Answer: x = 2, x = 3 ( whichever is m and whichever is n )
Step-by-step explanation: h
x^2 + 6x - 5 = 0
( x - 2 ) ( x - 3 ) you take the x^2 and you split it into separate groups
the negatives will give you a positive 6, but also a negative 5. you want to use multiples of 6 to add up to -5. so you do ( x - 2 ) and ( x - 3 ) and it doesn't matter what order you do the numbers!! both are negative trying to add up to a negative.
then you want to get x.
x - 2 = 0
add two to the 0 and x = 2
then the other x
x - 3 = 0
add the three to the 0 and x = 3
Answer:
x=-3+[tex]\sqrt{x} 14[/tex]
Step-by-step explanation:
I got it right on plato
Through 5 games in April, Lebron James has scored 112 points. At this rate, how many points will he score in his next 12 games? Round to the nearest point. _______ points
Answer:
269points
Step-by-step explanation:
112/5=22.4
22.4x12=268.8
268.8≈269
calculate the values of the expression below 5 - 2 * 3 + 6 (3^2+1)
Answer:
= 59
Step-by-step explanation:
5 - 2 * 3 + 6 (3² + 1)
= 5 - 2 * 3 + 6 * 10
= 5 - 6 + 6 * 10
= 5 - 6 + 60
= 59
Answer:
59Step-by-step explanation:
[tex]5-2\times \:3+6\left(3^2+1\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3^2+1\right)\::\quad 10\\\\=5-2\times \:3+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times \:3\::\quad 6\\=5-6+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:6\times \:10\::\quad 60\\\\=5-6+60\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5-6+60\:\\\\:\quad 59[/tex]
HW: Solve for the
1) 5(2- b) = 0
Plz help ASAP???
Answer:
[tex]\huge \boxed{b=2}[/tex]
Step-by-step explanation:
[tex]5(2- b) = 0[/tex]
[tex]\sf Divide \ both \ sides \ by \ 5.[/tex]
[tex]2-b=0[/tex]
[tex]\sf Subtract \ 2 \ from \ both \ sides.[/tex]
[tex]-b=-2[/tex]
[tex]\sf Cancel \ negative \ signs.[/tex]
[tex]b=2[/tex]
Answer:
b = 2
Step-by-step explanation:
5(2-b) = 0
=> 5 x 2 - 5 x b = 0
=> 10 - 5b = 0
=> -5b = -10
=> -b = -10/5
=> -b = -2
=> b = 2
Let's check whether our answer is correct:
=> 5(2-2) = 0
=> 5 (0) = 0
=> 0 = 0
A company makes a profit of $7 per software program and $8 per video game. The company can produce at most 90 software programs and at most 80 video games per week. Total production cannot exceed 120 items per week. How many items of each kind should be produced per week in order to maximize the profit? Use linear programming to solve. Show all your work.
Answer:
930 dollars
Step-by-step explanation:
Let software programs = S
Video game = V
Given that a company makes a profit of $7 per software program that is, 7S and $8 per video game that is, 8V. The company can produce at most 90 software programs and at most 80 video games per week. Since the Total production cannot exceed 120 items per week.
How many items of each kind should be produced per week in order to maximize the profit?
The to get profit P
P = 7S + 8V
Since the profit on video game is higher, we will give maximum production to video game. Therefore,
P = (30 × 7) + ( 8 × 90)
P = 210 + 720
P = 930 dollars
Can The intersection of two planes can be a ray.
Answer: Either the plane and the ray perfectly coincide in which case there is an infinity of solutions or the ray is away from the plane in which case there is no intersection. Generally in a C++ implementation, when the denominator is lower than a very small value, we simply return false (no intersection was found).
Step-by-step explanation:
The area of a rectangle is 36 units^2
The length is 9, and the width is Va.
What is the value of x?
What is the width of the rectangle?
Answer:
The width is 4
Step-by-step explanation:
the length times the with is the area
since the area is 36
9 times x = 36
so
since 9 x 4 = 36,
the width is 4
work out 2 ¼÷ ½ as a single fraction
Show all your working.
Answer:
Step-by-step explanation:
[tex]2\frac{1}{4}[/tex] ÷[tex]\frac{1}{2}[/tex] = [tex]\frac{9}{4}[/tex] ÷ [tex]\frac{1}{2}[/tex]
[tex]=\frac{9}{4}*\frac{2}{1}\\\\\\=\frac{9}{2}\\\\\\=4\frac{1}{2}[/tex]
Simplify -6/3 divided by 2/-9
two variable equation
LET x=0 x-2y=4 what is the value of y?
Solve for the missing variable: LET y=0: x-2y=4 what is the value of x?
