Represent a vector of 100 N in North-East direction

Explanation:

It is important to reach a decision only after noting the quality of responses received about the following pertinent questions;

1. What training program(s) have they gone through?

2. Do they have any licences?

3. Have they received any certifications from a recognized body?

4. Do they have any ongoing or past scientific research work?

5. Awards they've received, if any?

As this is a key decision of someone's life, making the decision on the basis of the provider's experience with similar cases and quality of service is the most important.

We should ask the following questions to the provider,

1.  Does the practitioner have licenses for such practice?

2. Where did the practitioner receive their educational qualifications from and do they still learn to be up to date with the advanced treatments available in the market?

3. Was the practitioner awarded for any similar cases or handled similar cases?

4. For how long they have been practicing?

5. Does the practitioner have a membership of any organizations or professional societies?

6. Can the treatment be covered by the insurance?

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Answer:

Advertising, events and experiences, and personal selling all become more important in the maturity stage.

Explanation:

In the growth stage, demand has its own momentum through word of mouth and interactive marketing. hope this helps you :)

A.30cm

B.282.7cm/s

C.26655cm/s²

Explanation:

A. Maximum displacement= Amplitude= 0.3m

B.mum velocity=

2πAf= 2π x 1.5x30 =282.7cm/s

C. Maximum acceleration

= ( angular velocity)² A= (2πf)² A

=( 2 x 3.142 x 1.5)² x 30

2665.5cm/s²

Answer:

3.0 m/s²

Explanation:

Given:

v₀ = 8.0 m/s

v = 14 m/s

t = 2.0 s

Find: a

v = at + v₀

14 m/s = a (2.0 s) + 8.0 m/s

a = 3.0 m/s²

Given that,

Mass of trackler, m₁ = 100 kg

Speed of trackler, u₁ = 2.6 m/s

Mass of halfback, m₂ = 92 kg

Speed of halfback, u₂ = -5 m/s (direction is opposite)

To find,

Mutual speed immediately after the collision.

Solution,

The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :

[tex]m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{100\times 2.6+92\times (-5)}{(100+92)}\\\\V=-1.04\ m/s[/tex]

So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.

Answer:

16.26 cm in front of the mirror

Explanation:

Using,

1/f = 1/u+1/v....................... Equation 1

Where f = focal focal length of the concave mirror, u = object distance, v = image distance.

make v the subject of the equation

v = fu/(u-f)................... Equation 2

Note: The focal length of a concave mirror is positive

Using the real- is- positive convention

Given: f = 22/2 = 11 cm, u = 34 cm.

Substitute into equation 2

v = (34×11)/(34-11)

v = 374/23

v = 16.26 cm.

The image will be formed 16.26 cm in front of the mirror.

Answer:

The angle through which the wheel turned is 947.7 rad.

Explanation:

initial angular velocity, [tex]\omega _i[/tex] = 33.3 rad/s

angular acceleration, α = 2.15 rad/s²

final angular velocity, [tex]\omega_f[/tex] = 72 rad/s

angle the wheel turned, θ = ?

The angle through which the wheel turned can be calculated by applying the following kinematic equation;

[tex]\omega_f^2 = \omega_i^2 + 2\alpha \theta\\\\\theta = \frac{\omega_f^2\ -\ \omega_i^2}{2\alpha } \\\\\theta = \frac{(72)^2\ -\ (33.3)^2}{2(2.15)}\\\\\theta = 947.7 \ rad[/tex]

Therefore, the angle through which the wheel turned is 947.7 rad.

Explanation:

Distance = speed × time

d = (600 km/hr) (2 hr)

d = 1200 km

Answer:

9 Ω

Explanation:

The following data were obtained from the question:

Resistor 1 (R1) = 3 Ω

Resistor 2 (R2) = 3 Ω

Resistor 3 (R3) = 3 Ω

Resistor 4 (R4) = 3 Ω

Resistor 5 (R5) = 3 Ω

Resistor 6 (R6) = 3 Ω

Resistor 7 (R7) = 3 Ω

Resistor 8 (R8) = 3 Ω

Resistor 9 (R9) = 3 Ω

Resistor 10 (R10) = 3 Ω

Resistor 11 (R11) = 3 Ω

Resistor 12 (R12) = 3 Ω

Equivalent Resistance (R) =.?

From the above diagram,

Resistor 1, 2, 3, 4, 5 and 6 are in series connection and in parralle connections with Resistor 7, 8, 9, 10, 11 and 12 which are also in series connection.

Thus we shall determine the equivalent resistance of Resistor 1, 2, 3, 4, 5 and 6

This is illustrated below:

Resistance Ra = R1 + R2 + R3 + R4 + R5 + R6

Ra = 3 + 3 + 3 + 3 + 3 + 3

Ra = 18 Ω

Next, we shall determine the equivalent resistance of Resistor 7, 8, 9, 10, 11 and 12.

