Question 1 When of alanine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezing point of pure . On the other hand, when of iron(III) chloride are dissolved in the same mass of , the freezing point of the solution is lower than the freezing point of pure . Calculate the van't Hoff factor for iron(III) chloride in . Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Answer:

P4 + 5O2 → P4O10

Explanation:

White Phosphorus - P4

Dioxygen - O2

Tetraphosphorus Decaoxide - P4O10

Answer:

13.3 atm(assuming the temperature given is in Celsius)

Explanation:

First, the moles of each gas must be found. .25 mol He, .50 mol CO, .33 mol NO. Next, each set of mols must be plugged into the ideal gas law, PV=nRT, for each gas. Move it around so you get the pressure P=nRT/V. When you calculate everything, you should get 3.08atm He, 6.15atm CO, and 4.06atm NO. Add these together and you get the pressure of the container.

Answer:

H3PO4 + 3NaOH ----> Na3PO4 + 3H2O

Explanation:

The balanced equation is given below

H3PO4 + 3NaOH ----> Na3PO4 + 3H2O

Answer:

[tex]H_3PO_4 (aq) + 3NaOH (aq) \rightarrow 3H_2O (l) + Na_3PO_4 (aq)[/tex]

Explanation:

Hello,

In this case, for the given reaction:

[tex]H_3PO_4 (aq) + NaOH (aq) \rightarrow H_2O (l) + Na_3PO_4 (aq)[/tex]

We must assure the law of conservation of mass is respected, so we equal the number of atoms at each side of the equation by adding the stoichiometric coefficients to the left of each compound as shown below:

[tex]H_3PO_4 (aq) + 3NaOH (aq) \rightarrow 3H_2O (l) + Na_3PO_4 (aq)[/tex]

So the coefficients are 1, 3, 3 and 1 respectively for each species in the chemical reaction.

Regards.

Answer:

yes

Explanation:

volcanoes have done wonderful things for the earth

volcanoes are necessary because:

fertile is another advantage of volcanic activity."In places like Japan,Indonesia,Philippines,Hawaii,volcanic material mixed in with the soil provides a lot of important nutrients

Answer:

.

Explanation:

.

Answer:

a) Sulphur + Oxygen → Sulphur dioxide

b) Carbon + Oxygen → Carbon dioxide

c) Sulphur + Iron → Iron sulphide

Answer:

Chemical rocket engines use a fuel (something to burn) and an oxidiser (something to react with the fuel). ... As the propellant reacts inside a combustion chamber, the chemical reaction produces hot gases. It is the ejection of these rapidly expanding hot gases at high speed from the rocket nozzle that

( I found this on a website called Science Learning. Full credit to them and their work. Check it out for more information)

Answer:

A. Enthalpy of hydration of CaCl2 = -2293 KJ/mol

Enthalpy of hydration of CaI2 = -2163 KJ/mol

B. Chloride ions

Explanation:

Enthalpy of hydration is the energy required to convert one mole of gaseous ions to aqueousions.

Enthalpy of hydration = Enthalpy of solution - lattice energy

For CaCl2;

Enthalpy of hydration = -46 - 2247 = -2293 KJ/mol

For CaI2;

Enthalpy of hydration = -104 - 2059 = -2163 KJ/mol

B. Since the enthalpy of hydration of CaCl2 is more negative than that of CaI2, it means that chloride ions are more easily attracted to water molecules. This we conclude because the difference in enthalpy values are due to the negative ions as the two compounds share a common positive calcium ion.

The enthalpy for hydration of calcium chloride is -2293 kJ/mol. The enthalpy for the hydration of calcium iodide is -2163 kJ/mol. The chloride ion Cl^- is more strongly attracted to water than iodide.

The enthalpy of hydration also the enthalpy of solvation is the quantity of energy released when 1 mole of gaseous ion is diluted.

