Question 5.4° A school with 20 professors forms 10 committees, each containing 6 profes- sors, such that every professor is on exactly 3 committees. Prove that it is possible to select a distinct representative from each committee.

Based on the given age ratio, Mina is 10 years old.

From the case, we know that the age ratio between these 3 people are:

L : M = 1 : 2

M : N = 3 : 4

L = 2M

N = 4/3 M

30 < L + M + N < 50

We can try to find Mina's age range as:

30 < 2M + M + 4/3 M < 50

30 < 13/3 M < 50

120 < 13M < 150

9 < M < 11

Please note that we round down the age range of Mina.

We take M = 10; then:

L = 2M = 2(10) = 20

N = 4/3 M = 4/3 (10) = 13

L + M + N = 20 + 10 + 13

L + M + N = 43 --> PROVEN!

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Answer:

1. To round to the nearest tenth, we'll need to look at the digit to the right of the tenths place, the hundredths place. Since there's a three in the hundredths place, we will round down to 4.9. The mean absolute deviation of these eight values rounded to the nearest tenth is 4.9.

2. 1

Order the numbers in the data set and find the median.

2

Subtract the median from each number in the data set.

3

Take the absolute value of each difference.

4

Add up all of the positive differences.

5

Divide this sum by the number of data points in the set.

3.The lower quartile, or first quartile (Q1), is the value under which 25% of data points are found when they are arranged in increasing order. The upper quartile, or third quartile (Q3), is the value under which 75% of data points are found when arranged in increasing order.

4.

Step-by-step explanation:

With probability that person has high blood pressure = 0.3 and the probability that person is a runner = 0.4, they are not independent events. So, Correct option is D .

Independence between two events is defined as follows, if two events A and B are independent, then the occurrence of one event (A) has no effect on the probability of occurrence of the other event (B). This can be mathematically represented as:

P(A ∩ B) = P(A) * P(B)

where P(A ∩ B) is the probability of both events A and B happening at the same time.

In this question, we are given the probabilities of two events: H (high blood pressure) and R (being a runner). The probability of H is 0.3 and the probability of R is 0.4. We are also given that the probability of H and R happening at the same time is 0.2.

Now, to check if H and R are independent, we need to see if the equation

P(H ∩ R) = P(H) * P(R)

holds true.

Plugging in the given values, we get:

0.2 = 0.3 * 0.4

This equation is false, so we can conclude that H and R are not independent events. This means that the occurrence of one event affects the probability of occurrence of the other event.

Option d) states that H and R are independent events, which we have just shown to be false.

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ATMs offer a convenient and fast way for people to perform financial transactions, such as withdrawing cash, depositing checks, and transferring funds.

Convenience: ATMs are available 24/7, making it easy to access your money and perform transactions outside of normal business hours.

Speed: ATMs are typically faster than bank tellers since you don't have to wait in line and can complete transactions quickly.

Privacy: ATMs offer a level of privacy that bank tellers may not, especially if you need to perform sensitive transactions like withdrawing large amounts of cash.

Fees: Some ATMs charge fees for using their services, especially if you are not a customer of that particular bank.

Limited services: While ATMs offer many basic banking services, they may not be able to perform more complex transactions that require the assistance of a bank teller.

Technical issues: ATMs can sometimes experience technical issues, such as running out of cash or malfunctioning, which can be frustrating for users.

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Information provided in the lesson is not in the question so i gave a general view

The volume of the solid formed when this region is rotated around the y-axis is V = ∫[1,9] π(8 - y/2)² dy cubic units

Volume is a measure of the amount of three-dimensional space that a solid object occupies.

To find the volume of the solid formed when the region is rotated around the y-axis, we need to use the disk method. This involves slicing the solid into thin disks perpendicular to the y-axis and adding up the volumes of all the disks.

Each disk will have a thickness of dy and a radius of x, which can be expressed in terms of y. We can find the radius of each disk by considering the distance between the y-axis and the edge of the region. Since the region is in quadrant i, we know that the edge of the region is at x = 0 (the y-axis) and x = 6 (the right boundary of the region). Therefore, the radius of each disk is given by x = 6 - (y - 5)/2, or equivalently, x = 8 - y/2.

