rate,
how many days will the task take to complete?
Answer:
28 days
Step-by-step explanation:
4 x 7 x 30= 840 total working hours
5 x 6 x n = 840
= n = 840 ÷ 30
= n = 28 days
The task will take approximately 1 day to complete with 5 people working for 6 hours per day.
Determining the time to complete the taskTotal work done in the first scenario = 4 × 7 × 30
= 840 work hours
Total work done in the second scenario = (5 × 6 × D)
= 4 × 7 × 30
Solving for D:
30D = (4 × 7 × 30) / (5 × 6)
D = (4 × 7) / (5 × 6)
D = 28 / 30
D ≈ 0.9333
Rounding up to the nearest whole day, D = 1
Therefore, the task will take approximately 1 day to complete with 5 people working for 6 hours per day.
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Solve each equation. Please write a fraction and not a decimal for numbers 1 and 4. If the answer is a fraction, write a fraction using the slash under the question mark key on your keyboard.
1. 2=5
2. +1.8=14.7
3. 6=12
4. 314=12+
5. 2.5=10
Answer:
[tex]1. \: \: \: 2x = 5 \\ x = \frac{5}{2} \\ 2. \: \: \: \: \: \: y + 1.8 = 14.7 \\ y = 14.7 - 1.8 \\ y = 12.9 \\ 3. \: \: \: \: \: 6 = \frac{1}{2} z \\ z = 6 \times 2 \\ z = 12 \\ 4. \: \: \: \: \: 3\frac{1}{4} = \frac{1}{2} + w \\ w = \frac{1}{2} - 3 \frac{1}{4} \\ w = \frac{12 + 2}{4} \\ w = \frac{14}{4} = \frac{7}{2} \\ please \: mark \: brainliest[/tex]
Triangles L M N and P O N connect at point N. Angles L M N and N O P are congruent.
Why is the information in the diagram enough to determine that △LMN ~ △PON using a rotation about point N and a dilation?
because both triangles appear to be equilateral
because∠MNL and ∠ONP are congruent angles
because one pair of congruent corresponding angles is sufficient to determine similar triangles
because both triangles appear to be isosceles, ∠MLN ≅ ∠LMN, and ∠NOP ≅ ∠OPN
Answer:
because one pair of congruent corresponding angles is sufficient to determine similar triangles.
Answer:
C
Step-by-step explanation:
If 8 Superscript y Baseline = 16 Superscript y + 2, what is the value of y?
Answer:
10. Where was the medical mission held? A. At Barangay Tatalon Marikina B. At Barangay Almanza Las Piñas City C. At Barangay Pamplona Las Piñas City D. At Barangay CAA BF INT'L Las Piñas City
The weights of a certain dog breed are approximately normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds. Use your graphing calculator to answer the following questions. Write your answers in percent form.
Required:
a. Find the percentage of dogs of this breed that weigh less than 53 pounds.
b. Find the percentage of dogs of this breed that weigh less than 49 pounds.
c. Find the percentage of dogs of this breed that weigh more than 49 pounds.
Answer:
a. 74.86%
b. 50%
c. 50%
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Normally distributed with a mean of 49 pounds, and a standard deviation of 6 pounds.
This means that [tex]\mu = 49, \sigma = 6[/tex]
a. Find the percentage of dogs of this breed that weigh less than 53 pounds.
The proportion is the p-value of Z when X = 53. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{53 - 49}{6}[/tex]
[tex]Z = 0.67[/tex]
[tex]Z = 0.67[/tex] has a p-value of 0.7486.
0.7486*100% = 74.86%, which is percentage of dogs of this breed that weigh less than 53 pounds.
b. Find the percentage of dogs of this breed that weigh less than 49 pounds.
p-value of Z when X = 49, so:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{49 - 49}{6}[/tex]
[tex]Z = 0[/tex]
[tex]Z = 0[/tex] has a p-value of 0.5
0.5 = 50% of dogs of this breed that weigh less than 49 pounds.
c. Find the percentage of dogs of this breed that weigh more than 49 pounds.