It can be expressed by using the formula:

[tex]\mathbf{\Delta H_{hyd} = \Delta H_{solution} + \Delta H_{LE}}[/tex]

The enthalpy for hydration of calcium chloride can be expressed as:

[tex]\mathbf{\Delta H_{hyd(cacl_2)} = \Delta H_{solution(caci_2)} + \Delta H_{LE(caci_2)}}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} = -46 \ kJ/mol +-2247 \ kJ/mol}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} =-2293 \ kJ/mol}[/tex]

The enthalpy for the hydration of calcium iodide can be expressed as:

[tex]\mathbf{\Delta H_{hyd(cal_2)} = \Delta H_{solution(caI_2)} + \Delta H_{LE(caI_2)}}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} = -104 \ kJ/mol +-2059 \ kJ/mol}[/tex]

[tex]\mathbf{\Delta H_{hyd(cacl_2)} =-2163 \ kJ/mol}[/tex]

From the above calculation, we can see that the enthalpy of hydration of calcium chloride is greater than that of calcium iodide,

Therefore, we can conclude that the chloride ion Cl^- is more strongly attracted to water than iodide.

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During respiration, the inhalation of Oxygen (O) using the energy from Glucose (C6H12O6) is the first chain reaction.

Products formed during respiration are: Carbon Dioxide (CO2) and Water (H2O)

Answer:

longitudinal waves and transverse waves.

Explanation:

Mechanical Waves are waves which propagate through a material medium (solid, liquid, or gas) at a wave speed which depends on the elastic and inertial properties of that medium. There are two basic types of wave motion for mechanical waves: longitudinal waves and transverse waves.

The two types of mechanical waves are transverse waves and longitudinal waves.

Transverse waves are characterized by oscillations perpendicular to the direction of wave propagation. In this type of wave, the particles of the medium move in a direction perpendicular to the wave's motion. Examples of transverse waves include electromagnetic waves like light and radio waves, as well as waves on a string or water waves.

Longitudinal waves, on the other hand, have oscillations parallel to the direction of wave propagation. In these waves, the particles of the medium move in the same direction as the wave. Sound waves are a common example of longitudinal waves, as well as seismic waves.

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Answer:

C is the answer.

Explanation:

They are both people of color who were the first to do something in their fields

Answer:

increases

Explanation:because it cant decrease

Answer:

remains the same

Explanation:

Answer:

0.209M

Explanation:

M1V1=M2V2

(28.5 mL)(0.183M)=(25.0mL)(M)

M2= 0.209M

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Hi, you have not provided structure of the aldehyde and alkoxide ion.

Therefore i'll show a mechanism corresponding to the proton transfer by considering a simple example.

Explanation: For an example, let's consider that proton transfer is taking place between a simple aldehyde e.g. acetaldehyde and a simple alkoxide base e.g. methoxide.

The hydrogen atom attached to the carbon atom adjacent to aldehyde group are most acidic. Hence they are removed by alkoxide preferably.

After removal of proton from aldehyde, a carbanion is generated. As it is a conjugated carbanion therefore the negative charge on carbon atom can conjugate through the carbonyl group to form an enolate which is another canonical form of the carbanion.

All the structures are shown below.

Answer:

Br2 (l) + 2e- ---------> 2Br- (aq) E° = 1.08 V cathode

Cu2+ (aq) + e- --------->Cu+ (aq) E° = 0.15 V anode

Explanation:

We have to first state the fact that the reaction having the most positive reduction potential occurs at the cathode in any spontaneous electrochemical cell. The half reaction with the less positive electrode potential usually occurs at the anode.

The overall reaction equation is;

2Cu2+ (aq) + Br2 (l) ----->2Cu+ (aq) + 2Br- (aq)

E°cell= E°cathode - E°anode

E°cathode= 1.08 V

E°anode= 0.15V

E°cell = 1.08-0.15 = 0.93 V

But

∆G°= -nFE°cell

n= 2, F=96500C, E°cell= 0.93V

∆G° = -(2× 96500× 0.93)

∆G= -179490 J

But;

∆G = -RTlnK

R=8.314 JK-1

T= 25+273= 298K

Kc= the unknown

∆G° = -179490 J

Substituting values and making lnK the subject of the formula

lnK= ∆G/-RT

lnK= -( -179490/8.314 × 298)

lnK= 72.45

K= e^72.45

K= 2.91×10^31

Answer:

Nitrifying Bacteria are a group of aerobic bacteria important in the nitrogen cycle as converters of soil ammonia to nitrates, compounds usable by plants. An example is nitrosomonas or nitrobacter and species in that family.