This is illustrated below:

Resistance Rb = R7 + R8 + R9 + R10 + R11 + R12

Rb = 3 + 3 + 3 + 3 + 3 + 3

Rb = 18 Ω

Thus, Ra and Rb are in parallel connections. The equivalent resistance between A and B can be obtained as shown below :

Ra = 18 Ω

Rb = 18 Ω

Equivalent resistance R =?

1/R = 1/Ra + 1/Rb

1/R = 1/18 + 1/18

1/R = 2/18

1/R = 1/9

Invert

R = 9 Ω

Therefore, the equivalent resistance between A and B is 9 Ω.

Answer:

3.6*10^18s

Explanation:

To find the period of the satellite

We need to apply kephler's third law

Which is

MP² = (4π²/G) d³

d=semi-major axis which is the distance from center of moon = 98km+1740km = 1838km

where M= mass of the moon = 7.3x10^22kg

P=period

G=newtonian gravatational constant= 6.67x10^-11

To find the Period solve for P

P = √[(4π²/G M)xd³]

P=√(4 π²/6.67x10^-22*7.3x10^22kg) x (1.838x10^6m)³]

= 3.6*10^18s

Answer:

The correct answer is:

doesn't change (d)

Explanation:

The total energy in a system is the sum of Kinetic and Potential energies in a system, assuming that energy is not lost to an external procedure. Now, let us define what potential and kinetic energies are:

Potential Energy: this is energy at rest or stored energy

Kinetic Energy: this is energy in motion

In a simple harmonic motion of a mass-spring system, there is no dissipative force, hence the total energy is equal to the potential and kinetic energies. The total energy is not changed rather, it varies between potential and kinetic energies depending on the point at which the mass is. The kinetic energy is greatest at the point of lowest amplitude (highest velocity) and lowest at the point of greatest amplitude (lowest velocity), while potential energy is greatest at the point of highest amplitude (lowest velocity) and lowest at the point of smallest amplitude ( highest velocity). However, at every point, the sum of kinetic and potential energies equals total energy.

Answer:

The velocity of a rotating object and the centripetal force exerted on it are proportional to each other. Centripetal force is equal to mv /r. If the velocity increases, the centripetal force increases as well.

Explanation:

The velocity has the direct effect on the centripetal force. Hence, increasing the velocity, centripetal force also increases or vice - versa.

The given problem is based on the basic concept of centripetal force and fundamentals involved in the centripetal force. The centripetal force is a center seeking force which comes to play, when any object undergoes the rotational motion around the circular path.

The mathematical expression for the centripetal force is given as,

[tex]F= \dfrac{mv^{2}}{r}[/tex]

Here,

m is the mass of an object.

v is the velocity of an object undergoing the motion around the circular path.

r is the radius of curvature.

From the concept of centripetal force, the velocity of a rotating object and the centripetal force exerted on it are proportional to each other. Centripetal force is equal to mv /r. If the velocity increases, the centripetal force increases as well.

Thus, we can conclude that the velocity has the direct effect on the centripetal force. Hence, increasing the velocity, centripetal force also increases or vice - versa.

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Answer: Distance=  5 blocks and displacement= -1 block

Explanation: distance is the total length of a journey while displacement is the shortest straight length of a journey!

Answer:

allows for better thermal equilibrium

Explanation:

Due to the cone shape, most of the liquid will be closer to the bottom than the top.  The large surface area of the bottom allows for faster heating.

Answer:

Hey there!

You are applying a force, pushing the ball, which makes the ball move forwards.

Friction is working in the opposite direction, slowing the ball down as it rolls on the floor.

Let me know if this helps :)

Answer:

B. 16 kJ

Explanation:

Energy = VIt.............. Equation 1

Where V = Voltage, I = Current, t = time

Given: V = 5.0 V, I = 1.5 A, t = 1 h = 3600 s.

Substitute these values into equation 2

E = 5.0(1.5)(3600)

E = 27000 J

E = 27 kJ.

Amount of energy left = 43 kJ - 27 kJ

Amount of energy left = 16 kJ.

Hence the right option is B. 16 kJ

Answer:

5) 4.00, 2.00, 1.0

Explanation:

wave equation is given as;

F₀ = V / λ

Where;

F₀ is the fundamental frequency = first harmonic

Length of the string for first harmonic is given as;

L₀ = (¹/₂) λ  

λ  = 2 L₀

when L₀ = 1

λ  = 2 x 1 = 2m

when L₀ = 2m

λ  = 2 x 2 = 4m

For First harmonic, the wavelength is 2m, 4m

For second harmonic;

L₁ = (²/₂)λ  

L₁ = λ

When L₁ = 1

λ  = 1 m

when L₁ = 2

λ  = 2 m

For second harmonic, the wavelength is 1m, 2m

Thus, the wavelength that could represent harmonics present on both strings is 4m, 2m, 1 m

Answer:

In Boyle's law the volume of a gas increases when the pressure decreases.