The area of each disk is given by the formula for the area of a circle, A = πr². Substituting our expression for x into this formula, we get

=> A = π(8 - y/2)².

To find the volume of the solid, we need to integrate the area of each disk over the range of y values that covers the region. Since the region has centroid (3,5) and area 12 square units, we know that the region must extend from y = 1 to y = 9. Therefore, the volume of the solid is given by the integral:

V = ∫[1,9] π(8 - y/2)² dy cubic units

Evaluating this integral will give us the volume of the solid formed by rotating the region around the y-axis.

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The solid is a cylinder with a typical disk or washer. It is obtained by rotating the region bounded by[tex]y = 6 - x^2[/tex]and y = 2 about the x-axis. The volume is 48π.

The region to be rotated is bounded by the equations [tex]y = 6 - x^2[/tex] and y = 2. The region is bounded horizontally by x = 0 and x = 2 and vertically by y = 2 and [tex]y = 6 - x^2.[/tex] To find the volume of the solid we can use the formula V = ∫2π0∫2y0rdrdθ. The integral inside is the area of a disk with radius r and the integral outside is the circumference of a circle with radius r. We substitute [tex]y = 6 - x^2[/tex] into the integral, giving us [tex]V = ∫2π0∫2(6 - x^2)0rdrdθ[/tex]. By solving the integral we get V = 48π.

y = 2

x² = 6×4 = 24

V = ∫2π0∫2y0rdrdθ

V = 48π

The solid is a cylinder with a typical disk or washer and is obtained by rotating the region bounded by [tex]y = 6 - x^2[/tex] and y = 2 about the x-axis.

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the probability that the sample mean cost for the 36 schools is between $25,575 and $26,500 is 54.14%.

Percentage is a way of expressing a number as a fraction of 100. The symbol for percentage is "%". For example, if you have 75%, it means 75 out of 100 or 0.75 as a decimal.

Given by the question.

We can solve these problems by using the central limit theorem and the formula for the standard error of the mean.

The standard error of the mean is:

SE = σ/√n

where σ is the population standard deviation, n is the sample size, and √ is the square root.

Using the given values, we have:

SE = 3204/√36 = 534

To find the probability that the sample mean cost for the 36 schools is less than $25,000, we need to calculate the z-score and then use a z-table to find the probability.

z = (25000 - 26489) / 534 = -2.79

Using a standard normal distribution table or calculator, we find that the probability of a z-score less than -2.79 is 0.0026 or 0.26%.

Therefore, the probability that the sample mean cost for the 36 schools is less than $25,000 is 0.26%.

To find the probability that the sample mean cost for the 36 schools is more than $26,000, we need to calculate the z-score and then use a z-table to find the probability.

z = (26000 - 26489) / 534 = -0.91

Using a standard normal distribution table or calculator, we find that the probability of a z-score more than -0.91 is 0.8186 or 81.86%.

Therefore, the probability that the sample mean cost for the 36 schools is more than $26,000 is 81.86%.

To find the probability that the sample mean cost for the 36 schools is between $25,575 and $26,500, we need to calculate the z-scores for both values and then use a z-table to find the probabilities.

z1 = (25575 - 26489) / 534 = -1.73

z2 = (26500 - 26489) / 534 = 0.21

Using a standard normal distribution table or calculator, we find that the probability of a z-score less than -1.73 is 0.0418 and the probability of a z-score less than 0.21 is 0.5832.

Therefore, the probability that the sample mean cost for the 36 schools is between $25,575 and $26,500 is the difference between these probabilities:

0.5832 - 0.0418 = 0.5414

Multiplying by 100, we get a probability of 54.14%.

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The cement and gravel must be used in construction is 60 and 80.

Suppose that we've got two quantities with measurements as 'a' and 'b'

Then, their ratio(ratio of a to b) a:b

or [tex]\dfrac{a}{b}[/tex]

We usually cancel out the common factors from both the numerator and the denominator of the fraction we obtained. Numerator is the upper quantity in the fraction and denominator is the lower quantity in the fraction).