The schematic diagram is attached below, which summarises the oxidation of ammonia or free nitrogen in the soil to nitrates for the cowpea plant's utilisation.

Answer:

Animal cells don't have a dividing cell wall like plant cells do

Explanation:

Plants cells use photosynthesis from the sun, which requires them to have chloroplast filled with chlorophyll to complete this function; animal cells do not have chloroplasts

Answer:

  MCl₂

Explanation:

The formula for boiling point elevation can be used to find x. The "complete dissociation" means there will be an ion of M and x ions of Cl in the solution. The number of moles of solute will be 30.2 grams divided by the molecular weight of MClx, where x is the variable we're trying to find.

  [tex]\Delta T=imK_b\qquad\text{where i=ions/mole, m=molality, $K_b\approx 0.512$}\\\\376.81-373.15=(x+1)\dfrac{\text{moles}}{\text{kg solvent}}(0.512)\\\\\dfrac{3.66}{0.512}=(x+1)\dfrac{\dfrac{30.2}{56+35.45x}}{0.1}=\dfrac{302(x+1)}{56+35.45x}\\\\\dfrac{3.66}{0.512\cdot 302}(56+35.45x)=x+1\\\\\dfrac{3.66\cdot 56}{0.512\cdot 302}-1=x\left(1-\dfrac{3.66\cdot 35.45}{0.512\cdot 302}\right)\\\\x=\dfrac{50.336}{24.877}\approx 2.023[/tex]

Then the formula for the salt is MCl₂.

Answer:

less than 4.62 g

Explanation:

Sodium chloride contains 39% sodium by mass. Hence, 1 g of sodium chloride will contain:

39/100 x 1 = 0.39 g of sodium.

If 1 g of sodium chloride contains 0.39 g of sodium, then how many g of sodium chloride will contain the 1.8 g required sodium per day?

1 g sodium chloride = 0.39 g sodium

x g sodium chloride = 1.8 g sodium

x = 1.8 x 1/0.39 = 4.62 g of sodium chloride

Since the adult is supposed to consume less than 1.8 g of sodium per day, the mass of sodium that should be consume per day and still be within the FDA guidelines will be less than 4.62 g of sodium chloride.

Answer:first one: 3.0g second one: 10g H2O(I)

Explanation:

Answer:

First blank: 3.0 g Pb

Second Blank: 10g [tex]H_{2} O[/tex](l)

Explanation:

Edge '21

Answer:

1. C+ ---- O-

2. O+ ---- Cl-

3. O+ ----- F-

4. C+ ----- N-

5. Cl- ----- C+

6. S- ----- H+

7. S+ ----- Cl -

Explanation:

Electronegativity determines the polarity . There may be two atoms in a bond with high electronegativity, in such cases the positive charge is given to atom with comparatively lower electronegativity. Electronegativity determines the easiness with which an atom attract electrons in a chemical bond. A polar bond is formed when the difference in the electronegativity of two combining atoms is between 0.4 and 1.7. The correct direction is

1. C+ ---- O-

2. O+ ---- Cl-

3. O+ ----- F-

4. C+ ----- N-

5. Cl- ----- C+

6. S- ----- H+

7. S+ ----- Cl -

Explanation:

[tex]CH_2O[/tex] is an energy rich molecule, which when reacts with oxygen produces carbon dioxide and energy. In aerobic reaction oxygen is consumed. IN this biochemical reaction oxygen is consumed and CO2 + CH4 is produced. Thus the reaction is aerobic one.