Step-by-step explanation:
(i) Let x = 0 and x-2y=4
Put x = 0 in x-2y=4
0-2y=4
-2y=4
y=-2
If x = 0, the value of y is -2.
(ii) Let y=0 and x-2y=4
Put y = 0 in x-2y=4
x-2(0)=4
x=4
If y = 0, the value of x is 4.
(4,0) (3,-1) (6,3) (2,-4) which are solutions to y=x-4
Answer:
None of them are
(4,-4)
Step-by-step explanation:
To find the value of x make y =0 then substitute into the formula. Therefore 0 = x-4 then make x the subject by adding 4 to the other side 4+0=x.
Then to find the value of y make x=0 then substitute it into the formula y=0-4 which is equal to - 4
I hope this helps
If y = 1/2(d + 1), find y when d = 7
Answer:
4
Step-by-step explanation:
Plug in 7 for d:
y= 1/2(7+1)
y=1/2(8) .... Adding what's in the parenthesis (PEMDAS)
y=4 ..... Multiply 1/2 by 8
Hope this helps:)
Answer:
[tex] \boxed{ \boxed{ \bold{ \purple{y = 4}}}}[/tex]Step-by-step explanation:
[tex] \sf{Given}[/tex]
[tex] \sf{d = 7}[/tex]
Let's find the value of y:
[tex] \sf{y = \frac{1}{2} (d + 1)}[/tex]
plug the value of d
[tex] \sf{ = \frac{1}{2} (7 + 1)}[/tex]
Add the numbers
[tex] \sf{= \frac{1}{2} \times 8}[/tex]
Calculate
[tex] \sf{ = 4}[/tex]
Hope I helped!
Best regards!
can you please solve this for me asap?
Hi there! :)
Answer:
(a) ≈ 3.61 cm.
(b) = 2.77 cm².
Use the Pythagorean theorem to solve for the side-length of DC. Let "s" represent the side-lengths:
s² + s² = 26
2s² = 26
Divide both sides by 2 to simplify:
s² = 13
Take the square root of both sides:
s = √13 ≈ 3.61 cm.
------------------------------------------------------------------------------------------
Calculate the shaded region by subtracting the area of the arc from the area of the square. DC represents the radius of the circle that the arc is apart of. Therefore:
Area of arc AC = 1/4 (πr²)
Solve for the area:
AC = 1/4 (π · (3.61)²)
AC = 1/4 (40.92)
AC = 10.23 cm²
Subtract this area from the area of the square (A = s²)
A = (√13)²
A = 13 cm²
13 - 10.23 = 2.77 cm²
Therefore, the solutions are:
(a) ≈ 3.61 cm.
(b) = 2.77 cm².
Find the value of a/b when a = 2/3 and b= 7/9
Answer:
6/7
Step-by-step explanation:
2/3X9/7
simplify 9 by 3
which equals:
2/1X3/7
=6/7
which value of x makes the equation 2.75(2x - 14)= 5.55
Answer:
x=881/110 =8^1/110 =8.009
Step-by-step explanation:
2.75(2x−14)=5.55
Divide both sides by 2.75.
2x-14=5.55/2.75
Expand 5.55/2.75 by multiplying both numerator and the denominator by 100.
2x−14= 555/275
Reduce the fraction 555/275 to lowest terms by extracting and canceling out 5.
2x−14= 111/5
Convert 14 to fraction 770/55 = 14
2x=111/55+770/55
Since 111/55 and 770/55 have the same denominator, add them by adding their numerators.
2x=111+770/5
Add 111 and 770 to get 881.
2x=881/55
Divide both sides by 2.
x= 881/55/2
Express 881/55/2 as a single fraction.
x= 881/55 x 2
Multiply 55 and 2 to get 110.
x = 881/110
Find the product. √5(2+√7) A)2√5+√35 B)√45 C)2√5+2√7 D)√10+√35
Answer:
[tex]\huge \boxed{2\sqrt{5} +\sqrt{35}}[/tex]
Step-by-step explanation:
[tex]\sqrt{5} (2+\sqrt{7} )[/tex]
Expand brackets.
[tex]\sqrt{5} (2)+\sqrt{5}(\sqrt{7} )[/tex]
[tex]2\sqrt{5} +\sqrt{5} \sqrt{7}[/tex]
Apply radical rule : [tex]\sqrt{a} \sqrt{b} =\sqrt{ab}[/tex]
[tex]2\sqrt{5} +\sqrt{5 \times 7}[/tex]
[tex]2\sqrt{5} +\sqrt{35}[/tex]
Answer:
[tex] \boxed{ \boxed{ \bold{ \blue{2 \sqrt{5} + \sqrt{35} }}}}[/tex]Option A is the correct option.