Suppose that we've got a = 6, and b= 4, then:

[tex]a:b = 6:2 = \dfrac{6}{2} = \dfrac{2 \times 3}{2 \times 1} = \dfrac{3}{1} = 3\\or\\a : b = 3 : 1 = 3/1 = 3[/tex]

Remember that the ratio should always be taken of quantities with same unit of measurement. Also, ratio is a unitless(no units) quantity.

Given that;

Ratio of cement:sand:gravel= 1:2.5:3.7

The weight of sand bag 150lb.

Let & be the proportion of cement in a mixture. The ratio of cement to sand is given as 1 : 2.5. With a 150-lb sand, then the proportion of cement is given by

1/2.5 = x/150

150=2.5x

x=150/2.5

x=1500/25

x=60

y= 80

Therefore, by the given ratio answer will be 60 and 80.

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A nontrivial linear combination of the vectors that equals the zero vector, we can conclude that the set is linearly dependent.

The set of vectors is linearly dependent because V3 can be written as a linear combination of V1, V2, and V4:

V3 = 2V1 - 3V2 + V4

To see this, we can write out each component of the vectors:

V1 = | 2 | , V2 = | 0 | , V3 = | -1 | , V4 = | 1 |

| 1 | | 1 | | 2 | | 3 |

Then we can plug in the values and see that the equation holds:

2V1 - 3V2 + V4 = 2| 2 | - 3| 0 | + | 1 | = | 4 | - | 0 | + | 1 | = | 5 |

| 1 | | 1 | | 3 | | 1 | | 1 | | 2 | | 3 | | 1 |

Since we have found a nontrivial linear combination of the vectors that equals the zero vector, we can conclude that the set is linearly dependent.

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The steps that she could use to solve the quadratic equation is determined as 2(x² + 6x + 9) = 18 + 3.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides. LHS = RHS is a common mathematical formula.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given:

2x² + 12x - 3 = 0

2x² + 12x = 3

divide through by 2

x² + 6x = ³/₂

Take half of coefficient of x, square it and add it both sides of the equation

(x + 3)² = ³/₂ + 3²

x² + 6x + 9 = 9 + ³/₂

2(x² + 6x + 9) = 18 + 3

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The interval of convergence for this power series is (-∞, ∞) and the radius of convergence is infinite.

The power series representation of the function f(x) = 4 - 3x centered at x = 0 is given by the formula:

[tex]f(x) = [infinity]n=0 (4 (-3)^n * x^n)[/tex]

This power series can be used to represent the function for values of x in the interval of convergence. The interval of convergence for this power series is calculated by taking the limit of the absolute value of the coefficient of the highest power of x as n approaches infinity. In this case, the coefficient of the highest power of x is [tex]4(-3)^n[/tex], so the limit of the absolute value of this coefficient is [tex]|4(-3)^∞|[/tex] = 0. Thus, the interval of convergence for this power series is (-∞, ∞).

We can also calculate the radius of convergence for this power series. The radius of convergence is the distance from the center of the series, in this case x = 0, to the point at which the series diverges. To calculate the radius of convergence we can use the ratio test. The ratio test states that if [tex]lim |a(n+1)/a(n)| < 1,[/tex] then the series converges. The ratio of any two consecutive terms in this series is [tex]|4(-3)^(n+1)/4(-3)^n| = |-3|[/tex], which is less than 1. Thus, the radius of convergence for this power series is infinite.

In conclusion, the power series representation of the function f(x) = 4 - 3x centered at x = 0 is given by the formula: [tex]f(x) = [infinity]n=0 (4 (-3)^n * x^n)[/tex]. The interval of convergence for this power series is (-∞, ∞) and the radius of convergence is infinite.

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The vectors are dependent. One set of numbers that makes the equation true is c1 = -8/77, c2 = 22/77, and c3 = 0.

