Raul started out fifteen meters to my left walking towards me. Three seconds
later, he was 6 meters to my left. How fast is Raul walking. Write an equation to
find his displacement, x, from the time, t. If he keeps going at the same rate,
where will he be 15 seconds from when he started?​

Answers

Answer 1

Answer:

Raul will be 30 meters to the right of observer.  

Explanation:

Raul is walking towards the observer, let be [tex]x[/tex] the position of Raul with respect to the observer and, besides, that [tex]x[/tex] is negative to the left and positive to the right.

Raul is moving at constant rate so that velocity ([tex]v[/tex]) is equal to:

[tex]v = \frac{x_{f}-x_{o}}{\Delta t}[/tex]

Where:

[tex]x_{o}[/tex], [tex]x_{f}[/tex] - Initial and final position of Raul regarding the observer, measured in meters.

[tex]\Delta t[/tex] - Change in time, measured in seconds.

Given that [tex]x_{o} = -15\,m[/tex], [tex]x_{f} = -6\,m[/tex] and [tex]\Delta t = 3\,s[/tex], the velocity of Raul is:

[tex]v = \frac{(-6\,m)-(-15\,m)}{3\,s}[/tex]

[tex]v = +3\,\frac{m}{s}[/tex]

The equation of his displacement is represented by clearing final position in the equation above:

[tex]x_{f} = x_{o}+v\cdot \Delta t[/tex]

If [tex]x_{o} = -15\,m[/tex] and [tex]v = +\frac{3}{5}\,\frac{m}{s}[/tex], the equation of motion is:

[tex]x_{f} = -15\,m + \left(+3\,\frac{m}{s} \right)\cdot \Delta t[/tex]

Then, if [tex]\Delta t = 15\,s[/tex], the final position of Raul regarding the observer is:

[tex]x_{f} = -15\,m + \left(+3\,\frac{m}{s} \right)\cdot (15\,s)[/tex]

[tex]x_{f} = +30\,m[/tex]

Raul will be 30 meters to the right of observer.  


Related Questions

Two balls are released from the same height on the moon. They both reach the ground at the same time. Which statement is correct about the two balls

Answers

Answer:

same acceleration

Explanation:

A car is traveling 35 mph on a smooth surface. If a balanced force is applied to the car, what happens?

Answers

Answer:

Here is the answer.

Explanation:

Balanced forces- they are those forces that produce 0 resultant forces.

therefore, on applying a balanced force on the object, it wouldn't result in any change, as resultant force would be 0.

A toy car, released from the table top, is at the
half-way mark along the ramp to the floor below.

Тар
Kinetic Energy
Gravitational Potential Energy
Both of these
None of these

Answers

Answer:

Gravitational Potential Energy

Explanation:

A toy car, released from the table top, is at the half-way mark along the ramp to the floor below will be experiencing Gravitational Potential Energy. Thus, the correct option is B.

What is Gravitational Potential Energy?

Gravitational energy is also known as the gravitational potential energy. It is the potential energy which a massive object has in relation to another massive object due to gravitational force. It is the potential energy which is associated with the gravitational field, and is released when the objects fall towards each other from a certain height.

When something has a high position, then its gravitational potential energy is high. For example, a book which is placed on a high bookshelf has a higher potential energy than a book which is placed on the bottom shelf because it has farther to fall.

Therefore, the correct option is B.

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What is your average velocity or speed if you travel 500 km in 3 hours

Answers

Answer:

166.6 km/h

Explanation:

500/3

=166.6

An automobile travels a displacement of 75km 45 degrees north of east. How many kilometers north does it travel?

Answers

Answer:

It travelled 53.03 Km North.

The distance traveled by the automobile is 53.03 km north.

The given parameter:

the displacement of the automobile, = 75 km 45 degrees north of east.

To find:

the distance traveled by the automobile

The vertical component of the displacement is equal to the distance traveled by the automobile in north.

[tex]distance \ towards \ north = 75 \ km \ \times \ sin(45)\\\\distance \ towards \ north = 75 \ km \times 0.7071\\\\distance \ towards \ north = 53.03 \ km \ north[/tex]

Thus, the distance traveled by the automobile is 53.03 km north.

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Part A
The initial velocity of a car moving along a straight path was 0 meters/second. After 10 seconds, it reached a velocity of 25 meters/second.
Calculate the car's average acceleration during this time period.

Answers

Answer:

2.5 m/s²

Explanation:

Using the formula, v = u + at ( v = Final velocity; u = Initial velocity; t = Time; a = Acceleration)

25 = 0 + 10a

a = 25/10 = 2.5 m/s²

A pie is cooked in an oven at 200 °C. The aluminium film that ckvered the pie can be touched soon after it is removed while the pie is still dangerously hot. Explain this?