Explanation:

Boyle's law states that at fixed mass of gas, the volume of a gas is inversely proportional to the gas pressure, provided temperature remain constant.

Mathematically it be expressed as;

P₁V₁ = P₂V₂

As the  volume of a gas increases,  the pressure decreases, or as the volume of the gas decreases, the pressure of the gas increases.

Therefore, in Boyle's law the volume of a gas increases when the pressure decreases.

Answer:

The resistor to be hooked up must be 9900 [tex]\Omega[/tex]

Explanation:

Recall how resistors in parallel combine to render an equivalent resistor:

[tex]\frac{1}{R_e} =\frac{1}{R_1} +\frac{1}{R_2}[/tex]

So we need to find which resistor (R2) we need to combine in parallel with resistor R1 (100 [tex]\Omega[/tex]) in order to obtain an equivalent resistor Re (99 [tex]\Omega[/tex]) :

[tex]\frac{1}{99} =\frac{1}{100} +\frac{1}{R_2}\\\frac{9900\,R_2}{99} =\frac{9900\,R_2}{100} +\frac{9900\,R_2}{R_2}\\100\,R_2= 99\,R_2+9900\\R_2=9900\,\,\Omega[/tex]

Answer:

the answers d

A Carnot heat engine and an irreversible heat engine both operate between the same high-temperature and low-temperature reservoirs. They absorb the same energy from the high-temperature reservoir as heat. The irreversible engine cannot absorb the same energy from the high-temperature reservoir as heat without violating the second law of thermodynamics, therefore the correct option is E.

It is a theoretical engine assumed to have the maximum efficiency among all engines out there in the universe.

No other engine can have greater efficiency than the Carnot engine.

The Carnot engine work on the principle of the Carnot cycle which assume that the heat and work tranfer processes are reversible in nature. there is no loss due to the friction of the piston.

As we know from the second law of thermodynamics that no other engine can have greater efficiency than the Carnot engine.

Thus, the irreversible engine cannot absorb the same energy from the high-temperature reservoir as heat without violating the second law of thermodynamics, therefore the correct option is E.

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Answer:

A) correct answer is C,   B)   correct answer is b  and C) The correct answer is b

Explanation:

In the exercises of geometric optics, the equation of the constructor tells us the location of the image.

        1 / f = 1 / p + 1 / q

where f is the focal length of the cornea-crystalline system, p and q are the distances to the object and the image.

In this case, the distance to the image on the retina is constant, about 3 cm. Therefore depending on the distance to the object) p = the focal length must change

        1 / q = 1 / f 1 / p

let's apply this expression to our case

A) indicates that the tree is at a medium distance

so that the image is formed on the retina THE SAME AS

correct answer is C

B) The squirrel is at a smaller distance (p ') than the tree (p), therefore if we substitute in the equation above we find that q must decrease. Consequently the image is in front of the retina

The mountain is very far, suppose in infinity, so the image is BEHIND THE RETINA

therefore the correct answer is b

C) The squirrel is very close so the curvature of the lens INCREASES, resulting in a DECREASE in the focal length

The correct answer is b

Answer:

work = 1728

Power = 134

Explaination:

by using the formula,

Work(W)= Force(F)×Distance(D)

Power(P)= Work(W)/Time taken(T)

Answer:

  I = 0.56 10⁻⁴ W / m²

Explanation:

Double-slit interference is described by the expression

         d sin θ = m λ

if we use trigonometry we can find the angle

        tan θ= y / L

how the angles are small

       tan θ = sin θ / cos θ = sin θ

      sin θ = y / L

we substitute

       d y / L = m λ

if we take into account that each slit also produces a diffraction phenomenon, the intensity distribution is the product of the intensity of the slits by the intensity of the diffraction process

      I = I₀ cos² (d a)   [(sin ba) / ba]²

      a = π sin θ /λ

where the separation of the slits and b is the width of the slits

we substitute

     I = I₀ [cos (d a)]²  [sin ba  /ba]²

     a = π y / (L λ)

let's reduce the magnitudes to the SI system

     λ = 582 nm = 582 10⁻⁹ m

     L = 75.0 cm = 75.0 10⁻² m

     d = 0.640 mm = 0.640 10⁻³ m

     b = 0.434 mm = 0.434 10⁻³ m

     Io = 4.40 10⁻⁴ W / m²

let's calculate for y = 0.710 mm = 0.710 10⁻³ m

     a = π 0.710 10⁻³ / (75 10⁻² 582 10⁻⁹)

      a = 5.11004 10³

I = 4.40 10⁻⁴ [cos (0.640 10⁻³ 5.11004 10³)]² (sin (0.434 10⁻³ 5.11004 10³) / (0.434 10⁻³ 5.11 10³)²