To decide if the vectors [77 22 22], [24 12 8], and [75 24 22] are directly reliant, we really want to find scalars c1, c2, and c3 with the end goal that:

c1[77 22 22] + c2[24 12 8] + c3[75 24 22] = [0 0 0]

We can set up an arrangement of straight conditions:

77c1 + 24c2 + 75c3 = 0

22c1 + 12c2 + 24c3 = 0

22c1 + 8c2 + 22c3 = 0

Utilizing column decrease, we can address this arrangement of conditions to track down the upsides of c1, c2, and c3:

[1 24/77 75/77 | 0]

[0 1 - 1 | 0]

[0 0 1 | 0]

The last column of the line decreased expanded network lets us know that c3 = 0. Subbing this back into the initial two conditions, we get:

77c1 + 24c2 = 0

22c1 + 12c2 = 0

Tackling for c1 and c2, we get:

c1 = - 8/77

c2 = 22/77

Consequently, the vectors [77 22 22], [24 12 8], and [75 24 22] are straightly ward, and we can find scalars that make the condition [0 0 0] = c1[77 22 22] + c2[24 12 8] + c3[75 24 22] valid.

Specifically, we have:

-8/77 [77 22 22] + 22/77 [24 12 8] = [-3/77 0 0]

Thus, one bunch of numbers that makes the condition genuine is c1 = - 8/77, c2 = 22/77, and c3 = 0, which gives a non-zero vector [-3/77 0 0] on the left-hand side.

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Answer:

2) 486 ft²

4) 38 ft²

5) 27 ft²

6) 149 ft²

Step-by-step explanation:

Just subtract the area of the unshaded part from the shaded part (as if the unshaded part wasn't there)

2) [shaded] (18 • 31.5) – [unshaded] (9 • 9) = 567 – 81 = 486

4) [shaded] (9 • 6) – [unshaded] (4 • 4) = 54 – 16 = 38

5) [shaded] (6 • 6) – [unshaded] (3 • 3) = 36 – 9 = 27

6) [shaded] (14 • 14) – [unshaded] (7 • 7)

= 196 – 49 = 149

The point (7, -8) is located in the third quadrant (Quadrant III) of the coordinate plane, as the x-coordinate is positive and the y-coordinate is negative.

In a coordinate plane, a quadrant is one of the four regions that are formed by dividing the plane into four equal parts by the x-axis and y-axis. The x-axis and y-axis intersect at the origin (0, 0), and the four regions are labeled as Quadrant I, Quadrant II, Quadrant III, and Quadrant IV

Therefore, Each quadrant has its own characteristics and is used in different applications, such as plotting points, graphing functions, and solving problems in mathematics and science.

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Answer:

-3 ≤ x ≤ 3

Step-by-step explanation:
The domain just means all the possible inputs/ x values of a function.

Answer:

Domain is everything under x

Step-by-step explanation:

D: {-3, -2, -1. 0, 1, 3}

Opposite numbers 5 and -5 are opposite because they are an equal distance from zero.

Absolute value, like |-5| = 5, means that the number is at five units of distance from zero.

The opposite of a number is obtained exchanging just the signal of the number.

The opposite of a number x is then given as follows:

-x.

As the number and it's opposite is the same distance from zero, they have the same absolute value.

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Third-degree Taylor polynomial for f(x) = e centered at a = 1 using a graphing calculator estimate the value of eˣ near x = 1.

A polynomial is an expression consisting of variables and coefficients, which involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents.

Now, let's focus on the Taylor polynomial. The Taylor polynomial of degree n for a function f(x) centered at a is given by the formula:

[tex]Tn(x) = f(a) + f'(a)(x - a) + f''(a)(x - a)^{2/2!} + f'''(a)(x - a)^{3/3!} + ... + f^{n}(a)(x - a)^{n/n!}[/tex]

In this formula, f'(a), f''(a), f'''(a), and f^(n)(a) are the first, second, third, and nth derivatives of f(x), respectively, evaluated at a. The symbol n! denotes the factorial of n, which is the product of all positive integers from 1 to n.