Answers

Answer and Explanation:

The aluminum is more productive in the absorption and heat transfer to other particles. It instantly converts heat absorbed from the environment into the atmosphere when removed from the oven, enabling us to operate with it faster than the pie that takes much longer to convert heat to the environment.

So this is the reason for pie to be the dangerously hot

A light beam travels through a diamond (n=2.42) to pure water (n=1.33). The refracted ray will:
a) bend toward the normal
b) bend away from the normal
c) remain unchanged
d) bend toward the normal then away

Answers

Answer:

b) bend away from the normal

Explanation:

According to snell's law , if i be the angle of incidence and r be the angle of refraction

sin i / sin r = 1.33 / 2.42

sin i / sin r = .55

Hence sin r > sin i

r > i

In other words angle of refraction will be more than angle of incidence . So, the ray will bend away from the normal .

What is the current in a circuit that has a power of 200 W and a resistance of 150 Ω

Answers

Answer:

Current = 1.15 A

Explanation:

Since we are finding the current

Power in a circuit can be found by using the formula

[tex]P = I ^{2} R[/tex]

Where

I is the current

R is the resistance

P is the power

From the question

Power = 200 W

Resistance = 150 Ω

Substitute the values into the above formula and solve for the current

That's

[tex]200 = 150{I}^{2} [/tex]

Divide both sides by 150

We have

[tex] {I}^{2} = \frac{200}{150} \\ = \frac{4}{3} [/tex]

Find the square root of both sides

We have

[tex]I = \sqrt{ \frac{4}{3} } [/tex]

= 1.154700

We have the final answer as

Current = 1.15 A

Hope this helps you

A certain part of a flat screen TV has a thickness of 150 nm how many meters is this

Answers

Answer:

[tex]1.5\,\,10^{-7}\,\,m= 0.00000015\,\,m[/tex]

Explanation:

The prefix nano means [tex]10^{-9}[/tex], therefore:

[tex]150 \,\,nm = 150\,\,10^{-9}\,m=1.5\,\,10^{-7}\,\,m= 0.00000015\,\,m[/tex]

An object accelerates 20.8 m/s2 when a force of 8.9 newtons is applied. What is the mass of the object?

Answers

Answer: 0.43kg

Explanation: a = 20.8m/s^2

                      F = 8.9N

                      m = ?

F = ma

8.9 = 20.8m

m = 8.9/20.8

= 0.43kg

Hope this helped..

A point on a wave completes one cycle every 5 seconds. The frequency of this wave is 1/5 seconds.
Question 2 options:
True
False

Answers

Answer:

True

Explanation:

1 cycle every 5 sec is the same when you set up the ratio as 1/5

Hope this helps!! Have a great day!!      :)

if an object is moving with constant speed then its distance-time graph will be a straight line. (a)along time axis. (b)along distance axis (c)parallel to time axis (d)inclined to time axis

Answers

Answer: (d)inclined to time axis

Explanation:

For a moving object, the distance equation can be written as:

D = S*t

if S = 0, we will have a line parallel to the time axis.

if S = infinity we will have a line parallel to the distance axis.

Both options are discarded here, as S = ∞ is not possible, and S = 0 would mean that the object is not moving.

where D is the distance moved at the time t, t is the variable, and S is the speed of the object.

As S is constant, this equation defines a linear relationship.

The graph of this line will be a line that is not parallel either to the time axis nor the distance axis, this will be an inclined line that goes between them.

So the correct option is: (d)inclined to time axis

A cell membrane has a thickness of about 7 nm. How many cell membranes would it take to make a stack 3.4 in high?

Answers

Answer:

486 of cell membranes

Explanation:

one cell membrane has 7*10^-9m as the height

So, by dividing 3.4 with 7*10^-9 you will get the number of cell require to form the height.

3.4/(7*10^-9)=485.71

because we can't have decimal number of cell we would round it into three significant figures, 486.

Dust particles fall down when a carpet or a piece of cloth is beaten by a stick,why?​

Answers

Dust particles fall down when we hit the carpet or a piece of cloth with a stick because it loses it inertia of rest and move forward, but dust particles fall down in absence of the carpet.

Friends tell you that on a recent trip their average velocity was +20 m/s. Is it possible that at any time during the trip their velocity was -20 m/s? Explain

Answers

Answer:

Yes , it is possible .

Explanation:

Suppose they travelled from A to B , a distance of 800 m at a velocity of

40m /s and then come back on the same path covering a distance of 200 m at the rate of 20/ s .In other words their velocity in their return journey was -20m /s .