The  mass of solid BaSO4 formed - 7.64 grams. and the pH of the mixed solution - 13.13

We can calculate the mass of the Ba(OH)2 by calculating the moles each solution contains

n(Ba(OH)2) = 1.00M x 0.05L

= 0.05 moles

0.494M x 0.0864L

= 0.04268 moles

According to balanced reaction 1 mole Ba(OH)2 react with 1 mole H2SO4 molar ratio between Ba(OH)2 to H2SO4 is 1:1 therefore to react with 0.05 mole Ba(OH)2 required H2SO4 = 0.05 mole but H2SO4 therefore H2SO4 is limiting reactant

Ba(OH)2 + H2SO4 ----> BaSO4 + 2 H2O  

0.04268<--- 0.04268  

= 0.0172 mole

0.0172:(0.05 + 0.0664)

= 0.1478 M

Ba(OH)2 is strong base therefore dissociate completely and 1 mole of Ba(OH)2 form to mole of OH- ion therefore concentration of OH- is double than Ba(OH)2

14 - -log[0.1478]

= 14 - 0.83

= 13.13 pH

0.0328 x ( 137 + 32 + 16 x 4 )

= 7.64 grams.

Thus, The  mass of solid BaSO4 formed - 7.64 grams. and the pH of the mixed solution - 13.13

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Answer:

8.3ml of 12M HCl contains 3.646 grams HCl

Explanation:

moles HCl = Molarity X Volume => Volume (Liters) = moles HCl/Molarity

Vol(L) = (3.646g/36.46g/mole)/12M = 0.0083Liter x 1000ml/L = 8.3ml

Answer:

A general instrument, which is used to determine the concentration of hydrogen ion within the aqueous solution is known as a pH meter. The meter helps in determining the alkalinity or acidity, which is articulated in the form of pH. It is also called a potentiometric pH meter as it helps in finding the variation in electrical potential between a reference electrode and a pH electrode. This electrical potential variation is associated with the pH of the solution.  

The potentiometric pH meter comprises a pair of electrodes and a basic electronic amplifier, some may even comprise a combination electrode and some sort of display that demonstrates pH units. The potentiometric pH meter generally exhibits a reference electrode or a combination electrode, and a glass electrode. The probes or electrodes are administered within a solution whose pH values are needed to be determined.  

Answer:

H2O / H+

Explanation:

In alkene hydration, water, being a very weak acid, with insufficient proton concentration, does not have the capacity to initiate the electrophilic addition reaction. An acid must be added to the medium for the reaction to take place.

The mechanism proceeds with the formation of a carbocation after adding the proton to the double bond. Alkene hydration is Markovnikov, that is, the proton is added to the less substituted carbon of the alkene.

Answer:

A. 2.5 x 10^M

Explanation:

H+=10^-pH

- Hope that helps! Please let me know if you need further explanation.

Answer:

A. 2.5 x 10^M

Explanation:

i took the test and i got it correct (edmentum)

Answer: 14.278880821321199

Explanation:

Answer:

521.12323

Explanation:

Answer:

14.2 g

Explanation:

40.00 mL = 0.04000 L solution of SnCl4

3.0 M = 3.0 mol/L Molarity of solution of SnCl4

3.0 mol/L * 0.04000 L = 0.12 mol SnCl4

                          4Cr + 3SnCl4 --> 4CrCl3 + 3Sn

from reaction               3 mol                         3 mol

given                            0.12 mol                   x mol

x = 0.12 mol Sn

Molar mass (Sn) =118.71 g/mol

0.12 mol Sn * 118.71 g/mol≈ 14.2 g

The heat transfer that we'll have will be:

- At first, the metal bar will emanate heat through radiation, to the atmosphere, and to the second metal, through conduction.

- Because of this, the second bar will start to increase it's temperature, up to the fusion point, spending the energy received on the fusion, and also radiating heat to the atmosphere. It won't emit heat in any other form, since heat transmission can happen only from a hot body to a cooler one, and the only things in contact are the two bars.

Answer:

conduction

Explanation:

they are in direct contact