In our case, we're given the function f(x) = e and a = 1. The first derivative of e^x is e^x, the second derivative is e^x, and the third derivative is also eˣ. Evaluating these derivatives at a = 1, we get:

f(1) = e¹ = e

f'(1) = e¹ = e

f''(1) = e¹ = e

f'''(1) = e¹ = e

Substituting these values into the formula for the Taylor polynomial, we get:

[tex]T3(x) = e + e(x - 1) + e(x - 1)^{2/2!} + e(x - 1)^{3/3!}[/tex]

Simplifying this expression, we get:

[tex]T3(x) = e + e(x - 1) + e(x - 1)^{2/2} + e(x - 1)^{3/6}[/tex]

This is the third-degree Taylor polynomial for f(x) = e centered at a = 1. It can be used to approximate the value of eˣ near x = 1.

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Complete Question:

A graphing calculator is recommended. Find the Taylor polynomial T3(x) for the function f centered at the number a. f(x) = e, a = 1.

We would expect John to weigh approximately 199.8 pounds at the end of week 8 if he continues to burn 6100 calories per week and maintains a proper diet.

Finding the best linear relationship between the independent and dependent variables is the aim of linear regression. To put it another way, it seeks out the line (or plane, or hyperplane in higher dimensions) that best fits the data. The dependent variable's future values for new values of the independent variable can then be predicted using this line.

We may build a linear regression model using the provided data, with activity (in calories) serving as the independent variable and weight (in pounds) serving as the dependent variable. Using this model, we can then forecast John's weight at the conclusion of week eight depending on the number of calories he burned in that week.

Using a spreadsheet or statistical software, we can calculate the regression equation:

Weight = -0.0049 x Exercise + 229.85

We can plug in the exercise value for week 8 (6100 calories) and solve for weight:

Weight = -0.0049 x 6100 + 229.85

Weight ≈ 199.8 pounds

Therefore, we would expect John to weigh approximately 199.8 pounds at the end of week 8 if he continues to burn 6100 calories per week and maintains a proper diet.

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The answer is (C) the absolute value of the z-score for the midterm exam grade is greater than for the final grade, so the midterm grade is more unusual.

To calculate the z-scores for the midterm and final exam grades, we first need to calculate the mean and standard deviation for each data set.

For the midterm exam grades:

mean = (80 + 78 + 85 + 82 + 79 + 79 + 78 + 86 + 80 + 84) / 10 = 81.1

standard deviation = sqrt([ (80-81.1)^2 + (78-81.1)^2 + ... + (84-81.1)^2 ] / 9) = 2.336

For the final exam grades:

mean = (81 + 88 + 68 + 69 + 69 + 81 + 82 + 86 + 76 + 71) / 10 = 77.1

standard deviation = sqrt([ (81-77.1)^2 + (88-77.1)^2 + ... + (71-77.1)^2 ] / 9) = 7.042

Now, we can calculate the z-scores for Jaymes's grade of 86 on each exam:

z-score for midterm grade = (86 - 81.1) / 2.336 = 2.094

z-score for final exam grade = (86 - 77.1) / 7.042 = 1.259

To determine which grade is more unusual, we need to compare the absolute values of the z-scores. Since the absolute value of the z-score for the midterm grade is greater than for the final exam grade (|2.094| > |1.259|), we can conclude that the midterm grade is more unusual for Jaymes. Therefore, the answer is (C).

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_____The given question is incomplete, the complete question is given below:

The midterm and final exam grades for a statistics course are provided in the data set below. Jaymes, a student in the class, scored 86 on both exams. Treat the given data sets as samples. Jaymes's wants to know which grade is more unusual, the midterm grade or the final exam grade. Use Use a TI-83, TI-83 Plus, or TI-84 calculator to calculate the z-scores corresponding to each grade. Round your answer to three decimal places.

Midterm 80, 78, 85, 82, 79, 79, 78, 86, 80, 84,

final 81, 88, 68, 69, 69, 81, 82, 86, 76, 71

(a) Using a direct proof, we can demonstrate that the assertion "For all integers a and b, if an is even and b is a multiple of 3, then ab is a multiple of 6" is true.

(b) The statement's opposite is "For all numbers a and b, if ab is a multiple of 6, then an is even and b is a multiple of 3.