      I = 4.40 10⁻⁴ cos² (3.2704)   (sin 2.2178 / 2.2178)²

remember that the angles are in radians

      I = 4.40 10⁻⁴   0.9835  (0.79789 / 2.2178)²

      I = 4.40 10⁻⁴   0.9835    0.1294

      I = 0.56 10⁻⁴ W / m²

Answer:

3 m

Explanation:

PE = mgh

120 J = (4 kg) (10 m/s²) h

h = 3 m

The book is 3m high from the ground.

The energy by virtue of its position is called the potential energy.

PE = mgh

where, g = 9.81 m/s²

Given is the mass of book m =4kg and the potential energy P.E = 120J, then the height is

120 J = (4 kg) (10 m/s²) h

h = 3 m

Thus, the book is 3m high from the ground.

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Answer:

The speed stays constant after the force stops pushing.

Explanation:

Speed always stays constant when the force stops pushing it.

Answer:

Each side is 13.3 cm long

Explanation:

Use the formula for density as the mass per unit of volume, to find the volume of the tank:

[tex]density=\frac{mass}{Vol} \\Vol=\frac{2350}{1} \,\,cm^3\\Vol=2350\,\,cm^3[/tex]

Now we can find the dimensions of the tank knowing that it is cubic, and therefore its volume is [tex]side^3[/tex]:

[tex]side^3=2350\,\,cm^3\\side=\sqrt[3]{2350} \,\,cm\\side\aprox13.3\,\,cm[/tex]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

t = 7.5 s

Answer:

The value is [tex]\delta P = 9000 \ Pa[/tex]

Explanation:

From the question we are told that

    The inlet and outlet velocity is [tex]v = 3 \ m/s[/tex]

     The  loss coefficient is  [tex]k = 2[/tex]

      Th specific weight of water  is  [tex]w = 9800 \ N/m^3[/tex]

Generally the pressure drop across the valve is mathematically represented as

       [tex]\delta P = \frac{1}{2} * k * \rho * v^2[/tex]

Here  [tex]\rho[/tex] is the density which is mathematically represented as

      [tex]\rho = \frac{w}{g}[/tex]

=>    [tex]\rho = \frac{9800}{9.8}[/tex]

=>   [tex]\rho = 1000 \ kg/m^3[/tex]

So

    [tex]\delta P = \frac{1}{2} * 2* 1000 * 3^2[/tex]

    [tex]\delta P = 9000 \ Pa[/tex]

Answer:

b. Observe the radio waves coming from all dark matter; from the strength of the radio waves from each cluster, estimate the amount of dark matter needed to produce them.

Explanation:

The universe is thought to be made up of 85% dark matters. Dark matter is called dark because it does not appear to interact with the electromagnetic field, which means it doesn't absorb, reflect or emit electromagnetic radiation, and is therefore difficult to detect. This means that option b is wrong since radio wave is an electromagnetic wave. Dark matter is a form of matter that makes up  about a quarter of the total mass–energy density of the universe. Dark matter was theorized due a variety of astrophysical observations and gravitational effects that cannot be explained by accepted theories of gravity unless there were more matter in the universe than can be seen.

Answer:

The quantity that will be combined to determine a particle's de Broglie wavelength is ENERGY.

Explanation:

Energy of a particle is given by;

E = hf

Where;

f is frequency of the particle's wave = c/λ

[tex]E = \frac{hc}{\lambda}[/tex]

[tex]\lambda= \frac{hc}{E}[/tex]

Where;

λ is the  particle's de Broglie wavelength

h is the Planck's constant = 6.626 x 10⁻³⁴ J/s (This is one of the universal physical quantities)

c is the speed of light, = 3 x 10⁸ m/s (This is also one of the universal physical quantities)

E is the energy of the particle.

Therefore, the quantity that will be combined to determine a particle's de Broglie wavelength is ENERGY.

The de Broglie wavelength of a particle can be calculated using energy and universal physical parameters.

The wavelength of a wave signal conveyed in space or down a wire is the distance among identical points (consecutive crests) in adjacent cycles.

When two persons have the same overall mentality and hence can communicate successfully, this is an instance of wavelength.

The de Broglie wavelength of a particle can be calculated using energy and universal physical parameters.

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