Net displacement = 600 m

Total time taken = (800 / 40) + (200 / 20)

= 20 + 10 = 30 s

Average velocity = net displacement / total time

= 600 / 30 = 20 m /s .

Hence average velocity of 20 m /s is possible .  

Tech A says that when a fuse has blown, it just has to be replaced, because it performed its job. Tech B says that when a fuse has blown, the circuit has to be diagnosed because the fuse was probably not the problem. Who is correct

Answers

Answer:

tech B

Explanation:

im assuming its ASE or CDX i got my ase certification

you should also always replace that fuse its there to stop a harmful amount of voltage to said thing like a starter or a a fan

Which motor and body should Devon use to build the car with the greatest acceleration? motor 1, with body 1 motor 1, with body 2 motor 2, with body 1 motor 2, with body 2

Answers

Answer:

hello your question is incomplete below is the complete question

Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as shown in the table.

Which motor and body should Devon use to build the car with the greatest acceleration?

motor 1, with body 1

motor 1, with body 2

motor 2, with body 1

motor 2, with body 2

answer: Motor 2 body 1

Explanation:

F = ma

hence a ( acceleration ) = F / m

force of motor 2 = 15 N since the mass of the motor is the same and that of the bodies aren't given

The motor and body that would produce the greatest acceleration would be : Motor 2 Body 1  if the mass of Body 1 is less than the mass of Body 2

Answer:

c

Explanation:

Jaune moves North 15 meters, South 5 meters, then North 8 meters. How far is Jaune DISPLACED?

Answers

Answer:

Displacement = 7 meters

Explanation:

Given that,

Jaune moves North 15 meters, South 5 meters, then North 8 meters. We need to find the displacement of Jaune.

The attached figure shows the motion of Jaune.

We know that, Displacement = final position - initial position

Initially, Jaune traveled 15 meters due North and finally, he travel 8 meters North.

Displcement = 15 m - 8 m

Displacement = 7 m

So, the displacement of Jaune is 7 meters.

What problems would we have if Pascal had failed to give the Pascal's law? Write some points.

Answers

Hydraulic jacks, automobile brakes and even the lift generated on airplane wings can be explained using Pascal's principle. Pascal's principle is based on the idea that fluids at rest are incompressible, allowing very large forces to be transmitted with the application of a smaller force.

Answer:

Pascal's law states that a change in pressure at any point in an enclosed fluid is transmitted equally throughout the fluid.

Explanation:

Applications of Pascal's law include

>The hidden standard of the water powered jack and pressure driven press.  

>Power intensification in the slowing mechanism of most engine vehicles.  

>Utilized in artesian wells, water pinnacles, and dams.  

>Scuba jumpers must comprehend this rule. At a profundity of 10 meters submerged, pressure is double the environmental weight adrift level, and increments by around 100 kPa for each expansion of 10 m depth.[5]  

>Generally Pascal's standard is applied to bound space (static flow), however because of the consistent flow process, Pascal's rule can be applied to the lift oil instrument (which can be represented as a U tube with pistons on either end).

Without Pascal's law, none of the above could be possible.

The table displays the scores of students on a recent exam. Find the mean of the
scores to the nearest 10th.
Score Number of Students
65
4.
70
2
75
2
80
1
85
7
90
5

Answers

Answer:

Solution

x f fx

65 4 260

70 2 140

75 2 150

80 1 80

85 7 595

90 5 450

total N=21 Summation fx=1675

We know

Mean= Summation fx/N

=1675/21

=79.8

Hence, the required mean is 79.8 ans.

The scores of students on a recent exam. The mean of the scores is  51.42857.

What is mean?

The mean is the ratio of addition of all the observation values and the number of observations.

The mean of the score is equal to

Mean =  {(65×4)+(70×2)+(75×2)+(80×1)+(85×7)+(90×5)} / (4+2+2+1+7+5)

Mean = 51.42857

Therefore, the mean of the scores is  51.42857.

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A solid aluminum cube has sides each of length L . A second cube of the same material has sides four times the length of the first cube; i.e., 4 L . Compared to the first cube, the total surface area of the second cube is 1. twenty-seven times the first cube. 2. sixteen times the first cube. 3. sixty-four times the first cube. 4. eight times the first cube. 5. twenty-four times the first cube. 6. two times the first cube

Answers

Answer:

Option (2) : Sixteen times the first cube

Explanation:

[tex]Surface \: Area \: of \: Cube = 6 {a}^{2} [/tex]

[tex] \frac{T.S.A \: of \: larger \: cube}{T.S.A \: of \: smaller \: cube} = \frac{6 \times 16 {l}^{2} }{6 \times {l}^{2} } = 16[/tex]

When the linear dimensions of a solid are multiplied by ' R ', the surface area of all or any part of it increases by R² , and the volume of all or any part of it increases by R³ .