Assume that both a and b are multiples of three and that an is an even number. Then, we can write a = 2k and b = 3n for some integers k and n, respectively. Adding these two equations together results in:

ab=(2k, 3n), 6kn

Due to the fact that k and n are both numbers, their product 6kn is also an integer. Ab is a multiple of 6, proving the assertion because of this.

(b) The statement's opposite is (b) "For all numbers a and b, if ab is a multiple of 6, then an is even and b is a multiple of 3." The following example refutes the converse assertion, which is untrue:

Let a and b each be three. Therefore, ab is a multiple of 6 and equals 12. The converse assertion is untrue because an is not an even number and b is not a multiple of three.

We have thus demonstrated the validity of the initial claim and its supporting evidence while demonstrating the falsity of the opposite claim.

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The expression "(7532 + 100y2) + 10(10y2 - 110)" can be written in the form "ay^2 + b" (a and b are constants). The required value of a + b is 6632.

Expanding the given expression, we have:

(7532 + 100y^2) + 10(10y^2 - 110)

= 7532 + 100y^2 + 100y^2 - 1100 (distributing the factor of 10)

= 200y^2 + 6432

So, we have expressed the given expression in the form ay^2 + b, where a = 200 and b = 6432. The sum of a and b is:

a + b = 200 + 6432 = 6632

Therefore, the value of a + b is 6632.

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The car that would the customer buy is option (c) Car 2, because it has a lower sample standard​ deviation, hence more predictable gas mileage.

The standard deviation is a measure of how much the data deviates from the mean.

Looking at the data sets, we can see that Car 1 has a wider range of gas mileage, with a minimum of 157 miles and a maximum of 318 miles per 10 gallons of gas. In comparison, Car 2 has a narrower range, with a minimum of 201 miles and a maximum of 279 miles per 10 gallons of gas. The range is a measure of spread, and we can see that Car 1 has a larger spread.

To further analyze the spread, we can calculate the sample standard deviation for each data set.  A higher standard deviation indicates more variability in the data. In this case, Car 1 has a sample standard deviation of 43.6 miles per 10 gallons of gas, while Car 2 has a sample standard deviation of 22.9 miles per 10 gallons of gas. This means that Car 1 has more variability in its gas mileage.

In terms of center, we can calculate the sample mean for each data set. The sample mean is a measure of the average gas mileage. Car 1 has a sample mean of 247.5 miles per 10 gallons of gas, while Car 2 has a sample mean of 249.7 miles per 10 gallons of gas. We can also calculate the median, which is the middle value of the data set. Car 1 has a median of 252.5 miles per 10 gallons of gas, while Car 2 has a median of 252.0 miles per 10 gallons of gas.

Based on these measures, we can see that there is very little difference between the two cars in terms of center. However, Car 2 has a lower sample standard deviation, indicating more predictable gas mileage. Therefore, the customer should choose Car 2 because it has more consistent gas mileage.

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A bar graph or a column chart would be the best type of graph to show the number of students who earned extra credit each day this week.

The visual display of data (often grouped) in the shape of vertical or horizontal rectangular bars, with the length of the bars corresponding to the measure of the data, is called a bar graph. Bar charts are another name for them.

The bar graph or column chart will allow you to easily compare the number of students who earned extra credit on each day of the week and see any trends or patterns that may exist.

The vertical bars on the graph represent the number of students who earned extra credit, and the horizontal axis shows the days of the week.

You could also consider using a line graph to show the trend in the number of students earning extra credit over the course of the week,

but this would not be as effective in comparing the number of students who earned extra credit each day.

Therefore, the bar graph or column chart is the required graph.

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Answer:

Step-by-step explanation:

He can walk 125km in 2 and a half hours

Answer:

125km

Step-by-step explanation:

If he walks 50km per hour and he walks 2 hours it's 2 x 50km = 100km

if walks for another half hour the half of 50km is 25km so 100km + 25km = 125km

The density of the liquid is 2g/cm³

The density of a substance is the relationship between the mass of the substance and how much space it takes up (volume). The mass of atoms, their size, and how they are arranged determine the density of a substance. Density equals the mass of the substance divided by its volume; D = m/v.