Step-by-step explanation:
[tex] \sf{ \sqrt{5} \: (2 + \sqrt{7} )}[/tex]
Distribute √5 through the parentheses
⇒[tex] \sf{ \sqrt{5} \times 2 + \sqrt{5} \times \sqrt{7} }[/tex]
Calculate the product
⇒[tex] \sf{2 \sqrt{5} + \sqrt{5 \times 7} }[/tex]
⇒[tex] \sf{2 \sqrt{5} + \sqrt{35} }[/tex]
Hope I helped!
Best regards!
Write an equation in slope-intercept form for each line described. Slope = 8, passes through (-7,5)
Answer:
Equation of given line: y=8x+61
See graph below for a visual of given straight line equation.
+graph%28+300%2C+300%2C+-10%2C+10%2C+-100%2C+100%2C+8x%2B61%29+
Vertical and passes through (-4,-2)
vertical slope means that the equation becomes: x=-4, (y does not matter)
hope it helps
What are the whole numbers between 3 to 10?
4, 5, 6, 7, 8 and 9 are the whole numbers between 3 to 10.
What are whole numbers?Whole numbers are a set of numbers including all natural numbers and 0. They are a part of real numbers that do not include fractions, decimals, or negative numbers. Counting numbers are also considered as whole numbers.
Two given whole numbers are 3 and 10.
The number of whole numbers between 3 to 10 is
(10-3)-1=6
The whole numbers between 3 to 10 are 4, 5, 6, 7, 8, 9.
Therefore, 4, 5, 6, 7, 8 and 9 are the whole numbers between 3 to 10.
Learn more about the whole numbers here:
https://brainly.com/question/29766862.
#SPJ2
Bill claims that he found the actual December temperature by adding either -5+3 or 3 +-5.
What property did Bill use?
Answer: Commutative property of addition
This is the idea that x+y is the same as y+x
We can add any two numbers in any order we want.
Other examples:
2+3 = 5 and 3+2 = 5
7+2 = 9 and 2+7 = 9
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks
Complete question :
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.
Answer:
575 - 12t
Step-by-step explanation:
Given the following :
Total number of fireworks = 575
Number of shots per minute = 12
To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.
In algebraic terms
[total number of fireworks on display - (number of shots per minute × t)]
575 - 12t
Find y' if x = cos(y).
1. Solve for y (complex solution)
y=−iln(x2−1+x)+2πn1, n1∈Z
y=−iln(−x2−1+x)+2πn2, n2∈Z
2. Solve for y (Easier)
y=−arccos(x)+2πn1, n1∈Z
y=arccos(x)+2πn2, n2∈Z, ∣x∣≤1
Mike is catering a party. He plans on having 4 trays of 5 appetizers each on the buffet at the beginning of the party and will rotate in new trays as those become empty. To ensure that he does not run out of appetizers during the party, he is going to make 2 appetizers per person in addition to the initial number put out on the buffet. Which of the following represents A, the amount of appetizers Mike needs to make, in terms of p, the amount of people attending the party?
A.
A = 20p + 2
B.
A = 20 + 2p
C.
A = 2 - 20p
D.
A = 2p - 20
Answer:
B
Step-by-step explanation:
Since he needs to make 2 appetizers per person, the variable "p" needs to go with the "2".
Also, since he is making 20 ( 4 trays, 5 apps each) extra appetizers for the beginning, we will need to add 20 to that number.
Two variable equation
Simplify 3+2-16x9
Simplify : 4-3+7(12-2)
Answer:
[tex]3+2-16x9[/tex] is [tex]5-16x^9[/tex] [tex]4-3+7(12-2)[/tex] is [tex]71[/tex]
Step-by-step explanation:
x=3y+6
how do I solve for y?
Answer: y=2X-3
Step-by-step explanation:
1st u need to subtract the 6 on each side so your left with, -6+X=3y, then u divide the 3 on each side and your left with, -3+2X=y.
What is the inverse function of y = -5/3x - 8?
Answer:
You can't graph inverse function on graphing calculator
Step-by-step explanation:
step 1 rewrite function f(x) --> y
step 2 change x and y's position
step 3 solve for y
step 4 replace Y with f-1(up to f) and (x)
kinyua spent 1/4 of his net january salary on school fees .he spent 1/4 of the remainder on electricity,he spent 1/9 of what remained on transport,if he finally had sh 3400,calculate his net january salary
Answer:
1-1/4 = 3/4.
3/4-1/4 = 2/4 = 1/2.
1/2-1/9 = 9/18-2/18 = 7/18.
7x/18 = 8400
X = $21,600 = Net Jan. salary.
Hope it helped u if yes mark me BRAINLIEST!