If the sides of the second cube are 4 times the sides of the first one, then the second cube has (4²) = sixteen times the surface area of the first one (2), and it has (4³) = 64 times the volume of the first one.

Study the interaction of the light rays with the mediums. Classify the medium in each image as being transparent or opaque.

Answers

Answer:

a) transparent

b) transparent

c) opaque

Explanation:

In the first one, the light rays go completely through, so it is transparent.

The second one I'm not too sure about. It is refraction so it's going through a different material, but the fact that it went through makes me say transparent.

Last one, the light rays are reflecting off the surface so it's opaque.

Please feel free to correct me if I'm wrong. This is just my understanding

How much time does it take for a car with a speed of 85 m/s to drive a distance of 200 m? (1 point)

Answers

The car will take 2.35 seconds to drive a distance of 200 m.

What is speed?

Speed is a physical quantity that is a measure of the rate of change in the position of an object. It is the rate of change of distance with respect to time. Speed is a scalar quantity and is expressed as the magnitude of velocity, which is the rate and direction of motion of an object. Speed is measured in meters per second (m/s).

To find the time it takes for the car to drive a distance of 200 m with a speed of 85 m/s, we can use the formula:

time = distance / speed

Plugging in the values given, we get:

time = 200 m / 85 m/s

Simplifying this expression, we get:

time = 2.35 s

Therefore, it takes 2.35 seconds for the car to drive a distance of 200 m with a speed of 85 m/s.

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where would information on the chemical and physical properties of a specific chemical be located in a laboratory or in the workplace?

Answers

Answer:

on the body of the container of the chemical and it also on the shelf where the chemical is kept in the laboratory.

Explanation:

The information on the chemical and physical properties of a specific chemical should  be located on the body of the container of the chemical. when storing chemicals in a laboratory the properties, both chemical and physical properties of the chemical should be written out and pasted on the body of the container that contains the chemicals.and also o the shelf where the chemical is kept in the laboratory or workplace .

A box 5cm long, 4cm wide and 6cm high would have what volume? Show your work

Answers

Explanation:

volume= length×width×height

5cm×4cm×6cm = 20×6= 120cm³

A statistical analysis used to examine the influence of one variable on another is

Answers

Answer: the correlation coefficien

Explanation:

Regression and correlation analysis are statistical techniques used extensively in physical geography to examine causal relationships between variables. ... Utilization of correlation analysis on dependent and independent variables produces a statistic called the correlation coefficient

Answer:the right answer is regression

Explanation:

I just took my test and correlation was wrong the correct answer is b regression

A. In what frame of reference does special relativity apply? b. In what frames must general relativity be used? c. Describe what happens to time and length at speeds close to the speed of light.

Answers

Answer:special relativity apply to INERTIAL FRAME REFERENCE

Explanation:

inertial frame of reference is the one in which acceleration is zero this means object is moving with constant velocity

800 J of heat is needed to raise the temperature of 2 kg of iron by 1°C. What is the heat capacity of 3.6 kg of iron?​

Answers

Answer: 1440 J/kg/degree Celsius

Explanation:

Heat capacity = thermal energy required / change in heat

4) A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
a) What is their speed during that run?
b) What is their velocity?
I
c) If they kept running at that velocity for another 1.3 seconds, what would their
final position be?

Answers

Answer:

(a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

Explanation:

Given that,

A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.

Suppose, the distance between 40 yard line and 25 yard line is 20 yard.

(a). We need to calculate their speed during that run

Using formula of speed

[tex]v=\dfrac{d}{t}[/tex]

Where. d = distance

t = time

Put the value into the formula

[tex]v=\dfrac{18.288}{2}[/tex]

[tex]v=10\ m/s[/tex]during that run

(b). We need to calculate their velocity

Using formula of speed

[tex]v=\dfrac{\Delta d}{\Delta t}[/tex]

Put the value into the formula

[tex]v=\dfrac{22.86-36.58}{2}[/tex]

[tex]v=-6.86\ m/s[/tex]

Negative sign shows the direction of motion.

(c). If they kept running at that velocity for another 1.3 seconds,

We need to calculate the final position

Using formula of position

[tex]d=vt[/tex]

Put the value into the formula

[tex]d=6.86\times1.3[/tex]

[tex]d=8.91\ m[/tex]

Hence, (a). Their speed during that run is 10 m/s.

(b). Their velocity is 6.86 m/s

(c). The final position is at 8.91 m.

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