Where D is the density

m is the mass and

v is the volume

mass = 100kg = 100000 g( 1kg = 1000g)

50l = 50 × 1000 = 50000cm³

density = 100000/50000

= 2g/cm³

therefore the density of the liquid is 2 g/cm³

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The dividends per share for the preferred stock are $2.50, $0.80, and $3.00 for 20Y1, 20Y2, and 20Y3, respectively.

The dividends per share for the common stock are $0.75, $0.24, and $0.90 for 20Y1, 20Y2, and 20Y3, respectively.

To determine the dividends per share for preferred and common stock, we need to divide the total dividends by the number of shares outstanding for each type of stock.

For the preferred stock:

20Y1: $37,500 ÷ 15,000 shares = $2.50 per share

20Y2: $12,000 ÷ 15,000 shares = $0.80 per share

20Y3: $45,000 ÷ 15,000 shares = $3.00 per share

For the common stock:

20Y1: $37,500 ÷ 50,000 shares = $0.75 per share

20Y2: $12,000 ÷ 50,000 shares = $0.24 per share

20Y3: $45,000 ÷ 50,000 shares = $0.90 per share

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The domain of the rational expression: x-5/3x-6 is all real numbers except 2. Option B is the correct answer.

A polynomial fraction with at least one variable in the denominator is referred to as a "rational expression." The expression is only linear or a polynomial if the variables are only in the numerator. Rational expressions can be used for pretty much anything that can be done with conventional fractions.

To determine a rational function's domain: Take the expression's denominator. Put a zero in that denominator. For the zeroes in the denominator, solve the ensuing equation.

All other x-values make up the domain.

The rational expression is given as:

x - 5 / 3x - 6

The rational expression does not exists when the denominator is equal to 0.

That is,

3x - 6 = 0

3x = 6

x = 2

The domain of a expression is all the input values for which the expression exists.

The given rational expression does not exist at x = 2.

Hence, the domain of the rational expression: x-5/3x-6 is all real numbers except 2. Option B is the correct answer.

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The correct description that best explains the domain of (g o f) (x) is: The elements in the domain of f(x) for which g(f(x)) is defined.

From the question, we have the following parameters that can be used in our computation:

(g o f) (x)

The expression (g o f)(x) is a composite function

The domain of (g o f)(x) is the set of all possible inputs x for which the composition (g o f)(x) is defined.

For the composition (g o f)(x) to be defined, it is necessary that the input x belongs to the domain of f(x), and the output of f(x) belongs to the domain of g(x).

Hence, the domain of (g o f)(x) consists of all the elements in the domain of f(x) for which g(f(x)) is defined

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The height of the tree to the nearest hundredth of a meter will be 6.40 meters.

Trigonometry is the branch of mathematics which set up a relationship between the sides and angles of right-angle triangles.

Let h be the height of the tree in meters. Then, based on the similar triangles formed by Ethan, his shadow, the tree, and its shadow, we have:

h / x = Ethan's height/distance to Ethan's feet from the tree

and

h / (x + 28.45) = Ethan's height/distance to Ethan's feet from the tip of the shadows

where x is the length of Ethan's shadow in meters. We can solve for x using the first equation as follows:

x = (Ethan's height/distance to Ethan's feet from the tree) * h

Substituting the given values, we get:

x = (1.85 / 24.3) x h = 0.076 x h

We can now substitute this value of x into the second equation and solve for h:

h / (0.076 x h + 28.45) = 1.85 / 24.3

Multiplying both sides by 0.076h + 28.45, we get:

h = (1.85 / 24.3) x (0.076h + 28.45)

Expanding the right side and simplifying, we get:

h = 0.070 x h + 5.95

Subtracting 0.070h from both sides, we get:

0.930h = 5.95

Dividing both sides by 0.930, we get:

h = 6.40 meters (rounded to the nearest hundredth)

Therefore, the height of the tree is approximately 6.40 meters.

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