Tysm!
help me please ┗( T﹏T )┛┗( T﹏T )┛┗( T﹏T )┛┗( T﹏T )┛┗( T﹏T )┛┗( T﹏T )┛┗( T﹏T )┛(i will give brainly)
Answer:
a) 08:04
b) 07:00
c) 14 minutes
Step-by-step explanation:
a) According to the timetable, a bus that leaves at 07:54 from Hope Street will arrive at School Rock at 08:04.
b) Since Jo needs to be at the school at 8 am, she can't arrive at a time that is past 8. This means that the latest time to catch the bus station is 07:00.
c) You have to subtract the time at which you reach the destination by the time at which you leave your starting time. It takes the bus 14 minutes to travel from the bus station to School Road.
07:14 - 07:00 = 00:14
Jonas is planning out his route for an upcoming race. He uses negative numbers to represent points before the finish line and positive numbers to represent points after the finish line. On Jonas's map, there is a bridge at -91 \dfrac34−91 4 3 minus, 91, start fraction, 3, divided by, 4, end fraction meters, and his wife is watching him at 14 \dfrac1214 2 1 14, start fraction, 1, divided by, 2, end fraction meters. What does 000 meters represent? Choose 1 answer: Choose 1 answer:
Answer:
(C)The finish line
A triangle has vertices at (-4,-6),(3,3), (7,2). Rounded to two decimal places, which of the following is the closest approximation of
the perimeter of the triangle?
A. 19.34
B. 12.36
C. 15.52
D. 29.12
Answer:
Hey there!
The perimeter of the triangle is the distance around it.
We can find the distance of two points using the distance formula, and add up all the distances to find the total distance.
-4, -6 to 3, 3 is 2
3, 3 to 7, 2 is 5
7, 2 to -4, -6 is about 5.4
2+5+5.39=12.4, which is closest to 12.36.
Let me know if this helps :)
[tex] \int \sec(x) dx[/tex]
Evaluate the integral above
[tex] 👋 [/tex] Hello ! ☺️
Step-by-step explanation:
∫sec(x)dx =
∫ [tex]\frac{sec(x).(secx + tanx)}{secx + tanx}dx[/tex]
∫ [tex] \frac{sec {}^{2} (x) + secxtanx}{secx + tanx}dx [/tex]
u = secx + tanx
[tex] du = secx tanx + sec {}^{2}x \: dx[/tex]
[tex] ∫\frac{1}{u}du [/tex]
∫sec(x)dx= ln |u|
[tex]\boxed{\color{gold}{∫sec(x)dx= ln |secx +tanx| + C}} [/tex]
[tex]<marquee direction="left" scrollamount="2" height="100" width="150">💘Mynea04</marquee>[/tex]
Answer:
[tex] = \ln( | \sec(x) + \tan(x) | ) + C[/tex]
Step-by-step explanation:
[tex] \int \sec(x) dx[/tex]
multiply and divide by sec x + tan x
[tex] = \int \frac{ \sec(x) ( \sec(x) + \tan(x) ) }{ \sec(x) + \tan(x) } dx[/tex]
let u = sec x + tan x
du = (sec x)(sec x + tan x) dx
[tex] = \int \frac{1}{u} du[/tex]
[tex] = \ln( |u| ) + C[/tex]
[tex] = \boxed{\color{green}{ \ln( | \sec(x) + \tan(x) | ) + C}}[/tex]
26 points with brainiest and 5 stars and thanks, please help! :[
Answer:
[tex]\Huge \boxed{{9}}[/tex]
Step-by-step explanation:
Let the age of Darrell be x.
Let the age of Bryce be y.
x = y + 8
xy = 153
Substitute x = y + 8 in the second equation.
(y+8)y = 153
Solve for y.
y² + 8y = 153
Subtract 153 from both sides.
y² + 8y - 153 = 0
Factor left side.
(y-9)(y+17) = 0
Set factors equal to 0.
y - 9 = 0, y = 9
y + 17 = 0, y = -17
The value of y has to be positive, so y = 9.
Substitute y = 9 in the first equation.
x = 9 + 8
x = 17
Darrell is 17 years old.
Bryce is 9 years old.
Answer:
[tex]\huge\boxed{9\ years}[/tex]
Step-by-step explanation:
Let Darrel's Age be x and Bryce's Age be y
Condition 1:
x = 8 + y
Condition 2:
xy = 153
Put the 1st equation in the second one
(8+y)y = 153
y²+8y-153 = 0
y²+17y-9y-153 = 0
y(y+17)-9(y+17) = 0
(y-9)(y+17) = 0
Either,
y-9 = 0 OR y+17 = 0
y = 9 OR y = -17 [Contrary to be given, Age can never be negative]
So, y = 9
And
Bryce's Age = 9 years