1 subtracted by the p-value of Z when X = 49, so:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{49 - 49}{6}[/tex]
[tex]Z = 0[/tex]
[tex]Z = 0[/tex] has a p-value of 0.5.
1 - 0.5 = 0.5 = 50% of dogs of this breed that weigh more than 49 pounds.
Help! 3-4 quick please!!
Seven-eighths of the 360 adults attending a school bazaar were relatives of the students. How many attendees were not relatives?
Answer:
45
Step-by-step explanation:
If 7/8 are relatives, 1/8 are not relatives
360 / 8 = 45
5. Add together 1 metres + 76cm + 8cm giving your answer in metres. (a) 1.584m (b) 1.89m (c) 2.34m (d) 3.06m (e) 9.9m
what's the answer in metres
Answer:
1.84metres
Step-by-step explanation:
convert 76cm to metres
76/100=0.76m
convert 8cm to metres
8/100=0.08m
therefore we have,
1+0.76+0.08=1.84metres
3.) If y varies directly as x and y = 24 when x = 6, find the variation constant and the equation of variation.
3.) If y varies directly as x and y = 24 when x = 6, find the variation constant and the equation of variation.
Solution:-A. Express the statement “y varies directly as x”, as y = kx .
B. Solve for k by substituting the given values in the equation.
[tex]\sf\rightarrow{y = kx}[/tex]
[tex]\sf\rightarrow{24 = 6k}[/tex]
[tex]\sf\rightarrow{K = \frac{24}{6} }[/tex]
[tex]\sf\rightarrow{K={\color{magenta}{4}}}[/tex]
Answer:-Therefore, the constant of variation is 4.C. Form the equation of the variation by substituting 4 in the statement y = kx. Thus , y = 4 x.
[tex]{\large{—————————————————————}}[/tex]
#CarryOnMath⸙
What is the biggest possible answer you can get by putting
one pair of brackets into the calculation below? Show your working.
9 - 4 + 5 x 3
Answer:
9-4+(5x3)
Step-by-step explanation:
9-4+15
24-4
20
5(x + 7) = 15
what is the value of x
Step-by-step explanation:
5(x + 7) = 15
x+7=3
x=-4!!!!!!
Answer:
x = -4
Step-by-step explanation:
Solve for x
5 ( x + 7 ) = 15Divide each side by 5
5( x + 7 ) ÷ 5 = 15 ÷ 5x + 7 = 3subtract 7 from both side
x + 7- 7 = 3 - 7x = -4Zoe draws ABC on the coordinate plane.
ТУ
B
5
4
3
2.
1
А
ol
1
12
13
4
5
What is the approximate perimeter of AABC to the nearest hundredth?
O A 8.47 units
o
B
12 units
C 12.94 units
O D. 15.31 units
Answer:
12.94 units
Step-by-step explanation:
Perimeter of ∆ABC = AB + BC + AC
✔️Distance between A(1, 1) and B(3, 5):
[tex] AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Where,
[tex] A(1, 1) = (x_1, y_1) [/tex]
[tex] B(3, 5) = (x_2, y_2) [/tex]
[tex] AB = \sqrt{(3 - 1)^2 + (5 - 1)^2} [/tex]
[tex] AB = \sqrt{(2)^2 + (4)^2} [/tex]
[tex] AB = \sqrt{4 + 16} [/tex]
[tex] AB = \sqrt{20} [/tex]
AB = 4.47 units
✔️Distance between B(3, 5) and C(5, 1)
[tex] BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
Where,
[tex] B(3, 5) = (x_1, y_1) [/tex]
[tex] C(5, 1) = (x_2, y_2) [/tex]
[tex] BC = \sqrt{(5 - 3)^2 + (1 - 5)^2} [/tex]
[tex] BC = \sqrt{(2)^2 + (-4)^2} [/tex]
[tex] BC = \sqrt{4 + 16} [/tex]
[tex] BC = \sqrt{20} [/tex]
BC = 4.47 units
✔️Distance between A(1, 1) and C(5, 1):
AC = |1 - 5| = 4 units
✅Perimeter of ∆ABC = 4.47 + 4.47 + 4 = 12.94 units